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  • Number guessing game (3+- guessed result)

    - by Nick Waring
    I've been assigned a task to create a game that generates 4 digits and the user has to guess the digits one at a time to get the correct result. If the number is correct a Y is displayed and if not, a N. This was easy, now the next step was to implement another two responses. If the answer is too high, a H is displayed and too low, an N. Again, was easy - now the third is to use the same design as game 2 but if the number is 3 higher than a H is displayed and same if it's 3 lower than a L is displayed - otherwise an X is displayed. I can't figure out how to do this. Here's my test code for game 2 for just one of the digits - any help is appreciated. (5 was used just for a test.) def guess(): x = 5 g= int(input("Guess the number: ")) if g == x: print("Y") elif g < x: print("L") else: print("H")

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  • How to set up a specific registration on Database

    - by ymorenz
    I'm creating a database so I can access names of people from a university. But I would like to create a registration ID for each person like 1012607, of which the first 2 numbers would be the year (11 for 2011) and the third digit would be the semester they registered (1 in the beginning of the year and 2 in the end of the year). The other 4 digits would be incremental. I don't know how to code a prefixed number in MySQL that can change only the last 4 digits and after a year change the first 2 digits every time you have a new registration. Can someone please help me?

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  • Implementing custom "Remember Me" with Stripe

    - by Matt
    Implementing remember me with Stripe, while not using their Checkout (not supported on PhoneGap), seems to be fine using the path: First time: Request token on the client side using card info. Create customer on server side using token. Upon confirm, charge customer. Second time: Check if current user is Stripe customer by requesting the info from our server. If is Stripe customer, show "use credit card on file" instead of regular CC form. Upon confirm, charge customer. However, there is one important convenience items missing--last four digits of card number. Most sites inform you of the card you're using before making the payment, pretty important in case you have to switch out cards. I have seen that you can retrieve charges which would allow me to get the last four digits. Is it bad practice to pull that and display it? Are there alternative solutions anyone has in mind?

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  • Project Euler 52: Ruby

    - by Ben Griswold
    In my attempt to learn Ruby out in the open, here’s my solution for Project Euler Problem 52.  Compared to Problem 51, this problem was a snap. Brute force and pretty quick… As always, any feedback is welcome. # Euler 52 # http://projecteuler.net/index.php?section=problems&id=52 # It can be seen that the number, 125874, and its double, # 251748, contain exactly the same digits, but in a # different order. # # Find the smallest positive integer, x, such that 2x, 3x, # 4x, 5x, and 6x, contain the same digits. timer_start = Time.now def contains_same_digits?(n) value = (n*2).to_s.split(//).uniq.sort.join 3.upto(6) do |i| return false if (n*i).to_s.split(//).uniq.sort.join != value end true end i = 100_000 answer = 0 while answer == 0 answer = i if contains_same_digits?(i) i+=1 end puts answer puts "Elapsed Time: #{(Time.now - timer_start)*1000} milliseconds"

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  • Project Euler 16: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 16.  As always, any feedback is welcome. # Euler 16 # http://projecteuler.net/index.php?section=problems&id=16 # 2^15 = 32768 and the sum of its digits is # 3 + 2 + 7 + 6 + 8 = 26. # What is the sum of the digits of the number 2^1000? import time start = time.time() print sum([int(i) for i in str(2**1000)]) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Why are UUID / GUID's in the format they are?

    - by Xeoncross
    Globally Unique Identifiers (GUID) are a grouped string with a specific format which I assume has a security reason. A GUID is most commonly written in text as a sequence of hexadecimal digits separated into five groups, such as: 3F2504E0-4F89-11D3-9A0C-0305E82C3301 Why aren't GUID/UUID strings just random bytes encoded using hexadecimal of X length? This text notation contains the following fields, separated by hyphens: | Hex digits | Description |------------------------- | 8 | Data1 | 4 | Data2 | 4 | Data3 | 4 | Initial two bytes from Data4 | 12 | Remaining six bytes from Data4 There are also several versions of the UUID standards. Version 4 UUIDs are generally internally stored as a raw array of 128 bits, and typically displayed in a format something like: uuid:xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx

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  • Ab Initio - Formatting a number in Left alignment

    - by Veera
    I have a requirement in Ab Initio to format a number in left alignment. I shouldn't be using String conversion (as Strings are left aligned by default), as it might cause compatibility problems in the other end. For example, if my Field has 7 bytes length, and I'm getting only two digits as my input, then these two digits should go into the first two bytes of my field (left aligned), instead of the last two bytes. So, is there any in-built function in Ab Initio, that can format a number as left aligned?

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  • How to update multiple rows with different values in mysql?

    - by user210481
    I have a table with a column 'A'. Some rows have 14 digits for the column 'A' and some have only 12. I need to transform all the entries to 14 digits. The datatype is varchar I would like to update all the rows at once (one query), adding zeros before the first digit, so an entry like 012345678910 would become 00012345678910. Is it possible to do it in one single query? Thanks

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  • Calling a function within a class

    - by JM4
    I am having trouble calling a specific function within a class. The call is made: case "Mod10": if (!validateCreditCard($fields[$field_name])) $errors[] = $error_message; break; and the class code is: class CreditCardValidationSolution { var $CCVSNumber = ''; var $CCVSNumberLeft = ''; var $CCVSNumberRight = ''; var $CCVSType = ''; var $CCVSError = ''; function validateCreditCard($Number) { $this->CCVSNumber = ''; $this->CCVSNumberLeft = ''; $this->CCVSNumberRight = ''; $this->CCVSType = ''; $this->CCVSError = ''; // Catch malformed input. if (empty($Number) || !is_string($Number)) { $this->CCVSError = $CCVSErrNumberString; return FALSE; } // Ensure number doesn't overrun. $Number = substr($Number, 0, 20); // Remove non-numeric characters. $this->CCVSNumber = preg_replace('/[^0-9]/', '', $Number); // Set up variables. $this->CCVSNumberLeft = substr($this->CCVSNumber, 0, 4); $this->CCVSNumberRight = substr($this->CCVSNumber, -4); $NumberLength = strlen($this->CCVSNumber); $DoChecksum = 'Y'; // Mod10 checksum process... if ($DoChecksum == 'Y') { $Checksum = 0; // Add even digits in even length strings or odd digits in odd length strings. for ($Location = 1 - ($NumberLength % 2); $Location < $NumberLength; $Location += 2) { $Checksum += substr($this->CCVSNumber, $Location, 1); } // Analyze odd digits in even length strings or even digits in odd length strings. for ($Location = ($NumberLength % 2); $Location < $NumberLength; $Location += 2) { $Digit = substr($this->CCVSNumber, $Location, 1) * 2; if ($Digit < 10) { $Checksum += $Digit; } else { $Checksum += $Digit - 9; } } // Checksums not divisible by 10 are bad. if ($Checksum % 10 != 0) { $this->CCVSError = $CCVSErrChecksum; return FALSE; } } return TRUE; } } When I run the application - I get the following message: Fatal error: Call to undefined function validateCreditCard() in C:\xampp\htdocs\validation.php on line 339 any ideas?

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  • Django: FloatField or DecimalFied for Currency ?

    - by Hellnar
    I am curious which one would be better fitting as a currency field ? I will do simple operations such as taking difference, the percentage between old and new prices. I plan to keep two digits after the zero (ie 10.50) and majority of the time if these digits are zero, I will be hiding these numbers and display it as "10"

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  • In SQL server, to convert a varchar which have this format (nnn:nn:nn)

    - by user1688917
    I have this varchar format as time accumulation and i want to convert it to an integer to do a SUM and get the total time for a group. The fist part which may be 1, 2, 3, 4 or even five digits represent the accumulation of Hours and then seperated by a colon. then come the second part which is accumulation of minutes and last accumulation of seconds (2 digits each). How to convert this to integer in one query if possile.

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  • Java OCR Help Needed

    - by maSnun
    Hello, How do I detect all the characters in an image? The image is in png and the font is constant. For simplicity, lets assume that the image has only numeric digits and there are only 4 digits on an image. I need to read all of them and output the text. Can you help? Thanks in advance.

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  • Ruby on Rails: How do you add add zeros in front of a number if it's under 10?

    - by sjsc
    I'm looking to convert single digit numbers to two-digit numbers like so: 9 ==> 09 5 ==> 05 12 == 12 4 ==> 04 I figure I could put a bunch of if-else statements (if number is under 10, then do a gsub) but figure that's horrible coding. I know Rails has number_with_precision but I see that it only applies to decimal numbers. Any ideas on how to convert single-digits to two-digits?

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  • Arbitrary-precision arithmetic Explanation

    - by TT
    I'm trying to learn C and have come across the inability to work with REALLY big numbers (i.e., 100 digits, 1000 digits, etc.). I am aware that there exist libraries to do this, but I want to attempt to implement it myself. I just want to know if anyone has or can provide a very detailed, dumbed down explanation of arbitrary-precision arithmetic. Thanks!

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  • I need to change a zip code into a series of dots and dashes (a barcode), but I can't figure out how

    - by Maggie
    Here's what I've got so far: def encodeFive(zip): zero = "||:::" one = ":::||" two = "::|:|" three = "::||:" four = ":|::|" five = ":|:|:" six = ":||::" seven = "|:::|" eight = "|::|:" nine = "|:|::" codeList = [zero,one,two,three,four,five,six,seven,eight,nine] allCodes = zero+one+two+three+four+five+six+seven+eight+nine code = "" digits = str(zip) for i in digits: code = code + i return code With this I'll get the original zip code in a string, but none of the numbers are encoded into the barcode. I've figured out how to encode one number, but it wont work the same way with five numbers.

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  • Formatting currency within a specific precision range

    - by Alex Prose
    I am trying to format currency that will always contain 2 decimal digits, but if there are extra digits of accuracy to display up to five. As an example: for value = 5.0 display: $5.00 for value = 5.023 display: $5.023 for value = 5.333333333333333 display: $5.33333 I have been playing with the .ToString() formatting, but I can't seem to find the right match of options. Clarification: I want to show from 2-5 decimals, truncating zeros after the second digit. for value = 5.000000000000000 display: $5.00 for value = 5.333333333333333 display: $5.33333

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  • Without width printing format in C

    - by yCalleecharan
    Hi, in C if I have a printf statement containing say "%.2f", it says that the precision is 2 digits after the decimal place. I haven't explicitly specify the width. I have two questions: Is this good programming practice?; Is without specifying the width means that the width of the field will get adjusted automatically when printing the number, irrespective of the number of digits it contains? Thanks a lot...

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  • How to save massive numbers in php...

    - by James Rattray
    I want Pi to like 100,000,000 decimals/digits... And variables (well for me) say they have a limit of 67,000,000 bytes... Is there any way around this? can you save the first 10,000 characters/digits into one? can you save it into an array 10,000 in each? Is there a way? If so how? Thanks alot...

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