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• Concatenate and group multiple rows in Oracle

  - by user1693347

  Suppose I have a table like this: NAME GROUP name1 groupA name2 groupB name5 groupC name4 groupA name3 groupC I'd like to have a result like this: GROUP NAMES groupA name1,name4 groupB name2 groupC name3,name5 If there were only one column in the table, I could concatenate the records by doing the following, but with grouping in the context, I really don't have much idea. Any suggestion is welcome, thanks in advance! Concatatenating one column table: SELECT names FROM (SELECT SYS_CONNECT_BY_PATH(names,' ') names, level FROM name_table START WITH names = (SELECT names FROM name_table WHERE rownum = 1) CONNECT BY PRIOR names < names ORDER BY level DESC) WHERE rownum = 1

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• Database copy between servers - user logins corrupted

  - by Steve

  When I copy a database from one server to another via backup and restore, I find I have to recreate the users in the database. I can't login as them right after the copy - I get cannot open default database, when the database that was just copied is the default database. Why is this? The logins exist on the target copy server.

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• Is a JOIN more/less efficient than EXISTS IN when no data is needed from the second table?

  - by twpc

  I need to look up all households with orders. I don't care about the data of the order at all, just that it exists. Is it more efficient to say something like this: SELECT HouseholdID, LastName, FirstName, Phone FROM Households INNER JOIN Orders ON Orders.HouseholdID = Households.HouseholdID or this: SELECT HouseholdID, LastName, FirstName, Phone FROM Households WHERE EXISTS (SELECT HouseholdID FROM Orders WHERE Orders.HouseholdID = Households.HouseholdID)

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• Replace BIT values with some text

  - by nihi_l_ist

  I have a BIT column with gender (0,1) and want to replace 0 and 1 in the resulting view with the words "man" and "woman". Can i do this right in the view with some system finction or i have to write my own function to do that?

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• What would be a good Database strategy to manage these two product options?

  - by bemused

  I have a site that allows users to purchase "items" (imagine it as an Advertisement, or a download). There are 2 ways to purchase. Either a subscription, 70 items within 1 month (use them or lose them--at the end of the month your count is 0) or purchase each item individually as you need it. So the user could subscribe and get 70/month or pay for 10 and use them when they want until the 10 are gone. Maybe it's the late hour, but I can't isolate a solution I like and thought some users here would surely have stumbled upon something similar. One I can imagine is webhosts. They sell hosting for monthy fees and sell counts of things like you get 5 free domains with our reseller account. or something like a movie download site, you can subscribe and get 100 movies each month, or pay for a one-time package of 10 movies. so is this a web of tables and where would be a good cross between the product a user has purchased and how many they have left? products productID, productType=subscription, consumable, subscription&consumable subscriptions SubscriptionID, subscriptionStartDate, subscriptionEndDate, consumables consumableID, consumableName UserProducts userID,productID,productType ,consumptionLimit,consumedCount (if subscription check against dates), otherwise just check that consumedCount is < than limit. Usually I can layout my data in a way that I know it will work the way I expect, but this one feels a little questionable to me. Like there is a hidden detail that is going to creep up later. That's why I decided to ask for help if someone in the vast expanse can enlighten me with their wisdom and experience and clue me in to a satisfying strategy. Thank you.

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• Strange SQL problem selecting multiple values for same column

  - by Nubber

  Hello there, Been at this for a few hours now and I can't make any sense of it. I've used this way of selecting multiple values for same column a few times, but there is something weird with this one. SELECT * FROM employee as s INNER JOIN works AS w1 ON w1.name = s.name INNER JOIN employee AS w2 ON w2.name = s.name INNER JOIN employee AS w3 ON w3.name = s.name WHERE w2.city = 'Washington' Basically what I want to do is find all companies which have people in all the cities. The company name is under 'works'. The problem is however that if I have the WHERE w2.city='Washington' it will make ALL the cities match Washington when it should only touch w2 and leave w3 alone so I could match it with another value. Anyone know why its doing this? Or know a better way to do it. Thank you very much in advance.

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• Performance problem on a query.

  - by yapiskan

  Hi, I have a performance problem on a query. First table is a Customer table which has millions records in it. Customer table has a column of email address and some other information about customer. Second table is a CommunicationInfo table which contains just Email addresses. And What I want in here is; how many times the email address in CommunicationInfo table repeats in Customers table. What could be the the most performer query. The basic query that I can explain this situation is; Select ci.Email, count(*) from Customer c left join CommunicationInfo ci on c.Email1 = ci.Email or c.Email2 = ci.Email Group by ci.Email But sure, it takes about 5, 6 minutes in execution. Thanks in Advance.

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• How to set up a specific registration on Database

  - by ymorenz

  I'm creating a database so I can access names of people from a university. But I would like to create a registration ID for each person like 1012607, of which the first 2 numbers would be the year (11 for 2011) and the third digit would be the semester they registered (1 in the beginning of the year and 2 in the end of the year). The other 4 digits would be incremental. I don't know how to code a prefixed number in MySQL that can change only the last 4 digits and after a year change the first 2 digits every time you have a new registration. Can someone please help me?

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• SqlCE Flush Interval - Will the default setting lead to corruption?

  - by NormD

  SqlCE has a parameter set on the Connect String called Flush Interval. It is defined as: The interval time (in seconds) before all committed transactions are flushed to disk. If not specified, the default value is 10. I thought that a committed transaction, by definition, is a transaction that has been flushed to disk, specifically the database file. If a transaction is only stored in RAM then cannot the transaction be easily lost? I thought that transactions were first written to a log file and then applied to the database file itself, so perhaps this parameter could mean the time to wait until the transaction log is applied to the database file? I would have thought that this parameter should be 0.

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• make select @@IDENTITY; a long?

  - by acidzombie24

  I am grabbing the last rowid and i am doing this select @@IDENTITY pk = (long)cmd.ExecuteScalar(); I get an invalid typecast bc this is int instead of long. Why doesnt this return a long? can i make it return long? Solution for now is to use pk = Convert.ToInt64(cmd.ExecuteScalar());

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• How do I display/compare a dynamic value of a mysql row in a if statement?

  - by Ralph The Mouf

  I have a checkboxes on my site that when unchecked, update their row in in the db as unchecked, and if checked,update their row in the db as checked. I am creating an ifstatement that will commence with its command if checked, and not if unchecked. I have echoed the variable and it is holding the proper value (checked or unchecked) but not sure if I am syntactically correct on displaying the state of the row in the db. This is what I am trying and will not work. I am new at php still and thank you very much for any help. if($auth->check_prof == 'checked'){// do the stuff in here}

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• mysql: what is a temporary table?

  - by every_answer_gets_a_point

  what is the purpose of a temporary table like in this statement? how is it different than a regular table? CREATE TEMPORARY TABLE tmptable SELECT A.* FROM batchinfo_2009 AS A, calibration_2009 AS B WHERE A.reporttime LIKE '%2010%' AND A.rowid = B.rowid;

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• How do you check if a certain index exists in a table?

  - by Lieven Cardoen

  Something like this: SELECT * FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WHERE CONSTRAINT_NAME ='FK_TreeNodesBinaryAssets_BinaryAssets' and TABLE_NAME = 'TreeNodesBinaryAssets' but for indexes.

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• Visual Studio 2010 ADO.NET Data Model vs Linq to SQL

  - by LaGrad

  What's the difference between the two? They seem to have the same functionality at first glance. Which one has faster performance which one is easier to use?

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• How do I find the latest TimeStamp(DateTime) for each of my products in combination with another con

  - by radbyx

  Hi, I've two tables: Product: ProductID ProductName StateLog: StateLogID ProductID (Foreign Key) State (bit) TimeStramp (DateTime) I need to find the heighest StateLog.TimeStamp for each StateLog.ProductID there have the StateLog.State = 0

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• How to check if resultset has only one row or more?

  - by TopCoder

  How to check if resultset has only one row or more?

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• Load huge sql dump to mySql

  - by jonathan

  Hi I have a huge mysql dump file generated from phpmyAdmin (150 000 lines of create table, inserts....) The mySql query tool fails to open such a big file. As a result i can't insert all the records. Is there a way to do this ? Thanks John

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• How to convert the time difference to hours(with 2 decimal place) in derby?

  - by jl

  Hi, I am using timestampdiff in derby db to retrieve the time difference between 2 time: startdate, and enddate. e.g. startdate = 2010-02-23 02:59:52.045 enddate = 2010-02-23 03:45:39.898 select {fn timestampdiff(SQL_TSI_HOUR, startdate, enddate)} as diff I would like to know how can I get the time diff in hours, e.g. 0.25, etc? Thank you.

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• what does this ADO OPEN Method do?

  - by every_answer_gets_a_point

  in plain english can you explain to me what happens here: rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable what i need to do is to be able to insert values into a table called batchinfo. would this be the best way to do an OPEN? the only thing i would be doing is inserting values.

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• MySQL join not returning rows

  - by John

  I'm attempting to create an anti-bruteforcer for the login page on a website. Unfortunately, my query is not working as expected. I would like to test how many times an IP address has attempted to login, and also return the ID of the user for my next step in the login process. However, I'm having a problem with the query... for one thing, this would only return rows if it was the same user as they had been trying to login to before. I need it to be any user. Secondly, regardless of whether I use LEFT JOIN, RIGHT JOIN, INNER JOIN or JOIN, it will not return the user's ID unless there is a row for the user in login_attempts. SELECT COUNT(`la`.`id`), `u`.`id` FROM `users` AS `u` LEFT JOIN `login_attempts` AS `la` ON `u`.`id` = `la`.`user_id` WHERE `u`.`username` = 'admin' AND `la`.`ip_address` = '127.0.0.1' AND `la`.`timestamp` >= '1'

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• SELECT Data from multiple tables?

  - by Kyle R

  I have 3 tables, with 3 fields all the same. I basically want to select information from each table For example: userid = 1 I want to select data from all 3 tables, where userid = 1 I am currently using: SELECT r.*, p.*, l.* FROM random r LEFT JOIN pandom p ON r.userid = p.userid LEFT JOIN landom l ON l.userid = r.userid WHERE r.userid = '1' LIMIT 0, 30 But it doesn't seem to work.

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• Does this behavior exist in all major databases?

  - by user198729

  mysql> select 0.121='0.121'; +---------------+ | 0.121='0.121' | +---------------+ | 1 | +---------------+ Does it hold for other database that number='number' is true?

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• TSQL to Map User to Database

  - by dtrick

  So I'm not able to user enterprise manager to do this... If I was I wouldn't even be asking this question. So I'm wondering if there is a way through TSQL to execute a command that maps a User to a particular Database and grants them 'owner' permissions. Thanks...

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• How to do Group By in grails to order by Count(*)

  - by skurt

  How do I translate: SELECT COUNT(*) AS `count`, `a` FROM `b` GROUP BY `a` ORDER BY `a` into grails or gorm query?

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• ERROR: there is no parameter $1 when creating view

  - by idlemoments

  When we try to create a view within a funcion we get ERROR: there is no parameter $1. This is the sample code. Begin CREATE VIEW artikelnr AS SELECT datum, 'uitgifte' as "type", CASE WHEN 'test'='test' THEN 0 END as "aantal ontvangen", aantal as "aantal uitgegeven" FROM uitgifteregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN uitgifte ON uitgifte.uitgiftenr = uitgifteregel.uitgiftenr UNION SELECT datum, 'ontvangst' as "type", aantal as "aantal ontvangen" , CASE WHEN 'test'='test' THEN 0 END as "aantal uitgegeven" FROM ontvangstregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN ontvangst ON ontvangst.ontvangstnr = ontvangstregel.ontvangstnr; Return new; end; When we replace new.artikelnr on line 7 with value 1 it works like it should, but the function needs to work with different artikelnr's. example line 7: JOIN artikel ON artikel.artikelnr = new.artikelnr Please point us in the right direction.

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