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  • How should I solve this MySql problem (PHP) ? (Beginner)

    - by Camran
    I have several tables in a MySql database. I have a classifieds website, and at the bottom I display the users last visited classifieds. I do this by storing the ID:s of the ads to an array in the cookie. Now, my db is made up like this kindof: Main Table: // Stores global information, ie these fields have to be filled out in every record, never be blank ID Price category Seller Item Table: // Stores descriptive info about whats for sale ID AD_ID (FK) //This is the same as ID in the MAIN TABLE Color Size Mileage etc My problem is that I need to know what category the ad is in, in order to query mysql for the right information I think. So I need two variables, but the cookie only has one (ID) stored. Offcourse I could make two queries, first one just matching the ID to the main_table and fetch the category from the Main_table. Then make the second query and fetch all other info from the right table. Here is an example if the category was Vehicles: SELECT * FROM main_table, vehicles_table, WHERE main_table.id=$id_from_cookie AND main_table.ad_id=vehicles_table.ad_id As you can see above, I need the category to write in what table to check, right? But I think there must be a smarter way, like fetching them in one single query using only one variable (id from cookie)? How should I do this? Understand? Let me know if you need more input... Thanks

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  • Left Join only returning one row

    - by Adam
    I am trying to join two tables. I would like all the columns from the product_category table (there are a total of 6 now) and count the number of products, CatCount, that are in each category from the products_has_product_category table. My query result is 1 row with the first category and a total count of 68, when I am looking for 6 rows with each individual category's count. <?php $result = mysql_query(" SELECT a.*, COUNT(b.category_id) AS CatCount FROM `product_category` a LEFT JOIN `products_has_product_category` b ON a.product_category_id = b.category_id "); while($row = mysql_fetch_array($result)) { echo ' <li class="ui-shadow" data-count-theme="d"> <a href="' . $row['product_category_ref_page'] . '.php" data-icon="arrow-r" data-iconpos="right">' . $row['product_category_name'] . '</a><span class="ui-li-count">' . $row['CatCount'] . '</span></li>'; } ?> I have been working on this for a couple of hours and would really appreciate any help on what I am doing wrong.

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  • limiting mysql results by range of a specific key INCLUDING DUPLICATES

    - by aVC
    I have a query SELECT p.*, m.*, (SELECT COUNT(*) FROM newPhotoonAlert n WHERE n.userIDfor='$id' AND n.threadID=p.threadID and n.seen='0') AS unReadCount FROM posts p JOIN myMembers m ON m.id = p.user_id LEFT JOIN following f ON (p.user_id = f.user_id AND f.follower_id='$id' AND f.request='0' AND f.status='1') JOIN myMembers searcher ON searcher.id = '$id' WHERE ((f.follower_id = searcher.id) OR m.id='$id') AND p.flagged <'5' ORDER BY p.threadID DESC,p.positionID It brings result as expected but I want to add Another CLAUSE to limit the results. Say a sample (minimal shown) set of data looks like this with the above query. threadID postID positionID url 564 1254 2 a.com 564 1245 1 a1.com 541 1215 3 b1.com 541 1212 2 b2.com 541 1210 1 b3.com 523 745 1 c1.com 435 689 2 d2.com 435 688 1 a4.com 256 345 1 s3.com 164 316 1 f1.com . . I want to get ROWS corresponding to 2 DISTINCT threadIDs starting from MAX, but I want to include duplicates as well. Something like AND p.threadID IN (Select just Two of all threadIDs currently selected, but include duplicate rows) So my result should be threadID postID positionID url 564 1254 2 a.com 564 1245 1 a1.com 541 1215 3 b1.com 541 1212 2 b2.com 541 1210 1 b3.com

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  • mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in

    - by user2533440
    I cannot figure out whats wrong with this code. Every time i try to run this file I get error mysql_fetch_assoc() expects parameter 1 to be resource <?php $q = "select * from tbfood"; $rs = mysql_query($q); while($msg = mysql_fetch_assoc($rs)){ echo "<p>".$msg["name"]."</p>"; echo "<p>".$msg["price"]."</p>"; if ($msg['idDruh'] == 1) { echo "string1"; } elseif ($msg['idDruh'] == 2) { echo "string2"; } elseif ($msg['idDruh'] == 3) { echo "string3"; } elseif ($msg['idDruh'] == 4) { echo "string4"; } elseif ($msg['idDruh'] == 5) { echo "string5"; } elseif ($msg['idDruh'] == 6) { echo "string6"; } elseif ($msg['idDruh'] == 7) { echo "string7"; } } ?>

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  • How to set up a specific registration on Database

    - by ymorenz
    I'm creating a database so I can access names of people from a university. But I would like to create a registration ID for each person like 1012607, of which the first 2 numbers would be the year (11 for 2011) and the third digit would be the semester they registered (1 in the beginning of the year and 2 in the end of the year). The other 4 digits would be incremental. I don't know how to code a prefixed number in MySQL that can change only the last 4 digits and after a year change the first 2 digits every time you have a new registration. Can someone please help me?

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  • what does this ADO OPEN Method do?

    - by every_answer_gets_a_point
    in plain english can you explain to me what happens here: rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable what i need to do is to be able to insert values into a table called batchinfo. would this be the best way to do an OPEN? the only thing i would be doing is inserting values.

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  • Concatenate and group multiple rows in Oracle

    - by user1693347
    Suppose I have a table like this: NAME GROUP name1 groupA name2 groupB name5 groupC name4 groupA name3 groupC I'd like to have a result like this: GROUP NAMES groupA name1,name4 groupB name2 groupC name3,name5 If there were only one column in the table, I could concatenate the records by doing the following, but with grouping in the context, I really don't have much idea. Any suggestion is welcome, thanks in advance! Concatatenating one column table: SELECT names FROM (SELECT SYS_CONNECT_BY_PATH(names,' ') names, level FROM name_table START WITH names = (SELECT names FROM name_table WHERE rownum = 1) CONNECT BY PRIOR names < names ORDER BY level DESC) WHERE rownum = 1

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  • ms-access: designing a report: printing text on specific x,y coordinates

    - by every_answer_gets_a_point
    i need to design a report that will print text on specified x,y coordinates for example, i will input (50,50), (60,60), (70,70) and i will have my program print text at those specific coordinates on the report. in total there will be about 50 different coordinates. how do i achieve this? should i be using a label control or a textbox? should i be creating the controls dynamically or should i already have controls set at the specified regions?

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  • SqlCE Flush Interval - Will the default setting lead to corruption?

    - by NormD
    SqlCE has a parameter set on the Connect String called Flush Interval. It is defined as: The interval time (in seconds) before all committed transactions are flushed to disk. If not specified, the default value is 10. I thought that a committed transaction, by definition, is a transaction that has been flushed to disk, specifically the database file. If a transaction is only stored in RAM then cannot the transaction be easily lost? I thought that transactions were first written to a log file and then applied to the database file itself, so perhaps this parameter could mean the time to wait until the transaction log is applied to the database file? I would have thought that this parameter should be 0.

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  • SQL Join Statement Issue

    - by coffeeaddict
    I'm tring to grab all fields from the latest Cash record, and then all fields from the related TransactionInfo record. I can't quite get this to work yet: select t.*, top 1 c.* from Cash c inner join TransactionInfo t on c.TransactionID = t.id order by createdOn desc

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  • MySQL join not returning rows

    - by John
    I'm attempting to create an anti-bruteforcer for the login page on a website. Unfortunately, my query is not working as expected. I would like to test how many times an IP address has attempted to login, and also return the ID of the user for my next step in the login process. However, I'm having a problem with the query... for one thing, this would only return rows if it was the same user as they had been trying to login to before. I need it to be any user. Secondly, regardless of whether I use LEFT JOIN, RIGHT JOIN, INNER JOIN or JOIN, it will not return the user's ID unless there is a row for the user in login_attempts. SELECT COUNT(`la`.`id`), `u`.`id` FROM `users` AS `u` LEFT JOIN `login_attempts` AS `la` ON `u`.`id` = `la`.`user_id` WHERE `u`.`username` = 'admin' AND `la`.`ip_address` = '127.0.0.1' AND `la`.`timestamp` >= '1'

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  • Load huge sql dump to mySql

    - by jonathan
    Hi I have a huge mysql dump file generated from phpmyAdmin (150 000 lines of create table, inserts....) The mySql query tool fails to open such a big file. As a result i can't insert all the records. Is there a way to do this ? Thanks John

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  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

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  • Strange SQL problem selecting multiple values for same column

    - by Nubber
    Hello there, Been at this for a few hours now and I can't make any sense of it. I've used this way of selecting multiple values for same column a few times, but there is something weird with this one. SELECT * FROM employee as s INNER JOIN works AS w1 ON w1.name = s.name INNER JOIN employee AS w2 ON w2.name = s.name INNER JOIN employee AS w3 ON w3.name = s.name WHERE w2.city = 'Washington' Basically what I want to do is find all companies which have people in all the cities. The company name is under 'works'. The problem is however that if I have the WHERE w2.city='Washington' it will make ALL the cities match Washington when it should only touch w2 and leave w3 alone so I could match it with another value. Anyone know why its doing this? Or know a better way to do it. Thank you very much in advance.

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  • make select @@IDENTITY; a long?

    - by acidzombie24
    I am grabbing the last rowid and i am doing this select @@IDENTITY pk = (long)cmd.ExecuteScalar(); I get an invalid typecast bc this is int instead of long. Why doesnt this return a long? can i make it return long? Solution for now is to use pk = Convert.ToInt64(cmd.ExecuteScalar());

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  • ERROR: there is no parameter $1 when creating view

    - by idlemoments
    When we try to create a view within a funcion we get ERROR: there is no parameter $1. This is the sample code. Begin CREATE VIEW artikelnr AS SELECT datum, 'uitgifte' as "type", CASE WHEN 'test'='test' THEN 0 END as "aantal ontvangen", aantal as "aantal uitgegeven" FROM uitgifteregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN uitgifte ON uitgifte.uitgiftenr = uitgifteregel.uitgiftenr UNION SELECT datum, 'ontvangst' as "type", aantal as "aantal ontvangen" , CASE WHEN 'test'='test' THEN 0 END as "aantal uitgegeven" FROM ontvangstregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN ontvangst ON ontvangst.ontvangstnr = ontvangstregel.ontvangstnr; Return new; end; When we replace new.artikelnr on line 7 with value 1 it works like it should, but the function needs to work with different artikelnr's. example line 7: JOIN artikel ON artikel.artikelnr = new.artikelnr Please point us in the right direction.

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  • Error 49 bad bind variable oracle forms

    - by mysticfalls
    I would like to ask regarding this error... Error 49 at line 5, column 6 bad bind variable 'S_ORD.payment_type' Here is the code: DECLARE N NUMBER; v_credit S_CUSTOMER.credit_rating%type; BEGIN IF :S_ORD.payment_type = 'CREDIT' THEN SELECT credit_rating INTO v_credit FROM S_CUSTOMER WHERE :S_ORD.customer_id = id; IF v_credit NOT IN ('GOOD', 'EXCELLENT') THEN :S_ORD.payment_type:= 'CASH'; n:=SHOW_ALERT('Payment_Type_Alert'); END IF; END IF; END; I'm new to oracle forms so I'm not sure if I have a missing setup or anything. S_ORD table exist and has a column payment_type, which consists of 'CREDIT' and 'CASH' value. Thank you.

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  • Complex SELECT statement; one-to-many all details in one row

    - by RubyWedge
    There are two tables: Products ID (Primary Key), ProductName PlannedByMonths ProductID (Primary Key) (Link to the Products table many-to-one), MonthNumber (Primary Key), QtytoProduce, How to write SELECT statement to retrieve results in the following format? ProductName, QtytoProduceMonth1, QtytoProduceMonth2, QtytoProduceMonth3, QtytoProduceMonth4, QtytoProduceMonth5, QtytoProduceMonth6, QtytoProduceMonth7, QtytoProduceMonth8, QtytoProduceMonth9, QtytoProduceMonth10, QtytoProduceMonth11, QtytoProduceMonth12 Thank you.

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