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  • How to change a recursive function for count files and catalogues?

    - by user661999
    <?php function scan_dir($dirname) { $file_count = 0 ; $dir_count = 0 ; $dir = opendir($dirname); while (($file = readdir($dir)) !== false) { if($file != "." && $file != "..") { if(is_file($dirname."/".$file)) ++$file_count; if(is_dir($dirname."/".$file)) { ++ $dir_count; scan_dir($dirname."/".$file); } } } closedir($dir); echo "There are $dir_count catalogues and $file_count files.<br>"; } $dirname = "/home/user/path"; scan_dir($dirname); ?> Hello, I have a recursive function for count files and catalogues. It returns result for each catalogue. But I need a common result. How to change the script? It returns : There are 0 catalogues and 3 files. There are 0 catalogues and 1 files. There are 2 catalogues and 14 files. I want: There are 2 catalogues and 18 files.

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  • Clarification on ZVals

    - by Beachhouse
    I was reading this: http://www.dereleased.com/2011/04/27/the-importance-of-zvals-and-circular-references/ And there's an example that lost me a bit. $foo = &$bar; $bar = &$foo; $baz = 'baz'; $foo = &$baz; var_dump($foo, $bar); /* string(3) "baz" NULL */ If you’ve been following along, this should make perfect sense. $foo is created, and pointed at a ZVal location identified by $bar; when $bar is created, it points at the same place $foo was pointed. That location, of course, is null. When $foo is reassigned, the only thing that changes is to which ZVal $foo points; if we had assigned a different value to $foo first, then $bar would still retain that value. I learned to program in C. I understand that PHP is different and it uses ZVals instead of memory locations as references. But when you run this code: $foo = &$bar; $bar = &$foo; It seems to me that there would be two ZVals. In C there would be two memory locations (and the values would be of the opposite memory location). Can someone explain?

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  • CakePHP: Missing database table

    - by Justin
    I have a CakePHP application that is running fine locally. I uploaded it to a production server and the first page that uses a database connection gives the "Missing Database Table" error. When I look at the controller dump, it's complaining about the first table. I've tried a variety of things to fix this problem, with no luck: I've confirmed that at the command line I can login with the given MySQL credentials in database.php I've confirmed this table exists I've tried using the MySQL root credentials (temporarily) to see if the problem lies with permissions of the user. The same error appeared. My debug level is currently set to 3 I've deleted the entire contents of /app/tmp/cache I've set 777 permissions on /app/tmp* I've confirmed that I can run DESCRIBE commands at the commant line MySQL when logged in with the MySQL credentials used by by the application I've verified that the CakePHP log file only contains the error I'm setting in the browser window. I've tried all the suggestions I could find in similar postings on SO I've Googled around and didn't find any other ideas I think I've eliminating the obvious problems and my research isn't turning anything up. I feel like I'm missing something obvious. Any ideas?

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  • Display a jQuery Dialog/Popup, then set a hidden field using the result of the dialog

    - by Dan Harris
    The Problem I have a page with a form on. It has a hidden field called: generic_portrait I want the user to click a link "select portrait" This will open a Dialog/Popup using jQuery, based on a dropdown completed earlier in the form. If the value of the dropdown called "gender" is "male" then show male options, if "gender" is set to "female" show female options. Each portrait has a radio button, each with a name assigned "male1", "male2" etc Depending on the radio button selected in the popup, I want the hidden field to be set to match this. The Questions What is the best way to show a dialog/popup using jQuery, different depending on a dropdown box on the page. Use Javascript to see what is selected, then show a corresponding Div? I can do the check to see what the dropdown is set to using jQuery, but how can I then shown a specific popup based on that? Once i've popped it up, how do I take the value assigned to the selected radio box, and set the hidden field called "generic_portrait" to this value. Why i'm asking Normally I would figure this out myself, as i'm sure it's not that difficult, but I don't use Javascript and/or PHP very often, and this is due for a client urgently. So I would really, really appreciate some help on this one. Thanks for all replies in advance.

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  • is_dir does not recognize folders

    - by Rakoon
    Hi I am trying to make a function that scans a folder for subfolders and then returns a numeric array with the names of those folders. This is the code i use for testing. Once i get it to print out the folder names and not just "." and ".." for present and above folder all will be well, and I can finish the function. <?php function super_l_getthemes($dir="themes") { if ($handle = opendir($dir)) { echo "Handle: {$handle}\n"; echo "Files:\n"; while (false !== ($file = readdir($handle))) { echo "{$file}<br>"; } closedir($handle); } ?> The above code works fine, and prints out all the contents of the folder: files, subfolders and the "." and ".." but if i replace: while (false !== ($file = readdir($handle))) { echo "{$file}<br>"; } with: while (false !== ($file = readdir($handle))) { if(file_exists($file) && is_dir($file)){echo "{$file}";} } The function only prints "." and ".." , not the two folder names that I'd like it to print. Any help is appreciated.

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  • entering datas of php page to database

    - by Rahima farzana.S
    I have a php form with two text boxes and i want to enter the text box values into the database. I have created the table (with two columns namely webmeasurementsuite id and webmeasurements id) I used the following syntax for creating table: CREATE TABLE `radio` ( `webmeasurementsuite id` INT NOT NULL, `webmeasurements id` INT NOT NULL ); Utilising the tutorial in the following link, I wrote the php coding but unfortunately the datas are not getting entered into the database. I am getting an error in the insert sql syntax. I checked it but i am not able to trace out the error.Can anyone correct me? I got the coding from http://www.webune.com/forums/php-how-to-enter-data-into-database-with-php-scripts.html $sql = "INSERT INTO $db_table(webmeasurementsuite id,webmeasurements id) values ('".mysql_real_escape_string(stripslashes($_REQUEST['webmeasurementsuite id']))."','".mysql_real_escape_string(stripslashes($_REQUEST['webmeasurements id']))."')"; echo$sql; My error is as follows: INSERT INTO radio(webmeasurementsuite id,webmeasurements id) values ('','')ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'id,webmeasurements id) values ('','')' at line 1

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  • Load function in jquery

    - by user345579
    Hi, I am relatively new to jquery and would like to know why the below code wouldn't work. I am trying to access the content from a file residing on my site and not outside. Is it because I have the jquery lib loading from google and not my site? The error message that I get in IE browser is "Access Denied". I am confused why the access is denied if I am trying to load a file from the same server and even same folder. <html> <head> <script type="text/javascript" language="JavaScript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript" language="JavaScript"> $(document).ready(function(){ $("#response").load("http://www.mydomain.com/loadme.php?route=links/getlinks&path=2"); }); </script> </head> <body> <div id="response" style="border: 1px solid #000;height:500px;">&nbsp;</div> </body> </html> any one please help me. thanks

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  • Creating a Variable From Two Others

    - by John
    Hello, In the HTML table below, I would like to add a third column that equals $row["countSubmissions"] times 10 plus $row["countComments"]. How could I do this? Thanks in advance, John $sqlStr = "SELECT l.loginid, l.username, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY countSubmissions DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.stripslashes($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.stripslashes($row["countComments"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • matching images inside a link in regex

    - by user225269
    What is wrong with regex pattern that I created: $link_image_pattern = '/\<a\shref="([^"]*)"\>\<img\s.+\><\/a\>/'; preg_match_all($link_image_pattern, $str, $link_images); What I'm trying to do is to match all the links which has images inside of them. But when I try to output $link_images it contains everything inside the first index: <pre> <?php print_r($link_images); ?> </pre> The markup looks something like this: Array ( [0] = Array ([0] = " <p>&nbsp;</p> <p><strong><a href="url">Title</a></strong></p> <p>Desc</p> <p><a href="{$image_url2}"><img style="background-image:none;padding-left:0;padding-right:0;display:inline;padding-top:0;border-width:0;" title="image" border="0" alt="image" src="{$image_url2}" width="569" height="409"></a></p> But when outputting the contents of the matches, it simply returns the first string that matches the pattern plus all the other markup in the page like this: <a href="{$image_url}"><img style="background-image:none;padding-left:0;padding-right:0;display:inline;padding-top:0;border-width:0;" title="image" border="0" alt="image" src="{$image_url}" width="568" height="347"></a></p> <p>&nbsp;</p> <p><strong><a href="url">Title</a></strong></p> <p>Desc</p> <p><a href="{$image_url2}"><img style="background-image:none;padding-left:0;padding-right:0;display:inline;padding-top:0;border-width:0;" title="image" border="0" alt="image" src="{$image_url2}" width="569" height="409"></a></p>")

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  • Server Unable to Capture the POST Data sent from another server by Redirecting the URL

    - by user1749092
    Recently i started working on the Payment Gateway( further spelled as 'PG') process for my site. And for the process we have to send the Post data by form to PG server by redirecting to there page and by response from the PG about the Transaction they are sending POST data by redirecting the URL to our server page, the problem arises here, as my server unable to retrieve the POST Data sent from PG server. As i am coding in PHP, i tried to print all the response coming from PG by print_r($_POST); and even tried with print_r($_REQUEST);. I didn't found any data printing except the PHPSESSID and some other data array. As for the confirmation I checked wether they sending the Data or not by the IE addon as "TamperIE" where it is showing the all the POST Data sending from there server. But it is not at all coming to our server. And I tried this process on some other Server, there i able to get the POST response but not with currently working server. So please can you suggest me what might be the problem. Thanks!

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  • Retrieving the first picture with a HTML parser

    - by justin01
    Hey guys, (Not a native english speaker) I'm doing a personal project in PHP in which I use the Simple HTML Parser to parse the HTML of a given URL and retrieve the first image in a DIV that have a specific ID or class (maincontent, content, main, wrapper, etc. - it's all in an array) and ignore ads. The goal is to take this image and make a thumbnail with it, pretty much like on Digg and others. I thought everything was working fine until I tried my script with the website Snopes ("http://www.snopes.com/photos/animals/luckycoyote.asp" <- this page more exactly). The source of the first image it gets is: " graphics/luckycoyote1.jpg ". So far, to correct this problem I created a little function that gets the domain name of the given URL and insert it before the IMG's source attribute. So for sites like Snopes.com, it gives me: "http://www.snopes.com/graphics/luckycoyote1.jpg" ... while the real URL for this image is "http://www.snopes.com*/photos/animals/graphics/luckycoyote1.jpg*" (or, more precisely: " http://graphics1.snopes.com/photos/animals/graphics/luckycoyote1.jpg " - note the subdomain here). So my main question is: how can I externally/dynamically retrieve the full URL address of an image ("absolute path") when I am only given the "relative path"? I'm pretty sure this is possible, since when I paste the link in Facebook's "What are you doing?" field for example, it gives me the correct path to the image while on the website, the source of the image is only (example) "image/photo/example.jpg". Thank you for your time.

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  • How can I work out if a date is on or before today?

    - by Yvonne
    My web application consists of library type system where books have due dates. I have the current date displayed on my page, simply by using this: date_default_timezone_set('Europe/London'); $date = date; print $date("d/m/Y"); I have set 'date' as a variable because I'm not sure if it makes a difference when I use it in the IF statement you're about see, on my library books page. On this page, I am simply outputting the due dates of the books, many have dates which have not yet reached todays date, and others which have dates greater than todays date. Basically, all I want is the due date to appear bold (or strong), if it has passed todays date (the system displayed date). This is what I have and thought would work: <? if ($duedate < $date) { echo '<td><strong>'; } else { echo '<td>'; } ?> <?php echo $date('d/m/Y', $timestamp);?></strong></td> I have declared $timestamp as a var which converts the date of default MySQL format to a UK version. Can anyone help me out? I thought this would've been very straight forward!

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  • problem during data fetch

    - by nectar
    here is my code $sql="SELECT * FROM $tbl_name WHERE ownerId='$UserId'"; $result=mysql_query($sql,$link)or die(mysql_error()); $row = mysql_fetch_array($result, MYSQL_ASSOC); <?php while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { echo "<tr>"; echo "<td>".$row['pinId']."</td>"; echo "<td>".$row['usedby']."</td>"; echo "<td>".$row['status']."</td>"; echo "</tr>"; } ?> it is ignoring the first record means if 4 rows are in $row its ignoring the 1st one rest three are coming on page. ownerId is not primary key.

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  • Optimizing near-duplicate value search

    - by GApple
    I'm trying to find near duplicate values in a set of fields in order to allow an administrator to clean them up. There are two criteria that I am matching on One string is wholly contained within the other, and is at least 1/4 of its length The strings have an edit distance less than 5% of the total length of the two strings The Pseudo-PHP code: foreach($values as $value){ foreach($values as $match){ if( ( $value['length'] < $match['length'] && $value['length'] * 4 > $match['length'] && stripos($match['value'], $value['value']) !== false ) || ( $match['length'] < $value['length'] && $match['length'] * 4 > $value['length'] && stripos($value['value'], $match['value']) !== false ) || ( abs($value['length'] - $match['length']) * 20 < ($value['length'] + $match['length']) && 0 < ($match['changes'] = levenshtein($value['value'], $match['value'])) && $match['changes'] * 20 <= ($value['length'] + $match['length']) ) ){ $matches[] = &$match; } } } I've tried to reduce calls to the comparatively expensive stripos and levenshtein functions where possible, which has reduced the execution time quite a bit. However, as an O(n^2) operation this just doesn't scale to the larger sets of values and it seems that a significant amount of the processing time is spent simply iterating through the arrays. Some properties of a few sets of values being operated on Total | Strings | # of matches per string | | Strings | With Matches | Average | Median | Max | Time (s) | --------+--------------+---------+--------+------+----------+ 844 | 413 | 1.8 | 1 | 58 | 140 | 593 | 156 | 1.2 | 1 | 5 | 62 | 272 | 168 | 3.2 | 2 | 26 | 10 | 157 | 47 | 1.5 | 1 | 4 | 3.2 | 106 | 48 | 1.8 | 1 | 8 | 1.3 | 62 | 47 | 2.9 | 2 | 16 | 0.4 | Are there any other things I can do to reduce the time to check criteria, and more importantly are there any ways for me to reduce the number of criteria checks required (for example, by pre-processing the input values), since there is such low selectivity?

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  • Sort MySQL query result by a alphanumeric field

    - by Jason Shultz
    I'm querying a table in a db using php. one of the fields is a column called "rank" and has data like the following: none 1-bronze 2-silver 3-gold ... 10-ambassador 11-president I want to be able to sort the results based on that "rank" column. any results where the field is "none" get excluded, so those don't factor in. As you can already guess, right now the results are coming back like this: 1-bronze 10-ambassador 11-president 2-silver 3-gold Of course, I would like for it to be sorted so it is like the following: 1-bronze 2-silver 3-gold ... 10-ambassador 11-president Right now the query is being returned as an object. I've tried different sort options like natsort, sort, array_multisort but haven't got it to work the way I'm sure it can. I would prefer keeping the results in an object form if possible. I'm passing the data on to a view in the next step. although, it's perfectly acceptable to pass the object to the view and then do the work there. so it's not an issue after all. :) thank you for your help. i'm hoping I'm making sense.

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  • Map Subdomains to Folders Owned/Run by Other Apache/PHP/Cpanel Users

    - by kristofferR
    I run a small service for Norwegian customers where they get automatically installed and configured Wordpress blogs on their own domains ready immediately after payment is finished. It's quite similar to Page.ly and WPEngine, just aimed at Norwegian customers with Norwegian Wordpress, support, billing etc. The backend is WHM/CPanel (Apache, PHP, mySQL), with a script running immediately after payment that installs and configures Wordpress and sends the customer an email with their username and password. Newly registered domains takes some time to propagate though, so for a day or two my customers unfortunately have to use a temporary URL before I can switch them over to their own domains. Right now my system uses mod_userdir ("serverIP/~cpanelusername"). However, it's not an optimal solution. It looks unprofessional, is confusing, and is quite problematic for both my customers and me. I'd rather prefer the temporary URL for their blogs to be "theirdomainwithoutextension.host.no", with "host.no" being a domain I own and served from the same server as the customer sites. I can easily modify the script to create the subdomains on my "host.no"-domain, but how can I seamlessly map the subdomains to folders owned/ran on/by different CPanel/Apache/PHP users?

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  • Recursive function for multidimensional array

    - by moja
    This is my code, and I need your help to understand it. <?php $tree = array( array( 'name' => 'Item-1', 'children' => array()), array('name' => 'Item-2', 'children' => array( array('name' => 'Item-2-1', 'children' => array()), )), array('name' => 'Item-3', 'children' => array( array('name' => 'Item-3-1', 'children' => array()), array('name' => 'Item-3-2', 'children' => array( array('name' => 'Item-3-2-1', 'children' => array()), array('name' => 'Item-3-2-2', 'children' => array()), array('name' => 'Item-3-2-3', 'children' => array( array('name' => 'Item-3-2-3-1', 'children' => array()), )), )), )), ); What i need is one recursive function, which will return all names (name). For example: Item-1 Item-2 Item-2-1 Item-3 Item-3-1 Item-3-2 ........ Thanks for your help.

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  • Batch Inserts And Prepared Query Error

    - by ircmaxell
    Ok, so I need to populate a MS Access database table with results from a MySQL query. That's not hard at all. I've got the program written to where it copies a template .mdb file to a temp name and opens it via odbc. No problem so far. I've noticed that Access does not support batch inserting (VALUES (foo, bar), (second, query), (third query)). So that means I need to execute one query per row (there are potentially hundreds of thousands of rows). Initial performance tests show a rate of around 900 inserts/sec into Access. With our largest data sets, that could mean execution times of minutes (Which isn't the end of the world, but obviously the faster the better). So, I tried testing a prepared statement. But I keep getting an error (Warning: odbc_execute() [function.odbc-execute]: SQL error: [Microsoft][ODBC Microsoft Access Driver]COUNT field incorrect , SQL state 07001 in SQLExecute in D:\....php on line 30). Here's the code I'm using (Line 30 is odbc_execute): $sql = 'INSERT INTO table ([field0], [field1], [field2], [field3], [field4], [field5]) VALUES (?, ?, ?, ?, ?, ?)'; $stmt = odbc_prepare($conn, $sql); for ($i = 200001; $i < 300001; $i++) { $a = array($i, "Field1 $", "Field2 $i", "Field3 $i", "Field4 $i", $i); odbc_execute($stmt, $a); } So my question is two fold. First, is there any idea on why I'm getting that error (I've checked, and the number in the array matches the field list which matches the number of parameter ? markers)? And second, should I even bother with this or just use the straight INSERT statements? Like I said, time isn't critical, but if it's possible, I'd like to get that time as low as possible (Then again, I may be limited by disk throughput, since 900 operations/sec is high already)... Thanks

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  • Pulling Data out of an object in Javascript

    - by PerryCS
    I am having a problem retreiving data out of an object passed back from PHP. I've tried many different ways to access this data and none work. In Firebug I see the following... (it looks nicer in Firebug) - I tried to make this look as close to Firebug as possible results Object { data="{"formName":"form3","formData":"data goes here"}", phpLiveDebug="<...s: 198.91.215.227"} data "{"formName":"form3","formData":"data goes here"}" phpLiveDebug "<...s: 198.91.215.227" I can access phpLiveDebug no problem, but the data portion is an object. I have tried the following... success: function(results) { //$("#formName").val(results.data.formName); //$("#formName").val(results.data[0].formName); //$("#formName").val(results.data[0]); //$("#formName").val(results.data[1]); //$("#formName").val(results.data[0]["formName"]); var tmp = results.data[formName]; alert("!" + tmp + "!"); $("#formName").val(tmp); $("#jqueryPHPDebug").val(results.phpLiveDebug); } This line works in the example above... $("#jqueryPHPDebug").val(results.phpLiveDebug); but... I can't figure out how to get at the data inside the results.data portion... as you can see above, I have been trying different things and more not even listed there. I was really hoping this line would work :) var tmp = results.data[formName]; But it doesn't. So, after many days of reading, tinkering, my solution was to re-write it to return data similar to the phpLiveDebug but then I thought... it's gotta be something simple I'm overlooking... Thank you for your time. Please try and explain why my logic (my horrible attempts at trying to figure out the proper method) above is wrong if you can?

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  • Delete file using a link

    - by user329394
    Hi all, i want to have function like delete file from database by using link instead of button. how can i do that? do i need to use href/unlink or what? Can i do like popup confirmation wther yes or no. i know how to do that, but where should i put the code? this is the part how where system will display all filename and do direct upload. Beside each files, there will be a function for 'Remove': $qry = "SELECT * FROM table1 a, table2 b WHERE b.id = '".$rs[id]."' AND a.ptkid = '".$rs[id]."' "; $sql = get_records_sql($qry); foreach($sql as $rs){ ?> <?echo '<a href="download.php?f='.$rs->faillampiran.'">'. basename($rs->faillampiran).'</a>'; ?><td><?echo '<a href=""> [Remove]</a>';?></td><? ?><br> <? } ?> thankz all

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  • Are multiline queries sql-injection safe?

    - by acmatos
    This might be a stupid question. Or maybe my hacking skills are limited (I don't practice them at all). I have a query that looks like this: <?php $query =<<<eot SELECT table_x.field1, table_x.field2, table_y.*, table_z.field4 FROM ( SELECT ... ) as table_y LEFT JOIN table_x ON table_x.field1 = table_y.field_x LEFT JOIN table_z ON table_z.field1 = table_y.field_z WHERE table_x.field3 = '$something' AND table_z.field4 = '1' AND table_z.field5 = '2' eot; ?> I have a lot of other tests on $something before it gets used, like $something = explode(' ',$something); (which later result in a string) none of them intend to prevent injection but they make it hard for the given injection to get as is to the actual query. However, there are ways. We all know how easy it is to replace a space for something else which is still valid.. So, it's not really a problem to make a potentially harmful piece of SQL reach that $something... But is there any way to comment the rest of the original query string if it is multi-line? I can comment AND table_z.field4 = '1' using ;-- but can't comment the following AND table_z.field5 = '2' Is it possible to open a multi-line comment /* without closing it or something looked like and therefore allow the injection to ignore the multi-line query?

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  • How to check Isavailablity in ajax?

    - by udaya
    Hi This is what i have in my view page <td width=""><input type="text" name="txtUserName" id="txtUserName" /></td> <td><input type="button" name="CheckUsername" id="CheckUsername" value="Check Availablity" onclick="Check_User_Name();"/></td> Onclick of the button the Check_User_Name function in my ajax.js loads This is the Check_User_Name function function Check_User_Name(source) { var UserName = document.getElementById('txtUserName').value; if(window.ActiveXObject) User_Name = new ActiveXObject("Microsoft.XMLHTTP"); else if(window.XMLHttpRequest) User_Name = new XMLHttpRequest(); var URL = newURL+"ssit/system/application/views/ssitAjax.php"; URL = URL +"?CheckUsername="+UserName; User_Name.onreadystatechange = User_Name_Fun; User_Name.open("GET",URL,true); User_Name.send(null); } function User_Name_Fun() { document.getElementById('User_div').innerHTML=User_Name.responseText; } Then I can have the value in echo username then the $result has all the user name Hows can i checkIsavailablity of username from here if(($_GET['CheckUsername']!="") || (isset($_GET['CheckUsername']))) { echo $UserName = $_GET['CheckUsername'];//echo username $_SESSION['state'] = $State; $queryres = "SELECT dUser_name FROM tbl_login WHERE dIsDelete='0'"; $result = mysql_query($queryres,$cn) or die("Selection Query Failed !!!");

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  • Migrating just article contect of Joomla 1.0 to 2.5.x / 3.x?

    - by user2919408
    I have a simple website using Joomla 1.0.15, just having articles in some categories. As i want to install or remove components from admin area, i got : "You are not authorised to view this resource" or something like that. This is uncommon, this site is about 5 years old, and never got error message like that. I think my website is hacked ?? I have set safe_mode = off in php.ini, turn of sh404sef, removing .htaccess file etc ... and it still does not work. Then i try to upgrade to Joomla 2.5.x / 3.x . I found that i must migrate to Joomla 1.5.x first, then from there to 2.5.x. I got problem installing "migration.zip" component in my Joomla 1.0.x (always alert/err message pop up is shown). Is there another way to migrate the website ? May be just get the article section, category, article id and the content of Joomla 1.0.x , then import it to Joomla 2.5.x / 3.x ? I don't need components, modules, mambots (if any) of the old site. How to do it ? Thanks

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  • codeigniter avoiding html div's

    - by rabidmachine9
    Hello there!Is there a proper syntax to avoid div's in codeigniter? I don't really like opening and closing tags all the time... <div class="theForm"> <?php echo form_open('edit/links');//this form uploads echo "Enter the Name: ". form_input('name','name'); echo "Enter the Link: ". form_input('url','url'); echo " ".form_submit('submit', 'Submit'); echo form_close(); if (isset($linksQuery) && count($linksQuery)){ foreach($linksQuery as $link){ echo anchor($link['link'], $link['name'].".", array("class" => "links")); echo form_open('edit/links',array('class' => 'deleteForm')); echo form_hidden('name',$link['name']); echo " ".form_submit('delete','Delete'); echo form_close(); echo br(2); } } ?> </div>

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  • Search for values in nested array

    - by dardub
    I have an array as follows array(2) { ["operator"] => array(2) { ["qty"] => int(2) ["id"] => int(251) } ["accessory209"] => array(2) { ["qty"] => int(1) ["id"] => int(209) } ["accessory211"] => array(2) { ["qty"] => int(1) ["id"] => int(211) } } I'm trying to find a way to verify an id value exists within the array and return bool. I'm trying to figure out a quick way that doesn't require creating a loop. Using the in_array function did not work, and I also read that it is quite slow. In the php manual someone recommended using flip_array() and then isset(), but I can't get it to work for a 2-d array. doing something like if($array['accessory']['id'] == 211) would also work for me, but I need to match all keys containing accessory -- not sure how to do that Anyways, I'm spinning in circles, and could use some help. This seems like it should be easy. Thanks.

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