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  • When running UPDATE ... datetime = NOW(); will all rows updated have the same date/time?

    - by Darryl Hein
    When you run something similar to: UPDATE table SET datetime = NOW(); on a table with 1 000 000 000 records and the query takes 10 seconds to run, will all the rows have the exact same time (minutes and seconds) or will they have different times? In other words, will the time be when the query started or when each row is updated? I'm running MySQL, but I'm thinking this applies to all dbs.

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  • How to handle carriage return with windows batch script?

    - by eric2323223
    Hi, I want to use bat to automate some of my work. It should first look up the value of a certain registry key, and then copy some files to the directory that included in the registry key value. I used reg query command to look up registry, such as: REG QUERY "HKLM\SYSTEM\CurrentControlSet\Control\Session Manager\Environment" /v PROCESSOR_ARCHITECTURE The result seems contains carriage return and I need to remove it, I've tried some solutions but all failed. Could anyone help me?

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  • Msg 102, Level 15, State 1, Line 1 Incorrect syntax near ' '.

    - by sajad
    i am trying to query from a temp table,and i keep getting the message Msg 102, Level 15, State 1, Line 1 Incorrect syntax near ' '. can somebody tell me wats the problem..is it due to convert.. plz help The query is select compid,2, convert(datetime, '01/01/' + CONVERT(char(4),cal_yr) ,101) ,0,  Update_dt, th1, th2, th3_pc , Update_id, Update_dt,1 from #tmp_CTF

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  • Escapeing values in PDO statements

    - by Pardoner
    Doesn't prepare() escape any quotes(') in a PDO statement? For some reason when I do this: $sql = "INSERT INTO sessions (id, name) VALUES (1,'O'brian')"; $query = $this->connection->prepare($sql); $query->execute(); I get this error: Could not insert record SQLSTATE[42000]: [Microsoft][SQL Server Native Client 10.0][SQL Server]Incorrect syntax near 'brian'. How could this be if I'm using prepare()?

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  • php check if record exist.

    - by user329394
    hi all, i found this to check if file exist. is there a way how to check if record exist first? php.net i want to check if record exist first, if exist then do update, else do insert. i do understand how to make a queries for select and insert and i dont have problem with it. if(record exist) { update query} else { insert query}

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  • Modifying MySQL Where Statement Based on Array

    - by Ryan
    Using an array like this: $data = array ( 'host' => 1, 'country' => 'fr', ) I would like to create a MySQL query that uses the values of the array to form its WHERE clause like: SELECT * FROM table WHERE host = 1 and country = 'fr' How can I generate this query string to use with MySQL?

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  • update SMS body, but not Date

    - by everinsearch
    I'm trying to update body of all sms on Android device with getContentResolver().update(Uri.parse("content://sms"), values..... query but after request done, also updates message creation/received time. How i can update message but leave old message date? I have tried send to update query ContentValues values = sms values oject; values.put("body", updatedBody); values.put("date", oldValues.getAsString("date")); but it does not help.

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  • How to differenciate two tables

    - by Nemat
    Hi friends.... I have two tables.I want to get all records from one table that are different from the records in second table. For eg. if we have four records in first table like A,B,C,D and three records in second table thats A,B,C then the answer of query should be D. I have tried "EXCEPT" operator but it doesnt work fine.Kindly help me in writing correct query for the given problem. Any help is appreciated.... Thanks in Advance Nemat

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  • How can I connect PHP 5.1 to Oracle 7?

    - by Travis Beale
    I have been able to query newer Oracle databases using the PHP oci8 extension with the Oracle 10.2 Instant Client. Unfortunately, the Oracle Instant Client seems to be unable to connect to an Oracle 7 database (version 7.3.3 to be precise). Is there a way to query an older Oracle database from PHP?

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  • MYSQL: Udate table column from subquery result

    - by Jhourlad Estrella
    On the Members table are columns "MemberID" and "PointsEarned". I want to update the PointsEarned column from the result of this query: SELECT m.MemberID, m.UserName, ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=2)*10 ) + ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=3)*3 ) + ( (SELECT COUNT(*) FROM ChatMessages as c WHERE c.MemberID=m.MemberID)*.1 ) as PointsEarned FROM Members as m Can anybody tell me how I should do it with a single query? Thanks!

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  • Calculate value from two field in third field

    - by terence6
    I'm trying to create a query, that will calculate sum of products on invoice. I have 3 tables : Product (with product's price) Invoice (with invoice id) Products on invoice (with invoice id, product id and number of particular products) So in my query I take invoice_id (from invoice), price (from product),number of products sold and invoice_id (from products on invoice) and calculate their product in fourth column. I know I sohuld use 'Totals' but how to achieve that ? Model:

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  • session variable values are not being passed between pages

    - by ravi nankani
    hi, i am a little new to php and although i have managed to pass values of session variables before this piece of code is leaving me puzzled <form action="team_reg2.php" method="post" name="form1" class="cent" id="form1"> Team Registration "; print "member$i"; print "\n"; print "\n"; print "Please enter only id\n"; } ? now this will pass via post to team_reg2.php echo " please note your team id is 1 "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } else { $str="select * from $query where ("; for($i=1;$i<=$num;$i++) { $name='mem'.$i; $text="p_id='$_POST[$name]'"; if($i==1) $str=$str.$text; else $str=$str.' or '.$text; } $str=$str.')'; $query2=$str; echo "$str"; // echo "$query2"; $que=mysql_query($query2,$con) or die(mysql_error()); $num=mysql_num_rows($que); if($num!=0) { while($result=mysql_fetch_array($que)) { echo "$result[p_id] is already registered in team $result[t_id]"; } //include("reg_team.html"); } else if($num==0) { //echo $query; $query2="select max(t_id) from $query"; $que=mysql_query($query2,$con) or die(mysql_error()); //echo "$que"; $result=mysql_fetch_array($que); $max=$result['max(t_id)']; $max++; $num=$_SESSION['max_team']; for($i=1;$i<=$num;$i++) { $name='mem'.$i; if($_POST[$name]!="") { $query2="insert into $query values($max,'$_POST[$name]')"; $que=mysql_query($query2,$con); } } echo " please note your team id is $max "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } } ? i have done session_start(); at the beginning of the page itself. The problem is that echoing $_SESSION variables in second file is not printing anything. someone please explain me whats going on. thank you

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  • Php random row help...

    - by Skillman
    I've created some code that will return a random row, (well, all the rows in a random order) But i'm assuming its VERY uneffiecent and is gonna be a problem in a big database... Anyone know of a better way? Here is my current code: $count3 = 1; $count4 = 1; //Civilian stuff... $query = ("SELECT * FROM `*Table Name*` ORDER BY `Id` ASC"); $result = mysql_query($query); while($row = mysql_fetch_array($result)) { $count = $count + 1; $civilianid = $row['Id']; $arrayofids[$count] = $civilianid; //echo $arrayofids[$count]; } while($alldone != true) { $randomnum = (rand()%$count) + 1; //echo $randomnum . "<br>"; //echo $arrayofids[$randomnum] . "<br>"; $currentuserid = $arrayofids[$randomnum]; $count3 += 1; while($count4 < $count3) { $count4 += 1; $currentarrayid = $listdone[$count4]; //echo "<b>" . $currentarrayid . ":" . $currentuserid . "</b> "; if ($currentarrayid == $currentuserid){ $found = true; //echo " '" .$found. "' "; } } if ($found == true) { //Reset array/variables... $count4 = 1; $found = false; } else { $listdone[$count3] = $currentuserid; //echo "<u>" . $count3 .";". $listdone[$count3] . "</u> "; $query = ("SELECT * FROM `*Tablesname*` WHERE Id = '$currentuserid'"); $result = mysql_query($query); $row = mysql_fetch_array($result); $username = $row['Username']; echo $username . "<br>"; $count4 = 1; $amountdone += 1; if ($amountdone == $count) { //$count $alldone = true; } } } Basically it will loop until its gets an id (randomly) that hasnt been chosen yet. -So the last username could take hours :P Is this 'bad' code? :P :(

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  • Parameterizing a SQL IN clause?

    - by Jeff Atwood
    How do I parameterize a query containing an IN clause with a variable number of arguments, like this one? select * from Tags where Name in ('ruby','rails','scruffy','rubyonrails') order by Count desc In this query, the number of arguments could be anywhere from 1 to 5. I would prefer not to use a dedicated stored procedure for this (or XML), but if there is some fancy SQL Server 2008 specific way of doing it elegantly, I am open to that.

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  • Select top/latest 10 in couchdb?

    - by drozzy
    How would I execute a query equivalent to "select top 10" in couch db? For example I have a "schema" like so: title body modified and I want to select the last 10 modified documents. As an added bonus if anyone can come up with a way to do the same only per category. So for: title category body modified return a list of latest 10 documents in each category. I am just wandering if such a query is possible in couchdb.

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  • ORACLE:- 'SELECT ORDER BY ASC' but 'USA' always first.

    - by Robert
    I have to write a drop down query for countries. But USA should always be first. The rest of the countries are in alphabetical order I tried the following query SELECT countries_id ,countries_name FROM get_countries WHERE countries_id = 138 UNION SELECT countries_id ,countries_name FROM get_countries WHERE countries_id != 138 ORDER BY 2 ASC

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  • SQL Select -> product -> comments -> user

    - by user1492716
    thanks for yout time helping on this ;) I'm new to SQL and wish to solve somethign in just one query and i dont know how to do it.- Basically I've a table of products, a table of users and a table of comments, linked by products.id - comments.pid and user.id - comments.uid , i wish to know what is the best practice to create just 1 query and get all products with child comments, including username.

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  • Sum of a summation in mysql

    - by dames
    I have the following query, in the top select statement (sum(l.app_ln_amnt)/count(l.app_ln_amnt)) works well but in the union I want to find the total of (sum(l.app_ln_amnt)/count(l.app_ln_amnt)) query from the top select statement However my solution seems to be off I need some help please select (sum(l.app_ln_amnt)/count(l.app_ln_amnt)), from receipt_history l UNION select SUM(sum(l.app_ln_amnt)/count(l.app_ln_amnt)), from receipt_history l

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  • Trying to pass variable from 1 Function to Another to Put in Array within same Model

    - by Jason Shultz
    Ok, that sounds really confusing. What I’m trying to do is this. I’ve got a function that uploads/resizes photos to the server. It stores the paths in the DB. I need to attach the id of the business to the row of photos. Here’s what I have so far: function get_bus_id() { $userid = $this->tank_auth->get_user_id(); $this->db->select('b.id'); $this->db->from ('business AS b'); $this->db->where ('b.userid', $userid); $query = $this->db->get(); if ($query->num_rows() > 0) { return $query->result_array(); } That get’s the id of the business. Then, I have my upload function which is below: /* Uploads images to the site and adds to the database. */ function do_upload() { $config = array( 'allowed_types' => 'jpg|jpeg|gif|png', 'upload_path' => $this->gallery_path, 'max_size' => 2000 ); $this->load->library('upload', $config); $this->upload->do_upload(); $image_data = $this->upload->data(); $config = array( 'source_image' => $image_data['full_path'], 'new_image' => $this->gallery_path . '/thumbs', 'maintain_ratio' => true, 'width' => 150, 'height' => 100 ); $this->load->library('image_lib', $config); $this->image_lib->resize(); $upload = $this->upload->data(); $bus_id = $this->get_bus_id(); $data = array( 'userid' => $this->tank_auth->get_user_id(), 'thumb' => $this->gallery_path . '/thumbs/' . $upload['file_name'], 'fullsize' => $upload['full_path'], 'busid'=> $bus_id['query'], ); echo var_dump($bus_id); $this->db->insert('photos', $data); } The problem I’m getting is the following: A PHP Error was encountered Severity: Notice Message: Undefined index: id Filename: models/gallery_model.php Line Number: 48 I’ve tried all sorts of ways to get the value over, but my limited knowledge keeps getting in the way. Any help would be really appreciated.

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  • Translate LINQ to sql statement

    - by zielu1
    Hi, I want to translate LINQ expression tree to SQL statement and I don't want to write my own code for this. Example: var query = from c in Customers where c.Country == "UK" && c.City == "London" select c); To SELECT ... FROM Customers AS c WHERE c.Country = "UK" AND c.City = "London" I know DataContext.Log, but I want to use: query.ToSqlStatementString() Thanks

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  • Sql joining a table

    - by benjamin button
    I have a question regarding the Sql Joins. whenever we join two different tables on some fields. what will happen exactly inside oracle which will result in the query output. will there be a temporary table created just for presenting the query output.

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  • MongoDB using NOT and AND together

    - by Stankalank
    I'm trying to negate an $and clause with MongoDB and I'm getting a MongoError: invalid operator: $and message back. Basically what I want to achieve is the following: query = { $not: { $and: [{institution_type:'A'}, {type:'C'}] } } Is this possible to express in a mongo query? Here is a sample collection: { "institution_type" : "A", "type" : "C" } { "institution_type" : "A", "type" : "D" } { "institution_type" : "B", "type" : "C" } { "institution_type" : "B", "type" : "D" } What I want to get back is the following: { "institution_type" : "A", "type" : "D" } { "institution_type" : "B", "type" : "C" } { "institution_type" : "B", "type" : "D" }

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  • how to count NULL categories in one SQL question

    - by grzes
    hi, i have a blog application were Post belongsTo Category and Category hasMany Post Post can have a Category or not - in latter case NULL value is present in Post.category_id field. Now i would like to have following category count with single SQL query category|post_count -------------- PHP | 2 JavaScript | 4 SomeOtherCat | 1 NULL | 3 The clue here is that i also want to count posts without category (NULL row above). Is it posibble with one SQL query?

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