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  • Ajax response seems to be getting lost

    - by Ringo Blancke
    I'm using the ddslick jquery dropdown plugin in conjunction with my Rails app. In view1, I have $('#challenges_dropdown').ddslick({ <snipped> onSelected: function (data) { $.ajax({ url: "/load_data", type: "GET", data: {"id": data.selectedData.value} }); } }); I.e., I make a call to my controller to load_data. The controller receives this correctly and then at the end, makes a call to render a separate view render "data" This view contains a script snippet that needs to run in order to update some elements of my original view. For some reason, this script snippet is just not running. I'm very confused. When I use a regular link with data-remote="true", then the whole process works perfectly. However, when I make an AJAX call, it fails. What's going on?? Thanks! Ringo

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  • $.ajax is not working

    - by Geetha
    Hi All, In my web page there is a textbox to get the scanned barcode value. Once we scan the barcode it has to get details from the database. I am creating the change event for the textbox. Problem: $.ajax is not working. Code: var target = $('#txtBarcode'), val = target.val(); target.change(monitor()); function monitor() { var xx = $('#txtBarcode').val(); $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", data: "{}", url: "HomePage.aspx/SearchProduct", dataType: "json", success: function(data) { alert("Success!!!"); } }); }

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  • JQuery: After adding some AJAX, some of the jquery code no longer works

    - by fwaokda
    Here's a pastebin link to my entire jQuery code. [ http://pastebin.com/w57ma5Gx ] The "Thumbnails" section was working fine before I added the ajax sections. Anyone can help me with why it quit working? And if I need to I can post another question but figured I'd try it here first. Whats a better way of writing the ajax code where it executes once upon loading the page and then every time I click the $("a#next") link afterwards? Right now I just repasted the code outside of the next link and that works, but seems silly to have the same code in two different places like that. Thanks!

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  • Using JQuery Lightbox within AJAX loaded content

    - by James
    Hey. So this is probably a very noob problem but I'm not good enough to fix it. Basically... I have a gallery that I am loading into the page via AJAX. It looks simply like this: <div id="gallery"> <a href="Image1.jpg"><img src="Image1Thumb.jpg" /></a> <a href="Image2.jpg" title=""><img src="Image2Thumb.jpg" /></a> </div> But because it's being loaded in as AJAX content, JQuery/Lightbox is not working and I've no idea how can I get the script to run/recognise this newly loaded content. Thanks! [Note: The JQuery Lightbox I am using.]

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  • IE not triggering jQuery Ajax success

    - by dayosuperstar
    Hello all, I'm working on a script to load some images async using jQuery. Here is a code snippet of the function that loads the images - try{ for(img in imgsArray){ $.ajax({ async: false, type: "get", url:imgsArray[img], success:function(imgFile){ alert("success"); //do something useful }, error:function(XMLHttpRequest,status,error){ //do nothing } });//ajax } } catch(e){ //oops } I have tested this in Firefox, Webkit (Safari,Chrome) and it works. The images are in a folder on the server and I'm using jQuery 1.3. any ideas? Much appreciated.

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  • ajax echo returns javascript code!

    - by StevanSteve
    Hi, i have an ajax call. Php page (A) called by ajax requires some other php page (B). Page "B" is php file looking something like this <html> <head> javascript code </head> <body> PHP Code </body> Inside of "head" tags is javascript code. Now, Page "A" includes page "B", but instead of expected result, it echoes pure javascript code from included page "B"! How to prevent that?

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  • jquery $.ajax call succeeds but returns nothing. (jsonp)

    - by Shawn
    $(document).ready(function() { $('#button').click(function() { try { var json = $.ajax({url : 'http://www.example.com/experimental/service.php', type : 'jsonp', success : function() {alert('success')}}); alert(json); } catch(err) { alert(err.description) } var sjson = JSON.stringify(json); $('#display').html(sjson); }) }) After a button is pressed I get an alert message that says "success" and also one that says undefined, referring to the fact that nothing was returned from the ajax call. I checked the firebug 'net' tab and indeed i get a succesful response from the server of "jsonp1272724228884( {} );" Any ideas?

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  • jquery, ajax, load post result to div

    - by mike
    Hello, I have a form that I need to post and show the result in a div. I'm not having any problems making the ajax call but I can't seem to figure out how to load the result to a div. I have tried: $.ajax({ type: 'POST', data: $('#someForm').serialize(), url: 'http://somedomain.com/my/url', success: function(data) { $('#someDiv').load(data); } }); but it does not seem to work properly. I'm nit sure if this should even work but the result is the the page i'm posting from being loaded into the div and not the url I'm posting to. Any help would be great! Thanks!

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  • How do you send an array as part of an (jquery) ajax request

    - by Ankur
    I tried to send an array as part of an ajax request like this: var query = []; // in between I add some values to 'query' $.ajax({ url: "MyServlet", data: query, dataType: "json", success: function(noOfResults) { alert(noOfResults); } }); } I wanted to see what I get back in the servlet, so I used this line: System.out.println(request.getParameterMap().toString()); Which returned {} suggesting an empty map. Firebug tells me I am getting a 400 bad request error If I send a queryString like attribute=value as the 'data' then everything works fine, so it has to do with not being able to send an array as is. What do I have to do to get that data into the servlet for further processing. I don't want to pull it out and turn it into a queryString in the JS if I can avoid it. EDIT: I used the .serializeArray() (jQuery) function before sending the data. I don't get the 400 but nothing useful is being sent through.

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  • ajax how to read out $_post variable

    - by alex
    Hi, I am trying to filter/search a database with ajax $.ajax({ type: "POST", url: "filterSearch.php", queryString: qry, success: function(data){ alert( "Data Saved: " + data ); $('#searchResult').html(data); // Fill the search results box } }); Now in filterSearch.php i have the following test codes if(isset($_POST['queryString'])) { echo "TEST"; } if($_POST['runquery']==1) { $sql = "SELECT * FROM fs_vacatures WHERE here-the-like-query?"; $msg = $sql; echo $msg; die(); } die(); But nor TEST or the $sql is return in the alert??

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  • Use AJAX to check for a new message

    - by Luke
    Quite simply, I need to alert the end user when they have a new private message. From a combination of research and other opinion, I realise I need to use AJAX for this. The mysql query would be SELECT id FROM tbl_messages WHERE to_viewed = 1 So when someone sends a message, I want an alert to popup on the screen to inform the user without a page reload. I have absolutely no idea what I am doing, but know what I want. Really need help with this, AJAX is definitely something I want to improve as it opens up greater possibilities! Thanks

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  • Show AJAX content after images have loaded

    - by Ben4Himv
    I am developing my own lightbox kind of jquery plugin. Everything works but I want to hide the loaded content until the images have loaded in the browser from the AJAX call. I found a similar post and I am using the following script but the setTimeout function is what reveals the content and not the .load function. Am I trying to achieve the impossible? $.ajax({ url: 'meet/'+ pLoad + '.html', success: function(data) { var imageCount = $(data).filter('img').length; var imagesLoaded = 0; $(data).hide() .appendTo('#zoom_inner') .filter('img') .load( function() { ++imagesLoaded; if (imagesLoaded >= imageCount) { $('#zoom_inner').children().show(); } }); setTimeout( function() { $('#zoom_inner').children().show() }, 5000 ); } });

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  • Jquery ajax and php die()

    - by BizMark
    Hi, I have an IE problem. I am using the jquery ajax method to call a php script. The php script just calls die(). In firefox, the error message is displayed, but in IE the success message is displayed without any data. I would prefer the error function to be called. Is there any way to fix this? I'm guessing my javascript code needs change somehow. Thanks! <?php die() ?> $.ajax({ url: "phps/php.php?id="+the_id, dataType: "json", error: function(){ alert('error'); }, success: function(data){ alert("SUCCESS"); } });

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  • Download content of the page using ajax jquery

    - by niao
    Greetings, how can I download some page content using ajax and jquery: I am doing something like that (2 versions inside one script): $("p").click(function() { $('#result').load('http://google.com'); $.ajax({ url='www.google.com', success: function(data) { $("result").html(data); alert('Load was performed.'); var url = 'www.wp.pl'; $('div#result').load(url); //var content = $.load(url); //alert(content); //$("#result").html("test"); } }); }); but it does not return any content

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  • How come $(this) is undefined after ajax call

    - by JohnnyQ
    I am doing an ajax request when an anchor tag is clicked with an ID set to href. Btw, this anchor tag is dynamically created. <a href="983" class="commentDeleteLink">delete</a> When the anchor tag is clicked the following code is executed: $('.commentDeleteLink').live('click', function(event) { event.preventDefault(); var result = confirm('Proceed?'); if ( result ) { $.ajax({ url: window.config.AJAX_REQUEST, type: "POST", data: { action : 'DELCOMMENT', comment : $('#commentText').val(), comment_id : $(this).attr('href') }, success: function(result) { alert($(this).attr('href')); //$(this).fadeOut(slow); } }); } }); When I tried to display $(this).attr('href') it says it's "undefined". What I really want to do is fadeOut the anchor tag but when I investigated the value of $(this) it is "undefined". What could be wrong with the snippet above?

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  • jQuery ajax get

    - by Happy
    There are many class="item" blocks on the page. For each one there is different var item_link and ajax request. Ajax searches for src attribute of .message img and throws it to var src. $(".item").each(function(){ var item_link = "http://..."; $(this).prepend('<div class="src"></div>'); $.get(item_link, function(data) { var src = $('.message img', data).attr('src'); }); }); How to print var src to <div class="src"></div>? Thanks.

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  • Ajax posting to PHP

    - by JQonfused
    Hi guys, I'm testing a jQuery ajax post method on a local Apache 2.2 server with PHP 5.3 (totally new at this). Here are the files, all in the same folder. html body (jQuery library included in head): <form id="postForm" method="post"> <label for="name">Input Name</label> <input type="text" name="name" id="name" /><br /> <label for="age">Input Age</label> <input type="text" name="age" id="age" /><br /> <input type="submit" value="Submit" id="submitBtn" /> </form> <div id="resultDisplay"></div> <script src="queryRequest.js"></script> queryRequest.js $(document).ready(function(){ $('#s').focus(); $('#postForm').submit(function(){ var name = $('#name').val(); var age = $('#age').val(); var URL = "post.php"; $.ajax({ type:'POST', url: URL, datatype:'json', data:{'name': name ,'age': age}, success: function(data){ $('#resultDisplay').append("Value returned.<br />name: "+data.name+" age: "+data.age); }, error: function() { $('resultDisplay').append("ERROR!") } }); }); }); post.php <?php $name = $_POST['name']; $age = $_POST['age']; $return = array('name' => $name, 'age' => $age); echo json_encode($return); ?> After inputting the two fields and pressing 'Submit', the success method is called, text appended, but the values returned from ajax post are undefined. And then after less than a second, the text fields are emptied, and the text appended to the div is gone. Doesn't seem like it's a page refresh, though, since there's no empty page flash. What's going on here? I'm sure it's a silly mistake but Firebug isn't telling me anything.

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  • call .js file after ajax load

    - by asovgir
    I am trying to apply a .js file to a page I loaded via ajax (since ajax automatically strips the content of all the javascript). var url; var textUrl = 'local/file.js'; $('a').click(function() { url = $(this).attr('href'); $('.secondaryDiv').load(url, function() { $.getScript(textUrl, function(data, textStatus, jqxhr) { console.log(data); //data returned from getScript console.log(textStatus); //return "success" console.log(jqxhr.status); //200 }); }); return false; }); Am I approaching this the right way? I tried everything I could think of and I can't get it to work

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  • Why does JAXB not create a member variable in its generated code when an XML schema base type and subtype have the same element declared in them?

    - by belltower
    I have a question regarding with regard to JAXB generated classes. As you can I see, I have a complex type, DG_PaymentIdentification1, declared in my schema. Its a restriction of PaymentIdentification1. DG_PaymentIdentification1 is also identical to PaymentIdentification1. I also have a type called DG_CreditTransferTransactionInformation10 which has a base type of CreditTransferTransactionInformation10 and is identical to it. I have included the relevant XML schema snippets below. <xs:complexType name="DG_PaymentIdentification1"> <xs:complexContent> <xs:restriction base="PaymentIdentification1"> <xs:sequence> <xs:element name="InstrId" type="DG_Max35Text_REF" minOccurs="0"/> <xs:element name="EndToEndId" type="DG_Max35Text_REF" id="DG-41"/> </xs:sequence> </xs:restriction> </xs:complexContent> </xs:complexType> <xs:complexType name="PaymentIdentification1"> <xs:sequence> <xs:element name="InstrId" type="Max35Text" minOccurs="0"/> <xs:element name="EndToEndId" type="Max35Text"/> </xs:sequence> </xs:complexType> <xs:complexType name="DG_CreditTransferTransactionInformation10"> <xs:complexContent> <xs:restriction base="CreditTransferTransactionInformation10"> <xs:sequence> <xs:element name="PmtId" type="DG_PaymentIdentification1"/> <xs:simpleType name="DG_Max35Text_REF"> <xs:restriction base="DG_NotEmpty35"> <xs:pattern value="[\-A-Za-z0-9\+/\?:\(\)\.,'&#x20;]*"/> </xs:restriction> </xs:simpleType> <xs:simpleType name="Max35Text"> <xs:restriction base="xs:string"> <xs:minLength value="1"/> <xs:maxLength value="35"/> </xs:restriction> </xs:simpleType> JAXB generates the following java class for DG_PaymentIdentification1: @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "DG_CreditTransferTransactionInformDGion10") public class DGCreditTransferTransactionInformation10 extends CreditTransferTransactionInformation10 { } My question is why doesnt the DGCreditTransferTransactionInformation10 generated class have a variable of type DG_PaymentIdentification1 in the generated code? The base class CreditTransferTransactionInformation10 does have a type PaymentIdentification1 declared in it. Is there any way of ensuring that DGCreditTransferTransactionInformation10 will have a DG_PaymentIdentification1 in it?

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  • Writing xml with powershell

    - by alex
    i have a script that get all the info i need about my SharePoint farm : [System.Reflection.Assembly]::LoadWithPartialName("Microsoft.SharePoint") > $null $farm = [Microsoft.SharePoint.Administration.SPFarm]::Local $websvcs = $farm.Services | where -FilterScript {$_.GetType() -eq [Microsoft.SharePoint.Administration.SPWebService]} $webapps = @() foreach ($websvc in $websvcs) { write-output "Web Applications" write-output "" foreach ($webapp in $websvc.WebApplications) { write-output "Webapp Name -->"$webapp.Name write-output "" write-output "Site Collections" write-output "" foreach ($site in $webapp.Sites) { write-output "Site URL --> -->" $site.URL write-output "" write-output "Websites" write-output "" foreach ($web in $site.AllWebs) { write-output "Web URL --> --> -->" $web.URL write-output "" write-output "Lists" write-output "" foreach ($list in $web.Lists) { write-output "List Title --> --> --> -->" $list.Title write-output "" } foreach ($group in $web.Groups) { write-output "Group Name --> --> --> -->" $group.Name write-output "" foreach ($user in $group.Users) { write-output "User Name --> --> --> -->" $user.Name write-output "" } } } } } } i want to make the output to an XML file and then connect the xml file to HTML and make a site of it for manager use how can i do it ? thanks for the help !

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  • Mac - KeyRemap4MacBook - Custom XML

    - by DjRikyx
    I hope someone of you know this powerfull Pref Panel to remap the keyboard.. Since i'm using a PC Keyboard, i wanted to make Screenshot a bit easy to do.. I managed to get working: -Command+Shift+3 to Stamp (full screen screenshot) -Command+Shift+4 to Control+Stamp (Selection Cursor Screenshot) Now i want to remap Shift+Stamp to Command+Shift+4+Space to get Windows Screenshot.. i tried but nothing was working.. Here is my current XML.. i only need to add the last remap! <?xml version="1.0"?> <root> <item> <name>Custom PC Style Screenshot</name> <appendix>Command+Shift_L+4+Space to Shift+F13</appendix> <appendix>Command+Shift_L+4 to Control+F13</appendix> <appendix>Command+Shift_L+3 to F13</appendix> <identifier>private.custom_pc_style_screenshot</identifier> <autogen></autogen> <autogen>--KeyToKey-- KeyCode::F13, VK_CONTROL, KeyCode::KEY_4, ModifierFlag::COMMAND_L | ModifierFlag::SHIFT_L</autogen> <autogen>--KeyToKey-- KeyCode::F13, KeyCode::KEY_3, ModifierFlag::COMMAND_L | ModifierFlag::SHIFT_L</autogen> Hope someone of you can help me out! Thank you

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