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  • jQuery child selector expression

    - by Saiful
    <div id="div"> <div> <!-- first level --> <div> <!-- second level --> <div>1.1</div> <!-- third level --> <div>1.2</div> </div> <div> <div></div> <div>2.2</div> </div> </div> </div> What are the jQuery selector expressions for selecting the followings: 1. div commented by first level 2. divs commented by second level 3. divs commented by third level

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  • SFINAE + sizeof = detect if expression compiles

    - by FredOverflow
    I just found out how to check if operator<< is provided for a type. template<class T> T& lvalue_of_type(); template<class T> T rvalue_of_type(); template<class T> struct is_printable { template<class U> static char test(char(*)[sizeof( lvalue_of_type<std::ostream>() << rvalue_of_type<U>() )]); template<class U> static long test(...); enum { value = 1 == sizeof test<T>(0) }; typedef boost::integral_constant<bool, value> type; }; Is this trick well-known, or have I just won the metaprogramming Nobel prize? ;) EDIT: I made the code simpler to understand and easier to adapt with two global function template declarations lvalue_of_type and rvalue_of_type.

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  • regular expression and escaping

    - by pstanton
    Sorry if this has been asked, my search brought up many off topic posts. I'm trying to convert wildcards from a user defined search string (wildcard is "*") to postgresql like wildcard "%". I'd like to handle escaping so that "%" => "\%" and "\*" => "*" I know i could replace \* with something else prior to replacing * and then swap it back, but i'd prefer not to and instead only convert * using a pattern that selects it when not proceeded by \. String convertWildcard(String like) { like = like.replaceAll("%", "\\%"); like = like.replaceAll("\\*", "%"); return like; } Assert.assertEquals("%", convertWildcard("*")); Assert.assertEquals("\%", convertWildcard("%")); Assert.assertEquals("*", convertWildcard("\*")); // FAIL Assert.assertEquals("a%b", convertWildcard("a*b")); Assert.assertEquals("a\%b", convertWildcard("a%b")); Assert.assertEquals("a*b", convertWildcard("a\*b")); // FAIL ideas welcome.

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  • Regular Expression .net flavor

    - by user1440109
    Dont ask how this works but currently it does ("^\|(.?)\|*$")....kinda. This removes all extra pipes...part one....I have searched all over no anwser yet. I am using VB2011 beta...asp web form......vb coding though! I want to capture special character pipe (|) which is used to seperate words...i.e. car|truck|van|cycle problem is users lead with, trail with, use multiple, and use spaces before and after...i.e. |||car||truck | van || cycle. another example: george bush|micheal jordon|bill gates|steve jobs <-- this would be correct but when I do remove space it takes correct space out. so I want to get rid of whitespace leading, trailing, any space before | and space after | and only allow one pipe (|)....in between alphanumeric of course.

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  • LINQ expression until to break a string

    - by wonea
    Using LINQ I'm looking to break down the following path string[], however I'd like to break it up to the point of the Binn folder. Is there a WHERE UNTIL operator in LINQ? c:\ Program Files\ Microsoft SQL Server\ MSSQL10.SQLEXPRESS\ MSSQL\ Binn\ sqlservr.exe What I'd like todo var words = from word in thepath where UNTIL thepath == "Binn" select word;

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  • Tell smarty to print block as is

    - by Juriy
    Hello guys, I need to inline some javascript code into the Smarty template files and these {ldelim} {rdelim} things are killing me. Is there a way to tell smarty to ignore the markup for a block and just output it as is? Something similar to CDATA blocks in the xml? Just in case: here is how simple javascript looks now: $(function() {ldelim} $( "#slides" ).accessNews({ldelim} speed : "{$speed}", slideBy : 1 {rdelim}); {rdelim}); creepy heh?

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  • Datable.Select sort expression

    - by xyz
    Hi, I have datatable with column name tag and 100 rows of data.I need to filter this table with tag starting with "UNKNOWN". What should my sortexpression for datatable.select be ? I'm trying the following. Datarow[] abc = null; abc = dtTagList.Select(string.format("tag='{0}'","UNKNOWN")) How can I achieve tag startswith 'UNKNOWN' in the above code ?

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  • Unable to retrieve search results from server side : Facebook Graph API usig Python

    - by DjangoRocks
    Hi all, I'm doing some simple Python + FB Graph training on my own, and I faced a weird problem: import time import sys import urllib2 import urllib from json import loads base_url = "https://graph.facebook.com/search?q=" post_id = None post_type = None user_id = None message = None created_time = None def doit(hour): page = 1 search_term = "\"Plastic Planet\"" encoded_search_term = urllib.quote(search_term) print encoded_search_term type="&type=post" url = "%s%s%s" % (base_url,encoded_search_term,type) print url while(1): try: response = urllib2.urlopen(url) except urllib2.HTTPError, e: print e finally: pass content = response.read() content = loads(content) print "==================================" for c in content["data"]: print c print "****************************************" try: content["paging"] print "current URL" print url print "next page!------------" url = content["paging"]["next"] print url except: pass finally: pass """ print "new URL is =======================" print url print "==================================" """ print url What I'm trying to do here is to automatically page through the search results, but trying for content["paging"]["next"] But the weird thing is that no data is returned; i received the following: {"data":[]} Even in the very first loop. But when i copied the URL into a browser, a lot of results were returned. I've also tried a version with my access token and th same thing happens. Can anyone enlighten me? +++++++++++++++++++EDITED and SIMPLIFIED++++++++++++++++++ ok thanks to TryPyPy, here's the simplified and edited version of my previous question: Why is that: import urllib2 url = "https://graph.facebook.com/searchq=%22Plastic+Planet%22&type=post&limit=25&until=2010-12-29T19%3A54%3A56%2B0000" response = urllib2.urlopen(url) print response.read() result in {"data":[]} ? But the same url produces a lot of data in a browser? Anyone? Best Regards.

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  • SSRS Dynamic Returning Dataset Collection Field in Expression

    - by Ray Clark
    I wrote a custom assembly to take a parameter value from the report and return a field from the dataset collection. My assembly returns the correct fields!name.value, but it shows me the string representation of it. How can I get it to resolve as the actual fields!name.value to display the actual data in the dataset? If I enter fields!name.value in manually it works fine showing me the value. If I resolve it with my custom code it display "fields!name.value" to me in the cell.

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  • Ambiguous Evaluation of Lambda Expression on Array

    - by Joe
    I would like to use a lambda that adds one to x if x is equal to zero. I have tried the following expressions: t = map(lambda x: x+1 if x==0 else x, numpy.array) t = map(lambda x: x==0 and x+1 or x, numpy.array) t = numpy.apply_along_axis(lambda x: x+1 if x==0 else x, 0, numpy.array) Each of these expressions returns the following error: ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() My understanding of map() and numpy.apply_along_axis() was that it would take some function and apply it to each value of an array. From the error it seems that the the lambda is being evaluated as x=array, not some value in array. What am I doing wrong? I know that I could write a function to accomplish this but I want to become more familiar with the functional programming aspects of python.

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  • Regular expression: who's greedier?

    - by polygenelubricants
    My primary concern is with the Java flavor, but I'd also appreciate information regarding others. Let's say you have a subpattern like this: (.*)(.*) Not very useful as is, but let's say these two capture groups (say, \1 and \2) are part of a bigger pattern that matches with backreferences to these groups, etc. So both are greedy, in that they try to capture as much as possible, only taking less when they have to. My question is: who's greedier? Does \1 get first priority, giving \2 its share only if it has to? What about: (.*)(.*)(.*) Let's assume that \1 does get first priority. Let's say it got too greedy, and then spit out a character. Who gets it first? Is it always \2 or can it be \3? Let's assume it's \2 that gets \1's rejection. If this still doesn't work, who spits out now? Does \2 spit to \3, or does \1 spit out another to \2 first?

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  • Regular Expression problem

    - by Yatendra Goel
    I want a regex to find the following types of strings: http://anything.abc.tld http://anything.abc.tld/ where abc - abc always remains abc anything - it could be any string tld - it could be any tld (top-level-domain) like .com .net .co.in .co.uk etc. Note: The url must not contain any other thing at the end, means http://anything.abc.tld/xyz is not acceptable.

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  • Why this C# Regular Expression crashes my program?

    - by robert_d
    using System; using System.IO; using System.Net; using System.Text.RegularExpressions; namespace Working { class Program4 { static string errorurl = "http://www.realtor.ca/propertyDetails.aspx?propertyId=8692663"; static void Main(string[] args) { string s; s = getWebpageContent(errorurl); s = removeNewLineCharacters(s); getFields(s); Console.WriteLine("End"); } public static void getFields(string html) { Match m; string fsRE = @"ismeasurement.*?>.*?(\d+).*?sqft"; m = Regex.Match(html, fsRE, RegexOptions.IgnoreCase); } private static string removeNewLineCharacters(string str) { string[] charsToRemove = new string[] { "\n", "\r" }; foreach (string c in charsToRemove) { str = str.Replace(c, ""); } return str; } static string getWebpageContent(string url) { WebClient client = new WebClient(); client.Headers.Add("user-agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705;)"); Stream data = client.OpenRead(url); StreamReader reader = new StreamReader(data); string s = reader.ReadToEnd(); data.Close(); reader.Close(); return s; } } } This program hangs. It runs correctly when I remove RegexOptions.IgnoreCase option or when I remove call to removeNewLineCharacters() function. Could someone tell me what is going on, please?

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  • Regular expression test can't decide between true and false (JavaScript)

    - by nw
    I get this behavior in both Chrome (Developer Tools) and Firefox (Firebug). Note the regex test returns alternating true/false values: > var re = /.*?\bbl.*\bgr.*/gi; undefined > re /.*?\\bbl.*\\bgr.*/gi > re.test("Blue-Green"); true > re.test("Blue-Green"); false > re.test("Blue-Green"); true > re.test("Blue-Green"); false However, testing the same regex as a literal: > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true I can't explain this and it's making debugging very difficult. Can anyone explain this behavior?

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  • Perl Regular expression remove double tabs, line breaks, white spaces

    - by Scoox
    Hi guys, I want to write a perl script that removes double tabs, line breaks and white spaces. What I have so far is: $txt=~s/\r//gs; $txt=~s/ +/ /gs; $txt=~s/\t+/\t/gs; $txt=~s/[\t\n]*\n/\n/gs; $txt=~s/\n+/\n/gs; But, 1. It's not beautiful. Should be possible to do that with far less regexps. 2. It just doesn't work and I really do not know why. It leaves some double tabs, white spaces and empty lines (i.e. lines with only a tab or whitespace) I could solve it with a while, but that is very slow and ugly. Any suggestions?

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  • Why this java application print "true"?

    - by user292084
    This is my first Class Hello.java public class Hello { String name = ""; } This is my second Class Test1.java public class Test1 { public static void main(String[] args) { Hello h = new Hello(); Test1 t = new Test1(); t.build(h); System.out.println((h.name)); } void build(Hello h){ h.name = "me"; } } When I run Test1.java, it prints "me". I think I understand, because of "reference transfer". This is my third Class Test2.java public class Test2 { public static void main(String[] args) { Hello h = null; Test2 t = new Test2(); t.build(h); System.out.println(((h == null))); } void build(Hello h){ h = new Hello(); } } When I run Test2.java, it prints "true", why ? Is it "reference transfer" no longer? I am confused.

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  • Regular Expression Sanitize (PHP)

    - by atif089
    Hello, I would like to sanitize a string in to a URL so this is what I basically need. Everything must be removed except alphanumeric characters and spaces and dashed. Spaces should be converter into dashes. Eg. This, is the URL! must return this-is-the-url Thanks

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  • .Net Regular Expression

    - by xzerox
    Alright so I want to grab the information on a website thats between [usernames] and [/usernames] I know how to get the string but how would I use regex to only have the information in the middle. Remember I am going to be having more then one thing on the page.

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  • Find a regular expression that matches a string?

    - by Mirai
    I need a model for finding all of the regular expressions that would match a particular string. Basically, I need an algorithm for doing what I do to generate a regex search string from some pattern. My purpose for this to create a list of potential regular expressions from a selection of text and order that list from least specific (i.e. string of characters with abitrary length) to most specific (i.e. the string itself) to be used in text editor.

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