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  • Content-disposition:inline header won't show images inline?

    - by hamstar
    I'm trying to show an image inline on a page. It is being served by a codeigniter controller. class Asset extends MY_Controller { function index( $folder, $file ) { $asset = "assets/$folder/$file"; if ( !file_exists( $asset ) ) { show_404(); return; } switch ( $folder ) { case 'css': header('Content-type: text/css'); break; case 'js': header('Content-type: text/javascript'); break; case 'images': $ext = substr( $file, strrpos($file, '.') ); switch ( $ext ) { case 'jpg': $ext = 'jpeg'; break; case 'svg': $ext = 'svg+xml'; break; } header('Content-Disposition: inline'); header('Content-type: image/'.$ext); } readfile( $asset ); } } When I load a image in Chrome of FF its pops up the download window. I know when the browser can't display the content inline it will force a download anyway, but these are PNG and GIF images which display in the browser fine otherwise. In IE it doesn't force a download but it displays the image in ASCII. If I comment out the entire image case it FF and Chrome both display the ASCII but not the image. I thought setting the content type would allow FF and Chrome to show the actual image, and also allow the location to be used as an src. The javascript and css shows fine of course. Anyone got any ideas how I can make the images show properly? Thanks :)

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  • jQuery form duplicate email validation on exit

    - by Zach Girod
    I have a site and I am using this plugin for validation in the registration process. I have seen sites where when you exit the email address field, it goes out and checks to see if the email address exists before you hits the submit button. I know this is ajax but I cannot figure it out. How do you validate if an email address (or any field) already exists before the users submits the form?

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  • how to sort a multidemensional array by an inner key

    - by Derek Vance
    i have this enormous array that i am pulling from an API for BattleField Bad Company 2, and the soldier stats can be pulled as a multi dimensional array with an inner array for each soldier, however the API sormats it sorting the soldiers by name alphabetically, i want to sort them by rank (which is just another key within that soldiers array). ive been trying to figure this out for days, anyone have any ideas? (ie sort the array by $arr[players][][rank] here is a bit of the array Array ( [players] = Array ( [0] = Array ( [name] = bigjay517 [rank] = 29 [rank_name] = SECOND LIEUTENANT II [veteran] = 0 [score] = 979440 [level] = 169 [kills] = 4134 [deaths] = 3813 [time] = 292457.42 [elo] = 319.297 [form] = 1 [date_lastupdate] = 2010-03-30T14:06:20+02:00 [count_updates] = 13 [general] = Array ( [accuracy] = 0.332 [dogr] = 86 [dogt] = 166 [elo0] = 309.104 [elo1] = 230.849 [games] = 384 [goldedition] = 0 [losses] = 161 [sc_assault] = 146333 [sc_award] = 567190 [sc_bonus] = 35305 [sc_demo] = 96961 [sc_general] = 264700 [sc_objective] = 54740 [sc_recon] = 54202 [sc_squad] = 53210 [sc_support] = 70194 [sc_team] = 21215 [sc_vehicle] = 44560 [slevel] = 0 [spm] = 0 [spm0] = 0 [spm1] = 0 [srank] = 0 [sveteran] = 0 [teamkills] = 67 [udogt] = 0 [wins] = 223 )

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  • SQL Query with ORDER BY Part 2

    - by Brett
    Hi SQL'ers, This is a followup question to: SQL Query with ORDER BY But I think the SQL logic is going to be quite different, so I am posting it as separate question. I am trying to extend my sql SELECT query it and having some trouble: I have the table: id type radius ------------------------- 1 type1 0.25 2 type2 0.59 3 type1 0.26 4 type1 0.78 5 type3 0.12 6 type2 0.45 7 type3 0.22 8 type3 0.98 and I am trying to learn how to SELECT the second smallest radius for each given type. So the returned recordset should look like: id type radius ------------------------- 3 type1 0.26 2 type2 0.59 7 type3 0.22 (Note: in the referenced question, I was looking for the lowest radius, not the second lowest radius). I am assuming I have to use LIMIT and OFFSET, but if I use the MIN() won't that return a distinct record containing the minimum radius? Does anyone have any thoughts on how to attack this? Many thanks, Brett

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  • Symfony Basic API Http Authentication

    - by Daniel Hertz
    Can someone point me in the right direction in regards to making an api use basic http authentication? I am creating a restful api with symfony but would like to require users to be logged in to get certain data. I would also like many of these methods be dependent on the the username in the authentication process in order to get some of the data (using the username from the credentials to get all of a users friends) Thanks!

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  • ActiveRecord + CodeIgniter - Return single value from query, not in array form.

    - by txmail
    Say you construct an activerecord query that will always just return a single value, how do you just address that single value instead of getting an array in return? For instance I am using an ActiveRecord query to return the SUM of a single column, it will only return this one single SUM, instead of having to parse the array is there a way to assign the value as a function return equal to that value instead of getting an array?

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  • login form using ajax, to submit without refreshing

    - by Brad
    I am using this tutorial to create a login form http://www.ryancoughlin.com/2008/11/04/use-jquery-to-submit-form/ It authenticates against w/ our ldap server. What I am having a problem with is the line success: function(){ $('form#submit').hide(function(){$('div.success').fadeIn();}); It runs success even though we don't even know if the username and password binded successfully. Is there a way to only run success if the username and password posted was binded successfully?

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  • How to pass variable value to gpg commands

    - by trainee
    $importkey = system('gpg --import newkey.asc . $username'); need to pass the file name as a variable.so that file name with its contents can be import in gnupg keyring. $gpg = system('gpg --recipient userid --output filename --armor --encrypt filename to encrypt', $retvalue); how can i pass the recipient email id(userid) and the filename as variable to gpg commands thanks!

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  • grep_replace: unknown modifier

    - by tic
    Let assume that $body is equal to something that does not interest me <!-- start --> some html code <!-- end --> something that does not interest me If I use $body=preg_replace("(.*)<!-- start -->(.*)<!-- end -->(.*)","$2",$body); I obtain: Warning: preg_replace() [function.preg-replace]: Unknown modifier '<' How have I to correct?

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  • Can I use this technique to provide free email service for my users?

    - by Naughty.Coder
    I'll let users register their [email protected] ,,, they enter their members area where they can : 1- send emails ( easy to do) 2- receive emails .. for receiving emails , I'll use a catch all email account , read the email and figure to whom it's sent (username), and then I save it on the database with userid of the username who has registerd ! Do I miss something here ... is it really this simple (if I don't have an email server) ?

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  • Integrating Simple Machines Forum in my custom membership site - login not working?

    - by Ali
    Hi guys I'm trying to integrate simple machines forum into my custom made membership website. I'm using the SMF API which is available here at http://download.simplemachines.org/?tools. The thing is that its working on my localhost testing server - however on my online server where the system is hosted - its not working. I have set it up so that when the user log into my own custom CMS membership site, he/she is logged in automatically to his/her corresponding account on the forum. However it works on my localhost but online its not working at all.. I log into my site and then browse to the forum to find out I havent been logged in there :( - I think its not creating the cookies or registering the session.. where should I look here. Please do help.

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  • How te execute with /bin/false shell

    - by Amar
    Hello I am trying to setup per-user fastcgi scripts that will run each on different port and with different user. Here is example of my script: #!/bin/bash BIND=127.0.0.1:9001 USER=user PHP_FCGI_CHILDREN=2 PHP_FCGI_MAX_REQUESTS=10000 etc... However, if I add user with /bin/false (which I want, since this is about to be something like shared hosting and I dont want users to have shell access), the script is run'd under 1001, 1002 'user' which, as I googled, might be security hole. My question is: Is it possible to allow user(s) execute shell scripts but disable them to log in via SSH ? Thank you

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  • multiple polls with email submit function

    - by Chris Mousdale
    I want to add a 4 sets of polls that each have around 4 radio buttons each for answers - then i would like to add an 'enter your email address' field below these polls. Finally I would like the submit button after the email field to 'submit' the data from the polls and the email address entered - so only one submit button. Just to make things even better, I would like some form of validation, that will not pass the form unless all 4 polls have a radio button pressed and a valid email. All this is then to go into a MySQL database. I have the email validation bit nailed - so thats fine.. it's the multiple polls bit thats getting me - I cannot get it to work?! Do i have to effectively add 5 forms? Any help would be greatly appreciated.

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  • How to Update Twitter profile picture using twitter api and data:image/gif;base64 ??

    - by Nok Imchen
    iVBORw0KGgoAAAANSUhEUgAAAAoAAAAKCAYAAACNMs+9AAAABGdBTUEAALGPC/xhBQAAAAlwSFlzAAALEwAACxMBAJqcGAAAAAd0SU1FB9YGARc5KB0XV+IAAAAddEVYdENvbW1lbnQAQ3JlYXRlZCB3aXRoIFRoZSBHSU1Q72QlbgAAAF1JREFUGNO9zL0NglAAxPEfdLTs4BZM4DIO4C7OwQg2JoQ9LE1exdlYvBBeZ7jqch9//q1uH4TLzw4d6+ErXMMcXuHWxId3KOETnnXXV6MJpcq2MLaI97CER3N0vr4MkhoXe0rZigAAAABJRU5ErkJggg== The above data is a picture in data:image/png;base64, format. Is it possible to update twitter profile picture without give the path of the image ( like http://....com) but by give the image data in the above format ???

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  • Booking form works but does not give feedback

    - by Naim
    I have a form where people can book seats for a given event. It's actually a WordPress plugin. When someone sends his booking, email notifications are sent properly and the event booking status is updated accordingly. The issue is that the booking form does not give any feedback whatsoever. Once you hit "book now", the graphic keeps loading and no feedback is ever displayed like for instance "booking sent successfully" or "there are errors in your form", even though the booking is saved correctly with both sides notified by email. I guess it's a JavaScript issue,Firebug console is not showing any error... So here is the code source of the booking form : Also please experience the issue live Here username: tester password: testsa Thanks! $('#em-booking-form').submit( function(e){ e.preventDefault(); var em_booking_doing_ajax = false; $.ajax({ url: EM.bookingajaxurl, data:$('#em-booking-form').serializeArray(), dataType: 'jsonp', type:'post', beforeSend: function(formData, jqForm, options) { if(em_booking_doing_ajax){ alert(EM.bookingInProgress); return false; } em_booking_doing_ajax = true; $('.em-booking-message').remove(); $('#em-booking').append('<div id="em-loading"></div>'); }, success : function(response, statusText, xhr, $form) { $('#em-loading').remove(); $('.em-booking-message').remove(); $('.em-booking-message').remove(); //show error or success message if(response.result){ $('<div class="em-booking-message-success em-booking-message">'+response.message+'</div>').insertBefore('#em-booking-form'); $('#em-booking-form').hide(); $('.em-booking-login').hide(); $(document).trigger('em_booking_success', [response]); }else{ if( response.errors != null ){ if( $.isArray(response.errors) && response.errors.length > 0 ){ var error_msg; response.errors.each(function(i, el){ error_msg = error_msg + el; }); $('<div class="em-booking-message-error em-booking-message">'+error_msg.errors+'</div>').insertBefore('#em-booking-form'); }else{ $('<div class="em-booking-message-error em-booking-message">'+response.errors+'</div>').insertBefore('#em-booking-form'); } }else{ $('<div class="em-booking-message-error em-booking-message">'+response.message+'</div>').insertBefore('#em-booking-form'); } } $('html, body').animate({ scrollTop: $("#em-booking").first().offset().top - 50 }); //sends user back to top of form //run extra actions after showing the message here if( response.gateway != null ){ $(document).trigger('em_booking_gateway_add_'+response.gateway, [response]); } if( !response.result && typeof Recaptcha != 'undefined'){ Recaptcha.reload(); } }, complete : function(){ em_booking_doing_ajax = false; $('#em-loading').remove(); } }); return false; });

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  • Google Maps Marker Click Event

    - by Mike
    I'd like to populate a google map with several markers. When the user clicks on a marker I would like it to send the user to a different webpage which is designated for that location. (for example: lets say the markers represent homes, when you click on a marker it takes you to a page with more information about the home) What is the simplest way to do this?

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  • zend_form ViewScript decorator / passing arguments

    - by timpone
    I have a form that is extend from Zend_Form. I am placing the form into a ViewScript decorator like this: $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml')))); I'd like to pass in a variable to this ViewScript but am not sure how this could be done. Since the partial renders out as a Zend_View (allowing $this-app_store_icon for rendering), it seems like there should be a way to pass variables to be rendered. I tried the following but to no avail. $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml'),array('app_store_picon'=>$current_app_store_picon)))); Any help on how to get this done would be appreciated. thanks

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  • Merge entries in CakePHP

    - by Andrea
    Let's say I have a Model, for example User, and I want to merge two instances of this Model, say merge User2 into User1. Explicitly this is what I mean: If a field is already filled in User1, it should remain the same If a field is missing in User1 but is present in User2, it should be copied If SomeModel BelongsTo User, every instance of SomeModel pointing to User2 should be modified to point to User1 Same if SomeModel HasAndBelongsToMany User If SomeModel HasMany User, and SomeModel1 Has User2 but no other instance Has User1, it should be modified so that SomeModel1 has User1 instead If SomeModel HasMany User, SomeModel1 Has User1 and SomeModel2 Has User2... well, I'm not sure here, I guess the only solution is to discard SomeModel2, since User1 can BelongTo only one SomeModel. Finally User2 should be removed. Is there a way to automate this? Maybe a Behaviour? If not, I may consider creating it, since I will need it a lot.

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  • Lightbox image / link URL

    - by GSTAR
    Basically I have a slightly non-standard implementation of FancyBox. By default you have to include a link to the large version of the image so that the Lightbox can display it. However, in my implementation, the image link URLs point to a script rather than directly to the image file. So for example, instead of: <a href="mysite/images/myimage.jpg" rel="gallery"> I have: <a href="mysite/photos/view/abc123" rel="gallery"> The above URL points to a function: public function actionPhotos($view) { $photo=Photo::model()->find('name=:name', array(':name'=>$view)); if(!empty($photo)) { $this->renderPartial('_photo', array('photo'=>$photo, true)); } } The "$this-renderPartial()" bit simply calls a layout file which includes a standard HTML tag to output. Now when the user clicks on a thumbnail, the above function is called and the large image is displayed in the Lightbox. Now if the user right clicks on the thumbnail and selects "open in new tab/window" then the image is displayed in the browser as per normal, i.e. just the image. I want to change this so that it displays the image within a layout. In the above code I can include the following and put it in an IF statement: $this->render('photos', array('photo'=>$photo)); This will call the layout file "photos" which contains the layout to display the image in. I have a specific limitation for this - the image URL must remain the same, i.e. no additional GET variables in the URL. However if we can pass in a GET variable in the background then that is OK. I will most likely need to change my function above so that it calls a different file for this functionality. EDIT: To demonstrate exactly what I am trying to do, check out the following: http://www.starnow.co.uk/KimberleyMarren Go to the photos tab and hover over a thumbnail - note the URL. Click the thumbnail and it will open up in the Lightbox. Next right click on that same thumbnail and select "open in new tab/new window". You will notice that the image is now displayed in a layout. So that same URL is used for displaying the image in the Lightbox and on its own page. The way StarNow have done this is using some crazy long JavaScript functionality, which I'm not too keen on replicating.

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  • Why can't Doctrine retrieve my model data?

    - by scottm
    So, I'm trying to use Doctrine to retrieve some data. I have some basic code like this: $conn = Doctrine_Manager::connection(CONNECTION_STRING); $site = Doctrine_Core::getTable('Site')->find('00024'); echo $site->SiteName; However, this keeps throwing a SQL error that 'column siteid does not exist'. When I look at the exception the SQL query is this (you can see the error is that the inner_tbl alias for siteid is set to s__siteid, so querying inner_tabl.siteid is what's broken): SELECT TOP 1 [inner_tbl].[siteid] AS [s__siteid] FROM (SELECT TOP 1 [s].[siteid] AS [s__siteid], [s].[name] AS [s__name], [s].[address] AS [s__address], [s].[city] AS [s__city], [s].[zip] AS [s__zip], [s].[state] AS [s__state], [s].[region] AS [s__region], [s].[callprocessor] AS [s__callprocessor], [s].[active] AS [s__active], [s].[dateadded] AS [s__dateadded] FROM [Sites] [s] WHERE ([s].[siteid] = '00024') ) AS [inner_tbl] Why is the query being generated this way? Could it be the way the Yaml schema is laid out? Site: connection: 0 tableName: Sites columns: siteid: type: string(5) fixed: true unsigned: false primary: true autoincrement: false name: type: string(300) fixed: false unsigned: false notnull: true primary: false autoincrement: false address: type: string(100) fixed: false unsigned: false notnull: false primary: false autoincrement: false city: type: string(100) fixed: false unsigned: false notnull: false primary: false autoincrement: false zip: type: string(5) fixed: false unsigned: false notnull: false primary: false autoincrement: false state: type: string(2) fixed: true unsigned: false notnull: true primary: false autoincrement: false region: type: integer(4) fixed: false unsigned: false notnull: true default: (5) primary: false autoincrement: false callprocessor: type: integer(4) fixed: false unsigned: false notnull: true primary: false autoincrement: false active: type: integer(1) fixed: false unsigned: false notnull: true primary: false autoincrement: false dateadded: type: timestamp(16) fixed: false unsigned: false notnull: true default: (getdate()) primary: false autoincrement: false

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  • SQL Query Not Functioning - No Error Message

    - by gamerzfuse
    // Write the data to the database $query = "INSERT INTO staff (name, lastname, username, password, position, department, birthmonth, birthday, birthyear, location, phone, email, street, city, state, country, zip, tags, photo) VALUES ('$name', '$lastname', '$username', '$password', '$position', '$department', '$birthmonth', '$birthday', '$birthyear', '$location', '$phone', '$email', '$street', '$city', '$state', '$country', '$zip', '$tags', '$photo')"; mysql_query($query); var_dump($query); echo '<p>' . $name . ' has been added to the Employee Directory.</p>'; if (!$query) { die('Invalid query: ' . mysql_error()); } Can someone tell me why the above code produced: string(332) "INSERT INTO staff (name, lastname, username, password, position, department, birthmonth, birthday, birthyear, location, phone, email, street, city, state, country, zip, tags, photo) VALUES ('Craig', 'Hooghiem', 'sdf', 'sdf', 'sdf', 'sdf', '01', '01', 'sdf', 'sdf', '', 'sdf', 'sdf', 'sd', 'sdf', 'sdf', 'sd', 'sdg', 'leftround.gif')" Craig has been added to the Employee Directory. But does not actually add anything into the database table "staff" ? I must be missing something obvious here.

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  • Zend Form: How to pass parameters into the constructor?

    - by Andrew
    I'm trying to test my form. It will be constructing other objects, so I need a way to mock them. I tried passing them into the constructor... class Form_Event extends Zend_Form { public function __construct($options = null, $regionMapper = null) { $this->_regionMapper = $regionMapper; parent::__construct($options); } ...but I get an exception: Zend_Form_Exception: Only form elements and groups may be overloaded; variable of type "Mock_Model_RegionMapper_b19e528a" provided What am I doing wrong?

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