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  • Drawing widgets (such as buttons) over QGraphicsView

    - by Aditya Bhatt
    How do I draw interactive widgets such as QButtons and Line Edits over a QGraphicsView? For ex, I have selected a region over an image in an image editing app which displays an image with QGraphicsView, and I want to annotate this region with a name. So I want to have a Line edit and two buttons (Cross and Tick) below this rectangular selection. How do I draw these? Sample code would be cool!

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  • error C2143: syntax error : missing ')' before 'constant

    - by user350217
    I keep getting this error on my project and i cant figure it out! please help! error C2143: syntax error : missing ')' before 'constant' the line is: while (selection == ('a','b','c', 'd', 'e', 'f', 'g', 'h', 'i','A','B' 'C', 'D', 'E', 'F', 'G', 'H', 'I'); also i know there is an easier way to write that line out but im not sure how i can do it. im a beginner at this so can any of you pros edit this line for me!

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  • C# mvc 3 using selectlist with selected value in view

    - by Rob
    I'm working on a MVC3 web application. I want a list of categories shown when editing a blo from whe applications managements system. In my viewmodel i've got the following property defined for a list of selectlistitems for categories. /// <summary> /// The List of categories /// </summary> [Display(Name = "Categorie")] public IEnumerable<SelectListItem> Categories { get; set; } The next step, my controller contains the following edit action where the list of selectlistitems is filled from the database. public ActionResult Edit(Guid id) { var blogToEdit = _blogService.First(x => x.Id.Equals(id)); var listOfCategories = _categorieService.GetAll(); var selectList = listOfCategories.Select(x =>new SelectListItem{Text = x.Name, Value = x.Id.ToString(), Selected = x.Id.Equals(blogToEdit.Category.Id)}).ToList(); selectList.Insert(0, new SelectListItem{Text = Messages.SelectAnItem, Value = Messages.SelectAnItem}); var viewModel = new BlogModel { BlogId = blogToEdit.Id, Active = blogToEdit.Actief, Content = blogToEdit.Text, Title = blogToEdit.Titel, Categories = selectList //at this point i see the expected item being selected //Categories = new IEnumerable<SelectListItem>(listOfCategories, "Id", "Naam", blogToEdit.CategorieId) }; return View(viewModel); } When i set a breakpoint just before the view is being returned, i see that the selectlist is filled as i expected. So at this point everything seems to be okay. The viewmodel is filled entirely correct. Then in my view (i'm using Razor) i've got the following two rules which are supposed to render the selectlist for me. @Html.LabelFor(m => m.Categories) @Html.DropDownListFor(model=>model.Categories, Model.Categories, Model.CategoryId) @Html.ValidationMessageFor(m => m.Categories) When I run the code and open the view to edit my blog, I can see all the correct data. Also the selectlist is rendered correctly, but the item i want to be selected lost it's selection. How can this be? Until the point the viewmodel is being returned with the view everything is okay. But when i view the webpage in the browser, the selectlist is there only with out the correct selection. What am I missing here? Or doing wrong?

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  • PHP edit unique row in table

    - by Robert
    I currently have a PHP form that uses AJAX to connect to MySQL and display records matching a user's selection (http://stackoverflow.com/questions/2593317/ajax-display-mysql-data-with-value-from-multiple-select-boxes) As well as displaying the data, I also place an 'Edit' button next to each result which displays a form where the data can be edited. My problem is editing unique records since currently I only use the selected values for 'name' and 'age' to find the record. If two (or more) records share the same name and age, I am only able to edit the first result.

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  • changing cell background color in qt

    - by Moayyad Yaghi
    hello .. i'm new to pyqt , and i'm still facing some newbie problems :D i have a QTableWidget that is item delegated on a QChoice control ( hope i said it right ) i need to have the cell background color changes whenever a user change the choice control selection briefly: how to change a cell background color in a table widget ?? i use pyqt4 and python 2.6 thanx in advance

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  • selecting among duplicated rows in VBA _updated

    - by Elaine Kuo
    I wanna select one row of each duplicated SIDs in a field below. (an attribute table of a shape file) The priority is R S = I 0 Therefore, among SID 87, FID1 will be selected. (SID 88, STATUS will be S+I) (SID 89, FID 6 will be chosen) (SID 90, deleting FID 9 or 10) Please kindly advise VBA cord to run the selection and thanks. FID SID STATUS 1 87 R 2 87 O 3 88 I 4 88 S 5 89 I 6 89 R 7 89 I 8 89 S 9 90 S 10 90 S

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  • Django admin breaking with non-default primary_key for model with a m2m relationship ?

    - by Gj
    I have a simple Post model with a m2m field to a Tag model. The Tag had for some reason to use a non default primary key. Inside the admin page for a Post, the labels for the multiple selection field for Tags appear, but not the input field itself. I also tried using the filter_horizontal for the tags, but still only the labels appear without the actual field. Any ideas why it breaks and/or workarounds? Thanks!

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  • How does Content-Aware fill work?

    - by CiscoIPPhone
    The upcoming version of Photoshop a feature called Content-Aware fill. This feature will fill a selection of an image based on the surrounding image - to the point it can generate bushes and clouds while being seamless with the surrounding image. See http://www.youtube.com/watch?v=NH0aEp1oDOI for a preview of the Photoshop feature I'm talking about. My question is: How does this feature work algorithmically?

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  • Creating a table with an initial element selected

    - by Tony
    I want to create a table which displays in each row a set of data, in addition to a radio button for possible selection. This can be achieved easily by using a simple table model class which extends the DefaultTableModel and a cell renderer and editor class which implements the TableCellRenderer and TableCellEditor interfaces respectively. What I really couldn't manage to do is to make the table to display initially one of the elements (rows) initially selected. It seems straightforward but it isn't...does anybody have a clue about it?

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  • Picture gallery with selected picture zoomed and bright

    - by Epoch
    I am trying to create a picture gallery in android, where picture in selection (in gallery) will be bigger in size, glow a little bit. Where as pictures not selected will be dull, and smaller in size. I tried gallery.setUnselectedAlpha() function to make images unselected dull, but it is not working. How to achieve the effect, please help.

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  • Joda Time cannot subtract one hour

    - by Leoa
    In my android program, I have a spinner that allows the user to select different times. Each selection is processed with Joda time to subtract the minutes. It works fine for minutes 0 to 59 and 61 and greater. However, when 60 minutes is subtracted, the time is not updated, and the original time is shown. How do I get Joda time to subtract 60 minutes? Spinner: public class MyOnItemSelectedListener implements OnItemSelectedListener { public void onItemSelected(AdapterView<?> parent, View view, int pos, long id1) { String mins = parent.getItemAtPosition(pos).toString(); int intmins=0; // process user's selection of alert time if(mins.equals("5 minutes")){intmins = 5;} if(mins.equals("10 minutes")){intmins = 10;} if(mins.equals("20 minutes")){intmins = 20;} if(mins.equals("30 minutes")){intmins = 30;} if(mins.equals("40 minutes")){intmins = 40;} if(mins.equals("50 minutes")){intmins = 50;} if(mins.equals("60 minutes")){intmins = 60;} if(mins.equals("120 minutes")){intmins = 120;} String stringMinutes=""+intmins; setAlarm(intmins, stringMinutes); } else { } public void onNothingSelected(AdapterView parent) { mLocationDisplay.setText(" " + location); } } public void setAlarm(int intmins, String mins) { // based alarm time on start time of event. TODO get info from database. String currentDate; SimpleDateFormat myFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss"); Date date1 = null; DateTime dt; currentDate = eventdate + " " + startTimeMilitary;// startTimeMilitary; try { date1 = myFormat.parse(currentDate); } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } dt = new DateTime(date1); long dateInMillis = dt.getMillis(); String sDateInMillis = Long.toString(dateInMillis); // subtract the selected time from the event's start time String newAlertTime = subtractTime(dt, intmins); newAlertTime = subtractTime(dt, intmins); //......}

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  • How to play songs in iPhone from server ?

    - by hib
    Hello all, In my current application I want to show a songs list in table view which is pretty easy but on selection of one of the songs it should be played in media player . How can I do so . Provide me if anyone have good tutorial or example link

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  • selecting row among duplicated ones in VBA

    - by Elaine Kuo
    ArcGIS 9.3 Arcobject I wanna select one row of each duplicated SIDs in a field below. (an attribute table of a shape file) The priority is R S = I 0 Therefore, among SID 87, FID1 will be selected. (SID 88, STATUS will be S+I) (SID 89, FID 6 will be chosen) Please kindly advise VBA cord to run the selection and thanks. FID SID STATUS 1 87 R 2 87 O 3 88 I 4 88 S 5 89 I 6 89 R 7 89 I 8 89 S

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  • How can I prevent ListBox from selecting an item when I right-click it?

    - by chaiguy
    The tricky part is that each item has a ContextMenu that I still want to open when it is right-clicked (I just don't want it selecting it). In fact, if it makes things any easier, I don't want any automatic selection at all, so if there's some way I can disable it entirely that would be just fine. I'm thinking of just switching to an ItemsControl actually, so long as I can get virtualization and scrolling to work with it.

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  • C# Help For Adding Radio Button For MenuStrip.

    - by Gayan J
    Im a beginner for C# language.So i need a help from who genius from this scheme.i need to add a radio button for menu strip. i already change "clickonclick" property to "true".but i need a option like radio button selection. you can see it from windows calculator menu bar.(click View) how can i get to it via using menustrip peoperty.

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  • session management: problem displaying username in the header

    - by aeonsleo
    hi, I am working on a simple login and logout module for my website without any security. I am using wamp on a windows xp machine. I am creating session when a user submits the login informaton it redirects to a process.php file which creates the session variables and starts session. Now if the login is successful user is redirected to the welcome page which includes a header file(which displays the header involving signin logout help options) The problem is the header is not changing the signin link to logout as the user logs successfully. The below code is from process.php which initiates a login. $username = $_POST['username']; $password = $_POST['password']; //echo "{$username}:{$password}"; $connection = mysql_connect("localhost","root",""); if(!$connection) { die("Database Connection Failed".mysql_error()); } $db_select = mysql_select_db("tester",$connection); if(!$db_select) { die("Database Selection Failed".mysql_error()); } $result = mysql_query("SELECT * FROM user",$connection); if(!$result) { die("Database Selection Failed".mysql_error()); } $q = "SELECT * FROM user " ."WHERE Name='".$username."' AND Password='".$password. "' "; // Run query $r = mysql_query($q); if ( $obj = @mysql_fetch_object($r) ) { session_start(); // Login good, create session variables $_SESSION["valid_id"] = session_id(); $_SESSION["valid_user"] = $_POST["username"]; $_SESSION["valid_time"] = time(); Header('Location: welcome.php'); The following code is from header.php which is included in welcome.php </div> <div id = "userdetail"> <?php if(isset($_SESSION["valid_user"])) { echo($_SESSION["valid_user"]." " ); echo("<a href=logout.php>Logout</a>"); } else { echo("<a href = login.php>Sign In</a>"); } ?> | Help | Search <input type = "text" name = "searchbox" value = "" /> </div> </div>

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  • Getting a borderless window to receive mouseMoved events (Cocoa OSX)

    - by Michael Minerva
    I have a little popup window used for selecting images sorted by groups, and I would like to add a selection box around whatever image is being hovered over. I am trying to this by overriding the mouseMoved event for the window but it seems that a window that has a border-less style mask receives no mouseMoved events even if you have set setAcceptsMouseMoved events to YES. Is there anyway to make a borderless window receive this events?

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  • Run django tests from a browser

    - by phoebebright
    I'd like to provide a browser page to help non-techies run the various tests I've created using the standard django test framework. The ideal would be for a way to display all the tests found for an application with tick boxes against each one, so the user could choose to run all tests or just a selection. Output would be displayed in a window/frame for review. Anyone know of such a thing?

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  • What JavaScript table widgets you can recommend? [2]

    - by sdespolit
    As so far i've "found" Yahoo UI library and it fully conforms to my requirements. Also there is jqGrid that i'm using right now. If there are any alternatives? UPDATE: Please suggest libraries and don't seek for matching all the requirements listed below. [i'll check it for myself] My reqs are: rows adding, deletinig rows reoder (optionally with drag and drop) rows selection inline editing json data over xhr (optional) simple integration with backbone.js disclaimer: there was almost the same question 2 years ago

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