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  • Multiple controllers with a single model

    - by Eric K
    I'm setting up a directory application for which I need to have two separate interfaces for the same Users table. Basically, administrators use the Users controller and views to list, edit, and add users, while non-admins need a separate interface which lists users in a completely different manner. To do this, would I be able to just set up another controller with different views but which accesses the Users model? Sorry if this is a simple question, but I've had a hard time finding how to do this.

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  • How to retrieve from two tables with same foriegn key repeated more than once?

    - by Sarenya
    How to display the datas of tables, that are linked by a primay key and foriegn key, where the foriegn key of the data repeats? For ex. I have two tables, ParentTable and Childtable. The primarykey of the Parent table acts as the foriegn key of the Child table. There are more than one record with same ParentId in Child table. How to retrieve them and display in a single Grid or List or any type of view?

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  • Dumb RichTextBox question

    - by John Williams
    I need to get a list of tags in a text, make their contents bold, and remove them. Can't figure out how to make it. E.g. with the following input: foo [b]bar[/b] The result should be: foo bar I use the following code to extract the tags: Dim matches = Regex.Matches(OriginalRich.Text, String.Format("(\[{0}\])(.*?)(\[/{0}\])", tag), RegexOptions.IgnoreCase Or RegexOptions.Compiled) Any help would be appreciated.

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  • valid attributes sequence of input type tag

    - by I Like PHP
    hello, I know it's very basic question and hope not so important, but i want to know the answer, please don't suggest only refer links. we all daily face <input> type tag and their attributes(type, class, id, value, name, size, maxlength, tabindex etc..), i just want to know that is there any sequence list of attributes in tag or we can use any sequence? is there any sequence then what it is?

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  • For loops in Matlab

    - by seidel
    I run through a for loop, each time extracting certain elements of an array, say element1, element2, etc. How do I then pool all of the elements I've extracted together so that I have a list of them?

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  • Transform a listbox to textbox.

    - by trikalos
    I want to transform a listbox to textbox when I'm clicking a checkbox. To explain, i have a listbox that contains addresses and if an address does't belong in the list someone can click to a checkbox called 'another address';so he can put another address.Thanx for your answer...

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  • Compare two table and find matching columns

    - by Karthick
    Hi, I have two tables table1 and table2, i need to write a select query which will list me the columns that exist in both the tables.(mysql) I need to do for different tables (2 at a time) Is this possible? I tried using INFORMATION_SCHEMA.COLUMNS but am not able to get it right.

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  • Simple pathfinding?

    - by pdx
    Does anyone know if there is a simple way to do pathfinding in PHP? I basically have a list of numbers (kinda like {origin:11485,outboundDirections:"11486,11487,11488"} and {origin:11487,outboundDirections:"11485,11676,94185"} and getting from 11485 to 94185 would result in 11485>11487>94185 with ways to "exixt", and I'm trying to figure out how to do this (it doesn't really have to be shortest path or anything AI-like, just a way to get from A to B) I have no idea where to start at all, unfortunately

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  • jquery quering the database

    - by mazhar
    the thing is that there are number of items in the html select list,what i want to do is to click on any of the item, then query the database on the id of that item. retrieve the value and then display that in the textbox, how would i query the database? I would really appreciate that if someone provides the code sample for querying the database

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  • Is there an easy way to "append()" two dictionaries together in Python?

    - by digitaldreamer
    If I have two dictionaries I'd like to combine in Python, i.e. a = {'1': 1, '2': 2} b = {'3': 3, '4': 4} If I run update on them it reorders the list: a.update(b) {'1': 1, '3': 3, '2': 2, '4': 4} when what I really want is attach "b" to the end of "a": {'1': 1, '2': 2, '3': 3, '4': 4} Is there an easy way to attach "b" to the end of "a" without having to manually combine them like so: for key in b: a[key]=b[key] Something like += or append() would be ideal, but of course neither works on dictionaries.

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