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  • How to iterate over every property of an object in javascript?

    - by OverloadUT
    Is there a way to iterate over every property of an object using the Prototype JavaScript framework? Here's the situation: I am getting an AJAX response in JSON that looks something like this: {foo: 1, bar: 2, barobj: {75: true, 76: false, 85: true}} If I evaluate that json response in to a variable response, I want to be able to iterate over each property in the response.barobj object to see which indexes are true and which are false. Prototype has both Object.keys() and Object.values() but oddly seems to not have a simple Object.each() function! I could take the results of Object.keys() and Object.values() and cross-reference the other as I iterate through one, but that is such a hack that I am sure there is a proper way to do it!

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  • rails controller defaults to respond with application/xml in production

    - by Dave Paroulek
    I have a standard contacts_controller.rb with index action that responds as follows: respond_to do |format| format.html format.xml { render :xml => @contacts } end In development, it works as intended: when I browse to http://localhost:3000/contacts, I get an html response. But, when I start the app using capistrano on a remote Ubuntu server and browse to the same url, I get an xml response. If I go to http://remote_host:8000/contacts.html, then I see the html response. If I comment out the format.xml { render :xml => @contacts }, then I see the desired html response. Pretty sure I'm missing something subtle about difference between Rails development and production modes. Any ideas about what I'm overlooking? Thanks, - Dave

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  • Is there a performance gain from defining routes in app.yaml versus one large mapping in a WSGIAppli

    - by jgeewax
    Scenario 1 This involves using one "gateway" route in app.yaml and then choosing the RequestHandler in the WSGIApplication. app.yaml - url: /.* script: main.py main.py from google.appengine.ext import webapp class Page1(webapp.RequestHandler): def get(self): self.response.out.write("Page 1") class Page2(webapp.RequestHandler): def get(self): self.response.out.write("Page 2") application = webapp.WSGIApplication([ ('/page1/', Page1), ('/page2/', Page2), ], debug=True) def main(): wsgiref.handlers.CGIHandler().run(application) if __name__ == '__main__': main() Scenario 2: This involves defining two routes in app.yaml and then two separate scripts for each (page1.py and page2.py). app.yaml - url: /page1/ script: page1.py - url: /page2/ script: page2.py page1.py from google.appengine.ext import webapp class Page1(webapp.RequestHandler): def get(self): self.response.out.write("Page 1") application = webapp.WSGIApplication([ ('/page1/', Page1), ], debug=True) def main(): wsgiref.handlers.CGIHandler().run(application) if __name__ == '__main__': main() page2.py from google.appengine.ext import webapp class Page2(webapp.RequestHandler): def get(self): self.response.out.write("Page 2") application = webapp.WSGIApplication([ ('/page2/', Page2), ], debug=True) def main(): wsgiref.handlers.CGIHandler().run(application) if __name__ == '__main__': main() Question What are the benefits and drawbacks of each pattern? Is one much faster than the other?

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  • Send and receive data in same ajax request with jquery

    - by Pedro Esperança
    What is the best way to send data and receive a response dependent on that data? Consider the php file used for the request: $test = $_POST['test']; echo json_encode($test); I have tried unsucessfully to achieve this with: $.ajax({ type: "POST", dataType: "json", data: '{test : worked}', url: 'ajax/getDude.php', success: function(response) { alert(response); } });

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  • C++ Stack Overflow

    - by PhilMAN
    Here is some code: void main() { GameEngine ge("phil", "anotherguy"); string response; do { ge.playGame(); cout << endl << "Do you want to (r)eplay the same battle, (s)tart a new battle, or (q)uit? "; cin >> response; } while(response == "r" || response == "R" || response == "s" || response == "S" ); } GameEngine::GameEngine(string name1, string name2) { p1Name = name1; p2Name = name2; } void GameEngine::playGame() { cout << "PLAY GAME" << endl; Army p1, p2; Battlefield testField; RuleSet rs; int xSize = 13; // Number of rows int ySize = 13; // Number of columns loadData(p1, p2, testField, rs, xSize, ySize); ... } void GameEngine::loadData(Army& p1, Army& p2, Battlefield& testField, RuleSet& rs, int& xSize, int& ySize) { string terrain = BattlefieldUtils::pickTerrain(); string armySplit[14];//id index 1 string ruleSplit[19];//in index 7 string armyP1, armyP2, ruleSet; Skill p1Skills[8]; Skill p2Skills[8]; CreatureStack p1Stacks[20]; CreatureStack p2Stacks[20]; ... } CreatureStack(){quantity = 0; isLive = false; id = -1;}; Army(){}; Battlefield(){}; RuleSet(){}; I have posted every line of code that executes until the program crashes. This code ran fine for a long time, I added some stuff that does not even execute until way after the code I have posted here, and bam stack overflow that occurs at GameEngine::loadData() line: CreatureStack p2Stacks[20]; will not go away. What am I doing wrong here? Is that all the stack can handle? I increased the stack size in Visual Studio and got the error to go away, but that slowed things down considerably, so I would rather just get to the source of the issue and fix that.

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  • Javascript Object Properties go to undefined after ajax request returns

    - by adasdas
    if you have an object and set a property for it, you can access that property in a function called on that object. but if you call a function and do an ajax request such that a different function is called from onreadystatechange, that secondary response function does not have access to the property. Thats a little confusing so see what I mean here. The property this.name is the one that changes. //from W3Schools website function getXHR(){if (window.XMLHttpRequest){return new XMLHttpRequest();}if (window.ActiveXObject){return new ActiveXObject("Microsoft.XMLHTTP");}return null;} function TestObject() { this.name = ""; //public var xhr = null; //private var response = function() //private { if(xhr.readyState > 3) { alert("B: my name is " + this.name); } } this.send = function() //public { alert("A: my name is " + this.name); if(xhr === null) { xhr = getXHR(); } var url = "http://google.com"; xhr.onreadystatechange = response; xhr.open("GET", url, true); xhr.send(null); } } var o = new TestObject(); o.name = "Ice Cube"; o.send(); Results are: A: my name is IceCube B: my name is undefined If response is public this happens as well. If xhr is public this also happens. Something occurs so that the response function called doesnt have access to the same parameters.

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  • how do i design a high pass filters in matlab without using the builtin function?

    - by noura
    hello everyone, i'm just not sure how to draw the frequency response (H) of the high pass filter? after drawing the frequency response i can get the b coefficient by taking the ifft of (H). so yeah, for a low pass filter, with a cutoff frequency of say pi/2 : the frequency response code will be H = exp(-1*j*w*4).*(((0 <= w) & (w<= pi/2)) | ((2*pi - pi/2 <= w) & (w<=2*pi)); sincr the response is "1" between 0 and pi/2 and between (2*pi - pi/2) and 2*pi. can you help me write H for a high pass filter? thanx in advance.

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  • Access to the path Server.MapPath is denied

    - by Alex
    I created one pdf document var document = new Document(); string path = Server.MapPath("AttachementToMail"); PdfWriter.GetInstance(document, new FileStream(path + "/"+DateTime.Now.ToShortDateString()+".pdf", FileMode.Create)); Now I want to download this document Response.ContentType = "Application/pdf"; Response.AppendHeader("Content-Disposition", "attachment; filename="+ DateTime.Now.ToShortDateString() + ".pdf" + ""); Response.TransmitFile(path); Response.End(); but it gave me error Access to the path '~\AttachementToMail' is denied. read / write access for IIS_IUSRS exists

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  • IE Information Bar, download file...how do I code for this?

    - by flatline
    I have a web page (asp.net) that compiles a package then redirects the user to the download file via javascript (window.location = ....). This is accompanied by a hard link on the page in case the redirect doesn't work - emulating the download process on many popular sites. When the IE information bar appears at the top due to restricted security settings, and a user clicks on it to download the file, it redirects the user to the page, not the download file, which refreshes the page and removes the hard link. What is the information bar doing here? Shouldn't it send the user to the location of the redirect? Am I setting something wrong in the headers of the download response, or doing something else wrong to send the file in the first place? C# Code: m_context.Response.Buffer = false; m_context.Response.ContentType = "application/zip"; m_context.Response.AddHeader("Content-Length", fs.Length.ToString()); m_context.Response.AddHeader("Content-Disposition", string.Format("attachment; filename={0}_{1}.zip", downloadPrefix, DateTime.Now.ToString("yyyy-MM-dd_HH-mm"))); //send the file

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  • Django test client gets 301 redirection when accessing url

    - by Michal Klich
    I am writing unittests for django views. I have observed that one of my views returns redirection code 301, which is not expected. Here is my views.py mentioned earlier. def index(request): return render(request, 'index.html', {'form': QueryForm()}) def query(request): if request.is_ajax(): form = QueryForm(request.POST) return HttpResponse('valid') Below is urls.py. urlpatterns = patterns('', url(r'^$', 'core.views.index'), url(r'^query/$', 'core.views.query') ) And unittest that will fail. def so_test(self): response = self.client.post('/') self.assertEquals(response.status_code, 200) response = self.client.post('/query', {}) self.assertEquals(response.status_code, 200) My question is: why there is status 301 returned?

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  • Path to background in servlet

    - by kapil chhattani
    //the below line is the element of my HTML form which renders the image sent by the servlet written further below. <img style="margin-left:91px; margin-top:-6px;" class="image" src="http://www.abcd.com/captchaServlet"> I generate a captcha code using the following code in java. public class captchaServlet extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { int width = 150; int height = 50; int charsToPrint = 6; String elegibleChars = "ABCDEFGHJKLMPQRSTUVWXYabcdefhjkmnpqrstuvwxy1234567890"; char[] chars = elegibleChars.toCharArray(); StringBuffer finalString = new StringBuffer(); for ( int i = 0; i < charsToPrint; i++ ) { double randomValue = Math.random(); int randomIndex = (int) Math.round(randomValue * (chars.length - 1)); char characterToShow = chars[randomIndex]; finalString.append(characterToShow); } System.out.println(finalString); BufferedImage bufferedImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); Graphics2D g2d = bufferedImage.createGraphics(); Font font = new Font("Georgia", Font.BOLD, 18); g2d.setFont(font); RenderingHints rh = new RenderingHints( RenderingHints.KEY_ANTIALIASING, RenderingHints.VALUE_ANTIALIAS_ON); rh.put(RenderingHints.KEY_RENDERING, RenderingHints.VALUE_RENDER_QUALITY); g2d.setRenderingHints(rh); GradientPaint gp = new GradientPaint(0, 0, Color.BLUE, 0, height/2, Color.black, true); g2d.setPaint(gp); g2d.fillRect(0, 0, width, height); g2d.setColor(new Color(255, 255, 0)); Random r = new Random(); int index = Math.abs(r.nextInt()) % 5; char[] data=new String(finalString).toCharArray(); String captcha = String.copyValueOf(data); int x = 0; int y = 0; for (int i=0; i<data.length; i++) { x += 10 + (Math.abs(r.nextInt()) % 15); y = 20 + Math.abs(r.nextInt()) % 20; g2d.drawChars(data, i, 1, x, y); } g2d.dispose(); response.setContentType("image/png"); OutputStream os = response.getOutputStream(); ImageIO.write(bufferedImage, "png", os); os.close(); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { processRequest(request, response); } } But in the above code background is also generated using the setPaint menthod I am guessing. I want the background to be some image from my local machine whoz URL i should be able to mention like URL url=this.getClass().getResource("Desktop/images.jpg"); BufferedImage bufferedImage = ImageIO.read(url); I am just writing the above two lines for making the reader understand better what the issue is. Dont want to use the exact same commands. All I want is the the background of the captcha code generated should be an image of my choice.

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  • How to print object data in javascript

    - by rxzhang
    I have the following object data: var response = { "response": { "numFound": 7945, "docs": [{ "description": "target", "url": "target", "id": "269653", "score": 6.9186745 }, { "description": "Target Kent", "url": "Target_Kent", "id": "37275", "score": 4.3241715 }] }, "highlighting": { "269653": { "description": ["<em>target</em>"] }, "37275": { "description": ["<em>Target</em> Kent"] } } }; I can use response.response.docs[0].description to print out "target". But I don't know how to print out "<em>target</em>". Thanks.

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  • ask help: I need to create a demo application in Java to test my new designed Java Api

    - by Christophe
    A new programmer needs yourhelp. I'm working on a porject of re-developement of Java driver for the company's PIN pad terminals. the Java Api (CPXApplicationUpdate) will allow the applications in pinpads to be updated and to be downloaded at different speed (Baud rate). the Java Api was created. i followed the protocolto build the message. the message is to send to a RS-232 port. i'm trying to use setter and getter to let the code work as an API. import java.io.InputStream; import java.io.OutputStream; import java.util.Properties; public class CPXApplicationUpdate extends CPXCommand { private int speed; // TODO: temporary variable for baud rate test stub. // speed: baud rate of the maintenance application performing DL /** Creates a new instance of CPXApplicationUpdate */ public CPXApplicationUpdate() { speed = 9600; // no baud rate change CPXProcessor.logger.fine("-------CPXApplicationUpdate constructor"); // setParam("timeout", _cmdInfo.getDefaultParValue("timeout")); } public CPXApplicationUpdate(int speedinit) { speed = speedinit; // TODO: where to get the speed? wait for user input. CPXProcessor.logger.fine("-------CPXApplicationUpdate constructor"); // setParam("timeout", _cmdInfo.getDefaultParValue("timeout")); } public void setSpeed(int speed){ this.speed = speed; } protected void buildRequest() throws ElitePortException { String trans = ""; // build the full-qualified message trans = addToRequest(trans, (char) 0); trans = addToRequest(trans, (char) 5); trans = addToRequest(trans, (char) 6); trans = addToRequest(trans, (char) 0); trans = addToRequest(trans, (char) 0); trans = addToRequest(trans, (char) 2); switch (speed) { case 9600: trans = addToRequest(trans, (char) 0x09); break; case 19200: trans = addToRequest(trans, (char) 0x0A); break; case 115200: trans = addToRequest(trans, (char) 0x0E); break; default: // TODO: unexpected baud rate. throw(); break; } trans = EncryptBinary(trans); trans = "F0." + trans; wrapRequest(trans); } protected String addToRequest(String req, char c) { CPXProcessor.logger.fine("adding char to request: I-" + (int) c + " C-" + c + " H-" + Integer.toHexString((int) c)); return req + c; } protected String addToRequest(String req, String s) { CPXProcessor.logger.fine("adding String to request: S-" + s); return req + s; } protected String addToRequest(String req) { return req; } public void analyzeResponse() { String response_transaction, response; int absLen = _response.length(); if (absLen < 4) return; response = _response.substring(3); CPXProcessor.logger.fine("stripped response=[" + response + "]"); for (int i = 0; i < response.length(); i++) { char c = response.charAt(i); CPXProcessor.logger.fine("[" + i + "] = " + c + " <> " + Integer.toHexString((int) c)); } int status = (short) response.charAt(3); CPXProcessor.logger.fine("status = " + status); _outputValues.put("status", "" + status); } please help me to correct the code. Now, i need to create a demo application to test if this java driver (Java Api) works. the value of the speed can be input by users (command line), or creat property files. how can i do that?

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  • xmlhttprequest responsetext coming for Accept header: text/xml , but server error for application/JS

    - by encryptor
    I have to get response text from a resourceindex page as JSON object. When I dont put a Accept header in the request, it shows me the xml response (i see it in an alert).. But I want the response as a JSON object.. What should I do. One solution would have been httpRequest.setRequestHeader('Accept', 'application/JSON'); but this gives me a server error :500 Also it says A message body writer for Java type, class ...., and MIME media type, application/octet-stream, was not found Can someone suggest on what to do to overcome this and get the response as JSON?

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  • Can i create different observables and different corresponding observers in java?

    - by mithun1538
    Hello everyone, Currently, I have one observable and many observers. What i need is different observables, and depending on the observable, different observers. How do I achieve this? ( For understanding, assume I have different apples - say apple1 apple2... I have observer_1 observing apple1, observer_2 observing apple2, observer_3 observing apple 2 and so on..). I tried creating different objects of the Observable class, but since observers are observing the same class of observable, I don't know how to access a particular instance of the Observable. I have included the following servlet code that contains Observer and Observable classes: public class CustomerServlet extends HttpServlet { public String getNextMessage() { // Create a message sink to wait for a new message from the // message source. return new MessageSink().getNextMessage(source); } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ObjectOutputStream dout = new ObjectOutputStream(response.getOutputStream()); String recMSG = getNextMessage(); dout.writeObject(recMSG); dout.flush(); } public void broadcastMessage(String message) { // Send the message to all the HTTP-connected clients by giving the // message to the message source source.sendMessage(message); } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { ObjectInputStream din= new ObjectInputStream(request.getInputStream()); String message = (String)din.readObject(); ObjectOutputStream dout = new ObjectOutputStream(response.getOutputStream()); dout.writeObject("1"); dout.flush(); if (message != null) { broadcastMessage(message); } // Set the status code to indicate there will be no response response.setStatus(response.SC_NO_CONTENT); } catch (Exception e) { e.printStackTrace(); } } @Override public String getServletInfo() { return "Short description"; }// </editor-fold> MessageSource source = new MessageSource(); } class MessageSource extends Observable { public void sendMessage(String message) { setChanged(); notifyObservers(message); } } class MessageSource extends Observable { public void sendMessage(String message) { setChanged(); notifyObservers(message); } } class MessageSink implements Observer { String message = null; // set by update() and read by getNextMessage() // Called by the message source when it gets a new message synchronized public void update(Observable o, Object arg) { // Get the new message message = (String)arg; // Wake up our waiting thread notify(); } // Gets the next message sent out from the message source synchronized public String getNextMessage(MessageSource source) { // Tell source we want to be told about new messages source.addObserver(this); // Wait until our update() method receives a message while (message == null) { try { wait(); } catch (Exception e) { System.out.println("Exception has occured! ERR ERR ERR"); } } // Tell source to stop telling us about new messages source.deleteObserver(this); // Now return the message we received // But first set the message instance variable to null // so update() and getNextMessage() can be called again. String messageCopy = message; message = null; return messageCopy; } }

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  • Facebook FB.api post how to specify a target

    - by Laurent Luce
    I am using FB.api OpenGraph to post a message on the user's wall. I would like the link target to be equal to '_blank' so it opens in a new tab. Is it possible ? The Facebook documentation doesn't give much details. var params = {}; params['message'] = 'message'; params['name'] = 'name'; params['link'] = 'http://link'; params['picture'] = 'http://picture'; params['description'] = 'description'; FB.api('/me/feed', 'post', params, function(response) { if (!response || response.error) { alert('Error occured'); } else { alert('Post ID: ' + response); } });

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  • programs hangs during socket interaction

    - by herrturtur
    I have two programs, sendfile.py and recvfile.py that are supposed to interact to send a file across the network. They communicate over TCP sockets. The communication is supposed to go something like this: sender =====filename=====> receiver sender <===== 'ok' ======= receiver or sender <===== 'no' ======= receiver if ok: sender ====== file ======> receiver I've got The sender and receiver code is here: Sender: import sys from jmm_sockets import * if len(sys.argv) != 4: print "Usage:", sys.argv[0], "<host> <port> <filename>" sys.exit(1) s = getClientSocket(sys.argv[1], int(sys.argv[2])) try: f = open(sys.argv[3]) except IOError, msg: print "couldn't open file" sys.exit(1) # send filename s.send(sys.argv[3]) # receive 'ok' buffer = None response = str() while 1: buffer = s.recv(1) if buffer == '': break else: response = response + buffer if response == 'ok': print 'receiver acknowledged receipt of filename' # send file s.send(f.read()) elif response == 'no': print "receiver doesn't want the file" # cleanup f.close() s.close() Receiver: from jmm_sockets import * s = getServerSocket(None, 16001) conn, addr = s.accept() buffer = None filename = str() # receive filename while 1: buffer = conn.recv(1) if buffer == '': break else: filename = filename + buffer print "sender wants to send", filename, "is that ok?" user_choice = raw_input("ok/no: ") if user_choice == 'ok': # send ok conn.send('ok') #receive file data = str() while 1: buffer = conn.recv(1) if buffer=='': break else: data = data + buffer print data else: conn.send('no') conn.close() I'm sure I'm missing something here in the sorts of a deadlock, but don't know what it is.

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  • This .NET code snippet will NOT actually create a cookie, right?

    - by Ryan
    I just realized that this cookie is not showing up like it should, and I checked the code which was not written by me but I am pretty sure that this is NOT enough to create a cookie right?? public static void CreateSSOCookies(string tokenID) { System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Domain = System.Web.HttpContext.Current.Request.ServerVariables["SERVER_NAME"].ToString().ToLower(); System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Value = tokenID.ToString(); System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Path = "~/"; System.Web.HttpContext.Current.Response.Cookies["ssocookies"].Expires = DateTime.Now.AddDays(7); } If it does work, where is the cookie then? Is the cookie name 'ssocookies' ?

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  • how to hide the image? how can i do ?

    - by user309381
    function Psend() { new Ajax.Request('Handler.ashx', { method: 'get', onSuccess: function(transport) { var response = transport.responseText || "no response text"; //alert("Success! \n\n" + response); var obj = response.evalJSON(true); for (i = 0; i < 4; i++) { DeCheBX = $('MyDiv').insert(new Element('input', { 'type': 'checkbox', 'id': "img" + obj[i].Nam, 'value': obj[i].IM, 'onClick': 'SayHi(this)' })); DeImg = $('MyDiv').insert(new Element('img', { 'id': "img" + obj[i].Nam, 'src': obj[i].IM, 'style': 'display = inline', 'onClick': 'Say(this)' })); document.body.appendChild(DeCheBX); document.body.appendChild(DeImg); } }, onFailure: function() { alert('Something went wrong...') } }); SayHi = function(x) { if ($(x).checked == true) { // $('id').hide(); **$('img'+i).style.visibility = "hidden";**// doesnt work } };

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  • In node.js slow readable stream attached to a faster pushing message queue eats up memory

    - by Vishal
    In my node.js program I have a response stream attached to a message queue (zeromq) delivering data at a very high rate. Due to slow network connection the response stream and its underlying implementation is unable to consume data at that pace thus occupying a lot of memory. Do you have any suggestion to solve this problem. For reference please see the code snippet below: zmq.on("message", function(data) { res.write(data); // End response on some event });

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  • How do I make php page return a 503 error (or anything non-200).

    - by Benju
    A former developer wrote or client-server api in PHP. It simply sends messages as xml using post/response in a very simplistic fashion. The problem is that even when there is an error (ex: invalid arguments passed into the server side) we get a HTTP 200 response with a page like this <h4>Unknown error!</h4> In firebug I can see that the actually HTTP response is a 200. How can we send a different response (ie:503) when we programatically detect in our php code that it is appropriate to do so.

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  • JSF: How to forward a request to another page in action?

    - by Satya
    I want to forward request to another page from action class I am using below code in my jsf action : public String submitUserResponse(){ ...... ...... parseResponse(uri,request,response); .... return "nextpage"; } public String parseResponse(String uri,request,response){ if(uri != null){ RequestDispatcher dispatcher = request.getRequestDispatcher(uri); dispatcher.forward(request, response); return null; } ................. .................. return "xxxx"; } "submitUserResponse" method is being called when user clicks the submit button from the jsp and this method returns "nextpage" string here request forwards to next page in normal flow. but in my requirement i will call "submitUserResponse () " which will execute and forwrd request to next page.It is going. but it is displaying some exceptions in server That is : java.lang.IllegalStateException: Cannot forward after response has been committed Here my doubts are: 1.why next lines of code is being executed after forwarding my request using dispatched.forward(uri) . Same thing happening in response.sendRedirect("").

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  • How do i close a socket after a timeout in node.js?

    - by rramsden
    I'm trying to close a socket after a connection times out after 1000ms. I am able to set a timeout that gets triggered after a 1000ms but I can't seem to destroy the socket... any ideas? var connection = http.createClient(80, 'localhost'); var request = connection.request('GET', '/somefile.xml', {'host':'localhost'}); var start = new Date().getTime(); request.socket.setTimeout(1000); request.socket.addListener("timeout", function() { request.socket.destroy(); sys.puts("socket timeout connection closed"); }); request.addListener("response", function(response) { var responseBody = []; response.setEncoding("utf8"); response.addListener("data", function(chunk) { sys.puts(chunk); responseBody.push(chunk); }); response.addListener("end", function() { }); }); request.end(); returns socket timeout connection closed node.js:29 if (!x) throw new Error(msg || "assertion error"); ^ Error: assertion error at node.js:29:17 at Timer.callback (net:152:20) at node.js:204:9

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  • Jquery .$.ajax is not working

    - by Saravanan I M
    I am using $.ajax for facebook invite and calling the url (Yii framework controller). The below code is not working. $.ajax is not working. function FacebookInviteFriends() { FB.ui ( { method : 'apprequests', data: '', display: 'dialog', title : 'Invite a Friend', message: 'I just sent you an invitation to play My Game.', filters: ['app_non_users'] }, function(response) { alert("start"); if (response && response.to) { alert("inside if"); $.ajax({ url: 'http://localhost:83/invitechips/createRecord', type: 'POST', data: {id : response.to} }).done(function() { alert( "Data Saved: "); }); } else { alert("inside else"); } } ); }

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  • Python HTTPSConnection.close() does not appear to close the connection?

    - by Dave
    I'm not sure if this is a bug or if I'm just doing something wrong. If I were to do an HTTP connection like this: import httplib http_connection = httplib.HTTPConnection("192.168.192.196") http_connection.request("GET", "/") http_connection.sock.settimeout(20) response = http_connection.getresponse() data = response.read() http_connection.close() Then at a DOS prompt, I do this: netstat -ano | find /i "192.168.192.196:80" | find /i "ESTABLISHED" I get nothing. However, if I do the same thing, but change it to an HTTPSConnection: import httplib http_connection = httplib.HTTPSConnection("192.168.192.196") http_connection.request("GET", "/") http_connection.sock.settimeout(20) response = http_connection.getresponse() data = response.read() http_connection.close() Then do this: netstat -ano | find /i "192.168.192.196:443" | find /i "ESTABLISHED" I will actually see that the connection remains established until I actually ^Z out of the Python shell. This is happening in one of the applications I'm responsible for. Python isn't actually hanging there - it's simply leaving the connection open. Am I doing something wrong here? Do I need extra code to close the HTTPS connection? This is Python 2.6.4, btw.

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