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  • Adding Related Entities without using navigation properties

    - by Barisa Puter
    I have the following classes, set for testing: public class Company { [DatabaseGenerated(DatabaseGeneratedOption.Identity)] public int Id { get; set; } public string Name { get; set; } } public class Employee { [DatabaseGenerated(DatabaseGeneratedOption.Identity)] public int Id { get; set; } public string Name { get; set; } public int CompanyId { get; set; } public virtual Company Company { get; set; } } public class EFTestDbContext : DbContext { public DbSet<Employee> Employees { get; set; } public DbSet<Company> Companies { get; set; } } For the sake of testing, I wanted to insert one company and one employee for that company with single SaveChanges call, like this: Company company = new Company { Name = "Sample company" }; context.Companies.Add(company); // ** UNCOMMENTED FOR TEST 2 //Company company2 = new Company //{ // Name = "Some other company" //}; //context.Companies.Add(company2); Employee employee = new Employee { Name = "Hans", CompanyId = company.Id }; context.Employees.Add(employee); context.SaveChanges(); Even though I am not using navigational properties, but instead I've made relation over Id, this somehow mysteriously worked - employee was saved with proper foreign key to company which got updated from 0 to real value, which made me go ?!?! Some hidden C# feature? Then I've decided to add more code, which is commented in the snippet above, making it to be inserting of 2 x Company entity and 1 x Employee entity, and then I got exception: Unable to determine the principal end of the 'CodeLab.EFTest.Employee_Company' relationship. Multiple added entities may have the same primary key. Does this mean that in cases where foreign key is 0, and there is a single matching entity being inserted in same SaveChanges transaction, Entity Framework will assume that foreign key should be for that matching entity? In second test, when there are two entities matching the relation type, Entity Framework throws an exception as it is not able to figure out to which of the Companies Employee should be related to.

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  • Same Salt, Different Encrypted Password is not working? Using Linq to update password.

    - by Xaisoft
    Hello, I am running into a wall regarding changing the password and was wondering if anyone had any ideas. Here are the database values prior to changing the password: Clear Text password = abc1980 Encrypted Password = Yn1N5l+4AUqkOM3WYO7ww/sCN+o= Salt = 82qVIhUIoblBRIRvFSZ1fw== After I change my password to abc1973, salt remains the same, but the Encrypted Password changes which is supposed to happen: Encrypted Password = rHtjLq3qxAl/7T1GfkxrsHzPsNk= However, when I try to login with abc1973 as the password, it does not login. If I try abc1980, it logs me in. It is updating the database, is it caching the values somewhere? Any ideas?

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  • SQL Server - How Do I Substract 2 Hours from Formatted Time

    - by user1842653
    I need to know how to add 2 hours to the below 'Completed' timestamp. Here is the Select statement Select Tsk.task_id,Tsk.org_id,Tsk.completed,Tsk.assgn_acct_id,name FROM tdstelecom.tasks As Tsk WHERE Tsk.task_id = '11094836' AND DATE(Tsk.completed) < CURDATE() AND DATE(Tsk.completed) >= DATE_SUB(CURDATE (),INTERVAL 180 DAY) Here are the results: 2012-08-22 14:18:14 Desired results: 2012-08-22 16:18:14

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  • Joining tables, if percentage is above certain value

    - by CluelessGerman
    My question is similar to this one: Compare rows and get percentage However, little different. I adapted my question to the other post. I got 2 tables. First table: user_id | post_id 1 1 1 2 1 3 2 12 2 15 And second table: post_id | rating 1 1 1 2 1 3 2 1 2 5 3 null 3 1 3 4 12 4 15 1 So now I would like to count the rating for each post, in the second table. If the rating has more than, lets say, 50% positive ratings than I want to get the post_id and going it to the post_id from table one and add 1 to the user_id. At the end it would return the user_id with the number of positive posts. The result for above table would be: user_id | helpfulPosts 1 2 2 1 The post with post_id 1 and 3 have positive rating, because more than 50% have ratings of 1-3. The post with id = 2 is not positive, because the rating is exactly 50%. How would I achieve this? For clarification: It's a mysql rdbm and a positive post, is one where the number of rating_ids with 1, 2 and 3 are more than half of the overall rating. Basically the same thing, from the other thread I posted above.

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  • What sort of schema can I use to accommodate manual date based data entries?

    - by meder
    I have an admin where users from multiple properties can enter in monthly statistics for twitter/facebook followers. We do not have access to the real data/db so this is why a manual entry. The form looks like this: Type ( radio, select **one** only ): - Twitter - Facebook Followers/Fans ( textfield ): Property (dropdown): Hotel A, Hotel B Date Start: mm/dd/yyyy (textfield) Date End: mm/dd/yyyy (textfield) Question 1.1: Since I am only keeping track of month per month, the date start/end fields which I have already created might be too specific. Would it be a better idea just to have a start month/year and and month/year if that's the only thing I care about? Question 1.2: What schema could I use for month to month statistics if I were to change the date start and end textfields to start month/year and end month/year dropdowns?

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  • Removing part of a string in PHP

    - by Nik
    I'm trying to take a query: SHOW TABLES; which will display a bunch of tables with the chat_ prefix. I want to remove the chat_ prefix from the string, format the variable (with a link), and display it. How is this accomplished?

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  • copy an identity column into another table

    - by slake
    I have 2 tables that are related,both have identity columns for primary keys and i am using a vb form to insert data into them,My problem is that i cannot get the child table to get the primary key of the parent table and use this as its foreign key in my database. the data is inserted fine though no foreign key constraint is made.I am wondering if a trigger will do it and if so how. All my inserting of data is done in vb. The user wont insert any keys. all these are identity columns that are auto generated. If a trigger is my way out please illustrate with an example. If there is another way i can do this in VB itself then please advise and an example will be greatly appreciated Thanks in advance

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  • difference between where and nested queries

    - by Chris H
    I'm not able to figure out the difference between these queries. I'm pretty sure that the first one is an equi-join. I'm not sure how the second one ISN'T the same as the first. The sub query in #2 selects all Ids from S, and then it returns all R's that also have those ID's, no? SELECT R.cname FROM R, S, WHERE R.Id = S.Id SELECT R.cname FROM R WHERE R.Id IN (SELECT S.Id FROM S)

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  • Copying Primary key to another field in Access.

    - by BashLover
    Hey, I'm struggling to copy the Primary Key to another field in Access. This is irrelevant , but clarifying on what I'm comparing. ... WHERE Tunniste=" & [Tarkiste] & "" Tunniste = Primary Key , Autonumber , ID (Generated by Access.) Tarkiste = This is the field I want to copy it to compare it. I'm open to suggestions, I've already try'ed with Form_Load, using the following code. Private Sub Form_Load() DoCmd.RunSQL "UPDATE Korut SET [Tarkiste]=('" & Tunniste & "');" End Sub But this copied the same key to all the entries in "Tarkiste" field. In simplicity I want 1:1 copy of field "Tunniste" to "Tarkiste" , whichever method it takes. Started from this question. File Picker Replaces All Rows With The Same Choice.

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  • Inserting data into a Database

    - by Erebus
    SO I'm making a "basic" login file where a person logs in and the data that person entered on that form gets transfered to another form aka my database/table. I think the problems is here but I'll post the rest of the code. CREATE FUNCTION dbo.Function4 ( parameter1 int = 5, parameter2 datatype ) RETURNS Table1 TABLE (UserName, Password, Password_Confirmation, Assets) AS BEGIN INSERT INTO Table1 (UserName, Password, Password_Confirmation, Assets) VALUES (a,b,c,d); /*SELECT ... FROM ...*/ RETURN END This is the Login Form using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace Login_Basic { public partial class Form2 : Form { public Form2() { InitializeComponent(); } Form3 Delta = new Form3(); private void label3_Click(object sender, EventArgs e) { } private void Form2_Load(object sender, EventArgs e) { this.Hide(); } private void textBox6_TextChanged(object sender, EventArgs e) { } private void textBox6_KeyPress(object sender, KeyPressEventArgs e) { int i = Convert.ToInt32(e.KeyChar); if (!(Char.IsDigit(e.KeyChar) || Char.IsControl(e.KeyChar) || (e.KeyChar == '.' && this.Text.Contains(".") == false))) e.Handled = true; } private void button1_Click(object sender, EventArgs e) { Delta.Show(); //if (textBox3.Text.Equals("")) //{ // MessageBox.Show("Please enter your username"); //} //else //{ // this.Hide(); //} // if (textBox4.Text.Equals("")) //{ // MessageBox.Show("Please enter your password"); // } // else //{ // this.Hide(); // } // if (textBox5.Text.Equals("")) // { // MessageBox.Show("Please re-enter your password"); // } // else // { // this.Hide(); // } //if (textBox6.Text.Equals("")) //{ // MessageBox.Show("Please enter your amount"); // // } // else // { // this.Hide(); // } } private void button3_Click(object sender, EventArgs e) { this.Hide(); } private void textBox3_TextChanged(object sender, EventArgs e) { } private void textBox4_TextChanged(object sender, EventArgs e) { } private void textBox5_TextChanged(object sender, EventArgs e) { } private void panel2_Paint(object sender, PaintEventArgs e) { /*if (textBox3.Text.Equals("") && textBox4.Text.Equals("") && textBox5.Text.Equals("") && textBox6.Text.Equals("")) { button1.Enabled = false; } else { button1.Enabled = true; }*/ } } } Here's a "Pic" of my database http://s299.photobucket.com/albums/mm305/krsimms123/Code.jpg Thanks in advance (I'll try and check this every few hours so I can help explain anything)

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  • Desgining a database with flexible user profile

    - by Mughrabi
    Hi, Am working on a design where I can have flexible attributes for a user & am confused how to continue the design of the schema. I made a table where I kept system needed information called users id username password Now, I wish to create a profile table and have one to one relation where all the other attributes in profile table such as email, first name, last name..etc. My question is, is there a way to add a third table in which even profile will be flexible if my clients need to create a new attribute he/she won't need any customization to the code? Regards,

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  • MySQL, select from different table... IF

    - by gubbfett
    I'm having a small trouble since it was a long time ago i studies databases and querys. For example i'll have two tables for cd:s, one with data and one with alternative translations. In the CD-table i have the original language, and it looks something like this Table for CDs (cds): id | name | language ----------------------- 1 | aaa | en 2 | bbb | en 3 | ccc | fi Table for languages (languages): cd_id | language | name ----------------------- 1 | fi | AAA 1 | de | AAACHTUNG 3 | en | CCC Now, i want to get all these cd:s in for example german, if there's no translation made i want it to be in the original language... How can i do this?

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  • "Remember" last three MySql queries; Cookie, passed variable or other method?

    - by Camran
    I have a classified website, with pretty sophisticated searching, and I am about to implement a function where the last three queries is displayed for the user, so that the user can go back easier through the queries. This because for each query the user has to provide a lot of input. I have four questions for you: I wonder, how can I save the actual query (SELECT * FROM etc etc)...? Do I need to add some form of encryption to be on the safe side? How will this affect performance? (I don't like the fact that cookies slow websites down) Anything else to think about? If you need more input, let me know... Btw, the website is PHP based. Thanks

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  • MySql Query to return number of photos in each album

    - by GivenPie
    MY table is set up like this, all I need to do is call a query to my Photos table. I have PhotoID as the primary key and GalleryID as the foreign key to Gallery. How can I could the number of unique PhotoID's for each multiple GalleryIDs. So to speak there are may duplicate GalleryIDs because there are many photos in a gallery. So I just need to could the number of unique PhotoIDs associated with that GalleryID. Can it be done in one query?

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  • Membership provider to use or not to use?????

    - by Shekhar_Pro
    Hi every one , Wish u all a Happy New Year. I am developing a website that uses facebook. Now for managing user i thought Using membrship provider. and choose'd to develop a Custom membership provider. Now my problem is that My data base schema dosn't match the Standred membership schema and the functions provided to Override take different argument than i expect. Like membership uses username as a username to log in. But i haev to use User email ID as the user name, also its searching functions is based on using Username as way to serach but i want it to search by UserID. Same Goes for User insertion, deletion, Updation.. please help me .... Edit Its just an idea, Would it be feasible to forcefully pass my values in the arguments and then handle them in my code.

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  • Getting data from the next row in Oracle cursor

    - by Chaotic_one
    Hi, I'm building nested tree and I need to get data for the next row in cursor, using Oracle. And I still need current row, so looping forward is not a solution. Example: OPEN emp_cv FOR sql_stmt; LOOP FETCH emp_cv INTO v_rcod,v_rname,v_level; EXIT WHEN emp_cv%NOTFOUND; /*here lies the code for getting v_next_level*/ if v_next_level > v_level then /*code here*/ elsif v_next_level < v_level then /*code here*/ else /*code here*/ end if; END LOOP; CLOSE emp_cv;

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  • mysql count(*) left join group by - the number of files in a folder

    - by Flavius
    Hi I have the following tables CREATE TABLE `files` ( `fileid` int(11) NOT NULL AUTO_INCREMENT, `filename` varchar(255) NOT NULL, `filesize` int(11) NOT NULL, `folder` int(11) NOT NULL, PRIMARY KEY (`fileid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; CREATE TABLE `folders` ( `directoryid` int(11) NOT NULL AUTO_INCREMENT, `directoryname` varchar(255) NOT NULL, PRIMARY KEY (`directoryid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; How to get a list of all folders and the number of files they hold, including folders who have no (zero) files? Recursion must not be taken into account. Found it select folders.directoryid, folders.directoryname, count(files.fileid) as no_files from folders left join files on files.folder = folders.directoryid group by folders.directoryid, folders.directoryname I hope it will help someone.

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  • How can I use two or more COUNT()s in one SELECT statament?

    - by jjj
    i develop this code: SELECT COUNT(NewEmployee.EmployeeID), NewEmployee.EmployeeId,EmployeeName FROM NewEmployee INNER JOIN NewTimeAttendance ON NewEmployee.EmployeeID = NewTimeAttendance.EmployeeID and NewTimeAttendance.TotalTime is null and (NewTimeAttendance.note = '' or NewTimeAttendance.note is null) and (month = 1 or month = 2 or month = 3) GROUP BY NewEmployee.EmployeeID, EmployeeName order by EmployeeID from my previous two questions selecting null stuff and counting issue...that amazing code is working beautifully fine..but now i need to select more than one count... ...searched (google) .... found alias...tried: SELECT COUNT(NewEmployee.EmployeeID) as attenddays, COUNT(NewEmployee.EmployeeID) as empabsent , NewEmployee.EmployeeId,EmployeeName FROM NewEmployee INNER JOIN NewTimeAttendance ON empabsent =NewEmployee.EmployeeID = NewTimeAttendance.EmployeeID and NewTimeAttendance.TotalTime is null and (NewTimeAttendance.note = '' or NewTimeAttendance.note is null ) and (month=1 or month =2 or month = 3) , attenddays = NewTimeAttendance.EmployeeID and NewTimeAttendance.TotalTime is null and (NewTimeAttendance.note = '' or NewTimeAttendance.note is null ) and (month=1 or month =2 or month = 3) GROUP BY NewEmployee.EmployeeID, EmployeeName order by EmployeeID Incorrect syntax near '='. second try: SELECT COUNT(NewEmployee.EmployeeID) as attenddays, COUNT(NewEmployee.EmployeeID) as absentdays, NewEmployee.EmployeeId,EmployeeName FROM NewEmployee INNER JOIN NewTimeAttendance ON attenddays(NewEmployee.EmployeeID = NewTimeAttendance.EmployeeID and NewTimeAttendance.TotalTime is null and (NewTimeAttendance.note = '' or NewTimeAttendance.note is null ) and (month=1 or month =2 or month = 3)) , absentdays(NewEmployee.EmployeeID = NewTimeAttendance.EmployeeID and NewTimeAttendance.TotalTime is null and (NewTimeAttendance.note = '' or NewTimeAttendance.note is null ) and (month=1 or month =2 or month = 3)) GROUP BY NewEmployee.EmployeeID, EmployeeName order by EmployeeID Incorrect syntax near '='. not very good ideas... so ...help thanks in advance

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  • get index name within specific table name

    - by AmRoSH
    I need to check if this index not exist in specific table name not in all tables because this select statement select all indexes under this condition. IF NOT EXISTS (SELECT name from sysindexes WHERE name = 'IDX_InsuranceID') CREATE NONCLUSTERED INDEX [IDX_InsuranceID] ON [dbo].[QuoteInsurances] ( [InsuranceID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = OFF, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON, FILLFACTOR = 80) ON [PRIMARY] GO Thanks,

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  • Query returning an ascending group number

    - by Dougman
    I have a query like below that has groups (COL1) and that group's values (COL2). select col1, col2 from (select 'A' col1, 1 col2 from dual union all select 'A' col1, 2 col2 from dual union all select 'B' col1, 1 col2 from dual union all select 'B' col1, 2 col2 from dual union all select 'C' col1, 1 col2 from dual union all select 'C' col1, 2 col2 from dual ) order by col1, col2; The output of this query looks like: COL1 COL2 ---- ---- A 1 A 2 B 1 B 2 C 1 C 2 What I need is a query that will return an ordered number increasing for each different group (COL1). It seems like there would be a simple way to accomplish this (maybe with analytics) but for some reason it is escaping me. GRPNUM COL1 COL2 ------ ---- ---- 1 A 1 1 A 2 2 B 1 2 B 2 3 C 1 3 C 2 I am running Oracle 10gR2.

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