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  • Highly recommended: "5 Things SQL Server does different from what many developers expect" by Nico Ja

    A couple of weeks ago, the Belgian Techdays were held in Antwerp. Together with Scott Hillier I presented the SharePoint pre-conference sessions (watch them online over here, search for pre-conference or SharePoint). Even though Belgium is not a very big country, the Microsoft team managed to get some high profile speakers like Anders Hejlsberg and Scott Hanselman. But if you have like 60 minutes to spare there is one session that I'd really recommend to check out, not related to SharePoint, but...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • TSQL formatting - a sure fire way to start a conversation.

    - by fatherjack
    There are probably as many opinions on ways to format code as there are people writing code and I am not here to say that any one is better than any other. Well, that isn't true. I am here to say that one way is better than another but this isn't a matter of preference or personal taste, this is an example of where sloppy formatting can cause TSQL to weird and whacky things but following some simple methods can make your code more reliable and more robust when . Take these two pieces of code, ready...(read more)

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  • SQL SERVER What is Spatial Database? Developing with SQL Server Spatial and Deep Dive into Spatial

    What is Spatial Database?A spatial database is a database that is optimized to store and query data related to objects in space, including points, lines and polygons. While typical databases can understand various numeric and character types of data, additional functionality needs to be added for databases to process spatial data types. (Source: Wikipedia)Today [...]...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Can't sync time between domain controller and another servers/computers (windows 2003)

    - by Anatoly
    Good morning, We have domain controller on windows server 2003 and another windows 2003 servers with terminal server and DB and regular workstations. Today in Israel we returned back to winter time (one hour back), domain controller now shows current time but all another machines in network show different time they went two hour back and there's difference in one hour between domain controller and another machines. I have tried to perform W32tm /resync /update but without success, where can be problem? Thank you.

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  • vCenter 5.1 SSO Configuration option not available in Web Client?

    - by goober
    Problem I just finished separately installing vCenter Server 5.1. I installed the components separately but on the same machine using a local SQL 2008 R2 DB (not SQL express). Everything appears to be working correctly with the exception of SSO. It doesn't find the AD server. This is to be expected (see below) but I don't know how to fix it. Potential Leads / Steps taken During the install of SSO, I was logged on as a local administrator (waiting on central IT dept to create a service account). As a result, I received a message saying that SSO wouldn't be able to automatically locate the AD. (fair eonugh) After I read up on it a little bit, I believed I could go into the SSO Configuration option in the Web client, like so: However, what I actually see is: I also notice that the "SSO Users and Groups" entry is not there. Betting that has something to do with it as well. Question How can I get the "Configure" Option to show up for SSO? Overall goal: How can I manually enter the AD server in this scenario while logged in as a local administrator? References VMWare vCenter 5.1 Installation: Part 9 (Optional SSO Configuration) [Derek Seaman's Blog] (used the image of correct configuration menu)

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  • Script to monitor free space in Hdd

    - by s.mihai
    I have a server app that crushes when the HDD free space it's a multiple of 4Gb (on a Windows Server 2003). In general i keep track myself o that weekly since i use the machine from time to time. Can you point out an app or script (i don't wanna install powershell, is this doable???) that copies some larger files from one folder to another to get the free space out of the multiple of 4Gb range. Best regards, Mike

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  • WebSphere Application Server V8 : IBM améliore les capacités techniques de son serveur d'applications, testez-le gratuitement

    WebSphere Application Server V8 : meilleures capacités techniques Pour le nouveau serveur d'applications d'IBM pour développeurs, testez-le gratuitement IBM vient de présenter la nouvelle version de son serveur d'applications (le plus vendu au monde) : WebSphere Application Server V8. WAS est « en tête des benchmarks et considéré par les analystes comme le serveur d'applications le plus solide du marché », se félicite IBM. Sa nouvelle version optimise le déploiement d'applications accessibles à partir de terminaux de tous formats : PC, smartphones, tablettes, etc. Autre nouveauté, WAS v8 supporte les langages Ruby et Python, il accélère le chargement...

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  • SQL Query for Determining SharePoint ACL Sizes

    - by Damon Armstrong
    When a SharePoint Access Control List (ACL) size exceeds more than 64kb for a particular URL, the contents under that URL become unsearchable due to limitations in the SharePoint search engine.  The error most often seen is The Parameter is Incorrect which really helps to pinpoint the problem (its difficult to convey extreme sarcasm here, please note that it is intended).  Exceeding this limit is not unheard of – it can happen when users brute force security into working by continually overriding inherited permissions and assigning user-level access to securable objects. Once you have this issue, determining where you need to focus to fix the problem can be difficult.  Fortunately, there is a query that you can run on a content database that can help identify the issue: SELECT [SiteId],      MIN([ScopeUrl]) AS URL,      SUM(DATALENGTH([Acl]))/1024 as AclSizeKB,      COUNT(*) AS AclEntries FROM [Perms] (NOLOCK) GROUP BY siteid ORDER BY AclSizeKB DESC This query results in a list of ACL sizes and entry counts on a site-by-site basis.  You can also remove grouping to see a more granular breakdown: SELECT [ScopeUrl] AS URL,       SUM(DATALENGTH([Acl]))/1024 as AclSizeKB,      COUNT(*) AS AclEntries FROM [Perms] (NOLOCK) GROUP BY ScopeUrl ORDER BY AclSizeKB DESC

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  • Windows XP SP3 client printer error over AD

    - by Alex
    I have Windows Server 2008r2 and a Windows XP SP3 client machine in Active Directory. My problem is that I've installed the printer on the windows server and shared it, the permissions are right, but when i try to connect to that printer from the windows xp client, it throws the following errer: "You do not have sufficient access to your computer to connect to the selected printer". Again, the permissions are right. I think I'm missing something that I couldn't find on the web. :( please help!

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  • Basics of Join Factorization

    - by Hong Su
    We continue our series on optimizer transformations with a post that describes the Join Factorization transformation. The Join Factorization transformation was introduced in Oracle 11g Release 2 and applies to UNION ALL queries. Union all queries are commonly used in database applications, especially in data integration applications. In many scenarios the branches in a UNION All query share a common processing, i.e, refer to the same tables. In the current Oracle execution strategy, each branch of a UNION ALL query is evaluated independently, which leads to repetitive processing, including data access and join. The join factorization transformation offers an opportunity to share the common computations across the UNION ALL branches. Currently, join factorization only factorizes common references to base tables only, i.e, not views. Consider a simple example of query Q1. Q1:    select t1.c1, t2.c2    from t1, t2, t3    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2   union all    select t1.c1, t2.c2    from t1, t2, t4    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3; Table t1 appears in both the branches. As does the filter predicates on t1 (t1.c1 > 1) and the join predicates involving t1 (t1.c1 = t2.c1). Nevertheless, without any transformation, the scan (and the filtering) on t1 has to be done twice, once per branch. Such a query may benefit from join factorization which can transform Q1 into Q2 as follows: Q2:    select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                   from t2, t3                    where t2.c2 = t3.c2 and t2.c2 = 2                                  union all                   select t2.c1 item_1, t2.c2 item_2                   from t2, t4                    where t2.c3 = t4.c3) VW_JF_1    where t1.c1 = VW_JF_1.item_1 and t1.c1 > 1; In Q2, t1 is "factorized" and thus the table scan and the filtering on t1 is done only once (it's shared). If t1 is large, then avoiding one extra scan of t1 can lead to a huge performance improvement. Another benefit of join factorization is that it can open up more join orders. Let's look at query Q3. Q3:    select *    from t5, (select t1.c1, t2.c2                  from t1, t2, t3                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2                 union all                  select t1.c1, t2.c2                  from t1, t2, t4                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3) V;   where t5.c1 = V.c1 In Q3, view V is same as Q1. Before join factorization, t1, t2 and t3 must be joined first before they can be joined with t5. But if join factorization factorizes t1 from view V, t1 can then be joined with t5. This opens up new join orders. That being said, join factorization imposes certain join orders. For example, in Q2, t2 and t3 appear in the first branch of the UNION ALL query in view VW_JF_1. T2 must be joined with t3 before it can be joined with t1 which is outside of the VW_JF_1 view. The imposed join order may not necessarily be the best join order. For this reason, join factorization is performed under cost-based transformation framework; this means that we cost the plans with and without join factorization and choose the cheapest plan. Note that if the branches in UNION ALL have DISTINCT clauses, join factorization is not valid. For example, Q4 is NOT semantically equivalent to Q5.   Q4:     select distinct t1.*      from t1, t2      where t1.c1 = t2.c1  union all      select distinct t1.*      from t1, t2      where t1.c1 = t2.c1 Q5:    select distinct t1.*     from t1, (select t2.c1 item_1                   from t2                union all                   select t2.c1 item_1                  from t2) VW_JF_1     where t1.c1 = VW_JF_1.item_1 Q4 might return more rows than Q5. Q5's results are guaranteed to be duplicate free because of the DISTINCT key word at the top level while Q4's results might contain duplicates.   The examples given so far involve inner joins only. Join factorization is also supported in outer join, anti join and semi join. But only the right tables of outer join, anti join and semi joins can be factorized. It is not semantically correct to factorize the left table of outer join, anti join or semi join. For example, Q6 is NOT semantically equivalent to Q7. Q6:     select t1.c1, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t2.c2 (+) = 2  union all    select t1.c1, t2.c2    from t1, t2      where t1.c1 = t2.c1(+) and t2.c2 (+) = 3 Q7:     select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                  from t2                  where t2.c2 = 2                union all                  select t2.c1 item_1, t2.c2 item_2                  from t2                                                                                                    where t2.c2 = 3) VW_JF_1       where t1.c1 = VW_JF_1.item_1(+)                                                                  However, the right side of an outer join can be factorized. For example, join factorization can transform Q8 to Q9 by factorizing t2, which is the right table of an outer join. Q8:    select t1.c2, t2.c2    from t1, t2      where t1.c1 = t2.c1 (+) and t1.c1 = 1 union all    select t1.c2, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t1.c1 = 2 Q9:   select VW_JF_1.item_2, t2.c2   from t2,             (select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 1           union all            select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 2) VW_JF_1   where VW_JF_1.item_1 = t2.c1(+) All of the examples in this blog show factorizing a single table from two branches. This is just for ease of illustration. Join factorization can factorize multiple tables and from more than two UNION ALL branches.  SummaryJoin factorization is a cost-based transformation. It can factorize common computations from branches in a UNION ALL query which can lead to huge performance improvement. 

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  • Serial plans: Threshold / Parallel_degree_limit = 1

    - by jean-pierre.dijcks
    As a very short follow up on the previous post. So here is some more on getting a serial plan and why that happens Another reason - compared to the auto DOP is not on as we looked at in the earlier post - and often more prevalent to get a serial plan is if the plan simply does not take long enough to consider a parallel path. The resulting plan and note looks like this (note that this is a serial plan!): explain plan for select count(1) from sales; SELECT PLAN_TABLE_OUTPUT FROM TABLE(DBMS_XPLAN.DISPLAY()); PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- Plan hash value: 672559287 -------------------------------------------------------------------------------------- | Id  | Operation            | Name  | Rows  | Cost (%CPU)| Time     | Pstart| Pstop | -------------------------------------------------------------------------------------- PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- |   0 | SELECT STATEMENT     |       |     1 |     5   (0)| 00:00:01 |       |     | |   1 |  SORT AGGREGATE      |       |     1 |            |          |       |     | |   2 |   PARTITION RANGE ALL|       |   960 |     5   (0)| 00:00:01 |     1 |  16 | |   3 |    TABLE ACCESS FULL | SALES |   960 |     5   (0)| 00:00:01 |     1 |  16 | Note -----    - automatic DOP: Computed Degree of Parallelism is 1 because of parallel threshold 14 rows selected. The parallel threshold is referring to parallel_min_time_threshold and since I did not change the default (10s) the plan is not being considered for a parallel degree computation and is therefore staying with the serial execution. Now we go into the land of crazy: Assume I do want this DOP=1 to happen, I could set the parameter in the init.ora, but to highlight it in this case I changed it on the session: alter session set parallel_degree_limit = 1; The result I get is: ERROR: ORA-02097: parameter cannot be modified because specified value is invalid ORA-00096: invalid value 1 for parameter parallel_degree_limit, must be from among CPU IO AUTO INTEGER>=2 Which of course makes perfect sense...

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  • Proper Data Structure for Commentable Comments

    - by Wesley
    Been struggling with this on an architectural level. I have an object which can be commented on, let's call it a Post. Every post has a unique ID. Now I want to comment on that Post, and I can use ID as a foreign key, and each PostComment has an ItemID field which correlates to the Post. Since each Post has a unique ID, it is very easy to assign "Top Level" comments. When I comment on a comment however, I feel like I now need a PostCommentComment, which attaches to the ID of the PostComment. Since ID's are assigned sequentially, I can no longer simply use ItemID to differentiate where in the tree the comment is assigned. I.E. both a Post and a Post Comment might have an ID of '5', so my foreign key relationship is invalid. This seems like it could go on infinitely, with PostCommentCommentComment's etc... What's the best way to solve this? Should I have a field in the comment called "IsPostComment" or something of the like to know which collection to attach the ID to? This strikes me as the best solution I've seen so far, but now I feel like I need to make recursive DataBase calls which start to get expensive. Meaning, I get a Post and get all PostComments where ItemID == Post.ID && where IsPostComment == true Then I take that as a collection, gather all the ID's of the PostComments, and do another search where ItemID == PostComment[all].ID && where IsPostComment == false, then repeat infinitely. This means I make a call for every layer, and if I'm calling 100 Posts, I might make 1000 DB calls to get 10 layers of comments each. What is the right way to do this?

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  • Remote desktop logs in with saved credentials when connecting from one computer but asks for username and password from another.

    - by AndrejaKo
    I have two computers on which I recently installed windows 7 64 bit. Using VPN, they connect to remote network on which there is a Windows Server 2000 SP4 computer. User is supposed to connect to server using remote desktop. I set same VPN and remote desktop settings on both computers with Windows 7. I set Remote desktop to save connection credentials on both computers, but when I connect to server form one computer, it uses saved credentials and I don't get log-in prompt on server side. On the other computer with same settings using same username and password, I get log-in prompt once the remote desktop connects to server. I even tried copying the .rdp file from the computer on which everything is working fine to the other computer, but that didn't help. Note that I'm not trying to have both computers connected at the same time. What is causing this and how do I make the other computer skip windows server 2000 log-in prompt.

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  • Materialized View does not import properly when importing a db for a second time in another schema [closed]

    - by marinus
    When I import a database with materialized view mv_mt in just one schema there are no errors. create materialized view mv_mt refresh complete next trunc( sysdate ) + 1 as SELECT sysdate, media_type.* from media_type; But when I try to import the same database to a copy in another schema in the same tablespace I get the following errors: IMP-00017: following statement failed with ORACLE error 1: "BEGIN DBMS_JOB.ISUBMIT(JOB=>438,WHAT=>'dbms_refresh.refresh(''"ALEXANDRA"" "."MV_MT"'');',NEXT_DATE=>TO_DATE('2012-07-02:14:22:36','YYYY-MM-DD:HH24:MI:" "SS'),INTERVAL=>'sysdate + 1 / 24 / 60 / 6 ',NO_PARSE=>TRUE); END;" IMP-00003: ORACLE error 1 encountered ORA-00001: unique constraint (SYS.I_JOB_JOB) violated ORA-06512: at "SYS.DBMS_JOB", line 100 ORA-06512: at line 1 IMP-00017: following statement failed with ORACLE error 23421: "BEGIN dbms_refresh.make('"ALEXANDRA"."MV_MT"',list=>null,next_date=>null," "interval=>null,implicit_destroy=>TRUE,lax=>FALSE,job=>438,rollback_seg=>NUL" "L,push_deferred_rpc=>TRUE,refresh_after_errors=>FALSE,purge_option => 1,par" "allelism => 0,heap_size => 0); END;" IMP-00003: ORACLE error 23421 encountered ORA-23421: job number 438 is not a job in the job queue ORA-06512: at "SYS.DBMS_SYS_ERROR", line 86 ORA-06512: at "SYS.DBMS_IJOB", line 793 ORA-06512: at "SYS.DBMS_REFRESH", line 86 ORA-06512: at "SYS.DBMS_REFRESH", line 62 ORA-06512: at line 1 IMP-00017: following statement failed with ORACLE error 23410: "BEGIN dbms_refresh.add(name=>'"ALEXANDRA"."MV_MT"',list=>'"ALEXANDRA"."MV" "_MT"',siteid=>0,export_db=>'ORCL01'); END;" IMP-00003: ORACLE error 23410 encountered ORA-23410: materialized view "ALEXANDRA"."MV_MT" is already in a refresh group ORA-06512: at "SYS.DBMS_SYS_ERROR", line 95 ORA-06512: at "SYS.DBMS_IREFRESH", line 484 ORA-06512: at "SYS.DBMS_REFRESH", line 140 ORA-06512: at "SYS.DBMS_REFRESH", line 125 ORA-06512: at line 1 Anyone any ideas?

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  • Word 2007 Question

    - by Lijo
    Hi Team, While preparing a Word 2007 document, I made a mistake. (Not to say I don't have any other copy of the document) While formatting (as a try) I applied the style "Apply Style to Body to match selection". This caused the document to go totally in a wronfg format - having numbers even in tables. Have you ever faced this? Could you please tell how to correct it? Hope you would be kind enough to answer this even though it is not striclty technical. Thanks Lijo

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  • Some rules are not listed when I open my GPO rules editor

    - by Copeleto
    Hi, I need to enable a rule using a GPO's, the rule is - Security Zones: Do not allow users to Add/Delete Sites. The rule is located Computer Configuration\Administrative Templates\Windows Components\Internet Explorer But I need to configure that rule on a windows server 2003 sp2, but does not appear, but If I look on a Windows 2008 the rule it's there. So the question is how can update my rule list on a windows server 2003? Thanks

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  • 6TO4 Windows 2003 DNS

    - by OptimAdam
    This is puzzling me a bit. We are running server 2003 DNS/DHCP and normally we disable IPV6 on the client end. But I have just noticed with windows 7 and server 2008 R2 if I disable IPv6 then it registers an 6TO4 address in DNS not its Standard IP address. If I enable IPv6 it registers its ip. Can anyone explain why this is? Regards Adam

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  • Interviewing a DBA

    - by kev
    Our Company is in the Process of recuiting a DBA. I have built a group test of questions from basic questions such as Pk and Fk constraints, simple querries(fizzbuzz style) to more advanced things such as indexes, Collation, isolation levels and how to trace deadlocks. However, that is the limit of my knowledge. So my question to all the DBA's is what is the base level knowledge that all DBA's should have? We are really looking for someone that will be able to manage our replication, analyzing some of our slower running queries(that the devs can go to for help) and someone that can trace some of the deadlock issues that we are having. Any help would be most appreciated!

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  • Adding Actions to a Cube in SQL Server Analysis Services 2008

    Actions are powerful way of extending the value of SSAS cubes for the end user. They can click on a cube or portion of a cube to start an application with the selected item as a parameter, or to retrieve information about the selected item. Actions haven't been well-documented until now; Robert Sheldon once more makes everything clear.

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  • telephony + exchange 2010 (unified messaging)

    - by Aceth
    ok i am a complete n00b when it comes to telephony ... i was wondering we are beginning to play with exchange 2010 in the office ... How can i connect a telephone line into the server? so we can ring in and get our emails via phone (we have a spare direct line) I'm going to guess it's not as easy as sticking a 56k modem into the server? Cheers

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  • Windows SBS 2003 Remote Desktop Problem

    - by david.healed
    Hi, I used to remote access the SBS 2003 server through RDC and it has been working all the time but now I am unable to connect to the server. Whenever I pressed the "Connect" button on the Remote Desktop Connection dialog, a dialog with messages like "Connecting to: xx.xx.xx.xx" and "Configuring remote session..." appeared and then disappeared quickly, leaving the Remote Desktop Connection dialog there. How to fix the problem? Thank you.

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