Search Results

Search found 8646 results on 346 pages for 'echo flow'.

Page 75/346 | < Previous Page | 71 72 73 74 75 76 77 78 79 80 81 82  | Next Page >

• why my image path is not taken?

  - by udaya

  Hi I am getting the image path from database in this foreach foreach($image as $row){ $value = $row['dPath']; $imgpath =base_url()."images/".$value;//this is not taken $imgpath = base_url()."images/con_icon.jpg";//this$imgpath is taken echo $value; when i give $imgpath as $imgpath = base_url()."images/con_icon.jpg"; it is accepted in <img src="<?php echo $imgpath; ?>" and image is displayed But when i give $imgpath as $imgpath =base_url()."images/".$value; but echo $value; results con_icon.jpg The image is not displayed what is the problem

  Read the article

• iphone app store rss failed to open

  - by suvendu

  I write this, $opts = array( 'http' = array( 'user_agent' = 'PHP libxml agent', ) ); $context = stream_context_create($opts); libxml_set_streams_context($context); $doc = new DOMDocument(); $doc-load("http://ax.itunes.apple.com/WebObjects/MZStoreServices.woa/ws/RSS/toppaidapplications/limit=25/xml"); foreach ($doc-getElementsByTagName('item') as $node) { $title = $node-getElementsByTagName('title')-item(0)-nodeValue; $desc = $node-getElementsByTagName('description')-item(0)-nodeValue; $link = $node-getElementsByTagName('link')-item(0)-nodeValue; $date = $node-getElementsByTagName('pubDate')-item(0)-nodeValue; echo $title; echo '<br>'; echo $desc; } ?

  Read the article

• PHP - How can I check if return() was called from an include()'d file?

  - by John Himmelman

  How can I tell if return() was called from within the included file. The problem is that include() returns 'int 1', even if return() wasn't called. Here is an example... included_file_1.php <?php return 1; included_file_2.php <?php echo 'no return here, meep'; main.php <?php $ret = include('included_file_1.php'); // This file DID return a value, int 1, but include() returns this value even if return() wasn't called in the included file. if ($ret === 1) { echo 'file did not return anything'; } var_dump($ret); $ret = include('included_file_2.php'); // The included file DID NOT return a value, but include() returns 'int 1' if ($ret === 1) { echo 'file did not return anything'; } var_dump($ret);

  Read the article

• Accessing XML/PHP with period in tag

  - by LuckyShot

  Hi guys, Quick newbie question here, how do I access totalResults? XML <?xml version="1.0" encoding="UTF-8"?> <OpenSearchDescription> <opensearch:totalResults>1</opensearch:totalResults> <posts> <post> <score>10</score> </post> </posts> </OpenSearchDescription> To access the score I would do this: PHP $xmlObj = simplexml_load_string($theXMLabove); echo $xmlObj->posts->post[0]->score; But none of these work for the totalResults: echo $xmlObj->opensearch:totalResults; echo $xmlObj->opensearch->totalResults; Sorry for asking such a lame question... Documentation on how to traverse XML with PHP is also appreciated :) Thanks!

  Read the article

• Bash script to (more or less) reliably check if the internet is up

  - by João Portela

  I need a bash script to put in a cron job that every minute checks if the internet is up. This is how I did it: #! /bin/sh host1=google.com host2=wikipedia.org curr_date=`date +"%Y%m%d%H%M"` echo -n "${curr_date};" ((ping -w5 -c3 $host1 || ping -w5 -c3 $host2) > /dev/null 2>&1) && echo "up" || (echo "down" && exit 1) How would you do it? Which hosts would you ping? Thanks in advance.

  Read the article

• Ruby - Passing Blocks To Methods

  - by Chris Bunch

  I'm trying to do Ruby password input with the Highline gem and since I have the user input the password twice, I'd like to eliminate the duplication on the blocks I'm passing in. For example, a simple version of what I'm doing right now is: new_pass = ask("Enter your new password: ") { |prompt| prompt.echo = false } verify_pass = ask("Enter again to verify: ") { |prompt| prompt.echo = false } And what I'd like to change it to is something like this: foo = Proc.new { |prompt| prompt.echo = false } new_pass = ask("Enter your new password: ") foo verify_pass = ask("Enter again to verify: ") foo Which unfortunately doesn't work. What's the correct way to do this?

  Read the article

• Passing CMD Results to Variable in a Batch File

  - by TripleNad

  I am trying to install an application and a group of services using PSTools, but I want to take into account that the computer I am trying to connect to may be turned off or on a different network, which is not reachable from the internal network. Basically if the machine is not able to be accessed through the admin share, this is the message that I am getting: Couldn't access MachineName: The network path was not found. Make sure that the default admin$ share is enabled on MachineName. This is the syntax I am using to try to capture the "Error Message" and then report back that if installation was successful or not (depending on if it can contact the machine) @echo off set /p name=What is the machine name?: psexec.exe \\\%name% -u *useraccount* -p *password* \\\ServerName\installation.bat FOR /F "tokens=*" %%A IN ('COMMAND ^| FIND "Couldn't access"') DO SET Error=%%A If "%Error%"=="Couldn't access" ECHO Installation Failed. Else ECHO Installtion complete. Pause exit Currently it hangs right at the point it's defining the Error Variable. Can't quite figure out what I am going wrong here.

  Read the article

• Displaying name instead of ID PHP MySQL

  - by Derek

  Hi, I need something simple; I have page where a user clicks an author to see the books associated with that author. On my page displaying the list of books for the author, I want a simple HTML title saying: 'The books for: AUTHORNAME' I can get the page to display author ID but not the name. When the user clicks the link in the previous page of the author, it looks likes this: <a href="viewauthorbooks.php?author_id=<?php echo $row['author_id']?>"><?php echo $row['authorname']?></a> And then on the 'viewauthorbooks.php?author_id=23' I have declared this at the start: $author_id = $_GET['author_id']; $authorname = $_GET['authorname']; And finally, 'The books for: AUTHORNAME, where it says AUTHORNAME, I have this: echo $authorname (With PHP tags, buts its not letting me put them in!) And this doesnt show anything, however if I change it to author_id, it displays the correct author ID that has been clicked, but its not exactly user friendly!! Can anyone help me out!

  Read the article

• PHP - How to retrieve session in php

  - by Klaus Jasper

  I created a table that contains id - names - jobs and page that shows the names only and beside each name there is button Job and session that contains the id. this is my code $query = mysql_query("SELECT * FROM table"); while($fetch = mysql_fetch_array("$query")){ $name = $fetch['names']; $id = $fetch['id']; echo '</br>'; echo $name; $_SESSION['name'] = $id; echo "<button>Job</button>"; } I want when the user click on button Job redirect to a page that contains the job of that session. so how can I do it?

  Read the article

• Fancybox The requested content cannot be loaded. Please try again later

  - by user964836

  <link rel="stylesheet" href="<?php echo $this->getSkinUrl(''); ?>js/fancybox/source/jquery.fancybox.css?v=2.0.6" type="text/css" media="screen" /> <script type="text/javascript" src="<?php echo $this->getSkinUrl(''); ?>js/fancybox/source/jquery.fancybox.pack.js?v=2.0.6"></script> <script type="text/javascript"> $(document).ready(function() { $("a#image").fancybox(); $("a#image").trigger('click'); $("a#image").hide(); }); <a id="image" href="banner-about-cart.png"><img src="<?php echo $this->getSkinUrl() ?>images/banner-about-cart.png" alt=""/></a> any idea? the image loding i test whitout fancy plugin i can see image in site, i usind magento as well

  Read the article

• Getting Undefined index errors when trying to use $_POST

  - by Apoorv Agrawal

  I'm getting the following error messages: Notice: Undefined index: name in C:\xampp\htdocs\ApoorvProject\PostMethod.php on line 7 Notice: Undefined index: email in C:\xampp\htdocs\ApoorvProject\PostMethod.php on line 9 This is what line 7 and line 9 contains: echo $_POST["name"]; echo "<br>"; echo $_POST["email"]; This is the body of my HTML documnent: <form action="PostMethod.php" method="post"> Name: <input type="text" name="name" /> Email: <input type="text" name="email" /> <input type="submit" /> </form> PostMethod.php is the name of my PHP file.

  Read the article

• generate php classes in bash

  - by Derek

  i have this script: #!/bin/bash if [[ -z "$1" ]] ; then echo "Class is required" exit 1; fi if [[ -z "$2" ]] ; then package="Default" else package=$2; fi echo "<?php /** * $1.class.php * * Vcard class file. * @name Project * @author Author * @link http://www.domain.com * @copyright Copyright © 2011 * @package $package * @version 1.0 */ /** * The main $1 class * @package $package */ class $1 { /** * Constructor setup. */ public function __construct() { } /** * Destructor setup. */ public function __destruct() { } } " > $1.class.php php -l $1.class.php echo "Done"; if i do: ./generate.sh my_class it creates everything with my_class. how can i modify this to: MyClass? i need to use MyClass for the filename, and the class name etc... later in the code i use the argument (in this case my_class) for some other purposes. thanks

  Read the article

• how to remove trailing and leading whitespace for user-provided input in dos?

  - by OopOop

  I know how to do this when the variable is pre-defined. However, when asking for the user to enter in some kind of input, how do I trim leading and trailing whitespace? This is what I have so far: @echo off set /p input=: echo. The input is %input% before ::trim left whitespace for /f "tokens=* delims= " %%a in ("%input%") do set input=%%a ::trim right whitespace (up to 100 spaces at the end) for /l %%a in (1,1,100) do if "!input:~-1!"==" " set input=!input:~0,-1! echo. The input is %input% after pause Thank you! :)

  Read the article

• Kernel module for /proc

  - by sb2367

  How to write a kernel module that creates a directory in /proc named mymod and a file in it name is mymodfile. This file should accept a number ranged from 1 to 3 when written into it and return the following messages when read based on the number already written into it: • 1: Current system time (in microseconds precision) • 2: System uptime • 3: Number of processes currently in the system “The Output” root@Paradise# echo 1 > /proc/mymod/mymodfile root@Paradise# cat /proc/mymod/mymodfile 08:30:24 342us root@Paradise# echo 2 > /proc/mymod/mymodfile root@Paradise# cat /proc/mymod/mymodfile up 1 day, 8 min root@Paradise# echo 3 > /proc/mymod/mymodfile root@Paradise# cat /proc/mymod/mymodfile process count: 48 please give me some hint how to write a kernel modules and how to compile and install it .

  Read the article

• Adding an additional link button to a form (using form->create)

  - by cloudhead

  I have recently been assigned a CSS & design project that's in a CakePHP environment and would like to know if I can add an additional button to the form, for a "sign up" link. The form is currently: echo $form->create('User', array('action' => 'login')); echo $form->inputs(array( 'legend' => 'Please log in:', 'username', 'password')); echo $form->end('Login'); I would like to inject a button that goes to an action of 'register', preferably after the "Login" button, on the same line, like this: username: [ ] password: [ ] [Log In] [Register] I have everything but the 'register' button. Is this possible using the 'automagic' form creation? Thank you.

  Read the article

• Solve code issue - string identity testing

  - by kovibb

  Please for help with shell script. I really dont understand where is problem. Where I write to the Input variable for example /home/Kovi/Deskop/netlist.exe I still get true answer but the extension "exe" is not "scs". I also try "==" but it didnt working. Please some advice. Thank you very much. echo -n "Insert Entire Path (with file name and it's extension) of Input Netlist > " read Input if [ "${Input##*.}"="scs" ]; then echo "Patch verification is succesful.; else echo "Patch verification is failed, script was aborted. File dont exist or is empty or unreadable or is not spectre netlist." error_exit; fi

  Read the article

• uploading different types of files mostly pdfs

  - by Anders Kitson

  I would like to upload different types of files pressumably pdfs to a certain directory I am currently trying to get this one script working that I found on snipplr but it is not working as I assumed it would, here is my code. <?php if( isset($_POST['submit']) ) { $target_path = "../downloads/"; $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name'])." has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } } ?> <form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post" enctype="multipart/form-data"> <input type="file"> <input type="submit" name="submit" value="submit" /> </form>

  Read the article

• How to check whether a mysql select statement result has a value or not in php?

  - by udaya

  I have a textbox UserName and a Check Availability button next to it..... I have checked the availability by passing UserName textbox value..... But it doesn't seem to work.... Here is what i am doing? echo $UserName = $_GET['CheckUsername']; $_SESSION['state'] = $State; $queryres = "SELECT dUser_name FROM tbl_login WHERE dUser_name='$UserName'"; $result = mysql_query($queryres,$cn) or die("Selection Query Failed !!!"); if($result==true) // this condition doesn't seem to work { echo "User Name Available"; } else { echo "Sorry user name taken"; }

  Read the article

• please explain the dataflow in MVC specially in codeigniter

  - by pokhara

  Dear friends, Can anyone please explain me the object flow in codeigniter MVC ? I can see for example when I put the followong code in controller it works, but i am not being able to figure out which part of this goes in model in vews. I tried several ways but coudn't. When i use the example codes from other it works but myself i am getting confused. Please help $query = $this->db->query("YOUR QUERY"); foreach ($query->result() as $row) { echo $row->title; echo $row->name; echo $row->body; }

  Read the article

• bash check if value in list

  - by tkoomzaaskz

  I've got a script with a variable taken from command line parameters. I want to check if it's value is one of dev, beta or prod. I've got following code snippet: #!/usr/bin/env bash ENV_NAME=$1 echo "env name = $ENV_NAME" ENVIRONMENTS=('dev','beta','prod') if [[ $ENVIRONMENTS =~ $ENV_NAME ]]; then echo 'correct' exit else echo 'incorrect' exit fi When I run my script, it doesn't matter which parameters I pass: ./script.sh beta or ./script.sh or ./script.sh whatever, I always get correct echoed. What is wrong in my script?

  Read the article

• check for several conditions when a user logs in

  - by paul

  I would like to accomplish the following: If a username or password field is null, notify the user. If user name already exists, do not insert into the database and notify user to create a different name. if the username is unique and password is not null, return the username to the user. As of now it always returns "Please enter a different user name." I believe the issue has to do with the database query but I am not sure. If anyone can have a look and see if I am making an error, I greatly appreciate it, thanks. if ($userName or $userPassword = null) { echo "Please enter a user name and password or return to the homepage."; } elseif (mysql_num_rows(mysql_query("SELECT count(userName) FROM logininfo WHERE userName = '$userName'")) ==1) { echo "Please enter a different user name."; } elseif ($userName and $userPassword != null) { echo "Your login name is: $userName"; }

  Read the article

• How to display the found matches of preg_match function in PHP?

  - by Eric

  I am using the following to check if links exist on file.php: $fopen = fopen('file.php', 'r'); $fread = fread($fopen, filesize('file.php')); $pattern = "/^<a href=/i"; if (preg_match($pattern, $fread)) { echo 'Match Found'; } else { echo 'Match Not Found'; } if I echo preg_match($pattern, $fread) I get a boolean value, not the found matches. I tried what was on the php.net manual and did this: preg_match($pattern, $fread, $matches); then when I echoed $matches I got "Array" message. So I tried a foreach loop and when that didn't display anything I tried $matches[0] and that too outputted nothing. So how does one go about displaying the matches found?

  Read the article

• if then endif , other smart solution in place of if then ....

  - by yael

  I have the following VB script How to write this VB script with case syntax? In order to perform professional writing in place if then…. yael Set fso = CreateObject("Scripting.FileSystemObject") If (fso.FileExists("C:\file1 ")) Then Verification=ok Else WScript.Echo("file1") Wscript.Quit(100) End If If (fso.FileExists("C:\file2 ")) Then Verification=ok Else WScript.Echo("file2") Wscript.Quit(100) End If If (fso.FileExists("C:\file3 ")) Then Verification=ok Else WScript.Echo("file3") Wscript.Quit(100) End If . . . .

  Read the article

• retrieved upload images in php

  - by hunter

  i want to retrieve image from client (ipod) programmed in objective c i use the following code $TARGET_PATH = "pics/"; $image = $_FILES['photo']; $TARGET_PATH =$TARGET_PATH . basename( $_FILES['photo']['name']); $TARGET_PATH =$TARGET_PATH.".jpg"; if(file_exists($TARGET_PATH)) { $TARGET_PATH =$TARGET_PATH .uniqid() . ".jpg"; } if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { $TARGET_PATH="http://www.".$_SERVER["SERVER_NAME"]."/abc/".$TARGET_PATH; echo $TARGET_PATH; echo "image upload successfully";} else{ echo "could not upload image"; } this code upload five to six images successfully and after that it gives me error i.e Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 42 Notice: Undefined index: photo in /home/abc/public_html/abc.com/fish/mycatch_post.php on line 53 could not upload image

  Read the article

• convert Bash command to php

  - by Keverw

  This is the bash command echo -n x && (echo 618cf954-6576-491d-8ac6-a1b888c4705d |xxd -r -p |openssl base64|tr '/+' '_-') This is my php <? $uuid = "618cf954-6576-491d-8ac6-a1b888c4705d"; $voiceid = "x" . $uuid; $voiceid = base64_encode($voiceid); $voiceid = str_replace("+", "-", $voiceid); $voiceid = str_replace("/", "_", $voiceid); echo $voiceid; ?> The bash gives the right output, the php one isn't. I'm not sure what i need to do deferent in php.

  Read the article

< Previous Page | 71 72 73 74 75 76 77 78 79 80 81 82  | Next Page >