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  • did you know some good web site about 'iphone css layouts' ,and can you help me to improve my code..

    - by zjm1126
    i want to create a webpage on iphone , but i can't complete it in a simple way, this is my code: <!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mobile 1.0//EN" "http://www.wapforum.org/DTD/xhtml-mobile10.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width,minimum-scale=1.0,maximum-scale=5.0,user-scalable=yes"> </head> <body onorientationchange="updateOrientation();" onload=updateOrientation()> <div id="a"> <input id='ab' type="button" value="button" /> </div> <div id=b style="display: none">sssadwq dwqdqw</div> <style type="text/css"> *{ margin:0; padding:0; } /* Reposition on orientation change */ body.landscape{ height: 268px; } body.landscape #a{ height:134px; line-height:134px; } body.landscape #b{ height:114px; width:470px; } body{ height: 416px; } #a{ line-height:208px; height:208px; text-align:center; } #b{ height:198px; width:310px; background:red; border:5px solid black; } </style> <script src="jquery-1.4.2.js" type="text/javascript"></script> <script type="text/javascript"> function updateOrientation() { var orientation = window.orientation; switch (orientation) { // If we're horizontal case 90: case -90: // Set orient to landscape $(document.body).addClass("landscape"); break; // If we're vertical default: // Set orient to portrait $(document.body).removeClass("landscape"); break; } } $('#ab').click(function(){ if($('#b').css('display')=='none')$('#b').css('display','block') else $('#b').css('display','none') }) </script> </body> </html> it use much more fixed number,this is not the best way ,i think the best way is to use the percentage more and more, can you do it fo me ,, thanks

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  • How can I get the fully qualified name of an assembly from it's basic name?

    - by GenericTypeTea
    I'm currently writing a custom forms application that allows a user to design a data capture form. I store the field's ControlType and ControlAssembly in the database and then create them on the forms at runtime. For example: ControlType = `System.Web.UI.WebControls.TextBox`. ControlAssembly= `System.Web`. So I can therefor create a fully qualified name and create the control doing the following: string target = Assembly.CreateQualifiedName("System.Web", field.ControlType); Type type = Type.GetType(target); Control control = Activator.CreateInstance(type) as Control; But, this will cause an error as "System.Web" is not a valid assembly name. The assembly name itself has to be fully qualified, i.e. System.Web.Extensions would be: "System.Web.Extensions, Version=1.0.61025.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35" Is there any way I can get the fully qualified name of the assembly System.Web without having to store the entirity of the version, culture and PKT?

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  • How can I debug this web service http handler?

    - by baron
    Hello everyone, I am building a Httphandler following these instructions here It manipulates HTTP POST and HTTP GET. I have a client with two buttons two POST and GET. After i've tested and happy everythings working I move it from localhost to IIS. Now when I do this I get an exception in the POST handler code. How on earth can I debug this code line by line? I managed to do this awhile ago, I thought it was by attaching to process but I can't work it out. I can emulate GET just by typing address in browser, post im not sure about. I've tried telnetting and sending it from there but haven't had any luck.

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  • Doing things depending of the action in a web page with Jquery.

    - by l2mt
    Hi... Anyone know how to do this: When some user left my site by closing the browser or tab or going to other site I would like to do an action (show an alert) and if the user clicks on a link or button to other page of my own site I would like to do another action... If I use unload event I can't differentiate between these two kind of behavior of the user... please help because I really need it. Thanks for the help.

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  • How to plan my web based project before starting code ?

    - by Arsheep
    Me and my friend started working together as partners , we have decided to make Kick-as* website after website. We have the ideas written down like 100's of them (yes we are choosing best and easy among them first). My friend does the layout design and arranging things , and my part is coding and server management. The little problem i am facing is lack of experience in planing a project. What i do is, I just start the code straight away and along with code I make DB, like when i need a table i make it. I know this is very bad approach for a medium sized project. Here at stackoverflow i saw lots of experienced coders. Need to learn a lot from you guys :) . So can you plese help me on how to plan a project and what coding standard/structure/frameworks to be used (I do PHP code). Thanks in advance.

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  • problem with opening link through safari with webview

    - by Desmond
    hi i had encounter a problem opening a web link through safari. this is my code header #import <UIKit/UIKit.h> @interface qrcode_info : UIViewController <UIWebViewDelegate,UIAlertViewDelegate> { } @property (nonatomic, retain) IBOutlet UIWebView *Web; @end //main file #import "qrcode_info.h" @implementation qrcode_info @synthesize Web; -(BOOL)Web:(UIWebView *)Web shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType { if (navigationType == UIWebViewNavigationTypeLinkClicked) { [[UIApplication sharedApplication] openURL:[request URL]]; return NO; } return YES; } //[[UIApplication sharedApplication] openURL:[inRequest URL]]; //return NO; - (void)viewDidLoad { [super viewDidLoad]; [Web loadRequest:[NSURLRequest requestWithURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] pathForResource:@"help" ofType:@"html"] isDirectory:NO]]]; //self.wvTutorial = [[WebViewController alloc] initWithNibName:@”WebView” bundle:[NSBundle mainBundle]]; }

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  • How to configure multiple web site with django and tornado?

    - by mapcuk
    On my VDS I use nginx, django and tornado. I had just one project, Now i gonna deploy another one project with a different domain name. I want to use different databases and folders. I know how to configure nginx for serving static resourses , but what about tornado? Should i run separeted instance of tornado for each project or is there any better solution?

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  • Spring transaction management breaks hibernate cascade

    - by TimmyJ
    I'm having a problem where the addition of spring's transaction management to an application causes Hibernate to throw the following error: org.hibernate.HibernateException: A collection with cascade="all-delete-orphan" was no longer referenced by the owning entity instance: org.fstrf.masterpk.domain.ReportCriteriaBean.treatmentArms org.hibernate.engine.Collections.processDereferencedCollection(Collections.java:96) org.hibernate.engine.Collections.processUnreachableCollection(Collections.java:39) org.hibernate.event.def.AbstractFlushingEventListener.flushCollections(AbstractFlushingEventListener.java:218) org.hibernate.event.def.AbstractFlushingEventListener.flushEverythingToExecutions(AbstractFlushingEventListener.java:77) org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:26) org.hibernate.impl.SessionImpl.flush(SessionImpl.java:1000) org.springframework.orm.hibernate3.SpringSessionSynchronization.beforeCommit(SpringSessionSynchronization.java:135) org.springframework.transaction.support.TransactionSynchronizationUtils.triggerBeforeCommit(TransactionSynchronizationUtils.java:72) org.springframework.transaction.support.AbstractPlatformTransactionManager.triggerBeforeCommit(AbstractPlatformTransactionManager.java:905) org.springframework.transaction.support.AbstractPlatformTransactionManager.processCommit(AbstractPlatformTransactionManager.java:715) org.springframework.transaction.support.AbstractPlatformTransactionManager.commit(AbstractPlatformTransactionManager.java:701) org.springframework.transaction.interceptor.TransactionAspectSupport.commitTransactionAfterReturning(TransactionAspectSupport.java:321) org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:116) org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:171) org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:204) $Proxy92.saveNewReportCriteria(Unknown Source) org.fstrf.masterpk.domain.logic.MasterPkFacade.saveNewReportCriteria(MasterPkFacade.java:134) org.fstrf.masterpk.controllers.ReportCriteriaController.setupReportType(ReportCriteriaController.java:302) sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) java.lang.reflect.Method.invoke(Method.java:585) org.springframework.web.bind.annotation.support.HandlerMethodInvoker.doInvokeMethod(HandlerMethodInvoker.java:413) org.springframework.web.bind.annotation.support.HandlerMethodInvoker.invokeHandlerMethod(HandlerMethodInvoker.java:134) org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.invokeHandlerMethod(AnnotationMethodHandlerAdapter.java:310) org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter.handle(AnnotationMethodHandlerAdapter.java:297) org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:875) org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:809) org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:571) org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:511) javax.servlet.http.HttpServlet.service(HttpServlet.java:710) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.jboss.web.tomcat.filters.ReplyHeaderFilter.doFilter(ReplyHeaderFilter.java:96) I'm using Spring 2.5 and annotations to implement this management. Here is the class containing the saveNewReportCriteria method (which, as can be seen by the stack trace, is causing the error) @Transactional( propagation = Propagation.REQUIRED, isolation = Isolation.DEFAULT, readOnly = false) public class HibernateReportCriteriaDao implements ReportCriteriaDao{ private HibernateTemplate hibernateTemplate; public Integer saveNewReportCriteria(ReportCriteriaBean reportCriteria) { hibernateTemplate.save(reportCriteria); List<Integer> maxIdList = hibernateTemplate.find("SELECT max(id) from ReportCriteriaBean"); logger.info("ID of newly saved list is: " + maxIdList.get(0)); return maxIdList.get(0); } public void setHibernateTemplate(HibernateTemplate hibernateTemplate) { this.hibernateTemplate = hibernateTemplate; } } Then I added the following sections to my configuration files to tell spring that I am using annotation driven transaction management: <bean id="actgDataSource" class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName" value="jdbc/actg" /> <property name="resourceRef" value="true" /> </bean> <bean id="transactionManager" class="org.springframework.jdbc.datasource.DataSourceTransactionManager"> <property name="dataSource" ref="actgDataSource" /> </bean> <tx:annotation-driven/> I'm pretty sure that the de-referencing error is being caused due to the proxy class that Spring AOP creates and uses in order to handle transaction management, but I have no idea how I'd go about fixing it.

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  • Launch a new page in Zend/php on button click

    - by BlueMonster
    PHP & Zend Noob here I've downloaded the skeleton project from here: https://github.com/zendframework/ZendSkeletonApplication Say i want to open a new page that simply displays "hello world" text if click on the "ZF2 Development Portal" button(bottom left green button) on the page that launches --- how do i do this? See image: I've read through this tutorial, but i'm not sure how the model, view, or controller are actually launched? See tutorial: http://blog.wilgucki.pl/2012/07/tworzenie-modulw-w-zend-framework-2.html From looking at the code, i know that i will have to change this line of code: <div class="span4"> <h2><?php echo $this->translate('Follow Development') ?></h2> <p><?php echo sprintf($this->translate('Zend Framework 2 is under active development. If you are interested in following the development of ZF2, there is a special ZF2 portal on the official Zend Framework website which provides links to the ZF2 %swiki%s, %sdev blog%s, %sissue tracker%s, and much more. This is a great resource for staying up to date with the latest developments!'), '<a href="http://framework.zend.com/wiki/display/ZFDEV2/Home">', '</a>', '<a href="http://framework.zend.com/zf2/blog">', '</a>', '<a href="http://framework.zend.com/issues/browse/ZF2">', '</a>') ?></p> <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> </div> More specifically this line: <p><a class="btn btn-success" href="http://framework.zend.com/zf2" target="_blank"><?php echo $this->translate('ZF2 Development Portal') ?> &raquo;</a></p> but i'm really confused as to what i'm supposed to change it to in order to launch a new page. Any ideas? Thanks in advance!

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  • ASP.NET Controls Not Recognized

    - by Liam
    I just installed the release version of Visual Studio 2010, and it looks like there's something wrong with the standard ASP.NET server controls. When I create a basic server control, such as a TextBox, the editor underlines it in green and says (I also get no intellisense for ASP.NET controls): Element 'TextBox' is not a known element. This can occur if there is a compilation error in the Web site, or the Web.config file is missing. The web site builds fine, and the Web.config file is not missing: <?xml version="1.0"?> <configuration> <system.web> <compilation debug="false" targetFramework="4.0" /> </system.web> </configuration> The controls work just fine in the code-behind, and they function correctly when I run the site. Is there some configuration problem here?

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  • Any particular reason why FaceBook's Subscribe Button isn't showing on my web page?

    - by Axonn
    I got this FaceBook profile for my upcoming website and I can't get the Subscribe button to show, NOT EVEN ON FaceBook's page! http://www.facebook.com/profile.php?id=100003492130845 Now, if you go here on FaceBook's page where we build the Subscribe button: http://developers.facebook.com/docs/reference/plugins/subscribe/ And add the above link, it will show nothing. I enabled subscribing and I also created myself a page, linked to the same profile: http://www.facebook.com/pages/Axonn-Says/372194956141393 But not even the page works ::- /. LATER EDIT: I temporarily added 2 other Subscribe buttons on my website to demonstrate that it works for example for Mark Zuck's page and to demonstrate that there are no JS conflicts. The 2 buttons appeared ok, but my button still didn't show up.

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  • any way to get sharepoint groups with a given site url

    - by standley-nguyen
    Hi all. I'm getting a stuck. Suppose that I create 5 sites. For each one, I create a few sharepoint groups. So, I create a dropdownlist control to bind 5 sites and when I click on any site there, I will get sharepoint groups created on it. But I always see the dropdownlist used to bind these groups still never change. I mean it only binds a few default groups in sahrepoint everytime. The new created groups is not. And I have confusion like this web.AssociatedGroups web.Groups web.SiteGroups which one we will use this case ? Please guide me Here my snippet code private void BindSPGroupsToDropDownList(DropDownList ddl, string siteUrl) { ddl.Items.Clear(); try { SPSecurity.RunWithElevatedPrivileges(delegate() { using (SPSite site = new SPSite(siteUrl)) { using (SPWeb web = site.OpenWeb()) { //web.SiteGroups foreach (SPGroup spGroup in web.Groups) { ddl.Items.Add(new ListItem(spGroup.Name.Trim(), spGroup.ID.ToString())); } } } }); } } thanks in advance

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  • I want to use VI-like commands in Web Browser?

    - by Frank
    I love VI and I'm looking for a plugin of some sort that would allow me to input text in my browser (preferably Firefox or Chrome) using VI commands. It would save me an immense amount of time and at the same time when writing long emails. Can anyone think of any plugins that would allow me to do this? I was hopeful with Vimperator (https://addons.mozilla.org/en-US/firefox/addon/4891) but after installing it, I realized that it didn't do the one VI think I wanted to do: create or edit a text box with VI commands. It just allowed me to do Browser commands and scrolling in VI-style.

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  • Dashcode Web App: How to programmatically manipulate bound array in dataSource?

    - by Kross
    Hi Everyone, I've started using Dashcode to write an interface for presenting the report data for some of our Cocoa tools. I am using a Dashcode data source and bindings to populate the elements in the WebView, and it all seems to be working well so far. One of the objects in my dataSource is an array of objects that I would like to manipulate programmatically. I can change the object values in the array just fine but if I want to replace the array, or any objects in the array, my bound table isn't able to observe the added objects. Here is the code that I thought would let me easily replace the bound array with new content: var dataSource = dashcode.getDataSource("reportData"); var newDetailArray = testArray(); dataSource.setValueForKeyPath(newDetailArray, "content.detailArray"); But this throws the exception: Exception while binding "content" to keypath "arrangedObjects " TypeError: Result of expression 'this.object.valueForKeyPath' [undefined] is not a function. Is there something I'm missing that will let me easily manipulate the array's contents programmatically?

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