Search Results

Search found 35068 results on 1403 pages for 'adam right'.

Page 76/1403 | < Previous Page | 72 73 74 75 76 77 78 79 80 81 82 83  | Next Page >

  • Setting height of div equal to containing div

    - by Syom
    i have the following simple script <div id="content"> <div id="left"> <div id="menu"> <ul> <li>menu</li> </ul> </div> <div id="left_ad"> </div> </div> <div id="middle"> some text here... </div> <div id="right"> <div id="right_ad"> <div id="ad2"> </div> </div> </div> </div> css: #content { margin: 0; padding: 0; overflow: hidden; position: relative; } #left { float: left; width:25%; margin-left:0; margin-right:0; margin-top:0; margin-bottom:-5000px; padding-left:0; padding-right:0; padding-top:0; padding-bottom:5000px; } #middle { background-image:url("http://localhost/kino/img/theme.png"); background-repeat:no-repeat; float: left; width:50%; margin-left:0; margin-right:0; margin-top:0; margin-bottom:-5000px; padding-left:0; padding-right:0; padding-top:0; padding-bottom:5000px; } #right { float: left; width:25%; margin-left:0; margin-right:-1px; margin-top:0; margin-bottom:-5000px; padding-left:0; padding-right:0; padding-top:0; padding-bottom:5000px; } #left_ad { background-image:url("http://localhost/kino/img/lens1.png"); background-repeat:no-repeat; min-height:498px; margin-left: auto; margin-right: auto; margin-top:31px; padding:0; width: 188px; position: relative; height: 100%; } as you see, left, middle and right have the same size of heigth, which is equal to max of them. and now, what is the question, i want left_ad to have the same heigth too. how can i set the heigth of left_id is equal to left? thanks

    Read the article

  • setting heigth of div equal to containing div

    - by Syom
    i have the following script <div id="content"> <div id="left"> <div id="menu"> <ul> <li>menu</li> </ul> </div> <div id="left_ad"> </div> </div> <div id="middle"> some text here... </div> <div id="right"> <div id="right_ad"> <div id="ad2"> </div> </div> </div> </div> css: #content { margin: 0; padding: 0; overflow: hidden; position: relative; } #left { float: left; width:25%; margin-left:0; margin-right:0; margin-top:0; margin-bottom:-5000px; padding-left:0; padding-right:0; padding-top:0; padding-bottom:5000px; } #middle { background-image:url("http://localhost/kino/img/theme.png"); background-repeat:no-repeat; float: left; width:50%; margin-left:0; margin-right:0; margin-top:0; margin-bottom:-5000px; padding-left:0; padding-right:0; padding-top:0; padding-bottom:5000px; } #right { float: left; width:25%; margin-left:0; margin-right:-1px; margin-top:0; margin-bottom:-5000px; padding-left:0; padding-right:0; padding-top:0; padding-bottom:5000px; } #left_ad { background-image:url("http://localhost/kino/img/lens1.png"); background-repeat:no-repeat; min-height:498px; margin-left: auto; margin-right: auto; margin-top:31px; padding:0; width: 188px; position: relative; height: 100%; } as you see, left, middle and right are have the same size of heigth, which is equal to max of them. and now, what is the question, i want left_ad to have the same heigth too. how can i set the heigth of left_id is equal to left? thanks

    Read the article

  • How to set BackGround color to a divider in JSplitPane

    - by Sunil Kumar Sahoo
    I have created a divider in JSplitPane. I am unable to set the color of divider. I want to set the color of divider. please help me how to set color of that divider import javax.swing.; import java.awt.; import java.awt.event.*; public class SplitPaneDemo { JFrame frame; JPanel left, right; JSplitPane pane; int lastDividerLocation = -1; public static void main(String[] args) { SplitPaneDemo demo = new SplitPaneDemo(); demo.makeFrame(); demo.frame.addWindowListener(new WindowAdapter() { public void windowClosing(WindowEvent e) { System.exit(0); } }); demo.frame.show(); } public JFrame makeFrame() { frame = new JFrame(); // Create a horizontal split pane. pane = new JSplitPane(JSplitPane.HORIZONTAL_SPLIT); left = new JPanel(); left.setBackground(Color.red); pane.setLeftComponent(left); right = new JPanel(); right.setBackground(Color.green); pane.setRightComponent(right); JButton showleft = new JButton("Left"); showleft.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { Container c = frame.getContentPane(); if (pane.isShowing()) { lastDividerLocation = pane.getDividerLocation(); } c.remove(pane); c.remove(left); c.remove(right); c.add(left, BorderLayout.CENTER); c.validate(); c.repaint(); } }); JButton showright = new JButton("Right"); showright.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { Container c = frame.getContentPane(); if (pane.isShowing()) { lastDividerLocation = pane.getDividerLocation(); } c.remove(pane); c.remove(left); c.remove(right); c.add(right, BorderLayout.CENTER); c.validate(); c.repaint(); } }); JButton showboth = new JButton("Both"); showboth.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { Container c = frame.getContentPane(); c.remove(pane); c.remove(left); c.remove(right); pane.setLeftComponent(left); pane.setRightComponent(right); c.add(pane, BorderLayout.CENTER); if (lastDividerLocation >= 0) { pane.setDividerLocation(lastDividerLocation); } c.validate(); c.repaint(); } }); JPanel buttons = new JPanel(); buttons.setLayout(new GridBagLayout()); buttons.add(showleft); buttons.add(showright); buttons.add(showboth); frame.getContentPane().add(buttons, BorderLayout.NORTH); pane.setPreferredSize(new Dimension(400, 300)); frame.getContentPane().add(pane, BorderLayout.CENTER); frame.pack(); pane.setDividerLocation(0.5); return frame; } } Thanks Sunil kumar Sahoo

    Read the article

  • C# - Parse HTML source as XML

    - by fonix232
    I would like to read in a dynamic URL what contains a HTML file, and read it like an XML file, based on nodes (HTML tags). Is this somehow possible? I mean, there is this HTML code: <table class="bidders" cellpadding="0" cellspacing="0"> <tr class="bidRow4"> <td>kucik (automata)</td> <td class="right">9 374 Ft</td> <td class="bidders_date">2010-06-10 18:19:52</td> </tr> <tr class="bidRow4"> <td>macszaf (automata)</td> <td class="right">9 373 Ft</td> <td class="bidders_date">2010-06-10 18:19:52</td> </tr> <tr class="bidRow2"> <td>kucik (automata)</td> <td class="right">9 372 Ft</td> <td class="bidders_date">2010-06-10 18:19:42</td> </tr> <tr class="bidRow2"> <td>macszaf (automata)</td> <td class="right">9 371 Ft</td> <td class="bidders_date">2010-06-10 18:19:42</td> </tr> <tr class="bidRow0"> <td>kucik (automata)</td> <td class="right">9 370 Ft</td> <td class="bidders_date">2010-06-10 18:19:32</td> </tr> <tr class="bidRow0"> <td>macszaf (automata)</td> <td class="right">9 369 Ft</td> <td class="bidders_date">2010-06-10 18:19:32</td> </tr> <tr class="bidRow8"> <td>kucik (automata)</td> <td class="right">9 368 Ft</td> <td class="bidders_date">2010-06-10 18:19:22</td> </tr> <tr class="bidRow8"> <td>macszaf (automata)</td> <td class="right">9 367 Ft</td> <td class="bidders_date">2010-06-10 18:19:22</td> </tr> <tr class="bidRow6"> <td>kucik (automata)</td> <td class="right">9 366 Ft</td> <td class="bidders_date">2010-06-10 18:19:12</td> </tr> <tr class="bidRow6"> <td>macszaf (automata)</td> <td class="right">9 365 Ft</td> <td class="bidders_date">2010-06-10 18:19:12</td> </tr> </table> I want to parse this into a ListView (or a Grid) to create rows with the data contained. All tr are different row, and all td in a given td is a column in the given row. And also I want it to be as fast as possible, as it would update itself in 5 seconds. Is there any library for this?

    Read the article

  • AVL tree in C language

    - by I_S_W
    Hey all; i am currently doing a project that requires the use of AVL trees , the insert function i wrote for the avl does not seem to be working , it works for 3 or 4 nodes at maximum ; i would really appreciate your help The attempt is below enter code here Tree insert(Tree t,char name[80],int num) { if(t==NULL) { t=(Tree)malloc(sizeof(struct node)); if(t!=NULL) { strcpy(t->name,name); t->num=num; t->left=NULL; t->right=NULL; t->height=0; } } else if(strcmp(name,t->name)<0) { t->left=insert(t->left,name,num); if((height(t->left)-height(t->right))==2) if(strcmp(name,t->left->name)<0) { t=s_rotate_left(t);} else{ t=d_rotate_left(t);} } else if(strcmp(name,t-name)0) { t-right=insert(t-right,name,num); if((height(t-right)-height(t-left))==2) if(strcmp(name,t-right-name)0){ t=s_rotate_right(t); } else{ t=d_rotate_right(t);} } t-height=max(height(t-left),height(t-right))+1; return t; }

    Read the article

  • Looking for ideas how to refactor my (complex) algorithm

    - by _simon_
    I am trying to write my own Game of Life, with my own set of rules. First 'concept', which I would like to apply, is socialization (which basicaly means if the cell wants to be alone or in a group with other cells). Data structure is 2-dimensional array (for now). In order to be able to move a cell to/away from a group of another cells, I need to determine where to move it. The idea is, that I evaluate all the cells in the area (neighbours) and get a vector, which tells me where to move the cell. Size of the vector is 0 or 1 (don't move or move) and the angle is array of directions (up, down, right, left). This is a image with representation of forces to a cell, like I imagined it (but reach could be more than 5): Let's for example take this picture: Forces from lower left neighbour: down (0), up (2), right (2), left (0) Forces from right neighbour : down (0), up (0), right (0), left (2) sum : down (0), up (2), right (0), left (0) So the cell should go up. I could write an algorithm with a lot of if statements and check all cells in the neighbourhood. Of course this algorithm would be easiest if the 'reach' parameter is set to 1 (first column on picture 1). But what if I change reach parameter to 10 for example? I would need to write an algorithm for each 'reach' parameter in advance... How can I avoid this (notice, that the force is growing potentialy (1, 2, 4, 8, 16, 32,...))? Can I use specific design pattern for this problem? Also: the most important thing is not speed, but to be able to extend initial logic. Things to take into consideration: reach should be passed as a parameter i would like to change function, which calculates force (potential, fibonacci) a cell can go to a new place only if this new place is not populated watch for corners (you can't evaluate right and top neighbours in top-right corner for example)

    Read the article

  • How to Find Intersections with Ellipses in PGF/TikZ

    - by infblnpf
    Hello, I am trying to display a sphere in PGF/TikZ to illustrate the idea of great circles. The code for my current result is: \begin{tikzpicture} \tikzfading[name=fade right, left color=transparent!20, right color=transparent!90] \tikzfading[name=fade out, inner color=transparent!100, outer color=transparent!10] \tikzfading[name=fade right gc, left color=transparent!0, right color=transparent!70] \draw [<->, dashed] (0,-5) -- (0,5); % y-axis \draw [->, dashed] (0, 0) -- (20:5); % x-axis \draw [->, dashed] (0, 0) -- (200:5); % x-axis \draw [->, dashed] (0, 0) -- (340:5); % z-axis \draw [->, dashed] (0, 0) -- (160:5); % z-axis \fill [color=cyan, opacity=0.15, path fading=fade out] (0,0) circle (4cm); % bounding circle \fill [color=cyan, opacity=0.25, path fading=fade right, fading angle=90] (0,0) ellipse (4cm and 1cm); % x-y-axis area % great circle 1 \draw [rotate=-40, color=red, path fading=fade right gc, fading angle=40] (0,0) ellipse (4cm and 1cm); % great circle 2 \draw[rotate=5, color=red, path fading=fade right gc, fading angle=5] (0,0) ellipse (1.5cm and 4cm); \end{tikzpicture} How do I find the two points of intersection of the two red ellipses (commented as great circle 1 and 2), find the point of intersection of a line (originating at the center (0,0)) with a ellipse, and place a little circle or rectangle there? Placing a little circle or rectangle there is not an issue. Thank you very much!

    Read the article

  • CSS Design question, I've got myself completely turned around.

    - by Matt Dawdy
    Okay, I have a couple of other questions out there, but I think I'd better just ask from the beginning how you CSS experts would do this. Client's page is split into 2 rows -- header has some info, some aligned to left of page, some to right, some in the middle. This is currently done using a table. I'm fine with leaving this alone or changing it. My real question is that I need a page layout to handle the following: 2 columns - column on left is 200px, but can be "close" down to to 10px (not a slider, it's either 200 or 10 px). The column on the right needs to be as big as it needs to be -- which might be larger than the width of the page. When left column is "closed" then the right column slides over of course. Again, this right column might be 300px or it might be 4000 pixels (it's a reporting interface). Now, to add another wrinkle, SOME pages have 3 columns. The first 2 columns are each exactly 200px, and both can be "closed" down to 10 px each. But, the user may not close both columns, maybe just 1. Or none. Or both. The third column needs to act just like I described above, being able to be larger than the page width, and sliding over to take advantage of any of the "closed" left columns. Whew! I'm pretty confused as to how to go about this, as either I get it right but I can't scroll over to the right at all (overflow: hidden) and information is lost, or the right column jumps down below the left 2 columns and just looks plain stupid. My minimum browser requirements are IE8, FF3.5, Chrome and Safari (latest versions of all). Any and all pointers are gladly accepted.

    Read the article

  • Changing the direction of a Combo box dropdown in SWT

    - by Kris
    Hi, I'm building an Eclipse plugin in SWT, and I have the following problem: one of my fields is a combo box, and in some cases it may have fairly long items as selection options. My plugin runs on the right side of the screen, so when you go to use the combo-box, the right side of the combo box is cut off. So, my question is: is there any way to change the dropdown's alignment relative to the combo control? It seems to be permanently left-aligned... and I'm pretty sure you can change the direction in Swing (though the only place I've seen it done is in the Substance UI demo. The Combo Box tab has boxes with North, South East, and West flyout directions... for my application, I need something like the West flyout) Note: Setting actual text limits is a last-case-scenario option; it would be quite a bit of guesswork to set the text limit dynamically (since the widget's view can be resized). Here's a picture (sorry, I can only have one link and no images :( ... I need some more rep :p) Left side of the line: Proper width - the view is the wide enough for the combo dropdown to display all the text; you can see the scrollbars on the right side. Right side of the line: Too small - Here, the view has been resized, and the combo dropdown scrollbar (as well as some of the text) is cut off by the right side of the screen. I always have more screen space available to the left (since this is always on the right hand side of the screen), but the combo dropdown always appears to the lower right. Hopefully this is clear enough.

    Read the article

  • Code Golf: Find the possible ways on a numpad

    - by ikar
    I was bored today at school and so I tried to amuse myself using my calculator and a "game" I've invented which isn't really a game but keeps the boringness away. Also some time has passed since the last real code-golf here, so I decided to create this one. Imagine a simplified numpad like you know it from your phone (I'll leave the 0 out for this code-golf as it kinda destroys all the fun) 1 2 3 4 5 6 7 8 9 Now the rules of the game were always: At the end every digit must have been visited exactly once You can start at any digit you want You can always move one digit up, down, left or right. You can't move diagonally! There a quite a lot of possible ways (or not; I haven't found out yet), here some trivial examples: > > v v < < > > | The output of the golf-program should look something like the above, I'll try to explain: Symbols: Go right < Go left ^ Go up v Go down | End of the way Example solutions: (Program output can either be the numbers pressed in the right order from beginning point to end, or an (ASCII) picture like above) 147852369 569874123 523698741 So if we speak out the example above it would be: Start at 1, move right to 2, move right to 3, go down to 6, go left to 5, go left to 4, go down to 7, go right to 8 then go right to 9 and we are finished! Now there are many different ways possible: You could as well start at 5 and go around it in a circle. So the task would be: Write a program that can compute (using brute-force or whatever) the possible solutions for the numpad problem described above. (Friendly rethorical question with smiley removed because it made some people think that this is homework)

    Read the article

  • position of View on asp.net mvc site master page

    - by ognjenb
    How fix data table to open only in Main Content Frame? Structure of my site.master page is: left content, main content and right content. When open View page in main content she goes to the right content if it is large. Is this CSS problem? My problem is similar to this http://www.inq.me/post/ASPNet-MVC-Extension-method-to-create-a-Security-Aware-HtmlActionLink.aspx This is my CSS(come with template): /*~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ PRIMARY LAYOUT STYLES ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~*/ .content-container { position:relative; _height:1px; min-height:1px; width:900px; /* background:url(images/bg-column-left.png) repeat-y;*/ } .content-container-inner { /*background:url(images/bg-column-right.png) repeat-y right;*/ _height:1px; min-height:1px; /*padding:0 200px;*/ position:relative; /*width:900px;*/ } .content-main { padding :15px 0% 0px 2%; /*position:relative;*/ min-height:1px; _height:1px; float:left; position:relative; /*width:96%;*/ /*width:900px;*/ } .content-left { padding:20px 10px; float:left; width:180px; margin-top:-1px; position:relative; margin-left:-100%; right:200px; _left:200px; border-top:1px dotted #797979; } .content-right { padding :15px 10px 10px 10px; float:left; width:160px; position:relative; margin-right:-200px; } .ads { text-align:center; margin:20px 0; } /*~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

    Read the article

  • Auto fit iframe

    - by kevin
    I have a difficulty on design a web page layout. This is my layout structure. <style> #left { float:left; width:600px; min-height:400px; } #right { float:right; width:200px; min-height:400px; } </style> <body> <center> <div id="page"> <div id="left"> <iframe /> </div> <div id="right">right panel</div> <div id="footer">footer</div> </center> </div> </body> How can i make the both left & right div grow when the right div's child increase more than the min height? How can i make the both left & right div grow when the content in the iframe is longer than the min height?

    Read the article

  • java threads don't see shared boolean changes

    - by andymur
    Here the code class Aux implements Runnable { private Boolean isOn = false; private String statusMessage; private final Object lock; public Aux(String message, Object lock) { this.lock = lock; this.statusMessage = message; } @Override public void run() { for (;;) { synchronized (lock) { if (isOn && "left".equals(this.statusMessage)) { isOn = false; System.out.println(statusMessage); } else if (!isOn && "right".equals(this.statusMessage)) { isOn = true; System.out.println(statusMessage); } if ("left".equals(this.statusMessage)) { System.out.println("left " + isOn); } } } } } public class Question { public static void main(String [] args) { Object lock = new Object(); new Thread(new Aux("left", lock)).start(); new Thread(new Aux("right", lock)).start(); } } In this code I expect to see: left, right, left right and so on, but when Thread with "left" message changes isOn to false, Thread with "right" message don't see it and I get ("right true" and "left false" console messages), left thread don't get isOn in true, but right Thread can't change it cause it always see old isOn value (true). When i add volatile modifier to isOn nothing changes, but if I change isOn to some class with boolean field and change this field then threads are see changes and it works fine Thanks in advance.

    Read the article

  • Html Agility Pack get all elements by class

    - by Adam
    I am taking a stab at html agility pack and having trouble finding the right way to go about this. For example: var findclasses = _doc.DocumentNode.Descendants("div").Where(d => d.Attributes.Contains("class")); However, obviously you can add classes to a lot more then divs so I tried this.. var allLinksWithDivAndClass = _doc.DocumentNode.SelectNodes("//*[@class=\"float\"]"); But that doesn't handle the cases where you add multiple classes and "float" is just one of them like this.. class="className float anotherclassName" Is there a way to handle all of this? I basically want to select all nodes that have a class = and contains float.

    Read the article

  • PowerBuilder IDE Customization for SCC

    - by Adam Hawkes
    Our PowerBuilder application is fairly large and has many objects in several PBLs for organizing our code. We often have 10 or more datawindows on one window, and these datawindows may be spread across two or three PBLs. For version control, we use exclusive check-out to avoid merge conflicts. The situation is that when you right-click on a datawindow object from the Window painter you get a context-menu with options like "Script" and "Properties" and "Modify Datawindow...". We'd like to add one for "Check-out..." to avoid having to hunt for the datawindow in several PBLs. Any ideas on how to do this, or something similar, would be greatly appreciated.

    Read the article

  • Select from mysql by day with different timezones (php)

    - by Adam
    I'm storing leads in a database, and each lead has a datetime field with a PST timezone based date & time. I want my user to be able to display all leads from a certain date (e.g. today, yseterday), and choose the timezone. E.g. if I want to see all leads that were generated yesterday in EST timezone, I need to first convert (or read) all the datetime values to EST, and then only select those who are in the right range (yesterday). What would be the best way to do that?

    Read the article

  • Carbide / Symbian C++ - Change Application Icon

    - by adam
    I am using Carbide (just upgraded to 2.0) to develop an S60 3rd Edition application. I would like to know the easiest way to change the icon (both the application icon on the device menu and the icon at the top left of the main view) because I have the need to skin my application in many different ways as easily as possible. All my efforts with messing around with .mif files have so far failed. I have a 44x44 .svg icon I made with Illustrator, could someone please help me in the right direction? Thanks!

    Read the article

  • How do I dynamically instantiate a class in javascript?

    - by Adam
    I'm starting out with classes in Javascript and have hit a wall. I've looked all over for a tutorial that goes a little further than simply how to construct a class (usually Animal) then extend the class and have a Method do something (Dog alert('Bark');). I have created a class that I want a user to be able to instantiate (is that the right word)? For example the first stage in my program is for the user to give the class a name, and then start to populate the various variables in the class. When they've done that they may do it again many times. So if: var className = new MyObject(); How do I dynamically create the name of the new object className and then refer to it later in the code?

    Read the article

  • mysql query: SELECT DISTINCT column1, GROUP BY column2

    - by Adam
    Right now I have the following query: SELECT name, COUNT(name), time, price, ip, SUM(price) FROM tablename WHERE time >= $yesterday AND time <$today GROUP BY name And what I'd like to do is add a DISTINCT by column 'ip', i.e. SELECT DISTINCT ip FROM tablename So my final output would be all the columns, from all the rows that where time is today, grouped by name (with name count for each repeating name) and no duplicate ip addresses. What should my query look like? (or alternatively, how can I add the missing filter to the output with php)? Thanks in advance.

    Read the article

  • On-line business card creator with PDF proof

    - by Adam
    I'm doing some research, and looking to create a simple on-line business card creator. I need to give users the ability to pick a business card template and then update the text with their own information. Then I need to create a PDF proof for the user to sign off on, as well as create a hi-rez pdf for print. Can anyone point me in the right direction? I'm trying to find some resources on how to create the PDF Heres a quick example I found of what I'm trying to do. https://www.staplescopyandprint.ca/PrintOnline/InputFields.aspx?type=PersonalCard Any input at this point would be a big help thanks!

    Read the article

  • Twitter + OAuth Problem -- Cancel Button

    - by Adam Storr
    Hi everyone, I'm implementing OAuth to post on Twitter... which works perfectly. My issue is for those who entered the Twitter login area by accident and want to press the "Cancel" button. Unfortunately, the "Cancel" button is dismissed but then immediately reappears. Here is the code for the "Cancel" button: - (void)cancel:(id)sender { if ([_delegate respondsToSelector: @selector(OAuthTwitterControllerCanceled:)]) [_delegate OAuthTwitterControllerCanceled: self]; [self performSelector: @selector(dismissModalViewControllerAnimated:) withObject: (id) kCFBooleanTrue afterDelay: 0.0]; } I think what I need to do is put the right code in the viewDidDisappear area... the problem is I don't know what code to put in. Any help would be great! Thanks so much!

    Read the article

  • make reference to an empty query in flex

    - by Adam
    a bit of a dumb questions I'm sure I'm trying to allow user to set an item to be default. I've got a function that run a query to first find the current default item. Then runs a second query that unsets the current default item. Then a third query runs to set the new user selected item to be the default. This seem to work fine when a default item has been perviously selected, but when I try to set the default item initially I get the good old "Cannot access a property or method of a null object reference." error. This is because the first query that runs returns no items I'm sure. So I need to write an if statement that if the first query returns nothing to skip the second and go right to the third. The only problem is I can't make a reference to a null object. So how do I go about writing this statement. Thanks

    Read the article

  • SQL Server union selects built dynamically from list of words

    - by Adam Tuttle
    I need to count occurrence of a list of words across all records in a given table. If I only had 1 word, I could do this: select count(id) as NumRecs where essay like '%word%' But my list could be hundreds or thousands of words, and I don't want to create hundreds or thousands of sql requests serially; that seems silly. I had a thought that I might be able to create a stored procedure that would accept a comma-delimited list of words, and for each word, it would run the above query, and then union them all together, and return one huge dataset. (Sounds reasonable, right? But I'm not sure where to start with that approach...) Short of some weird thing with union, I might try to do something with a temp table -- inserting a row for each word and record count, and then returning select * from that temp table. If it's possible with a union, how? And does one approach have advantages (performance or otherwise) over the other?

    Read the article

  • .GIF re edit! Can't figure it out!!

    - by Adam C
    http://img227.imageshack.us/img227/1892/hatersgonna.gif That is the photo.. I am trying to cut around it so its a little smaller and make him walk the opposite direction. The reason I am doing this is for a VBulletin forum signature since it marquees left to right. I have tried editing the animation in Photoshop and I flipped the canvas to horizontal... I can't figure this out.. I've been at it for HOURS. hah Also if anyone can make it just a little darker that would be amazing. "no I'm not asking for free help" but any help would be great Thank you so much

    Read the article

  • What is the best way to organize Java code since you can't pass by reference?

    - by Adam
    I'm learning how to code in Java after after coming from C. In C I always separated everything into individual functions to make the code easier to follow and edit. I was trying to do this in java but now since I realized that you can't use pointers, I am a bit confused as to what the best way to do this is. So for example I want to have a method that creates four alerts for me. So I pass it an alert builder that can then create the alerts. I can return them in an array, but in my code I already have the alerts individually named, and I would like to keep it that way so I wouldn't need to refer to them as alert[1], alert[2]... etc. So that means I would have to rename them, which would add additional code which would probably be longer than the code in the actual method! Am I thinking about this the right way? Is there anything I can do?

    Read the article

< Previous Page | 72 73 74 75 76 77 78 79 80 81 82 83  | Next Page >