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  • Distinct or group by on some columns but not others

    - by Nazadus
    I have a view that I'm trying to filter with something similar to DISTINCT on some columns but not others. I have a view like this: Name LastName Zip Street1 HouseholdID (may not be unique because it may have multiple addresses -- think of it in the logical sense as grouping persons but not physical locations; If you lookup HouseholdID 4130, you may get two rows.. or more, because the person may have mutiple mailing locations) City State I need to pull all those columns but filter on LastName,Zip, and Street1. Here's the fun part: The filter is arbitrary -- meaning I don't care which one of the duplicates goes away. This is for a mail out type thing and the other information is not used for any other reason than than to look up a specific person if needed (I have no idea why). So.. given one of the records, you can easily figure out the removed ones. As it stands now, my Sql-Fu fails me and I'm filtering in C# which is incredibly slow and is pretty much a foreach that starts with an empty list and adds the row in if the combined last name, zip, and street aren't are not in the list. I feel like I'm missing a simple / basic part of SQL that I should be understanding.

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  • Group Specific set of data by Day

    - by Jacques444
    Need to get a certian subgroup of data per day (Seperated by weekday) For example Select weekday,bla,blabla,blablabla from dbo.blabla where bla = @StartDate and bla <=@endDate I need the output to be: Monday bla blabla blablabla Tuesday bla blabla blablabla If someone could help me that would be awesome. Thanks & Regards Jacques

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  • Java Matcher groups: Understanding The difference between "(?:X|Y)" and "(?:X)|(?:Y)"

    - by user358795
    Can anyone explain: Why the two patterns used below give different results? (answered below) Why the 2nd example gives a group count of 1 but says the start and end of group 1 is -1? public void testGroups() throws Exception { String TEST_STRING = "After Yes is group 1 End"; { Pattern p; Matcher m; String pattern="(?:Yes|No)(.*)End"; p=Pattern.compile(pattern); m=p.matcher(TEST_STRING); boolean f=m.find(); int count=m.groupCount(); int start=m.start(1); int end=m.end(1); System.out.println("Pattern=" + pattern + "\t Found=" + f + " Group count=" + count + " Start of group 1=" + start + " End of group 1=" + end ); } { Pattern p; Matcher m; String pattern="(?:Yes)|(?:No)(.*)End"; p=Pattern.compile(pattern); m=p.matcher(TEST_STRING); boolean f=m.find(); int count=m.groupCount(); int start=m.start(1); int end=m.end(1); System.out.println("Pattern=" + pattern + "\t Found=" + f + " Group count=" + count + " Start of group 1=" + start + " End of group 1=" + end ); } } Which gives the following output: Pattern=(?:Yes|No)(.*)End Found=true Group count=1 Start of group 1=9 End of group 1=21 Pattern=(?:Yes)|(?:No)(.*)End Found=true Group count=1 Start of group 1=-1 End of group 1=-1

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  • MySQL - Structure for Permissions to Objects

    - by Kerry
    What would be an ideal structure for users permissions of objects. I've seen many related posts for general permissions, or what sections a user can access, which consists of a users, userGroups and userGroupRelations or something of that nature. In my system there are many different objects that can get created, and each one has to be able to be turned on or off. For instance, take a password manager that has groups and sub groups. Group 1 Group 2 Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Each group can contain a set of passwords. A user can be given read, write, edit and delete permissions to any group. More groups can get created at any point in time. If someone has permission to a group, I should be able to make him have permissions to all sub groups OR restrict it to just that group. My current thought is to have a users table, and then a permissions table with columns like: permission_id (int) PRIMARY_KEY user_id (int) INDEX object_id (int) INDEX type (varchar) INDEX read (bool) write (bool) edit (bool) delete (bool) This has worked in the past, but the new system I'm building needs to be able to scale rapidly, and I am unsure if this is the best structure. It also makes the idea of having someone with all subgroup permissions of a group more difficult. So, as a question, should I use the above structure? Or can someone point me in the direction of a better one?

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  • Group and sort blog posts by date in Rails

    - by Senthil
    I've searched all over web and have not found the answer. I'm trying to have a very standard archive option for my blog based on date. A request to url blog.com/archive/2009 shows all posts in 2009, blog.com/archive/2009/11 shows all posts in November 2009 etc. I found two different of code but not very helpful to me. def display_by_date year = params[:year] month = params[:month] day = params[:day] day = '0'+day if day && day.size == 1 @day = day if (year && month && day) render(:template => "blog/#{year}/#{month}/#{date}") elsif year render(:template => "blog/#{year}/list") end end def archive year = params[:year] month = params[:month] day = params[:day] day = '0'+day if day && day.size == 1 if (year && month && day) @posts_by_month = Blog.find(:all, :conditions => ["year is?", year]) else @posts_by_month = Blog.find(:all).group_by { |post| post.created_at.strftime("%B") } end end Any help is appreciated.

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  • SQL statement HAVING MAX(some+thing)=some+thing

    - by Andreas
    I'm having trouble with Microsoft Access 2003, it's complaining about this statement: select cardnr from change where year(date)<2009 group by cardnr having max(time+date) = (time+date) and cardto='VIP' What I want to do is, for every distinct cardnr in the table change, to find the row with the latest (time+date) that is before year 2009, and then just select the rows with cardto='VIP'. This validator says it's OK, Access says it's not OK. This is the message I get: "you tried to execute a query that does not include the specified expression 'max(time+date)=time+date and cardto='VIP' and cardnr=' as part of an aggregate function." Could someone please explain what I'm doing wrong and the right way to do it? Thanks

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  • Is it possible to group validation?

    - by lambdabutz
    I am using a lot of my own validation methods to compare the data from one association to the other. I've noticed that I'm constantly checking that my associations aren't nil before trying to call anything on them, but I am also validating their presence, and so I feel that my nil checks are redundant. Here's an example: class House < ActiveRecord::Base has_one :enterance, :class => Door has_one :exit, :class => Door validates_presence_of :enterance, :exit validate :not_a_fire_hazard def not_a_fire_hazard if enterance && exit && enterance.location != exit.location errors.add_to_base('If there is a fire you will most likely die') return false end end end I feel like I am repeating myself by checking the existence of enterance and exit within my own validation. Is there a more "The Rails Way" to do this?

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  • LINQ group one type of item

    - by Nelson
    I have a List that has various derived classes. I may have something like this: List<BaseClass> list = new List<BaseClass>() { new Class1(), new Class2(1), new Class3(), new Class2(2), new Class4() }; I am trying to use LINQ to semi-sort the list so that the natural order is maintained EXCEPT for Class2. All Class2 instances should be grouped together at the place that the first Class2 occurs. Here is what the output should be like: List<BaseClass> list = new List<BaseClass>() { new Class1(), new Class2(1), new Class2(2), new Class3(), new Class4() }; I can't for the life of me figure out how to do this...

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  • sql "Group By" and "Having"

    - by Hans Rudel
    im trying to work through some questions and im not sure how to do the following Q:Find the hard drive sizes that are equal among two or more PCs. its q15 on this site http://www.sql-ex.ru/learn_exercises.php#answer_ref The database scheme consists of four tables: Product(maker, model, type) PC(code, model, speed, ram, hd, cd, price) Laptop(code, model, speed, ram, hd, screen, price) Printer(code, model, color, type, price) any pointers would be appreciated.

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  • Java: Selected rows's index does not changes when I sort them!

    - by adrian7
    Hello, I have a Jtable on which I called the method table1.setAutoCreateRowSorter(true);. So this works on well. But I also have a methos in my JFrame class which is fired when i push a button. It gets the selected rows indexes using this code int selectedRows[] = this.table1.getSelectedRows();. And displays an edit window for the first row corresponding in the selected interval. The problem is that if I don't click on column's headers (I mean i don't sorte them at all) my method works perfect. But when I sort the row, the indexes of the rows doesn't seems to change at all - thus resulting an edit window for the old row whicn was initially in that position before making any sort. I am using JDK 6 could anyonw give ma a tip?

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  • RichFaces Toolbargroup centering a group

    - by Jeremiah
    Hello there I am trying use a toolbar so that it has three parts part A is aligned left part B is aligned Center part C is aligned right both the right and left i can use the location attribute ... but since there is no center attribute i am not able to center part b. I can use a rich:spacer but this makes the toolbar rigid and when the screen size is reduced the toolbar gets overlapped ... is there any i can center this without the toolbar getting over lapped. Any suggestions or workarounds is welcome cheers

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  • Javascript Regex multiple group matches in pattern

    - by mummybot
    I have a question for a Javascript regex ninja: How could I simplify my variable creation from a string using regex? I currently have it working without using any grouping, but I would love to see a better way! The string is: var url = 'resources/css/main.css?detect=#information{width:300px;}'; The code that works is: var styleStr = /[^=]+$/.exec(url).toString(); var id = /[^\#][^\{]+/.exec(styleStr).toString(); var property = /[^\{]+/.exec(/[^\#\w][^\:]+/.exec(styleStr)).toString(); var value = /[^\:]+/.exec(/[^\#\w\{][^\:]+[^\;\}]/.exec(styleStr)).toString(); This gives: alert(id) //information alert(property) //width alert(value) //300px Any takers?

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  • jquery selecting all elements except the last per group

    - by Anthony
    I have a table that looks like: <table> <tr> <td>one</td><td>two</td><td>three</td><td>last</td> </tr> <tr> <td>blue</td><td>red</td><td>green</td><td>last</td> </tr> <tr> <td>Monday</td><td>Tuesday</td><td>Wednesday</td><td>last</td> </tr> </table> What I want is a jquery selector that will choose all but the last td of each table row. I tried: $("tr td:not(:last)").css("background-color","red"); //changing color just as a test... But instead of all cells but the last on each row being changed, all cells but the very last one in the table are selected. Similarly, if I change it to: $("tr td:last").css("background-color","red"); the only one that changes is the very last cell. How do I choose the last (or not last) of each row?

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  • Hash Code for a group of three fields

    - by Gauranga
    I have three fields namely Number1 Number2 Time I am trying to write a function in java that returns a unique hash value (long needs to be the return type of hash) for the above fields. This hash would then be used to store database rows corresponding to the above mentioned fields in a HashSet. I am new to writing a hash code function, can someone please review what I have. Any help would be appreciated. public class HashCode { private long Number1; private long Number2; String Time; public HashCode(long Number1, long Number2, String Time){ this.Number1 = Number1; this.Number2 = Number2; this.Time = Time; } public long getHashCode() { long hash = 3; hash = 47 * hash + (long) (this.Number1 ^ (this.Number1 >>> 32)); hash = 47 * hash + (long) (this.Number2 ^ (this.Number2 >>> 32)); hash = 47 * hash + (this.Time != null ? this.Time.hashCode() : 0); return hash; } }

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  • Select Top N Records Ordered by X, But Have Results in Reverse Order

    - by I. J. Kennedy
    I'm trying to get the top N records (when ordered by some column X), but have the result set in reverse order. The following statement is incorrect, but probably demonstrates what I'm after: SELECT * FROM (SELECT TOP 10 * FROM FooTable ORDER BY X DESC) ORDER BY X ASC For example, column X could be an ID or a timestamp; I want the latest 10 records but want them returned in forward chronological order.

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  • How to animate a UIButton selected background Image

    - by Thomas Joos
    hi all, I have a class defining a custom UIButton. I configurate a normal and selected state like this: //custom image UIImage *image = [UIImage imageNamed:@"customIconCreationBG.png"]; UIImage *stretchImage = [image stretchableImageWithLeftCapWidth:0.0 topCapHeight:0.0]; [self setBackgroundImage:stretchImage forState:UIControlStateNormal]; UIImage *imageSelected = [UIImage imageNamed:@"customIconCreationBG_selected.png"]; UIImage *stretchImageSelected = [imageSelected stretchableImageWithLeftCapWidth:0.0 topCapHeight:0.0]; [self setBackgroundImage:stretchImageSelected forState:UIControlStateSelected]; In another class I'm filling an array with custom buttons and i'm adding a button pressed method. It sets the selected state to TRUE -(void)buttnPressed:(id)sender { NSLog(@"button pressed"); [[NSNotificationCenter defaultCenter] postNotificationName:@"unselectBGIcons" object:self]; HorizontalListIcon *pressedIcon = ((HorizontalListIcon *)sender); [pressedIcon setSelected:TRUE]; } The button switches to another background, which is great. Is there a way to animate this change ( fading in? ) because it's a bit hard now. Greets

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  • Installing a group of .deb files in Ubuntu

    - by p00ya
    Hi. I have a directory of .deb files which I copied from the cache folder of apt. There are many applications and Ubuntu updates among them. but there's no dependency failure because they were all downloaded by 'add/remove applications' and 'update manager' automatically. Now I have installed the same version of Ubuntu (9.04) and I want to install those apps and updates again(though they are not new versions). In other words, I want to make this fresh Ubuntu install exactly like the old one but without downloading any thing and using only those .deb files that I copied. All I have is an archive folder containing the .deb files and a 'pkgcache.bin' file. I know I can double-click the .deb files and install them manually but then I have to find out and follow the dependencies one by one from the installer errors. I have also tried adding an offline repository but it didn't work. I think because all of my .deb's are in on folder, and there is no separate 'main', 'restricted', ... folder?! Is there a way to do all of this automatically? thanks

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  • How to make WPF Listview works same as Photoshop layer

    - by Youngjae
    As we can see in Photoshop layer window (or other image editting tool also), it has several features: groups with folder-like header (collapse/expandable) ungroupped item (no header) sort "manually" by dragging. In case of No 1, I made groupped item with expander control. (ref: http://www.dotnetspark.com/kb/1753-expand-and-collapse-listbox-group-header.aspx) In case of No 3, Sort manually can be solved with this code. (ref: codeproject.com/kb/WPF/ListViewDragDropManager.aspx) but I don't know how to list ungroupped items together. Of course, the ungroupped items may not have a header. I am using ICollectionView and MVVM. Does ICollectionView can make it?

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  • Linq: How to calculate the sales Total price and group them by product

    - by Daoming Yang
    I have a order list and I want to generate and rank the product with its total sales and quantity. With @tvanfosson's help, I can bring the grouped product detail with the following code, but how can I calculate and add up the total sales and quantity into each productListResult's object? Can anyone help me with this? Many thanks. var orderProductVariantListResult = productList.SelectMany(o => o.OrderProductVariantList) .Select(opv => new { Product = opv.ProductVariant.Product, Quantity = opv.Quantity, PriceSales = opv.PriceSales, Sales = opv.Quantity * opv.PriceSales, }); var productListResult = orderProductVariantResult .Select(pv => pv.Product) .GroupBy(p => p) .Select(g => new { Product = g.Key, TotalOrderCount = g.Count() }) .OrderByDescending(x => x.TotalOrderCount).ToList();

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  • jQuery is not picking up correct values from a Div Tag

    - by Adi Mathur
    I want to pick up the values in a Div tag like which is some what like this <html> <head> </head> <body> <div id="page"> <html> <head></head> <body> Hellow World </body> </html> </div> </body> </html> I want to select the content inside a div tag . var msg = $("#page").html(); alert(msg); this code is not working . i want that whole 2nd page along with the HTML tag is copied. How do i do that ? I want the output to be the WHOLE thing INCLUDING the HTML tags

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  • Delete object[i] from table or group in corona sdk

    - by Rober Dote
    i have a problem (obviusly :P) i'm create a mini game, and when i touch a Object-A , creates an Object-B. If i touch N times, this create N Object-B. (Object-B are Bubbles in my game) so, i try when I touch the bubble (object-B), that disappears or perform any actions. I try adding Object-B to Array local t = {} . . . bur = display.newImage("burbuja.png") table.insert(t,bur) and where i have my eventListeners i wrote: for i=1, #t do bur[i]:addEventListener("tap",reventar(i)) end and my function 'reventar' local function reventar (event,id) table.remove(t,id) end i'm lost, and only i want disappears the bubbles.

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  • Jquery validator plugin- Validates at least one in the group

    - by christian
    [http://jsfiddle.net/mhmBs/][1] I tried using the method that he uses in a jquery validator plugin.. My error container is separated from the form, it is outside the form. When I use that method to validated that the user input at least one from 3 input text boxes. It validates the field, but the other items to be validated is ignored specially the items before 3 input text boxes.

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