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  • Merging XML records into one

    - by BhanuPratap Tarigopula
    I am new to XSLT. I have requirement of merging and adding. XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <OrderDetail action="add"> <OrderedUnits>12</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> If the LocationCode, Date, and PONumber fields match, I need to add the OrderedUnits and make it only one entry. Expected output XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>30</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> How can I write this XSLT?

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  • php code to return xml

    - by anwar
    hi there i have a question and need help on this from you guys . I have a database created for a game called gamesleaderboard and the fields are id, player_name, score, leveltime. and my task is after getting the score, i have to insert it to a database and sort the dbase accordingly. after sorting, the code will return an xml in the following structure: Ahmad100080 Basel95090 Samer920100 Seyd900110 Ahmad100080 Basel95090 Samer920100 Seyd900110 Ahmad100080 Basel95090 plz tell me the necessary details how to do this thankyou.

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  • Python modify an xml file

    - by michele
    I have this xml model. link text So I have to add some node (see the text commented) to this file. How I can do it? I have writed this partial code but it doesn't work: xmldoc=minidom.parse(directory) child = xmldoc.createElement("map") for node in xmldoc.getElementsByTagName("Environment"): node.appendChild(child) Thanks in advance.

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  • Sort/Group XML data with PHP?

    - by Volmar
    I'm trying to make a page using data from the discogs.com (XML)-API. i've been parsing it with simpleXML and it's working pretty well but there is some things i'm not sure how to do. Here is part of the XML: <releases> <release id="1468764" status="Accepted" type="Main"> <title>Versions</title> <format>12", EP</format> <label>Not On Label</label> <year>1999</year> </release> <release id="72246" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>LP</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="890064" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>CD</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="1563561" status="Accepted" type="TrackAppearance"> <title>Ännu En Gång Vol. 3</title> <trackinfo>Backtrack</trackinfo> <format>Cass, Comp, Mix</format> <label>Hemmalaget</label> <year>2001</year> </release> </releases> What i want to achieve is something similair to how discogs presents the releases: http://www.discogs.com/artist/Mics+Of+Fury where diferent versions of the same release are sorted together. (see. The M.O.F Blend in my link) This is done on discogs with having a master release that features the other releases. unfortunately this information isn't present in the API data, so i want to do the same thing by grouping the <release>-nodes with the same <title>-tags, or add a flag to the <releases> that don't have a unique <title>? any good ideas on the best way of doing this? i also like to know if it's possible to count the <release>-nodes (child of releases) that have the same type-attribute? like in this example count the releases with the type "Main"? maybe it's better to do this things with XMLReader or XPath?

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  • Does an XPathDocument load the whole xml document?

    - by Wires
    If I do XPathDocument doc = new XPathDocument("filename.xml"); Does that load the entire document into memory? I'm writing a mobile phone app and the document might store lots of data that doesn't ever need to all be loaded at the same time. Mobile phones don't usually have too much ram!

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  • xml appending issue - in ie, chrome browsers

    - by 3gwebtrain
    Hi, i am using this coding for my xml information to append in to html. As well it works fine. but in the ie7,ie8 as well chrome browser it's not propelry. This code work9ing well with firefox,opera, safari.. i unable to find, what is the mistake i made this.. any one help me please? $(function(){ var thisPage; var parentPage; $('ul.left-navi li a').each(function(){ $('ul.left-navi li a').removeClass('current'); var pathname = (window.location.pathname.match(/[^\/]+$/)[0]); var currentPage = $(this).attr('href'); var pathArr = new Array(); pathArr = pathname.split("."); var file = pathArr[pathArr.length - 2]; thisPage = file; if(currentPage==pathname){ $(this).addClass("active"); } }) $.get('career-utility.xml',function(myData){ var receivedData = myData; var myXml = $(myData).find(thisPage); parentPage = thisPage; var overviewTitle = myXml.find('overview').attr('title'); var description = myXml.find('discription').text(); var mainsublinkTitle = myXml.find('mainsublink').attr('title'); var thisTitle = myXml.find("intro").attr('title'); var thisIntro = myXml.find("introinfo").text(); $('<h3>'+overviewTitle+'</h3>').appendTo('.overViewInfo'); $('<p>'+description+'</p>').appendTo('.overViewInfo'); var sublinks = myXml.find('mainsublink').children('sublink'); $('#intro h3').append(thisTitle); $('#intro').append(thisIntro); sublinks.each(function(numsub){ var newSubLink = $(this); var sublinkPage = $(this).attr('pageto'); var linkInfo = $(this).text(); $('ul.career-link').append('<li><a href="'+sublinkPage+'">'+linkInfo+'</a></li>'); }) // alert('thisTitle : '+thisTitle+'thisIntro :'+thisIntro); $(myXml).find('listgroup').each(function(index){ var count = index; var listGroup = $(this); var listGroupTitle = $(this).attr('title'); var shortNote = $(this).attr('shortnote'); var subLink = $(this).find('sublist'); var firstList = $(this).find('list'); $('.grouplist').append('<div class="list-group"><h3>'+listGroupTitle+'</h3><ul class="level-one level' + count + '"></ul></div>'); firstList.each(function(listnum) { $(this).wrapInner('<li>') .find('sublistgroup').wrapInner('<ul>').children().unwrap() .find('sublist').wrapInner('<li>').children().unwrap(); // Append content of 'list' node $('ul.level'+count).append($(this).children()); }); }); }); })

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  • Saving an XML that has invalid characters

    - by BDotA
    there are code snippets that strip the invalid characters inside a string before we save it as an XML ... but I have one more problem: Let's say my user wants to have a column name like "[MyColumnOne] ...so now I do not want to strip these "[","] well because these are the ones that user has defined and wants to see them so if I use some codes that are stripping the invalid characters they are also removing "[" and "[" but in this case I still need them to be saved... what can I do?

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  • Convert text to xml

    - by Nave
    I want to convert a tab delimited text file to a XML file. I was able to do it with a single character delimiter. But how do i extend it to tabs? I am coding in C# and using Visual Studio 2010.

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  • TouchCode XML parsing error

    - by itsaboutcode
    Hi, I have a xml document which has only one element in the document, which is <error>error string<error> But when i try to parse it, it says this document has no element at all. In other words when i try to access the rootElement it says "null" CXMLDocument *rssParser = [[[CXMLDocument alloc] initWithContentsOfURL:url options:0 error:nil] autorelease]; NSLog(@"Root: %@",[[rssParser rootElement] name]); Please tell me what is wroing with this. Thanks

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  • 'How decode my encode xml data?

    - by Alex
    Hi <% 'Stage 1 datas=Server.URLencode("<PaginationData currentPage=""1"" totalPages=""9""/>") response.write "Encode = " datas &"</br></br>" 'Stage 2 response.write "Decode = " 'How i again decode my encode data? %> In the "Stage 1" , i encode my xml data In the "Stage 2", How i decode the "Stage 1" Encode data? hoping your support

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