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  • Passing input value thru XML loop and return value

    - by Mike Dyer
    "X" is reading the form value, but it is still passing and older "var thisMarket" value. The objective is to take a zip code via HTML form: <form id="market" name="market" onSubmit="return validateZIP(this.zip.value);" method="get" action=""> <input type="text" name="zip" id="zip" value="zipcode" onfocus="if(!this._haschanged){this.value=''};this._haschanged=true;" style="float:left; width:100px; margin-top:5px;"> <input type="image" style="float:left; margin-top:5px; border: 0pt none ; width: 22px; height:17px;" src="images/nav/bottom/linkbar/btn_search_btn.gif" onClick="findLda();"> </form> The script being passed thru is: function findLda(x){ marketName = new Array(); marketURL = new Array(); zip = new Array(); zip_temp = new Array(); zipMatch = false; var shareZip = "Shared Zips"; var thisMarket = "Market value"; xmlDoc=loadXML("/_includes/market.xml"); var Offer,node; document.getElementById('market').innerHTML=''; for(var j=0; j<xmlDoc.getElementsByTagName('market').length; j++){ node = xmlDoc.getElementsByTagName('market')[j]; marketName.push(node.childNodes[3].textContent); marketURL.push(node.childNodes[5].textContent); for(var k=0; k<node.getElementsByTagName('zip').length; k++){ if(node.getElementsByTagName('zip')[k].textContent!=null){ zip_temp.push(node.getElementsByTagName('zip')[k].textContent); } } zip.push(zip_temp); zip_temp = new Array(); } //loop the zip Array to find a match for the query Zip. for(k=0; k<zip.length; k++){ for(m=0; m<zip[k].length; m++){ if(x == zip[k][m].toString()){ zipMatch=true; thisMarket=marketName[k].toString(); } } } alert(thisMarket); } The objective naturally is to take field input (A), pass it thru market.xml - initialize a loop and match a zip (B), alert the result (C). Looking for any direction with what is existing or a completely new direction. Thanks!

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  • AS3 XML problem

    - by dd
    My Flash project is made of several .swf files, one of them loads XML gallery. everything works fine on my machine, but when I upload it to the testing server gallery content doesn't load. All my paths are relative to Main swf file. I can't make them absolute URLs, b/c I have to deliver zip package. What could be wrong?

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  • c# update xml file

    - by Pila
    I want to replace a xml node that is not a child of the root element. how can I do it - not in .Net 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like : XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); how can I replace this olditem?

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  • Help with XML path views

    - by xmlpath
    Hi all, is there any tool that will give me a view for XML fields like so. I want something that will show me the a view like so, if i select element1 Service/Body/element1 Is there any tool for eclipse for doing the above. Thanks.

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  • One log4j.xml - many scripts

    - by psed
    One of my utility jar files is used by different nix scripts, located in different categories. Problem: unable to initialize log4j framework (unable to find log4j.xml). Solution, that allows to configure logger correctly while launching jar classes by different scripts - usage of env vars and force configuring using DOMConfigurtor.configure(pathToConfXml) method. is it possible to avoid path hardcoding and configure logger inside of a script? Appreciate all your help. Thanks.

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  • xml schema construction

    - by amanrahahla
    in xml can any concept inhert the attribute of the main concept as an example: book( -author -title -isbn -price) and textbook as a subconcept from book can textbook take the same attribute of book and how?

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  • update XML file

    - by Pila
    I want to replace an XML node that is not a child of the root element. How can I do it - not in .NET 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like: XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); How can I replace this old item?

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  • changing the serialization procedure for a graph of objects (.net framework)

    - by pierusch
    Hello I'm developing a scientific application using .net framework. The application depends heavily upon a large data structure (a tree like structure) that has been serialized using a standard binaryformatter object. The graph structure looks like this: <serializable()>Public class BigObjet inherits list(of smallObject) end class <serializable()>public class smallObject inherits list(of otherSmallerObjects) end class ... The binaryFormatter object does a nice job but it's not optimized at all and the entire data structure reaches around 100Mb on my filesystem. Deserialization works too but it's pretty slow (around 30seconds on my quad core). I've found a nice .dll on codeproject (see "optimizing serialization...") so I wrote a modified version of the classes above overriding the default serialization/deserialization procedure reaching very good results. The problem is this: I can't lose the data previosly serialized with the old version and I'd like to be able to use the new serialization/deserialization method. I have some ideas but I'm pretty sure someone will be able to give me a proper and better advice ! use an "helper" graph of objects who takes care of the entire serialization/deserialization procedure reading data from the old format and converting them into the classes I nedd. This could work but the binaryformatter "needs" to know the types being serialized so........ :( modify the "old" graph to include a modified version of serialization procedure...so I'll be able to deserialize old file and save them with the new format......this doesn't sound too good imho. well any help will be higly highly appreciated :)

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  • php DOM, get values from xml document, php xml

    - by Michael
    I'm trying to get some information (itemID, title, price and mileage) for multiple listings from ebay website using their api . So far I got this link up http://open.api.ebay.com/shopping?callname=GetMultipleItems&responseencoding=XML&appid=Morcovar-c74b-47c0-954f-463afb69a4b3&siteid=0&version=525&IncludeSelector=ItemSpecifics&ItemID=220617293997,250645537939,230485306218 I've saved the document as .xml file using php curl and now I need to get/extract the values(itemID, title, price and mileage) into arrays and store them in database. Unfortunately I never worked with php dom and I can't figure it out how to extract the values . I tried to follow the tutorial found on IBM website http://www.ibm.com/developerworks/library/os-xmldomphp/ but I had no success. Some help would be highly appreciated.

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  • Trying to send XML via EMail and the XML includes a byte[]

    - by barbary
    Hello All, I want to send an email that has a machine readable part you cut and paste into an asp.net page and you get the information. I have stored all the information in an object and then used an XMLSerizer to create some xml. It all worked fine until I added some Images as byte[] to the object. If I dump the resulting string to disk then I can recreate the object fine but after it appears in the email client and I try to cut and paste it it never works. Clearly there are non standard characters coming out that email clients don't like. Is there some encoding I could apply to my XML that would make it display correctly in an email client? Then I could cut, paste, decode and deserilize to get my object back. Please an example of how to encode the string in c# would be great.

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  • XML Parsing Error: junk after document element

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^ Can someone please tell me what's wrong?

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  • What is this XML Parse Error?

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^

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  • How to find specific value of the node in xml file

    - by user2735149
    I am making windows phone 8 app based the webservices. This is my xml code: - <response> <timestamp>2013-10-31T08:30:56Z</timestamp> <resultsOffset>0</resultsOffset> <status>success</status> <resultsLimit>8</resultsLimit> <resultsCount>38</resultsCount> - <headlines> - <headlinesItem> <headline>City edge past Toon</headline> <keywords /> <lastModified>2013-10-30T23:45:22Z</lastModified> <audio /> <premium>false</premium> + <links> - <api> - <news> <href>http://api.espn.com/v1/sports/news/1600444?region=GB</href> </news> </api> - <web> <href>http://espnfc.com/uk/en/report/381799/city-edge-toon?ex_cid=espnapi_public</href> </web> - <mobile> <href>http://m.espn.go.com/soccer/gamecast?gameId=381799&lang=EN&ex_cid=espnapi_public</href> </mobile> </links> <type>snReport</type> <related /> <id>1600444</id> <story>Alvardo Negredo and Edin Dzeko struck in extra-time to book Manchester City's place in the last eight of the Capital One Cup, while Costel Pantilimon kept a clean sheet in the 2-0 win to keep the pressure on Joe Hart. </story> <linkText>Newcastle 0-2 Man City</linkText> - <images> - <imagesItem> <height>360</height> <alt>Man City celebrate after Edin Dzeko scored their second extra-time goal at Newcastle.</alt> <width>640</width> <name>Man City celeb Edin Dzeko goal v nufc 20131030 [640x360]</name> <caption>Man City celebrate after Edin Dzeko scored their second extra-time goal at Newcastle.</caption> <type>inline</type> <url>http://espnfc.com/design05/images/2013/1030/mancitycelebedindzekogoalvnufc20131030_640x360.jpg</url> </imagesItem> </images> Code behind: myData = XDocument.Parse(e.Result, LoadOptions.None); var data = myData.Descendants("headlines").FirstOrDefault(); var data1 = from query in myData.Descendants("headlinesItem") select new UpdataNews { News = (string)query.Element("headline").Value, Desc = (string)query.Element("description"), Newsurl = (string)query.Element("links").Element("mobile").Element("href"), Imageurl=(string)query.Element("images").Element("imagesItem").Element("url").Value, }; lstShow.ItemsSource = data1; I am trying to get value from xml tags and assign them to News,Desc, etc. Everything works fine except Imageurl, it shows NullException. I tried same method for Imageurl, i dont know whats going wrong. Help..

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  • How to convert XML to a HTML table using XSL for-each

    - by Meeeee
    I am trying to convert some XML with XSL, to make the output look better and more readable for other users. I have some XML along the lines of: <G> <OE> <example1>Sample 1</example1> <example2>Sample 2</example2> <var name="name1"> <integer>1</integer> </var> </OE> </G> I want to get all the details from it and display it in a table so I use the following XSL code: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template match="/"> <html> <body> <h2>Heading</h2> <table border="1"> <tr bgcolor="#3399FF"> <th>Example 1</th> <th>Example 2</th> <th>Var name</th> <th>Int</th> </tr> <xsl:for-each select="G/OE"> <xsl:for-each select="var"> <tr> <td> <xsl:value-of select="Example 1" /> </td> <td> <xsl:value-of select="Example 2" /> </td> <td> <xsl:value-of select="@name" /> </td> <td> <xsl:value-of select="integer" /> </td> </tr> </xsl:for-each> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> I know that the following XSL won't work properly. I want the output to be: Sample 1, Sample 2, name1, 1 - in a table format. My problem is I don't know how to do this. In the above XSL code it will only retrieve var and integer. If I only use the top <xsl:for-each>, then only the first two are retrieved. I have tried moving the 2nd <xsl:for-each> after the first to have been selected, so between: <td><xsl:value-of select="Example 2"/></td> and <td><xsl:value-of select="@name"/></td> I get an error. Is there any way to solve this problem? Thanks for the help.

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  • Binding Combobox to XML (wpf)

    - by mortor
    <EssenceList> <Essence GUID="464"> <Properties> <Property Name="Name"> <value>mt-1232-1. (1-1-3)</value> </Property> </Properties> <Characteristics> <Characteristic GUID="78"> <value>gadget</value> </Characteristic> <Characteristic GUID="79"> <value>measures</value> </Characteristic> </Characteristics> <LinkedEssences> <LinkType Type="ObjGroup"> <LinkedEssence GUID="369" /> </LinkType> <LinkType Type="ObjGroupProp" /> <LinkType Type="RoleObject"> <LinkedEssence GUID="5747"/> </LinkType> </LinkedEssences> </Essence> ... <Essence GUID="5747" Type="Role"> <Properties> <Property Name="Name"> <value>????-22</value> </Property> <Property Name="ShortName"> <value>UKPG-22</value> </Property> <Property Name="TagPrefix"> <value>UKPG22</value> </Property> <Property Name="useParentTagPrefix"> <value>0</value> </Property> </Properties> </Essence> ... <Essence GUID="5748" Type="Role"> </Essence> ... in example is a xml file with data from database. now i need to bind it to some fields... i use the XMLDataProvider here <Grid.DataContext> <XmlDataProvider x:Name="dataxml" XPath="EssenceList/Essence" Source="464.xml"/> </Grid.DataContext> and mostof simple texboxes i bind like <TextBox Text="{Binding XPath=/EssenceList/Essence/LinkedEssences/LinkType[1]/LinkedEssence/@GUID}" /> but now i need to bind a combobox this way: - the first Essence in the document contains LinkedEssences, that contains and - in document below there is a full description for it that contains the NAME property i need ????-22 UKPG22 0 and many other available Essences for this combobox i managed to bind the list of thems to combobox <ComboBox ItemTemplate="{StaticResource rolelistTemplate}" ItemsSource="{Binding XPath=/EssenceList/Essence[@Type]}" /> so it displays it well, but i can't bind it to my LinkedEssences.

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  • How to check if string is a valid XML element name?

    - by xsaero00
    I need a regex or a function in PHP that will validate a string to be a good XML element name. Form w3schools: XML elements must follow these naming rules: Names can contain letters, numbers, and other characters Names cannot start with a number or punctuation character Names cannot start with the letters xml (or XML, or Xml, etc) Names cannot contain spaces I can write a basic regex that will check for rules 1,2 and 4, but it won't account for all punctuation allowed and won't account for 3rd rule \w[\w0-9-]

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  • Reading an XML file and store data to mysql database.

    - by Jack Brown
    Hi I need the following php script to do a currency conversion using a different XML file. Its a script from white-hat design http://www.white-hat-web-design.co.uk/articles/php-currency-conversion.php The script needs to be amended to do the following: 1, The php script downloads every 24 hours an xml file from rss.timegenie.com/foreign_exchange_rates_forex rss.timegenie.com/forex.xml rss.timegenie.com/forex2.xml 2, It then stores the xml file data/contents to a mysql database file ie currency and rate. Any advice would be appreciated.

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  • linq to xml query returning a list of all child elements

    - by Xience
    I have got an xml document which looks something like this. <Root> <Info>....</Info> <Info>....</Info> <response>....</response> <warning>....</warning> <Info>....</Info> </Root> How can i write a linqToXML query so that it returns me an IEnumerable containing each child element, in this case all five child elements of , so that i could iterate over them. The order of child elements is not definite, neither is number of times the may appear. Thanks in advance

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  • Android vertical line xml

    - by Kaspa
    Hello, I'm trying to figure out how to define a verical line (1px thick) to be used as a drawable. to make a horizontal one, it's pretty straightforward: <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="line"> <stroke android:width="1dp" android:color="#0000FF"/> <size android:height="50dp" /> </shape> The question is, how to make this line vertical? Yes, there are workarounds, such as drawing a rectangle shape 1px thick, but that complicates the drawable xml, if it consists of multiple <item> elements. Anyone had any chance with this?

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