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  • Best way to access database from android

    - by Brandon Delany
    I am working on a Android app and I have a dilemma. I have a list of Objects. I have to update each of these objects with a database. I have 2 methods: Method 1: I can loop through the Objects. For each object I can connect to the server, update it, and then move on to the next Object, and so forth. Method 2: I can store the Objects in a list, send the whole list to the server, update it on the server side, then return a list of updated objects. My questions are: Which method is faster? Which method is easier on the phone's battery? By the way, Method 1 is easier for me to code :). Thank you.

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  • append files to an archive without reading/rewriting the whole archive

    - by bene
    I've got many files that I want to store in a single archive file. My first approach was to store the files in a gzipped tarball. The problem is, that I've to rewrite the whole archive if a single file is added. I could get rid of the gzip compression, but adding a file would still be expensive. What other archive format would you suggest that allows fast append operations?

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  • red black tree balancing?

    - by Anirudh Kaki
    i am working to generate tango tree, where i need to check whether every sub tree in tango is balanced or not. if its not balanced i need to make it balance? I trying so hard to make entire RB-tree balance but i not getting any proper logic so can any one help me out?? here i am adding code to check how to find my tree is balanced are not but when its not balanced how can i make it balance. static boolean verifyProperty5(rbnode n) { int left = 0, right = 0; if (n != null) { bh++; left = blackHeight(n.left, 0); right = blackHeight(n.right, 0); } if (left == right) { System.out.println("black height is :: " + bh); return true; } else { System.out.println("in balance"); return false; } } public static int blackHeight(rbnode root, int len) { bh = 0; blackHeight(root, path1, len); return bh; } private static void blackHeight(rbnode root, int path1[], int len) { if (root == null) return; if (root.color == "black"){ root.black_count = root.parent.black_count+1; } else{ root.black_count = root.parent.black_count; } if ((root.left == null) && (root.right == null)) { bh = root.black_count; } blackHeight(root.left, path1, len); blackHeight(root.right, path1, len); }

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  • Hibernate sequence should only generate when ID is <=0

    - by Tim Leys
    Hi all, I'm using the folowing sequence in my code. (I got the sequence and @Id @SequenceGenerator(name = "S912_PRO_SEQ", sequenceName = "S912_PRO_SEQ", allocationSize = 1) @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "S912_PRO_SEQ") @Column(name = "PRO_ID", unique = true, nullable = false, precision = 9, scale = 0) public int getId() { return this.id; } And using the following sequence / triggers in my DB. CREATE SEQUENCE S912_PRO_SEQ nomaxvalue minvalue 20; CREATE OR REPLACE TRIGGER S912_PRO_B_I_TRG BEFORE INSERT ON S912_project REFERENCING OLD AS OLD NEW AS NEW FOR EACH ROW ENABLE begin IF :NEW.pro_ID IS NULL THEN select S912_PRO_SEQ.nextval into :new.pro_ID from dual; END IF; end; I was wondering if there is a way to let hibernate generate a sequence ONLY if the ID is <=0 (not set) or if the ID already exists. I know for most cases my trigger would fix the situation. But I do not want to rely completely on it. I hope someone can help me out :p

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  • How to get error text in controller from BindingResult

    - by Mike
    I have an controller that returns JSON. It takes a form, which validates itself via spring annotations. I can get FieldError list from BindingResult, but they don't contain the text that a JSP would display in the tag. How can I get the error text to send back in JSON? @RequestMapping(method = RequestMethod.POST) public @ResponseBody JSONResponse submit(@Valid AnswerForm answerForm, BindingResult result, Model model, HttpServletRequest request, HttpServletResponse response) { if (result.hasErrors()) { response.setStatus(HttpServletResponse.SC_BAD_REQUEST); JSONResponse r = new JSONResponse(); r.setStatus(JSONResponseStatus.ERROR); //HOW DO I GET ERROR MESSAGES OUT OF BindingResult??? } else { JSONResponse r = new JSONResponse(); r.setStatus(JSONResponseStatus.OK); return r; } } JSONREsponse class is just a POJO public class JSONResponse implements Serializable { private JSONResponseStatus status; private String error; private Map<String,String> errors; private Map<String,Object> data; ...getters and setters... } Calling BindingResult.getAllErrors() returns an array of FieldError objects, but it doesn't have the actual errors.

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  • Coding Conventions - Naming Enums

    - by Walter White
    Hi all, Is there a document describing how to name enumerations? My preference is that an enum is a type. So, for instance, you have an enum Fruit{Apple,Orange,Banana,Pear, ... } NetworkConnectionType{LAN,Data_3g,Data_4g, ... } I am opposed to naming it: FruitEnum NetworkConnectionTypeEnum I understand it is easy to pick off which files are enums, but then you would also have: NetworkConnectionClass FruitClass Also, is there a good document describing the same for constants, where to declare them, etc.? Walter

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  • XML strings in JAXB

    - by OOO
    I have a JPA entity class mimicking a table. Something like this: @XmlType(name="MyClassElementType") public class MyClass { String name; String xmlDesc; public MyClass() {} @XmlElement String getName() { return name; } void setName(String name) { this.name = name; } @XmlElement String getXmlDesc() { return xmlDesc; } void setXmlDesc(String xmlDesc) { this.xmlDesc = xmlDesc; } } In a Jersey REST get call I'm trying to return this class: @Get @Produces("application/xml") public MyClass get() { return myClass; } Now I'm expecting the already xml string(xmlStr) to be returned as is, but Jersey/JAXB escapes it... So anyway around this?

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  • how to show integer values in JComboBox?

    - by Edan
    Hello, I would like to know how to set a JComboBox that contain integers values that I could save. Here is the definitions of values: public class Item { private String itemDesc; private int itemType; public static int ENTREE=0; public static int MAIN_MEAL=1; public static int DESSERT=2; public static int DRINK=3; private float price; int[] itemTypeArray = { ENTREE, MAIN_MEAL, DESSERT, DRINK }; Object[][] data = {{itemDesc, new Integer(itemType), new Float(price)}}; . . . } Now, I want the add a JComboBox that the user will choose 1 of the items (ENTREE, MAIN_MEAL...) and then I could set the number as an Integer. I know that JComboBox need to be something like that: JComboBox combo = new JComboBox(itemTypeArray.values()); JOptionPane.showMessageDialog( null, combo,"Please Enter Item Type", `JOptionPane.QUESTION_MESSAGE);` What am I doing wrong?

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  • MySQL create memory leak in Tomcat

    - by mabuzer
    I have set a JDBCRealm for web-app inside tomcat, and when I reload it I got this from tomcat: SEVERE: A web application registered the JBDC driver [com.mysql.jdbc.Driver] but failed to unregister it when the web application was stopped. To prevent a memory leak, the JDBC Driver has been forcibly unregistered. I use tomcat 6.0.24, with MySQL Connector 5.1.10,,,

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  • Is it possible to put GWT application on vkonakte.ru?

    - by Vasil Remeniuk
    Hi, Does anyone know if it's possible to put GWT application on vkontakte.ru (for the note, it's the most popular social networking site for the russian-speaking audience, 75+ mln subscribers). I know that integration with Facebook is possible, but as long as vkontakte.ru is not a direct Facebook-clone (they use different engines), I'm not sure, the same integration scenario will work for vkontakte. Thanks in advance!

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  • [hibernate - jpa] @CollectionOfElements without create the apposite table

    - by blow
    Hi all. I have this: Municipality class @Entity public class Municipality implements Serializable { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private Long id; private String country; private String province; private String name; @Column(name="cod_catasto") private String codCatastale; private String cap; @CollectionOfElements private List<Address> addressList; public Municipality() { } ... Address class @Embeddable public class Address implements Serializable { @ManyToOne(fetch=FetchType.LAZY) @Cascade(CascadeType.SAVE_UPDATE) private Municipality municipality; @Column(length=45) private String address; public Address() { } ... Address is embedded in another class Person. When i save an instance of Person, hibernate create 3 tables: PERSON, MUNICIPALITY and MUNICIPALITY_ADDRESSLIST. MUNICIPALITY_ADDRESSLIST contains 2 fields: MUNICIPALITY_ID (FK) and STREET. I don't want this table, i only want the ID of table MUNICIPALITY into table PERSON(that embeds Address), what should i do? I tried to add @JoinTable in Municipality entity like this: @CollectionOfElements @JoinTable(name="person") private List<Address> addressList; It partially worked, but i cant choose the column name of table PERSON that contains ID of the table MUNICIPALITY, it is, by hibernate choose, simply "MUNICIPALITY_ID"... Thbaks.

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  • Android spinner inside a custom control - OnItemSelectedListener does not trigger

    - by Idan
    I am writing a custom control that extends LinearLayout. Inside that control I am using a spinner to let the user select an item from a list. The problem I have is that the OnItemSelectedListener event does not fire. When moving the same code to an Activity/Fragment all is working just fine. I have followed some answers that was given to others asking about the same issue, and nothing helped. still the event does not fire. This is my code after I followed the answers that suggested to put the spinner inside my layout XML instead of by code. I am getting the same result when I try to just "new Spinner(ctx)"... layout XML: <Spinner android:id="@+id/accSpinner" android:layout_width="0dip" android:layout_height="0dip" /> Initialization function of the control (called on the control constructor): private void init() { LayoutInflater layoutInflater = LayoutInflater.from(mContext); mAccountBoxView = layoutInflater.inflate(R.layout.control_accountselector, null); mTxtAccount = (TextView)mAccountBoxView.findViewById(R.id.txtAccount); mSpinner = (Spinner)mAccountBoxView.findViewById(R.id.accSpinner); mAccountBoxView.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { mSpinner.performClick(); } }); setSpinner(); addView(mAccountBoxView); } private void setSpinner() { ArrayAdapter<String> dataAdapter = new ArrayAdapter<String>(mContext, android.R.layout.simple_spinner_item, mItems); dataAdapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item); mSpinner.setAdapter(dataAdapter); mSpinner.setOnItemSelectedListener(new OnItemSelectedListener() { @Override public void onItemSelected(AdapterView<?> parent, View view, int position, long id) { String selectedItem = mItems.get(position); handleSelectedItem(selectedItem); } @Override public void onNothingSelected(AdapterView<?> parent) { } }); } The spinner raises just fine when i touch my control and the list of items is there as it should. When I click an item the spinner closes but I am never getting to onItemSelected nor onNothingSelected.. Any ideas?

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  • JPanel on top of JLabel

    - by newbie
    Good day! Is it possible to add a JPanel on top of a JLabel? I would like my JFrame to have a background image and in order to this, i used this code (based from past stackoverflow answers): setLocation(150,50); setSize(700,650); setVisible(true); JLabel contentPane = new JLabel(); contentPane.setIcon(new ImageIcon("pics/b1.jpg")); contentPane.setLayout( new BorderLayout()); setContentPane( contentPane ); Now my problem is, I cannot put a panel on my JFrame because of the JLabel background. Please help. Thanks.

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  • Cannot insert non latin symbols in MySQL

    - by glebreutov
    I'm writing web-app using MySQL version 5.1.45, Tomcat 5.5.28 and Hibernate 3 When I'm trying to save string that contains non-latin characters (for example ??????) error occurs: 1589 [main] WARN org.hibernate.util.JDBCExceptionReporter - SQL Error: 1366, SQLState: HY000 1589 [main] ERROR org.hibernate.util.JDBCExceptionReporter - Incorrect string value: '\xD0\xA3\xD0\xBF\xD1\x8F...' for column 'name' at row 1 Hibernate connection settings <property name="connection.driver_class">com.mysql.jdbc.Driver</property> <property name="connection.url">jdbc:mysql://localhost/E2012?characterEncoding=UTF8&amp;useUnicode=true</property> <property name="connection.username">***</property> <property name="connection.password">***</property> <property name="hibernate.connection.charSet">UTF8</property> MySQL config My.cnf [client] default-character-set=utf8 [mysqld] default-character-set=utf8 Even query set name utf-8 doesn't resolve problem Thanks for help!

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  • Using Session Bean provided data on JSF welcome page

    - by takachgeza
    I use JSF managed beans calling EJB methods that are provide data from database. I want to use some data already on the welcome page of the application. What is the best solution for it? EJBs are injected into JSF managed beans and it looks like the injection is done after executing the constructor. So I am not able to call EJB methods in the constructor. The normal place for EJB call is in the JSF action methods but how to call such a method prior to loding the first page of the application? A possible solution would be to call the EJB method conditionally in a getter that is used on the welcome page, for example: public List getProductList(){ if (this.productList == null) this.productList = myEJB.getProductList(); return this.productList; } Is there any better solution? For example, in some config file?

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  • XSL-stylesheet URI using JAX-WS and Glassfish v3.

    - by Tony
    Hi there. I'm trying to use XSL-stylesheets in order to transform some generated XML-data to HTML-output. The architecture that I'm using is as follows: [Client Side] Web-Browser = [Server Side: Glassfish v3] JSP-pages - Web-Services. My web service generates some XML-data, then I want to format it with XSL-stylesheet, pass the result to JSP-page and show to user. I'm using JAXP for XSL-transformations and I want to create a javax.xml.transform.stream.StreamSource object with XSL-file stream for the javax.xml.transform.Transformer object, but I'm having a difficulty with specifying the path/URL for the XSL-file. So the question is: where should I put my XSL-stylesheets in a project and how should I access them from code? I'm using Glassfish v3 and NetBeans 6.8. Thanks.

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  • Reading annotation property in aspect

    - by Lukasz Koniecki
    How to read annotation property value in aspect? I want my Around advice to be executed for all joint points annotated with @Transactional(readonly=false). @Around("execution(* com.mycompany.services.*.*(..)) " + "&& @annotation(org.springframework.transaction.annotation.Transactional)") public Object myMethod(ProceedingJoinPoint pjp) throws Throwable { }

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