Search Results

Search found 21236 results on 850 pages for 'password generator mac'.

Page 77/850 | < Previous Page | 73 74 75 76 77 78 79 80 81 82 83 84  | Next Page >

  • windows 7 file explorer preview window and password protected word docs

    - by Carbonara
    When using the windows 7 explorer with the preview pane open you get a little preview of a file when you click on it. This includes Word and Excel spreadsheets etc. My problem is if the Word doc is password protected clicking on it in explorer automatically asks for the password to display its preview. It does this if you single or double clicking on it. You then get an empty Word instance running (which allows it to display the preview) and another instance of Word with your actual file and you're asked for the password twice in total. This is annoying and untidy. Is there a way of stopping the preview pane from wanting to display password protected documents and thus not asking for the password to display a preview?

    Read the article

  • ssh login successful, but scp password gives me "Permission denied"

    - by YANewb
    I'm trying to get some blogging software up on an organizational remote server. I tried to set up a SSH Key but was having problems and decided that getting the blog up and running was more important than dealing with the SSH Key issue, so I ssh-keygen -R remoteserver.com. Now I can successfully login with ssh -v [email protected] and the correct password. Once logged in I can move around and read any file and directory that I should be able to read. But when I try to edit an existing -rw-r--r-- file with VIM, it shows up as read-only, if I try to edit permissions I get chmod: file.ext: Operation not permitted, and if I try to scp a new file from my local machine I'm prompted for the remote user's password, and then get scp: /home/path/to/file.ext: Permission denied. Since I didn't have any of these problems before I tried to set up the ssh key, I suspect these anomalies are a side effect of that, but I don't know how to troubleshoot this. So what does a foolish server-newb, such as myself, need to do to get edit capability back as a remote user? Addendum 1: My userids are different between my local machine and the remote server. For ssh I ssh -v [email protected]. if I whoami I get remoteuser For scp I scp file.ext [email protected]:/path/to/file.ext from the local directory with file.ext while logged in as the local user. if I whoami I get localuser The ls -l for two different files I've tried scp: -rw-r--r--@ 1 localuser localgroup 20 Feb 11 21:03 phpinfo.php -rw-r--r-- 1 root localgroup 4 Feb 11 22:32 test.txt The ls -l for the file I've tried to VIM: -rw-r--r-- 1 remoteuser remotegroup 76 Jul 27 2009 info.txt Addendum 2: In the past I've set up ssh-keys for git repositories. I don't want to completely destroy them, so in an attempt to follow a deer's train of thinking I renamed my ~/.ssh/ to ~/.ssh-bak/, then tested the different types of access. The abridged version of the terminal commands and results is below; I think everything is working until the 8th line from the end. localcomputer:~ localuser$ ssh -v [email protected] OpenSSH_5.2p1, OpenSSL 0.9.8l 5 Nov 2009 debug1: Reading configuration data /etc/ssh_config debug1: Connecting to remoteserver.com [###.###.###.###] port 22. debug1: Connection established. debug1: identity file /Users/localuser/.ssh/identity type -1 debug1: identity file /Users/localuser/.ssh/id_rsa type -1 debug1: identity file /Users/localuser/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.8p2 FreeBSD-20110503 debug1: match: OpenSSH_5.8p2 FreeBSD-20110503 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.2 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY The authenticity of host 'remoteserver.com (###.###.###.###)' can't be established. RSA key fingerprint is ##:##:##:##:##:##:##:##:##:##:##:##:##:##:##:##. Are you sure you want to continue connecting (yes/no)? yes Warning: Permanently added 'remoteserver.com,###.###.###.###' (RSA) to the list of known hosts. debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: /Users/localuser/.ssh/identity debug1: Trying private key: /Users/localuser/.ssh/id_rsa debug1: Trying private key: /Users/localuser/.ssh/id_dsa debug1: Next authentication method: password [email protected]'s password: debug1: Authentication succeeded (password). debug1: channel 0: new [client-session] debug1: Requesting [email protected] debug1: Entering interactive session. Last login: Sun Feb 12 18:00:54 2012 from 68.69.164.123 FreeBSD 6.4-RELEASE-p8 (VKERN) #1 r101746: Mon Aug 30 10:34:40 MDT 2010 [remoteuser@remoteserver /home]$ ls -l total ### -rw-r--r-- 1 remoteuser remotegroup 76 Aug 12 2009 info.txt [remoteuser@remoteserver /home]$ vim info.txt ~ {at the bottom of the VIM screen it tells me it's [read only]} [remoteuser@remoteserver /home]$ whoami remoteuser [remoteuser@remoteserver /home]$ logout debug1: client_input_channel_req: channel 0 rtype exit-status reply 0 debug1: client_input_channel_req: channel 0 rtype [email protected] reply 0 debug1: channel 0: free: client-session, nchannels 1 Connection to remoteserver.com closed. Transferred: sent 3872, received 12496 bytes, in 107.4 seconds Bytes per second: sent 36.1, received 116.4 debug1: Exit status 0 localcomputer:localdirectory name$ scp -v phpinfo.php [email protected]:/home/www/remotedirectory/phpinfo.php Executing: program /usr/bin/ssh host remoteserver.com, user remoteuser, command scp -v -t /home/www/remotedirectory/phpinfo.php OpenSSH_5.2p1, OpenSSL 0.9.8l 5 Nov 2009 debug1: Reading configuration data /etc/ssh_config debug1: Connecting to remoteserver.com [###.###.###.###] port 22. debug1: Connection established. debug1: identity file /Users/localuser/.ssh/identity type -1 debug1: identity file /Users/localuser/.ssh/id_rsa type -1 debug1: identity file /Users/localuser/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.8p2 FreeBSD-20110503 debug1: match: OpenSSH_5.8p2 FreeBSD-20110503 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.2 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'remoteserver.com' is known and matches the RSA host key. debug1: Found key in /Users/localuser/.ssh/known_hosts:1 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: /Users/localuser/.ssh/identity debug1: Trying private key: /Users/localuser/.ssh/id_rsa debug1: Trying private key: /Users/localuser/.ssh/id_dsa debug1: Next authentication method: password [email protected]'s password: debug1: Authentication succeeded (password). debug1: channel 0: new [client-session] debug1: Requesting [email protected] debug1: Entering interactive session. debug1: Sending command: scp -v -t /home/www/remotedirectory/phpinfo.php Sending file modes: C0644 20 phpinfo.php Sink: C0644 20 phpinfo.php scp: /home/www/remotedirectory/phpinfo.php: Permission denied debug1: client_input_channel_req: channel 0 rtype exit-status reply 0 debug1: channel 0: free: client-session, nchannels 1 debug1: fd 0 clearing O_NONBLOCK debug1: fd 1 clearing O_NONBLOCK Transferred: sent 1456, received 2160 bytes, in 0.6 seconds Bytes per second: sent 2322.3, received 3445.1 debug1: Exit status 1

    Read the article

  • sudo prompts for password over ssh

    - by Joe Watkins
    I have sudo set up for a shell script as follows on "hostname" (sudo -l output): (suser) NOPASSWD: /path/script* sudoers content is: myuser ALL=(suser) NOPASSWD: /path/script* this works fine, so I can run the following, logged in locally on hostname, without need for password: sudo -u suser /path/script however, when I use ssh (with keys set up, so no password require) to login and run, as follows: ssh hostname sudo -u suser /path/script I get prompted for a password, and when the password is entered I get: Sorry, user myuser is not allowed to execute '/path/script' as suser on hostname. Why? NB the following does not prompt for password at any point: $ ssh hostname $ sudo -u suser /path/script

    Read the article

  • Forgot password to development database

    - by ninja08
    I've created a database using terminal while following along with a tutorial. Although I had a lot of trouble getting the databases to install. Now after finally getting it to work I changed a few things, actually just the name of the database using the rake command to just "next". The password should be 'secret password'. How can I change the password or find out what it is or change it? It doesn't seem to be edited my databases.yml file with the password, especially since it still just says 'root' as username with now password in there.

    Read the article

  • Escape a ! in the password parameter of wget

    - by Dave
    I'm trying to execute something like this: wget --user=foo --password=bar! url The ! in the password is causing problems. I've tried escaping it with \, as in --password=bar\! I've tried encapsulating in single and double quotes. I put the password in a separate file and tried --password=cat pass.txt Each time, I get a 403 Forbidden. Using -d, I see that the SSL handshake is successful. On the Windows command line, the command works. My assumption is that I need to escape the ! differently, but I don't know how else.

    Read the article

  • login as rsh in rhel 6 without entering password

    - by cartmancakes
    I need to be able to login to a RHEL 6 server using rsh (please don't flame me about security, it's irrelevant in this particular instance) as root without having to enter a password. My procedure for setting this up works great in RHEL 5.x, but does not work in RHEL 6. I suspect this has something to do with PAM, but I'm inexperienced with how to use PAM. Can someone help me with this? /etc/pam.d/rsh auth required pam_rhosts.so auth required pam_nologin.so account include common-account password include common-password session required pam_loginuid.so session include common-session /etc/pam.d/rlogin auth required pam_nologin.so auth [user_unknown=ignore success=ok ignore=ignore auth_err=die default=bad] pam_securetty.so auth sufficient pam_rhosts.so auth include common-auth auth required pam_mail.so account include common-account password include common-password session required pam_loginuid.so session include common-session Thanks!

    Read the article

  • Running a command line app with sudo and password automatically on OS X startup

    - by Designer023
    I need to run an app at startup/login on my mac. I want it to launch in the background and start doing it's work without interrupting me or me having to start it up because I invariably forget and then when I need it, it wasn't running! I have tried using AppleScript to tell Terminal to run it and type my password in, but it ends up opening multiple Terminal windows and not working. Ideally I need a script that I can just add to the user login items and it will run for me. The app has no way of taking a password argument either and it has a password as well as the sudo! I need a solution that can either be done as an applescript (which can be made into an executable) or i need a commandline script but I have no idea about them. This is the manual code I type $ sudo serverStatus password:123456 password:serverpass My AppleScript: tell application Terminal activate do shell script "sudo serverStatus" delay 5 do shell script "123456" delay 2 do shell script "serverpass" end tell

    Read the article

  • NIS AD password synch for new accounts

    - by user135004
    I have a Win2k3R2 DC with NIS. All is working well but its no longer synching the passwords for new accounts. When creating a new AD user, NIS does its thing and sends its Unix account to the synched linux server. It's doing everything its supposed to do but not the users password to the server (getent passwd returns the ABCD!efgh12345$67890 password for the new account). Thinking that password synchronization is not working, I changed the password of an existing working account and it synchs the new password. If I delete a new or old AD user, it deletes it on the linked linux server as well. All this tells me that NIS is doing its thing (at least with existing accounts) No updates have been installed on the DC. I am not even sure where to start here.

    Read the article

  • Windows 7 file explorer preview window and password protected word documents

    - by Carbonara
    When using the Windows 7 Explorer with the preview pane open you get a little preview of a file when you click on it. This includes Word, Excel spreadsheets, etc. My problem is if the Word document is password protected. Clicking on it in Explorer automatically asks for the password to display its preview. It does this if you single or double clicking on it. You then get an empty Word instance running (which allows it to display the preview) and another instance of Word with your actual file and you're asked for the password twice in total. This is annoying and untidy. Is there a way of stopping the preview pane from wanting to display password protected documents and thus not asking for the password to display a preview?

    Read the article

  • Password format not liked by installer

    - by Box293
    I'm installing Chargeback and I get to the database-related information page (step 5 on page 17 of the users guide). Using a Windows account (it is an administrator of the server and I am logged on as that user) Username: DOMAIN\ServiceVMware-CB Password: #$%UuuU2u (this isn't the password but it does start with #$% and is the same length and case) I click the Test Connected and it returns back OK. I click Next and then I am given a warning telling me that the account does not have the right permissions. Check that it has log on as a service etc etc etc. I quit the installer. I change the password in the domain to Uuuuuu3 I reboot the server I restart the server The installer has no problems with the newer password. I'm not fussed either way, I'm just trying to save someone else the pain and perhaps the allowed password format could be added to the documentation. BTW I am using Server 2008 SP2 x64 with SQL Express 2005 x64.

    Read the article

  • Password Management for Oracle WebLogic customers

    - by Anthony Shorten
    One of the most common requests for enhancements I get across my desk is that customers wish to allow end users to change their passwords from our products. Now, typically password management is not in the realm of individual applications but it is an infrastructure requirement, so we don't usually add this to our roadmaps by default. The issue is that with the vast range of security stores that can be used with our product line across the Web Application Servers we support, it is almost impossible to come up with a generic enough API to work across them. If you have a specific security store on a specific Web Application Server platform then there are simpler solutions. There are a number of ways of implementing this without providing functionality specific functionality: Oracle sells Identity Management software that offers common API's to manage passwords. You can purchase those products and link to the password change dialog in those products using Navigation Keys. If you are a customer using Oracle WebLogic, then there is a sample JSP's that can be linked to provide this functionality under Oracle TechNet (registration required) under Code Samples (project S20). These can be added as a Navigation Key to complete the functionality. This will allow end users to manage their own passwords. Obviously these are all samples and should be treated as customizations when you implement them. If you wish to understand Navigation Keys, then look at the Oracle Utilities Application Framework Integration Guidelines (Doc Id: 789060.1) available from My Oracle Support.

    Read the article

  • Tale of an Encrypted SSIS Package in msdb and a Lost Password

    - by Argenis
      Yesterday a Developer at work asked for a copy of an SSIS package in Production so he could work on it (please, dear Reader – withhold judgment on Source Control – I know!). I logged on to the SSIS instance, and when I went to export the package… Oops. I didn’t have that password. The DBA who uploaded the package to Production is long gone; my fellow DBA had no idea either - and the Devs returned a cricket sound when queried. So I posed the obligatory question on #SQLHelp and a bunch of folks jumped in – some to help and some to make fun of me (thanks, @SQLSoldier @crummel4 @maryarcia and @sqljoe). I tried their suggestions to no avail…even ran some queries to see if I could figure out how to extract the package XML from the system tables in msdb:   SELECT CAST(CAST(p.packagedata AS varbinary(max)) AS varchar(max)) FROM msdb.dbo.sysssispackages p WHERE p.name = 'LePackage'   This just returned a bunch of XML with encrypted data on it:  I knew there was a job in SQL Agent scheduled to execute the package, and when I tried to look at details on the job step I got the following: Not very helpful. The password had to be saved somewhere, but where?? All of a sudden I remembered that there was a system table I hadn’t queried yet: SELECT sjs.command FROM msdb.dbo.sysjobs sj JOIN msdb.dbo.sysjobsteps sjs ON sj.job_id = sjs.job_id WHERE sj.name = 'Run LePackage' The result: “Well, that’s really secure”, I thought to myself. Cheers, -Argenis

    Read the article

  • How can I check if a user has written his username and password correctly?

    - by Sergio Tapia
    I'm using a Linq-to-SQL class called Scans.dbml. In that class I've dragged a table called Users (username, password, role) onto the graphic area and now I can access User object via a UserRepository class: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace Scanner.Classes { public class UserRepository { private ScansDataContext db = new ScansDataContext(); public User getUser(string username) { return db.Users.SingleOrDefault(x => x.username == username); } public bool exists(string username) { } } } Now in my Login form, I want to use this Linq-to-SQL goodness to do all the data related activities. UserRepository users = new UserRepository(); private void btnLogin_Click(object sender, EventArgs e) { loginToSystem(); } private void loginToSystem() { if (users.getUser(txtUsername.Text)) { } //If txtUsername exists && User.password == Salt(txtPassword) //then Show.MainForm() with User.accountType in constructor to set permissions. } I need help with verifying that a user exists && that that users.password is equal to SALT(txtpassword.text). Any guidance please?

    Read the article

  • Is there a code-generator to create DataTable definition block from Excel Work sheet?

    - by burak ozdogan
    Hi, Basically the thing I want to achieve is to have a data-table that I want to use in my unit tests. And when I run my unit tests, I do not want to read any excel file into a data-table -or any call to Db-. So, I would like to have method that returns a data-table with the values that I can use in my test. Is there already any written tool to read an excel sheet and generate a code that defines an ADO.Net DataTable? Thanks, burak ozdogan

    Read the article

  • IP address detection for geo-location or MAC address much secure?

    - by SuperRomia
    Recent study many websites are using geo-location technology on their Websites. I'm planning to implement one website which can be detect the web visitor more accurate. An found that Mozilla is using some kind of detect MAC address technology in their Geo-Location web service. Is it violate some privacy issue? I believe most of Geo-location service providers only offer country to city level. But the Mac address detection enable to locate the web visitors' location more correctly than using IP address detection. If detect the MAC address is not practical, which geo-location service provider is offering more accurate data to detect my Website visitor around the world?

    Read the article

  • Transparent proxy which preserves client mac address

    - by A G
    I have a customer that wants to intercept SSL traffic as it leaves their network. My proposed solution is to setup a proxy that is transparent and both layer 2 and layer 3 so it can simply be dropped into their network without any change in config required. The proxy has two NICs, one connected to the server, the other to the client. The client, proxy and gateway are under control of the customer, the server is not. For example: client --- Proxy --- gateway -|- server I have my proxy program configured with IP_TRANSPARENT socket option to it can respond to connections destined for a remote IP. I am using the following setup: iptables -t mangle -A PREROUTING -p tcp --dport 80 -j TPROXY --on-port 3128 --tproxy-mark 1/1 iptables -t mangle -A PREROUTING -p tcp -j MARK --set-mark 1 ip rule add fwmark 1/1 table 1 ip route add local 0.0.0.0/0 dev lo table 1 The client in question is on its own subnet and has been configured so that the proxy is the default gateway. The result is: Client sends a frame to the proxy; source IP is client, source mac is client, destination IP is server, destination mac is proxy Proxy forwards this frame to the gateway; source IP is proxy, source mac is proxy, destination IP is server, destination mac is gateway Gateway forwards this to the server and gets a response back. Gateway sends reply back to proxy; source IP is server, source mac is gateway, destination IP is proxy, destination mac is proxy Proxy forwards this reply to client; source IP is server, source mac is proxy, destination IP is client, destination mac is client. The tproxy and iptables configuration lets the proxy send packets with a non local ip address. Is there a way to make something transparent at the mac address level? That is, put the client on the same subnet as the gateway. The gateway sees the source IP and mac as that of the client, even though they originated from the proxy. Could this be done by configuring the proxy as a bridge then use ebtables to escalate the traffic to be handled by iptables? When I use ebtables to push something up to iptables, it appears my proxy program doesn't respond to the packets as they are destined for the gateways's mac address, not the proxy's. What are some other potential avenues I could investigate? EDIT: When the client and gateway are on different subnets (and client has set the proxy as the gateway), it works as described in 1 to 5. But I want to know if it is possible to have the client and gateway on the same subnet and have the proxy fully transparent (ie client is not aware of the proxy). Thanks! EDIT 2: I can configure the proxy as a bridge using brctl, but cannot find a way to direct this traffic to my proxy program - asked here Possible for linux bridge to intercept traffic?. Currently, with the description numbered 1 to 5, it operates at layer 3; it is transparent on the client side (client thinks it is talking to the server's IP), but not on the gateway side (gateway is talking to the proxy's IP). What I want to find out is, is it possible to make this operate at layer 2, so it is fully transparent? What are the available options I should research? Thanks

    Read the article

  • How do i get a more recent version of Java on my Mac than is showing up in software update?

    - by Bec
    I need at least Java 1.6 to run a program that someone else in my lab wrote On the Java website it tells me to update Java via apple's software update function, i've run this a few times but it only got up to Java 1.5.0_24 and it now says no more updates are available for my computer Is there another way to update Java on a Mac? Is my operating system maybe to old for Java 1.6? i'm not sure what i'm running exactly, and i can't find a list of what mac operating systems run what versions of Java because the java site just suggests using Mac's software update.

    Read the article

  • How to enable a two-finger drag on a mac in Silverlight?

    - by Edward Tanguay
    In a Silverlight 4 application I have a ScrollViewer which I enable the user to scroll with the mouse wheel by using SetIsMouseWheelScrollingEnabled(): <ScrollViewer x:Name="CodeBoxScrollViewerModelSingular" tk:DockPanel.Dock="Left" Style="{StaticResource ScrollViewerCodeBoxStyle}"> <TextBox Text="{Binding SingularModelFileContent}" Style="{StaticResource TextBoxCodeBoxStyle}"/> </ScrollViewer> CodeBoxScrollViewerModelSingular.SetIsMouseWheelScrollingEnabled(true); However, someone tested it on a Mac and said: The only problem I noticed on a quick test was that I couldn't scroll down by using a two-finger drag, which has been standard UI behavior on the Mac for several years now. Is there any way to enable a "two-finger drag" on the Mac as you can enable mouse wheel scrolling?

    Read the article

  • For what programs are Objective C and Ruby ideal on the Mac?

    - by Kurt
    Hi, as a Mac outsider it seems that two popular programming languages on the Mac appear to be Objective C and Ruby. From what I understand the main API Cocoa seems to be written in and optimized for Objective C, but it is also possible to use Ruby for that. Are there different areas where each language is ideal, for example, I could imagine Objective C could be ideal for a GUI layer, or standalone desktop app, and Ruby could be good for web services etc. What about classic business logic, or data access layers? What language would be a good choice for a library of services for example? Can we write a library in one language and link to it from a main program written in the other language? If I wanted to write a layered enterprise application using domain driven design and dependency injection which languages could support each concerns? Are things like DDD and DI common amongst Mac devs? Just a curious outsider.

    Read the article

  • Does Java Mac OSX native look and feel respect UIManager font changes?

    - by Erik Lickerman
    I have a java applet and the only look and feel that works properly is the native mac one. I wanted to make the fonts a bit larger and tried using the standard UIManager methods UIManager.put("Label.font", new Font("Georgia", Font.PLAIN, 18)); This produces no change. It does not throw an exception, of course. Does anyone know if the native mac look and feel ignores these? I know there are specific ways to make controls different sizes on mac but these only seem to make them smaller. You cannot make the controls larger than regular.

    Read the article

  • Can a MAC address be used as a reliable part of a rights management (DRM) scheme?

    - by Jarrod Mosen
    We're currently writing some software that we want to protect. We thought that registering a user's MAC address in a database upon activation of the software seemed viable; we can profile and grab that with a Java applet, (is there a better way?) so getting it isn't too much of a problem. However, we want their computer to only run the application, and download application files/updates from the server when their MAC address has been verified with their one on-file. We understand that this means a lockdown to one computer, but special changes can be made on request. What would be the best way to verify their MAC address, to see if it exists in the database, and then serve them the files to run the application? (And to simply run it on subsequent requests, to prevent re-downloading.)

    Read the article

  • How can I write an autostarting dock app for the Mac?

    - by TreeUK
    I have an application I'd like to build that starts when you start the mac and will appear in the dock. I have some experience with Objective-C and iPhone dev but none with Mac dev, I'm also a PC user normally so I'm not au fait with the norms of Mac usage. Any guidance here is appreciated. How do you get an application to autostart? Can you run an app in the tray bar? (with the clock etc in) or do apps only run in the dock?

    Read the article

< Previous Page | 73 74 75 76 77 78 79 80 81 82 83 84  | Next Page >