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  • What is the wrong of this converted code?

    - by Gum Slashy
    I'm developing shape identification project using javacv and I have found some opencv code to identify U shapes in particular image and I have try to convert it in to javacv but it doesn't provide same out put. Can you please help me to convert this opencv code into javacv? This is Opencv code import cv2 import numpy as np img = cv2.imread('sofud.jpg') gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY) ret,thresh = cv2.threshold(gray,127,255,1) contours,hierarchy = cv2.findContours(thresh,cv2.RETR_LIST,cv2.CHAIN_APPROX_SIMPLE) for cnt in contours: x,y,w,h = cv2.boundingRect(cnt) if 10 < w/float(h) or w/float(h) < 0.1: cv2.rectangle(img,(x,y),(x+w,y+h),(0,0,255),2) cv2.imshow('res',img) cv2.waitKey(0) cv2.destroyAllWindows() This is the expected output This is the code that I have converted import com.googlecode.javacpp.Loader; import com.googlecode.javacv.CanvasFrame; import static com.googlecode.javacpp.Loader.*; import static com.googlecode.javacv.cpp.opencv_core.*; import static com.googlecode.javacv.cpp.opencv_imgproc.*; import static com.googlecode.javacv.cpp.opencv_highgui.*; import java.io.File; import javax.swing.JFileChooser; public class TestBeam { public static void main(String[] args) { CvMemStorage storage=CvMemStorage.create(); CvSeq squares = new CvContour(); squares = cvCreateSeq(0, sizeof(CvContour.class), sizeof(CvSeq.class), storage); JFileChooser f=new JFileChooser(); int result=f.showOpenDialog(f);//show dialog box to choose files File myfile=null; String path=""; if(result==0){ myfile=f.getSelectedFile();//selected file taken to myfile path=myfile.getAbsolutePath();//get the path of the file } IplImage src = cvLoadImage(path);//hear path is actual path to image IplImage grayImage = IplImage.create(src.width(), src.height(), IPL_DEPTH_8U, 1); cvCvtColor(src, grayImage, CV_RGB2GRAY); cvThreshold(grayImage, grayImage, 127, 255, CV_THRESH_BINARY); CvSeq cvSeq=new CvSeq(); CvMemStorage memory=CvMemStorage.create(); cvFindContours(grayImage, memory, cvSeq, Loader.sizeof(CvContour.class), CV_RETR_CCOMP, CV_CHAIN_APPROX_SIMPLE); System.out.println(cvSeq.total()); for (int i = 0; i < cvSeq.total(); i++) { CvRect rect=cvBoundingRect(cvSeq, i); int x=rect.x(),y=rect.y(),h=rect.height(),w=rect.width(); if (10 < (w/h) || (w/h) < 0.1){ cvRectangle(src, cvPoint(x, y), cvPoint(x+w, y+h), CvScalar.RED, 1, CV_AA, 0); //cvSeqPush(squares, rect); } } CanvasFrame cnvs=new CanvasFrame("Beam"); cnvs.setDefaultCloseOperation(javax.swing.JFrame.EXIT_ON_CLOSE); cnvs.showImage(src); //cvShowImage("Final ", src); } } This is the out put that I got please can some one help me to solve this problem ?

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  • Removing the transperancy from image while keeping the actual image

    - by KPL
    Hello people, I have three images,and , they are not square or rectangular in shape. They are just like face of anyone. So,basically, my images are in the size 196x196 or anything like that, but complete square or rectangle with the face in the middle and transperant background in the rest of the portion. Now, I want to remove the transperant background too and just keep the faces. Don't know if this is possible and mind you, this isn't a programming question.

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  • How to read and save data from text file with variable number of columns in a Matrix in Matlab

    - by khan
    I have a text file with integer values. each row contains information about specific object. But unfortunately each row has different number of column. because of which when i try to use file_content = load('txtfile.txt'); it gives me error message that previous number of columns does not match. i also tried to use fgetl, fscanf, etc function but was unsuccessful. Can anybody give me a piece of code, or help me how to read a txt file and save in matrix in matlab. Three sample rows are given below. 1 1 1 1 1 95 17 54 111 92 17 54 111 92 17 54 111 92 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 54 109 92 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 58 109 96 15 58 109 96 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 58 109 96 15 56 109 94 15 56 109 94 15 58 109 96 15 58 109 96 15 56 109 94 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 17 58 111 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 56 109 94 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 1 1 1 2 96 185 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 15 56 109 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 54 107 92 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 13 56 107 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 54 109 92 15 54 109 92 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 1 1 1 3 186 245 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 56 109 94 15 58 109 96 15 58 109 96 15 58 109 96 15 58 109 96 13 58 107 96 13 56 107 94 13 56 107 94 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 56 107 94 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 58 107 96 13 60 107 98 13 58 107 96 13 58 107 96 15 58 109 96 13 58 107 96 As you can see the rows doesn't have equal number of columns. So how can i read and save it in a Matrix. Any help in this regards will be highly appreciated. Thanks

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  • Scaling up an image

    - by codefail
    How do I fulfill the condition "returns the entire scaled up image" If I am coding this correctly, scaleColor handles individual colors, getRed handles the red, etc. I am multiplying this by the input, numTimes, which will create a new image that is scaled up it. This scaled up (increase size) is to be returned. This is what I have. Image Image::scaleUp(int numTimes) const { for (int x = 0; x < width; x++) { for (int y = 0; y < height; y++) { pixelData[x][y].scaleColor(pixelData[x][y].scaleRed(pixelData[x][y].getRed()*numTimes)); pixelData[x][y].scaleColor(pixelData[x][y].scaleGreen(pixelData[x][y].getGreen()*numTimes)); pixelData[x][y].scaleColor(pixelData[x][y].scaleBlue(pixelData[x][y].getBlue()*numTimes)); } } //return Image(); }

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  • What is the best way to detect white color?

    - by dnul
    I'm trying to detect white objects in a video. The first step is to filter the image so that it leaves only white-color pixels. My first approach was using HSV color space and then checking for high level of VAL channel. Here is the code: //convert image to hsv cvCvtColor( src, hsv, CV_BGR2HSV ); cvCvtPixToPlane( hsv, h_plane, s_plane, v_plane, 0 ); for(int x=0;x<srcSize.width;x++){ for(int y=0;y<srcSize.height;y++){ uchar * hue=&((uchar*) (h_plane->imageData+h_plane->widthStep*y))[x]; uchar * sat=&((uchar*) (s_plane->imageData+s_plane->widthStep*y))[x]; uchar * val=&((uchar*) (v_plane->imageData+v_plane->widthStep*y))[x]; if((*val>170)) *hue=255; else *hue=0; } } leaving the result in the hue channel. Unfortunately, this approach is very sensitive to lighting. I'm sure there is a better way. Any suggestions?

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  • What is the fastest way to find duplicates in multiple BIG txt files?

    - by user2950750
    I am really in deep water here and I need a lifeline. I have 10 txt files. Each file has up to 100.000.000 lines of data. Each line is simply a number representing something else. Numbers go up to 9 digits. I need to (somehow) scan these 10 files and find the numbers that appear in all 10 files. And here comes the tricky part. I have to do it in less than 2 seconds. I am not a developer, so I need an explanation for dummies. I have done enough research to learn that hash tables and map reduce might be something that I can make use of. But can it really be used to make it this fast, or do I need more advanced solutions? I have also been thinking about cutting up the files into smaller files. To that 1 file with 100.000.000 lines is transformed into 100 files with 1.000.000 lines. But I do not know what is best: 10 files with 100 million lines or 1000 files with 1 million lines? When I try to open the 100 million line file, it takes forever. So I think, maybe, it is just too big to be used. But I don't know if you can write code that will scan it without opening. Speed is the most important factor in this, and I need to know if it can be done as fast as I need it, or if I have to store my data in another way, for example, in a database like mysql or something. Thank you in advance to anybody that can give some good feedback.

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  • CUDA small kernel 2d convolution - how to do it

    - by paulAl
    I've been experimenting with CUDA kernels for days to perform a fast 2D convolution between a 500x500 image (but I could also vary the dimensions) and a very small 2D kernel (a laplacian 2d kernel, so it's a 3x3 kernel.. too small to take a huge advantage with all the cuda threads). I created a CPU classic implementation (two for loops, as easy as you would think) and then I started creating CUDA kernels. After a few disappointing attempts to perform a faster convolution I ended up with this code: http://www.evl.uic.edu/sjames/cs525/final.html (see the Shared Memory section), it basically lets a 16x16 threads block load all the convolution data he needs in the shared memory and then performs the convolution. Nothing, the CPU is still a lot faster. I didn't try the FFT approach because the CUDA SDK states that it is efficient with large kernel sizes. Whether or not you read everything I wrote, my question is: how can I perform a fast 2D convolution between a relatively large image and a very small kernel (3x3) with CUDA?

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  • C++ converting binary(P5) image to ascii(P2) image (.pgm)

    - by tubby
    I am writing a simple program to convert grayscale binary (P5) to grayscale ascii (P2) but am having trouble reading in the binary and converting it to int. #include <iostream> #include <fstream> #include <sstream> using namespace::std; int usage(char* arg) { // exit program cout << arg << ": Error" << endl; return -1; } int main(int argc, char* argv[]) { int rows, cols, size, greylevels; string filetype; // open stream in binary mode ifstream istr(argv[1], ios::in | ios::binary); if(istr.fail()) return usage(argv[1]); // parse header istr >> filetype >> rows >> cols >> greylevels; size = rows * cols; // check data cout << "filetype: " << filetype << endl; cout << "rows: " << rows << endl; cout << "cols: " << cols << endl; cout << "greylevels: " << greylevels << endl; cout << "size: " << size << endl; // parse data values int* data = new int[size]; int fail_tracker = 0; // find which pixel failing on for(int* ptr = data; ptr < data+size; ptr++) { char t_ch; // read in binary char istr.read(&t_ch, sizeof(char)); // convert to integer int t_data = static_cast<int>(t_ch); // check if legal pixel if(t_data < 0 || t_data > greylevels) { cout << "Failed on pixel: " << fail_tracker << endl; cout << "Pixel value: " << t_data << endl; return usage(argv[1]); } // if passes add value to data array *ptr = t_data; fail_tracker++; } // close the stream istr.close(); // write a new P2 binary ascii image ofstream ostr("greyscale_ascii_version.pgm"); // write header ostr << "P2 " << rows << cols << greylevels << endl; // write data int line_ctr = 0; for(int* ptr = data; ptr < data+size; ptr++) { // print pixel value ostr << *ptr << " "; // endl every ~20 pixels for some readability if(++line_ctr % 20 == 0) ostr << endl; } ostr.close(); // clean up delete [] data; return 0; } sample image - Pulled this from an old post. Removed the comment within the image file as I am not worried about this functionality now. When compiled with g++ I get output: $> ./a.out a.pgm filetype: P5 rows: 1024 cols: 768 greylevels: 255 size: 786432 Failed on pixel: 1 Pixel value: -110 a.pgm: Error The image is a little duck and there's no way the pixel value can be -110...where am I going wrong? Thanks.

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  • What is the best algorithm to locate a point in an image file?

    - by suugaku
    Hi all, I want to create a mark sheet recognizer. Here is the description: My system uses black and white color scheme. The mark sheet paper has a small black rectangle on each corner and an additional small black rectangle, to determine orientation, near one of the previous rectangles. The paper is scanned to yield an image (in bmp format for example). The first step is to locate these five references in image as eficient as possible. My rough idea is to trace row by row and from left to right for each row. It sounds very slow I think. Is there any better way to do that? Thank you in advance. regards, Suugaku

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  • MongoDB: What's the point of using MapReduce without parallelism?

    - by netvope
    Quoting http://www.mongodb.org/display/DOCS/MapReduce#MapReduce-Parallelism As of right now, MapReduce jobs on a single mongod process are single threaded Without parallelism, what are the benefits of MapReduce compared to simpler or more traditional methods for queries and data aggregation? To avoid confusion: the question is NOT "what are the benefits of document-oriented DB over traditional relational DB"

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  • Parallelizing some LINQ to XML

    - by Lol coder
    How can I make this code run in parallel? List<Crop> crops = new List<Crop>(); //Get up to 10 pages of data. for (int i = 1; i < 10; i++) { //i is basically used for paging. XDocument document = XDocument.Load(string.Format(url, i)); crops.AddRange(from c in document.Descendants("CropType") select new Crop { //The data here. }); }

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  • Matlab matrix translation and rotation multiple times

    - by pinnacler
    I have a map of individual trees from a forest stored as x,y points in a matrix. I call it fixedPositions. It's cartesian and (0,0) is the origin. I would like 0/360 degrees to be the top of the screen and 90 degrees to be to the right. Given a velocity and a heading, i.e. .5 m/s and 60 degrees (2 o'clock equivalent on a watch), how do I rotate that x,y points, so that the new origin is centered at (.5cos(60),.5sin(60)) and 60 degrees is now at the top of the screen? Then if I were to give you another heading and speed, i.e. 0 degrees and 2m/s, it should calculate it from the last point, not the original fixedPositions origin. I've wasted my day trying to figure this out. I wish I took matrix algebra but I'm at a loss. I tried doing cos(30) and even those wouldn't compute correctly, which after an hour I realize were in radians.

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  • How to scale JPEG image down so that text is clear as possible?

    - by Juha Syrjälä
    I have some JPEG images that I need scale down to about 80% of original size. Original image dimension are about 700px × 1000px. Images contain some computer generated text and possibly some graphics (similar to what you would find in corporate word documents). How to scale image so that the text is as legible as possible? Currently we are scaling the imaeg down using bicubic interpolation, but that makes the text blurry and foggy.

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  • Integrating PayMill: The token filled input field is not created, error "field_invalid_amount"

    - by automatix
    I'm implementing the Credit Card Payment form of PayMill according to the Payment Form docu. So I copied the JS from the Bridge docu page and the form from the Payment Form docu page. But no token is created. When I try to debug the JS and add console.info(error.apierror); into the paymillResponseHandler(...) function, I get the error code: field_invalid_amount. According to the support page There are three possible reasons for this error message: no amount value was provided numbers were rounded wrong delimiter symbol But the amuont is provided and I've already tried different delimiter symbols. What "numbers were rounded" means, is not clear. What can be the problem and how to fix this issue? Code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta name="generator" content="PSPad editor, www.pspad.com"> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script> <title> </title> </head> <body> <!-- PayMill HEAD start --> <link rel="stylesheet" href="https://netdna.bootstrapcdn.com/twitter-bootstrap/2.2.1/css/bootstrap.no-responsive.no-icons.min.css" /> <script type="text/javascript"> var PAYMILL_PUBLIC_KEY = '51668632777bf03b57f861c5a7278a38'; </script> <script type="text/javascript" src="https://bridge.paymill.com/"></script> <!-- PayMill HEAD stop --> <!-- PayMill FORM start --> <form id="payment-form" class="span4" action="payment.php" method="POST"> <p class="payment-errors alert-error span3" style="display:none;"> </p> <div id="payment-form-cc"> <div class="controls controls-row"> <div class="span2"> <label class="card-number-label">Kreditkarte </label> <input class="card-number span2" type="text" size="20" value="4111111111111111"/> </div> <div class="span1"> <label class="card-cvc-label">CVC </label> <input class="card-cvc span1" type="text" size="4" value="111"/> </div> </div> <div class="controls controls-row"> <div class="span3 card-icon"> </div> </div> <div class="controls controls-row"> <div class="span3"> <label class="card-holdername-label">Karteninhaber </label> <input class="card-holdername span3" type="text" size="20" value="lala"/> </div> </div> <div class="controls controls-row"> <div class="span3"> <label class="card-expiry-label">Gültigkeitsdatum (MM/YYYY) </label> <input class="card-expiry-month span1" type="text" size="2" value="12"/> <span style="float:left;"> / </span> <input class="card-expiry-year span1" type="text" size="4" value="2015"/> </div> </div> </div> <div class="controls controls-row"> <div class="span2"> <label class="amount-label">Betrag </label> <input class="amount span2" type="text" size="5" value="9,99" name="amount"/> </div> <div class="span1"> <label class="currency-label">Währung </label> <input class="currency span1" type="text" size="3" value="EUR" name="currency"/> </div> </div> <div class="controls controls-row"> <div class="span4"> <button class="submit-button btn btn-primary" type="submit" >Pay!</button> </div> </div> </form> <!-- PayMill FORM stop --> <!-- PayMill FOOT start --> <script type="text/javascript"> function paymillResponseHandler(error, result) { if (error) { console.info(error.apierror); // Displays the error above the form $(".payment-errors").text(error.apierror); } else { console.info('OK'); var form = $("#payment-form"); // Output token var token = result.token; // Insert token into form in order to submit to server form.append( "<input type='hidden' name='paymillToken' value='"+token+"'/>" ); // Submit form form.get(0).submit(); } } </script> <script type="text/javascript"> paymill.createToken({ number: $('.card-number').val(), // required exp_month: $('.card-expiry-month').val(), // required exp_year: $('.card-expiry-year').val(), // required cvc: $('.card-cvc').val(), // required amount_int: $('.card-amount-int').val(), // required, e.g. "4900" for 49.00 EUR currency: $('.currency').val(), // required cardholder: $('.card-holdername').val() // optional }, paymillResponseHandler); </script> <!-- PayMill FOOT stop --> </body> </html>

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  • Expert system for writing programs?

    - by aaa
    I am brainstorming an idea of developing a high level software to manipulate matrix algebra equations, tensor manipulations to be exact, to produce optimized C++ code using several criteria such as sizes of dimensions, available memory on the system, etc. Something which is similar in spirit to tensor contraction engine, TCE, but specifically oriented towards producing optimized rather than general code. The end result desired is software which is expert in producing parallel program in my domain. Does this sort of development fall on the category of expert systems? What other projects out there work in the same area of producing code given the constraints?

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  • I/O Asynchronous Completion

    - by lockedscope
    In the following, it is said that an I/O handle must be associated with the thread pool but i could not find where in the given example an handle is associated with the thread. Which function or code helps to bind the file handle in that example? Using asynchronous I/O completion events, a thread from the thread pool processes data only when the data is received, and once the data has been processed, the thread returns to the thread pool. To make an asynchronous I/O call, an operating-system I/O handle must be associated with the thread pool and a callback method must be specified. When the I/O operation completes, a thread from the thread pool invokes the callback method. http://msdn.microsoft.com/en-us/library/aa720215(VS.71).aspx

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