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  • How do I compare 2 fields and return the lowest value of each record?

    - by BigRob
    I'm slowly learning access to make a database of products and suppliers for my parents' business. What i've got is a table of products indexed by our product reference and 2 more tables for 2 different suppliers that contains the suppliers product reference and price that links with our reference. I've made a query that performs a left outer join such that it returns a table of our products with each supplier's reference and price, i.e: Ref | Product Name | Supplier 1 Ref | Supplier 1 Price | Supplier 2 Ref | Supplier 2 Price Here's the query I used: SELECT Catalog.Ref, Catalog.[Product Name], Catalog.Price, [D Products].[Supplier Ref], [D Products].Cost, [GS Products].[Supplier Ref], [GS Products].Cost FROM ([Catalog] LEFT JOIN [D Products] ON Catalog.Ref = [D Products].Ref) LEFT JOIN [GS Products] ON Catalog.Ref = [GS Products].Ref; Not all products are available from both suppliers, hence the outer join. What I want to do (with a query?) is to take the table produced by the query above and simply show the product reference, cheapest supplier reference and cheapest supplier price, i.e: Ref | Cheapest Suppplier Ref | Cheapest Supplier Price Unfortunately my SQL knowledge isn't quite good enough to figure this out, but if anyone can help i'd really appreciate it. Thanks, Rob

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  • how to change a while sql query loop into an array loop

    - by Mac Taylor
    hey guys i record number of queries of my website and in page the below script runs , 40 extra queries added to page . how can I change this sql connection into a propper and light one function tree_set($index) { //global $menu; Remove this. $q=mysql_query("select id,name,parent from cats where parent='$index'"); if(mysql_num_rows($q) === 0) { return; } // User $tree instead of the $menu global as this way there shouldn't be any data duplication $tree = $index > 0 ? '<ul>' : ''; // If we are on index 0 then we don't need the enclosing ul while($arr=mysql_fetch_assoc($q)) { $subFileCount=mysql_query("select id,name,parent from cats where parent='{$arr['id']}'"); if(mysql_num_rows($subFileCount) > 0) { $class = 'folder'; } else { $class = 'file'; } $tree .= '<li>'; $tree .= '<span class="'.$class.'">'.$arr['name'].'</span>'; $tree .=tree_set("".$arr['id'].""); $tree .= '</li>'."\n"; } $tree .= $index > 0 ? '</ul>' : ''; // If we are on index 0 then we don't need the enclosing ul return $tree; } i heard , this can be done by changing it into an array , but i don't know how to do so thanks in advance

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  • submit in html on sql query

    - by user1644661
    i need to run this sql query , which give me a list of Id and Dates i want to click each result and take with me the Id value to the next form i wrote this query above but i see in the debager that the hidden ID get his value but not pass to the next form i think i have a problem with the submit() . where should i put him ? thanks anat function ShowAllCarts($user_email) { $connB = new ProductDAO(); $connB->Connect(); $pro_query = "SELECT * FROM Cart WHERE `Email`='$user_email';"; $db_result = $connB->ExecSQL($pro_query); $html_result = '<div data-role="content"> <ul data-role="listview" data-theme="b"> '; $html_result .= '<form action="PreviouscartProduct.php" method="POST"/>'; while($row_array = $db_result->fetch_array(MYSQLI_ASSOC)) { $Id= $row_array['Id']; $Date= $row_array['Date']; //$html_result // $html_result .="<li><a href='PreviouscartProduct.php'>Cart number: $Id from Date: $Date><input type='hidden' name='Id' value'<?=$Id?>'</input></a></li>'"; $html_result .= '<a onclick="this.form.submit();" </a>; } $html_result .= ' </ul> </div>'; $html_result .= '</form>'; $connB->Disconnect(); return $html_result; } //display all carts $func_result = ShowAllCarts($Email);

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  • highlighting data values in a sql result set

    - by potatoe
    I can think of a number of ways to do this in PHP or even JavaScript, but I'm wondering if there's a SQL-based technique I'm overlooking. I have a database table, let's say 20 fields X 10 rows. I want to display the entire table on an web page, so I'd do something like SELCT * FROM data_table;, and then format the result set using HTML table tags. However, I'd also like to highlight values in the table based on whether they are the maximum or minimum value in their column. For example, I'd add bold tags around the max in each column. A resulting table might look something like this, with bold tags shown: id | field1 | field2 | field3 | ... 0 | 5 | 2 | <b>7</b> | ... 1 | 3 | <b>8</b> | 6 | ... 2 | <b>9</b> | 5 | 1 | ... ... I could do a separate SELECT with an ORDER BY for each field and then interpret the results, but that seems like a lot of extra DB access. My alternative right now is to just fetch the whole table, and then sort/search for the highlight values using PHP. Is there a better way?

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  • getting double value from group concact

    - by Sackling
    I am having a problem where I am getting duplicated values from what I think I should be getting. here is my sql: SELECT DISTINCT p.products_image, pd.products_name, p.products_id, p.products_model, p.manufacturers_id, m.manufacturers_name, p.products_price, p.products_sort_order, p.products_tax_class_id, pd.products_viewed, group_concat(p2i.icons_id separator ",") AS icon_ids, group_concat(pi.icon_class separator ",") AS icon_class, IF(s.status, s.specials_new_products_price, NULL) AS specials_new_products_price, IF(s.status, s.specials_new_products_price, p.products_price) AS final_price FROM products p LEFT JOIN specials s ON p.products_id = s.products_id LEFT JOIN manufacturers m ON p.manufacturers_id = m.manufacturers_id JOIN products_description pd ON p.products_id = pd.products_id JOIN products_to_categories p2c ON p.products_id = p2c.products_id INNER JOIN products_specifications ps7 ON p.products_id = ps7.products_id LEFT JOIN products_to_icon p2i ON p.products_id = p2i.products_id LEFT JOIN products_icons pi ON p2i.icons_id = pi.icons_id WHERE p.products_status = '1' AND pd.language_id = '1' AND ps7.specification IN ('Polycotton' , 'Reflective') AND ps7.specifications_id = '7' AND ps7.language_id = '1' AND p2c.categories_id = '21' GROUP BY p.products_id ORDER BY p.products_sort_order The column that is getting double values is icon_ids from the group concact. This seams to happen only if ploycotton, and reflective are both IN ps7.specification. If it is only one or the other then it works fine. The products_to_icon table contains 2 columns, products_id and icons_id. If a product has 2 icons, there are 2 rows so I'm pretty sure it is this fact that is causing the duplicate icons ids. When I run this, the icon_ids column for a product with 2 icons is "4,4,6,6" for example, when what I need is "4,6"

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  • What's wrong with this inner query (MySQL)...

    - by stuboo
    ...besides the fact that I am a total amateur? My table is set up like this: CREATE TABLE `messages` ( `id` int(6) unsigned NOT NULL AUTO_INCREMENT, `patient_id` int(6) unsigned NOT NULL, `message` varchar(255) NOT NULL, `savedate` int(10) unsigned NOT NULL, `senddate` int(10) unsigned NOT NULL, `SmsSid` varchar(40) NOT NULL COMMENT 'where we store the cookies from twilio', `sendorder` tinyint(3) unsigned NOT NULL COMMENT 'the order we want the msg sent in', `sent` tinyint(1) NOT NULL COMMENT '0=queued, 1=sent, 2=sent-unqueued,4=rec-unread,5=recd-read', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=143 ; I need a query that will SELECT * FROM `messages` WHERE `senddate` < $now AND `sent` = 0 (AND LIMIT TO ONLY ONE RECORD PER `patient_id`) I've tried the following: SELECT * FROM `messages` WHERE `senddate` IN (SELECT `patient_id`, max(`senddate`) GROUP by `patient_id`) AND `senddate` < $now AND `sent` = 0 ; But I get this error: MySQL client version: 5.1.37 `#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP by patient_id) AND senddate < 1270093898 AND sent = 0 LIMIT 0, 30' at line 5

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  • mysql report sql help

    - by sfgroups
    I have mysql table with data like this. record will have server with total cpu and virtual server with cpu assinged type, cpu srv1, 10 vsrv11, 2 vsrv12, 3 srv2, 15 vsrv21, 6 vsrv22, 7 vsrv23, 1 from the above data, I want to create output like this. server, total cpu, assigned cpu, free cpu srv1, 10, 5, 5 srv2, 15, 14, 1 Can you help me on creating sql query for this report? I have changed my table and data like this. CREATE TABLE `cpuallocation` ( `servertype` varchar(10) DEFAULT NULL, `servername` varchar(20) DEFAULT NULL, `hostname` varchar(20) DEFAULT NULL, `cpu_count` float DEFAULT NULL, UNIQUE KEY `server_uniq_idx` (`servertype`,`servername`,`hostname`) insert into cpuallocation values('srv', 'server1', '',16); insert into cpuallocation values('vir', 'server1', 'host1',5); insert into cpuallocation values('vir', 'server1', 'host2',2.5); insert into cpuallocation values('vir', 'server1', 'host3',4.5); insert into cpuallocation values('srv', 'server2', '',8); insert into cpuallocation values('vir', 'server2', 'host1',5); insert into cpuallocation values('vir', 'server2', 'host2',2.5); insert into cpuallocation values('srv', 'server3', '',24); insert into cpuallocation values('vir', 'server3', 'host1',12); insert into cpuallocation values('vir', 'server3', 'host2',2); insert into cpuallocation values('srv', 'server4', '',12); Update: I created two view, now I getting the result I want. create view v1 as select servername, sum(cpu_count) as cpu_allocated from cpuallocation where servertype='vir' group by servername; create view v2 as select servername, cpu_count as total_cpu from cpuallocation where servertype='srv'; select a.servername, a.total_cpu, b.cpu_allocated from v2 as a left join v1 as b on a.servername=b.servername; +------------+-----------+---------------+ | servername | total_cpu | cpu_allocated | +------------+-----------+---------------+ | server1 | 16 | 12 | | server2 | 8 | 7.5 | | server3 | 24 | 14 | | server4 | 12 | NULL | +------------+-----------+---------------+ 4 rows in set (0.00 sec) Is it possible to create a query with-out creating views?

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  • Advance Query with Join

    - by user1462589
    I'm trying to convert a product table that contains all the detail of the product into separate tables in SQL. I've got everything done except for duplicated descriptor details. The problem I am having all the products have size/color/style/other that many other products contain. I want to only have one size or color descriptor for all the items and reuse the "ID" for all the product which I believe is a Parent key to the Product ID which is a ...Foreign Key. The only problem is that every descriptor would have multiple Foreign Keys assigned to it. So I was thinking on the fly just have it skip figuring out a Foreign Parent key for each descriptor and just check to see if that descriptor exist and if it does use its Key for the descriptor. Data Table PI Colo Sz OTHER 1 | Blue | 5 | Vintage 2 | Blue | 6 | Vintage 3 | Blac | 5 | Simple 4 | Blac | 6 | Simple =================================== Its destination table is this =================================== DI Description 1 | Blue 2 | Blac 3 | 5 4 | 6 6 | Vintage 7 | Simple ============================= Select Data.Table Unique.Data.Table.Colo Unique.Data.Table.Sz Unique.Data.Table.Other ======================================= Then the dual part of the questions after we create all the descriptors how to do a new query and assign the product ID to the descriptors. PI| DI 1 | 1 1 | 3 1 | 4 2 | 1 2 | 3 2 | 4 By figuring out how to do this I should be able to duplicate this pattern for all 300 + columns in the product. Some of these fields are 60+ characters large so its going to save a ton of space. Do I use a Array?

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  • Parallel MySQL queries for HTML table - WHILE(x or y)?

    - by Beti Chode
    I'm trying to create a table using PHP. What I need is a table with two columns. So I have an SQL table with 4 fields - primary key id, language, word and definition. The language for each is either Arabic or Russian. I want a table that does the following: | defintion | |____________________| | | | rus1 | arab1 | | rus2 | arab2 | | rus3 | arab3 | | rus4 | | So it divides the list by English word, creates a for each English word, then lists Russian equivalents in the left column and Arabic in the right. However there are often not the same number for both. What I am doing right now is running a WHILE loop in a WHILE loop. The outer loop is running fine but I think I am doing the inner loop wrong. Here is the bulk of the code: $definitions=mysql_query("SELECT DISTINCT definition FROM words") WHILE($row=mysql_fetch_array($definitions) { ECHO '<tr><th colspan="2">' . $row['definition'] . '</th></tr>'; $russian="SELECT * FROM words WHERE language='Russian' AND definition='".$row['definition']."'"; $arabic="SELECT * FROM words WHERE language='Arabic' AND definition='".$row['definition']."'"; WHILE($rus=mysql_fetch_array($russian) or $arb=mysql_fetch_array($arabic)) { ECHO '<tr><td>'.$rus['word'].'</td><td>'.$arb['word'].'</td></tr>'; } } Sadly I am getting soemthing like this: | defintion | |____________________| | | | rus1 | | | rus2 | | | rus3 | | | rus4 | | | | arab1 | | | arab2 | | | arab3 | Not sure what other way I can do this? I tried changing the or to || thinking the different precedence would cause another outcome, but then I get ONLY the Russian column. I'm out of ideas, you guys are my only hope!

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  • Replace beginning words

    - by Newbie
    I have the below tables. tblInput Id WordPosition Words -- ----------- ----- 1 1 Hi 1 2 How 1 3 are 1 4 you 2 1 Ok 2 2 This 2 3 is 2 4 me tblReplacement Id ReplacementWords --- ---------------- 1 Hi 2 are 3 Ok 4 This The tblInput holds the list of words while the tblReplacement hold the words that we need to search in the tblInput and if a match is found then we need to replace those. But the problem is that, we need to replace those words if any match is found at the beginning. i.e. in the tblInput, in case of ID 1, the words that will be replaced is only 'Hi' and not 'are' since before 'are', 'How' is there and it is not in the tblReplacement list. in case of Id 2, the words that will be replaced are 'Ok' & 'This'. Since these both words are present in the tblReplacement table and after the first word i.e. 'Ok' is replaced, the second word which is 'This' here comes first in the list of ID category 2 . Since it is available in the tblReplacement, and is the first word now, so this will also be replaced. So the desired output will be Id NewWordsAfterReplacement --- ------------------------ 1 How 1 are 1 you 2 is 2 me My approach so far: ;With Cte1 As( Select t1.Id ,t1.Words ,t2.ReplacementWords From tblInput t1 Cross Join tblReplacement t2) ,Cte2 As( Select Id, NewWordsAfterReplacement = REPLACE(Words,ReplacementWords,'') From Cte1) Select * from Cte2 where NewWordsAfterReplacement <> '' But I am not getting the desired output. It is replacing all the matching words. Urgent help needed*.( SET BASED )* I am using SQL Server 2005. Thanks

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  • LINQ Many to Many With In or Contains Clause (and a twist)

    - by Chris
    I have a many to many table structure called PropertyPets. It contains a dual primary key consisting of a PropertyID (from a Property table) and one or more PetIDs (from a Pet table). Next I have a search screen where people can multiple select pets from a jquery multiple select dropdown. Let's say somebody selects Dogs and Cats. Now, I want to be able to return all properties that contain BOTH dogs and cats in the many to many table, PropertyPets. I'm trying to do this with Linq to Sql. I've looked at the Contains clause, but it doesn't seem to work for my requirement: var result = properties.Where(p => search.PetType.Contains(p.PropertyPets)); Here, search.PetType is an int[] array of the Id's for Dog and Cat (which were selected in the multiple select drop down). The problem is first, Contains requires a string not an IEnumerable of type PropertyPet. And second, I need to find the properties that have BOTH dogs and cats and not just simply containing one or the other. Thank you for any pointers.

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  • How could I install Ubuntu One on KDE and use it with dolphin?

    - by tobiasBora
    I see in some topics that to install ubuntu-one, I've to execute these commands : sudo add-apt-repository ppa:apachelogger/ubuntuone-kde sudo apt-get update sudo apt-get install ubuntuone-kde However, it don't work (Is ppa:apachelogger/ubuntuone-kde closed ?) : sudo add-apt-repository ppa:apachelogger/ubuntuone-kde You are about to add the following PPA to your system: ubuntuone-kde tag:launchpad.net:2008:redacted More info: https://launchpad.net/~apachelogger/+archive/ubuntuone-kde Press [ENTER] to continue or ctrl-c to cancel adding it Executing: gpg --ignore-time-conflict --no-options --no-default-keyring --secret-keyring /tmp/tmp.UJpbwWvbov --trustdb-name /etc/apt/trustdb.gpg --keyring /etc/apt/trusted.gpg --primary-keyring /etc/apt/trusted.gpg --keyserver hkp://keyserver.ubuntu.com:80/ --recv tag:launchpad.net:2008:redacted gpg: « tag:launchpad.net:2008:redacted » n'est pas une ID de clé: ignoré How could I install ubunto-one on KDE and use it with dolphin ?

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  • Microsoft Developer Training Kits

    - by Ricardo Peres
    Here's a personal list of some of Microsoft's available and updated developer training kits: PHP on Windows Training Kit: http://www.microsoft.com/downloads/details.aspx?displaylang=en&familyid=c8498c9b-a85a-4afa-90c0-593d0e4850cb Identity Developer Training Kit: http://www.microsoft.com/downloads/details.aspx?familyid=C3E315FA-94E2-4028-99CB-904369F177C0&displaylang=en Office 2010 Developer Training Kit: http://www.microsoft.com/downloads/details.aspx?displaylang=en&FamilyID=f1599288-a99f-410f-a219-f4375dbe310c SharePoint 2010 Developer Training Kit: http://www.microsoft.com/downloads/details.aspx?FamilyID=bfd1603b-7550-4b8e-be85-4215a5069b90 Silverlight 4 Training: http://www.microsoft.com/downloads/details.aspx?FamilyID=24cea29e-042e-41c9-aa16-684a0ca5f5db SQL Server 2008 R2 Training Kit (includes SQL Server 2008): http://www.microsoft.com/downloads/details.aspx?FamilyID=fffaad6a-0153-4d41-b289-a3ed1d637c0d Visual Studio 2010 and .NET Framework 4 Training Kit: http://www.microsoft.com/downloads/details.aspx?FamilyID=752cb725-969b-4732-a383-ed5740f02e93 Windows Server 2008 R2 Developer Training Kit: http://www.microsoft.com/downloads/details.aspx?FamilyID=c48b3eb4-ad4b-461c-9d5a-25f45d949b92&displaylang=en Windows 7 Training Kit For Developers: http://www.microsoft.com/downloads/details.aspx?familyid=1C333F06-FADB-4D93-9C80-402621C600E7&displaylang=en Windows Phone 7 Training Kit for Developers: http://www.microsoft.com/downloads/details.aspx?familyid=CA23285F-BAB8-47FA-B364-11553E076A9A&displaylang=en Windows Mobile 6.5 Developer Tool Kit: http://www.microsoft.com/downloads/details.aspx?familyid=20686A1D-97A8-4F80-BC6A-AE010E085A6E&displaylang=en

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  • Donald Farmer comes to SQLBits

    What do medieval archaeology, fish farming, Southwestern University of Chongqing and Microsoft Business Intelligence have in common? If you know, you should tell Donald Farmer, because he has been deeply involved in all of them at various times. Donald has worked in the Microsoft Business Intelligence team for 8 years covering many subject areas: data integration, information quality, metadata intelligence, master data management, OLAP, predictive analytics and self-service BI. He is a well-known speaker at Microsoft and other industry events, and the author of several books and articles.   Great news from SQLBits! We can now confirm that Donald Farmer has agreed to do a pre-conference training day and the key note for our SQL Server 2008 and SQL Server 2008 R2 day. As Program Manager for Project Gemini, no-one is better placed to tell you what is going to be in R2 and what is not! More information about the Pre-conference Training Day and SQL 2008 and R2 Friday will be released soon.

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  • Donald Farmer comes to SQLBits

    What do medieval archaeology, fish farming, Southwestern University of Chongqing and Microsoft Business Intelligence have in common? If you know, you should tell Donald Farmer, because he has been deeply involved in all of them at various times. Donald has worked in the Microsoft Business Intelligence team for 8 years covering many subject areas: data integration, information quality, metadata intelligence, master data management, OLAP, predictive analytics and self-service BI. He is a well-known speaker at Microsoft and other industry events, and the author of several books and articles.   Great news from SQLBits! We can now confirm that Donald Farmer has agreed to do a pre-conference training day and the key note for our SQL Server 2008 and SQL Server 2008 R2 day. As Program Manager for Project Gemini, no-one is better placed to tell you what is going to be in R2 and what is not! More information about the Pre-conference Training Day and SQL 2008 and R2 Friday will be released soon.

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  • Webcasts con TechNet Latam Windows Server y Windows 7

    - by David Nudelman
    La gente de Microsoft TechNet LATAM me invitó a presentar 3 webcasts sobre Windows Server 2008 R2 e implementación de Windows 7, temas que tengo bastante familiaridad. Os dejo la información y el enlace de registro. 25 de Mayo - 2:30 PM-4:00 PM (UTC-05:00) Webcast TechNet: "Una demo para conocer Windows Server 2008 R2" 26 de Mayo - 2:30 PM-4:00 PM (UTC-05:00) Webcast TechNet: "Serie Cómo hacer: Determinación de la mejor opción de implementación y herramientas que se deben utilizar con sus clientes" 1 de Junio - 1:30 PM-3:00 PM (UTC-05:00) Webcast TechNet: "Implementación rápida - Cambio de clientes de XP a Win7 fácil y rápido" Saludos, David Nudelman Technorati Tags: webcasts,server 2008 r2,windows 7,mvp

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  • VSDB to SSDT Series : Introduction

    - by Etienne Giust
    At the office, we extensively use VS2010 SQL Server 2008 Database Projects and SQL Server 2008 Server Projects  in our Visual Studio 2010 solutions. With Visual Studio 2012, those types of projects are replaced by the  SQL Server Database Project  using the SSDT (SQL Server Data Tools) technology. I started investigating the shift from Visual Studio 2010 to Visual Studio 2012 and specifically what needs to be done concerning those database projects in terms of painless migration, continuous integration and standalone deployment. I will write my findings in a series of 4 short articles: Part 1 will be about the database projects migration process and the cleaning up that ensues Part 2 will be about creating SQL Server 2008 Server Projects equivalents with the new SSDT project type Part 3 will introduce a replacement to the vsdbcmd.exe command used for deployment in our continuous integration process Part 4 will explain how to create standalone packages of SSDT projects for deployment on non accessible servers (such as a production server)

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  • BizTalk 2009 - Project Creation Failed

    - by StuartBrierley
    A couple of weeks ago I had some issue with my BizTalk Server 2009 development environment  which resulted in a reinstall of Visual Studio 2008 and the Visual Studio 2008 Service Pack 1. Following this reinstall I began to have problems when trying to create  BizTalk 2009 projects: Error Details: “Create BizTalk Project …. Project Creation Failed” It turns out that this is a known issue with BizTalk Server 2009 and Visual Studio 2008, whereby the installation of the Visual Studio Service Pack 1 can cause corruption to the BizTalk installation preventing the creation of any new projects. To resolve this issue go to control panel > add or remove programs > Microsoft BizTalk Server 2009 and select Change or Remove.  When the window opens choose “Repair”.  Upon completion you should once again be able to create BizTalk projects.

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  • E-Business Suite R12 Certified on 2012 Hyper-V Windows Guests

    - by John Abraham
    Oracle E-Business Suite Release 12 (12.1) is now certified on Windows Server 2008 (32-bit) and Windows Server 2008 R2 running as guest operating systems within Window Server 2012 Hyper-V virtual machines. Hyper-V is a built-in feature of Microsoft Windows Server that allows for the creation and management of virtualized computing environments. With this certification, the E-Business Suite is now supported on the above Windows virtualized guest operating systems in a similar way to non-virtualized Windows. References Note 761567.1 - Oracle E-Business Suite Installation and Upgrade Notes Release 12 (12.1.1) for Microsoft Windows Server (32-bit) Note 1188535.1 - Migrating Oracle E-Business Suite R12 to Microsoft Windows Server 2008 R2 Note 1563794.1 - Certified Software on Microsoft Windows Server 2012 Hyper-V Windows Server Hyper-V Overview

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  • Hyper-V Windows Guest Isletim Sistemleri için E-Business Suite R12 Sertifikasi Yayinlandi

    - by TUFEKCIOGLU,FATIH
    Windows Server 2012 Hyper-V sanal makinalarinda guest isletim sistemi olarak çalisan Windows Server 2008 (32-bit) ve Windows Server 2008 R2 için Oracle E-Business Suite Release 12 (12.1) sertifikasi yayinlandi. Hyper-V, Microsoft Windows sunucularda bulunan dahili bir özelliktir ve sanallastirilmis ortamlar olusturmaya ve yönetmeye olanak saglar. Bu sertifika ile E-Business Suite, yukarida belirtilen Windows sanallastirilmis guest isletim sistemleri üzerinde desteklenmektedir. Referanslar : •Note 761567.1 - Oracle E-Business Suite Installation and Upgrade Notes Release 12 (12.1.1) for Microsoft Windows Server (32-bit)•Note 1188535.1 - Migrating Oracle E-Business Suite R12 to Microsoft Windows Server 2008 R2•Note 1563794.1 - Certified Software on Microsoft Windows Server 2012 Hyper-V•Windows Server Hyper-V Overview Orjinal Kaynak (Original Source) : Steven Chan Oracle Blog : https://blogs.oracle.com/stevenChan/entry/e_business_suite_r12_certified

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  • [Oracle Identity Manager] 11g R2 Bundle Patch 09 is Available!

    - by mustafakaya
    Oracle Identity Manager Bundle Patch 09 is available now. You can download BP09 from here. Also,there is a important recommendation for BP08!  List of bugs fixed with BP09; Bug:12699224 : Trusted source reconciliation fails to create users with many reconciliation field mappings. Bug:14407437 : Provisioning through bulk request inserts null records into child tables. Bug:14493217 : Target resource reconciliation throws ORA-06512 error when the Descriptive field is mapped to a field that does not have a reconciliation field mapping. Bug:16044671 : User form customization fails if a UDF contains invalid character. Bug:16545968 : Modifying any attribute on a service account changes the account type as a primary account. Bug:16562633 : Oracle Identity Manager throws javax.el.elexceptions while viewing profile under direct report. Bug:16662834 : User not reprovisoned after user is deleted and created in the target with the same orclguid. Bug:16662905 : If an LOV field is required on an Application Instance form, no validation is enforced on the LOV field although it is required. Bug:16701873 : The Members tab of a role displays only enabled users and does not display disabled users. Bug:16862846 : When a notification is being sent, the mail ID in the Reply To field is set as the recipient's mail ID instead of the sender's mail ID. Bug:16824062 : When you use API to fetch or delete child data from an account, the child data row value is null. Therefore, child data is not returned. Bug:16912736 : There is a performance issue when the provisioned application instance details is opened for a user.

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