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  • Find value of selected item in Drop down menu.

    - by Ozaki
    I have a drop down menu in an ASPX page along the lines of: <form> <select name="cars"> <option value="volvo">Volvo</option> <option value="saab">Saab</option> <option value="fiat" selected="selected">Fiat</option> <option value="audi">Audi</option> </select> </form> That is dynamically generated from another controller (value and label). After the user selects one of the options I need to find out what the selected value/label (will be the same) is so I can hit an update button and retrieve the data on that option. What would be the easiest way to find out the value of the user "selected" option?

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  • HTML form isn't emailing

    - by Anonmattymous
    I have this as my form <div class="contactInputs"> <p>Send us a message</p> <form class="messageForm" autocomplete="on" name="contactform" method="post" action="/freequote.php"> <input type="text" name="name" placeholder="Name*" required> <input type="text" name="companyname" placeholder="Company Name"> <input type="email" name="email" placeholder="Email*" required> <input type="tel" name="phone" placeholder="Phone"> <input class="contact-submit" type="submit"> </form> <textarea type="textarea" name="message" placeholder="Your Messages*" required></textarea> </div> And this is the PHP used to do send the Email. <?php if(isset($_POST['email'])) { $email_to = "[email protected]"; $email_subject = "Your email subject line"; function died($error) { echo "We are very sorry, but there were error(s) found with the form you submitted. "; echo "These errors appear below.<br /><br />"; echo $error."<br /><br />"; echo "Please go back and fix these errors.<br /><br />"; die(); } if(!isset($_POST['name']) || !isset($_POST['companyname']) || !isset($_POST['email']) || !isset($_POST['phone']) || !isset($_POST['comments'])) { died('We are sorry, but there appears to be a problem with the form you submitted.'); } $name = $_POST['name']; $companyname = $_POST['companyname']; $email_from = $_POST['email']; $phone = $_POST['phone']; $message = $_POST['comments']; $error_message = ""; $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/'; if(!preg_match($email_exp,$email_from)) { $error_message .= 'The Email Address you entered does not appear to be valid.<br />'; } $string_exp = "/^[A-Za-z .'-]+$/"; if(!preg_match($string_exp,$name)) { $error_message .= 'The First Name you entered does not appear to be valid.<br />'; } if(!preg_match($string_exp,$companyname)) { $error_message .= 'The Last Name you entered does not appear to be valid.<br />'; } if(strlen($message) < 2) { $error_message .= 'The Comments you entered do not appear to be valid.<br />'; } if(strlen($error_message) > 0) { died($error_message); } $email_message = "Form details below.\n\n"; function clean_string($string) { $bad = array("content-type","bcc:","to:","cc:","href"); return str_replace($bad,"",$string); } $email_message .= "First Name: ".clean_string($name)."\n"; $email_message .= "Last Name: ".clean_string($companyname)."\n"; $email_message .= "Email: ".clean_string($email_from)."\n"; $email_message .= "phone: ".clean_string($phone)."\n"; $email_message .= "Comments: ".clean_string($message)."\n"; $headers = 'From: '.$email_from."\r\n". 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion(); @mail($email_to, $email_subject, $email_message, $headers); ?> Thank you for contacting us. We will be in touch with you very soon. <?php } ?> But whenever i try to submit it, i get the errors We are very sorry, but there were error(s) found with the form you submitted. These errors appear below. We are sorry, but there appears to be a problem with the form you submitted. Please go back and fix these errors. Does anyone see whats wrong

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  • How to make a form using ajax, onchange event, reload to SAME page

    - by user1348220
    I've been studying this for a while and I'm not sure if I'm going about this the right way because every form I setup according to examples, it doesn't do what I need. I need to setup a form that will: set session when you select from dropdown menu not reload/refresh page (i've read that using AJAX solves this) submit and stay on SAME page (confused because most AJAX examples send it to different process.php page which is supposedly "invisible" but it doesn't "stay" on the same page, it redirects. Basically, client selects quantity of 1 to 10. If they select "2"... it does NOT reload the page.. but it DOES set a session[quantity]=2. Should be simple... but do I POST to same page as form? or POST to different page and it somehow redirects? Also, one test I did it kept pasting my "echo session[quantity]" down the page like 7, 2, 3, 5, etc. etc. each time instead of replacing it. I would paste code but it's all over the place and I'm hoping for direction on which methods to use. Feel I need to start all over again. Edit: trying to add code below but can't seem to paste it properly. <? ob_start();?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Submit Form with out refreshing page Tutorial</title> <!-- JavaScript --> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript" > $(function() { $(".submit").click(function() { var gender = $("#gender").val(); var dataString = '&gender=' + gender; if(gender=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "join.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); </script> <style type="text/css"> body{ } .error{ color:#d12f19; font-size:12px; } .success{ color:#006600; font-size:12px; } </style> </head> <body id="public"> <div style="height:30px"></div> <div id="container"> <div style="height:30px"></div> <form method="post" name="form"> <select id="gender" name="gender"> <option value="">Gender</option> <option value="male">Male</option> <option value="female">Female</option> </select> <div> <input type="submit" value="Submit" class="submit"/> <span class="error" style="display:none"> Please Enter Valid Data</span> <span class="success" style="display:none"> Your gender is <?php echo $_SESSION['gender'];?></span> </div> </form> <div style="height:20px"></div> </div><!--container--> </body> </html> <? ob_flush(); ?> and here is my page where the POST goes called join.php (called that in example so I went with it for now) <?php session_start(); if($_POST) { $gender = $_POST['gender']; $_SESSION['gender'] = $gender; } else { } ?>

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  • What is the recommended way to handle different user roles in a C# application?

    - by Sergio Tapia
    I'm going to make a small application for a business that will be used locally for scanning, and storing documents in a database located on the local machine or on a machine located in the same LAN. I could create a table called Users with username and password and according to the usertype ID show a form, or another form. But I'm more interested in the recommended approach by seasoned programmers. Any advice?

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  • Using CreateWindow() to make additional Window on a thread - C

    - by Jamie Keeling
    Hello, I have a windows form that has a simple menu and performs a simple operation, I want to be able to create another windows form with all the functionality of a menu bar, message pump etc.. as a separate thread so I can then share the results of the operation to the second window. I.E. 1) Form A opens Form B opens as a separate thread 2)Form A performs operation 3)Form A passes results via memory to Form B 4)Form B display results I'm confused as to how to go about it, the main app runs fine but i'm not sure how to add a second window if the first one already exists. I think that using CreateWindow will allow me to make another window but again i'm not sure how to access the message pump so I can respond to certain events like WM_CREATE on the second window. I hope it makes sense. Thanks!

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  • Accepting bank account information in a form

    - by jeffthink
    What security concerns are there when accepting a user's bank account information (account number and routing number) via a form on a page that is using SSL, and posting it back to the server where I then curl off a HTTPS request to send that information to an ACH service like First ACH or ACH Direct via their API? We wouldn't be saving the bank account information in our database. I know another option is to use Paypal's Mass Pay API, but they think it's unprofessional (at least for their business) to require customers to have a paypal account to get paid. Thoughts?

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  • Spring-Hibernate: How to submit a for when the object has one-to-many relations?

    - by Czar
    Hi, I have a form changeed the properties of my object CUSTOMER. Each customer has related ORDERS. The ORDER's table has a column customer_id which is used for the mapping. All works so far, I can read customers without any problem. When I now e.g. change the name of the CUSTOMER in the form (which does NOT show the orders), after saving the name is updated, but all relations in the ORDERS table are set to NULL (the customer_id for the items is set to NULL. How can I keep the relationship working? THX

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  • How to keep PayPal variables secure

    - by dclowd9901
    I'm trying to link my 3rd party shopping cart to PayPal, and in the process I'm finding that my variables are extremely exposed, such that, if someone uses, say, Firebug, to manipulate the values of my variables, they can change the cost of the items in the transaction. I'm very new to online carts and shopping, so my question is how do I keep this layer of exposure away from users and secure for the website?

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  • replace values in form.data when form fails validation

    - by John
    Hi I have a form field which requires a json object as its value when it is rendered. When the form is submitted it returns a comma seperated string of ids as its value (not a json string). however if the form does not validate i want to turn this string of ids back into a json string so it will display properly (is uses jquery to render the json object correctly). how would i do this? I was thinking of overwriting the form.clean method but when I tried to change self.data['fieldname'] I got the error 'This QueryDict instance is immutable' and when i tried to change self.cleaned_data['fieldname'] it didn't make a difference to the value of the field. Thanks

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  • Codeigniter form action with slashes instead of normal GETs?

    - by Ethan
    Hey, so this is one of those questions that seems obvious, and I'm probably going to feel stupid, but here goes: I'm doing a CodeIgniter site with a search. Think of a Google type input, where you'd search for "white huskies." I have a search results page that takes a URI (MySite.com/dogs/white huskies), and takes the third part, and performs the search on that term. I'd like this to be done in the URI, and no by POST so my users can bookmark results. The problem I'm having is how to get that search button directed to Mysite.com/dogs/WHATEVER IS IN THE INPUT. How do I get the what is in the input part into the anchor href? I know I could do this with javascript, but I've heard it's bad practice to force people to have javascript for things this small. Thanks for the help!

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  • IsAuthenticated is false!

    - by Naor
    This is how I login ('user' holds the data of the user): HttpResponse Response = HttpContext.Current.Response; HttpRequest Request = HttpContext.Current.Request; FormsAuthenticationTicket ticket = new FormsAuthenticationTicket(1, user.UserId.ToString(), DateTime.Now, DateTime.Now.AddHours(12), false, UserResolver.Serialize(user)); HttpCookie cookie = new HttpCookie(FormsAuthentication.FormsCookieName, FormsAuthentication.Encrypt(ticket)); cookie.Path = FormsAuthentication.FormsCookiePath; Response.Cookies.Add(cookie); string redirectUrl = user.HomePage; Response.Redirect(redirectUrl); After this login I get IsAuthenticated == false. Why?? It worked for me before an hour but I don't know what is wrong now.

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  • Integrating PayMill: The token filled input field is not created, error "field_invalid_amount"

    - by automatix
    I'm implementing the Credit Card Payment form of PayMill according to the Payment Form docu. So I copied the JS from the Bridge docu page and the form from the Payment Form docu page. But no token is created. When I try to debug the JS and add console.info(error.apierror); into the paymillResponseHandler(...) function, I get the error code: field_invalid_amount. According to the support page There are three possible reasons for this error message: no amount value was provided numbers were rounded wrong delimiter symbol But the amuont is provided and I've already tried different delimiter symbols. What "numbers were rounded" means, is not clear. What can be the problem and how to fix this issue? Code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta name="generator" content="PSPad editor, www.pspad.com"> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script> <title> </title> </head> <body> <!-- PayMill HEAD start --> <link rel="stylesheet" href="https://netdna.bootstrapcdn.com/twitter-bootstrap/2.2.1/css/bootstrap.no-responsive.no-icons.min.css" /> <script type="text/javascript"> var PAYMILL_PUBLIC_KEY = '51668632777bf03b57f861c5a7278a38'; </script> <script type="text/javascript" src="https://bridge.paymill.com/"></script> <!-- PayMill HEAD stop --> <!-- PayMill FORM start --> <form id="payment-form" class="span4" action="payment.php" method="POST"> <p class="payment-errors alert-error span3" style="display:none;"> </p> <div id="payment-form-cc"> <div class="controls controls-row"> <div class="span2"> <label class="card-number-label">Kreditkarte </label> <input class="card-number span2" type="text" size="20" value="4111111111111111"/> </div> <div class="span1"> <label class="card-cvc-label">CVC </label> <input class="card-cvc span1" type="text" size="4" value="111"/> </div> </div> <div class="controls controls-row"> <div class="span3 card-icon"> </div> </div> <div class="controls controls-row"> <div class="span3"> <label class="card-holdername-label">Karteninhaber </label> <input class="card-holdername span3" type="text" size="20" value="lala"/> </div> </div> <div class="controls controls-row"> <div class="span3"> <label class="card-expiry-label">Gültigkeitsdatum (MM/YYYY) </label> <input class="card-expiry-month span1" type="text" size="2" value="12"/> <span style="float:left;"> / </span> <input class="card-expiry-year span1" type="text" size="4" value="2015"/> </div> </div> </div> <div class="controls controls-row"> <div class="span2"> <label class="amount-label">Betrag </label> <input class="amount span2" type="text" size="5" value="9,99" name="amount"/> </div> <div class="span1"> <label class="currency-label">Währung </label> <input class="currency span1" type="text" size="3" value="EUR" name="currency"/> </div> </div> <div class="controls controls-row"> <div class="span4"> <button class="submit-button btn btn-primary" type="submit" >Pay!</button> </div> </div> </form> <!-- PayMill FORM stop --> <!-- PayMill FOOT start --> <script type="text/javascript"> function paymillResponseHandler(error, result) { if (error) { console.info(error.apierror); // Displays the error above the form $(".payment-errors").text(error.apierror); } else { console.info('OK'); var form = $("#payment-form"); // Output token var token = result.token; // Insert token into form in order to submit to server form.append( "<input type='hidden' name='paymillToken' value='"+token+"'/>" ); // Submit form form.get(0).submit(); } } </script> <script type="text/javascript"> paymill.createToken({ number: $('.card-number').val(), // required exp_month: $('.card-expiry-month').val(), // required exp_year: $('.card-expiry-year').val(), // required cvc: $('.card-cvc').val(), // required amount_int: $('.card-amount-int').val(), // required, e.g. "4900" for 49.00 EUR currency: $('.currency').val(), // required cardholder: $('.card-holdername').val() // optional }, paymillResponseHandler); </script> <!-- PayMill FOOT stop --> </body> </html>

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  • PHP SQL Form Insert

    - by Prateek Sachan
    I've developed a form that inserts many things into the database. But somehow, when the page is filled up; it inserts only the user_password that too of the database admin. here is the code. Any help would be great. Invalid Name: We want names with more than 3 letters. Invalid E-mail: Type a valid e-mail please. Passwords are invalid: Passwords doesnt match or are invalid! Please enter your contact number. Please enter your age Congratulations! All fields are OK ;)

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  • Google App Engine django model form does not pick up BlobProperty

    - by Wes
    I have the following model: class Image(db.Model): auction = db.ReferenceProperty(Auction) image = db.BlobProperty() thumb = db.BlobProperty() caption = db.StringProperty() item_to_tag = db.StringProperty() And the following form: class ImageForm(djangoforms.ModelForm): class Meta: model = Image When I call ImageForm(), only the non-Blob fields are created, like this: <tr><th><label for="id_auction">Auction:</label></th><td><select name="auction" id="id_auction"> <option value="" selected="selected">---------</option> <option value="ahRoYXJ0bWFuYXVjdGlvbmVlcmluZ3INCxIHQXVjdGlvbhgKDA">2010-06-19 11:00:00</option> </select></td></tr> <tr><th><label for="id_caption">Caption:</label></th><td><input type="text" name="caption" id="id_caption" /></td></tr> <tr><th><label for="id_item_to_tag">Item to tag:</label></th><td><input type="text" name="item_to_tag" id="id_item_to_tag" /></td></tr> I want the Blob fields to be included in the form as well (as file inputs). What am I doing wrong?

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  • Using now() in a <asp:textbox>

    - by Anthony
    Can anyone help. I am using a formview in VS 2005. I have different elements in my form databound to a database and I am performing an INSERT SQL statement. No problem. The problem is that I am trying to enter the current date into the SQL statement and I am having a problem. I can add <%now()% to the "Text" property of the asp:Textbox. But when I do, then I can't bind the textbox to a specific database column. How do I do both???? I can do this: <asp:TextBox ID="TextBox2" runat="server" Text='<%# Bind("Initiate_Date") %>' ></asp:TextBox> Or this: <asp:TextBox ID="TextBox2" runat="server" Text='<%# now() %>' ></asp:TextBox> But I don't know how to do both.

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  • Symfony Form render with Self Referenced Entity

    - by benarth
    I have an Entity containing Self-Referenced mapping. class Category { /** * @var integer * * @ORM\Column(name="id", type="integer") * @ORM\Id * @ORM\GeneratedValue(strategy="AUTO") */ private $id; /** * @var string * * @ORM\Column(name="name", type="string", length=100) */ private $name; /** * @ORM\OneToMany(targetEntity="Category", mappedBy="parent") */ private $children; /** * @ORM\ManyToOne(targetEntity="Category", inversedBy="children") * @ORM\JoinColumn(name="parent_id", referencedColumnName="id") */ private $parent; } In my CategoryType I have this : public function buildForm(FormBuilderInterface $builder, array $options) { $plan = $this->plan; $builder->add('name'); $builder->add('parent', 'entity', array( 'class' => 'xxxBundle:Category', 'property' => 'name', 'empty_value' => 'Choose a parent category', 'required' => false, 'query_builder' => function(EntityRepository $er) use ($plan) { return $er->createQueryBuilder('u') ->where('u.plan = :plan') ->setParameter('plan', $plan) ->orderBy('u.id', 'ASC'); }, )); } Actually, when I render the form field Category this is something like Cat1 Cat2 Cat3 Subcat1 Subcat2 Cat4 I would like to know if it's possible and how to display something more like, a kind of a simple tree representation : Cat1 Cat2 Cat3 -- Subcat1 -- Subcat2 Cat4 Regards.

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  • Model state inferno - how can Model.A be two different things at the same time?

    - by Martin
    I have this <%=Model.StartDate%> <%=Html.Hidden("StartDate", Model.StartDate)%> it outputs: 2010-05-11 11:00:00 +01:00 <input type="hidden" value="2010-03-17 11:00:00 +01:00" name="StartDate" id="StartDate"> What the... It's a paging mechanism so the hidden value was valid on the first page and I've been able to move forward to the next page. But since the values won't update properly it ends there. What do I need to do? Using firefox.

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  • How to get a Javascript routine to NOT act if it's in a text box?

    - by talkingnews
    I've got a simple page, and in that page runs a simple jquery keypress routine to catch clicks of the numbers 1 to 9 (has to be that to pass RNIB accessibility test). And in that page is a form, which can have numbers entered as part of a postcode. http://find.talking-newspapers.co.uk/result.php?addressInput=kingston Scroll to the bottom, try typing 8 or 9 for example. The text is entered, but it also acts on the keypress. Expected, but not good. I'm aware of various things like document.getElementById, but I can't figure out how to put these together to ensure that while the cursor is in the text input box, it doesn't act out the keypress catcher.

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  • jQuery mobile ajax login form authentication

    - by Jakub Zak
    I know i already asked simillar question, but now when I work with jQuery Mobile I can't figure it out. So I have this form: <div data-role="page" data-theme="a" id="login_page"> <div data-role="header" data-position="fixed"> <h1>****</h1> </div> <div data-role="content"> <form id="login_form" method="POST" data-ajax="false"> <label for="basic">Username:</label> <input type="text" name="name" id="username" value=""/> <label for="basic">Password:</label> <input type="password" name="password" id="password" value=""/> <input type="submit" value="Login" id="login" name="login"/> </form> </div> <div data-role="footer" data-position="fixed"> <div data-role="navbar"></div> </div> </div> And I need to submit Username and Password to php script, where php replies and send "success" or "failed". Here is php: <?php session_start(); $username = $_POST["name"]; $password = $_POST["password"]; include('mysql_connection.php'); mysql_select_db("jzperson_imesUsers", $con); $res1 = mysql_query("SELECT * FROM temp_login WHERE username='$username' AND password='$password'"); $count=mysql_num_rows($res1); if($count==1){ echo "success"; }else{ echo "failed"; } ?> And to do all this I want to use this script: $(document).ready(function() { $("form").submit(function(){ $.mobile.showPageLoadingMsg(); $.ajax({ url: "http://imes.jzpersonal.com/login_control.php", type: "POST", dataType: "jsonp", jsonp: "jsoncallback", data: $("form#login_form").serialize(), success: function( response ){ $.mobile.changePage( "http://imes.jzpersonal.com/user_panel.html"); } }); return false; }); }); But I can't make it work, I know I must have mistakes in there, I just can't find them, or better way to do it. Thank you in advance for any help.

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  • Form character encoding problems with special characters

    - by Enrique
    Hello I have a jsp with an html form. I set the content type like this: <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1" %> When I send special characters like á é í ó ú they are saved correctly in the database. My table charset is utf-8. I want to change iso-8859 to utf-8 like this to standardize my application and accept more special characters: <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8" %> but when I change it to utf-8 the special characters á é í ó ú are not saved correctly in the databse. When I try to save á it is saved as á In the server side I'm using Spring MVC. I'm getting the text field value like this: String strField = ServletRequestUtils.getStringParameter(request, "field");

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  • Proper HTML technique to create an web form out of an image

    - by Lars
    I plan to create an interactive golf score card for my website (XHTML). (Btw. thats how such a scorecard looks like: ScoreCard). So at the end one should be able to insert a score for each hole in the appropriated input field in the virtual scorecard on the website. For me it is very important that the interactive scorecard really looks the same as the original (paper-) scorecard does and so my first approach was to scan and slice the scorecard image to reach that appearance. Here you can see the way I sliced the image: The idea was to insert HTML text input for each score field ending up with something like this: After I sliced the image I reconstructed it using the HTML . To do that I put the image slices as the cell background. <table> <tr> <td style="background: url("slice1.jpg") width="58px" height="25px"> <input type="text"></inputText> </td> </tr> ... </table> At the first moment this worked fine (as Gimp offers quite a nice feature for this). Then the problem was that I had to create a HTML table to create the exact layout. As you can see the lower part of the layout is split up into 3 columns. The middle column is split up into several (for each hole) rows. So the left and right column have to be spanned over those rows. Ok finally that worked, but it lead to some kind of scaling problem. If I zoom in or out on the table the middle column (and only that one) is not scaled the right way. Iam not able to fix this, and so I start doubting if this is the right technique for html image virtualization. Iam really no specialist in the area of creating websites, so I would really appriciate any help on this. Maybe there is a complete other and better technique to do that, as I think it is a common job in webcreation. I couldnt find any nice examples or tuts on that.

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  • JS Display Content based on Dropdown User input

    - by Thomas
    I am working on a search box that displays different options based on a users selection via dropdown box. Basically I need a really clean, light-weight method for switching out different divs without reloading the page. Im new to JS, but I know enough that there should be some really simple way of setting the display property using JS - Im just not totally sure how to go about it. Any help would be really appreciated, thanks.

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  • Option not clickable with mouse click after focus on select

    - by Manna
    I have configured a keyboard navigation for customized selects. Here the codepen to see in action : http://codepen.io/Mannaio/pen/ebyBi?editors=001 You can use the arrows up and down inside the selects and click the option with enter or tab button. I have a problem now and these are the steps reproduce the error 1) Do Focus on Input Name 2) Press Tab 3) If you hover and then do click with the mouse in any of the select options, they can not be selected with the mouse click This is the only error, it works perfectly if you move the arrows up and down and then you press the enter o tab, i want to to be able to select the option also with the mouse click after i do the focus with the tab button in the customized select Technically the problem is that the hover with the keyboards up and down is different when i hover with the mouse in the select-options. Line 185 function setSelected(menuitem) { $("ul.select-options.active li").removeClass("itemhover"); $("ul.select-options.active li").eq(menuitem).addClass("itemhover"); };

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