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  • jtextfield keyevent handling issue

    - by vamsi
    doesn't .getKeyCode( ) return the key's int value? Because i have set my jtextfield to listen to keylistener, and in the keytyped method, i check what key has been pressed. Here's a snippet of my code: JTextField jtf = new JTextField( ); jtf.addKeyListener( this ); . . . public void keyTyped( KeyEvent e ) { if( e.getKeyCode( ) == KeyEvent.VK_ENTER ) System.out.println( "pressed enter" ); } but everytime i type enter in the jtextfield, nothing happens, ie nothing prints.

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  • How to make Requests HttpOnly in strus1.1 [on hold]

    - by WSDL
    I am using struts1.2 with jboss4 sever.I have to make my requests HttpOnly.How do I make this with jobss4 and struts1.2.Please Help me .It is urgent private void validateToken(HttpServletRequest request, HttpServletResponse response) { HttpSession session = request.getSession(true); String token = (String)session.getAttribute(TOKEN_KEY); if (token == null) { token = getRandomString(); session.setAttribute(TOKEN_KEY, token); // System.out.println("Executing the Filter............XSS1"); response.addHeader("Set-Cookie", "httpOnly"); } } private String getRandomString() { return String.valueOf(System.currentTimeMillis()); }

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  • Eclipse autocompletion problem

    - by Gene Marin
    Just installed Eclipse Helios (Win7 64) and I'm having a strange problem. I type syso-Ctrl-Space which is expected to complete to System.out.println("") but it doesn't work! I searched the web for about an hour now, I set Preferences Java Editor Content Assist to defaults, nothing. Everything else seems to work. Ideas? To be clear: the shortcut works, it completes everything except "syso" as seen so far, on syso (also tried sysout) it says "No Default Proposals". I couldn't find this kind of shortcuts in the Content Assist, but I set them to default anyway.

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  • When is a scala partial function not a partial function?

    - by Fred Haslam
    While creating a map of String to partial functions I ran into unexpected behavior. When I create a partial function as a map element it works fine. When I allocate to a val it invokes instead. Trying to invoke the check generates an error. Is this expected? Am I doing something dumb? Comment out the check() to see the invocation. I am using scala 2.7.7 def PartialFunctionProblem() = { def dream()() = { println("~Dream~"); new Exception().printStackTrace() } val map = scala.collection.mutable.HashMap[String,()=>Unit]() map("dream") = dream() // partial function map("dream")() // invokes as expected val check = dream() // unexpected invocation check() // error: check of type Unit does not take parameters }

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  • input file cannot be found

    - by Eric Smith
    I am just messing around with reading input files with java until I got stumped at the most basic of steps... finding the input file! The input.txt file is in the same directory as my class file that is calling it yet eclipse still gives me an error that it cant be found: "Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException" My code: package pa; import java.util.Scanner; public class Project { public static void main(String[] args) { java.io.File file = new java.io.File("input.txt"); System.out.println(file.getAbsolutePath()); Scanner input = new Scanner(file); } } input.txt is in the same package, same folder and everything. I'm confused :(

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  • GCJ Creates duplicate dummy symbol

    - by vickirk
    Hi, I'm trying to build a java application with gcj but getting the error below. multiple definition of `java resource .dummy' gcj versions are 4.4.1 on Ubuntu and 4.3.4 on cygwin/windows XP and I'm building it with gcj --main=my.MainClass --classpath=my my/*java Anyone seen this or know a workaround without installing an earlier version of gcj. If that is the way to do it does anyone know how to do that on cygwin or will I have to build it? Here is a minimal test case that gives this error public class A { public static void main(String[] args) { System.out.println(new B()); } } public class B { public String toString() { return "Hello"; } } gcj --main=A src/A.java src/B.java

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  • Com port don't work in java

    - by ?????? ?????
    Does't work with java... don't sent message to my microchip. please help public static void main(String[] args) { SerialPort serialPort = new SerialPort("COM1"); try { serialPort.openPort(); serialPort.setParams(9600, 8, 1, 0); serialPort.setParams(SerialPort.BAUDRATE_9600, SerialPort.DATABITS_8, SerialPort.STOPBITS_1, SerialPort.PARITY_NONE); serialPort.writeBytes("Test"); readBytes(), ???? ?? ??????? ?????? byte[] buffer = serialPort.readBytes(10); //????????? ???? serialPort.closePort(); } catch (SerialPortException ex) { System.out.println(ex); } } } byte[] Write "[@B********" Star is a random number.

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  • JTable Boolean cell .. how to read it

    - by dimitar
    Hello guys, i have a table with a column that contains Boolean type. now when i try to run a program i have a problem: System.out.println(table.getColumnClass(5)); b= (Boolean)table.getValueAt(row, 5); It prints class java.lang.Boolean but also: Exception in thread "AWT-EventQueue-0" java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Boolean and i even try with b= (Boolean)table.getValueAt(row, 5); b= Boolean.parseBoolean((String)table.getValueAt(row, 5)); b= table.getValueAt(row, 5); but those show error too. So how to fix this guys?

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  • The system cannot find the path specified with FileWriter

    - by Nazgulled
    Hi, I have this code: private static void saveMetricsToCSV(String fileName, double[] metrics) { try { FileWriter fWriter = new FileWriter( System.getProperty("user.dir") + "\\output\\" + fileTimestamp + "_" + fileDBSize + "-" + fileName + ".csv" ); BufferedWriter csvFile = new BufferedWriter(fWriter); for(int i = 0; i < 4; i++) { for(int j = 0; j < 5; j++) { csvFile.write(String.format("%,10f;", metrics[i+j])); } csvFile.write(System.getProperty("line.separator")); } csvFile.close(); } catch(IOException e) { System.out.println(e.getMessage()); } } But I get this error: C:\Users\Nazgulled\Documents\Workspace\Só Amigos\output\1274715228419_5000-List-ImportDatabase.csv (The system cannot find the path specified) Any idea why? I'm using NetBeans on Windows 7 if it matters...

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  • ajax parameter to send correctly a variable to a specified url

    - by kawtousse
    I am trying to send data to a servlet from a js file but the servlet never received the parameter. so this is what I have: function showProject(prj) { xmlhttp=GetXmlHttpObject(); if (xmlhttp==null) { alert ("Browser does not support HTTP Request"); return; } var url="ServletxmlGenerator"; idprj = prj.options[prj.selectedIndex].value; //alert(idprj); url=url+"?idprj="+idprj; xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } and to capture th request it is with: public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String projectcode=request.getParameter("idprj"); System.out.println("++++projectCode:=" +projectcode); the output is like: ++++projectCode:=null Can any one explain it to me it seems to be correct but i didnot find the error.Thinks

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  • Tricky Big-O complexity

    - by timeNomad
    public void foo (int n, int m) { int i = m; while (i > 100) i = i/3; for (int k=i ; k>=0; k--) { for (int j=1; j<n; j*=2) System.out.print(k + "\t" + j); System.out.println(); } } I figured the complexity would be O(logn). That is as a product of the inner loop, the outer loop -- will never be executed more than 100 times, so it can be omitted. What I'm not sure about is the while clause, should it be incorporated into the Big-O complexity? For very large i values it could make an impact, or arithmetic operations, doesn't matter on what scale, count as basic operations and can be omitted?

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  • Is there a simpler way to convert a byte array to a 2-byte-size hexadecimal string?

    - by Tom Brito
    Is there a simpler way of implement this? Or a implemented method in JDK or other lib? /** * Convert a byte array to 2-byte-size hexadecimal String. */ public static String to2DigitsHex(byte[] bytes) { String hexData = ""; for (int i = 0; i < bytes.length; i++) { int intV = bytes[i] & 0xFF; // positive int String hexV = Integer.toHexString(intV); if (hexV.length() < 2) { hexV = "0" + hexV; } hexData += hexV; } return hexData; } public static void main(String[] args) { System.out.println(to2DigitsHex(new byte[] {8, 10, 12})); } the output is: "08 0A 0C" (without the spaces)

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  • Stuck with the first record while parsing an XML in Java

    - by Ritwik G
    I am parsing the following XML : <table ID="customer"> <T><C_CUSTKEY>1</C_CUSTKEY><C_NAME>Customer#000000001</C_NAME><C_ADDRESS>IVhzIApeRb ot,c,E</C_ADDRESS><C_NATIONKEY>15</C_NATIONKEY><C_PHONE>25-989-741-2988</C_PHONE><C_ACCTBAL>711.56</C_ACCTBAL><C_MKTSEGMENT>BUILDING</C_MKTSEGMENT><C_COMMENT>regular, regular platelets are fluffily according to the even attainments. blithely iron</C_COMMENT></T> <T><C_CUSTKEY>2</C_CUSTKEY><C_NAME>Customer#000000002</C_NAME><C_ADDRESS>XSTf4,NCwDVaWNe6tEgvwfmRchLXak</C_ADDRESS><C_NATIONKEY>13</C_NATIONKEY><C_PHONE>23-768-687-3665</C_PHONE><C_ACCTBAL>121.65</C_ACCTBAL><C_MKTSEGMENT>AUTOMOBILE</C_MKTSEGMENT><C_COMMENT>furiously special deposits solve slyly. furiously even foxes wake alongside of the furiously ironic ideas. pending</C_COMMENT></T> <T><C_CUSTKEY>3</C_CUSTKEY><C_NAME>Customer#000000003</C_NAME><C_ADDRESS>MG9kdTD2WBHm</C_ADDRESS><C_NATIONKEY>1</C_NATIONKEY><C_PHONE>11-719-748-3364</C_PHONE><C_ACCTBAL>7498.12</C_ACCTBAL><C_MKTSEGMENT>AUTOMOBILE</C_MKTSEGMENT><C_COMMENT>special packages wake. slyly reg</C_COMMENT></T> <T><C_CUSTKEY>4</C_CUSTKEY><C_NAME>Customer#000000004</C_NAME><C_ADDRESS>XxVSJsLAGtn</C_ADDRESS><C_NATIONKEY>4</C_NATIONKEY><C_PHONE>14-128-190-5944</C_PHONE><C_ACCTBAL>2866.83</C_ACCTBAL><C_MKTSEGMENT>MACHINERY</C_MKTSEGMENT><C_COMMENT>slyly final accounts sublate carefully. slyly ironic asymptotes nod across the quickly regular pack</C_COMMENT></T> <T><C_CUSTKEY>5</C_CUSTKEY><C_NAME>Customer#000000005</C_NAME><C_ADDRESS>KvpyuHCplrB84WgAiGV6sYpZq7Tj</C_ADDRESS><C_NATIONKEY>3</C_NATIONKEY><C_PHONE>13-750-942-6364</C_PHONE><C_ACCTBAL>794.47</C_ACCTBAL><C_MKTSEGMENT>HOUSEHOLD</C_MKTSEGMENT><C_COMMENT>blithely final instructions haggle; stealthy sauternes nod; carefully regu</C_COMMENT></T> </table> with the following java code: package xmlparserformining; import java.util.List; import java.util.Iterator; import org.dom4j.Document; import org.dom4j.DocumentException; import org.dom4j.Node; import org.dom4j.io.SAXReader; public class XmlParserForMining { public static Document getDocument( final String xmlFileName ) { Document document = null; SAXReader reader = new SAXReader(); try { document = reader.read( xmlFileName ); } catch (DocumentException e) { e.printStackTrace(); } return document; } public static void main(String[] args) { String xmlFileName = "/home/r/javaCodez/parsing in java/customer.xml"; String xPath = "//table/T/C_ADDRESS"; Document document = getDocument( xmlFileName ); List<Node> nodes = document.selectNodes( xPath ); System.out.println(nodes.size()); for (Node node : nodes) { String customer_address = node.valueOf(xPath); System.out.println( "Customer address: " + customer_address); } } } However, instead of getting all the various customer records, I am getting the following output: 1500 Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E Customer address: IVhzIApeRb ot,c,E and so on .. What is wrong here? Why is it printing only the first record ?

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  • PIG doesn't read my custom InputFormat

    - by Simon Guo
    I have a custom MyInputFormat that suppose to deal with record boundary problem for multi-lined inputs. But when I put the MyInputFormat into my UDF load function. As follow: public class EccUDFLogLoader extends LoadFunc { @Override public InputFormat getInputFormat() { System.out.println("I am in getInputFormat function"); return new MyInputFormat(); } } public class MyInputFormat extends TextInputFormat { public RecordReader createRecordReader(InputSplit inputSplit, JobConf jobConf) throws IOException { System.out.prinln("I am in createRecordReader"); //MyRecordReader suppose to handle record boundary return new MyRecordReader((FileSplit)inputSplit, jobConf); } } For each mapper, it print out I am in getInputFormat function but not I am in createRecordReader. I am wondering if anyone can provide a hint on how to hoop up my costome MyInputFormat to PIG's UDF loader? Much Thanks. I am using PIG on Amazon EMR.

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  • delete item from array

    - by davit-datuashvili
    hello can anybody tell me what is wrong here? i want delete item from array but it shows me error ArrayIndexOutBound exception public class delete{ public static void main(String[]args){ int i; //delete item from array int k[]=new int[]{77,99,44,11,00,55,66,33,10}; //delete 55 int searchkey=55; int nums=k.length; for ( i=0;i<nums;i++) if (k[i]==searchkey) break; for (int t=i;t<nums;t++) k[t]=k[t+1]; nums--; for (int m=0;m<nums;m++){ System.out.println(k[m]); } } }

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  • sending binary data via POST on android

    - by wo_shi_ni_ba_ba
    Android supports a limited version of apache's http client(v4). typically if I want to send binary data using content type= application/octet-stream via POST, I do the following: HttpClient client = getHttpClient(); HttpPost method=new HttpPost("http://192.168.0.1:8080/xxx"); System.err.println("send to server "+s); if(compression){ byte[]compressed =compress(s); RequestEntity entity = new ByteArrayRequestEntity(compressed); method.setEntity(entity); } HttpResponse resp=client.execute(method); however ByteArrayRequestEntity is not supported on android. what can I do?

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  • lexical analysis gives only one output?

    - by Caffè
    I tested this example(lexe.java), but it gave me only one output. I gave this text as a reader: public class LexeTest{ private int a = 14; } And the nextToken() function is : public Category nextToken () { if (inp.findWithinHorizon (tokenPat, 0) == null) return Category.EOF; else { lastLexeme = inp.match ().group (0); if (inp.match ().start (1) != -1) return nextToken (); else if (inp.match ().start (2) != -1) return Category.IDENT; else if (inp.match ().start (3) != -1) return Category.NUMERAL; Category result = tokenMap.get (lastLexeme); if (result == null) return Category.ERROR; else return result; } } Isdie the main method: System.out.println(lexeObject.nextToken()); output is : IDENT Why? but the textfile contains multiple keywords? Anyone know what's the problem?

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  • Arrays- Square root of an Array and printing the result JAVA

    - by roger34
    Hello, The title says it all, really. I'm trying to get an array of (9) numbers squared then printed but I keep coming back with only one result - the number of numbers in the array squared- obviously not what I want. Thanks for any help. Ok, here is my terrible code so far. Trying to pass it to a method as well. public static void main ( String args[] ) { double[] nums = {126, 12.939, 795, 320.16, 110, 34.7676, 7773, 67, 567, 323}; System.out.println ("Square root is " +square); square(nums); } public static double square (double [] array) { double result; for( double i = 0; i < array.length ; i++ ) result = Math.sqrt(array[i]); return result; } }

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  • java - POST vs JDBC

    - by Dan
    OK so here's the code: import java.io.BufferedReader; import java.io.InputStreamReader; import java.net.URL; public class Main { public static void main(String[] args) { try { URL my_url = new URL("http://www.viralpatel.net/blogs/"); BufferedReader br = new BufferedReader(new InputStreamReader(my_url.openStream())); String strTemp = ""; while(null != (strTemp = br.readLine())){ System.out.println(strTemp); } } catch (Exception ex) { ex.printStackTrace(); } } } Using this method I can use POST and GET methods using PHP scripts. I can then use the PHP scripts to the MySQL database which in turn outputs back to the java applet. Is this possible? (and safer?) Thanks.

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  • Smack API - How to display loop jxTaskpane for expand and collapse roster list

    - by MYE
    Hello everybody ! i have problem to display Taskpane for loop. i have a code to get the groups of roster (Groups : Friends - Business - Company, so on) my code is : Roster rost = xmppcon.getRoster(); Collection<RosterGroup> groups = rost.getGroups(); for(RosterGroup group : groups){ DefaultListModel model = new DefaultListModel(); model.addElement(group.getEntries()); String GroupNameCount = group.getName() + "("+group.getEntryCount()+")"; jXTaskPane1.setTitle(GroupNameCount); jXList1.setModel(model); } but jxTaskpane not loop, but when i print group name it print 2 line (because in database user A have two group is Friends and NIIT) sample print System.out.println(group.getName()); result: Friends NIIT

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  • Object can not be resolved.

    - by Gabriel A. Zorrilla
    I have this code: public class Window extends JFrame { public Window(){ ... JButton button = new JButton("OK"); getContentPane().add(button); ButtonHandler handler = new ButtonHandler(); button.addActionListener(handler); ... } private class ButtonHandler implements ActionListener { public void actionPerformed(ActionEvent event){ if (event.getSource() == button){ // <--- "button can not be resolved" System.out.println("Hello"); } } } I'm getting that error in Eclipse. I just made a (simplified) example found in a book, dont know what can be wrong. Knowledge eye required! :)

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  • How to sort Map in Java

    - by kalpesh
    hi i want to sort map according to its key value plz see code below public static void main(String[] args) { SortedMap map = new TreeMap(); // Add some elements: map.put("2", "Two"); map.put("1", "One"); map.put("5", "Five"); map.put("4", "Four"); map.put("3", "Three"); map.put("10", "Ten"); map.put("12", "Twelve"); map.put("7", "Seven"); map.put("9", "Nine"); Iterator iterator = map.keySet().iterator(); while (iterator.hasNext()) { Object key = iterator.next(); System.out.println("key : " + key + " value :" + map.get(key)); } } Result Should come below key : 1 value :One key : 2 value :Two key : 3 value :Three key : 4 value :Four key : 5 value :Five key : 7 value :Seven key : 9 value :Nine key : 10 value :Ten key : 12 value :Twelve

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  • Casting a primitive int to a Number

    - by Tamer
    Let's say that I have the following: int a = 2; Number b = (Number) a; System.out.println(b); // Prints 2 http://java.sun.com/docs/books/jls/first_edition/html/15.doc.html#238146 says that a primitive value may not be cast to a reference type. Does Java know to create an Integer from the primitive int and then cast to the superclass? How exactly does Java handle this behind the scenes? Thanks!

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  • Why doesn't this loop terminate?

    - by David
    Here's the sample code: public static void col (int n) { if (n % 2 == 0) n = n/2 ; if (n % 2 != 0) n = ((n*3)+1) ; System.out.println (n) ; if (n != 1) col (n) ; } this works just fine until it gets down to 2. then it outputs 2 4 2 4 2 4 2 4 2 4 infinitely. it seems to me that if 2 is entered as n then (n % 2 == 0) is true 2 will be divided by 2 to yeild 1. then 1 will be printed and since (n != 1) is false the loop will terminate. Why doesn't this happen?

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  • Java: opening and reading from a file without locking it.

    - by rogue780
    I need to be able to mimic 'tail -f' with Java. I'm trying to read a log file as it's being written by another process, but when I open the file to read it, it locks the file and the other process can't write to it anymore. Any help would be greatly appreciated! Here is the code that I'm using currently: public void read(){ Scanner fp = null; try{ fp = new Scanner(new FileReader(this.filename)); fp.useDelimiter("\n"); }catch(java.io.FileNotFoundException e){ System.out.println("java.io.FileNotFoundException e"); } while(true){ if(fp.hasNext()){ this.parse(fp.next()); } } }

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