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  • Hibernate -using Table per subclass - how to link an existing superclass object to a sibclass object

    - by Chandni
    Hi, I have a User hibernate class, Clerk class and Consumer class. All these maps to their own tables in database. The User PK also acts as Clerk's and Consumer's PK. So now my problem is that if a user is initially a Clerk, he has a record in Users table and Clerks table. If that user wants to become a consumer, I want to link that User's record to the new Consumer's record. So even if I pass the userId to the consumer's record, it treats it as a new User to be persisted and gives a duplicate_key exception. How do I tell Hiernate to link the same user object with this new Consumer object. Thanks in advance, -Chandni

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  • Swing verify code on event dispatch thread at runtime

    - by Jeff Storey
    Are there any libraries that instrument code to verify that methods called on swing components are called on the event dispatch thread? It probably wouldn't be too difficult to write some basic code for doing this, but I'm sure there are edge cases and whatnot that other people have handled. I'm looking for this at runtime though, not for unit tests. thanks, Jeff

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  • Best practice for storage and retrieval of error messages.

    - by ferrari fan
    What is a best practice for storing user messages in a configuration file and then retrieving them for certain events throughout an application? I was thinking of having 1 single configuration file with entries such as REQUIRED_FIELD = {0} is a required field INVALID_FORMAT = The format for {0} is {1} etc. and then calling them from a class that would be something like this public class UIMessages { public static final String REQUIRED_FIELD = "REQUIRED_FIELD"; public static final String INVALID_FORMAT = "INVALID_FORMAT"; static { // load configuration file into a "Properties" object } public static String getMessage(String messageKey) { // return properties.getProperty(messageKey); } } Is this the right way to approach this problem or is there some de-facto standard already in place?

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  • Android map overly transparency has unwanted gradient

    - by DavidP2190
    I'm a making my first android app and for part of it I need some shaded areas over a mapview. I've got this working so far but the when I set the alpha of the fill colour, it goes strange. I'm not allowed to post images yet, but you can see what happens here: http://i.imgur.com/leXmc.png I'm not sure what causes it, but here is some code from where it gets drawn. public boolean draw(Canvas canvas, MapView mapView, boolean shadow, long when) { Paint paint = new Paint(); paint.setStrokeWidth(2); paint.setColor(android.graphics.Color.GREEN); paint.setStyle(Paint.Style.FILL_AND_STROKE); paint.setAlpha(25); screenPoints = new Point[10]; Path path = new Path(); for (int x = 0; x<greenZone.length; x++){ screenPoints[x] = new Point(); mapView.getProjection().toPixels(greenZone[x], screenPoints[x]); } path.moveTo(screenPoints[0].x, screenPoints[0].y); for (int x = 1; x < screenPoints.length-1; x++){ paint.setAlpha(25); if (x<9){ path.lineTo(screenPoints[x].x, screenPoints[x].y); canvas.drawPath(path, paint); } else{ path.moveTo(screenPoints[screenPoints.length-1].x, screenPoints[screenPoints.length-1].y); path.lineTo(screenPoints[0].x, screenPoints[0].y); canvas.drawPath(path, paint); } } return true; } Thanks.

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  • Using a JMS Session from different threads

    - by Evan
    From the javadoc for Session it states: A Session object is a single-threaded context for producing and consuming messages. So I understand that you shouldn't use a Session object from two different threads at the same time. What I'm unclear on is if you could use the Session object (or children such as a Queue) from a different thread than the one it created. In the case I'm working on, I'm considering putting my Session objects into a pool of available sessions that any thread could borrow from, use, and return to the pool when it is finished with it. Is this kosher? (Using ActiveMQ BTW, if that impacts the answer at all.)

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  • Making change recursively: How do I modify my algorithm to print all combinations?

    - by cb
    I have an algorithm that recursively makes change in the following manner: public static int makeChange(int amount, int currentCoin) { //if amount = zero, we are at the bottom of a successful recursion if (amount == 0){ //return 1 to add this successful solution return 1; //check to see if we went too far }else if(amount < 0){ //don't count this try if we went too far return 0; //if we have exhausted our list of coin values }else if(currentCoin < 0){ return 0; }else{ int firstWay = makeChange(amount, currentCoin-1); int secondWay = makeChange(amount - availableCoins[currentCoin], currentCoin); return firstWay + secondWay; } } However, I'd like to add the capability to store or print each combination as they successfully return. I'm having a bit of a hard time wrapping my head around how to do this. The original algorithm was pretty easy, but now I am frustrated. Any suggestions? CB

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  • Stopping and Play button for Audio (Android)

    - by James Rattray
    I have this problem, I have some audio I wish to play... And I have two buttons for it, 'Play' and 'Stop'... Problem is, after I press the stop button, and then press the Play button, nothing happens. -The stop button stops the song, but I want the Play button to play the song again (from the start) Here is my code: final MediaPlayer mp = MediaPlayer.create(this, R.raw.megadeth); And then the two public onclicks: (For playing...) button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click button.setText("Playing!"); try { mp.prepare(); } catch (IllegalStateException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } mp.start(); // } }); And for stopping the track... final Button button2 = (Button) findViewById(R.id.cancel); button2.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { mp.stop(); mp.reset(); } }); Can anyone see the problem with this? If so could you please fix it... (For suggest) Thanks alot... James

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  • How can i use Stopwatch [ apache ] to calculate the time taken by a method?

    - by Rakesh Juyal
    I am using StopWatch [ apache ] to get the time taken by my method. The approach i am following is StopWatch stopWatch = new StopWatch(); stopWatch.start(); myMethod(); stopWatch.stop(); logger.info( "Time taken by myMethod: " + stopWatch.getTime() + " millisecs"); stopWatch.reset(); stopWatch.start(); anotherMethod(); stopWatch.stop(); logger.info( "Time taken by anotherMethod: " + stopWatch.getTime() + " millisecs"); Thats the only thing i know about StopWatch :). How/when to use split(), unsplit(), getSplitTime(),suspend()... ?

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  • Persistence unit is not persistent

    - by etam
    I need persistence unit that creates embedded database which stays persistent after closing EntityManager. This is my PU: <persistence-unit name="hello-jpa" transaction-type="RESOURCE_LOCAL"> <class>hello.jpa.User</class> <properties> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.format_sql" value="true"/> <property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect"/> <property name="hibernate.connection.driver_class" value="org.hsqldb.jdbcDriver"/> <property name="hibernate.connection.username" value="sa"/> <property name="hibernate.connection.password" value=""/> <property name="hibernate.connection.url" value="jdbc:hsqldb:target/hsql.db"/> <property name="hibernate.hbm2ddl.auto" value="update"/> </properties> </persistence-unit> And it deletes data after closing application.

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  • How do I show TextView's in LinearLayout that layed on other Layout?

    - by gelassen
    Good day. I have three layouts: first is the root, second and third lie in first. I try add TextView object in third layout and objects had been added in third layout (I saw it in debage mode) but this objects didn't showed on screen. May be someone know where is the problem? <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical"> <LinearLayout android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="horizontal"> <Button android:id="@+id/addJokeButton" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/app_name" /> <EditText android:id="@+id/newJokeEditText" android:layout_width="fill_parent" android:layout_height="wrap_content" /> </LinearLayout> <LinearLayout android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical"> </LinearLayout> </LinearLayout> protected void initLayout() { setContentView(R.layout.advanced); LinearLayout linearLayout = (LinearLayout) getLayoutInflater().inflate( R.layout.advanced, null); m_vwJokeEditText = (EditText) findViewById(R.id.newJokeEditText); m_vwJokeButton = (Button) findViewById(R.id.addJokeButton); m_vwJokeLayout = (LinearLayout) linearLayout.getChildAt(1); } protected void addJoke(Joke joke) { m_arrJokeList.add(joke); LayoutParams lparams = new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT); TextView textView = new TextView(this); setColor(textView); textView.setLayoutParams(lparams); textView.setText(joke.getJoke()); m_vwJokeLayout.addView(textView); }

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  • Best practices retrieving XML/stream from HTTP in Android

    - by Jeffrey
    Hello everyone, what are the best practices parsing XML from an HTTP resource in Android? I've been using HttpURLConnection to retrieve an InputStream, wrapping it with a BufferedInputStream, and then using SAX to parse the buffered stream. For the most part it works, though I do receive error reports of SocketTimeoutException: The operation timed out or general parsing error. I believe it's due to the InputStream. Would using HttpClient instead of HttpURLConnection help? If yes, why? Should the stream be output to a file, having the file parsed instead of the stream? Any input or direction would be greatly appreciated. Thanks for your time.

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  • error in midlet while implementing command..

    - by garima
    hi I have imported import com.sun.lwuit.Command; import javax.microedition.midlet.; import javax.microedition.lcdui.; in my code but still the following errors are coming... exitCommand = new Command("Exit", Command.EXIT, 2); //line 1 textbox.addCommand(exitCommand); //line 2 Command.EXIT cannot be resolved.. The method addCommand(Command) in the type Displayable is not applicable for the arguments (Command)

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  • JSF hiding exceptions?

    - by bshacklett
    I have a managed bean for a JSF page which is doing JPA calls in the constructor to populate fields in the bean. I'm having a bit of trouble with another call to persist an entity (to populate data for testing). I'm expecting it to throw some sort of exception since it's not working, but I'm not getting anything. Just of the heck of it I tried the following: Query newQuery = em.createQuery("Bad Syntax"); List newList = newQuery.getResultList(); I'd expect an IllegalArgumentException here since the query string is completely invalid, but the page still loads and I don't see any exceptions anywhere. Am I right in expecting this exception? If so, why am I not seeing it?

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  • Solr; "rookie" question

    - by Camran
    I have a SolrPhpClient on my classifieds website, and whenever users wants to add/remove classified the index in Solr gets updated via Php code. So I wonder, does this mean that my Solr index is open for anybody to alter with? Same Q applies to the Solr Admin page. If I set a password for the admin page, does this mean that my classifieds website wont have access to updating/removing documents from the Solr index? Thanks

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  • Is there a simpler way to convert a byte array to a 2-byte-size hexadecimal string?

    - by Tom Brito
    Is there a simpler way of implement this? Or a implemented method in JDK or other lib? /** * Convert a byte array to 2-byte-size hexadecimal String. */ public static String to2DigitsHex(byte[] bytes) { String hexData = ""; for (int i = 0; i < bytes.length; i++) { int intV = bytes[i] & 0xFF; // positive int String hexV = Integer.toHexString(intV); if (hexV.length() < 2) { hexV = "0" + hexV; } hexData += hexV; } return hexData; } public static void main(String[] args) { System.out.println(to2DigitsHex(new byte[] {8, 10, 12})); } the output is: "08 0A 0C" (without the spaces)

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  • Using a Session Scoped Bean

    - by jboyd
    The following code is returning null: private MyAppUser getMyAppUser(HttpSession session) { MyAppUser myAppUser = (MyAppUser) session.getAttribute("myAppUserManager"); return myAppUser; } Despite the fact that I have the following in my context: <bean id="myAppUserManager" class="com.myapp.profile.MyAppUser" scope="session"/> This doesn't make any sense to me, the "myAppUser" bean is a bean that absolutely can never be null, and I need to be able to reference it from controllers, I don't need it in services or repositories, just controllers, but it doesn't seem to be getting stored in the session, the use case is extremely simple, but I haven't been able to get to the bottom of what's wrong, or come up with a good workaround

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  • Different behaviour using unidirectional or bidirectional relation

    - by sinuhepop
    I want to persist a mail entity which has some resources (inline or attachment). First I related them as a bidirectional relation: @Entity public class Mail extends BaseEntity { @OneToMany(mappedBy = "mail", cascade = CascadeType.ALL, orphanRemoval = true) private List<MailResource> resource; private String receiver; private String subject; private String body; @Temporal(TemporalType.TIMESTAMP) private Date queued; @Temporal(TemporalType.TIMESTAMP) private Date sent; public Mail(String receiver, String subject, String body) { this.receiver = receiver; this.subject = subject; this.body = body; this.queued = new Date(); this.resource = new ArrayList<>(); } public void addResource(String name, MailResourceType type, byte[] content) { resource.add(new MailResource(this, name, type, content)); } } @Entity public class MailResource extends BaseEntity { @ManyToOne(optional = false) private Mail mail; private String name; private MailResourceType type; private byte[] content; } And when I saved them: Mail mail = new Mail("[email protected]", "Hi!", "..."); mail.addResource("image", MailResourceType.INLINE, someBytes); mail.addResource("documentation.pdf", MailResourceType.ATTACHMENT, someOtherBytes); mailRepository.save(mail); Three inserts were executed: INSERT INTO MAIL (ID, BODY, QUEUED, RECEIVER, SENT, SUBJECT) VALUES (?, ?, ?, ?, ?, ?) INSERT INTO MAILRESOURCE (ID, CONTENT, NAME, TYPE, MAIL_ID) VALUES (?, ?, ?, ?, ?) INSERT INTO MAILRESOURCE (ID, CONTENT, NAME, TYPE, MAIL_ID) VALUES (?, ?, ?, ?, ?) Then I thought it would be better using only a OneToMany relation. No need to save which Mail is in every MailResource: @Entity public class Mail extends BaseEntity { @OneToMany(cascade = CascadeType.ALL, orphanRemoval = true) @JoinColumn(name = "mail_id") private List<MailResource> resource; ... public void addResource(String name, MailResourceType type, byte[] content) { resource.add(new MailResource(name, type, content)); } } @Entity public class MailResource extends BaseEntity { private String name; private MailResourceType type; private byte[] content; } Generated tables are exactly the same (MailResource has a FK to Mail). The problem is the executed SQL: INSERT INTO MAIL (ID, BODY, QUEUED, RECEIVER, SENT, SUBJECT) VALUES (?, ?, ?, ?, ?, ?) INSERT INTO MAILRESOURCE (ID, CONTENT, NAME, TYPE) VALUES (?, ?, ?, ?) INSERT INTO MAILRESOURCE (ID, CONTENT, NAME, TYPE) VALUES (?, ?, ?, ?) UPDATE MAILRESOURCE SET mail_id = ? WHERE (ID = ?) UPDATE MAILRESOURCE SET mail_id = ? WHERE (ID = ?) Why this two updates? I'm using EclipseLink, will this behaviour be the same using another JPA provider as Hibernate? Which solution is better?

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  • HTTP status 405 - HTTP method POST is not supported by this URL

    - by Wont Say
    I am getting this "HTTP method POST is not supported by this URL" error when I run my project. The funny thing is, it was running perfectly fine two days ago. After I made a few changes to my code but then restored my original code and its giving me this error. Could you please help me? Here is my index.html: <form method="post" action="login.do"> <div> <table> <tr><td>Username: </td><td><input type="text" name="e_name"/> </td> </tr> <tr><td> Password: </td><td><input type="password" name="e_pass"/> </td> </tr> <tr><td></td><td><input type="submit" name ="e_submit" value="Submit"/> Here is my Login servlet: public class Login extends HttpServlet { /** * Processes requests for both HTTP * <code>GET</code> and * <code>POST</code> methods. * * @param request servlet request * @param response servlet response * @throws ServletException if a servlet-specific error occurs * @throws IOException if an I/O error occurs */ protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, SQLException { response.setContentType("text/html;charset=UTF-8"); PrintWriter out = response.getWriter(); try { /* * TODO output your page here. You may use following sample code. */ int status; String submit = request.getParameter("e_submit"); String submit2 = request.getParameter("a_submit"); out.println("Here1"); String e_name = request.getParameter("e_name"); String e_password = request.getParameter("e_pass"); String a_name = request.getParameter("a_name"); String a_password = request.getParameter("a_pass"); out.println(e_name+e_password+a_name+a_password); Author author = new Author(a_name,a_password); Editor editor = new Editor(e_name,e_password); // If it is an AUTHOR login: if(submit==null){ status = author.login(author); out.println("Author Login"); //Incorrect login details if(status==0) { out.println("Incorrect"); RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- AUTHOR else { out.println("Correct login details"); HttpSession session = request.getSession(); session.setAttribute(a_name, "a_name"); RequestDispatcher view = request.getRequestDispatcher("index_S.jsp"); view.forward(request, response); } } //If it is an EDITOR login else if (submit2==null){ status = editor.login(editor); //Incorrect login details if(status==0) { RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- EDITOR else { out.println("correct"); HttpSession session = request.getSession(); session.setAttribute(e_name, "e_name"); session.setAttribute(e_password, "e_pass"); RequestDispatcher view = request.getRequestDispatcher("index_S_1.html"); view.forward(request, response); } } out.println("</body>"); out.println("</html>"); } finally { out.close(); } } @Override protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doPost(req, resp); } @Override protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doGet(req, resp); }} And my web.xml looks like this: <?xml version="1.0" encoding="UTF-8"?> <servlet> <servlet-name>action</servlet-name> <servlet-class>org.apache.struts.action.ActionServlet</servlet-class> <init-param> <param-name>config</param-name> <param-value>/WEB-INF/struts-config.xml</param-value> </init-param> <init-param> <param-name>debug</param-name> <param-value>2</param-value> </init-param> <init-param> <param-name>detail</param-name> <param-value>2</param-value> </init-param> <load-on-startup>2</load-on-startup> </servlet> <servlet> <servlet-name>Login</servlet-name> <servlet-class>controller.Login</servlet-class> </servlet> <servlet-mapping> <servlet-name>action</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Login</servlet-name> <url-pattern>/login.do</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.html</welcome-file> </welcome-file-list> I use Glassfish v3 server - let me know anything else you need to know

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  • Why is my file being cleared if I don't save it?

    - by Kat
    My program is suppose to maintain a collection of Photos in a PhotoAlbum. It begins by reading a folder of photos and adds them to my PhotoAlbum. It then prints a menu that allows the user to list all the photos, add a photo, find a photo, save, and quit the program. Right now if I run my program it will add the 100 photos to the PhotoAlbum, but if I quit the program without saving, it clears the file I am reading from even if I haven't added a photo or done anything to the PhotoAlbum and I'm not sure why. Here is my method for printing to a file: private static void saveFile(PrintWriter writer) { String result; ArrayList<Photo> temp = album.getPhotoAlbum(); for (int i = 0; i < temp.size(); i++){ result = temp.get(i).toString() + "\n"; writer.println(result); } writer.close(); } And where the PrintWriter is instantiated: File file = new File(args[0] + File.separator + "album.dat"); try { PrintWriter fout = new PrintWriter(new FileWriter(file)); fileWriter = fout; } catch (IOException e){ System.out.println("ReadFromFile: Folder " + args[0] + " is not found."); System.exit(0); } And where it is called in my runMenu Method: private static void runMainMenu(Scanner scan) { String input; do { showMainMenu(); input = scan.nextLine().toLowerCase(); switch (input.charAt(0)) { case 'p': System.out.println(album.toString()); break; case 'a': album.addPhoto(readPhoto(scan, t)); break; case 'f': findMenu(scan); break; case 's': saveFile(fileWriter); System.exit(0); break; case 'q': break; default: System.out.println("Invalid entry: " + input.charAt(0)); break; } } while (!input.equalsIgnoreCase("q")); }

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  • What does this do and why does it require a transaction?

    - by S. Palin
    What does the following code example do and why does it require a transaction? // PersistenceManager pm = ...; Transaction tx = pm.currentTransaction(); User user = userService.currentUser(); List<Account> accounts = new ArrayList<Account>(); try { tx.begin(); Query query = pm.newQuery("select from Customer " + "where user == userParam " + "parameters User userParam"); List<Customer> customers = (List<Customer>) query.execute(user); query = pm.newQuery("select from Account " + "where parent-pk == keyParam " + "parameters Key keyParam"); for (Customer customer : customers) { accounts.addAll((List<Account>) query.execute(customer.key)); } } finally { if (tx.isActive()) { tx.rollback(); } }

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  • Spring - Redirect after POST (even with validation errors)

    - by Taylor L
    I'm trying to figure out how to "preserve" the BindingResult so it can be used in a subsequent GET via the Spring <form:errors> tag. The reason I want to do this is because of Google App Engine's SSL limitations. I have a form which is displayed via HTTP and the post is to an HTTPS URL. If I only forward rather than redirect then the user would see the https://whatever.appspot.com/my/form URL. I'm trying to avoid this. Any ideas how to approach this? Below is what I'd like to do, but I only see validation errors when I use return "create". @RequestMapping(value = "/submit", method = RequestMethod.POST) public final String submit( @ModelAttribute("register") @Valid final Register register, final BindingResult binding) { if (binding.hasErrors()) { return "redirect:/register/create"; } return "redirect:/register/success"; }

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