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  • Ubuntu Desktop does not load

    - by Niklas
    If I login on my Ubuntu 14.04, I get the following desktop: This weird behavior appeared after I executed sudo apt-get update && sudo apt-get upgrade and restarted my computer. Don't know why though. To my Ubuntu I have tried the following (nothing seems to work so far) Fix any broken packages: sudo apt-get update sudo apt-get autoclean sudo apt-get clean sudo apt-get autoremove Locate any broken packages and reinstall them: sudo apt-get install debsums sudo apt-get clean sudo debsums_init sudo debsums -cs sudo apt-get install --reinstall $(sudo dpkg -S $(sudo debsums -c) | cut -d : -f 1 | sort -u) Removing some compiz files: rm -r ~/.cache/compizconfig-1 rm -r ~/.compiz Purging of NVIDIA and installing NVIDIA-prime: sudo apt-get install --reinstall ubuntu-desktop sudo apt-get install unity sudo apt-get purge nvidia* bumblebee* sudo apt-get install nvidia-prime sudo shutdown -r now Compizconfig Settings Manager: sudo apt-get install compizconfig-settings-manager export DISPLAY=:0 ccsm // Back to UI and enablement of Unity Plugin Unity replace, which stopped at a while and did nothing afterwards unity --replace Some dconf reset dconf reset -f /org/compiz/ unity --reset-icons &disown Actually dconf did not work and I got this error: error: Cannot autolaunch D-Bus without X11 $DISPLAY Can anybody help me on that? This is my hardware (hope it helps in any way): Intel® Core™ i7-3770 ASUS GTX660TI-DC2-OG-2GD5 (NVIDIA driver is/was installed) ASUS P8Z77-V LX Corsair DIMM 8 GB DDR3-1600 Kit Samsung 830series 2,5" 256 GB (Windows is installed here) Seagate ST31000524AS 1 TB (3/4 are reserved for files; 1/4 is for Ubuntu (16GB swap included))

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  • Law of Demeter confusion [duplicate]

    - by user2158382
    This question already has an answer here: Rails: Law of Demeter Confusion 4 answers I am reading a book called Rails AntiPatterns and they talk about using delegation to to avoid breaking the Law of Demeter. Here is their prime example: They believe that calling something like this in the controller is bad (and I agree) @street = @invoice.customer.address.street Their proposed solution is to do the following: class Customer has_one :address belongs_to :invoice def street address.street end end class Invoice has_one :customer def customer_street customer.street end end @street = @invoice.customer_street They are stating that since you only use one dot, you are not breaking the Law of Demeter here. I think this is incorrect, because you are still going through customer to go through address to get the invoice's street. I primarily got this idea from a blog post I read: http://www.dan-manges.com/blog/37 In the blog post the prime example is class Wallet attr_accessor :cash end class Customer has_one :wallet # attribute delegation def cash @wallet.cash end end class Paperboy def collect_money(customer, due_amount) if customer.cash < due_ammount raise InsufficientFundsError else customer.cash -= due_amount @collected_amount += due_amount end end end The blog post states that although there is only one dot customer.cash instead of customer.wallet.cash, this code still violates the Law of Demeter. Now in the Paperboy collect_money method, we don't have two dots, we just have one in "customer.cash". Has this delegation solved our problem? Not at all. If we look at the behavior, a paperboy is still reaching directly into a customer's wallet to get cash out. Can somebody help me clear the confusion. I have been searching for the past 2 days trying to let this topic sink in, but it is still confusing.

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  • Rails: The Law of Demeter [duplicate]

    - by user2158382
    This question already has an answer here: Rails: Law of Demeter Confusion 4 answers I am reading a book called Rails AntiPatterns and they talk about using delegation to to avoid breaking the Law of Demeter. Here is their prime example: They believe that calling something like this in the controller is bad (and I agree) @street = @invoice.customer.address.street Their proposed solution is to do the following: class Customer has_one :address belongs_to :invoice def street address.street end end class Invoice has_one :customer def customer_street customer.street end end @street = @invoice.customer_street They are stating that since you only use one dot, you are not breaking the Law of Demeter here. I think this is incorrect, because you are still going through customer to go through address to get the invoice's street. I primarily got this idea from a blog post I read: http://www.dan-manges.com/blog/37 In the blog post the prime example is class Wallet attr_accessor :cash end class Customer has_one :wallet # attribute delegation def cash @wallet.cash end end class Paperboy def collect_money(customer, due_amount) if customer.cash < due_ammount raise InsufficientFundsError else customer.cash -= due_amount @collected_amount += due_amount end end end The blog post states that although there is only one dot customer.cash instead of customer.wallet.cash, this code still violates the Law of Demeter. Now in the Paperboy collect_money method, we don't have two dots, we just have one in "customer.cash". Has this delegation solved our problem? Not at all. If we look at the behavior, a paperboy is still reaching directly into a customer's wallet to get cash out. EDIT I completely understand and agree that this is still a violation and I need to create a method in Wallet called withdraw that handles the payment for me and that I should call that method inside the Customer class. What I don't get is that according to this process, my first example still violates the Law of Demeter because Invoice is still reaching directly into Customer to get the street. Can somebody help me clear the confusion. I have been searching for the past 2 days trying to let this topic sink in, but it is still confusing.

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  • How can I be certain that my code is flawless? [duplicate]

    - by David
    This question already has an answer here: Theoretically bug-free programs 5 answers I have just completed an exercise from my textbook which wanted me to write a program to check if a number is prime or not. I have tested it and seems to work fine, but how can I be certain that it will work for every prime number? public boolean isPrime(int n) { int divisor = 2; int limit = n-1 ; if (n == 2) { return true; } else { int mod = 0; while (divisor <= limit) { mod = n % divisor; if (mod == 0) { return false; } divisor++; } if (mod > 0) { return true; } } return false; } Note that this question is not a duplicate of Theoretically Bug Free Programs because that question asks about whether one can write bug free programs in the face of the the limitative results such as Turing's proof of the incomputability of halting, Rice's theorem and Godel's incompleteness theorems. This question asks how a program can be shown to be bug free.

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  • Why is Java not telling me when I can't use Integer?

    - by Sebi
    For a small project (Problem 10 Project Euler) i tried to sum up all prime numbers below 2 millions. So I used a brute force method and iterated from 0 to 2'000'000 and checked if the number is a prime. If it is I added it to the sum: private int sum = 0; private void calculate() { for (int i = 0; i < 2000000; i++) { if (i.isPrime()) { sum = sum + i; } } sysout(sum) } The result of this calculation is 1179908154, but this is incorrect. So i changed int to BigInteger and now i get the correct sum 142913828922. Obviously the range of int was overflowed. But why can't Java tell my that? (e.g. by an exception)

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  • Java: omitting a data member from the equals method.

    - by cchampion
    public class GamePiece { public GamePiece(char cLetter, int nPointValue) { m_cLetter=cLetter; m_nPointValue=nPointValue; m_nTurnPlaced=0; //has not been placed on game board yet. } public char GetLetter() {return m_cLetter;} public int GetPointValue() {return m_nPointValue;} public int GetTurnPlaced() {return m_nTurnPlaced;} public void SetTurnPlaced(int nTurnPlaced) { m_nTurnPlaced=nTurnPlaced; } @Override public boolean equals(Object obj) { /*NOTE to keep this shorter I omitted some of the null checking and instanceof stuff. */ GamePiece other = (GamePiece) obj; //not case sensitive, and I don`t think we want it to be here. if(m_cLetter != other.m_cLetter) { return false; } if(m_nPointValue != other.m_nPointValue) { return false; } /* NOTICE! m_nPointValue purposely omitted. It does not affect hashcode or equals */ return true; } @Override public int hashCode() { /* NOTICE! m_nPointValue purposely omitted. It should not affect hashcode or equals */ final int prime = 41; return prime * (prime + m_nPointValue + m_cLetter); } private char m_cLetter; private int m_nPointValue; private int m_nTurnPlaced;//turn which the game piece was placed on the game board. Does not affect equals or has code! } Consider the given piece of code. This object has been immutable until the introduction of the m_nTurnPlaced member (which can be modified by the SetTurnPlaced method, so now GamePiece becomes mutable). GamePiece is used in an ArrayList, I call contains and remove methods which both rely on the equals method to be implemented. My question is this, is it ok or common practice in Java for some members to not affect equals and hashcode? How will this affect its use in my ArrayList? What type of java Collections would it NOT be safe to use this object now that it is mutable? I've been told that you're not supposed to override equals on mutable objects because it causes some collections to behave "strangely" (I read that somewhere in the java documentation).

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  • More ruby-like solution to this problem?

    - by RaouL
    I am learning ruby and practicing it by solving problems from Project Euler. This is my solution for problem 12. # Project Euler problem: 12 # What is the value of the first triangle number to have over five hundred divisors? require 'prime' triangle_number = ->(num){ (num *(num + 1)) / 2 } factor_count = ->(num) do prime_fac = Prime.prime_division(num) exponents = prime_fac.collect { |item| item.last + 1 } fac_count = exponents.inject(:*) end n = 2 loop do tn = triangle_number.(n) if factor_count.(tn) >= 500 puts tn break end n += 1 end Any improvements that can be made to this piece of code?

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  • c++ and c# speed compared

    - by Mack
    I was worried about C#'s speed when it deals with heavy calculations, when you need to use raw CPU power. I always thought that C++ is much faster than C# when it comes to calculations. So I did some quick tests. The first test computes prime numbers < an integer n, the second test computes some pandigital numbers. The idea for second test comes from here: Pandigital Numbers C# prime computation: using System; using System.Diagnostics; class Program { static int primes(int n) { uint i, j; int countprimes = 0; for (i = 1; i <= n; i++) { bool isprime = true; for (j = 2; j <= Math.Sqrt(i); j++) if ((i % j) == 0) { isprime = false; break; } if (isprime) countprimes++; } return countprimes; } static void Main(string[] args) { int n = int.Parse(Console.ReadLine()); Stopwatch sw = new Stopwatch(); sw.Start(); int res = primes(n); sw.Stop(); Console.WriteLine("I found {0} prime numbers between 0 and {1} in {2} msecs.", res, n, sw.ElapsedMilliseconds); Console.ReadKey(); } } C++ variant: #include <iostream> #include <ctime> int primes(unsigned long n) { unsigned long i, j; int countprimes = 0; for(i = 1; i <= n; i++) { int isprime = 1; for(j = 2; j < (i^(1/2)); j++) if(!(i%j)) { isprime = 0; break; } countprimes+= isprime; } return countprimes; } int main() { int n, res; cin>>n; unsigned int start = clock(); res = primes(n); int tprime = clock() - start; cout<<"\nI found "<<res<<" prime numbers between 1 and "<<n<<" in "<<tprime<<" msecs."; return 0; } When I ran the test trying to find primes < than 100,000, C# variant finished in 0.409 seconds and C++ variant in 5.553 seconds. When I ran them for 1,000,000 C# finished in 6.039 seconds and C++ in about 337 seconds. Pandigital test in C#: using System; using System.Diagnostics; class Program { static bool IsPandigital(int n) { int digits = 0; int count = 0; int tmp; for (; n > 0; n /= 10, ++count) { if ((tmp = digits) == (digits |= 1 << (n - ((n / 10) * 10) - 1))) return false; } return digits == (1 << count) - 1; } static void Main() { int pans = 0; Stopwatch sw = new Stopwatch(); sw.Start(); for (int i = 1; i <= 123456789; i++) { if (IsPandigital(i)) { pans++; } } sw.Stop(); Console.WriteLine("{0}pcs, {1}ms", pans, sw.ElapsedMilliseconds); Console.ReadKey(); } } Pandigital test in C++: #include <iostream> #include <ctime> using namespace std; int IsPandigital(int n) { int digits = 0; int count = 0; int tmp; for (; n > 0; n /= 10, ++count) { if ((tmp = digits) == (digits |= 1 << (n - ((n / 10) * 10) - 1))) return 0; } return digits == (1 << count) - 1; } int main() { int pans = 0; unsigned int start = clock(); for (int i = 1; i <= 123456789; i++) { if (IsPandigital(i)) { pans++; } } int ptime = clock() - start; cout<<"\nPans:"<<pans<<" time:"<<ptime; return 0; } C# variant runs in 29.906 seconds and C++ in about 36.298 seconds. I didn't touch any compiler switches and bot C# and C++ programs were compiled with debug options. Before I attempted to run the test I was worried that C# will lag well behind C++, but now it seems that there is a pretty big speed difference in C# favor. Can anybody explain this? C# is jitted and C++ is compiled native so it's normal that a C++ will be faster than a C# variant. Thanks for the answers!

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  • List of divisors of an integer n (Haskell)

    - by Code-Guru
    I currently have the following function to get the divisors of an integer: -- All divisors of a number divisors :: Integer -> [Integer] divisors 1 = [1] divisors n = firstHalf ++ secondHalf where firstHalf = filter (divides n) (candidates n) secondHalf = filter (\d -> n `div` d /= d) (map (n `div`) (reverse firstHalf)) candidates n = takeWhile (\d -> d * d <= n) [1..n] I ended up adding the filter to secondHalf because a divisor was repeating when n is a square of a prime number. This seems like a very inefficient way to solve this problem. So I have two questions: How do I measure if this really is a bottle neck in my algorithm? And if it is, how do I go about finding a better way to avoid repetitions when n is a square of a prime?

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  • How to find the largest square in the number (Java)

    - by Ypsilon IV
    Hello everyone, I want to find the largest square in the number, but I am stuck at some point. I would really appreciate some suggestions. This is what I've done so far: I take the number on the input, factorize into prime numbers, and put the sequence of prime numbers to ArrayList. Numbers are sorted, in a sense, thus the numbers in the sequence are increasing. For example, 996 is 2 2 3 83 1000 is 2 2 2 5 5 5 100000 is 2 2 2 2 2 5 5 5 5 5 My idea now is to count number of occurrences of each elements in the sequence, so if the number of occurrences is divisible by two, then this is the square. In this way, I can get another sequence, where the right most element divisible by two is the largest square. What is the most efficient way to count occurrences in the ArrayList? Or is there any better way to find the largest square? Many thanks in advance!

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  • Split text files Accross threads

    - by Kevin
    The problem: I have a few text files (10) with numbers in them on every line. I need to have them split across some threads I create using the pthread library. these threads that are created (worker threads) are to find the largest prime number that gets sent to them (and over all the largest prime from all of the text files). My current thoughts on solutions: I am thinking myself to have two arrays and all of the text files in one array and the other array will contain a binary file that I can read say 1000 lines and send the pointer to the index of that binary file in a struct that contains the id, file pointer, and file position and let it crank through that. a little bit of what I am talking about pthread_create(&threads[index],NULL,calc_sqrt,(void *)threadFields[index]);//Pass struct to each worker Struct: typedef struct threadFields{ int *id, *position; FILE *Fin; }tField; If anyone has any insight or a better solution it would be greatly appreciated Thanks

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  • Différence entre :before et ::before, les pseudos-element en CSS3 par Louis Lazaris, traduit par Jérôme Debray

    Lorsquevous faites une recherche sur les pseudo-éléments en CSS, vous pouvez constater différentes syntaxes pour :before et :after, précédés de deux-points doublés (::) ou non. Cela peut sembler un peu déroutant de prime abord mais il y a, en fait, une explication plutôt simple. J'avais supposé qu'il y avait une différence de fonctionnement entre les deux types de syntaxe, mais ce n'est pas le cas comme le montre, ci dessous, les explications courte et longue.

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  • Ubuntu 14.04 Nvidia Optimus Bumblebee error

    - by Cristian
    I know that in Ubuntu 14.04 there exists nvidia-prime for Nvidia Optimus, but I don't like it and neither am I able to get it work. After upgrading from Ubuntu 12.04 everything crashed, and I made a clean install of Ubuntu 14.04 and Bumblebee, but now I have new troubles. After running optirun glxgears I get the following error: **[ 4703.996785] [ERROR]Cannot access secondary GPU, secondary X is not active.** **[ 4703.996910] [ERROR]Aborting because fallback start is disabled.** Please help.

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  • How Do Colors Influence Web Design?

    Colors hold prime importance in any web design. Colors are what add visual vibrancy to the design and layout of the website. In fact, a website without colors looks plain and bland and seldom appeals... [Author: Kabir Bedi - Web Design and Development - April 05, 2010]

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  • Google I/O 2012 - Get your Content on Google TV

    Google I/O 2012 - Get your Content on Google TV Christian Kurzke , Andrew Jeon, Mark Lindner Google TV devices are typically the largest screen in the house, which makes them a prime platform for developers who want to distribute high quality, long form content right to the living room. We will talk about different options for hosting, streaming and securing your content on Google TV, and how to ensure your audience has a great experience viewing your content. For all I/O 2012 sessions, go to developers.google.com From: GoogleDevelopers Views: 1562 26 ratings Time: 01:01:00 More in Science & Technology

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  • Open Source Gets Political

    <b>Linux User and Developer:</b> "In response to a petition, the Prime Minister has dropped Mandelson&#8217;s plans for a controversial &#8216;three strikes&#8217; rule forcing ISPs to permanently disconnect those repeatedly accused of illegal file sharing by copyright holders."

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  • WebP se dote d'un mode de compression d'images sans perte, le format open source de Google veut aussi concurrencer le PNG

    WebP se dote d'un mode de compression d'images sans perte Le format open source de Google veut aussi concurrencer le PNG Mise à jour du 21 novembre 2011 Google voit grand pour son format d'image WebP et veut manifestement en faire un format à tout faire. Positionné au départ (lire ci-devant) comme un concurrent plus optimisé que le JPEG, avec en prime une couche alpha progressive (de transparence), il se dote aujourd'hui de capacités d'optimisation non destructives des images, à l'instar du PNG. Le nouveau mode lossless (sans perte) allierait densité de compression et facilité de décodage d'après un billet...

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  • Description des fichiers de données du client mail gratuit DreamMail

    bonjour, DreamMail est un client chinois mail pop3 et webmail classique mais assez complet sous windows son principal intérêt est de permettre le partage réseau d'un compte mail entre plusieurs utilisateurs. (ms jet database) Pour les plus curieux, j'ai écris un petit article décrivant en détail la structure de cette database avec en prime un exemple de script...

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  • Understanding Keyword Research Data

    Whenever any company goes ahead and decides to launch a campaign to increase their business sales and raise their profits over the internet then their first concern must be increased traffic. Well, this is the prime goal of every internet venture in a general manner. What is the purpose of having any content on the web when there are no visitors to that website and there is no body actually visiting your sites.

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  • High Value DoFollow Backlinks and Their Importance to Your Site Rankings

    For a website to be popular, it needs to be ranked rather high in the search engines. There are multitudes of ways this can be achieved. Among the most popular would be the amassing of backlinks to boost the site's popularity. Of course, not all backlinks have the same value and those procuring links for their site may wish to look towards dofollow backlinks as the prime links to acquire.

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