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• Android 3.1+ USB as virtual COM port

  - by ZachMc

  I have a third party usb device, that when plugged into a Windows machine, is recognized as a serial device and assigned to the COM 4 port. I can communicate with the device just like I would with a device connected via a serial port. For instance, I can write "abc" serially to the device via the USB connection. I have been searching for a way to do a similar thing in Android. If I try the Usb Host method, and use a UsbManager to open the UsbDevice, I can get one interface, with 2 endpoints. I have tried sending control messages using the method in UsbDeviceConnection, but the method returns -1 for everything (though I don't know what I should use for the parameters of that method). Is there a way to get an OutputStream that I can write to that will send bytes to the USB device? Right now I am looking at recompiling the kernel to include a virtual COM port driver and write some native code to be able to do this. Thanks! Edit: I am using the FTDI serial to USB converter circuit. Is this compatible with Android?

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• java.io.FileNotFoundException (Permission denied) When trying to write to the Android sdcard

  - by joefischer1

  I am trying to select an image file from the photo gallery and write to the sdcard. Below is the code that results in an exception. It appears to throw this exception when trying to create the FileOutputStream. I have the following line added to the manifest file nested inside the application element. I can't find a solution to the problem: <uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" /> public boolean saveSelectedImage( Uri selectedImage, int imageGroup, int imageNumber ) { boolean exception = false; InputStream input = null; OutputStream output = null; if( externalStorageIsWritable() ) { try { ContentResolver content = ctx.getContentResolver(); input = content.openInputStream( selectedImage ); if(input != null) Log.v( CLASS_NAME, "Input Stream Opened successfully"); File outFile = null; File root = Environment.getExternalStorageDirectory( ); if(root == null) Log.v(CLASS_NAME, "FAILED TO RETRIEVE DIRECTORY"); else Log.v(CLASS_NAME, "ROOT DIRECTORY is:"+root.toString()); output = new FileOutputStream( root+"/Image"+ imageGroup + "_" + imageNumber + ".png" ); if(output != null) Log.e( CLASS_NAME, "Output Stream Opened successfully"); // output = new FileOutputStream // ("/sdcard/Image"+imageGroup+"_"+imageNumber+".png"); byte[] buffer = new byte[1000]; int bytesRead = 0; while ( ( bytesRead = input.read( buffer, 0, buffer.length ) ) >= 0 ) { output.write( buffer, 0, buffer.length ); } } catch ( Exception e ) { Log.e( CLASS_NAME, "Exception occurred while moving image: "); e.printStackTrace(); exception = true; } finally { // if(input != null)input.close(); // if(output != null)output.close(); // if (exception ) return false; } return true; } else return false; }

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• Read from one large file and write to many (tens, hundreds, or thousands) files in Java?

  - by Rudiger

  I have a large-ish file (4-5 GB compressed) of small messages that I wish to parse into approximately 6,000 files by message type. Messages are small; anywhere from 5 to 50 bytes depending on the type. Each message starts with a fixed-size type field (a 6-byte key). If I read a message of type '000001', I want to write append its payload to 000001.dat, etc. The input file contains a mixture of messages; I want N homogeneous output files, where each output file contains only the messages of a given type. What's an efficient a fast way of writing these messages to so many individual files? I'd like to use as much memory and processing power to get it done as fast as possible. I can write compressed or uncompressed files to the disk. I'm thinking of using a hashmap with a message type key and an outputstream value, but I'm sure there's a better way to do it. Thanks!

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• Java Process.waitFor() and IO streams

  - by lynks

  I have the following code; String[] cmd = { "bash", "-c", "~/path/to/script.sh" }; Process p = Runtime.getRuntime().exec(cmd); PipeThread a = new PipeThread(p.getInputStream(), System.out); PipeThread b = new PipeThread(p.getErrorStream(), System.err); p.waitFor(); a.die(); b.die(); The PipeThread class is quite simple so I will include it in full; public class PipeThread implements Runnable { private BufferedInputStream in; private BufferedOutputStream out; public Thread thread; private boolean die = false; public PipeThread(InputStream i, OutputStream o) { in = new BufferedInputStream(i); out = new BufferedOutputStream(o); thread = new Thread(this); thread.start(); } public void die() { die = true; } public void run() { try { byte[] b = new byte[1024]; while(!die) { int x = in.read(b, 0, 1024); if(x > 0) out.write(b, 0, x); else die(); out.flush(); } } catch(Exception e) { e.printStackTrace(); } try { in.close(); out.close(); } catch(Exception e) { } } } My problem is this; p.waitFor() blocks endlessly, even after the subprocess has terminated. If I do not create the pair of PipeThread instances, then p.waitFor() works perfectly. What is it about the piping of io streams that is causing p.waitFor() to continue blocking? I'm confused as I thought the IO streams would be passive, unable to keep a process alive, or to make Java think the process is still alive.

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• Blackberry app stuck trying to access a server.

  - by Tejaswi Yerukalapudi

  Hi, I've built a ASP.NET webservice and I'm trying to access it from a Blackberry. I've been testing it out with multiple devices and the simulator and it works fine, but there's just the one Blackberry 9000 (It's not the model, I've tried it out with another Blackberry 9000), and it's stuck waiting for a response from the server. Relevant section of the code that accesses this - System.out.println("IN ntwk access thread, start point"); HttpConnection connection = (HttpConnection)Connector.open(serviceURL + WSNAME); connection.setRequestMethod(HttpConnection.POST); connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded"); connection.setRequestProperty("Content-length", Integer.toString(postData1.length)); OutputStream requestOutput = connection.openOutputStream(); requestOutput.write(postData1); requestOutput.close(); final int responseCode = connection.getResponseCode(); if(responseCode!= HttpConnection.HTTP_OK) { //Process the error condition } // Request succeeded process the data. It seems to be getting stuck after connection.getResponseCode(). Is there some way I can verify what's going wrong with this particular device? Thanks, Teja

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• JAVA - Download PDF file from Webserver

  - by Augusto Picciani

  I need to download a pdf file from a webserver to my pc and save it locally. I used Httpclient to connect to webserver and get the content body: HttpEntity entity=response.getEntity(); InputStream in=entity.getContent(); String stream = CharStreams.toString(new InputStreamReader(in)); int size=stream.length(); System.out.println("stringa html page LENGTH:"+stream.length()); System.out.println(stream); SaveToFile(stream); Then i save content in a file: //check CRLF (i don't know if i need to to this) String[] fix=stream.split("\r\n"); File file=new File("C:\\Users\\augusto\\Desktop\\progetti web\\test\\test2.pdf"); PrintWriter out = new PrintWriter(new FileWriter(file)); for (int i = 0; i < fix.length; i++) { out.print(fix[i]); out.print("\n"); } out.close(); I also tried to save a String content to file directly: OutputStream out=new FileOutputStream("pathPdfFile"); out.write(stream.getBytes()); out.close(); But the result is always the same: I can open pdf file but i can see white pages only. Does the mistake is around pdf stream and endstream charset encoding? Does pdf content between stream and endStream need to be manipulate in some others way?

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• sharing message object between web applications

  - by jezhilvalan

  I need to share java mail message objects between two web applications(A and B). WebApplication A obtains the message and write it to the outputStream for(int i=0;i<messagesArr.length;i++){ uid = pop3FolderObj.getUID(messagesArr[i]); //storing messages with uid names inorder to maintain uniqueness File f = new File("F:/PersistedMessagesFolder" + uid); FileOutputStream fos = new FileOutputStream(f); messagesArr[i].writeTo(fos); fos.flush(); fos.close(); } Is FileOutputStream the best output stream for persisting message objects? Is it possible to use ObjectOutputStream for message object persistence? WebApplication B reads the message object via InputStream FileInputStream fis = new FileInputStream("F:/MessagesPersistedFolder"+uid); MimeMessage mm = new MimeMessage(sessionObj,fis); What if the mail message object which is already written via WebApplication A is not a MimeMessage? How can I read non-mime messages using input stream? MimeMessage constructor mandates sessionObj as the first parameter? How can I obtain this sessionObj in WebApplicationB? Do I have to again establish store connection with the same emailid,emailpassword,popserver and port(already used in WebApplication A) with the email server inorder to obtain this session object? Even if obtained, will this session object remains the same as that of the session object which is priorly obtained in WebApplicationA? Since I am using uids to name Message objects (inorder to maintain uniqueness of file names) how can I share these uids between WebApplication A and WebApplication B? WebApplication B needs the uid inorder to access the specific file which is present in "F:/MessagesPersistedFolder" Please help me in resolving the aforeseen issues.

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• How can I overlay images over one another in Java?

  - by Sam

  So I have been posting all over and have yet to get a solid answer: I have created an image resizing class, with a crop method. The cropping works great. The issue that I am having is the background color that I specify in the drawImage function of Graphics is not working correctly. It defaults to black as the background regardless of what I supply (in this case Color.WHITE). Also, the overlaying image or top most image (comes from a file) is being inverted (I think it is) or otherwise discolored. Just so you can conceptualize this a little bit better, I am taking a jpeg and overlaying it on top of a new BufferedImage, the new buffered image's background is not being set. Here is the code below that I am working with: public void Crop(int Height, int Width, int SourceX, int SourceY) throws Exception { //output height and width int OutputWidth = this.OutputImage.getWidth(); int OutputHeight = this.OutputImage.getHeight(); //create output streams ByteArrayOutputStream MyByteArrayOutputStream = new ByteArrayOutputStream(); MemoryCacheImageOutputStream MyMemoryCacheImageOutputStream = new MemoryCacheImageOutputStream(MyByteArrayOutputStream); //Create a new BufferedImage BufferedImage NewImage = new BufferedImage(Width, Height, BufferedImage.TYPE_INT_RGB); Graphics MyGraphics = NewImage.createGraphics(); MyGraphics.drawImage(this.OutputImage, -SourceX, -SourceY, OutputWidth, OutputHeight, Color.WHITE, null); // Get Writer and set compression Iterator MyIterator = ImageIO.getImageWritersByFormatName("png"); if (MyIterator.hasNext()) { //get image writer ImageWriter MyImageWriter = (ImageWriter)MyIterator.next(); //get params ImageWriteParam MyImageWriteParam = MyImageWriter.getDefaultWriteParam(); //set outputstream MyImageWriter.setOutput(MyMemoryCacheImageOutputStream); //create new ioimage IIOImage MyIIOImage = new IIOImage(NewImage, null, null); //write new image MyImageWriter.write(null, MyIIOImage, MyImageWriteParam); } //convert output stream back to inputstream ByteArrayInputStream MyByteArrayInputStream = new ByteArrayInputStream(MyByteArrayOutputStream.toByteArray()); MemoryCacheImageInputStream MyMemoryCacheImageInputStream = new MemoryCacheImageInputStream(MyByteArrayInputStream); //resassign as a buffered image this.OutputImage = ImageIO.read(MyMemoryCacheImageInputStream); }

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• How to handle error with content-disposition

  - by František Žiacik

  Hi, how should I handle an exception that occurs after sending a Content-Disposition header for an attachment? I'm trying to generate a report at server and send it as a file, but if an exception occurs during the report generation, the error message itself is sent to browser which still takes it as a content of a file and shows a Save As dialog. User cannot know there was an error generating report, saves the file which is in wrong format now. Is there a way to cancel the response with this header and redirect to an error page? Or what else can I do to inform user about the error? Probably I could generate the report first and only if there was no error send the headers, but I want the report render directly to the Response output stream so that it does not need to stay in memory. Here is my code: this.Response.ContentType = "application/octet-stream"; this.Response.AddHeader("Content-Disposition", @"attachment; filename=""" + item.Name + @""""); this.Response.Flush(); GenerateReportTo(this.Response.OutputStream); // Exception occurs Thanks for any suggestions

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• VB.NET trying simple captcha

  - by Pride Grimm

  I'm trying to write a simple captcha program in vb.net. I'm just wanting to make an image from random numbers and display it, check the answer, and then proceed. I'm pretty new to vb.net, so I found some code to generate the information. I will cite the owner when I find it again (http://www.knowlegezone.com/80/article/Technology/Software/Asp-Net/Simple-ASP-NET-CAPTCHA-Tutorial) This is in the onload() of default2.aspx Public Sub returnNumer() Dim num1 As New Random Dim num2 As New Random Dim numQ1 As Integer Dim numQ2 As Integer Dim QString As String numQ1 = num1.Next(10, 15) numQ2 = num2.Next(17, 31) QString = numQ1.ToString + " + " + numQ2.ToString + " = " Session("answer") = numQ1 + numQ2 Dim bitmap As New Bitmap(85, 35) Dim Grfx As Graphics = Graphics.FromImage(bitmap) Dim font As New Font("Arial", 18, FontStyle.Bold, GraphicsUnit.Pixel) Dim Rect As New Rectangle(0, 0, 100, 50) Grfx.FillRectangle(Brushes.Brown, Rect) Grfx.DrawRectangle(Pens.PeachPuff, Rect) ' Border Grfx.DrawString(QString, font, Brushes.Azure, 0, 0) Response.ContentType = "Image/jpeg" bitmap.Save(Response.OutputStream, System.Drawing.Imaging.ImageFormat.Jpeg) bitmap.Dispose() Grfx.Dispose() End Sub So I put this in a separate page, like this This all works find and dandy, but when I get the answer from the session like this Dim literal As String = Convert.ToString(Session("answer")) It's always one behind. So if The images adds to 32, the answer in session isn't 32. But after a refresh (and a new image) the session("answer") will be 32. Is there a way to refresh the session on page 1, after the default2.aspx loads? Is there a better way to do this? I though about trying to run the code all on one page, and trying to set the src of and image to returnNumber(), but I need a bit of help on that one.

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• Java: How to make this main thread wait for the new thread to terminate

  - by Jeff Bullard

  I have a java class that creates a process, called child, using ProcessBuilder. The child process generates a lot of output that I am draining on a separate thread to keep the main thread from getting blocked. However, a little later on I need to wait for the output thread to complete/terminate before going on, and I'm not sure how to do that. I think that join() is the usual way to do this but I'm not sure how to do that in this case. Here is the relevant part of the java code. // Capture output from process called child on a separate thread final StringBuffer outtext = new StringBuffer(""); new Thread(new Runnable() { public void run() { InputStream in = null; in = child.getInputStream(); try { if (in != null) { BufferedReader reader = new BufferedReader(new InputStreamReader(in)); String line = reader.readLine(); while ((line != null)) { outtext.append(line).append("\n"); ServerFile.appendUserOpTextFile(userName, opname, outfile, line+"\n"); line = reader.readLine(); } } } catch (IOException iox) { throw new RuntimeException(iox); } } }).start(); // Write input to for the child process on this main thread // String intext = ServerFile.readUserOpTextFile(userName, opname, infile); OutputStream out = child.getOutputStream(); try { out.write(intext.getBytes()); out.close(); } catch (IOException iox) { throw new RuntimeException(iox); } // ***HERE IS WHERE I NEED TO WAIT FOR THE THREAD TO FINISH *** // Other code goes here that needs to wait for outtext to get all // of the output from the process // Then, finally, when all the remaining code is finished, I return // the contents of outtext return outtext.toString();

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• Sending JSON to a server

  - by SK9

  I'm running the following Java, an HttpURLConnection PUT request with JSON data that will be sent from an Android device. I'll handle any raised exceptions after this is working. Authenticator.setDefault(new Authenticator() { protected PasswordAuthentication getPasswordAuthentication() { return new PasswordAuthentication(nameString, pwdString.toCharArray()); } }); url = new URL(myURLString); HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection(); urlConnection.setDoOutput(true); urlConnection.setChunkedStreamingMode(0); urlConnection.setRequestMethod("PUT"); urlConnection.setRequestProperty("Content-Type", "application/json"); OutputStream output = null; try { output = urlConnection.getOutputStream(); output.write(jsonArray.toString().getBytes()); } finally { if (output != null) { output.close(); } } int status = ((HttpURLConnection) urlConnection).getResponseCode(); System.out.println("" + status); urlConnection.disconnect(); I'm receiving an HTTP 500 error (internal error code), that an unexpected property is blocking the request. The JSONArray comprises JSONObjects whose keys I know are correct. The server is pretty standard, and expects HTTP PUTs with JSON bodies. Am I missing something glaring? Thanking you kindly in advance.

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• Why do the outputs differ when I run this code using Netbeans 6.8 and Eclipse?

  - by Vimal Basdeo

  When I am running the following codes using Eclipse and Netbeans 6.8. I want to see the available COM ports on my computer. When running in Eclipse it is returning me all available COm ports but when running t in Netbeans, it does not seem to find any ports .. public static void test(){ Enumeration lists=CommPortIdentifier.getPortIdentifiers(); System.out.println(lists.hasMoreElements()); while (lists.hasMoreElements()){ CommPortIdentifier cn=(CommPortIdentifier)lists.nextElement(); if ((CommPortIdentifier.PORT_SERIAL==cn.getPortType())){ System.out.println("Name is serail portzzzz "+cn.getName()+" Owned status "+cn.isCurrentlyOwned()); try{ SerialPort port1=(SerialPort)cn.open("ComControl",800000); port1.setSerialPortParams(9600, SerialPort.DATABITS_8, SerialPort.STOPBITS_1, SerialPort.PARITY_NONE); System.out.println("Before get stream"); OutputStream out=port1.getOutputStream(); InputStream input=port1.getInputStream(); System.out.println("Before write"); out.write("AT".getBytes()); System.out.println("After write"); int sample=0; //while((( sample=input.read())!=-1)){ System.out.println("Before read"); //System.out.println(input.read() + "TEsting "); //} System.out.println("After read"); System.out.println("Receive timeout is "+port1.getReceiveTimeout()); }catch(Exception e){ System.err.println(e.getMessage()); } } else{ System.out.println("Name is parallel portzzzz "+cn.getName()+" Owned status "+cn.isCurrentlyOwned()+cn.getPortType()+" "); } } } Output with Netbeans false Output using Eclipse true Name is serail portzzzz COM1 Owned status false Before get stream Before write After write Before read After read Receive timeout is -1 Name is serail portzzzz COM2 Owned status false Before get stream Before write After write Before read After read Receive timeout is -1 Name is parallel portzzzz LPT1 Owned status false2 Name is parallel portzzzz LPT2 Owned status false2

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• Java Socks Proxy Socket Error

  - by Ionut Ungureanu

  I am trying to create a http request through a SOCKS (v4 / v5) proxy in Java. After reading about socks communication protocol on WikiPedia, I have put togheter this piece of code: Socket sock = new Socket(); InetSocketAddress remoteProxyAddress = new InetSocketAddress(proxy ip, proxy port); sock.connect(remoteProxyAddress, connTimeout); InputStream in = sock.getInputStream(); OutputStream out = sock.getOutputStream(); out.write(0x04); out.write(0x01); out.write((endpoint.getPort() >> 8) & 0xff); out.write((endpoint.getPort() >> 0) & 0xff); out.write(endpoint.getAddress().getAddress()); out.write(0x0); out.flush(); And here comes the part where I read from the proxy server. The problem is that the response is always "-1". I have tried the proxy on Firefox and it works perfect. So... the problem is in my app. Can anyone help me? Thanks!

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• Real Time Sound Captureing J2ME

  - by Abdul jalil

  i am capturing sound in J2me and send these bytes to remote system, i then play these bytes on remote system.five second voice is capture and send to remote system. i get the repeated sound again .i am making a sound messenger please help me where i am doing wrong i am using the follown code . String remoteTimeServerAddress="192.168.137.179"; sc = (SocketConnection) Connector.open("socket://"+remoteTimeServerAddress+":13"); p = Manager.createPlayer("capture://audio?encoding=pcm&rate=11025&bits=16&channels=1"); p.realize(); RecordControl rc = (RecordControl)p.getControl("RecordControl"); ByteArrayOutputStream output = new ByteArrayOutputStream(); OutputStream outstream =sc.openOutputStream(); rc.setRecordStream(output); rc.startRecord(); p.start(); int size=output.size(); int offset=0; while(true) { Thread.currentThread().sleep(5000); rc.commit(); output.flush(); size=output.size(); if(size0) { recordedSoundArray=output.toByteArray(); outstream.write(recordedSoundArray,0,size); } output.reset(); rc.reset(); rc.setRecordStream(output); rc.startRecord(); }

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• "A generic error occurred in GDI+" error while showing uploaded images

  - by Prasad

  i am using the following code to show the image that has been saved in my database from my asp.net mvc(C#) application:. public ActionResult GetSiteHeaderLogo() { SiteHeader _siteHeader = new SiteHeader(); Image imgImage = null; long userId = Utility.GetUserIdFromSession(); if (userId > 0) { _siteHeader = this.siteBLL.GetSiteHeaderLogo(userId); if (_siteHeader.Logo != null && _siteHeader.Logo.Length > 0) { byte[] _imageBytes = _siteHeader.Logo; if (_imageBytes != null) { using (System.IO.MemoryStream imageStream = new System.IO.MemoryStream(_imageBytes)) { imgImage = Image.FromStream(imageStream); } } string sFileExtension = _siteHeader.FileName.Substring(_siteHeader.FileName.IndexOf('.') + 1, _siteHeader.FileName.Length - (_siteHeader.FileName.IndexOf('.') + 1)); Response.ContentType = Utility.GetContentTypeByExtension(sFileExtension.ToLower()); Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.BufferOutput = false; if (imgImage != null) { ImageFormat _imageFormat = Utility.GetImageFormat(sFileExtension.ToLower()); imgImage.Save(Response.OutputStream, _imageFormat); imgImage.Dispose(); } } } return new EmptyResult(); } It works fine when i upload original image. But when i upload any downloaded images, it throws the following error: System.Runtime.InteropServices.ExternalException: A generic error occurred in GDI+. System.Runtime.InteropServices.ExternalException: A generic error occurred in GDI+. at System.Drawing.Image.Save(Stream stream, ImageCodecInfo encoder, EncoderParameters encoderParams) at System.Drawing.Image.Save(Stream stream, ImageFormat format) For. Ex: When i upload the original image, it shows as logo in my site and i downloaded that logo from the site and when i re-upload the same downloaded image, it throws the above error. It seems very weird to me and not able to find why its happening. Any ideas on this?

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• How to get the compression ratio for a GZipped file ?

  - by Enigma

  Here is how I compressed the data: <%@ page import="javax.servlet.jsp.*,java.io.*,java.util.zip.*" %> <% String encodings = request.getHeader("Accept-Encoding"); PrintWriter outWriter = null; if ((encodings != null) && (encodings.indexOf("gzip") != -1)) { OutputStream outA = response.getOutputStream(); outWriter = new PrintWriter(new GZIPOutputStream(outA), false); response.setHeader("Content-Encoding", "gzip"); int a = response.getBufferSize(); System.out.println("ZIPPED VERSION BF:"+a); } else { System.out.println("UN-ZIPPED VERSION"); outWriter = new PrintWriter(response.getOutputStream(), false); } outWriter.println("<HTML><BODY>"); for(int i=0; i<1000; i++) { outWriter.println(" blah blah blah<br>"); } outWriter.println("</BODY></HTML>"); outWriter.close(); %>

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• public class ImageHandler : IHttpHandler

  - by Ken

  cmd.Parameters.AddWithValue("@id", new system.Guid (imageid)); What using System reference would this require? Here is the handler: using System; using System.Collections.Specialized; using System.Web; using System.Web.Configuration; using System.Web.Security; using System.Globalization; using System.Configuration; using System.Data.SqlClient; using System.Data; using System.IO; using System.Web.Profile; using System.Drawing; public class ImageHandler : IHttpHandler { public void ProcessRequest(HttpContext context) { string imageid; if (context.Request.QueryString["id"] != null) imageid = (context.Request.QueryString["id"]); else throw new ArgumentException("No parameter specified"); context.Response.ContentType = "image/jpeg"; Stream strm = ShowProfileImage(imageid.ToString()); byte[] buffer = new byte[8192]; int byteSeq = strm.Read(buffer, 0, 8192); while (byteSeq > 0) { context.Response.OutputStream.Write(buffer, 0, byteSeq); byteSeq = strm.Read(buffer, 0, 8192); } //context.Response.BinaryWrite(buffer); } public Stream ShowProfileImage(String imageid) { string conn = ConfigurationManager.ConnectionStrings["MyConnectionString1"].ConnectionString; SqlConnection connection = new SqlConnection(conn); string sql = "SELECT image FROM Profile WHERE UserId = @id"; SqlCommand cmd = new SqlCommand(sql, connection); cmd.CommandType = CommandType.Text; cmd.Parameters.AddWithValue("@id", new system.Guid (imageid));//Failing Here!!!! connection.Open(); object img = cmd.ExecuteScalar(); try { return new MemoryStream((byte[])img); } catch { return null; } finally { connection.Close(); } } public bool IsReusable { get { return false; } } }

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• File mkdirs() method not working in android/java

  - by Leif Andersen

  I've been pulling out my hair on this for a while now. The following method is supposed to download a file, and save it to the location specified on the hard drive. private static void saveImage(Context context, boolean backgroundUpdate, URL url, File file) { if (!Tools.checkNetworkState(context, backgroundUpdate)) return; // Get the image try { // Make the file file.getParentFile().mkdirs(); // Set up the connection URLConnection uCon = url.openConnection(); InputStream is = uCon.getInputStream(); BufferedInputStream bis = new BufferedInputStream(is); // Download the data ByteArrayBuffer baf = new ByteArrayBuffer(50); int current = 0; while ((current = bis.read()) != -1) { baf.append((byte) current); } // Write the bits to the file OutputStream os = new FileOutputStream(file); os.write(baf.toByteArray()); os.close(); } catch (Exception e) { // Any exception is probably a newtork faiilure, bail return; } } Also, if the file doesn't exist, it is supposed to make the directory for the file. (And if there is another file already in that spot, it should just not do anything). However, for some reason, the mkdirs() method never makes the directory. I've tried everything from explicit parentheses, to explicitly making the parent file class, and nothing seems to work. I'm fairly certain that the drive is writable, as it's only called after that has already been determined, also that is true after running through it while debugging. So the method fails because the parent directories aren't made. Can anyone tell me if there is anything wrong with the way I'm calling it? Also, if it helps, here is the source for the file I'm calling it in: https://github.com/LeifAndersen/NetCatch/blob/master/src/net/leifandersen/mobile/android/netcatch/services/RSSService.java Thank you

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• How did My Object Get into ASP.NET Page State?

  - by Paul Knopf

  I know what this error is, how to fix it, etc. My question is that I don't know why my current page I am developing is throwing this error when I am not using the foo class directly in any way, nor am I setting anything to the viewstate. I am using postbacks alot, but like I said, I am not storing anything in the viewstate etc one integer. I am using nhibernate if that is relevant. Any idea why I need to mark this classes as serializable that arent being used? Where should I start investigating? [SerializationException: Type 'FlexiCommerce.Persistence.NH.ContentPersister' in Assembly 'FlexiCommerce.Persistence.NH, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null' is not marked as serializable.] System.Runtime.Serialization.FormatterServices.InternalGetSerializableMembers(RuntimeType type) +9434541 System.Runtime.Serialization.FormatterServices.GetSerializableMembers(Type type, StreamingContext context) +247 System.Runtime.Serialization.Formatters.Binary.WriteObjectInfo.InitMemberInfo() +160 System.Runtime.Serialization.Formatters.Binary.WriteObjectInfo.InitSerialize(Object obj, ISurrogateSelector surrogateSelector, StreamingContext context, SerObjectInfoInit serObjectInfoInit, IFormatterConverter converter, ObjectWriter objectWriter, SerializationBinder binder) +218 System.Runtime.Serialization.Formatters.Binary.ObjectWriter.Write(WriteObjectInfo objectInfo, NameInfo memberNameInfo, NameInfo typeNameInfo) +388 System.Runtime.Serialization.Formatters.Binary.ObjectWriter.Serialize(Object graph, Header[] inHeaders, __BinaryWriter serWriter, Boolean fCheck) +444 System.Runtime.Serialization.Formatters.Binary.BinaryFormatter.Serialize(Stream serializationStream, Object graph, Header[] headers, Boolean fCheck) +133 System.Runtime.Serialization.Formatters.Binary.BinaryFormatter.Serialize(Stream serializationStream, Object graph) +13 System.Web.UI.ObjectStateFormatter.SerializeValue(SerializerBinaryWriter writer, Object value) +2937 [ArgumentException: Error serializing value 'Music#2' of type 'FlexiCommerce.Components.Category.'] System.Web.UI.ObjectStateFormatter.SerializeValue(SerializerBinaryWriter writer, Object value) +3252 System.Web.UI.ObjectStateFormatter.SerializeValue(SerializerBinaryWriter writer, Object value) +2276 [ArgumentException: Error serializing value 'System.Object[]' of type 'System.Object[].'] System.Web.UI.ObjectStateFormatter.SerializeValue(SerializerBinaryWriter writer, Object value) +3252 System.Web.UI.ObjectStateFormatter.Serialize(Stream outputStream, Object stateGraph) +116 System.Web.UI.ObjectStateFormatter.Serialize(Object stateGraph) +57 System.Web.UI.ObjectStateFormatter.System.Web.UI.IStateFormatter.Serialize(Object state) +4 System.Web.UI.Util.SerializeWithAssert(IStateFormatter formatter, Object stateGraph) +37 System.Web.UI.HiddenFieldPageStatePersister.Save() +79 System.Web.UI.Page.SavePageStateToPersistenceMedium(Object state) +108 System.Web.UI.Page.SaveAllState() +315 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +2492

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• Unreleased Resource: Streams

  - by Vibhas

  Hi freinds i am getting a warning in the fortify report for the following code: if (null != serverSocket) { OutputStream socketOutPutStream = serverSocket .getOutputStream(); if (null != socketOutPutStream) { oos = new ObjectOutputStream(socketOutPutStream); if (null != oos) { int c; log.info("i am in Step 3 ooss " + oos); while ((c = mergedIS.read()) != -1) { oos.writeByte(c); } } log.info("i am in Step 4 "); } } in the catch block i have mentioned : catch (UnknownHostException e) { //catch exception Vibhas added log.info("UnknownHostException occured"); } catch (IOException e) { //catch exception Vibhas added log.info("IOException occured"); } catch (Exception e) { //catch exception //log.info("error occured in copyFile in utils-->"+e.getMessage()+"file name is-->"+destiFileName); }finally{ if (null != oos){ oos.flush(); oos.close(); } catch (Exception e) { //catch exception } } Warning which i am getting in the fortify report is: Abstract: The function copyFile() in ODCUtil.java sometimes fails to release a system resource allocated by getOutputStream() on line 61. Sink: ODCUtil.java:64 oos = new ObjectOutputStream(socketOutPutStream)() 62 if (null != socketOutPutStream) { 63 64 oos = new ObjectOutputStream(socketOutPutStream); 65 if (null != oos) { 66 int c;

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• Android - BitmapFactory.decodeByteArray - OutOfMemoryError (OOM)

  - by Bob Keathley

  I have read 100s of article about the OOM problem. Most are in regard to large bitmaps. I am doing a mapping application where we download 256x256 weather overlay tiles. Most are totally transparent and very small. I just got a crash on a bitmap stream that was 442 Bytes long while calling BitmapFactory.decodeByteArray(....). The Exception states: java.lang.OutOfMemoryError: bitmap size exceeds VM budget(Heap Size=9415KB, Allocated=5192KB, Bitmap Size=23671KB) The code is: protected Bitmap retrieveImageData() throws IOException { URL url = new URL(imageUrl); InputStream in = null; OutputStream out = null; HttpURLConnection connection = (HttpURLConnection) url.openConnection(); // determine the image size and allocate a buffer int fileSize = connection.getContentLength(); if (fileSize < 0) { return null; } byte[] imageData = new byte[fileSize]; // download the file //Log.d(LOG_TAG, "fetching image " + imageUrl + " (" + fileSize + ")"); BufferedInputStream istream = new BufferedInputStream(connection.getInputStream()); int bytesRead = 0; int offset = 0; while (bytesRead != -1 && offset < fileSize) { bytesRead = istream.read(imageData, offset, fileSize - offset); offset += bytesRead; } // clean up istream.close(); connection.disconnect(); Bitmap bitmap = null; try { bitmap = BitmapFactory.decodeByteArray(imageData, 0, bytesRead); } catch (OutOfMemoryError e) { Log.e("Map", "Tile Loader (241) Out Of Memory Error " + e.getLocalizedMessage()); System.gc(); } return bitmap; } Here is what I see in the debugger: bytesRead = 442 So the Bitmap data is 442 Bytes. Why would it be trying to create a 23671KB Bitmap and running out of memory?

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• download large files using servlet

  - by niks

  I am using Apache Tomcat Server 6 and Java 1.6 and am trying to write large mp3 files to the ServletOutputStream for a user to download. Files are ranging from a 50-750MB at the moment. The smaller files aren't causing too much of a problem but with the larger files it and getting socket exception broken pipe. File fileMp3 = new File(objDownloadSong.getStrSongFolder() + "/" + strSongIdName); FileInputStream fis = new FileInputStream(fileMp3); response.setContentType("audio/mpeg"); response.setHeader("Content-Disposition", "attachment; filename=\"" + strSongName + ".mp3\";"); response.setContentLength((int) fileMp3.length()); OutputStream os = response.getOutputStream(); try { int byteRead = 0; while ((byteRead = fis.read()) != -1) { os.write(byteRead); } os.flush(); } catch (Exception excp) { downloadComplete = "-1"; excp.printStackTrace(); } finally { os.close(); fis.close(); }

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• Read varbinary data in java

  - by masoud farahani

  I made a Java application which reads some files from SQL server. Those files are saved to a varbinary(MAX) field in SQL Server by a third party web service. My problem is that when I want to read those files with my Java application, those binary data show different content in the Java application. In fact, I read data byte by byte and I figured out that some bytes did not show the real values which were saved in the database. I found out what the problem is, but I couldn’t find a solution yet. I found out that in the web service every varbinary data is saved to database as byte data (in .Net each byte takes 0 to 255). But, when I want to read the binary data in Java, it takes different values and cause an exception with some values, because in Java a byte value takes -127 to 127. In my Java application I want to write those data to a file by OutputStream.write(byte[]) method. How can I solve this problem? I think that I have to find a way to convert c# byte[] to a Java byte[] (or binary data), but how can I do that?

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• Post valuse and upload Image to php server in android

  - by lawat

  I am trying to upload image from android phone to php server with additional values,the method is post my php file look like this if($_POST['val1']){ if($_POST['val2']){ if($_FILE['image']){ ...... } } }else{ echo "Value not found"; } I am doing is URL url=new URL("http://www/......../myfile.php"); HttpURLConnection con=(HttpURLConnection) url.openConnection(); con.setDoInput(true); con.setDoOutput(true); con.setUseCaches(false); con.setRequestMethod("POST");//Enable http POST con.setRequestProperty("Connection", "Keep-Alive"); con.setRequestProperty("Content-Type", "multipart/form-data;boundary="+"****"); connection.setRequestProperty("uploaded_file", imagefilePath); DataOutputStream ostream = new DataOutputStream( con.getOutputStream()); String res=("Content-Disposition: form-data; name=\"val1\""+val1+"****"+ "Content-Disposition: form-data; name=\"val2\""+val2+"****" "Content-Disposition: form-data; name=\"image\";filename=\"" + imagefilePath +"\""+"****"); outputStream.writeBytes(res); my actual problem is values are not posting so first if condition get false and else section is executed that is it give value not found please help me

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