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  • Rails - authoritative source for your database schema?

    - by keruilin
    I have Rails app, and every once in a while, when I bring new developer onboard they exclaim that they should be able to produce the current DB schema in their dev environment by running the whole history of the migrations. I personally don't think that migrations is the authoritative source for your schema. Right now what we do is load a production copy of the DB, with the current schema, onto the dev machine. And, from there, the schema can be maintained via incremental migrations. So my question are: What is the authoritative source of your schema on a Rails project? What is now considered the best-practice way to maintain your DB schema?

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  • Nested Data XML design

    - by esryl
    Looking to nest (to unlimited levels) elements in XML. Like so: <items> <item> <name>Item One</name> <item> <name>Item Two</name> </item> <item> <name>Item Three</name> <item> <name>Item Four</name> </item> <!-- etc... --> </item> </item> </items> However. While browsing for a solution I noticed in the comments of: http://stackoverflow.com/questions/988139/weird-nesting-in-xml while the above is well formed it would not validate against any sinsible DTD. Two things, what is a better way of nesting similar elements, and secondly what would be the design of the DTD. UPDATE: Would prefer to validate against an XML Schema rather than DTD.

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  • Spring validation has error in XML document from ServletContext resource

    - by user1441404
    I applied spring validation in my registration page .but the follwing error are shown in my server log of my app engine server. javax.servlet.UnavailableException: org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 22 in XML document from ServletContext resource [/WEB-INF/spring/appServlet/servlet-context.xml] is invalid; nested exception is org.xml.sax.SAXParseException; lineNumber: 22; columnNumber: 30; cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'property'. My code is given below : <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd > <beans:bean name="/register" class="com.my.registration.NewUserRegistration"> <property name="validator"> <bean class="com.my.validation.UserValidator" /> </property> <beans:property name="formView" value="newuser"></beans:property> <beans:property name="successView" value="home"></beans:property> </beans:bean> <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <beans:property name="prefix" value="/WEB-INF/views/" /> <beans:property name="suffix" value=".jsp" /> </beans:bean> </beans:beans>

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  • Iterate through deserialized xml object

    - by Bruce Adams
    I have a deserialized xml c# objet. I need to iterate through the oject to display all items, in this case there's just one, and display the name, colors and sizes for each item. The xml: <?xml version="1.0" encoding="utf-8"?> <Catalog Name="Example"> <Items> <Item Name="ExampleItem"> <Colors> <Color Name="Black" Value="#000" /> <Color Name="White" Value="#FFF" /> </Colors> <Sizes> <Size Name="Small" Value="10" /> <Size Name="Medium" Value="20" /> </Sizes> </Item> </Items> </Catalog> xsd.exe generated classes: //------------------------------------------------------------------------------ // <auto-generated> // This code was generated by a tool. // Runtime Version:2.0.50727.4927 // // Changes to this file may cause incorrect behavior and will be lost if // the code is regenerated. // </auto-generated> //------------------------------------------------------------------------------ using System.Xml.Serialization; // // This source code was auto-generated by xsd, Version=2.0.50727.42. // /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] [System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] public partial class Catalog { private CatalogItemsItem[][] itemsField; private string nameField; /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Item", typeof(CatalogItemsItem[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItem[][] Items { get { return this.itemsField; } set { this.itemsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItem { private CatalogItemsItemColorsColor[][] colorsField; private CatalogItemsItemSizesSize[][] sizesField; private string nameField; /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Color", typeof(CatalogItemsItemColorsColor[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItemColorsColor[][] Colors { get { return this.colorsField; } set { this.colorsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Size", typeof(CatalogItemsItemSizesSize[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItemSizesSize[][] Sizes { get { return this.sizesField; } set { this.sizesField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItemColorsColor { private string nameField; private string valueField; /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Value { get { return this.valueField; } set { this.valueField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItemSizesSize { private string nameField; private string valueField; /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Value { get { return this.valueField; } set { this.valueField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] [System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] public partial class NewDataSet { private Catalog[] itemsField; /// <remarks/> [System.Xml.Serialization.XmlElementAttribute("Catalog")] public Catalog[] Items { get { return this.itemsField; } set { this.itemsField = value; } } } Deserialization code: System.Xml.Serialization.XmlSerializer xSerializer = new System.Xml.Serialization.XmlSerializer(typeof(Catalog)); TextReader reader = new StreamReader("catalog.xml"); Catalog catalog = (Catalog)xSerializer.Deserialize(reader); foreach (var item in catalog.Items) { } reader.Close(); When I setp through the code there is one item present in catalog.items, but it is empty, no name, colors or sizes. Any ideas what I need to do? Thanks

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  • Merging two XML files into one XML file using Java

    - by dmurali
    I am stuck with how to proceed with combining two different XML files(which has the same structure). When I was doing some research on it, people say that XML parsers like DOM or StAX will have to be used. But cant I do it with the regular IOStream? I am currently trying to do with the help of IOStream but this is not solving my purpose, its being more complex. For example, What I have tried is; public class GUI { public static void main(String[] args) throws Exception { // Creates file to write to Writer output = null; output = new BufferedWriter(new FileWriter("C:\\merged.xml")); String newline = System.getProperty("line.separator"); output.write(""); // Read in xml file 1 FileInputStream in = new FileInputStream("C:\\1.xml"); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String strLine; while ((strLine = br.readLine()) != null) { if (strLine.contains("<MemoryDump>")){ strLine = strLine.replace("<MemoryDump>", "xmlns:xsi"); } if (strLine.contains("</MemoryDump>")){ strLine = strLine.replace("</MemoryDump>", "xmlns:xsd"); } output.write(newline); output.write(strLine); System.out.println(strLine); } // Read in xml file 2 FileInputStream in = new FileInputStream("C:\\2.xml"); BufferedReader br1 = new BufferedReader(new InputStreamReader(in)); String strLine1; while ((strLine1 = br1.readLine()) != null) { if (strLine1.contains("<MemoryDump>")){ strLine1 = strLine1.replace("<MemoryDump>", ""); } if (strLine1.contains("</MemoryDump>")){ strLine1 = strLine1.replace("</MemoryDump>", ""); } output.write(newline); output.write(strLine1); I request you to kindly let me know how do I proceed with merging two XML files by adding additional content as well. It would be great if you could provide me some example links as well..! Thank You in Advance..! System.out.println(strLine1); } }

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  • Raw XML Push from input stream captures only the first line of XML

    - by pqsk
    I'm trying to read XML that is being pushed to my java app. I originally had this in my glassfish server working. The working code in glassfish is as follows: public class XMLPush implements Serializable { public void processXML() { StringBuilder sb = new StringBuilder(); BufferedReader br = null; try { br = ((HttpServletRequest)FacesContext.getCurrentInstance().getExternalContext().getRequest()).getReader (); String s = null; while((s = br.readLine ()) != null) { sb.append ( s ); } //other code to process xml ........... ............................. }catch(Exception ex) { XMLCreator.exceptionOutput ( "processXML","Exception",ex); } .... ..... }//processXML }//class It works perfect, but my client is unable to have glassfish on their server. I tried grabbing the raw xml from php, but I couldn't get it to work. I decided to open up a socket and listen for the xml push manually. Here is my code for receiving the push: public class ListenerService extends Thread { private BufferedReader reader = null; private String line; public ListenerService ( Socket connection )thows Exception { this.reader = new BufferedReader ( new InputStreamReader ( connection.getInputStream () ) ); this.line = null; }//ListenerService @Override public void run () { try { while ( (this.line = this.reader.readLine ()) != null) { System.out.println ( this.line ); ........ }//while } System.out.println ( ex.toString () ); } } catch ( Exception ex ) { ... }//catch }//run I haven't done much socket programing, but from what I read for the past week is that passing the xml into a string is bad. What am I doing wrong and why is it that in glassfish server it works, and when I just open a socket myself it doesn't? this is all that I receive from the push: PUT /?XML_EXPORT_REASON=ResponseLoop&TIMESTAMP=1292559547 HTTP/1.1 Host: ************************ Accept: */* Content-Length: 470346 Expect: 100-continue <?xml version="1.0" encoding="UTF-8" ?> Where did the xml go? Is it because I am placing it in a string? I just need to grab the xml and save it into a file and then process it. Everything else works, but this.Any help would be greatly appreciated.

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  • XML: What to use as a list separator

    - by Heinzi
    There are two ways to specify lists of values in XML. Variant 1: <Database Name="myDatabase"> <Table Name="myTable1" /> <Table Name="myTable2" /> <Table Name="myTable3" /> ... </Database> Variant 2: <Database Name="myDatabase" Tables="myTable1 myTable2 myTable3 ..." /> Clearly, Variant 1 is cleaner and can be extended more easily, but im many cases Variant 2 is more readable and "user-friendly". When using Variant 2, what should be used as the separator? The XML Schema standard seems to prefer whitespace, whereas some real-world examples use commas instead. Is there a particular reason to choose one over the other (assuming that the values contain neither whitspace nor commas)?

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  • ???????/?????????XML?? ~Oracle????XML~

    - by Yusuke.Yamamoto
    ????? ??:2010/08/25 ??:??????/?? Oracle Database ?XML???????????????????????????????????????????? Oracle Database ?XML???????Oracle Database ? XPath ???Oracle Database ? XQuery ???Oracle Database ????????????XML???????Oracle Database ?XML??????????????????"2?"?????? ????????? ????????????????? http://otndnld.oracle.co.jp/ondemand/otn-seminar/movie/XML2_08251330.wmv http://www.oracle.com/technetwork/jp/content/open-0825-xmlfesta2-251028-ja.pdf

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  • Defining recursive algebraic data types in XML XSD

    - by Ben Challenor
    Imagine I have a recursive algebraic data type like this (Haskell syntax): data Expr = Zero | One | Add Expr Expr | Mul Expr Expr I'd like to represent this in XML, and I'd like an XSD schema for it. I have figured out how to achieve this syntax: <Expr> <Add> <Expr> <Zero/> </Expr> <Expr> <Mul> <Expr> <One/> </Expr> <Expr> <Add> <Expr> <One/> </Expr> <Expr> <One/> </Expr> </Add> </Expr> </Mul> </Expr> </Add> </Expr> with this schema: <xs:complexType name="Expr"> <xs:choice minOccurs="1" maxOccurs="1"> <xs:element minOccurs="1" maxOccurs="1" name="Zero" type="Zero" /> <xs:element minOccurs="1" maxOccurs="1" name="One" type="One" /> <xs:element minOccurs="1" maxOccurs="1" name="Add" type="Add" /> <xs:element minOccurs="1" maxOccurs="1" name="Mul" type="Mul" /> </xs:choice> </xs:complexType> <xs:complexType name="Zero"> <xs:sequence> </xs:sequence> </xs:complexType> <xs:complexType name="One"> <xs:sequence> </xs:sequence> </xs:complexType> <xs:complexType name="Add"> <xs:sequence> <xs:element minOccurs="2" maxOccurs="2" name="Expr" type="Expr" /> </xs:sequence> </xs:complexType> <xs:complexType name="Mul"> <xs:sequence> <xs:element minOccurs="2" maxOccurs="2" name="Expr" type="Expr" /> </xs:sequence> </xs:complexType> But what I really want is this syntax: <Add> <Zero/> <Mul> <One/> <Add> <One/> <One/> </Add> </Mul> </Add> Is this possible? Thanks!

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  • Build XML document using Linq To XML

    - by JasonDR
    Given the following code: string xml = ""; //alternativley: string xml = "<people />"; XDocument xDoc = null; if (!string.IsNullOrEmpty(xml)) { xDoc = XDocument.Parse(xml); xDoc.Element("people").Add( new XElement("person", "p 1") ); } else { xDoc = new XDocument(); xDoc.Add(new XElement("people", new XElement("person", "p 1") )); } As you can see, if the xml variable is blank, I need to create the rood node manually, and append the person the root node, whereas if it is not, I simple add to the people element My question is, is there any way to generically create the document, where it will add all referenced node automatically if they do not already exists?

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  • android sdk main.out.xml parsing error?

    - by mobibob
    I just started a new Android project, "WeekendStudy" to continue learning Android development and I got stumped compiling the default 'hello weekendstudy' compile / run. I think that I missed a step in configuration and setup, but I am at a loss to find out where. I have an AVD configured, set and launched. When I press 'run', the SDK is building a file main.out.xml and then fails as this: [2010-03-06 09:46:47 - WeekendStudy]Error in an XML file: aborting build. [2010-03-06 09:46:48 - WeekendStudy]res/layout/main.xml:0: error: Resource entry main is already defined. [2010-03-06 09:46:48 - WeekendStudy]res/layout/main.out.xml:0: Originally defined here. [2010-03-06 09:46:48 - WeekendStudy]/Users/mobibob/Projects/workspace-weekend/WeekendStudy/res/layout/main.out.xml:1: error: Error parsing XML: no element found [2010-03-06 09:48:16 - WeekendStudy]Error in an XML file: aborting build. [2010-03-06 09:48:16 - WeekendStudy]res/layout/main.xml:0: error: Resource entry main is already defined. [2010-03-06 09:48:16 - WeekendStudy]res/layout/main.out.xml:0: Originally defined here. [2010-03-06 09:48:16 - WeekendStudy]/Users/mobibob/Projects/workspace-weekend/WeekendStudy/res/layout/main.out.xml:1: error: Error parsing XML: no element found [2010-03-06 09:55:29 - WeekendStudy]res/layout/main.xml:0: error: Resource entry main is already defined. [2010-03-06 09:55:29 - WeekendStudy]res/layout/main.out.xml:0: Originally defined here. [2010-03-06 09:55:29 - WeekendStudy]/Users/mobibob/Projects/workspace-weekend/WeekendStudy/res/layout/main.out.xml:1: error: Error parsing XML: no element found [2010-03-06 09:55:49 - WeekendStudy]Error in an XML file: aborting build. [2010-03-06 09:55:49 - WeekendStudy]res/layout/main.xml:0: error: Resource entry main is already defined. [2010-03-06 09:55:49 - WeekendStudy]res/layout/main.out.xml:0: Originally defined here. [2010-03-06 09:55:49 - WeekendStudy]/Users/mobibob/Projects/workspace-weekend/WeekendStudy/res/layout/main.out.xml:1: error: Error parsing XML: no element found

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  • Element was not expected While Deserializing an Array with XML Serialization

    - by Anthony Shaw
    OK. I'm trying to work on communicating with the Pivotal Tracker API, which only returns data in an XML format. I have the following XML that I'm trying to deserialize into my domain model. <?xml version="1.0" encoding="UTF-8"? <stories type="array" count="2" total="2" <story <id type="integer"2909137</id <project_id type="integer"68153</project_id <story_typebug</story_type <urlhttp://www.pivotaltracker.com/story/show/2909137</url <current_stateunscheduled</current_state <description</description <nameTest #2</name <requested_byAnthony Shaw</requested_by <created_at type="datetime"2010/03/23 20:05:58 EDT</created_at <updated_at type="datetime"2010/03/23 20:05:58 EDT</updated_at </story <story <id type="integer"2909135</id <project_id type="integer"68153</project_id <story_typefeature</story_type <urlhttp://www.pivotaltracker.com/story/show/2909135</url <estimate type="integer"-1</estimate <current_stateunscheduled</current_state <description</description <nameTest #1</name <requested_byAnthony Shaw</requested_by <created_at type="datetime"2010/03/23 20:05:53 EDT</created_at <updated_at type="datetime"2010/03/23 20:05:53 EDT</updated_at </story </stories My 'story' object is created as follows: public class story { public int id { get; set; } public int estimate { get; set; } public int project_id { get; set; } public string story_type { get; set; } public string url { get; set; } public string current_state { get; set; } public string description { get; set; } public string name { get; set; } public string requested_by { get; set; } public string labels { get; set; } public string lighthouse_id { get; set; } public string lighthouse_url { get; set; } public string owned_by { get; set; } public string accepted_at { get; set; } public string created_at { get; set; } public attachment[] attachments { get; set; } public note[] notes { get; set; } } When I execute my deserialization code, I receive the following exception: Exception: There is an error in XML document (2, 2). Inner Exception: <stories xmlns='' was not expected. I can deserialize the individual stories just fine, I just cannot deserialize this xml into an array of 'story' objects And my deserialization code (value is a string of the xml) var byteArray = Encoding.ASCII.GetBytes(value); var stream = new MemoryStream(byteArray); var deserializedObject = new XmlSerializer(typeof (story[])).Deserialize(stream) Does anybody have any ideas?

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  • Convert xml as string

    - by hakish
    i have a scenario where in i need to send an xml as a tag content in a SOAP request message to a webservice for example <arg_1><xml version="1.0" encoding="UTF-8"?><sometag><somemoretag>abcd</somemoretag></sometag></arg_1></code> arg_1 happens to be an String parameter to a webservice. So i bring in a CDATA section for this <arg_1><![CDATA[<xml version="1.0" encoding="UTF-8"?><sometag><somemoretag>abcd</somemoretag></sometag>]]></arg_1> But this keeps throwing me an exception org.xml.sax.SAXException: WSWS3084E: Error: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize. Message being parsed: I keep getting this exception. Has anyone seen this before??

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  • Parsing XML in a non-XML column

    - by slugster
    Hi, i am reasonably proficient with SQLServer, but i'm not a DBA so i'm not sure how to approach this. I have an XML chunk stored in an ntext column. Due to it being a legacy database and the requirements of the project i cannot change the table (yet). This is an example of the data i need to manipulate: <XmlSerializableHashtable xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Entries> <Entry> <key xsi:type="xsd:string">CurrentYear</key><value xsi:type="xsd:string">2010</value> </Entry> <Entry> <key xsi:type="xsd:string">CurrentMonth</key><value xsi:type="xsd:string">4</value> </Entry> </Entries> </XmlSerializableHashtable> each row will have a chunk like this, but obviously with different keys/values in the XML. Is there any clever way i can parse this XML in to a name/value pairs style view? Or should i be using SQLServer's XML querying abilities even though it isn't an XML column? If so, how would i query a specific value out of that column? (Note: adding a computed XML column on the end of the table is a possibility, if that helps). Thanks for any assistance!

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  • Extract a subset of XML file using XSL

    - by Lucas -luky- Noleto
    I have this XML file: <Response> <errorCode>error Code</errorCode> <errorMessage>msg</errorMessage> <ResponseParameters> <className> <attribute1>a</attribute1> <attribute2>b</attribute2> </className> </ResponseParameters> </Response> And I want the output to be: <className> <attribute1>a</attribute1> <attribute2>b</attribute2> </className> My current XSL file is including also "ResponseParameters" tag, which I do not want. EDIT: note that the node className is dynamic. I do not know what will be this name at runtime. <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output indent="yes" /> <xsl:template match="/"> <xsl:copy-of select="//ResponseParameters"> </xsl:copy-of> </xsl:template> </xsl:stylesheet>

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  • XML Deserialization in VB/VBA

    - by oharab
    I have a set of VBA classes in an MS Access database. I have an xml string with data I want to create new classes with. Other than setting each property individually, is there an easy way to deserialize the XML into my object? I've seen the code using the TypeLib library Public Sub ISerializable_Deserialize(xml As IXMLDOMNode) Dim tTLI As TLIApplication Dim tInvoke As InvokeKinds Dim tName As String Dim tMem As MemberInfo tInvoke = VbLet For Each tMem In TLI.ClassInfoFromObject(Me).Members tName = LCase(tMem.Name) CallByName Me, tMem.Name, VbLet, xml.Attributes.getNamedItem(tName).Text Next tMem End Sub but this doesn't seem to work with the standard class modules. I get a 429 error: ActiveX Component Cannot Be Created Can anyone else help me out? I'd rather not have to set each propery by hand if I can help it, some of these classes are huge!

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  • Parsing third-party XML

    - by mare
    What path would you took to parse a large XML file (2MB - 20 MB or more), that does not have a schema (I cannot infer one with XSD.exe because the file structure is odd, check the snippet below)? Options 1) XML Deserialization (but as said, I don't have a schema and XSD tool complains about the file contents), 2) Linq to XML, 3) loading into XmlDocument, 4) Manual parsing with XmlReader & stuff. This is XML file snippet: <?xml version="1.0" encoding="utf-8"?> <xmlData date="29.04.2010 12:09:13"> <Table> <ident>079186</ident> <stock>0</stock> <pricewotax>33.94000000</pricewotax> <discountpercent>0.00000000</discountpercent> </Table> <Table> <ident>079190</ident> <stock>1</stock> <pricewotax>10.50000000</pricewotax> <discountpercent>0.00000000</discountpercent> <pricebyquantity> <Table> <quantity>5</quantity> <pricewotax>10.00000000</pricewotax> <discountpercent>0.00000000</discountpercent> </Table> <Table> <quantity>8</quantity> <pricewotax>9.00000000</pricewotax> <discountpercent>0.00000000</discountpercent> </Table> </pricebyquantity> </Table> </xmlData>

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  • can a valid xml body have escaped characters for the '<' and '>' around the element names

    - by prmatta
    My web service is receiving xml from a third party that looks like this: <SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"> <SOAP-ENV:Body> &lt;Foo&gt;bar&lt;/Foo&gt; </SOAP-ENV:Body> </SOAP-ENV:Envelope> My jaxws web service rejects this with a parsing error. Also if I try to validate this xml using soapui it says Body with element-only content type cannot have text element. My question is, is that xml valid? Or is the client supposed to send me something without escaping the < and . Any references to xml standards or rules are appreciated.

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  • Binding XML in Sliverlight without Nominal Classes

    - by AnthonyWJones
    Lets say I have a simple chunck of XML:- <root> <item forename="Fred" surname="Flintstone" /> <item forename="Barney" surname="Rubble" /> </root> Having fetched this XML in Silverlight I would like to bind it with xaml of this ilke:- <ListBox x:Name="ItemList" Style="{StaticResource Items}"> <ListBox.ItemTemplate> <DataTemplate> <StackPanel Orientation="Horizontal"> <TextBox Text="{Binding Forename}" /> <TextBox Text="{Binding Surname}" /> </StackPanel> </DataTemplate> </ListBox.ItemTemplate> </ListBox> Now I can bind simply enough with LINQ to XML and a nominal class:- public class Person { public string Forename {get; set;} public string Surname {get; set;} } So here is the question, can it be done without this class? IOW coupling between the Sliverlight code and the input XML is limited to the XAML only, other source code is agnostic to the set of attributes on the item element. Edit: The use of XSD is suggested but ultimately it amounts the same thing. XSD-Generated class. Edit: An anonymous class doesn't work, Silverlight can't bind them. Edit: This needs to be two way, the user needs to be able to edit the values and these value end up in the XML. (Changed original TextBlock to TextBox in sample above).

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  • Mutating XML in Clojure

    - by mac
    Clojures clojure.xml/parse, clojure.zip/xml-zip and clojure.contrib.zip-filter.xml/xml- are excellent tools for pulling values out of xml, but what if I want to change the xml (the result of clojure.zip/xml-zip) based on what I learn from xml- "queries" and write the result back out as xml? I would have expected that (clojure.contrib.prxml/prxml (clojure.xml/parse xml-content)) spit back xml, but that is not the case.

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  • LINQ to XML via C#

    - by user70192
    Hello, I'm new to LINQ. I understand it's purpose. But I can't quite figure it out. I have an XML set that looks like the following: <Results> <Result> <ID>1</ID> <Name>John Smith</Name> <EmailAddress>[email protected]</EmailAddress> </Result> <Result> <ID>2</ID> <Name>Bill Young</Name> <EmailAddress>[email protected]</EmailAddress> </Result> </Results> I have loaded this XML into an XDocument as such: string xmlText = GetXML(); XDocument xml = XDocument.Parse(xmlText); Now, I'm trying to get the results into POCO format. In an effort to do this, I'm currently using: var objects = from results in xml.Descendants("Results") select new Results // I'm stuck How do I get a collection of Result elements via LINQ? I'm particularly confused about navigating the XML structure at this point in my code. Thank you!

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  • Parsing JSON into XML using Windows Phone

    - by Henry Edwards
    I have this code, but can't get it all working. I am trying to get a json string into xml. So that I can get a list of items when i parse the data. Is there a better way to parse json into xml. If so what's the best way to do it, and if possible could you give me a working example? The URL that is in the code is not the URL that i am using using System; using System.Collections.Generic; using System.Linq; using System.Net; using System.Windows; using System.Windows.Controls; using System.Windows.Documents; using System.Windows.Input; using System.Windows.Media; using System.Windows.Media.Animation; using System.Windows.Shapes; using Microsoft.Phone.Controls; using Newtonsoft.Json; using Newtonsoft.Json.Serialization; using Newtonsoft.Json.Converters; using Newtonsoft.Json.Utilities; using Newtonsoft.Json.Linq; using Newtonsoft.Json.Schema; using Newtonsoft.Json.Bson; using System.Xml; using System.Xml.Serialization; using System.Xml.Linq; using System.Xml.Linq.XDocument; using System.IO; namespace WindowsPhonePanoramaApplication3 { public partial class Page2 : PhoneApplicationPage { public Page2() { InitializeComponent(); } private void Form1_Load(object sender, EventArgs e1) { /* because the origional JSON string has multiple root's this needs to be added */ string json = "{BFBC2_GlobalStats:"; json += DownlodUrl("http://api.bfbcs.com/api/xbox360?globalstats"); json += "}"; XmlDocument doc = (XmlDocument)JsonConvert.DeserializeObject(json); textBox1.Text = GetXmlString(doc); } private string GetXmlString() { throw new NotImplementedException(); } private string DownlodUrl(string url) { string result = null; try { WebClient client = new WebClient(); result = client.DownloadString(url); } catch (Exception ex) { // handle error result = ex.Message; } return result; } private string GetXmlString(XmlDocument xmlDoc) { sw = new StringWriter(); XmlTextWriter xw = new XmlTextWriter(sw); xw.Formatting = System.Xml.Formatting.Indented; xmlDoc.WriteTo(xw); return sw.ToString(); } } } The URL outputs the following code: {"StopName":"Race Hill", "stopId":7553, "NaptanCode":"bridwja", "LongName":"Race Hill", "OperatorsCode1":" 5", "OperatorsCode2":" ", "OperatorsCode3":" ", "OperatorsCode4":"bridwja", "Departures":[ { "ServiceName":"", "Destination":"", "DepartureTimeAsString":"", "DepartureTime":"30/01/2012 00:00:00", "Notes":""}` Thanks for your responses. So Should i just leave the data a json and then view the data via that??? Is this a way to show the data from a json string. public void Load() { // form the URI UriBuilder uri = new UriBuilder("http://mysite.com/events.json"); WebClient proxy = new WebClient(); proxy.OpenReadCompleted += new OpenReadCompletedEventHandler(OnReadCompleted); proxy.OpenReadAsync(uri.Uri); } void OnReadCompleted(object sender, OpenReadCompletedEventArgs e) { if (e.Error == null) { var serializer = new DataContractJsonSerializer(typeof(EventList)); var events = (EventList)serializer.ReadObject(e.Result); foreach (var ev in events) { Items.Add(ev); } } } public ObservableCollection<EventDetails> Items { get; private set; } Edit: Have now kept the url as json and have now got it working by using the json way.

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