Search Results

Search found 3804 results on 153 pages for 'regex'.

Page 80/153 | < Previous Page | 76 77 78 79 80 81 82 83 84 85 86 87  | Next Page >

  • Get Specific part of a String in Javascript

    - by streetparade
    I have a string containing something like this "Hello bla bla bla bla ok, once more bla können. // this is static: it doesn't change This is a text, this also a text. // this is dynamically added text it can change each time My name mysurename // this is also static text www.blabla.com " Now I have content and I have to get the first part of the string and the third part, I want to be able to have 3 parts, I think I have to split it using something like split(); string1 = "Hello bla bla bla bla ok, once more bla können.; string2 = ""; // i have this part string3 ="My name mysurename"; If it helps the first part ends with "können. " and the third part ends with the url above // its a fictional URL

    Read the article

  • How can I use a regular expression to match something in the form 'stuff=foo' 'stuff' = 'stuff' 'mor

    - by PherricOxide
    I need a regexp to match something like this, 'text' | 'text' | ... | 'text'(~text) = 'text' | 'text' | ... | 'text' I just want to divide it up into two sections, the part on the left of the equals sign and the part on the right. Any of the 'text' entries can have "=" between the ' characters though. I was thinking of trying to match an even number of 's followed by a =, but I'm not sure how to match an even number of something.. Also note I don't know how many entries on either side there could be. A couple examples, '51NL9637X33' | 'ISL6262ACRZ-T' | 'QFN'(~51NL9637X33) = '51NL9637X33' | 'ISL6262ACRZ-T' | 'INTERSIL' | 'QFN7SQ-HT1_P49' | '()' Should extract, '51NL9637X33' | 'ISL6262ACRZ-T' | 'QFN'(~51NL9637X33) and, '51NL9637X33' | 'ISL6262ACRZ-T' | 'INTERSIL' | 'QFN7SQ-HT1_P49' | '()' '227637' | 'SMTU2032_1' | 'SKT W/BAT'(~227637) = '227637' | 'SMTU2032_1' | 'RENATA' | 'SKT28_5X16_1-HT5_4_P2' | '()' :SPECIAL_A ='BAT_CR2032', PART_NUM_A='202649' Should extract, '227637' | 'SMTU2032_1' | 'SKT W/BAT'(~227637) and, '227637' | 'SMTU2032_1' | 'RENATA' | 'SKT28_5X16_1-HT5_4_P2' | '()' :SPECIAL_A ='BAT_CR2032', PART_NUM_A='202649' Also note the little tilda bit at the end of the first section is optional, so I can't just look for that.

    Read the article

  • MySQL REGEXP: matching blank entries

    - by Erwin Paglinawan
    Hi, I have this SQL condition that is supposed to retrieve all rows that satisfy the given regexp condition: country REGEXP ('^(USA|Italy|France)$') However, I need to add a pattern for retrieving all blank country values. Currently I am using this condition country REGEXP ('^(USA|Italy|France)$') OR country = "" How can achieve the same effect without having to include the OR clause? Thanks, Erwin

    Read the article

  • regular expression or replace function in where clause of a mysql query.

    - by Salil
    Hi All, I write a mysql query select * from table where name like '%salil%' which works fine but it will no return records with name 'sal-il', 'sa@lil'. So i want a query something like below select * from table where remove_special_character_from(name) like '%salil%' remove_special_character_from(name) is a mysql method or a regular expression which remove all the special characters from name before like executed.

    Read the article

  • preg_replace to capitalize a letter after a quote

    - by Summer
    I have names like this: $str = 'JAMES "JIMMY" SMITH' I run strtolower, then ucwords, which returns this: $proper_str = 'James "jimmy" Smith' I'd like to capitalize the second letter of words in which the first letter is a double quote. Here's the regexp. It appears strtoupper is not working - the regexp simply returns the unchanged original expression. $proper_str = preg_replace('/"([a-z])/',strtoupper('$1'),$proper_str); Any clues? Thanks!!

    Read the article

  • Converting John Resig's JavaScript Templating Engine to work with PHP Templates

    - by Serhiy
    I'm trying to convert the John Resig's Templating Engine to work with PHP. Essentially what I would like to achieve is the ability to use certain Kohana Views via a JavaScript templating engine, that way I can use the same views for both a standard PHP request and a jQuery AJAX request. I'm starting with the basics and would like to be able to convert http://github.com/nje/jquery-tmpl/blob/master/jquery.tmpl.js To work with php like so... ### From This ### <li><a href="{%= link %}">{%= title %}</a> - {%= description %}</li> ### Into This ### <li><a href="<?= $link ?>"><?= $title ?></a> - <?= description ?></li> The RexEx in it is a bit over my head and it's apparently not as easy as changing the %} to ? in lines 148 to 158. Any help would be highly appreciated. I'm also not sure of how to take care of the $ difference that PHP variables have. Thanks, Serhiy

    Read the article

  • PHP email validation question?

    - by GeNx
    Will this email validation allow foreign email address like russian, hebrew and so on? And how can I just check for the @ sign? Here is the php code. if (preg_match ('/^[\w.-]+@[\w.-]+\.[A-Za-z]{2,6}$/', $_POST['email'])) { $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); } else { echo '<p class="error">Please enter a valid email address!</p>'; }

    Read the article

  • Changing input name attribute

    - by Parhs
    Hello! I have some hidden inputs like this <input name="exam.normals[1].blahblah" ..../> I would like somehow to replace the [1] with a number that I want (index). I aint lazy but I am trying to find a good way to do this... A solution would be a replace of exam.normals[1] with exam.normals[+ index +] but I should substr the whole string first.... With regexp I don’t know how to do the replace. good...

    Read the article

  • django urls.py regex isn't working

    - by Phil
    This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

    Read the article

  • case-insensitive regexp match on non-english text in perl cgi script

    - by jonny
    ok. I have list of catalog paths and need to filter out some of them. Match pattern comes in non-Unicode encoding. Tried following: require 5.004; use POSIX qw(locale_h); my $old_locale = setlocale(LC_ALL); setlocale(LC_ALL, "ru_RU.cp1251"); @{$data -> {doc_folder_rights}} = grep { $_->{doc_folder} =~/$_REQUEST{q}/i; # catalog path pattern in $_REQUEST{q} } @{$data -> {doc_folder_rights}}; setlocale(LC_ALL, $old_locale); What I need is case-insensitive regexp pattern matching when pattern contains russsian letters.

    Read the article

  • Regular Expression for any number divisible by 60 using C# .Net ?

    - by Steve Johnson
    Hi there, I need to apply validation on input time intervals that are taken in as seconds. Now i am not really good at Regular expressions. So can any body help making a regular expression that can test whether a number is divisible by 60. I was wondering if i could use to test one that check that the number is divisible by 10 and then check whether the same is divisible by 6. For number divisible by 10 here [\d*0] is the expression i guess. Please correct me if i am wrong. Hope somebody solves my problem. Thanks

    Read the article

  • Regular expression for checking website url

    - by Linto davis
    I need to check the web address, using regular expression. if user type url as www.test.com http://www.test.com https://www.test.com i have a regular expression like /^(http\:\/\/[a-zA-Z0-9_-]+(?:.[a-zA-Z0-9_-]+)*.[a-zA-Z]{2,4}(?:\/[a-zA-Z0-9_]+)*(?:\/[a-zA-Z0-9_]+.[a-zA-Z]{2,4}(?:\?[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)?)?(?:\&[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)*)$/ but it will only allow the second option only. how can i modify the regular expression so that , it should accept 1st and 3rd option too

    Read the article

  • PHP Key name array

    - by Sean McRaghty
    I have an array $data fruit => apple, seat => sofa, etc. I want to loop through so that each key becomes type_key[0]['value'] so eg type_fruit[0]['value'] => apple, type_seat[0]['value'] => sofa, and what I thought would do this, namely foreach ($data as $key => $value) { # Create a new, renamed, key. $array[str_replace("/(.+)/", "type_$1[0]['value']", $key)] = $value; # Destroy the old key/value pair unset($array[$key]); } print_r($array); Doesn't work. How can I make it work? Also, I want everything to be in the keys (not the values) to be lowercase: is there an easy way of doing this too? Thanks.

    Read the article

  • Splitting a string according to a delimiter when elements in the string can contain the delimiter

    - by Vivin Paliath
    I have a string that looks like this: "#Text() #SomeMoreText() #TextThatContainsDelimiter(#blah) #SomethingElse()" I'd like to get back [#Text(), #SomeMoreText(), #TextThatContainsDelimiter(#blah), #SomethingElse()] One way I thought about doing this was to require that the # to be escaped into \#, which makes the input string: "#Text() #SomeMoreText() #TextThatContainsDelimiter(\#blah) #SomethingElse()" I can then split it using /[^\\]#/ which gives me: [#Text(), SomeMoreText, TextThatContainsDelimiter(\#blah), SomethingElse()] The first element will contain # but I can strip it out. However, is there a cleaner way to do this without having to escape the #, and which ensures that the first element will not contain a #? Basically I'd like it to split by # only if the # is not enclosed by parentheses. My hunch is that since the # is context-sensitive and and regular expressions are only suited for context-free strings, this may not be the right tool. If so, would I have to write a grammar for this and roll my own parser/lexer?

    Read the article

  • perl escaping \n or \t

    - by Michael
    I need to escape \n so on output I really get newline or tab $ perl -p -e 's/e/a/ge' now I want each e to be substituted with \n $ perl -p -e 's/e/\n/ge' but even \n gives me an error. this was a simplified example. In real script(makefile) I have substitute := perl -p -e 's/@([^@]+)@/defined $$ENV{$$1} ? $$ENV{$$1} : $$1/ge' and in target I have such a nice command $(substitute) $< > $@ and if the input file for perl contains \n at output I will see it literally... I want to have real newline.

    Read the article

  • rename files with the same name

    - by snorpey
    Hi. I use the following function to rename thumbnails. For example, if I upload a file called "image.png" to an upload folder, and this folder already has a file named "image.png" in it, the new file automatically gets renamed to "image-copy-1.png". If there also is a file called "image-copy-1.png" it gets renamed to "image-copy-2.png" and so on. The following function returns the new filename. At least that's what it is supposed to do... The renaming doesn't seeem to work correctly, though. Sometimes it produces strange results, like: 1.png 1-copy-1.png 1-copy-2.png 1-copy-2-copy-1.png 1-copy-2-copy-3.png I hope you understand my problem, despite my description being somewhat complex... Can you tell me what went wrong here? (bonus question: Is regular expressions the right tool for doing this kind of stuff?) <?php function renameDuplicates($path, $file) { $fileName = pathinfo($path . $file, PATHINFO_FILENAME); $fileExtension = "." . pathinfo($path . $file, PATHINFO_EXTENSION); if(file_exists($path . $file)) { $fileCopy = $fileName . "-copy-1"; if(file_exists($path . $fileCopy . $fileExtension)) { if ($contains = preg_match_all ("/.*?(copy)(-)(\\d+)/is", $fileCopy, $matches)) { $copyIndex = $matches[3][0]; $fileName = substr($fileCopy, 0, -(strlen("-copy-" . $copyIndex))) . "-copy-" . ($copyIndex + 1); } } else { $fileName .= "-copy-1"; } } $returnValue = $fileName . $fileExtension; return $returnValue; }?>

    Read the article

  • Regular expressions and the question mark

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions?

    Read the article

  • Wanted: a very simple java RegExp API

    - by itsadok
    I'm tired of writing Pattern p = Pattern.compile(... Matcher m = p.matcher(str); if (m.find()) { ... Over and over again in my code. I was going to write a helper class to make it neater, but I then I wondered: is there a library that tries to provide a simpler facade for Regular Expressions in Java? I'm thinking something in the style of commons-lang and Guava.

    Read the article

  • Parse string with bash and extract number

    - by cleg
    Hello I've got supervisor's status output, looking like this. frontend RUNNING pid 16652, uptime 2:11:17 nginx RUNNING pid 16651, uptime 2:11:17 redis RUNNING pid 16607, uptime 2:11:32 I need to extract nginx's PID. I've done it via grep -P command, but on remote machine grep is build without perl regular expression support. Looks like sed or awk is exactly what I need, but I don't familiar with them. Please help me to find a way how to do it, thanks in advance.

    Read the article

< Previous Page | 76 77 78 79 80 81 82 83 84 85 86 87  | Next Page >