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  • Mysql return value as 0 in the fetch result.

    - by Karthik
    I have this two tables, -- -- Table structure for table `t1` -- CREATE TABLE `t1` ( `pid` varchar(20) collate latin1_general_ci NOT NULL, `pname` varchar(20) collate latin1_general_ci NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci; -- -- Dumping data for table `t1` -- INSERT INTO `t1` VALUES ('p1', 'pro1'); INSERT INTO `t1` VALUES ('p2', 'pro2'); -- -------------------------------------------------------- -- -- Table structure for table `t2` -- CREATE TABLE `t2` ( `pid` varchar(20) collate latin1_general_ci NOT NULL, `year` int(6) NOT NULL, `price` int(3) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci; -- -- Dumping data for table `t2` -- INSERT INTO `t2` VALUES ('p1', 2009, 50); INSERT INTO `t2` VALUES ('p1', 2010, 60); INSERT INTO `t2` VALUES ('p3', 2007, 200); INSERT INTO `t2` VALUES ('p4', 2008, 501); my query is, SELECT * FROM `t1` LEFT JOIN `t2` ON t1.pid = t2.pid Getting the result, pid pname pid year price p1 pro1 p1 2009 50 p1 pro1 p1 2010 60 p2 pro2 NULL NULL NULL My question is, i want to get the price value is 0 instead of NULL. How can i write the query to getting the price value is 0. Thanks in advance for help.

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  • How do I return the entire set / array using NSPredicate?

    - by Prairiedogg
    I'm building a carArray and want to filter the contents conditionally, using an NSPredicate, like so: NSPredicate *pred; switch (carType) { case FreeCar: pred = [NSPredicate predicateWithFormat:@"premium = NO"]; break; case PremiumCar: pred = [NSPredicate predicateWithFormat:@"premium = YES"]; break; default: pred = [NSPredicate predicateWithFormat:@"SOME PREDICATE THAT RETURNS EVERYTHING"]; break; } self.carArray = [aCarArrayIGotFromSomewhere filteredArrayUsingPredicate:pred]; My question is, what is the correct syntax for the value I've stubbed in as SOME PREDICATE THAT RETURNS EVERYTHING which returns all of the instances in the array / set? PS - I know the answer and will post it immediately, just sharing it for everyone's reference as an earlier search on SO did not yield the result.

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  • PHP Modify the return of a loop over and over.

    - by Joshua Anderson
    Basically I want to do a php loop that base64_encodes its self 5 times. //For example i want to encode "test" which is "dGVzdA==" then we encode "dGVzdA==" which is "ZEdWemRBPT0=" then encode "ZEdWemRBPT0=" which is "WkVkV2VtUkJQVDA9" I can't figure out how to create a loop that modifies its self each time it runs. // this is what i had function enloop($dowork){ for ($i=1; $i&lt;=5; $i++) { returns base64_encode($dowork); } } enloop($code); //THIS SCRIPT DOES THIS Repeats the encode 5 times, lets say your encodign the word test for example the output would be dGVzdA==dGVzdA==dGVzdA==dGVzdA==dGVzdA==

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  • How can I return a link to an active state after mouseout?

    - by Craig
    var menuEnter = { 'color': hoverColor}; var menuLeave = { 'color': 'C0C0C0'}; new ('div#menu a.level1 span.bg', menuEnter, menuLeave, { transition: Fx.Transitions.linear, duration: 200 }, { transition: Fx.Transitions.sineIn, duration: 500 }); I would like the active menu color to not be affected by the mouseleave var. Thank you.

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  • SQL query to return data from two separate rows in a table joined to a master table

    - by Ali
    I have a TWO tables of data with following fields table1=(ITTAG,ITCODE,ITDESC,SUPcode) table2=(ACCODE,ACNAME,ROUTE,SALMAN) This is my customer master table that contains my customer data such as customer code, customer name and so on... Every Route has a supervisor (table1=supcode) and I need to know the supervisor name in my table which both supervisor name and code exist in one table. table1 has contain all names separated by ITTAG. For example, supervisor's name has ITTAG='K'; also salesman's name has ITTAG='S'. ITTAG ITCODE ITDESC SUPCODE ------ ------ ------ ------- S JT JOHN TOMAS TF K WK VIKI KOO NULL Now this is the result which I want ACCODE ACNAME ROUTE SALEMANNAME SUPERVISORNAME ------- ------ ------ ------------ --------------- IMC1010 ABC HOTEL 01 JOHN TOMAS VIKI KOO I hope this this information is sufficient to get the query..

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  • How to make Nokogiri transparently return un/encoded Html entities untouched?

    - by svenfuchs
    How can I use Nokogiri with having html entities (like German umlauts) untouched? I.e.: # this is fine node = Nokogiri::HTML.fragment('<p>&ouml;</p>') node.to_s # => '<p>&ouml;</p>' # this is not node = Nokogiri::HTML.fragment('<p>ö</p>') node.to_s # => '<p>&ouml;</p>' # this is what I need node = Nokogiri::HTML.fragment('<p>ö</p>') node.to_s # => '<p>ö</p>' I've tried to mess with both PARSE_OPTIONS and :save_with options but could not come up with a way to have Nokogiri just transparently behave like above. Any pointers?

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  • Is it valid for Hibernate list() to return duplicates?

    - by skaffman
    Is anyone aware of the validity of Hibernate's Criteria.list() and Query.list() methods returning multiple occurrences of the same entity? Occasionally I find when using the Criteria API, that changing the default fetch strategy in my class mapping definition (from "select" to "join") can sometimes affect how many references to the same entity can appear in the resulting output of list(), and I'm unsure whether to treat this as a bug or not. The javadoc does not define it, it simply says "The list of matched query results." (thanks guys). If this is expected and normal behaviour, then I can de-dup the list myself, that's not a problem, but if it's a bug, then I would prefer to avoid it, rather than de-dup the results and try to ignore it. Anyone got any experience of this?

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  • How do I return specific keys from the $_POST array?

    - by Brook
    I would like to check to see if there are any keys in $_POST that contain a string. The string will not be the full key, only part of the key. (ie. search string = "delRowID", $_POST key = "delRowID_16"). I have tried to use array_keys($_POST,"delRowID"), but it has never returned anything. CODE print_r($_POST); print_r(array_keys($_POST,"delRowID")); RETURNS Array ( [delRowID] => 29 [qAction] => [elmUpdateId] => [elmTtl] => [elmDesc] => [elmStr] => ) Array ( )

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  • How can I make a Yes/No combobox return true/false?

    - by Kasper Hansen
    I am new to creating forms in Visual Studio and C#. But I made a UI that has some comboboxes where the DropDownStyle is DropDownList. The items shown is Yes and No. But I need to assign this as a boolean value to a property on some object ai and currently do this: if (cmbExample.Text == "Yes") { ai.isPacketType = true; } else if (cmbExample.Text == "No") { ai.isPacketType = false; } I basically want to do something like this (or some other one liner): ai.isPacketType = cmbExample.Text; How do I link the Text Yes to the value true and No to false?

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  • Query XML file with PHP to return certain bookmarks...

    - by josh brown
    I have an XML file full of bookmarks from Google Bookmarks. (File: http://gist.github.com/324844) I want to pull the bookmark based on this path: xml_api_reply-bookmarks-bookmark-labels-label. So, my question is How can I use SimpleXML to grab the bookmarks that have the label Inspiration? Some bookmarks may have more than one bookmark.

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  • Convert Java program to C

    - by imicrothinking
    I need a bit of guidance with writing a C program...a bit of quick background as to my level, I've programmed in Java previously, but this is my first time programming in C, and we've been tasked to translate a word count program from Java to C that consists of the following: Read a file from memory Count the words in the file For each occurrence of a unique word, keep a word counter variable Print out the top ten most frequent words and their corresponding occurrences Here's the source program in Java: package lab0; import java.io.File; import java.io.FileReader; import java.util.ArrayList; import java.util.Calendar; import java.util.Collections; public class WordCount { private ArrayList<WordCountNode> outputlist = null; public WordCount(){ this.outputlist = new ArrayList<WordCountNode>(); } /** * Read the file into memory. * * @param filename name of the file. * @return content of the file. * @throws Exception if the file is too large or other file related exception. */ public char[] readFile(String filename) throws Exception{ char [] result = null; File file = new File(filename); long size = file.length(); if (size > Integer.MAX_VALUE){ throw new Exception("File is too large"); } result = new char[(int)size]; FileReader reader = new FileReader(file); int len, offset = 0, size2read = (int)size; while(size2read > 0){ len = reader.read(result, offset, size2read); if(len == -1) break; size2read -= len; offset += len; } return result; } /** * Make article word by word. * * @param article the content of file to be counted. * @return string contains only letters and "'". */ private enum SPLIT_STATE {IN_WORD, NOT_IN_WORD}; /** * Go through article, find all the words and add to output list * with their count. * * @param article the content of the file to be counted. * @return words in the file and their counts. */ public ArrayList<WordCountNode> countWords(char[] article){ SPLIT_STATE state = SPLIT_STATE.NOT_IN_WORD; if(null == article) return null; char curr_ltr; int curr_start = 0; for(int i = 0; i < article.length; i++){ curr_ltr = Character.toUpperCase( article[i]); if(state == SPLIT_STATE.IN_WORD){ article[i] = curr_ltr; if ((curr_ltr < 'A' || curr_ltr > 'Z') && curr_ltr != '\'') { article[i] = ' '; //printf("\nthe word is %s\n\n",curr_start); if(i - curr_start < 0){ System.out.println("i = " + i + " curr_start = " + curr_start); } addWord(new String(article, curr_start, i-curr_start)); state = SPLIT_STATE.NOT_IN_WORD; } }else{ if (curr_ltr >= 'A' && curr_ltr <= 'Z') { curr_start = i; article[i] = curr_ltr; state = SPLIT_STATE.IN_WORD; } } } return outputlist; } /** * Add the word to output list. */ public void addWord(String word){ int pos = dobsearch(word); if(pos >= outputlist.size()){ outputlist.add(new WordCountNode(1L, word)); }else{ WordCountNode tmp = outputlist.get(pos); if(tmp.getWord().compareTo(word) == 0){ tmp.setCount(tmp.getCount() + 1); }else{ outputlist.add(pos, new WordCountNode(1L, word)); } } } /** * Search the output list and return the position to put word. * @param word is the word to be put into output list. * @return position in the output list to insert the word. */ public int dobsearch(String word){ int cmp, high = outputlist.size(), low = -1, next; // Binary search the array to find the key while (high - low > 1) { next = (high + low) / 2; // all in upper case cmp = word.compareTo((outputlist.get(next)).getWord()); if (cmp == 0) return next; else if (cmp < 0) high = next; else low = next; } return high; } public static void main(String args[]){ // handle input if (args.length == 0){ System.out.println("USAGE: WordCount <filename> [Top # of results to display]\n"); System.exit(1); } String filename = args[0]; int dispnum; try{ dispnum = Integer.parseInt(args[1]); }catch(Exception e){ dispnum = 10; } long start_time = Calendar.getInstance().getTimeInMillis(); WordCount wordcount = new WordCount(); System.out.println("Wordcount: Running..."); // read file char[] input = null; try { input = wordcount.readFile(filename); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); System.exit(1); } // count all word ArrayList<WordCountNode> result = wordcount.countWords(input); long end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordcount: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); System.out.println("wordsort: running ..."); start_time = Calendar.getInstance().getTimeInMillis(); Collections.sort(result); end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordsort: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); Collections.reverse(result); System.out.println("\nresults (TOP "+ dispnum +" from "+ result.size() +"):\n" ); // print out result String str ; for (int i = 0; i < result.size() && i < dispnum; i++){ if(result.get(i).getWord().length() > 15) str = result.get(i).getWord().substring(0, 14); else str = result.get(i).getWord(); System.out.println(str + " - " + result.get(i).getCount()); } } public class WordCountNode implements Comparable{ private String word; private long count; public WordCountNode(long count, String word){ this.count = count; this.word = word; } public String getWord() { return word; } public void setWord(String word) { this.word = word; } public long getCount() { return count; } public void setCount(long count) { this.count = count; } public int compareTo(Object arg0) { // TODO Auto-generated method stub WordCountNode obj = (WordCountNode)arg0; if( count - obj.getCount() < 0) return -1; else if( count - obj.getCount() == 0) return 0; else return 1; } } } Here's my attempt (so far) in C: #include <stdio.h> #include <stdlib.h> #include <stdbool.h> #include <string.h> // Read in a file FILE *readFile (char filename[]) { FILE *inputFile; inputFile = fopen (filename, "r"); if (inputFile == NULL) { printf ("File could not be opened.\n"); exit (EXIT_FAILURE); } return inputFile; } // Return number of words in an array int wordCount (FILE *filePointer, char filename[]) {//, char *words[]) { // count words int count = 0; char temp; while ((temp = getc(filePointer)) != EOF) { //printf ("%c", temp); if ((temp == ' ' || temp == '\n') && (temp != '\'')) count++; } count += 1; // counting method uses space AFTER last character in word - the last space // of the last character isn't counted - off by one error // close file fclose (filePointer); return count; } // Print out the frequencies of the 10 most frequent words in the console int main (int argc, char *argv[]) { /* Step 1: Read in file and check for errors */ FILE *filePointer; filePointer = readFile (argv[1]); /* Step 2: Do a word count to prep for array size */ int count = wordCount (filePointer, argv[1]); printf ("Number of words is: %i\n", count); /* Step 3: Create a 2D array to store words in the file */ // open file to reset marker to beginning of file filePointer = fopen (argv[1], "r"); // store words in character array (each element in array = consecutive word) char allWords[count][100]; // 100 is an arbitrary size - max length of word int i,j; char temp; for (i = 0; i < count; i++) { for (j = 0; j < 100; j++) { // labels are used with goto statements, not loops in C temp = getc(filePointer); if ((temp == ' ' || temp == '\n' || temp == EOF) && (temp != '\'') ) { allWords[i][j] = '\0'; break; } else { allWords[i][j] = temp; } printf ("%c", allWords[i][j]); } printf ("\n"); } // close file fclose (filePointer); /* Step 4: Use a simple selection sort algorithm to sort 2D char array */ // PStep 1: Compare two char arrays, and if // (a) c1 > c2, return 2 // (b) c1 == c2, return 1 // (c) c1 < c2, return 0 qsort(allWords, count, sizeof(char[][]), pstrcmp); /* int k = 0, l = 0, m = 0; char currentMax, comparedElement; int max; // the largest element in the current 2D array int elementToSort = 0; // elementToSort determines the element to swap with starting from the left // Outer a iterates through number of swaps needed for (k = 0; k < count - 1; k++) { // times of swaps max = k; // max element set to k // Inner b iterates through successive elements to fish out the largest element for (m = k + 1; m < count - k; m++) { currentMax = allWords[k][l]; comparedElement = allWords[m][l]; // Inner c iterates through successive chars to set the max vars to the largest for (l = 0; (currentMax != '\0' || comparedElement != '\0'); l++) { if (currentMax > comparedElement) break; else if (currentMax < comparedElement) { max = m; currentMax = allWords[m][l]; break; } else if (currentMax == comparedElement) continue; } } // After max (count and string) is determined, perform swap with temp variable char swapTemp[1][20]; int y = 0; do { swapTemp[0][y] = allWords[elementToSort][y]; allWords[elementToSort][y] = allWords[max][y]; allWords[max][y] = swapTemp[0][y]; } while (swapTemp[0][y++] != '\0'); elementToSort++; } */ int a, b; for (a = 0; a < count; a++) { for (b = 0; (temp = allWords[a][b]) != '\0'; b++) { printf ("%c", temp); } printf ("\n"); } // Copy rows to different array and print results /* char arrayCopy [count][20]; int ac, ad; char tempa; for (ac = 0; ac < count; ac++) { for (ad = 0; (tempa = allWords[ac][ad]) != '\0'; ad++) { arrayCopy[ac][ad] = tempa; printf("%c", arrayCopy[ac][ad]); } printf("\n"); } */ /* Step 5: Create two additional arrays: (a) One in which each element contains unique words from char array (b) One which holds the count for the corresponding word in the other array */ /* Step 6: Sort the count array in decreasing order, and print the corresponding array element as well as word count in the console */ return 0; } // Perform housekeeping tasks like freeing up memory and closing file I'm really stuck on the selection sort algorithm. I'm currently using 2D arrays to represent strings, and that worked out fine, but when it came to sorting, using three level nested loops didn't seem to work, I tried to use qsort instead, but I don't fully understand that function as well. Constructive feedback and criticism greatly welcome (...and needed)!

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  • Best way to return a user-generated file, AJAX or Forms?

    - by Bill Zimmerman
    Hi, I'm new to web programming, so I need some help. I am writing a custom file-creation app for my site. A user visits the page, clicks on some various options and toggles some checkboxes, and the presses a 'download now' link. I have a PHP backend which will be processing the submission, and generating a PDF file. After the user presses the download link, I want the download to start like it would for any static link. My question is: What is the best way to do this? From my limited understanding, I have a choice between using AJAX or somehow using forms to submit the data. What are the advantages/disadvantages of each? Does anyone have any good links to examples? Thanks

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  • [Django] Change state of obiects

    - by gameboy
    hi I have following problem. I have model: class Towar(models.Model): nrSeryjny=models.CharField(max_length=100) opis=models.CharField(max_length=255) naStanie=models.NullBooleanField(null=True) def __unicode__(self): return "%s" % self.opis def lowerName(self): return self.__class__.__name__.lower() def checkState(self): return self.naStanie def changeState(self,state): self.naStanie=state class Meta: ordering=['nrSeryjny'] app_label = 'baza' permissions=(("view_towar","mozna miec podglad dla towar"),) and model : class Wypozyczenie(models.Model): dataPobrania=models.DateField() pracownik=models.ForeignKey(User,null=True) kontrahent=models.ForeignKey(Kontrahenci,null=True) towar=models.ForeignKey(Towar,null=True) objects=WypozyczenieManager() default_objects=models.Manager() ZwrotyObjects=WypozyczenieZwrotyManager() def lowerName(self): return self.__class__.__name__.lower() def __unicode__(self): if self.towar == None: return "Dla:%s -- Kto:%s -- Kiedy:%s -- Co:%s" % (self.kontrahent,self.pracownik,self.dataPobrania,"Brak") else: return "Dla:%s -- Kto:%s -- Kiedy:%s -- Co:%s" % (self.kontrahent,self.pracownik,self.dataPobrania,self.towar) class Meta: ordering=['dataPobrania'] app_label = 'baza' permissions=(("view_wypozyczenie","mozna miec podglad dla wypozyczenie"),) and view to adding models: def modelAdd(request,model,modelForm): mod=model() if request.user.has_perm('baza.add_%s' % mod.lowerName()): if request.method=='POST': form=modelForm(request.POST) if form.is_valid(): form.save() return HttpResponseRedirect('/'+ mod.lowerName() + '/') else: form=modelForm() v=RequestContext(request,{'form':form}) return render_to_response('add_form.html',v) and i whant do that, when i add Wypozyczenie and save it then the Towar that is stored by Wypozyczenie change his na stanie from True to False Greets

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  • How to implement rank structure

    - by Luke101
    What is the best way to implement a rank system: here is the code i will use public class MyRank { private int LevelOneMaxPoints = 100; private int LevelTwoMinPoints = 200; private int LevelTwoMaxPoints = 299; private int LevelThreeMinPoints = 300; private int LevelThreeMaxPoints = 399; private int LevelFourMinPoints = 400; private int LevelFourMaxPoints = 599; private int LevelFourPlusMinPoints = 600; private int LevelFourPlusMaxPoints = 999; private int LevelFiveMinPoints = 1000; private int LevelFiveMaxPoints = 1299; private int LevelSixMinPoints = 1300; private int LevelSixMaxPoints = 2699; private int LevelSevenMinPoints = 2700; private int LevelSevenMaxPoints = 3999; private int LevelEightMinPoints = 4000; private int LevelEightMaxPoints = 5499; private int LevelEightPlusMinPoints = 5500; private int LevelEightPlusMaxPoints = 7499; private int LevelNineMinPoints = 7500; private int LevelNineMaxPoints = 9999; private int LevelTenMinPoints = 10000; private string LevelOneName = "Private"; private string LevelTwoName = "PV2"; private string LevelThreeName = "Private Fist Class"; private string LevelFourName = "Specialist"; private string LevelFourPlusName = "Corporal"; private string LevelFiveName = "Sergeant"; //private string LevelSixName = "Staff Sergeant"; private string LevelSevenName = "Sergeant First Class"; private string LevelEightName = "Master Sergeant"; private string LevelEightPlusName = "First Sergeant"; private string LevelNineName = "Sergeant Major"; //private string LevelTenName = "Sergeant Major of the Answers"; private int points = 0; public string RankName { get; private set; } public MyRank(int points) { this.points = points; RankName = GetRankName(); } private string GetRankName() { if (points >= Int32.MinValue && points <= LevelOneMaxPoints) return LevelOneName; else if (points >= LevelTwoMinPoints && points <= LevelTwoMaxPoints) return LevelTwoName; else if (points >= LevelThreeMinPoints && points <= LevelThreeMaxPoints) return LevelThreeName; else if (points >= LevelFourMinPoints && points <= LevelFourMaxPoints) return LevelFourName; else if (points >= LevelFourPlusMinPoints && points <= LevelFourPlusMaxPoints) return LevelFourPlusName; else if (points >= LevelFiveMinPoints && points <= LevelFiveMaxPoints) return LevelFiveName; else if (points >= LevelSixMinPoints && points <= LevelSixMaxPoints) return LevelFiveName; else if (points >= LevelSevenMinPoints && points <= LevelSevenMaxPoints) return LevelSevenName; else if (points >= LevelEightMinPoints && points <= LevelEightMaxPoints) return LevelEightName; else if (points >= LevelEightPlusMinPoints && points <= LevelEightPlusMaxPoints) return LevelEightPlusName; else if (points >= LevelNineMinPoints && points <= LevelNineMaxPoints) return LevelNineName; else if (points >= LevelNineMinPoints && points <= LevelNineMaxPoints) return LevelNineName; else if (points >= LevelTenMinPoints) return LevelFourName; else return "No Rank"; } } Do you think this is the most efficient way to do this?

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  • How can I return the number of rows affected in sqlplus to a shell script?

    - by jessica
    Here is my shell script: # Deletes data from the 'sample' table starting August 30, 2011. # This is done in stages with a 7 second break every # 2 seconds or so to free up the database for other users. # The message "Done." will be printed when there are # no database entries left to delete. user="*****" pass="*****" while(true); do starttime=`date +%s` while [[ $((`date +%s` - $starttime)) -lt 2 ]]; do sqlplus $user/$pass@//blabla <<EOF whenever sqlerror exit 1 delete from sample where sampletime >= to_date('08-30-2011','mm-dd-yyyy') and rownum <= 2; commit; EOF rows = ??? if [ $rows -eq 0 ] ; then echo "Done." exit 0; fi done sleep 7 done If there is no way to get the number of rows, maybe I can use an error code returned by sqlplus to figure out when to end the script? Any thoughts? Thank you!

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  • How to return arrays with the biggest elements in C#?

    - by theateist
    I have multiple int arrays: 1) [1 , 202,4 ,55] 2) [40, 7] 3) [2 , 48 ,5] 4) [40, 8 ,90] I need to get the array that has the biggest numbers in all positions. In my case that would be array #4. Explanation: arrays #2, #4 have the biggest number in 1st position, so after the first iteration these 2 arrays will be returned ([40, 7] and [40, 8 ,90]) now after comparing 2nd position of the returned array from previous iteration we will get array #4 because 8 7 and so on... Can you suggest an efficient algorithm for this? Doing with Linq will be preferable. UPDATE There is no limitation for the length, but as soon as some number in any position is greater, so this array is the biggest.

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  • Can I use foreach to return only a certain type from a collection?

    - by RoboShop
    If I enter the code below, I get an error. Basically, the foreach will break when it comes across a Control that isn't a label. foreach (Label currControl in this.Controls()) { ... } I have to do something like this. foreach (Control currControl in this.Controls()) { if(typeof(Label).Equals(currControl.GetType())){ ... } } can anyone think of a better way of doing it without me needing to check the type? Can I somehow get foreach to skip the objects that aren't Labels?

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  • Right way to return proxy model instance from a base model instance in Django ?

    - by sotangochips
    Say I have models: class Animal(models.Model): type = models.CharField(max_length=255) class Dog(Animal): def make_sound(self): print "Woof!" class Meta: proxy = True class Cat(Animal): def make_sound(self): print "Meow!" class Meta: proxy = True Let's say I want to do: animals = Animal.objects.all() for animal in animals: animal.make_sound() I want to get back a series of Woofs and Meows. Clearly, I could just define a make_sound in the original model that forks based on animal_type, but then every time I add a new animal type (imagine they're in different apps), I'd have to go in and edit that make_sound function. I'd rather just define proxy models and have them define the behavior themselves. From what I can tell, there's no way of returning mixed Cat or Dog instances, but I figured maybe I could define a "get_proxy_model" method on the main class that returns a cat or a dog model. Surely you could do this, and pass something like the primary key and then just do Cat.objects.get(pk = passed_in_primary_key). But that'd mean doing an extra query for data you already have which seems redundant. Is there any way to turn an animal into a cat or a dog instance in an efficient way? What's the right way to do what I want to achieve?

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  • [Wordpress] How do I return values from custom created meta box?

    - by Steven
    I've just followed this example from Wordpress and I have successfully added an extra Meta Box in Post interface, and the value is stored in DB. Now my question is, how can I retrieve and display the content of this meta box? I'm trying the following code: $intro = get_post_meta($post->ID, 'post_intro', true); echo $intro; But I get nada. What am I doing wrong? And while I'm here, does anybody know if I can place this extra meta box above the default text box in Wordpress post page?

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  • Does unboxing just return a pointer to the value within the boxed object on the heap?

    - by Charles
    I this MSDN Magazine article, the author states (emphasis mine): Note that boxing always creates a new object and copies the unboxed value's bits to the object. On the other hand, unboxing simply returns a pointer to the data within a boxed object: no memory copy occurs. However, it is commonly the case that your code will cause the data pointed to by the unboxed reference to be copied anyway. I'm confused by the sentence I've bolded and the sentence that follows it. From everything else I've read, including this MSDN page, I've never before heard that unboxing just returns a pointer to the value on the heap. I was under the impression that unboxing would result in you having a variable containing a copy of the value on the stack, just as you began with. After all, if my variable contains "a pointer to the value on the heap", then I haven't got a value type, I've got a pointer. Can someone explain what this means? Was the author on crack? (There is at least one other glaring error in the article). And if this is true, what are the cases where "your code will cause the data pointed to by the unboxed reference to be copied anyway"? I just noticed that the article is nearly 10 years old, so maybe this is something that changed very early on in the life of .Net.

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  • Multi-argument decorators in 2.6

    - by wheaties
    Generally don't do OO-programming in Python. This project requires it and am running into a bit of trouble. Here's my scratch code for attempting to figure out where it went wrong: class trial(object): def output( func, x ): def ya( self, y ): return func( self, x ) + y return ya def f1( func ): return output( func, 1 ) @f1 def sum1( self, x ): return x which doesn't compile. I've attempted to add the @staticmethod tag to the "output" and "f1" functions but to no avail. Normally I'd do this def output( func, x ): def ya( y ): return func( x ) + y return ya def f1( func ): return output( func, 1 ) @f1 def sum1( x ): return x which does work. So how do I get this going in a class?

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