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  • Blackberry read local properties file in project

    - by Dachmt
    Hi, I have a config.properties file at the root of my blackberry project (same place as Blackberry_App_Descriptor.xml file), and I try to access the file to read and write into it. See below my class: public class Configuration { private String file; private String fileName; public Configuration(String pathToFile) { this.fileName = pathToFile; try { // Try to load the file and read it System.out.println("---------- Start to read the file"); file = readFile(fileName); System.out.println("---------- Property file:"); System.out.println(file); } catch (Exception e) { System.out.println("---------- Error reading file"); System.out.println(e.getMessage()); } } /** * Read a file and return it in a String * @param fName * @return */ private String readFile(String fName) { String properties = null; try { System.out.println("---------- Opening the file"); //to actually retrieve the resource prefix the name of the file with a "/" InputStream is = this.getClass().getResourceAsStream(fName); //we now have an input stream. Create a reader and read out //each character in the stream. System.out.println("---------- Input stream"); InputStreamReader isr = new InputStreamReader(is); char c; System.out.println("---------- Append string now"); while ((c = (char)isr.read()) != -1) { properties += c; } } catch (Exception e) { } return properties; } } I call my class constructor like this: Configuration config = new Configuration("/config.properties"); So in my class, "file" should have all the content of the config.properties file, and the fileName should have this value "/config.properties". But the "name" is null because the file cannot be found... I know this is the path of the file which should be different, but I don't know what i can change... The class is in the package com.mycompany.blackberry.utils Thank you!

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  • JPA Cascade delete.

    - by Win Man
    Hi, I am new to JPA/Hibernate. Currently using EJB3, Hibernate/JPA. I have an inheritacnce structure as follows.. @Entity @DiscriminatorColumn(name = "form_type") @Inheritance(strategy = InheritanceType.JOINED) @GenericGenerator(name = "FORMS_SEQ", strategy = "sequence-identity", parameters = @Parameter(name = "sequence", value = "FORMS_SEQ")) @Table(name = "Forms") public abstract class Form{ //code for Form } @Entity @Table(name = "CREDIT_CARDS") @PrimaryKeyJoinColumn(name="CREDIT_CARD_ID") public class CreditCardForm extends Form { //Code for CreditCards. } When I add a row with save the rows are properly inserted into the parent and the child table. However when I try to delete I get an error - 10:19:35,465 ERROR [TxPolicy] javax.ejb.EJBTransactionRolledbackException: Removing a detached instance com.data.entities.form.financial.CreditCard#159? I am using a simple for loop to determine the inheritance type - CreditCard or DebitCard and then calling entityManager.remove(entity). What am I doing wrong? Code for delete.. for(Form content: contents){ if(content.getType()==Type.CREDIT_CARD){ creditCardService.delete((CreditCard)content); } Thanks. WM

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  • What does the \- mean in the mvn dependency tree output

    - by Calm Storm
    Hi, I tried doing a mvn dependency:tree and I get a tree of dependencies. The output looks like below. I want to know what is the "-" symbol that is shown at times and the "+-" symbol for other dependencies (it doesnt seem to be the scope) My actual question is, My project depends on many modules which internally depends on many spring artifacts. There are a few version clashes. I want to upgrade all spring related libraries to say the latest one (2.6.x or above). What is the preferred way to do this? Should I declare all the deps spring-context, spring-support (and 10 other artifacts) in my pom.xml and point them to 2.6.x ? Is there any other better method ? [INFO] +- com.xxxx:yyy-jar:jar:1.0-SNAPSHOT:compile [INFO] | +- com.xxxx:zzz-commons:jar:1.0-SNAPSHOT:compile [INFO] | | +- org.springframework:spring-dao:jar:2.0.7:compile [INFO] | | +- org.springframework:spring-jdbc:jar:2.0.7:compile [INFO] | | +- org.springframework:spring-web:jar:2.0.7:compile [INFO] | | +- org.springframework:spring-support:jar:2.0.7:compile [INFO] | | +- net.sf.ehcache:ehcache:jar:1.2:compile [INFO] | | +- commons-collections:commons-collections:jar:3.2:compile [INFO] | | +- aspectj:aspectjweaver:jar:1.5.3:compile [INFO] | | +- betex-commons:betex-commons:jar:5.5.1-2:compile [INFO] | | \- javax.servlet:servlet-api:jar:2.4:compile [INFO] | +- org.springframework:spring-beans:jar:2.0.7:compile [INFO] | +- org.springframework:spring-jmx:jar:2.0.7:compile [INFO] | +- org.springframework:spring-remoting:jar:2.0.7:compile [INFO] | +- org.apache.cxf:cxf-rt-core:jar:2.0.2-incubator:compile [INFO] | | +- org.apache.cxf:cxf-api:jar:2.0.2-incubator:compile [INFO] | | | +- org.apache.geronimo.specs:geronimo-activation_1.1_spec:jar:1.0-M1:compile [INFO] | | | +- org.codehaus.woodstox:wstx-asl:jar:3.2.1:compile [INFO] | | | +- org.apache.neethi:neethi:jar:2.0.2:compile [INFO] | | | \- org.apache.cxf:cxf-common-schemas:jar:2.0.2-incubator:compile

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  • Is it possible to use ActiveObjects (or another ORM) with an embedded database & JWS technology ?

    - by phmr
    I would like to embed a database in my JWS application. As a matter of fact I have to use HSQL or SQLite. Hibernate may support (HSQL or SQLite, does it ?) but the workflow is rather complex for my application but maybe it's the way to go for my needs. In ActiveObjects database shoould be "linked" to by a path because of JDBC, but is it possible to specify a database that is inside a JAR and how ?

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  • Is this a good approach to address double-base64-encoding?

    - by Freiheit
    My software understands attachments, like PNGs attached to user records. These attachments are usually sent in from outside sources as a Base64 encoded string. The database stores whatever data it is given, Base64 encoded or not. When I serve up the attachment for download I do this: if (Base64.isBase64(data)) { data = Base64.decodeBase64(data); } There is a potential for data that is double encoded. For instance the sender of a message had base64 encoded data, then encoded it again when building the message to send to me. I think the following code would address that circumstance: while (Base64.isBase64(data)) { data = Base64.decodeBase64(data); } So if data is encoded multiple times, it would be decoded until its in its 'raw' state and then served up for download. Is this approach an acceptable way to address that problem? Ideally some sort of checking could happen at the edge when I receive attachment data, but that will take more time. This looping seems to be a faster way to do it. The 'Base64' library is Apache Commons: http://commons.apache.org/codec/apidocs/org/apache/commons/codec/binary/Base64.html I trust it to properly identify Base64 encoded data.

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  • Prefuse: Reloading of XML files

    - by John
    Hello all, I am a new to the prefuse visualization toolkit and have a couple of general questions. For my purpose, I would like to perform an initial visualization using prefuse (graphview / graphml). Once rendered, upon a user click of a node, I would like to completely reload a new xml file for a new visualization. I want to do this in order to allow me to "pre-package" graphs for display. For example. If I search for Ted. I would like to have an xml file relating to Ted load and render a display. Now in the display I see that Ted has nodes associated called Bill and Joe. When I click Joe, I would like to clear the display and load an xml file associated with Joe. And so on. I have looked into loading one very large xml file containing all node and node relationship info and allowing prefuse to handle this using the hops from one level to another. However, eventually I am sure that system performance issues will arise due to the size of data. Thanks in advance for any help, John

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  • Is it possible to override List accessors in Grails domain classes?

    - by Ali G
    If I have a List in a Grails domain class, is there a way to override the addX() and removeX() accessors to it? In the following example, I'd expect MyObject.addThing(String) to be called twice. In fact, the output is: Adding thing: thing 2 class MyObject { static hasMany = [things: String] List things = [] void addThing(String newThing) { println "Adding thing: ${newThing}" things << newThing } } class BootStrap { def init = { servletContext -> MyObject o = new MyObject().save() o.things << 'thing 1' o.addThing('thing 2') } def destroy = { } }

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  • ORM model and DAO in my particular case

    - by EugeneP
    I have the DB structure as follows: table STUDENT (say, id, surname, etc) table STUDENT_PROPERTIES (say, name_of_the_property:char, value_of_the_property:char, student_id:FK) table COURSE (id, name, statusofcourse_id) table STATUSOFCOURSE (id, name_of_status:char ('active','inactive','suspended' etc)) table STUDENT_COURSE (student_id,course_id,statusofcourse_id) Let's try to pick up domain objects in my database: Student and Course are main entities. Student has a list of courses he attends, also he has a list of properties, that is all for this student. Next, Course entitity. It may contain a list of students that attend it. But in fact, the whole structure looks like this: the starting point is Student, with it's PK we can look a list of his properties, then we look into the STUDENT_COURSE and extract both FK of the Course entity and also the Status of the combination, it would look like "Student named bla bla, with all his properties, attends math and the status of it is "ACTIVE". now, quotation 1) Each DAO instance is responsible for one primary domain object or entity. If a domain object has an independent lifecycle, it should have its own DAO. 2) The DAO is responsible for creations, reads (by primary key), updates, and deletions -- that is, CRUD -- on the domain object. Now, first question is What are entities in my case? Student, Course, Student_Course, Status = all except for StudentProperties? Do I have to create a separate DAO for every object?

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  • Troubles Iterating Over A HashMap with JSF, MyFaces & Facelets

    - by Lee Theobald
    Hi all, I'm having some trouble looping over a HashMap to print out it's values to the screen. Could someone double check my code to see what I'm doing wrong. I can't seem to find anything wrong but there must be something. In a servlet, I am adding the following to the request: Map<String, String> facetValues = new HashMap<String, String>(); // Filling the map req.setAttribute(facetField.getName(), facetValues); In one case "facetField.getName()" evaluates to "discipline". So in my page I have the following: <ui:repeat value="${requestScope.discipline}" var="item"> <li>Item: <c:out value="${item}"/>, Key: <c:out value="${item.key}"/>, Value: <c:out value="${item.item}"/></li> </ui:repeat> The loop is ran once but all the outputs are blank?!? I would have at least expected something in item if it's gone over the loop once. Checking the debug popup for Facelets, discipline is there and on the loop. Printing it to the screen results in something that looks like a map to me (I've shortened the output) : {300=0, 1600=0, 200=0, ... , 2200=0} I've also tried with a c:forEach but I'm getting the same results. So does anyone have any ideas where I'm going wrong? Thanks for any input, Lee

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  • Specify JDK for Maven to use

    - by DanInDC
    Hi all. I am trying to build a Hudson plugin I've modified and it requires jdk1.6. This is fine, but I don't see how I can tell maven where the different jdk is. I've found few mentions on the internet but they don't seem to apply to me. Some suggest adding some config to .m2/settings.xml but I don't have a settings.xml. Plus, I don't want to use 1.6 for all maven builds. One kink is I am using mvn in cygwin, if that matters at all. It appears I should be able to make the specification in the project pom file, but the existing pom is pretty bare. So bottom line is, is there a way to specify a jdk for a single invocation of maven?

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  • Things possible in IntelliJ that aren't possible in Eclipse?

    - by Epaga
    I have heard from people who have switched either way and who swear by the one or the other. Being a huge Eclipse fan but having not had the time to try out IntelliJ, I am interested hearing from IntelliJ users who are "ex-Eclipsians" some specific things that you can do with IntelliJ that you can not do with Eclipse. Note: This is not a subjective question nor at all meant to turn into a holy IDE war. Please downvote any flamebait answers. Thanks.

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  • Override the Local module directory for cvs using Hudson

    - by Roberto
    Hi guys, I'm using Hudson and I need to change the checkout directory for cvs. Instead of checkout/update the project under the workspace dir, I'd like to specify a dir (as you can do for svn, changing the Local module directory conf) that will match the cvs tree structure. Eg. under cvs dir1/dir2/project on my box workspace/dir1/dir2/project is that possible with cvs and Hudson? Maybe there's a way to override the cvs call? Thanks! Roberto

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  • servlet-mapping for Wordpress on Tomcat using Quercus

    - by Jeremy
    I have a web app running in Tomcat and I'm trying to add a Wordpress blog to it using Quercus. It works if I hit a .php file in my blog, but links to my articles are structured like http://myapp.com/blog/2011/01/my-first-post/ which don't work. Below is my web.xml: <welcome-file-list> <welcome-file>index.do</welcome-file> <welcome-file>index.php</welcome-file> </welcome-file-list> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/myapp-service.xml</param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <servlet> <servlet-name>myapp</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>myapp</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <servlet> <servlet-name>Quercus Servlet</servlet-name> <servlet-class>com.caucho.quercus.servlet.QuercusServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Quercus Servlet</servlet-name> <url-pattern>*.php</url-pattern> </servlet-mapping> I've tried many combos of url-pattern such as /blog, /blog/*, etc. I can't get anything to work. Any help is appreciated. Thanks!

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  • Enum.values() vs EnumSet.allOf( ). Which one is more preferable?

    - by Alexander Pogrebnyak
    I looked under the hood for EnumSet.allOf and it looks very efficient, especially for enums with less than 64 values. Basically all sets share the single array of all possible enum values and the only other piece of information is a bitmask which in case of allOf is set in one swoop. On the other hand Enum.values() seems to be a bit of black magic. Moreover it returns an array, not a collection, so in many cases it must be decorated with Arrays.asList( ) to be usable in any place that expects collection. So, should EnumSet.allOf be more preferable to Enum.values? More specifically, which form of for iterator should be used: for ( final MyEnum val: MyEnum.values( ) ); or for ( final MyEnum val: EnumSet.allOf( MyEnum.values ) );

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  • Best way to get database result as XML?

    - by John
    I am querying a database and getting the result set as an arraylist. I would like to return this list as XML, but not sure how to do it. Does anyone have an example of returning a result set as XML and is using an Arraylist the best way to do this?

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  • Abstract Base Class or Class?

    - by Mohit Deshpande
    For my semester project, my team and I are supposed to make a .jar file (library, not runnable) that contains a game development framework and demonstrate the concepts of OOP. Its supposed to be a FRAMEWORK and another team is supposed to use our framework and vice-versa. So I want to know how we should start. We thought of several approaches: 1. Start with a plain class public class Enemy { public Enemy(int x, int y, int health, int attack, ...) { ... } ... } public class UserDefinedClass extends Enemy { ... } 2. Start with an abstract class that user-defined enemies have to inherit abstract members public abstract class Enemy { public Enemy(int x, int y, int health, int attack, ...) { ... } public abstract void draw(); public abstract void destroy(); ... } public class UserDefinedClass extends Enemy { ... public void draw() { ... } public void destroy() { ... } } 3. Create a super ABC (Abstract Base Class) that ALL inherit from public abstract class VectorEntity { ... } public abstract class Enemy extends VectorEntity { ... } public class Player extends VectorEntity { ... } public class UserDefinedClass extends Enemy { ... } Which should I use? Or is there a better way?

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  • Single DispatcherServlet with Multiple Controllers

    - by jwmajors81
    I am trying to create some restful web services using Spring MVC 3.0. I currently have an issue that only 1 of my 2 controllers will work at any given time. As it turns out, whichever class comes first when sorted alphabetically will work properly. The error I get is: handleNoSuchRequestHandlingMethod No matching handler method found for servlet request: path '/polinq.xml', method 'GET', parameters map[[empty]] I had a very simliar message earlier also, except instead of the map being empty it was something like map[v--String(array)] Regardless of the message though, currently the LocationCovgController works and the PolicyInquiryController doesn't. If I change the change of the PolicyInquiryController to APolicyInquiryController, then it will start funcitoning properly and the LocationCovgController will stop working. Any assistance would be greatly appreciated. Thank you very much, Jeremy The information provided below includes the skeleton of both controller classes and also the servlet config file that defines how spring should be setup. Controller 1 package org.example; @Controller @RequestMapping(value = "/polinq.*") public class PolicyInquiryController { @RequestMapping(value = "/polinq.*?comClientId={comClientId}") public ModelAndView getAccountSummary( @PathVariable("comClientId") String commercialClientId) { // setup of variable as was removed. ModelAndView mav = new ModelAndView("XmlView", BindingResult.MODEL_KEY_PREFIX + "accsumm", as); return mav; } } Controller 2 package org.example; @Controller @RequestMapping(value = "/loccovginquiry.*") public class LocationCovgController { @RequestMapping(value = "/loccovginquiry.*method={method}") public ModelAndView locationCovgInquiryByPolicyNo( @PathVariable("method")String method) { ModelAndView mav = new ModelAndView("XmlView", BindingResult.MODEL_KEY_PREFIX + "loccovg", covgs); return mav; } } Servlet Config <context:component-scan base-package="org.example." /> <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver" p:order="0"> <property name="mediaTypes"> <map> <entry key="atom" value="application/atom+xml"/> <entry key="xml" value="application/xml"/> <entry key="json" value="application/json"/> <entry key="html" value="text/html"/> </map> </property> <property name="defaultContentType" value="text/html"/> <property name="ignoreAcceptHeader" value="true"/> <property name="favorPathExtension" value="true"/> <property name="viewResolvers"> <list> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> </list> </property> <property name="defaultViews"> <list> <bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView"/> </list> </property> </bean> <bean class="org.springframework.web.servlet.view.BeanNameViewResolver" /> <bean id="XmlView" class="org.springframework.web.servlet.view.xml.MarshallingView"> <property name="marshaller" ref="marshaller"/> </bean> <oxm:jaxb2-marshaller id="marshaller"> <oxm:class-to-be-bound name="org.example.policy.dto.AccountSummary"/> <oxm:class-to-be-bound name="org.example.policy.dto.InsuredName"/> <oxm:class-to-be-bound name="org.example.policy.dto.Producer"/> <oxm:class-to-be-bound name="org.example.policy.dto.PropertyLocCoverage"/> <oxm:class-to-be-bound name="org.example.policy.dto.PropertyLocCoverages"/> </oxm:jaxb2-marshaller>

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  • Pentaho - Reporting Tool - Is the .prpt file (report template file) contains datasource information

    - by Yatendra Goel
    I am new Pentaho Reporting Tool. I have the following question: When I created a report using Pentaho Report Designer, it output a report file having .prpt extension. After that I found an example on internet where the following code were used to display the report in html format:| protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ResourceManager manager = new ResourceManager(); manager.registerDefaults(); String reportPath = "file:" + this.getServletContext().getRealPath("sampleReport.prpt"); try { Resource res = manager.createDirectly(new URL(reportPath), MasterReport.class); MasterReport report = (MasterReport) res.getResource(); HtmlReportUtil.createStreamHTML(report, response.getOutputStream()); } catch (Exception e) { e.printStackTrace(); } } And the report got printed successfully. So as we haven't specified any datasource information here, I think that the .prpt file contains that information in it. If that's true than Isn't Jasper is better Reporting tool than Pentaho because when we display Jasper reports, we have to provide datasource details also so in that way our report is flexible and is not bound to any particular database.

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