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Search found 32007 results on 1281 pages for 'php openid'.

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  • Internet Explorer dont show a piece of my site

    - by Ramza
    Hi guys, i am creating a new site, based in a pre-existing web page The original site is http://oasisrio.intermediasp.com/ Its works great in Firefox, Chrome, and IE But the new one "oasisba.intermediasp.com" Dont show the right bar in IE, i check all that i can think about and i dont found the problem. Someone have any ideas why this is happening? PD: Sorry for my crapy english

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  • SQL Query to select upcoming events with a start and end date

    - by Chris T
    I need to display upcoming events from a database. The problem is when I use the query I'm currently using any events with a start day that has passed will show up lower on the list of upcoming events regardless of the fact that they are current My table (yaml): columns: title: type: string(255) notnull: true default: Untitled Event start_time: type: time end_time: type: time start_day: type: date notnull: true end_day: type: date description: type: string(500) default: This event has no description category_id: integer My query (doctrine): $results = Doctrine_Query::create() ->from("sfEventItem e, e.Category c") ->select("e.title, e.start_day, e.description, e.category_id, e.slug") ->addSelect("c.title, c.slug") ->orderBy("e.start_day, e.start_time, e.title") ->limit(5) ->execute(array(), Doctrine_Core::HYDRATE_ARRAY); Basically I'd like any events that is currently going on (so if today is in between start_day and end_day) to be at the top of the list. How would I go about doing this if it's even possible? Raw sql queries are good answers too because they're pretty easy to turn into DQL.

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  • symfony + doctrine + inheritance, how to make them work?

    - by imac
    I am beginning to work with Symfony, I've found some documentation about inheritance. But also found this discouraging article, which make me doubt if Doctrine handles inheritance any good at all... Has anyone find a smart solution for inheritance in Symfony+Doctrine? As an example, I have already structured the database something like this: CREATE TABLE `poster` ( `poster_id` int(11) NOT NULL AUTO_INCREMENT, `user_name` varchar(50) NOT NULL, PRIMARY KEY (`poster_id`), UNIQUE KEY `id` (`poster_id`), ) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1; CREATE TABLE `user` ( `user_id` int(11) NOT NULL, `real_name` varchar(50) DEFAULT NULL, PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`), CONSTRAINT `user_fk` FOREIGN KEY (`user_id`) REFERENCES `poster` (`poster_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; From that, Doctrine generated this "schema.yml": Poster: connection: doctrine tableName: poster columns: poster_id: type: integer(4) fixed: false unsigned: false primary: true autoincrement: true user_name: type: string(50) fixed: false unsigned: false primary: false notnull: true autoincrement: false relations: Post: local: poster_id foreign: poster_id type: many User: local: poster_id foreign: user_id type: many Version: local: poster_id foreign: poster_id type: many User: connection: doctrine tableName: user columns: user_id: type: integer(4) fixed: false unsigned: false primary: true autoincrement: false real_name: type: string(50) fixed: false unsigned: false primary: false notnull: false autoincrement: false relations: Poster: local: user_id foreign: poster_id type: one User creation for this structure with Doctrine auto-generated forms does not work. Any clue will be appreciated.

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  • Removing the last character of a string IF it is $variable

    - by KeenLearner
    Hi there, I've made a little script to convert titles into url friendly things. ie: 'I am a title' becomes 'I_am_a_title' My script basically goes through and turns spaces, apostrophes, commas etc etc into an underscore. The problem is, sometimes my url's end up like this: 'i_am_a_title_' with a trailing underscore... So i figure, add a little bit to go through and search to see if the last character is an underscore on the final result, and if it is, then swap it. I looked into the strrchr() function but I seem to be hitting a wall of my own understanding. How is this sort of thing accomplished?

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  • problems with inserting data in database

    - by jannes braet
    $message=$_POST['answer']; $message=nl2br($message); $message=strip_tags($message, '<p><a><b><i><strong><em><code><sub><sup><img><ul><ol><li>'); $message = mysql_real_escape_string($message); $user=$_SESSION['SESS_MEMBER_ID']; $qry="INSERT INTO forum_rules (message,author,date) VALUES ($message,$user,'".date("Y-m-d H:i:s")."')"; $result=mysql_query($qry) or die(mysql_error()); if (!$result) { echo "error inserting data into database"; } else { ... } this codes always outputs error inserting data into database and i don't see what i'm doing wrong. i hav also tried to do it without the date part but that didn't work tho. can someone please tell me what i'm doing wrong here

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  • get $_SERVER['HTTP_X_REQUESTED_WITH'] with iframe

    - by keith
    I'm working with Colorbox and if I specify to use an iframe with it then the $_SERVER['HTTP_X_REQUESTED_WITH'] variable is no longer available to me. I need that in order to detect if ajax has loaded so then I can include a header/footer or not. Anyway to get this variable or is there another variable that I can get when I use iframe? Thanks.

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  • CodeIgnitor is generating multiple sessions in the database, why?

    - by Derrick
    Ive got a site that does a few ajax calls on page load, now for some reason, codeIgnitor is inserting 4 sessions (I'm assuming for each ajax call) as you load the page. I'm storing the sessions in the database. I'm pretty sure there should only be one session per browser? FF seems to only generate one, other browsers seem to create a whole bunch of sessions. Multiple sessions for the same user are giving me some serious authentication problems. any ideas?

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  • Hyperlink for each record

    - by shantanuo
    I need a link for each depotname that will bring up a child window with the details of the last 10 backup status. while($data=mysql_fetch_array($res)) { if(is_null($depot_array) || !in_array($data['depotname'],$depot_array )) { $depot_array[$r]=$data['depotname']; if($data['SCP_status'] <> 'success') { echo "<tr id='fail'>"; The results of the following query should be displayed in a child window. select * from backup_log where depotname = $data['depotname']

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  • How to let Zend render a dynamic footer on every page?

    - by koko
    In the app I'm building, I'd like to have a nice footer with data from the database (tags) and a contact-form. All the parts are scripted, but now I'd like to put them all together. The elements of the footer are the same for every page loaded, only the content is different. How can I do this, without having to put too much code on every controller?

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  • Rapid Web Application Development ASP.net vs. Open Source Platforms

    - by Yaaqov
    Good morning - I'm an intermediate-level developer who wants to build on online data-driven app (CRUD with a few calculations and basic HTML form inputs, nothing fancy) that keeps track of user sessions, and looks "professional" (or at least not "homemade"). I'm looking to development something with the look-and-feel that users get from sites like: http://www.datamasher.org/ http://www.thisweknow.org/ (About page says it was made with Ruby on Rails, which I'm unfamiliar with) (stackoverflow.com) Any pointers on whether I should just go the Miscrosoft route, and develop in ASP.net with WebForms, or if there's a quick qay to do this kind of development (with a WYSIWYG environment) on an open-source platform? I'm willing to learn, if it's somethat I can use to quickly drag/drop, add code, and publish online. Templates would be a plus, too. I apologize is the question seems a bit vague.

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  • Can I embed a .png image into an html page?

    - by Ole Jak
    So I have a .png file. I am using windows OS. How can I embed my png file/image into (blank by default) file.html so that when you open that file in any browser you see that image, but the file is not anyhow linked to it - it is ebbeded into it? Step by step instructions would be nice.

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  • display image and run script for fifteen seconds

    - by Ryan Max
    This is very similar to a question I asked the other day but my page code has become significantly more complicated and I need to revisit it. I've been using the following code: $('#myLink').click(function() { $('#myImg').attr('src', 'newImg.jpg'); setTimeout(function() { $('#myImg').attr('src', 'oldImg.jpg'); }, 15000); }); To replace an image for a set period of time (15 seconds) when the link is clicked, then after 15 seconds, revert to the original image. However now, I'd like to run a snippet of javascript as well when the link is clicked (in addition to replacing the image), and only when the link is clicked (it's related to the 15 second image) and then have the js code disappear as well after the 15 seconds...however I'm not sure how to have jquery send js code into the page...Basically I just want jQuery to "echo" this code onto the page underneath the 15 second while I am there, but I don't know how jquery formats this "echo". Does this question make sense? interval = 500; imgsrc = "webcam/image.jpg"; function Refresh() { tmp = new Date(); tmp = "?" + tmp.getTime(); document.images["image1"].src = imgsrc + tmp; setTimeout("Refresh()", interval); } Refresh(); It's script for a webcam. Basically it takes a new picture every half a second and replaces it on the page. You must forgive me, I'm new to jquery, I don't know how to make this script work in a jquery context. i'm sorry, I'm explaining badly. This is what I need to happen, step by step: 1) User comes to the page and there is a static image that says "Click here to view webcam" 2) User clicks image 3) Image is replaced by live webcam image, which is refreshed every .5 seconds by the second script in my question. 4) After 15 seconds the live webcam reverts back to the static image saying "click here to view webcam" It is ONLY during that 15 second interval that I wan the webcam refresh script running, otherwise it's wasting bandwidth on an element that isn't even shown. Sorry for the confusion.

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  • Unable to send an associative array in JSON format in Zend to client

    - by Anorflame
    Hi, In one of my actions in a controller, I'm using the json view helper to send back a response to an ajax request. On the client side I alert the data that is passed to the success callback function. It works fine as long as the response is a number or an array with default keys. Once I try to send an associative array, it alerts with [object Object]. Server code: $childArray = array('key'=>'value'); $this->_helper->json($childArray); javascript: function displayChildren(data){ alert(data); } ... $.ajax({ url: "/po/add", dataType: "json", data: {format: "json"}, success: displayChildren }); I have no idea what am I doing wrong here, so any help would be appreciated...

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  • Textarea without wysiwyg editor but have nice format

    - by dantan
    I have a texteare where someone can input text. I do not want a wysiwyg editor. But what would be great: Strip all tags, but make correct <p> and <br /> if user input has new lines. Additionally convert all urls, with or without http// or parameter to clickable links. I cannot find a solution. So you could type into the textarea: ........ This is a paragraph This ist still in the paragraph this is a new paragraph www.this-would-be-clickable new paragraphp `<strong>`this will be shown not bold`</strong>` ........ thankfull for every advice

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  • problem in getting desired date format in loop

    - by Rishi2686
    Hi there, I have a date format like this : $date1 = "Sun May 09 20:07:50 +0000 2010"; and I have to convert it to: 09-05-2010 I am using date("d-m-Y", $date1)); When I print this individually it gives proper result but I am using it in loop it gives me results like: 31-12-1969 I don't understand why this is so? Can you help, please?

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  • Zend Framework, what $this->_forward is doing

    - by RageZ
    Hello everyone, I would like someone to explain me what _forward is exactly doing, I cannot see if _forward is also rendering the attached view to the action or just executing the action. Also is it possible to pass argument to $this-action in a view script ? More generally my problem is how to code a confirmation page, let's say the user input some stuff and you want to show him confirmation, is forward is mean for that case ? Thanks

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  • 500 error with CodeIgniter

    - by feylya
    I have just moved my CodeIgniter project to a new server and now I'm getting a 500 error and no output from the project. It works fine on my old server and in my test environment. I'm completely stumped how to troubleshoot this, especially as there's nothing of use in the log files. Any help would be great!

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  • Is it possible to cancel function override in parent class and use function from top level parent

    - by Anatoliy Gusarov
    class TopParent { protected function foo() { $this->bar(); } private function bar() { echo 'Bar'; } } class MidParent extends TopParent { protected function foo() { $this->midMethod(); parent::foo(); } public function midMethod() { echo 'Mid'; } public function generalMethod() { echo 'General'; } } Now the question is if I have a class, that extends MidParent because I need to call class Target extends MidParent { //How to override this method to return TopParent::foo(); ? protected function foo() { } } So I need to do this: $mid = new MidParent(); $mid->foo(); // MidBar $taget = new Target(); $target->generalMethod(); // General $target->foo(); // Bar UPDATE Top parent is ActiveRecord class, mid is my model object. I want to use model in yii ConsoleApplication. I use 'user' module in this model, and console app doesn't support this module. So I need to override method afterFind, where user module is called. So the Target class is the class that overrides some methods from model which uses some modules that console application doesn't support.

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  • how to print data in a table from mysql

    - by robertdd
    hello, i want to extract the last eight entries from my database and print them into a 2 columns table!like this: |1|2| |3|4| |5|6| |7|8| is that possible? this is my code: $db = new Database(DB_SERVER, DB_USER, DB_PASS, DB_DATABASE); $db->connect(); $sql = "SELECT ID, movieno FROM movies ORDER BY ID DESC LIMIT 8 "; $rows = $db->query($sql); print '<table width="307" border="0" cellspacing="5" cellpadding="4">'; while ($record = $db->fetch_array($rows)) { $vidaidi = $record['movieno']; print <<<END <tr> <td> <a href="http://www.youtube.com/watch?v=$vidaidi" target="_blank"> <img src="http://img.youtube.com/vi/$vidaidi/1.jpg" width="123" height="80"></a> </td> </tr> END; } print '</table>';

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  • Codeigniter error logs show a 404 non-existing images directory...need to worry?

    - by user342199
    I've recently started logging my errors through codeIgniter. Since doing so, I have noticed a lot of 404 errors for directories that don't exist. For example: ERROR - 2010-05-15 21:06:26 -- 404 Page Not Found -- someController/images Where someController is, obviously, a controller. The problem is, there are no functions within that controller called images, nor are there any links to a directory by that name. Could this be that someone is trying to hack my site? If so, do I need to worry? If not, why is this happening? Thanks, and forgive the newby-ness.

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