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  • Zend Framework - counting rows in select clause ?

    - by moogeek
    Hello! I'm investigating Zend Framework and currently stucked in counting resulting rows of sql query... Every method I try (from documentation and some blogposts and tutorials) returns an error (like Call to undefined function) or simply gives the incorrect value. I've tried this: $checkquery = $db->select() ->from('users', 'COUNT(*)') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=fetchRow($checkquery)->num; ...then this one: $checkquery = $db->select() ->from('users', '*') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=count($checkquery->fetchAll()); and even: $checkquery = $db->select() ->from('users', '*') ->where('login = ?', $login) ->where('password = ?', $password) ->query(); $checkrequest=$checkquery->fetchAll()->num; Also rowCount() and count(fetchRow()) and count(fetchAll()->toArray()). But always I got an error message or duplicate inserts in db in further insert function. So what is the correct way to do the resulting row calculation in select clause in Zend Framework 1.9 (I use this one) ?

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  • Is there any short way to load data to the properties of a class, for each column name matching the properties of the class?

    - by Ugur Gümüshan
    I want to load data to an instance of an object using its constructor and I write $this->property=$row["colname"] each time for each property. the mysql_fetch_object function fetches the data as an object but I am not sure if the instance of an object can be assigned to some object from inside. othwerwise I would use __construct($object) { $this=$object; } //doesn't give any syntax error Maybe I should look into iteration of properties and use foreach($object as $key => $value) $value=$object[$key]; or can I assign like $this=$object; within the constructor?

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  • inserting unique date into txt document

    - by durian
    I'm trying this script to insert only a unique date into a text file, but it isn't working properly: $log_file_name = "logfile.txt"; $log_file_path = "log_files/$id/$log_file_name"; if(file_exists($log_file_path)){ $not = "not"; $todaydate = date('d,m,Y'); $today = "$todaydate;"; $strlength = strlen($today); $file_contents = file_get_contents($log_file_path); $file_contents_arry = explode(";",$file_contents); if(!in_array($todaytodaydate,$file_contents_arry)){ $append = fopen($log_file_path, 'a'); $write = fwrite($append,$today); //writes our string to our file. $close = fclose($append); //closes our file } else { $append = fopen($log_file_path, 'a'); $write = fwrite($append,$not); //writes our string to our file. $close = fclose($append); //closes our file } } else{ mkdir("log_files/$id", 0700); $todaydate = date('d,m,Y'); $today = "$todaydate;"; $strlength = strlen($today); $create = fopen($log_file_path, "w"); $write = fwrite($create, $today, $strlength); //writes our string to our file. $close = fclose($create); //closes our file } The problem is with the if else statement where it should be written if it's already in the array.

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  • Update query with conditional?

    - by dmontain
    I'm not sure if this possible. If not, let me know. I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; (meaning that the update of field3 is controlled by a conditional statement) Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. //run this query to update only fields 1 and 2 $update_part1 = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2 WHERE key=:key"); //if field3 should be update, run a separate query to update it separately if ($update3){ $update_part2 = $mypdo->prepare("UPDATE tablename SET field3=:field3 WHERE key=:key"); } But hopefully there is a way to accomplish this in 1 query?

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  • programming question about numbers

    - by Syom
    it's a task, on which i think during whole day. i have four integer numbers a, b, c, d, and ineger x[1,40]. i must write a program, which can find the values of {a,b,c,d}, for which one of following equations is true for any (x<=40, x=1) x=a or x=b or x=a+b or x=a+b+c+d or x+a=c+d or x+a+b=c+d or ... x+a+b+c=d or ... it is very difficult to explain what i want to say. maybe the example will be helpful. example: if x=17, by {a=1,b=2,c=5,d=15} i can write x+a+b=c+d whole question is to present any x[1,40] by {a,b,c,d}. hope that you understand what i want to say, and thanks in advance

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  • How to change Zend_Db_Table name within a Model to insert in multiple tables

    - by jwhat
    Using Zend Framework, I've created a Model to insert a record into a database. My question is, after $this->insert($data) how can I switch the active table so that I can insert a record into another table? Here's my code so far: class Model_DbTable_Foo extends Zend_Db_Table_Abstract { protected $_name = 'foo'; public function addFoo($params) { $data = array( 'foo' => $params['foo'], ); $this->insert($data); $foo_id = $this->getAdapter()->lastInsertId(); $data2 = array( 'bar' => $params['bar'] ); // I need to change the Db Table name here. $this->insert($data2); $bar_id = $this->getAdapter()->lastInsertId(); } }

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  • Populate FILE field with default text

    - by dclowd9901
    I'm trying to reutilize code that generates FILE fields for use when something is to be added to the database, and grayed out (and disabled) with data already in the database when the item in question is being edited or viewed in detail. However, I can't seem to get the text to fill the field. I'm using this: echo '<input type="file" name="small[]" value="' . $value_from_database . '" DISABLED><br>'; Am I missing anything? If not, are there any decent workarounds?

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  • Drupal. Use AJAX to update view's content

    - by ozke
    Hi, I've created a view in Drupal that retrieves a list of nodes. The display of this view is a page and it works perfectly well. It does even allow me to filter its content by argument. See the current's view configuration (click to enlarge): I want to use AJAX to use the filter (by parameter) functionality without reloading the page. I've enabled the "Use AJAX" option but I am not sure on how to continue. Any ideas on how to do that? By the way, I'm building my own theme (in case that changes anything). Thanks in advance Update: Basically, this view works when I browse through section/parameter1, section/parameter2... but I want to do the same with AJAX, without reloading the page. I hope is clearer now

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  • speed up the speed of a sql query to mysql?

    - by fayer
    in my mysql database i've got the geonames database, containing all countries, states and cities. i am using this to create a cascading menu so the user could select where he is from: country - state - county - city. but the main problem is that the query will search through all the 7 millions rows in that table each time i want to get the list of children rows, and that is taking a while 10-15 seconds. i wonder how i could speed this up: caching? table views? reorganizing table structure somehow? and most important, how do i do these things? are there good tutorials you could link to me? i appreciate all help and feedback discussing smart ways of handling this issue!

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  • Form validation with optional File Upload field callback

    - by MotiveKyle
    I have a form with some input fields and a file upload field in the same form. I am trying to include a callback into the form validation to check for file upload errors. Here is the controller for adding and the callback: public function add() { if ($this->ion_auth->logged_in()): //validate form input $this->form_validation->set_rules('title', 'title', 'trim|required|max_length[66]|min_length[2]'); // link url $this->form_validation->set_rules('link', 'link', 'trim|required|max_length[255]|min_length[2]'); // optional content $this->form_validation->set_rules('content', 'content', 'trim|min_length[2]'); $this->form_validation->set_rules('userfile', 'image', 'callback_validate_upload'); $this->form_validation->set_error_delimiters('<small class="error">', '</small>'); // if form was submitted, process form if ($this->form_validation->run()) { // add pin $pin_id = $this->pin_model->create(); $slug = strtolower(url_title($this->input->post('title'), TRUE)); // path to pin folder $file_path = './uploads/' . $pin_id . '/'; // if folder doesn't exist, create it if (!is_dir($file_path)) { mkdir($file_path); } // file upload config variables $config['upload_path'] = $file_path; $config['allowed_types'] = 'jpg|png'; $config['max_size'] = '2048'; $config['max_width'] = '1920'; $config['max_height'] = '1080'; $config['encrypt_name'] = TRUE; $this->load->library('upload', $config); // upload image file if ($this->upload->do_upload()) { $this->load->model('file_model'); $image_id = $this->file_model->insert_image_to_db($pin_id); $this->file_model->add_image_id_to_pin($pin_id, $image_id); } } // build page else: // User not logged in redirect("login", 'refresh'); endif; } The callback: function validate_upload() { if ($_FILES AND $_FILES['userfile']['name']): if ($this->upload->do_upload()): return true; else: $this->form_validation->set_message('validate_upload', $this->upload->display_errors()); return false; endif; else: return true; endif; } I am getting the error Fatal error: Call to a member function do_upload() on a non-object on line 92 when I try to run this. Line 92 is the if ($this->upload->do_upload()): line in the validate_upload callback. Am I going about this the right way? What's triggering this error?

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  • Why aren't my MySQL Group By Hours vs Half Hours files Not displaying same data?

    - by stogdilla
    I need to be able to display data that I have in 15 minute increments in different display types. I have two queries that are giving me trouble. One shows data by half an hour, the other shows data by hour. The only issue is that the data totals change between queries. It's not counting the data that happens between the time frames, only AT the time frames. Ex: There are 5 things that happen at 7:15am. 2 that happen at 7:30am and 4 that show at 7:00am. The 15 minute view displays all of the data. The half hour view displays the data from 7:00am and from 7:30am but ignores the 7:15am. The hour display only shows the 7:00am data Here are my queries: $query="SELECT * FROM data WHERE startDate='$startDate' and queue='$queue' GROUP BY HOUR(start),floor(minute(start)/30)"; and $query="SELECT * FROM data WHERE startDate='$startDate' and queue='$queue' GROUP BY HOUR(start) "; How can I pull out the data in groups like I have but get all the data included? Is the issue the way the data is stored in the mysql table? Currently I have a column with dates (2010-03-29) and a column with times (00:00) Do I need to convert these into something else?

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  • Some specific questions about object oriented and MVC design.

    - by Samn
    I have two objects, Users and Mail. Users create Mail objects and send them to other users. If I wanted to get all mail for a User, I could create a method like GetMail() that would return an array of Mail objects owned by that User. But if I wanted to get all mail across the system, what "type" of object would be responsible for that? To solve this problem, I usually create a Manager, which is an object responsible for dealing with a collection of a particular type of object. MailManager deals with collections of Mail objects. GetMailForUser() is one method, GetAllMail() is another method. The User objects invokes the MailManager and executes GetMailForUser(me). Is this stupid? When a user executes the controller CreateMail, a new instance of the Mail object is created. The Mail object, seeing it is creating a new Mail of type 'sent', decides to go ahead and create a second Mail object for the recipient, of type 'received'. Creating one Mail object triggers the creation of a second Mail object. Is this stupid? Should the controller have created both Mail objects, or just the first 'sent' one? When two Users are friends, the association is stored in a table of Relationships. I use a simple object for Relationships. A RelationshipManager has a method called GetFriendsForUser(). The User object has a method GetFriends(), which invokes the RelationshipManager. Is this stupid?

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  • How to check whether user is login in web application?

    - by Morgan Cheng
    I want to learn the whole details of web application authentication. So, I decided to write a CodeIgniter authentication library from scratch. Now, I have to make design decision about how to determine whether one user is login. Basically, after user input username & password pair. A cookie is set for this session, following navigations in the web application will not require username & password. The server side will check whether the session cookie is valid to determine whether current user is login. The question is: how to determine whether cookie is valid cookie issued from server side? I can image the most simple way is to have the cookie value stored in session status as well. For each HTTP request, compare the value from cookie and the value from server session. (Since CodeIgniter session library store session variables in cookies, it is not applicable without some tweak.) This method requires storage in server side. For huge web application that is deployed in multiple datacenters. It is possible that user input username & password when browsing in one datacenter, while he/she access the web application in another datacenter later. The expected behavior is that user just input username & password once. As a result, all datacenters should be able to access the session status. That is possible not applicable even the session status is stored in external storage such as database. I tried Google. I login Google with Asian proxy which is supposed to direct me to datacenters in Asian. Then I switch to North American proxy which should direct me to datacenters in North America. It recognize my login without asking username and password again. So, is there any way to determine whether user is login without server side session status?

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  • different explanation

    - by Delirium tremens
    The following code echoes 5, not 10: $global_obj = null; class my_class { var $value; function my_class() { global $global_obj; $global_obj = &$this; } } $a = new my_class; $a->my_value = 5; $global_obj->my_value = 10; echo $a->my_value; "Upon first examination, it would seem that the constructor of my_class stores a reference to itself inside the $global_obj variable. Therefore, one would expect that, when we later change the value of $global_obj-my_value to 10, the corresponding value in $a would change as well. Unfortunately, the new operator does not return a reference, but a copy of the newly created object." Please, give me a different explanation.

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  • MySQL parameter resource error

    - by Derek
    Here is my error: Warning: mysql_query() expects parameter 2 to be resource, null given... This refers to line 23 of my code which is: $result = mysql_query($sql, $connection) My entire query code looks like this: $query = "SELECT * from users WHERE userid='".intval( $_SESSION['SESS_USERID'] )."'"; $result = mysql_query($query, $connection) or die ("Couldn't perform query $query <br />".mysql_error()); $row = mysql_fetch_array($result); I don't have a clue what has happpened here. All I wanted to do was to have the value of the users 'fullname' displayed in the header section of my web page. So I am outputting this code immediately after to try and achieve this: echo 'Hello '; echo $row['fullname']; Before this change, I had it working perfectly, where the session variable of fullname was echoed $_SESSION['SESS_NAME']. However, because my user can update their information (including their name), I wanted the name displayed in the header to be updated accordingly, and not displaying the session value.

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  • Doctrine join enitiy or null

    - by Medvedev
    I have an entity Entity\User with avatar: /** * @ORM\OneToOne(targetEntity="Entity\Avatar", cascade={"remove"}, fetch="LAZY") */ protected $avatar; And Entity\Message entity /** * @ORM\ManyToOne(targetEntity="Entity\User") */ protected $user; When i try to load all messages with users and avatars. But not all user have avatar. SELECT m, u, a FROM Entity\Message m JOIN m.user u JOIN u.avatar a ORDER BY m.id DESC How to load all messages with user who avatars and who does not have?

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  • Add CSS to Form Type is Symfony2

    - by Umair Iqbal
    I have an edit form, The form is made through symfony2 Form types. I checked the documentation but couldn't find any option for adding CSS to the form. The form display the data correctly and everything is fine what I want to do is to add styling to each field. My Edit Type is public function buildForm(FormBuilder $builder, array $options) { $builder ->add('id', 'hidden') ->add('patent_name', 'text', array('label' => 'Patent Name')) ->add('description', 'textarea', array('label' => 'Description', 'required' => false)) ->add('appln_auth','text', array('label' => 'Application Authorization')) ; } Anyone has any idea ho I can add css ? Thanks

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  • database change after pressing 'X' button

    - by Anup Prakash
    What i know:- We can use Ajax to change database from javascript. So whenever we press the 'X' button on title bar it calls "onbeforeunload" event. And by this event we can change the database. But in my case, i want to change the status of user only when user click on 'X' button. Not in case of changing the page. As because changing the page is unloading the page. and closing the page is also unloading the page(As much i know). Is there any way to differentiate between closing the page and moving from one page to other page? I want to use it for changing the status of user(i.e. login/logout), whenever he presses cross button. I don't want to set status "logout" when user changes the page. I want to set status "logout" when user 'X' the button. Plese help me.

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  • Make MediaWiki use accounts on my site?

    - by acidzombie24
    I have a site in ASP.NET and i thought it would be cool if i can redirect users to wiki.mysite.com. Now i would like to know if i can easily make MediaWiki recognize users logged into my site. I dont want any anonymous posters. Is there a way to hook or have mediawiki use accounts/cookies from my site instead of using its own database/account system?

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  • Compare values in serialized column in Doctrine with Query Builder

    - by ReynierPM
    I'm building a FormType for a Symfony2 project but I need some Query Builder on the field since I need to compare some values with the one stored on DB and show the results. This is what I have: .... ->add('servicio', 'entity', array( 'mapped' => false, 'class' => 'ComunBundle:TipoServicio', 'property' => 'nombre', 'required' => true, 'label' => false, 'expanded' => true, 'multiple' => true, 'query_builder' => function (EntityRepository $er) { return $er->createQueryBuilder('ts') ->where('ts.tipo_usuario = (:tipo)') ->setParameter('tipo', 1); } )) .... But tipo_usuario at DB table is stored as serialized text for example: record1: value1 | a:1:{i:0;s:1:"1";} record2: value2 | a:4:{i:0;s:1:"1";i:1;s:1:"2";i:2;s:1:"3";i:3;s:1:"4";} I'll have two different forms (I don't know how to pass the Request to a form) in the first one I'll only show the first record and for the second one the first and second record for example: First form will show: checkbox: value1 Second form will show: checkbox: value1 checkbox: value2 I achieve this? Any help?

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