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• Use of class definitions inside a method in Java

  - by Bragaadeesh

  Hi public class TestClass { public static void main(String[] args) { TestClass t = new TestClass(); } private static void testMethod(){ class TestMethodClass{ int a; int b; int c; } TestMethodClass testMethodClass = new TestMethodClass(); } } I found out that the above piece of code is perfectly legal in Java. I have the following questions. What is the use of ever having a class definition inside a method? Will a class file be generated for TestMethodClass Its hard for me to imagine this concept in an Object Oriented manner. Having a class definition inside a behavior. Probably can someone tell me with equivalent real world examples. Thanks

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• Java Double Array

  - by user1062058

  I'm having trouble setting up and placing values into an array using a text file containing the floating point numbers 2.1 and 4.3 each number is separated by a space - below is the error I'm getting: Exception in thread "main" java.util.NoSuchElementException import java.util.*; import java.io.*; public class DoubleArray { public static void main(String[] args) throws FileNotFoundException { Scanner in = new Scanner(new FileReader("mytestnumbers.txt")); double [] nums = new double[2]; for (int counter=0; counter < 2; counter++) { int index = 0; index++; nums[index] = in.nextDouble(); } } } Thanks, I'm sure this isn't a hard question to answer... I appreciate your time.

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• Java : Using parent class method to access child class variable

  - by Jayant

  I have the following scenario : public class A { private int x = 5; public void print() { System.out.println(x); } } public class B extends A { private int x = 10; /*public void print() { System.out.println(x); }*/ public static void main(String[] args) { B b = new B(); b.print(); } } On executing the code, the output is : 5. How to access the child class(B's) variable(x) via the parent class method? Could this be done without overriding the print() method (i.e. uncommenting it in B)? [This is important because on overriding we will have to rewrite the whole code for the print() method again]

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• Call function based off of a string in Lisp

  - by powerj1984

  I am passing in command line arguments to my Lisp program and they are formatted like this when they hit my main function: ("1 1 1" "dot" "2 2 2") I have a dot function and would like to call it directly from the argument, but this isn't possible because something like (funcall (second args)...) receives "dot" and not dot as the function name. I tried variations of this function: (defun remove-quotes (s) (setf (aref s 0) '"")) to no avail, before realizing that the quotes were not really a part of the string. Is there a simple way to do this, or should I just check each string and then call the appropriate function? Thanks!

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• Matlab Error- fplot();

  - by udsha

  >> fplot(fh,[-2 4]) ??? Undefined function or variable "e". Error in ==> myfun at 3 Y(:,2) = e(:).^x; Error in ==> fplot at 102 x = xmin; y = feval(fun,x,args{4:end}); I tried to plot two function using this m file. function Y = myfun(x) Y(:,1) = 3*x; Y(:,2) = e(:).^x;

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• what (clip) and DataLine.Info represents...?

  - by user528050

  I got this code from one of my friend. import java.io.*; import javax.sound.sampled.*; public class xx { public static void main(String args[]) { try { File f=new File("mm.wav"); AudioInputStream a=AudioSystem.getAudioInputStream(f); AudioFormat au=a.getFormat(); DataLine.Info di=new DataLine.Info(Clip.class,au); Clip c=(Clip)AudioSystem.getLine(di); c.open(a); c.start(); } catch(Exception e) { System.out.println("Exception caught "); } } } But i didn't understand what this line means Cilp c=(Clip)AudioSystem.getLine(di); what (clip) represents....? And my 2nd problem is what is the DataLine is it an interface and what is the meaning of this statement DataLine.Info....?

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• How to remove strings of certain lengths

  - by Macosx Iam

  So I have this array, and I want to delete strings that are 2 or 4 characters in length (strings that contain 2 or 4 characters). I am doing this method, and it doesn't work, even though logically, it SHOULD work. public static void main(String[] args) { ArrayList<String> list = new ArrayList<String>(); list.add("This"); list.add("is"); list.add("a"); list.add("test"); for (int i=0; i<list.size(); i++) { if(list.get(i).length()==2 || list.get(i).length()==4) { list.remove(i); } } } I'd like to stick to this method of doing it. Can you please give me some suggestions as to how to correct this code? The output of this code when I run it is: [is, a] Even though I want the output to be [a] because "is" is 2 characters long.

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• Trying to understand Java RSA key size

  - by Tom Brito

  The key generator was initilized with a size of 1024, so why the printed sizes are 635 and 162? import java.security.KeyPair; import java.security.KeyPairGenerator; import java.security.NoSuchAlgorithmException; import java.security.NoSuchProviderException; import java.security.interfaces.RSAPrivateKey; import java.security.interfaces.RSAPublicKey; public class TEST { public static KeyPair generateKeyPair() throws NoSuchAlgorithmException, NoSuchProviderException { KeyPairGenerator keyPairGenerator = KeyPairGenerator.getInstance("RSA", "BC"); keyPairGenerator.initialize(1024); return keyPairGenerator.generateKeyPair(); } public static void main(String[] args) throws Exception { KeyPair keyPair = generateKeyPair(); RSAPrivateKey privateKey = (RSAPrivateKey) keyPair.getPrivate(); RSAPublicKey publicKey = (RSAPublicKey) keyPair.getPublic(); System.out.println("Size = " + privateKey.getEncoded().length); System.out.println("Size = " + publicKey.getEncoded().length); } }

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• php string to array and split

  - by RussP

  Hi folks Looking for suggestions as to the best way to do this (I know there are many options): take a variable like this: $args = ('post_type=post&order_by=DESC&limit=10'); the create a function to convert that variable into parts like this: $post_type = post; $order_by = DESC; $limit= 10; Reason is I want a client to be able to use a string like the first to pass variables to a sql query in much the same way (but doesn't have to be exact) as you can do it in WordPress.

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• Fractional Calculator in Java

  - by user2888881

  I am trying to create a fractional calculator in Java with inputs of mixed fractions, proper fractions, improper fractions or integers. It should include the four basic operators as well. The program should be set up as a loop where it is continuous until the user types "quit". I have coded the beginning loop but have no idea where to go from there. Please help, I am a beginner and would really appreciate it. Thank you again. This is what I have so far: import java.util.*; public class FractionCalculator { private static Scanner input; public static void main(String[] args) { input = new Scanner(System.in); String x = "quit"; System.out.println("Enter a fraction"); while (true) { String y = input.next(); if (y.equals(x)) { break; } } } }

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• C# compiler fails to recognize a class is implementing an interface

  - by Freek

  The following code fails to compile (using VS2010) and I don't see why. The compiler should be able to infer that List is 'compatible' (sorry for lack of a better word) with IEnumerable, but somehow it doesn't. What am I missing here? interface ITest { void Test(); } class TestClass : ITest { public void Test() { } } class Program { static void Test(IEnumerable<ITest> tests) { foreach(var t in tests) { Console.WriteLine(t); } } static void Main(string[] args) { var lst = new List<TestClass>(); Test(lst); // fails, why? Test(lst.Select(t=>t as ITest)); //success Test(lst.ToArray()); // success } }

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• scala coalesces multiple function call parameters into a Tuple -- can this be disabled?

  - by landon9720

  This is a troublesome violation of type safety in my project, so I'm looking for a way to disable it. It seems that if a function takes an AnyRef (or a java.lang.Object), you can call the function with any combination of parameters, and Scala will coalesce the parameters into a Tuple object and invoke the function. In my case the function isn't expecting a Tuple, and fails at runtime. I would expect this situation to be caught at compile time. object WhyTuple { def main(args: Array[String]): Unit = { fooIt("foo", "bar") } def fooIt(o: AnyRef) { println(o.toString) } } Output: (foo,bar)

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• Bash redirection: save stderr/stdout to different files and still print them out on a console

  - by Alby

  Here is a simple program. class Redirection { public static void main (String args[]){ System.out.println("Hello World_Stdout"); System.err.println("Hello World_Stderr"); } } I want to see the all the outputs on a console, but at the same time I want to store stdout and stderr in different files. I tried the following command, to no avail. $java Redirection 3>&1 2>stderr 1>stdout 1>&3 2>&3 stderr& stdout files have the file size of 0. So basically I want to do what "tee" command does but I also want to capture stderr as well.

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• Put an array of Objects in nodes of another array of Objects [JAVA]

  - by zengr

  public class hello { public static void main(String[] args) { Object[] newarray = new Object[1]; Object[] obj = new Object[2]; obj[0] = "Number1"; //string value obj[1] = "Number2"; //string value newarray[0] = obj; //this works Object[] tmp_obj = new Object[2]; tmp_obj = newarray[0]; //obviously does not work System.out.println(tmp_obj[0]); //nope System.out.println(tmp_obj[1]); //nope } } So, now if I want to access the values "Number1" and "Number2" which are stored in obj[0] and obj[1]; obj is in newarray[0]. what should I do? Is this a possible? Thanks

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• Java: ListA.addAll(ListB) fires NullPointerException?

  - by HH

  The err part is Capitalized in the code, it also comes in foreaching. Because of the abstract list, it cannot be initialized, declaration is in a static field. The lists have the same type. import java.util.*; public class Test { public static final List<String> highPrio = Arrays.asList("*","/"); public static List<String> ops; public static void main(String[] args) { //ERROR HERE, why do it throw nullPointer? ops.addAll(highPrio); for(String s : ops) { System.out.println(s); } } }

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• Why Timer does not work if we do not generate a window?

  - by Roman

  Here is the code: import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.JFrame; import javax.swing.Timer; public class TimerSample { public static void main(String args[]) { new JFrame().setVisible(true); ActionListener actionListener = new ActionListener() { public void actionPerformed(ActionEvent actionEvent) { System.out.println("Hello World Timer"); } }; Timer timer = new Timer(500, actionListener); timer.start(); } } It generates a window and then periodically prints "Hello World Timer" in the terminal (Command Prompt). If I comment this line new JFrame().setVisible(true); the application do not print anything to the command line. Why?

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• Constructors + Dependency Injection

  - by Sunny

  If I am writing up a class with more than 1 constructor parameter like: class A{ public A(Dependency1 d1, Dependency2 d2, ...){} } I usually create a "argument holder"-type of class like: class AArgs{ public Dependency1 d1 { get; private set; } public Dependency2 d2 { get; private set; } ... } and then: class A{ public A(AArgs args){} } Typically, using a DI-container I can configure the constructor for dependencies & resolve them & so there is minimum impact when the constructors need to change. Is this considered an anti-pattern and/or any arguments against doing this?

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• Eclipse bug? Switching on a null with only default case

  - by polygenelubricants

  I was experimenting with enum, and I found that the following compiles and runs fine on Eclipse (Build id: 20090920-1017, not sure exact compiler version): public class SwitchingOnAnull { enum X { ,; } public static void main(String[] args) { X x = null; switch(x) { default: System.out.println("Hello world!"); } } } When compiled and run with Eclipse, this prints "Hello world!" and exits normally. With the javac compiler, this throws a NullPointerException as expected. So is there a bug in Eclipse Java compiler?

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• When debugging in VS 2008 why does the debugger land on a second return statement?

  - by Hellfire

  When debugging the following console program: class Program { static void Main(string[] args) { Console.WriteLine(DoIt(false)); Console.WriteLine(DoIt(true)); } private static Boolean DoIt(Boolean abort) { try { throw new InvalidOperationException(); } catch(Exception ex) { if (abort) { return true; } Console.WriteLine("Got here"); return false; } } } Why does the IDE land on the second return statement during the second call to DoIt()? The results of the execution is correct but the debugging experience is misleading. Is this a known issue? Is the behavior in VS 2010 the same?

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• question about Batcher odd-even sort

  - by davit-datuashvili

  hi i ave question about Batcher's odd-even sort i have following code public class Batcher{ public static void batchsort(int a[],int l,int r){ int n=r-l+1; for (int p=1;p<n;p+=p) for (int k=p;k>0;k/=2) for (int j=k%p;j+k<n;j+=(k+k)) for (int i=0;i<n-j-k;i++) if ((j+i)/(p+p)==(j+i+k)/(p+p)) exch(a,l+j+i,l+j+i+k); } public static void main(String[]args){ int a[]=new int[]{2,4,3,4,6,5,3}; batchsort(a,0,a.length-1); for (int i=0;i<a.length;i++){ System.out.println(a[i]); } } public static void exch(int a[],int i,int j){ int t=a[i]; a[i]=a[j]; a[j]=t; } } //result is 3 3 4 4 5 2 6 what i missed ? hat is wrong?

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• Java Swing Visual Editor HELP please

  - by bat

  How would i call this function in my main? private JFrame getMainpageframe1() { if (mainpageframe1 == null) { mainpageframe1 = new JFrame(); mainpageframe1.setSize(new Dimension(315, 306)); mainpageframe1.setContentPane(getMainpage()); mainpageframe1.setTitle("Shopping For Less: Main Page"); mainpageframe1.setVisible(true); mainpageframe1.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); } return mainpageframe1; } public static void main(String[] args) { //call that function to output the JFrame? } thanks

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• Set intersection of two strings

  - by user1785712

  import java.util.*; class set { public static void main(String args[]) { TreeSet<Character> t1 = new TreeSet<Character>(); TreeSet<Character> t2 = new TreeSet<Character>(); String s1 = "Ambitab bachan"; String s2 = "Ranjikanth"; for(char c1:s1.toCharArray()) t1.add(c1); for(char c2:s2.toCharArray()) t2.add(c2); t2.retainAll(t1); System.out.println(t2); } } this program find the common character in two different string. in this program Treeset is used to store the value and retainAll() method is used to find the common characters. can anybody help me reduce the line of coding.thanks in advance

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• Simple Java math operations

  - by user1730056

  I'm making a BMI calculator that doesn't seem to be working. The math operations work if i just do something like w/h, but once i had the brackets, it returns an error. If i change the variables w and h and use a constant number, the operation works. Another problem is that although i'm making result a double, it seems to be rounding to the nearest int. Could someone tell me what I'm doing wrong here? public class ass10 { public static void main(String[] args) { bmi(223,100); } public static bmi(int w, int h){ double result; result = (w/(h*h))*703 System.out.println(result) } }

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• is the + in += on a Map a prefix operator of =?

  - by Steve

  In the book "Programming in Scala" from Martin Odersky there is a simple example in the first chapter: var capital = Map("US" -> "Washington", "France" -> "Paris") capital += ("Japan" -> "Tokyo") The second line can also be written as capital = capital + ("Japan" -> "Tokyo") I am curious about the += notation. In the class Map, I didn't found a += method. I was able to the same behaviour in an own example like class Foo() { def +(value:String) = { println(value) this } } object Main { def main(args: Array[String]) = { var foo = new Foo() foo = foo + "bar" foo += "bar" } } I am questioning myself, why the += notation is possible. It doesn't work if the method in the class Foo is called test for example. This lead me to the prefix notation. Is the + a prefix notation for the assignment sign (=)? Can somebody explain this behaviour?

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• C# - opening process and changing window position

  - by bartq

  I want to open from c# an application (standalone flashplayer) and set it position to (0,0) on the screen. How can I do this? So far I've managed to open flashplayer: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Diagnostics; namespace swflauncher { class Program { static void Main(string[] args) { Process flash = new Process(); flash.StartInfo.WindowStyle = ProcessWindowStyle.Normal; flash.StartInfo.FileName = "D:\\development\\flex4\\runtimes\\player\\10\\win\\FlashPlayer.exe"; flash.Start(); } } }

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