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  • C# Uploading files to file server

    - by JustFoo
    Hello All, Currently I have an application that receives an uploaded file from my web application. I now need to transfer that file to a file server which happens to be located on the same network (however this might not always be the case). I was attempting to use the webclient class in C# .NET. string filePath = "C:\\test\\564.flv"; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.28\\Files\\test.flv"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } The machine located at 192.168.1.28 is a file server and has a share c:\Files. As of right now I am receiving an error of Login failed bad user name or password, but I can open explorer and type in that path login successfully. I can also login using remote desktop, so I know the user account works. Any ideas on this error? Is it possible to transfer a file directly like that? With the webclient class or maybe some other class? Thanks

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  • Null file when uploading via MVC

    - by Josh
    I have the following form on an .NET MVC View: <form method="post" enctype="multipart/form-data" action="/Video/UploadDocument"> <input type="file" id="document1" name="document1"/> <input type="submit" value="Save"/> </form> And the controller has the following signature that gets called: public ActionResult UploadDocument(HttpPostedFileBase file) { return View(); } When I break inside the UploadDocument method, the parameter 'file' is null. I've selected a valid document on my desktop and know it contains text. What am I missing to get this file upload working?

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  • Uploading to S3 using Curl

    - by Carl Crawley
    Hi All, I'm currently using cURL to upload a file from my server to S3 using AJAX to call the script. So I have the following: $fullfilepath = '/server/sitepath/files/' . $_POST['file']; $upload_url = 'https://'.$_POST['buckets'].'.s3.amazonaws.com/'; $params = array( 'key'=>$_POST['key'], 'AWSAccessKeyId'=>$_POST['AWSAccessKeyId'], 'acl'=>$_POST['acl'], 'success_action_status'=>$_POST['success_action_status'], 'policy'=>$_POST['policy'], 'signature'=>$_POST['signature'], 'Content-Type'=>$_POST['Content-Type'], 'file'=>"@$fullfilepath" ); $ch = curl_init(); curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_URL, $upload_url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $params); $response = curl_exec($ch); curl_close($ch); echo $response; However, I'm getting an S3 error as follows when it posts and I'm unsure why because I'm not passing JSON to it. <?xml version="1.0" encoding="UTF-8"?> <Error><Code>InvalidPolicyDocument</Code><Message>Invalid Policy: Invalid JSON.</Message><RequestId>B29469C6151BE0E8</RequestId><HostId>BFPk6W2kt1b6hTtx0mEq6dWdN/IhO0gNR5bct//7LAOwJxm1C3PrxS4RPv1blzJ8</HostId></Error> I've googled it for the last hour or so and can't seem to figure it out. If I change the order of the Array fields, it gives me a different error - I believe the order of the posted fields is important somehow. any help would be much appreciated! C

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  • Move rotating image along Canvas

    - by fatnic
    Hi. I've managed to make an image rotate on my canvas. And I've managed to make an image move along the canvas. My problem now is making it do both. I have got it working but I seems a bit like a hack. I've posted a demo online Here's the code. var cnv = document.getElementById("drawing"); var c = cnv.getContext('2d'); var image = new Image(); image.src = 'images/spaceship.png'; var imgWidth = image.width; var imgHeight = image.height; var i=0; function animate() { c.clearRect(0,0,640,480); c.save(); c.translate(-(imgWidth/2)+i,200); c.rotate(i * Math.PI/180); c.translate(-(imgWidth/2),-(imgHeight/2)); c.drawImage(image, 0, 0); c.restore(); (i==640+imgWidth) ? i=0: i+=2; }; setInterval(animate, 1); I think my problem is I'm not understanding the translate() method properly. Is this the correct way to do it or am I competely way off?

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  • Javascript to PHP, mysql uploading, one button pressing solution

    - by user2897858
    my program is generating buttons from a mysql database.When one of the button is pressed, it would uplod the current time and the gps coordinate. Sadly, it only works if the same button is pressed twice, but its not an option, because the button has to dissappear. I would like to have some help in coding how to make that possible the user only need to press the button once for the correct upload.Thanks in advance Here is the full code of my my file: <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>title</title> </head> <?php $maidatum=date("Ymj"); echo "<script>getLocation();</script>"; //Az adatbázishoz való csatlakozás $conn = mysql_connect("localhost","root","asd"); if(!($conn))die("Nincs conn a kiszolgálóval!".mysql_error()); $adatbazisneve="schtrans"; mysql_select_db($adatbazisneve,$conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); //Combobox $sql = "SELECT Jaratszam,Vezeto FROM user"; $rs = mysql_query($sql) or die(mysql_error()); echo "<form action=\"\" method=\"post\">"; echo<<<nev <select name='Lista'> nev; while($row = mysql_fetch_array($rs)){ echo "<option value='".$row["Jaratszam"]."'>".$row["Vezeto"]."</option>"; }mysql_free_result($rs); echo "</select>"; ///Combox vége echo<<<lekerd <form action="" method="post"> <input type="submit" name="bekuldes" value="Lekérdez" /> </form> </form> lekerd; echo<<<gps <form action="" method="post"> <input type="hidden" name= "longitude" id="longitude"> <input type= "hidden" name ="latitude" id="latitude"> </form> gps; if(isset($_POST["bekuldes"])) { $jaratszam = $_POST['Lista']; $_SESSION['jaratsz']=$jaratszam; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } if(isset($_POST["ido"])) { $hanyadik=$_POST["ido"]; $longitudee="longitude$hanyadik"; $latitudee="latitude$hanyadik"; ?> <script> var x=document.getElementById("log"); function getLocation() { if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(showPosition); } else{x.innerHTML="GPS szolgáltatás nem müködik ezen a böngészon, kérlek értesítsd a rendszergazdát!";} } function showPosition(position) { var latitude = position.coords.latitude; var longitude = position.coords.longitude; document.getElementById("<?php echo $longitudee;?>").value = longitude; document.getElementById("<?php echo $latitudee;?>").value = latitude; } </script> <?php echo "<script>getLocation();</script>"; $latitude=$_POST["latitude"]; $longitude=$_POST["longitude"]; print_r($_POST); $currentime=date("H:i:s"); $acim=$_SESSION['adatok0'][$hanyadik]; $idofeltolt_parancs="UPDATE cim_$maidatum SET ido='$currentime',lat='$latitude',longi='$longitude' WHERE cimid='$acim';"; $feltoltes=mysql_query($idofeltolt_parancs, $conn) or die(mysql_error()); //tryy $jaratszam=$_SESSION['jaratsz']; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } mysql_close($conn); ?> </html>

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  • Uploading youtube videos through a common account

    - by Dave
    Is it possible to have users of my site upload videos from their home computers onto MY youtube account? What does that involve and can someone point me to some relevant examples. I DONT want to host the videos myself, even temporarily, unless completely unavoidable.These will be short videos though, maybe about a min or two long, not high def, so its not too unimaginable...

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  • Generated HTML word document not displaying image correctly

    - by spiderdijon
    I'm trying to add an image to a generated html word document that is embedded in a classic ASP page. The code looks something like this: <% Response.ContentType = "application/msword" %> <html xmlns:v="urn:schemas-microsoft-com:vml" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:w="urn:schemas-microsoft-com:office:word"> ... <v:shape id="_x0000_s1030" type="#_x0000_t75" style='position:absolute; left:0;text-align:left;margin-left:0;margin-top:17.95pt;width:7in;height:116.85pt; z-index:2;mso-position-horizontal:center;mso-position-horizontal-relative:page; mso-position-vertical-relative:page'> <v:imagedata src="http://xxx/image001.gif" o:title="image001"/> <w:wrap anchorx="page" anchory="page"/> <w:anchorlock/> </v:shape><![endif]--><![if !vml]><span style='mso-ignore:vglayout;position: absolute;z-index:0;left:0px;margin-left:0px;margin-top:24px;width:672px; height:156px'><img width=672 height=156 src="http://xxx/image001.gif" v:shapes="_x0000_s1030"></span><![endif]> The image URL is correct and can be viewed through a browser, however when the word document opens, the image has a red x, with the error message: The image cannot be displayed. Your computer may not have enough memory to open the image, or the image may be corrupted. Restart your computer, and then open the file again. If the red x still appears, you may have to delete the image and then insert it again. If i copy the html code and try to open the word document on my local machine, it displays the image correctly. It just doesn't work when retrieving the document from the server. This happens for any images I try to add. Is there another way to add images to html-generated word documents that can be output from an asp page? Thanks.

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  • css background image is being cut off..

    - by Ronedog
    I have an unordered list and the background image is being cut off when trying to place it next to the text. I'm using jquery to add the class to the anchor tag to display the image, and its working fine, the only problem is the image gets cut off. I've been playing around with the css, but can't seem to figure out how to make the image display properly...it seems like the < li is hiding the image behind it somehow...can I place the image in front of the < li to make it display...or am I missing something else? Can someone help me? Thanks. Here's the HTML: <ul id="nav> <li> <a class="folder_closed">Item 1</a> </li> </ul> Here's the CSS: ul#nav{ margin-left:0; margin-right:0; padding-left:0px; text-indent:15px; } #nav > li{ vertical-align: top; text-align:left; clear: both; margin-left:0px; margin-right:0px; padding-right:0px; padding-left:15px; } .folder_open{ position:relative; background-image: url(../images/maximize.png); background-repeat: no-repeat; background-position: -5px 1px; } .folder_closed{ position:relative; background-image: url(../images/minimize.png); background-repeat: no-repeat; background-position: -5px 1px; }

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  • asp.net C# uploading big file and processing it

    - by JewelThief
    I want to be able to upload file from my .aspx page to my web server so that it can be preocessed into a different format. e.g. user will upload a doc and in few seconds it would see a pdf version of the doc on the web page. I have web service available which can convert doc to pdf. now 1- how do i automate upload + conversion process. 2- how do i handle big files here. 3- how not to make user wait for all this thing to happen.

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  • Uploading file is not working

    - by VinTem
    I have done the following form <% form_for @anexo, :url => {:action => "create"}, :html => {:multpart => true} do |f| %> <%= f.error_messages %> <p> <%= f.label :descricao, "Descrição"%> <%= f.text_field :descricao %> </p> <p> <%= f.label :arquivo_anexo, "Arquivo Anexo" %> <%= f.file_field :arquivo_anexo %> </p> <p> <%= f.submit "Adicionar anexo" %> </p> <% end %> With a model like this: def arquivo_anexo=(novo_arqquivo) self.arquivo = novo_arquivo.read self.nome = File.basename(novo_arquivo.original_filename) self.content_type = novo_arquivo.content_type.chomp end But when I my file is not been sent through the form. When I check the params array using the debugger the data is not sent. Does anyone have any idea or sugestions? Thanks

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  • php and asp problem in uploading

    - by moustafa
    i have an ASP web services to change byte array that given from the client and change it to a file and save it in the web server the code is like this : [WebMethod] public string UploadFile(byte[] f, string fileName) { try { MemoryStream ms = new MemoryStream(f); String path="/myfile/"; String location=HttpContext.Current.Server.MapPath(path); FileStream fs = new FileStream(HttpContext.Current.Server.MapPath(path)+fileName, FileMode.Create); ms.WriteTo(fs); ms.Close(); fs.Close(); return "OK"; } catch (Exception ex) { return ex.Message.ToString(); } } the web services need byte array and file name.. i build the client in php upload.php the code is <html> <body> <form action="action1.php" method="post" enctype="multipart/form-data"> Pilih File Anda: <input type="file" name="myfile" /> <input type="submit" value="Upload" /> </form> </body> <html> and action1.php the code is: <?php require_once('nusoap.php'); $client = new nusoap_client('http://192.168.254.160/testuploadah/FileUploader.asmx?WSDL', 'wsdl','','', '', ''); $err = $client->getError(); if ($err) { echo '<h2>Constructor error</h2><pre>' . $err . '</pre>'; } if(is_uploaded_file($_FILES['myfile']['tmp_name'])){ $uploadFile = $_FILES['myfile']; ////how can read byte array of $uploadFile so i can send to web services??? ////are php only can send array or string ? $params[]->f=??????????????? $params[]->fileName=$_FILES['myfile']['name']; $result = $client->call('UploadFile', $params,'', '', false, true); if ($client->fault) { echo '<h2>Fault</h2><pre>'; print_r($result); echo '</pre>'; } else { //Check for errors $err = $client->getError(); if ($err) { //// Display the error echo '<h2>Error</h2><pre>' . $err . '</pre>'; } else { //// Display the result echo '<h2>Result</h2><pre>'; print_r($result); echo '</pre>'; } } } ?> how can i Send the byte array parameter to the web services,so the web services can started???? i still can resolve this problem,the web services always return an error because i can't send byte array

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  • A generic error occurred in GDI+, JPEG Image to MemoryStream

    - by madcapnmckay
    Hi, This seems to be a bit of an infamous error all over the web. So much so that I have been unable to find an answer to my problem as my scenario doesn't fit. An exception gets thrown when I save the image to the stream. Weirdly this works perfectly with a png but gives the above error with jpg and gif which is rather confusing. Most similar problem out there relate to saving images to files without permissions. Ironically the solution is to use a memory stream as I am doing.... public static byte[] ConvertImageToByteArray(Image imageToConvert) { using (var ms = new MemoryStream()) { ImageFormat format; switch (imageToConvert.MimeType()) { case "image/png": format = ImageFormat.Png; break; case "image/gif": format = ImageFormat.Gif; break; default: format = ImageFormat.Jpeg; break; } imageToConvert.Save(ms, format); return ms.ToArray(); } } More detail to the exception. The reason this causes so many issues is the lack of explanation :( System.Runtime.InteropServices.ExternalException was unhandled by user code Message="A generic error occurred in GDI+." Source="System.Drawing" ErrorCode=-2147467259 StackTrace: at System.Drawing.Image.Save(Stream stream, ImageCodecInfo encoder, EncoderParameters encoderParams) at System.Drawing.Image.Save(Stream stream, ImageFormat format) at Caldoo.Infrastructure.PhotoEditor.ConvertImageToByteArray(Image imageToConvert) in C:\Users\Ian\SVN\Caldoo\Caldoo.Coordinator\PhotoEditor.cs:line 139 at Caldoo.Web.Controllers.PictureController.Croppable() in C:\Users\Ian\SVN\Caldoo\Caldoo.Web\Controllers\PictureController.cs:line 132 at lambda_method(ExecutionScope , ControllerBase , Object[] ) at System.Web.Mvc.ActionMethodDispatcher.Execute(ControllerBase controller, Object[] parameters) at System.Web.Mvc.ReflectedActionDescriptor.Execute(ControllerContext controllerContext, IDictionary`2 parameters) at System.Web.Mvc.ControllerActionInvoker.InvokeActionMethod(ControllerContext controllerContext, ActionDescriptor actionDescriptor, IDictionary`2 parameters) at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClassa.<InvokeActionMethodWithFilters>b__7() at System.Web.Mvc.ControllerActionInvoker.InvokeActionMethodFilter(IActionFilter filter, ActionExecutingContext preContext, Func`1 continuation) InnerException: OK things I have tried so far. Cloning the image and working on that. Retrieving the encoder for that MIME passing that with jpeg quality setting. Please can anyone help.

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  • Change an Image while using JCrop

    - by Bathan
    Hi guys! Im working on a new feature in my site and I got stucked really bad. Im using JCrop obviously to crop an Image on my website. The new feature that I've been asked to Implement is to allow the user to change the colors of the Image being cropped. I have now 3 images , Color, GrayScale and Sepia. I can change the source of the image tag using javascript so the image gets changed without reload but I cannot do this once the JCrop has been enabled because it replaces the original Image for a new one. I thought I could disable JCrop, Replace the Image and then Re-Enable, but i couldnt do such thing. The example I found where the JCrop gets destroyed (example5 in Demo zip) uses an object : jcrop_api = $.Jcrop('#cropbox'); But Im enabling JCrop in a different manner,more like Example 3 : jQuery('#cropbox').Jcrop({ onChange: showPreview, onSelect: showPreview, aspectRatio: 1 }); How can I destroy JCrop so I can replace te Image? Is there another way to do this? Please help! I Could easily reload the page each time the user changes de color of the image but we all know that's not cool. Any comments will be apreciated. Thanks

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  • Uploading file to DropBox causing UnlinkedException

    - by Boardy
    I am currently working on android project and trying to enable DropBox functionality. I've selected the access type to App Only, and I can successfully authenticate and it creates an Apps directory and inside that creates a directory with the name of my app. When I then try to put a file in the DropBox directory it goes into the DropBoxException catch and in the logcat prints com.dropbox.client2.exception.DropboxUnlinkedException. I've done a google and from what I've seen this happens if the apps directory has been deleted and so authentication is required to be re-done, but this isn't the case, I have deleted it and I am putting the file straight after doing the authentication. Below is the code that retrieves the keys and stores the file on dropbox. AccessTokenPair tokens = getTokens(); UploadFile uploadFile = new UploadFile(context, common, this, mDBApi); uploadFile.execute(mDBApi); Below is the code for the getTokens method (don't think this would help but you never know) private AccessTokenPair getTokens() { AccessTokenPair tokens; SharedPreferences prefs = context.getSharedPreferences("prefs", 0); String key = prefs.getString("dropbox_key", ""); String secret = prefs.getString("dropbox_secret", ""); tokens = new AccessTokenPair(key, secret); return tokens; } Below is the class that extends the AsyncTask to perform the upload class UploadFile extends AsyncTask<DropboxAPI<AndroidAuthSession>, Void, bool> { Context context; Common common; Synchronisation sync; DropboxAPI<AndroidAuthSession> mDBApi; public UploadFile(Context context, Common common, Synchronisation sync, DropboxAPI<AndroidAuthSession> mDBApi) { this.context = context; this.common = common; this.sync = sync; this.mDBApi = mDBApi; } @Override protected bool doInBackground(DropboxAPI<AndroidAuthSession>... params) { try { File file = new File(Environment.getExternalStorageDirectory() + "/BoardiesPasswordManager/dropbox_sync.xml"); FileInputStream inputStream = new FileInputStream(file); Entry newEntry = mDBApi.putFile("android_sync.xml", inputStream, file.length(), null, null); common.showToastMessage("Successfully uploade Rev: " + newEntry.rev, Toast.LENGTH_LONG); } catch (IOException ex) { Log.e("DropBoxError", ex.toString()); } catch (DropboxException e) { Log.e("DropBoxError", e.toString()); e.printStackTrace(); } return null; } I have no idea why it would display the UnlinkedException so any help would be greatly appreciated.

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  • Mysql query trouble: uploading

    - by Jakub Zak
    I'm trying for last hour solve this problem. I have a long form and I'm trying to upload info into mysql database. Into table I made. This is the mysql query I'm using: mysql_query("INSERT INTO `users_temp`(`first_name`, `surname`, `birthday`, `nationality`, `email`, `mobile`, `landline`, `address`, `town`, `post_code`, `country`, `password`, `code_conf`) VALUES ([$f_name],[$s_name],[$bday],[$nationality],[$email],[$mobile],[$landline],[$address],[$town],[$post_code],[$country],[$pass],[$conf_code])"); If anyone see any problem why it doesn't work pls let me know. Thank you...

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  • Multiple File Selection For Uploading in ASP.NET

    - by IrfanRaza
    Hi Friends, There are several resources available on net to upload multiple files, but using multiple FileUpload controls. What I need to have multiple file selection dialog box so that user can select multiple files at one shot and then all files should be uploaded on one click. Anyone of you have any idea? Thanks in advance.

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  • Using DotNetOpenAuth AccessToken for uploading docx file to google

    - by PrashantC
    Hi , I am using DotNetOpenAuth Package, I am trying to upload a package to google docs, Using client credentials i am able to do it successfully using following code, DocumentEntry objDocumentEntry = new DocumentEntry(); objDocumentsService.setUserCredentials(strUserName,strPassWord); string strAuthenticationToken = objDocumentsService.QueryAuthenticationToken(); objDocumentEntry = objDocumentsService.UploadDocument(Server.MapPath("test.docx"), "New Name"); I want achieve save with plain oAuth, I am having following code written for it, if (this.TokenManager != null) { if (!IsPostBack) { var google = new WebConsumer(GoogleConsumer.ServiceDescription, this.TokenManager); // Is Google calling back with authorization? var accessTokenResponse = google.ProcessUserAuthorization(); if (accessTokenResponse != null) { this.AccessToken = accessTokenResponse.AccessToken; } else if (this.AccessToken == null) { // If we don't yet have access, immediately request it. GoogleConsumer.RequestAuthorization(google, GoogleConsumer.Applications.DocumentsList); } } } I successfully get "AccessToken", But i am not sure how to use it.. Do we need to exchange this token? what excatly to do with this token? Is it a sessionToken? Please provide some inputs, I am badly stuck with this problem from last 3 days, Prashant C

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  • Uploading multiple files using Spring MVC 3.0.2 after HiddenHttpMethodFilter has been enabled

    - by Tiny
    I'm using Spring version 3.0.2. I need to upload multiple files using the multiple="multiple" attribute of a file browser such as, <input type="file" id="myFile" name="myFile" multiple="multiple"/> (and not using multiple file browsers something like the one stated by this answer, it indeed works I tried). Although no versions of Internet Explorer supports this approach unless an appropriate jQuery plugin/widget is used, I don't care about it right now (since most other browsers support this). This works fine with commons fileupload but in addition to using RequestMethod.POST and RequestMethod.GET methods, I also want to use other request methods supported and suggested by Spring like RequestMethod.PUT and RequestMethod.DELETE in their own appropriate places. For this to be so, I have configured Spring with HiddenHttpMethodFilter which goes fine as this question indicates. but it can upload only one file at a time even though multiple files in the file browser are chosen. In the Spring controller class, a method is mapped as follows. @RequestMapping(method={RequestMethod.POST}, value={"admin_side/Temp"}) public String onSubmit(@RequestParam("myFile") List<MultipartFile> files, @ModelAttribute("tempBean") TempBean tempBean, BindingResult error, Map model, HttpServletRequest request, HttpServletResponse response) throws IOException, FileUploadException { for(MultipartFile file:files) { System.out.println(file.getOriginalFilename()); } } Even with the request parameter @RequestParam("myFile") List<MultipartFile> files which is a List of type MultipartFile (it can always have only one file at a time). I could find a strategy which is likely to work with multiple files on this blog. I have gone through it carefully. The solution below the section SOLUTION 2 – USE THE RAW REQUEST says, If however the client insists on using the same form input name such as ‘files[]‘ or ‘files’ and then populating that name with multiple files then a small hack is necessary as follows. As noted above Spring 2.5 throws an exception if it detects the same form input name of type file more than once. CommonsFileUploadSupport – the class which throws that exception is not final and the method which throws that exception is protected so using the wonders of inheritance and subclassing one can simply fix/modify the logic a little bit as follows. The change I’ve made is literally one word representing one method invocation which enables us to have multiple files incoming under the same form input name. It attempts to override the method protected MultipartParsingResult parseFileItems(List fileItems, String encoding) {} of the abstract class CommonsFileUploadSupport by extending the class CommonsMultipartResolver such as, package multipartResolver; import java.io.UnsupportedEncodingException; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import javax.servlet.ServletContext; import org.apache.commons.fileupload.FileItem; import org.springframework.util.StringUtils; import org.springframework.web.multipart.MultipartException; import org.springframework.web.multipart.MultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartResolver; final public class MultiCommonsMultipartResolver extends CommonsMultipartResolver { public MultiCommonsMultipartResolver() { } public MultiCommonsMultipartResolver(ServletContext servletContext) { super(servletContext); } @Override @SuppressWarnings("unchecked") protected MultipartParsingResult parseFileItems(List fileItems, String encoding) { Map<String, MultipartFile> multipartFiles = new HashMap<String, MultipartFile>(); Map multipartParameters = new HashMap(); // Extract multipart files and multipart parameters. for (Iterator it = fileItems.iterator(); it.hasNext();) { FileItem fileItem = (FileItem) it.next(); if (fileItem.isFormField()) { String value = null; if (encoding != null) { try { value = fileItem.getString(encoding); } catch (UnsupportedEncodingException ex) { if (logger.isWarnEnabled()) { logger.warn("Could not decode multipart item '" + fileItem.getFieldName() + "' with encoding '" + encoding + "': using platform default"); } value = fileItem.getString(); } } else { value = fileItem.getString(); } String[] curParam = (String[]) multipartParameters.get(fileItem.getFieldName()); if (curParam == null) { // simple form field multipartParameters.put(fileItem.getFieldName(), new String[] { value }); } else { // array of simple form fields String[] newParam = StringUtils.addStringToArray(curParam, value); multipartParameters.put(fileItem.getFieldName(), newParam); } } else { // multipart file field CommonsMultipartFile file = new CommonsMultipartFile(fileItem); if (multipartFiles.put(fileItem.getName(), file) != null) { throw new MultipartException("Multiple files for field name [" + file.getName() + "] found - not supported by MultipartResolver"); } if (logger.isDebugEnabled()) { logger.debug("Found multipart file [" + file.getName() + "] of size " + file.getSize() + " bytes with original filename [" + file.getOriginalFilename() + "], stored " + file.getStorageDescription()); } } } return new MultipartParsingResult(multipartFiles, multipartParameters); } } What happens is that the last line in the method parseFileItems() (the return statement) i.e. return new MultipartParsingResult(multipartFiles, multipartParameters); causes a compile-time error because the first parameter multipartFiles is a type of Map implemented by HashMap but in reality, it requires a parameter of type MultiValueMap<String, MultipartFile> It is a constructor of a static class inside the abstract class CommonsFileUploadSupport, public abstract class CommonsFileUploadSupport { protected static class MultipartParsingResult { public MultipartParsingResult(MultiValueMap<String, MultipartFile> mpFiles, Map<String, String[]> mpParams) { } } } The reason might be - this solution is about the Spring version 2.5 and I'm using the Spring version 3.0.2 which might be inappropriate for this version. I however tried to replace the Map with MultiValueMap in various ways such as the one shown in the following segment of code, MultiValueMap<String, MultipartFile>mul=new LinkedMultiValueMap<String, MultipartFile>(); for(Entry<String, MultipartFile>entry:multipartFiles.entrySet()) { mul.add(entry.getKey(), entry.getValue()); } return new MultipartParsingResult(mul, multipartParameters); but no success. I'm not sure how to replace Map with MultiValueMap and even doing so could work either. After doing this, the browser shows the Http response, HTTP Status 400 - type Status report message description The request sent by the client was syntactically incorrect (). Apache Tomcat/6.0.26 I have tried to shorten the question as possible as I could and I haven't included unnecessary code. How could be made it possible to upload multiple files after Spring has been configured with HiddenHttpMethodFilter? That blog indicates that It is a long standing, high priority bug. If there is no solution regarding the version 3.0.2 (3 or higher) then I have to disable Spring support forever and continue to use commons-fileupolad as suggested by the third solution on that blog omitting the PUT, DELETE and other request methods forever. Just curiously waiting for a solution and/or suggestion. Very little changes to the code in the parseFileItems() method inside the class MultiCommonsMultipartResolver might make it to upload multiple files but I couldn't succeed in my attempts (again with the Spring version 3.0.2 (3 or higher)).

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  • Uploading files to varbinary(max) in SQL Server -- works on one server, not the other

    - by pjabbott
    I have some code that allows users to upload file attachments into a varbinary(max) column in SQL Server from their web browser. It has been working perfectly fine for almost two years, but all of a sudden it stopped working. And it stopped working on only the production database server -- it still works fine on the development server. I can only conclude that the code is fine and there is something up with the instance of SQL Server itself. But I have no idea how to isolate the problem. I insert a record into the ATTACHMENT table, only inserting non-binary data like the title and the content type, and then chunk-upload the uploaded file using the following code: // get the file stream System.IO.Stream fileStream = postedFile.InputStream; // make an upload buffer byte[] fileBuffer; fileBuffer = new byte[1024]; // make an update command SqlCommand fileUpdateCommand = new SqlCommand("update ATTACHMENT set ATTACHMENT_DATA.WRITE(@Data, NULL, NULL) where ATTACHMENT_ID = @ATTACHMENT_ID", sqlConnection, sqlTransaction); fileUpdateCommand.Parameters.Add("@Data", SqlDbType.Binary); fileUpdateCommand.Parameters.AddWithValue("@ATTACHMENT_ID", newId); while (fileStream.Read(fileBuffer, 0, fileBuffer.Length) > 0) { fileUpdateCommand.Parameters["@Data"].Value = fileBuffer; fileUpdateCommand.ExecuteNonQuery(); <------ FAILS HERE } fileUpdateCommand.Dispose(); fileStream.Close(); Where it says "FAILS HERE", it sits for a while and then I get a SQL Server timeout error on the very first iteration through the loop. If I connect to the development database instead, everything works fine (it runs through the loop many, many times and the commit is successful). Both servers are identical (SQL Server 9.0.3042) and the schemas are identical as well. When I open Activity Monitor right after the timeout to see what's going it, it says the last command is (@Data binary(1024),@ATTACHMENT_ID decimal(4,0))update ATTACHMENT set ATTACHMENT_DATA.WRITE(@Data, NULL, NULL) where ATTACHMENT_ID = @ATTACHMENT_ID which I would expect but it also says it has a status of "Suspended" and a wait type of "PAGEIOLATCH_SH". I looked this up and it seems to be a bad thing but I can't find anything specific to my stuation. Ideas?

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  • uploading problem

    - by Syom
    i can't upload large files, but i've set php.ini max_execution_time = 3600 max_input_time = 600 memory_limit = 100M post_max_size = 100M file_uploads = On upload_max_filesize = 100M it returns a 500 error - [an error occurred while processing this directive] could you say why? thanks

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