Search Results

Search found 19350 results on 774 pages for 'mysql views'.

Page 82/774 | < Previous Page | 78 79 80 81 82 83 84 85 86 87 88 89  | Next Page >

  • EC2 Amazon Linux AMI MySQL CPU @ 62% When Idle?

    - by Jeff
    I am running MySQL on an Amazon Linux AMI. There is nothing connected to it. There are no connections and no other applications running that use MySQL. It is completely idle, but yet, top is reporting that mysql is using 62% of the CPU? Why is this happening and how do I fix it? Cpu(s): 0.2%us, 0.2%sy, 0.0%ni, 97.8%id, 0.0%wa, 0.0%hi, 0.0%si, 1.7%st Mem: 1738504k total, 390708k used, 1347796k free, 56888k buffers Swap: 917500k total, 0k used, 917500k free, 229804k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 2959 mysql 20 0 466m 39m 5244 S 62.2 2.3 4:00.67 mysqld 1 root 20 0 19252 1504 1212 S 0.0 0.1 0:00.20 init 2 root 20 0 0 0 0 S 0.0 0.0 0:00.00 kthreadd There are no connections... mysql> show processlist; +----+------+-----------+------+---------+------+-------+------------------+ | Id | User | Host | db | Command | Time | State | Info | +----+------+-----------+------+---------+------+-------+------------------+ | 5 | root | localhost | NULL | Query | 0 | NULL | show processlist | +----+------+-----------+------+---------+------+-------+------------------+

    Read the article

  • MySQL Connect in 4 Days - Sessions From Users and Customers

    - by Bertrand Matthelié
    72 1024x768 Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Cambria","serif";} Let’s review today the conference sessions where users and customers will describe their use of MySQL as well as best practices. Remember you can plan your schedule with Schedule Builder. Saturday, 11.30 am, Room Golden Gate 7: MySQL and Hadoop—Chris Schneider, Ning.com Saturday, 1.00 pm, Room Golden Gate 7: Thriving in a MySQL Replicated World—Ed Presz and Andrew Yee, Ticketmaster Saturday, 1.00 pm, Room Golden Gate 8: Rick’s RoTs (Rules of Thumb)—Rick James, Yahoo! Saturday, 2.30 pm, Room Golden Gate 3: Scaling Pinterest—Yashwanth Nelapati and Evrhet Milam, Pinterest Saturday, 4.00 pm, Room Golden Gate 3: MySQL Pool Scanner: An Automated Service for Host Management—Levi Junkert, Facebook Sunday, 10.15 am, Room Golden Gate 3: Big Data Is a Big Scam (Most of the Time)—Daniel Austin, PayPal Sunday, 11.45 am, Room Golden Gate 3: MySQL at Twitter: Development and Deployment—Jeremy Cole and Davi Arnaut, Twitter Sunday, 1.15 pm, Room Golden Gate 3: CERN’s MySQL-as-a-Service Deployment with Oracle VM: Empowering Users—Dawid Wojcik and Eric Grancher, DBA, CERN Sunday, 2.45 pm, Room Golden Gate 3: Database Scaling at Mozilla—Sheeri Cabral, Mozilla Sunday, 5.45 pm, Room Golden Gate 4: MySQL Cluster Carrier Grade Edition @ El Chavo, Latin America’s #1 Facebook Game—Carlos Morales, Playful Play You can check out the full program here as well as in the September edition of the MySQL newsletter. Not registered yet? You can still save US$ 300 over the on-site fee – Register Now!

    Read the article

  • MySQL documentation writer for MEM and Replication wanted!

    - by stefanhinz
    As MySQL is thriving and growing, we're looking for an experienced technical writer located in the UK or Ireland to join the MySQL documentation team. For this job, we need the best and most dedicated people around. You will be part of a geographically distributed documentation team responsible for the technical documentation of all MySQL products. Team members are expected to work independently, requiring discipline and excellent time-management skills as well as the technical facilities and experience to communicate across the Internet. Candidates should be prepared to work intensively with our engineers and support personnel. The overall team is highly distributed across different geographies and time zones. Our source format is DocBook XML. We're not just writing documentation, but also handling publication. This means you should be familiar with DocBook, and willing to learn our publication infrastructure. Your areas of responsibility would initially be MySQL Enterprise Monitor, and MySQL Replication. This means you should be familiar with MySQL in general, and preferably also with the MySQL Enterprise offerings. A MySQL certification will be considered an advantage. Other qualifications you should have: Native English speaker 5 or more years previous experience in writing software documentation Familiarity with distributed working environments and versioning systems such as SVN Comfortable with working on multiple operating systems, particularly Windows, Mac OS X, and Linux Ability to administer own workstations and test environment Excellent written and oral communication skills Ability to provide (online) samples of your work, e.g. books or articles If you're interested, contact me under [email protected]. For reference, the job offer can be viewed here.

    Read the article

  • Building MySQL with boost on windows

    - by user13177919
    As you've probably heard already MySQL needs boost to build. However, in the good ol' MySQL tradition, the above link does give you only the instructions on how to build it on linux. And completely ignores the fact that there're other OSes too that people develop on. To fill in that gap, I've compiled a small step by step guide on how to do it on windows. Note that I always, as a principle, build out-of-source. The typical setup I have is : bzr clone lp:~mysql/mysql-server/5.7 mysql-trunkcd mysql-trunkmkdir bldcd bldcmake -DWITH_DEBUG=1 -DMYSQL_PROJECT_NAME=mysql-trunk ..devenv /build debug mysql-trunk.sln This has been tested to work on a 32 bit compile using VS2013 on a Windows7 64 bit build. Note that you'll need other things too (bison, eventually openssl etc) that I will assume you already have set up. Steps: Download Boost 1.55.0. It's the *only* version that is known to work currently. Extract boost_1_55_0/ from the zip to c:\boost\boost_1_55_0 Go to Control Panel/System/Environment variables and set WITH_BOOST=C:\boost\boost_1_55_0 in User variables. Make sure you restart your open command line terminal windows after this !  If you're upgrading from non-boost build, remove your bld/ directory and create a new one. run cmake as you'd typically do. You should get: -- Local boost dir C:/boost/boost_1_55_0 -- Local boost zip LOCAL_BOOST_ZIP-NOTFOUND -- BOOST_VERSION_NUMBER is #define BOOST_VERSION 105500 -- BOOST_INCLUDE_DIR C:/boost/boost_1_55_0 Build as normal (devenv /build debug ...). It should work.

    Read the article

  • Using a comma seperated data in MYSQL "IN" clause

    - by Sashi Kant
    I have a column in one of my table where I store multiple ids seperated by comma's. Is there a way in which I can use this column's value in the "IN" clause of a query. The column(city) has values like 6,7,8,16,21,2 I need to use as Select * from table where e_ID in (Select city from locations where e_Id=?) I am satisfied with Crozin's answer, but I am open to suggestions, views and options. Feel free to share your views.

    Read the article

  • Rendering ASP.NET MVC Razor Views outside of MVC revisited

    - by Rick Strahl
    Last year I posted a detailed article on how to render Razor Views to string both inside of ASP.NET MVC and outside of it. In that article I showed several different approaches to capture the rendering output. The first and easiest is to use an existing MVC Controller Context to render a view by simply passing the controller context which is fairly trivial and I demonstrated a simple ViewRenderer class that simplified the process down to a couple lines of code. However, if no Controller Context is available the process is not quite as straight forward and I referenced an old, much more complex example that uses my RazorHosting library, which is a custom self-contained implementation of the Razor templating engine that can be hosted completely outside of ASP.NET. While it works inside of ASP.NET, it’s an awkward solution when running inside of ASP.NET, because it requires a bit of setup to run efficiently.Well, it turns out that I missed something in the original article, namely that it is possible to create a ControllerContext, if you have a controller instance, even if MVC didn’t create that instance. Creating a Controller Instance outside of MVCThe trick to make this work is to create an MVC Controller instance – any Controller instance – and then configure a ControllerContext through that instance. As long as an HttpContext.Current is available it’s possible to create a fully functional controller context as Razor can get all the necessary context information from the HttpContextWrapper().The key to make this work is the following method:/// <summary> /// Creates an instance of an MVC controller from scratch /// when no existing ControllerContext is present /// </summary> /// <typeparam name="T">Type of the controller to create</typeparam> /// <returns>Controller Context for T</returns> /// <exception cref="InvalidOperationException">thrown if HttpContext not available</exception> public static T CreateController<T>(RouteData routeData = null) where T : Controller, new() { // create a disconnected controller instance T controller = new T(); // get context wrapper from HttpContext if available HttpContextBase wrapper = null; if (HttpContext.Current != null) wrapper = new HttpContextWrapper(System.Web.HttpContext.Current); else throw new InvalidOperationException( "Can't create Controller Context if no active HttpContext instance is available."); if (routeData == null) routeData = new RouteData(); // add the controller routing if not existing if (!routeData.Values.ContainsKey("controller") && !routeData.Values.ContainsKey("Controller")) routeData.Values.Add("controller", controller.GetType().Name .ToLower() .Replace("controller", "")); controller.ControllerContext = new ControllerContext(wrapper, routeData, controller); return controller; }This method creates an instance of a Controller class from an existing HttpContext which means this code should work from anywhere within ASP.NET to create a controller instance that’s ready to be rendered. This means you can use this from within an Application_Error handler as I needed to or even from within a WebAPI controller as long as it’s running inside of ASP.NET (ie. not self-hosted). Nice.So using the ViewRenderer class from the previous article I can now very easily render an MVC view outside of the context of MVC. Here’s what I ended up in my Application’s custom error HttpModule: protected override void OnDisplayError(WebErrorHandler errorHandler, ErrorViewModel model) { var Response = HttpContext.Current.Response; Response.ContentType = "text/html"; Response.StatusCode = errorHandler.OriginalHttpStatusCode; var context = ViewRenderer.CreateController<ErrorController>().ControllerContext; var renderer = new ViewRenderer(context); string html = renderer.RenderView("~/Views/Shared/GenericError.cshtml", model); Response.Write(html); }That’s pretty sweet, because it’s now possible to use ViewRenderer just about anywhere in any ASP.NET application, not only inside of controller code. This also allows the constructor for the ViewRenderer from the last article to work without a controller context parameter, using a generic view as a base for the controller context when not passed:public ViewRenderer(ControllerContext controllerContext = null) { // Create a known controller from HttpContext if no context is passed if (controllerContext == null) { if (HttpContext.Current != null) controllerContext = CreateController<ErrorController>().ControllerContext; else throw new InvalidOperationException( "ViewRenderer must run in the context of an ASP.NET " + "Application and requires HttpContext.Current to be present."); } Context = controllerContext; }In this case I use the ErrorController class which is a generic controller instance that exists in the same assembly as my ViewRenderer class and that works just fine since ‘generically’ rendered views tend to not rely on anything from the controller other than the model which is explicitly passed.While these days most of my apps use MVC I do still have a number of generic pieces in most of these applications where Razor comes in handy. This includes modules like the above, which when they error often need to display error output. In other cases I need to generate string template output for emailing or logging data to disk. Being able to render simply render an arbitrary View to and pass in a model makes this super nice and easy at least within the context of an ASP.NET application!You can check out the updated ViewRenderer class below to render your ‘generic views’ from anywhere within your ASP.NET applications. Hope some of you find this useful.ResourcesViewRenderer Class in Westwind.Web.Mvc Library (Github)Original ViewRenderer ArticleRazor Hosting Library (GitHub)Original Razor Hosting Article© Rick Strahl, West Wind Technologies, 2005-2013Posted in ASP.NET  MVC   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

    Read the article

  • Pure Front end JavaScript with Web API versus MVC views with ajax

    - by eyeballpaul
    This was more a discussion for what peoples thoughts are these days on how to split a web application. I am used to creating an MVC application with all its views and controllers. I would normally create a full view and pass this back to the browser on a full page request, unless there were specific areas that I did not want to populate straight away and would then use DOM page load events to call the server to load other areas using AJAX. Also, when it came to partial page refreshing, I would call an MVC action method which would return the HTML fragment which I could then use to populate parts of the page. This would be for areas that I did not want to slow down initial page load, or areas that fitted better with AJAX calls. One example would be for table paging. If you want to move on to the next page, I would prefer it if an AJAX call got that info rather than using a full page refresh. But the AJAX call would still return an HTML fragment. My question is. Are my thoughts on this archaic because I come from a .net background rather than a pure front end background? An intelligent front end developer that I work with, prefers to do more or less nothing in the MVC views, and would rather do everything on the front end. Right down to web API calls populating the page. So that rather than calling an MVC action method, which returns HTML, he would prefer to return a standard object and use javascript to create all the elements of the page. The front end developer way means that any benefits that I normally get with MVC model validation, including client side validation, would be gone. It also means that any benefits that I get with creating the views, with strongly typed html templates etc would be gone. I believe this would mean I would need to write the same validation for front end and back end validation. The javascript would also need to have lots of methods for creating all the different parts of the DOM. For example, when adding a new row to a table, I would normally use the MVC partial view for creating the row, and then return this as part of the AJAX call, which then gets injected into the table. By using a pure front end way, the javascript would would take in an object (for, say, a product) for the row from the api call, and then create a row from that object. Creating each individual part of the table row. The website in question will have lots of different areas, from administration, forms, product searching etc. A website that I don't think requires to be architected in a single page application way. What are everyone's thoughts on this? I am interested to hear from front end devs and back end devs.

    Read the article

  • Kendo UI Mobile with Knockout for Master-Detail Views

    - by Steve Michelotti
    Lately I’ve been playing with Kendo UI Mobile to build iPhone apps. It’s similar to jQuery Mobile in that they are both HTML5/JavaScript based frameworks for buildings mobile apps. The primary thing that drew me to investigate Kendo UI was its innate ability to adaptively render a native looking app based on detecting the device it’s currently running on. In other words, it will render to look like a native iPhone app if it’s running on an iPhone and it will render to look like a native Droid app if it’s running on a Droid. This is in contrast to jQuery Mobile which looks the same on all devices and, therefore, it can never quite look native for whatever device it’s running on. My first impressions of Kendo UI were great. Using HTML5 data-* attributes to define “roles” for UI elements is easy, the rendering looked great, and the basic navigation was simple and intuitive. However, I ran into major confusion when trying to figure out how to “correctly” build master-detail views. Since I was already very family with KnockoutJS, I set out to use that framework in conjunction with Kendo UI Mobile to build the following simple scenario: I wanted to have a simple “Task Manager” application where my first screen just showed a list of tasks like this:   Then clicking on a specific task would navigate to a detail screen that would show all details of the specific task that was selected:   Basic navigation between views in Kendo UI is simple. The href of an <a> tag just needs to specify a hash tag followed by the ID of the view to navigate to as shown in this jsFiddle (notice the href of the <a> tag matches the id of the second view):   Direct link to jsFiddle: here. That is all well and good but the problem I encountered was: how to pass data between the views? Specifically, I need the detail view to display all the details of whichever task was selected. If I was doing this with my typical technique with KnockoutJS, I know exactly what I would do. First I would create a view model that had my collection of tasks and a property for the currently selected task like this: 1: function ViewModel() { 2: var self = this; 3: self.tasks = ko.observableArray(data); 4: self.selectedTask = ko.observable(null); 5: } Then I would bind my list of tasks to the unordered list - I would attach a “click” handler to each item (each <li> in the unordered list) so that it would select the “selectedTask” for the view model. The problem I found is this approach simply wouldn’t work for Kendo UI Mobile. It completely ignored the click handlers that I was trying to attach to the <a> tags – it just wanted to look at the href (at least that’s what I observed). But if I can’t intercept this, then *how* can I pass data or any context to the next view? The only thing I was able to find in the Kendo documentation is that you can pass query string arguments on the view name you’re specifying in the href. This enabled me to do the following: Specify the task ID in each href – something like this: <a href=”#taskDetail?id=3></a> Attach an “init method” (via the “data-show” attribute on the details view) that runs whenever the view is activated Inside this “init method”, grab the task ID passed from the query string to look up the item from my view model’s list of tasks in order to set the selected task I was able to get all that working with about 20 lines of JavaScript as shown in this jsFiddle. If you click on the Results tab, you can navigate between views and see the the detail screen is correctly binding to the selected item:   Direct link to jsFiddle: here.   With all that being done, I was very happy to get it working with the behavior I wanted. However, I have no idea if that is the “correct” way to do it or if there is a “better” way to do it. I know that Kendo UI comes with its own data binding framework but my preference is to be able to use (the well-documented) KnockoutJS since I’m already familiar with that framework rather than having to learn yet another new framework. While I think my solution above is probably “acceptable”, there are still a couple of things that bug me about it. First, it seems odd that I have to loop through my items to *find* my selected item based on the ID that was passed on the query string - normally, with Knockout I can just refer directly to my selected item from where it was used. Second, it didn’t feel exactly right that I had to rely on the “data-show” method of the details view to set my context – normally with Knockout, I could just attach a click handler to the <a> tag that was actually clicked by the user in order to set the “selected item.” I’m not sure if I’m being too picky. I know there are many people that have *way* more expertise in Kendo UI compared to me – I’d be curious to know if there are better ways to achieve the same results.

    Read the article

  • Which of the following relational database management systems would a company adopt (for migration), if any, MS Access, MS SQL Server or MySQL?

    - by Hassan Hagi
    Dear programmers, as part of my final year university project, I am conducting research into relational database management systems such as Microsoft Office Access 2007, Microsoft SQL Server 2008 and MySQL 5.1. The description does not need to be detailed however; I am trying to find empirical evidence and professional opinion/fact to determine which of the three databases are best suited for the required size of company (stated or unstated). OS: Microsoft windows (XP or newer) Please consider the following, but full details are not necessary: Memory management Migration Design constraints Integrity (data and others) Triggers User constraints Ease of use Performance Crash Recovery (not the operating system) Total Cost of Ownership (TCO) Also any info on Open source (to do with the three RDBMS) Thank you for your time and help. Hassan Hagi

    Read the article

  • 127.0.0.1:9051 doesnt work after apache, mysql, php installation?

    - by Rana Muhammad Waqas
    I have installed apache2, mysql, and php and now it doesnt let Vidalia run on localhost. i tried to change the TCP connection (controlport) to any other ip 192.168.0.40 and tried to change the default port 9051 to any other but that doesnt work. I thought apache is running so i used this command sudo service apache2 stop but that still doesnt work. So now when i type 127.0.0.1:9051 in browser it says and if i type only type 127.0.0.1 after stopping the apapche2 service with the command mentioned above it says unable to connect I am not sure what to do now Help!

    Read the article

  • The layout page "~/Views/Shared/_Layout.cshtml" could not be found

    - by Rei Brazilva
    I got this error and I can't figure out what is going on. I am positive the _layout.cshtml resides in the shared folder and for the sake of trying things out, I moved to the Home folder and it then told that the Views/Home/_Layout.cshtml couldn't be found there either. So now I'm thinking the problem is in the call for this file for some reason. I'm not going to pretend I know ASP.NET MVC4, so please when you answer, explain it as you would to someone who is not familiar with the system at all. Believe it or not, this error came from tutorial #1 ha ha Here's the code to show that I did code it right: @{ ViewBag.Title = "Home Page"; Layout = "~/Views/Shared/_Layout.cshtml"; } And here is a picture of the location p.s. I did my research, Google has nothing and there is another question here but it was asked on 2008 with MVC3 which is completely different I am running ASP.NET MVC4 on Azure Thanks

    Read the article

  • BizTalk 2010 - BAM Portal - No Views to Display

    - by Stuart Brierley
    Our latest BizTalk Server 2010 development project is utilising BizTalk as the integration ring around a new and sizable implementaion of Dynamics AX 2012. With this project we have decided to use BAM to monitor the processes within our various new applications.Although I have been specialising in BizTalk for around 9 years, this is my first time using BAM so it is an interesting process to be going through.Recently when deploying a solution I was attempting to check the BAM Portal to see that the View that I had created was properly deployed and that the Activity I was populating was being surfaced in the Portal as expected. Initially I was presented with the message "No view to display" in the "My Views" area of the BAM Portal landing page.This was because you need to set the permissions on the views that you want to see from the command line using the bm.exe tool:bm.exe add-account -AccountName:YourServerOrDomain\YourUsername -View:YourViewThis tool can be found in the BAM folder at the BizTalk installation location:C:\Program Files (x86)\Microsoft BizTalk Server 2010\Tracking

    Read the article

  • What is the best way to INSERT a large dataset into a MySQL database (or any database in general)

    - by Joe
    As part of a PHP project, I have to insert a row into a MySQL database. I'm obviously used to doing this, but this required inserting into 90 columns in one query. The resulting query looks horrible and monolithic (especially inserting my PHP variables as the values): INSERT INTO mytable (column1, colum2, ..., column90) VALUES ('value1', 'value2', ..., 'value90') and I'm concerned that I'm not going about this in the right way. It also took me a long (boring) time just to type everything in and testing writing the test code will be equally tedious I fear. How do professionals go about quickly writing and testing these queries? Is there a way I can speed up the process?

    Read the article

  • How can I make my Java desktop application to run on different computers in a network locally and updating same mysql database?

    - by JaMpa
    I have developed Java desktop application for registration of students in the computer laboratories in our college, but what I need is to make this application whenever it runs on any computer (Windows XP machines) on the laboratory each and every data filled by the college students goes to the same MySql database (through WAMP server) running on the server machine (Win Server 2003). Also, I need this application to run during booting of windows computers in the laboratory for the purpose when any student tries to switch on any PC in the comp lab before interfacing the desktop icons should sign in through user name and password when he has already registered or signing up in order for getting the access.

    Read the article

  • showing null rows using join

    - by Pradyut Bhattacharya
    Hi, In mysql i m selecting from a table shouts having a foreign key to another table named "roleuser" with the matching column as user_id Now the user_id column in the shouts table for some rows is null (not actually null but with no inserts in mysql) How to show all the rows of the shouts table either with user_id null or not I m executing the sql statement SELECT s.*, r.firstname, r.lastname FROM shouts s left join roleuser r where r.user_id = s.user_id limit 50; which does not executes and shows You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where r.user_id = s.user_id limit 50' at line 2 but using inner join the sql executes which shows rows which only have user_id values in the shouts table. the nulls are not shown. SELECT s.*, r.firstname, r.lastname FROM shouts s inner join roleuser r where r.user_id = s.user_id limit 50; How can i show all the rows from the shouts table and null values in the firstname and lastname columns where the user_id is null in the shouts table. If not at all possible with sql may be using stored procedures... Thanks Pradyut

    Read the article

  • Getting percentage of "Count(*)" to the number of all items in "GROUP BY"

    - by celalo
    Let's say I need to have the ratio of "number of items available from certain category" to "the the number of all items". Please consider a MySQL table like this: /* mysql> select * from Item; +----+------------+----------+ | ID | Department | Category | +----+------------+----------+ | 1 | Popular | Rock | | 2 | Classical | Opera | | 3 | Popular | Jazz | | 4 | Classical | Dance | | 5 | Classical | General | | 6 | Classical | Vocal | | 7 | Popular | Blues | | 8 | Popular | Jazz | | 9 | Popular | Country | | 10 | Popular | New Age | | 11 | Popular | New Age | | 12 | Classical | General | | 13 | Classical | Dance | | 14 | Classical | Opera | | 15 | Popular | Blues | | 16 | Popular | Blues | +----+------------+----------+ 16 rows in set (0.03 sec) mysql> SELECT Category, COUNT(*) AS Total -> FROM Item -> WHERE Department='Popular' -> GROUP BY Category; +----------+-------+ | Category | Total | +----------+-------+ | Blues | 3 | | Country | 1 | | Jazz | 2 | | New Age | 2 | | Rock | 1 | +----------+-------+ 5 rows in set (0.02 sec) */ What I need is basically a result set resembles this one: /* +----------+-------+-----------------------------+ | Category | Total | percentage to the all items | (Note that number of all available items is "9") +----------+-------+-----------------------------+ | Blues | 3 | 33 | (3/9)*100 | Country | 1 | 11 | (1/9)*100 | Jazz | 2 | 22 | (2/9)*100 | New Age | 2 | 22 | (2/9)*100 | Rock | 1 | 11 | (1/9)*100 +----------+-------+-----------------------------+ 5 rows in set (0.02 sec) */ How can I achieve such a result set in a single query? Thanks in advance.

    Read the article

  • Creating PHP strings using other variables...works manually, can't figure out how automatically

    - by Matt
    Hello, I'm trying to get a variable to be formed automatically using data pulled from a mysql database. I know the data is being pulled from the database in some form resembling its original form, but that data does not act the same as data that is manually typed and assigned to a string. For example, if a cell in a mysql table says... I said "goodbye" before I left. She also said "goodbye." ...and I manually copy/paste it and add the necessary escapes... $string1 = " I said \"goodbye\" before I left. She also said \"goodbye.\" "; ...that does not equal... $string1 = $mysqlResultArray['specificCellWithQuoteShownAbove'] Interestingly, if I echo both versions of $string1 and view the output, they appear to be exactly the same. But they do not function the same when put through various functions I've created. The functions only work if I do the manual copy/paste method--which is not what I want, obviously. I'm not sure if it has to do with the line breaks or the escapes--or some combination of the two. But while both strings are superficially the same, they are apparently functionally different and I don't know why. So how can I create $string1 without manually copy/pasting the contents from the mysql entry and instead querying for the data and assigning it to $string1 in such a way that it's exactly functionally equivalent as the manual copy/pasted string?

    Read the article

  • Ordering by number of rows?

    - by Rob
    Alright, so I have a table outputting data from a MySQL table in a while loop. Well one of the columns it outputs isn't stored statically in the table, instead it's the sum of how many times it appears in a different MySQL table. Sorry I'm not sure this is easy to understand. Here's my code: $query="SELECT * FROM list WHERE added='$addedby' ORDER BY time DESC"; $result=mysql_query($query); while($row=mysql_fetch_array($result, MYSQL_ASSOC)){ $loghwid = $row['hwid']; $sql="SELECT * FROM logs WHERE hwid='$loghwid' AND time < now() + interval 1 hour"; $query = mysql_query($sql) OR DIE(mysql_error()); $boots = mysql_num_rows($query); //Display the table } The above is the code displaying the table. As you can see it's grabbing data from two different MySQL tables. However I want to be able to ORDER BY $boots DESC. But as its a counting of a completely different table, I have no idea of how to go about doing that. I would appreciate any help, thank you.

    Read the article

  • multiple mysql_real_query() in while loop

    - by Steve
    It seems that when I have one mysql_real_query() function in a continuous while loop, the query will get executed OK. However, if multiple mysql_real_query() are inside the while loop, one right after the other. Depending on the query, sometimes neither the first query nor second query will execute properly. This seems like a threading issue to me. I'm wondering if the mysql c api has a way of dealing with this? Does anyone know how to deal with this? mysql_free_result() doesn't work since I am not even storing the results. //keep polling as long as stop character '-' is not read while(szRxChar != '-') { // Check if a read is outstanding if (HasOverlappedIoCompleted(&ovRead)) { // Issue a serial port read if (!ReadFile(hSerial,&szRxChar,1, &dwBytesRead,&ovRead)) { DWORD dwErr = GetLastError(); if (dwErr!=ERROR_IO_PENDING) return dwErr; } } // Wait 5 seconds for serial input if (!(HasOverlappedIoCompleted(&ovRead))) { WaitForSingleObject(hReadEvent,RESET_TIME); } // Check if serial input has arrived if (GetOverlappedResult(hSerial,&ovRead, &dwBytesRead,FALSE)) { // Wait for the write GetOverlappedResult(hSerial,&ovWrite, &dwBytesWritten,TRUE); //load tagBuffer with byte stream tagBuffer[i] = szRxChar; i++; tagBuffer[i] = 0; //char arrays are \0 terminated //run query with tagBuffer if( strlen(tagBuffer)==PACKET_LENGTH ) { sprintf(query,"insert into scan (rfidnum) values ('"); strcat(query, tagBuffer); strcat(query, "')"); mysql_real_query(&mysql,query,(unsigned int)strlen(query)); i=0; } mysql_real_query(&mysql,"insert into scan (rfidnum) values ('2nd query')",(unsigned int)strlen("insert into scan (rfid) values ('2nd query')")); mysql_free_result(res); } }

    Read the article

  • MySQL Interview Questions

    - by Campbell
    Hi, I've been asked to screen some candidates for a MySQL DBA / Developer position for a role that requires an enterprise level skill set. I myself am a SQL Server person so I know what I would be looking for from that point of view with regards to scalability / design etc but is there anything specific I should be asking with regards to MySQL? I would ideally like to ask them about enterprise level features of MySQL that they would typically only use when working on a big database. Need to separate out the enterprise developers from the home / small website kind of guys. Thanks.

    Read the article

  • Can I force MySql table name case sensitivity on file systems that aren't case sensitive

    - by Brian Deacon
    So our target environment is linux, making mysql case-sensitive by default. I am aware that we can make our linux environment not case sensitive with the lower_case_table_names variable, but we would rather not. We have a few times been bitten with a case mismatch because our dev rigs are OSX, and mysql is not case sensitive there. Is there a way we can force table names to be case sensitive on my OSX install of MySql (5.0.83 if that matters) so that we catch a table name case mismatch prior to deploying to the integration servers running on linux?

    Read the article

  • Cassandra or mysql 5

    - by saturngod
    Should I use cassandra in 100,000 users project ? In mysql 5 have full text search and partition table. I'm starting to make Question and answer system like stackoverflow with CodeIgniter. It's move from vbulletin to new system. In old vbulletin have around 100,000 users and total post is around 80,000. In next 3 or 4 year, users and posts will be more and more. So, Should I use cassandra instead of mysql 5 ? If I use cassandra, I need to change gridserver in mediatemple to DV server in mediatemple. Cassandra is not built in hosting system. So, I must use VPS or DV server. If I use mysql 5, hosting is not problem but how about speed and search. Btw, What database using in Stack Over ?

    Read the article

  • Mysql gem troubles with Snow Leopard upgrade

    - by so1o
    I have done everything that is on the web (i think) i have the new 64 bit xcode that came with snow leopard installed completely removed mysql, removed gems compeltely, removed rails installed mysql 64 bit, installed gems, installed mysql gem with the env ARCHFLAGS set I still get this nasty NameError: uninitialized constant MysqlCompat::MysqlRes from /Users/Navara/Sites/tuosystems/vendor/rails/activesupport/lib/active_support/dependencies.rb:440:in `load_missing_constant' from /Users/Navara/Sites/tuosystems/vendor/rails/activesupport/lib/active_support/dependencies.rb:80:in `rake_original_const_missing' from /usr/local/lib/ruby/gems/1.8/gems/rake-0.8.7/lib/rake.rb:2503:in `const_missing' Im not sure how to debug this.. any pointers will be greatly appreciated!

    Read the article

  • Passing object from PHP to Mysql Stored procedure

    - by user268982
    Hi All, Scenario :- I have to call MYSQL stored procedure from PHP and do some operations ( around 15 commands ) on the database Problem :- I have to call stored procedure with 36 parameters. Lot of parameters . I don't think it is a good idea to pass these many individual parameters and even heard passing individul parameters increases network traffic. Looking for :- I created a Data Object at PHP side and is there any way I can create similar kind of Object in MYSQL and pass this object as a parameter and extract the data from the object in MYSQL stored procedure Thanks for your help Regards Kiran

    Read the article

  • PHP, MySQL, and temporary tables

    - by dave
    Php novice. 1.Is there anything wrong with this PHP & MySQL code? include_once "db_login.php" ; $sql = "DROP TEMPORARY TABLE IF EXISTS temp_sap_id_select" ; mysql_query ( $sql ) or ( "Error " . mysql_error () ) ; $sql = " CREATE TEMPORARY TABLE temp_sap_id_select ( `current_page` INT NOT NULL, `total_pages` INT NOT NULL, `select_date` DATE NOT NULL, `select_schcode` CHAR(6) NOT NULL, `select_user` CHAR(30) NOT NULL, `select_id` CHAR(9) NOT NULL ) " ; mysql_query ( $sql ) or ( "Error " . mysql_error () ) ; 2.Admittedly, I'm a dull boy, but I'll ask anyway: If I'm using a MySQL GUI and have open the target database, will it be aware of the above temporary table created by PHP/MySQL (IF the temporary table is properly created)?

    Read the article

< Previous Page | 78 79 80 81 82 83 84 85 86 87 88 89  | Next Page >