Search Results

Search found 64010 results on 2561 pages for 'google app engine python'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 820/2561 | < Previous Page | 816 817 818 819 820 821 822 823 824 825 826 827  | Next Page >

  • How to accept localized date format (e.g dd/mm/yy) in a DateField on an admin form ?

    - by tomjerry
    Is it possible to customize a django application to have accept localized date format (e.g dd/mm/yy) in a DateField on an admin form ? I have a model class : class MyModel(models.Model): date = models.DateField("Date") And associated admin class class MyModelAdmin(admin.ModelAdmin): pass On django administration interface, I would like to be able to input a date in following format : dd/mm/yyyy. However, the date field in the admin form expects yyyy-mm-dd. How can I customize things ? Nota bene : I have already specified my custom language code (fr-FR) in settings.py, but it seems to have no effect on this date input matter. Thanks in advance for your answer

    Read the article

  • Infinite loop when adding a row to a list in a class in python3

    - by Margaret
    I have a script which contains two classes. (I'm obviously deleting a lot of stuff that I don't believe is relevant to the error I'm dealing with.) The eventual task is to create a decision tree, as I mentioned in this question. Unfortunately, I'm getting an infinite loop, and I'm having difficulty identifying why. I've identified the line of code that's going haywire, but I would have thought the iterator and the list I'm adding to would be different objects. Is there some side effect of list's .append functionality that I'm not aware of? Or am I making some other blindingly obvious mistake? class Dataset: individuals = [] #Becomes a list of dictionaries, in which each dictionary is a row from the CSV with the headers as keys def field_set(self): #Returns a list of the fields in individuals[] that can be used to split the data (i.e. have more than one value amongst the individuals def classified(self, predicted_value): #Returns True if all the individuals have the same value for predicted_value def fields_exhausted(self, predicted_value): #Returns True if all the individuals are identical except for predicted_value def lowest_entropy_value(self, predicted_value): #Returns the field that will reduce <a href="http://en.wikipedia.org/wiki/Entropy_%28information_theory%29">entropy</a> the most def __init__(self, individuals=[]): and class Node: ds = Dataset() #The data that is associated with this Node links = [] #List of Nodes, the offspring Nodes of this node level = 0 #Tree depth of this Node split_value = '' #Field used to split out this Node from the parent node node_value = '' #Value used to split out this Node from the parent Node def split_dataset(self, split_value): fields = [] #List of options for split_value amongst the individuals datasets = {} #Dictionary of Datasets, each one with a value from fields[] as its key for field in self.ds.field_set()[split_value]: #Populates the keys of fields[] fields.append(field) datasets[field] = Dataset() for i in self.ds.individuals: #Adds individuals to the datasets.dataset that matches their result for split_value datasets[i[split_value]].individuals.append(i) #<---Causes an infinite loop on the second hit for field in fields: #Creates subnodes from each of the datasets.Dataset options self.add_subnode(datasets[field],split_value,field) def add_subnode(self, dataset, split_value='', node_value=''): def __init__(self, level, dataset=Dataset()): My initialisation code is currently: if __name__ == '__main__': filename = (sys.argv[1]) #Takes in a CSV file predicted_value = "# class" #Identifies the field from the CSV file that should be predicted base_dataset = parse_csv(filename) #Turns the CSV file into a list of lists parsed_dataset = individual_list(base_dataset) #Turns the list of lists into a list of dictionaries root = Node(0, Dataset(parsed_dataset)) #Creates a root node, passing it the full dataset root.split_dataset(root.ds.lowest_entropy_value(predicted_value)) #Performs the first split, creating multiple subnodes n = root.links[0] n.split_dataset(n.ds.lowest_entropy_value(predicted_value)) #Attempts to split the first subnode.

    Read the article

  • Programmatically sync the db in Django

    - by Attila Oláh
    I'm trying to sync my db from a view, something like this: from django import http from django.core import management def syncdb(request): management.call_command('syncdb') return http.HttpResponse('Database synced.') The issue is, it will block the dev server by asking for user input from the terminal. How can I pass it the '--noinput' option to prevent asking me anything? I have other ways of marking users as super-user, so there's no need for the user input, but I really need to call syncdb (and flush) programmatically, without logging on to the server via ssh. Any help is appreciated.

    Read the article

  • grabbing a substring while scraping with Python2.6

    - by Diego
    Hey can someone help with the following? I'm trying to scrape a site that has the following information.. I need to pull just the number after the </strong> tag.. [<li><strong>ISBN-13:</strong> 9780375853401</li>, <li><strong>Pub. Date: </strong> 05/11/2010</li>] [<li><strong>UPC:</strong> 490355000372</li>, <li><strong>Catalog No:</strong> 15024/25</li>, <li><strong>Label:</strong> CAMERATA</li>] here's a piece of the code I've been using to grab the above data using mechanize and BeautifulSoup. I'm stuck here as it won't let me use the find() function for a list br_results = mechanize.urlopen(br_results) html = br_results.read() soup = BeautifulSoup(html) local_links = soup.findAll("a", {"class" : "down-arrow csa"}) upc_code = soup.findAll("ul", {"class" : "bc-meta3"}) for upc in upc_code: upc_text = upc.contents.contents print upc_text

    Read the article

  • how to fill a part of a circle using PIL?

    - by valya
    hello. I'm trying to use PIL for a task but the result is very dirty. What I'm doing is trying to fill a part of a piece of a circle, as you can see on the image. Here is my code: def gen_image(values): side = 568 margin = 47 image = Image.open(settings.MEDIA_ROOT + "/i/promo_circle.jpg") draw = ImageDraw.Draw(image) draw.ellipse((margin, margin, side-margin, side-margin), outline="white") center = side/2 r = side/2 - margin cnt = len(values) for n in xrange(cnt): angle = n*(360.0/cnt) - 90 next_angle = (n+1)*(360.0/cnt) - 90 nr = (r * values[n] / 5) max_r = r min_r = nr for cr in xrange(min_r*10, max_r*10): cr = cr/10.0 draw.arc((side/2-cr, side/2-cr, side/2+cr, side/2+cr), angle, next_angle, fill="white") return image

    Read the article

  • csrf error in django

    - by niklasfi
    Hello, I want to realize a login for my site. I basically copied and pasted the following bits from the Django Book together. However I still get an error (CSRF verification failed. Request aborted.), when submitting my registration form. Can somebody tell my what raised this error and how to fix it? Here is my code: views.py: # Create your views here. from django import forms from django.contrib.auth.forms import UserCreationForm from django.http import HttpResponseRedirect from django.shortcuts import render_to_response def register(request): if request.method == 'POST': form = UserCreationForm(request.POST) if form.is_valid(): new_user = form.save() return HttpResponseRedirect("/books/") else: form = UserCreationForm() return render_to_response("registration/register.html", { 'form': form, }) register.html: <html> <body> {% block title %}Create an account{% endblock %} {% block content %} <h1>Create an account</h1> <form action="" method="post">{% csrf_token %} {{ form.as_p }} <input type="submit" value="Create the account"> </form> {% endblock %} </body> </html>

    Read the article

  • Difference between internet and Desktop jave EE app server

    - by immer
    Hello. I need some clarification. I know that in order to run a java EE project, one needs a java EE compliant application server, such as tomcat, jboss, glashfish, etc. But, i download these to my desktop, but how about when i run it online? Are Jboss, tomcat, glashfish, etc. application servers just for your desktop, or are these the app server internet service providers have as well. I am trying to use godaddy as my internet service provider; i called them, but the customer service guy didnt know what application server they had, or did i ask the wrong question? Or how can i know waht application server they have? Thank you, any help is greatly appreciated.

    Read the article

  • Accented characters in matplotlib

    - by OldJim
    Does anyone know a way to get matplotlib to render accented chars (é,ã,â,etc)? For instance i'm trying to use accented chars on set_yticklabels() and matplot renders squares instead, and when i use unicode() it renders the wrong chars. Is there a way to make this work? Thanks in advance, Jim.

    Read the article

  • List Directories and get the name of the Directory

    - by chrissygormley
    Hello, I am trying to get the code to list all the directories in a folder, change directory into that folder and get the name of the current folder. The code I have so far is below and isn't working at the minute. I seem to be getting the parent folder name. import os for directories in os.listdir(os.getcwd()): dir = os.path.join('/home/user/workspace', directories) os.chdir(dir) current = os.path.dirname(dir) new = str(current).split("-")[0] print new I also have other files in the folder but I do not want to list them. I have tried the below code but I haven't got it working yet either. for directories in os.path.isdir(os.listdir(os.getcwd())): Can anyone see where I am going wrong? Thanks

    Read the article

  • Performing non-blocking requests? - Django

    - by RadiantHex
    Hi folks, I have been playing with other frameworks, such as NodeJS, lately. I love the possibility to return a response, and still being able to do further operations. e.g. def view(request): do_something() return HttpResponse() do_more_stuff() #not possible!!! Maybe Django already offers a way to perform operations after returning a request, if that is the case that would be great. Help would be very much appreciated! =D

    Read the article

  • How can I use a config-file in Expression Blend 4?

    - by sofri
    Hi, while trying to use the "InfoStrat"-Bing-Maps-Control in Expression Blend 4 for my Surface Application, I get the error message: "Mixed mode assembly is built against version v2.0.50527 of the runtime and cannot be loaded in the 4.0 runtime without additional configuration information" I already found out that I need to write this configfile: <configuration> <startup useLegacyV2RuntimeActivationPolicy="true"> <supportedRuntime version="v4.0"/> </startup> </configuration> But Expression Blend doesn't seem to recognize that it is there. So how can I solve this problem?

    Read the article

  • Django: Geocoding an address on form submission?

    - by User
    Trying to wrap my head around django forms and the django way of doing things. I want to create a basic web form that allows a user to input an address and have that address geocoded and saved to a database. I created a Location model: class Location(models.Model): address = models.CharField(max_length=200) city = models.CharField(max_length=100) state = models.CharField(max_length=100, null=True) postal_code = models.CharField(max_length=100, null=True) country = models.CharField(max_length=100) latitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) longitude = models.DecimalField(max_digits=18, decimal_places=10, null=True) And defined a form: class LocationForm(forms.ModelForm): class Meta: model = models.Location exclude = ('latitude','longitude') In my view I'm using form.save() to save the form. This works and saves an address to the database. I created a module to geocode an address. I'm not sure what the django way of doing things is, but I guess in my view, before I save the form, I need to geocode the address and set the lat and long. How do I set the latitude and longitude before saving?

    Read the article

  • Django: Applying Calculations To A Query Set

    - by TheLizardKing
    I have a QuerySet that I wish to pass to a generic view for pagination: links = Link.objects.annotate(votes=Count('vote')).order_by('-created')[:300] This is my "hot" page which lists my 300 latest submissions (10 pages of 30 links each). I want to now sort this QuerySet by an algorithm that HackerNews uses: (p - 1) / (t + 2)^1.5 p = votes minus submitter's initial vote t = age of submission in hours Now because applying this algorithm over the entire database would be pretty costly I am content with just the last 300 submissions. My site is unlikely to be the next digg/reddit so while scalability is a plus it is required. My question is now how do I iterate over my QuerySet and sort it by the above algorithm? For more information, here are my applicable models: class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Notes: I don't have "downvotes" so just the presence of a Vote row is an indicator of a vote or a particular link by a particular user.

    Read the article

  • How do i add a new object with suds?

    - by Jerome
    I'm trying to use suds but have so far been unsuccessful at figuring this out. Hopefully it's something simple that i'm missing. Any help would be highly appreciated. This is supposed to be the raw soap message that i need to achieve: <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:api="http://api.service.apimember.soapservice.com/"> <soapenv:Header/> <soapenv:Body> <api:insertOrUpdateMemberByObj> <token>t67GFCygjhkjyUy8y9hkjhlkjhuii</token> <member> <dynContent> <entry> <key>FIRSTNAME</key> <value>hhhhbbbbb</value> </entry> </dynContent> <email>[email protected]</email> </member> </api:insertOrUpdateMemberByObj> </soapenv:Body> </soapenv:Envelope> So i use suds to create the member object: member = client.factory.create('member') produces: (apiMember){ attributes = (attributes){ entry[] = <empty> } } How exactly do i append an 'entry'? I try this: member.attributes.entry.append({'key':'FIRSTNAME','value':'test'}) and that produces this: (apiMember){ attributes = (attributes){ entry[] = { value = "test" key = "FIRSTNAME" }, } } However, what i actually need is: (apiMember){ attributes = (attributes){ entry[] = (entry) { value = "test" key = "FIRSTNAME" }, } } How do i achieve this?

    Read the article

  • CherryPy and RESTful web api

    - by hyperboreean
    What's the best approach of creating a RESTful web api in CherryPy? I've been looking around for a few days now and nothing seems great. For Django it seems that are lots of tools to do this, but not for CherryPy or I am not aware of them

    Read the article

  • Most efficient way to update attribute of one instance

    - by Begbie00
    Hi all - I'm creating an arbitrary number of instances (using for loops and ranges). At some event in the future, I need to change an attribute for only one of the instances. What's the best way to do this? Right now, I'm doing the following: 1) Manage the instances in a list. 2) Iterate through the list to find a key value. 3) Once I find the right object within the list (i.e. key value = value I'm looking for), change whatever attribute I need to change. for Instance within ListofInstances: if Instance.KeyValue == SearchValue: Instance.AttributeToChange = 10 This feels really inefficient: I'm basically iterating over the entire list of instances, even through I only need to change an attribute in one of them. Should I be storing the Instance references in a structure more suitable for random access (e.g. dictionary with KeyValue as the dictionary key?) Is a dictionary any more efficient in this case? Should I be using something else? Thanks, Mike

    Read the article

  • PyParsing: Not all tokens passed to setParseAction()

    - by Rosarch
    I'm parsing sentences like "CS 2110 or INFO 3300". I would like to output a format like: [[("CS" 2110)], [("INFO", 3300)]] To do this, I thought I could use setParseAction(). However, the print statements in statementParse() suggest that only the last tokens are actually passed: >>> statement.parseString("CS 2110 or INFO 3300") Match [{Suppress:("or") Re:('[A-Z]{2,}') Re:('[0-9]{4}')}] at loc 7(1,8) string CS 2110 or INFO 3300 loc: 7 tokens: ['INFO', 3300] Matched [{Suppress:("or") Re:('[A-Z]{2,}') Re:('[0-9]{4}')}] -> ['INFO', 3300] (['CS', 2110, 'INFO', 3300], {'Course': [(2110, 1), (3300, 3)], 'DeptCode': [('CS', 0), ('INFO', 2)]}) I expected all the tokens to be passed, but it's only ['INFO', 3300]. Am I doing something wrong? Or is there another way that I can produce the desired output? Here is the pyparsing code: from pyparsing import * def statementParse(str, location, tokens): print "string %s" % str print "loc: %s " % location print "tokens: %s" % tokens DEPT_CODE = Regex(r'[A-Z]{2,}').setResultsName("DeptCode") COURSE_NUMBER = Regex(r'[0-9]{4}').setResultsName("CourseNumber") OR_CONJ = Suppress("or") COURSE_NUMBER.setParseAction(lambda s, l, toks : int(toks[0])) course = DEPT_CODE + COURSE_NUMBER.setResultsName("Course") statement = course + Optional(OR_CONJ + course).setParseAction(statementParse).setDebug()

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 816 817 818 819 820 821 822 823 824 825 826 827  | Next Page >