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  • How to reference another project in Eclipse with Google appengine project?

    - by virsir
    I am trying to extract some common classes out to be a common jar, and I want to reference it by the appengine project in Eclipse. It compiles well but could not run. The console just told that some classes from the common jar project could not be found. I know I can just export the project into a jar, but I may want to change it sometimes, so I prefer keep it dynamic. And I know maven may be an option but there is no official maven support for appengine, and I will not try to learn it. Then how can I make it work?

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  • Does the JPQL avg aggregate function work with Integers?

    - by Kyle Renfro
    I have a JPA 2 Entity named Surgery. It has a member named transfusionUnits that is an Integer. There are two entries in the database. Executing this JPQL statement: Select s.transfusionUnits from Surgery s produces the expected result: 2 3 The following statement produces the expected answer of 5: Select sum(s.transfusionUnits) from Surgery s I expect the answer of the following statement to be 2.5, but it returns 2.0 instead. Select avg(s.transfusionUnits) from Surgery s If I execute the statement on a different (Float) member, the result is correct. Any ideas on why this is happening? Do I need to do some sort of cast in JPQL? Is this even possible? Surely I am missing something trivial here.

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  • Can Hibernate default a Null String to Empty String

    - by sliver
    In our application we are pulling data from a DB2 mainframe database. If the database has "low values" in a field, hibernate sends a "null" value in the object. This occurs even if the column is defined as "not null". As we are doing XML parsing on this, Castor is having trouble with it. I would like to fix this in Hibernate. Also, all of the hibernate hbm files are generated, so we can't mess with them (they are regened from time to time.) Any way to intercept all Strings and replace nulls with ""?

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  • I Want to get a week value

    - by satya
    I wan to get the value of only one week. I am using the following JPA query: SELECT a FROM questions.dao.hibernate.Questions a WHERE (a.posted_date-CURRENT_DATE)>= 7 But I am getting an error message like org.hibernate.QueryException: could not resolve property: posted_date of: questions.dao.hibernate.Questions [SELECT a FROM questions.dao.hibernate.Questions a WHERE (a.posted_date-CURRENT_DATE)>=7] Please help me. Thanks

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  • OpenGL extensions available on different Android devices

    - by MH114
    I'm in the process of writing an OpenGL ES powered framework for my next Android game(s). Currently I'm supporting three different techniques of drawing sprites: the basic way: using vertex arrays (slow) using vertex-buffer-objects (VBOs) (faster) using the draw_texture extension (fastest, but only for basic sprites, i.e. no transforming) Vertex arrays are supported in OpenGL ES 1.0 and thus in every Android-device. I'm guessing most (if not all) of the current devices also support VBOs and draw_texture. Instead of guessing, I'd like to know the extensions supported by different devices. If majority of devices support VBOs, I could simplify my code and focus only on VBOs + draw_texture. It'd be helpful to know what different devices support, so if you have an Android-device, do report the extensions list please. :) String extensions = gl.glGetString(GL10.GL_EXTENSIONS); I've got a HTC Hero, so I can share those extensions next.

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  • Using inheritance and polymorphism to solve a common game problem

    - by Barry Brown
    I have two classes; let's call them Ogre and Wizard. (All fields are public to make the example easier to type in.) public class Ogre { int weight; int height; int axeLength; } public class Wizard { int age; int IQ; int height; } In each class I can create a method called, say, battle() that will determine who will win if an Ogre meets and Ogre or a Wizard meets a Wizard. Here's an example. If an Ogre meets an Ogre, the heavier one wins. But if the weight is the same, the one with the longer axe wins. public Ogre battle(Ogre o) { if (this.height > o.height) return this; else if (this.height < o.height) return o; else if (this.axeLength > o.axeLength) return this; else if (this.axeLength < o.axeLength) return o; else return this; // default case } We can make a similar method for Wizards. But what if a Wizard meets an Ogre? We could of course make a method for that, comparing, say, just the heights. public Wizard battle(Ogre o) { if (this.height > o.height) return this; else if (this.height < o.height) return o; else return this; } And we'd make a similar one for Ogres that meet Wizard. But things get out of hand if we have to add more character types to the program. This is where I get stuck. One obvious solution is to create a Character class with the common traits. Ogre and Wizard inherit from the Character and extend it to include the other traits that define each one. public class Character { int height; public Character battle(Character c) { if (this.height > c.height) return this; else if (this.height < c.height) return c; else return this; } } Is there a better way to organize the classes? I've looked at the strategy pattern and the mediator pattern, but I'm not sure how either of them (if any) could help here. My goal is to reach some kind of common battle method, so that if an Ogre meets an Ogre it uses the Ogre-vs-Ogre battle, but if an Ogre meets a Wizard, it uses a more generic one. Further, what if the characters that meet share no common traits? How can we decide who wins a battle?

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  • garbage collector Issue

    - by Eslam
    this question is like my previous one Given: 3. interface Animal { void makeNoise(); } 4. class Horse implements Animal { 5. Long weight = 1200L; 6. public void makeNoise() { System.out.println("whinny"); } 7. } 8. public class Icelandic extends Horse { 9. public void makeNoise() { System.out.println("vinny"); } 10. public static void main(String[] args) { 11. Icelandic i1 = new Icelandic(); 12. Icelandic i2 = new Icelandic(); 13. Icelandic i3 = new Icelandic(); 14. i3 = i1; i1 = i2; i2 = null; i3 = i1; 15. } 16. } When line 14 is reached, how many objects are eligible for the garbage collector? A. 0 B. 1 C. 2 D. 3 E. 4 F. 6 i choosed A but the right answer is E, but i don't know Why?

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  • Antlr MismatchedSetException During Interpretation

    - by user1646481
    I am new to Antlr and I have defined a basic grammar using Antlr 3. The grammar compiles and ANTLRWorks generates the Parser and Lexer code without any problems. The grammar can be seen below: grammar i; @header { package i; } module : 'Module1'| 'Module2'; object : 'I'; objectType : 'Name'; filters : EMPTY | 'WHERE' module; table : module object objectType; STRING : ('a'..'z'|'A'..'Z')+; EMPTY : ' '; The problem is that when I interpret the table Parser I get a MismatchedSetException. This is due to having the EMPTY. As soon as I remove EMPTY from the grammar, the interpretation works. I have looked on the Antlr website and some other examples and the Empty space is ' '. I am not sure what to do. I need this EMPTY. As soon as I change the EMPTY to be the following: EMPTY : ''; instead of: EMPTY : ' '; It actually interprets it. However, I am getting the following Exception: Interpreting... [10:57:23] problem matching token at 1:4 NoViableAltException(' '@[1:1: Tokens : ( T__4 | T__5 | T__6 | T__7 | T__8 | T__9 | T__10 | T__11 | T__12 | T__13 | T__14 | T__15 | T__16 );]) [10:57:23] problem matching token at 1:9 NoViableAltException(' '@[1:1: Tokens : ( T__4 | T__5 | T__6 | T__7 | T__8 | T__9 | T__10 | T__11 | T__12 | T__13 | T__14 | T__15 | T__16 );]) When I take out the EMPTY, there are no problems at all. I hope you can help.

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  • Display values inside a JList -

    - by sharon Hwk
    I have a method that returns a HashMap, and is defined as follows; public HashMap<Integer, Animal> allAnimal(){ return returnsAHashMap; } Animal will have the following values in its class: public Animal{ int animalID; String animalName; // i have declared getters/setters } I have a GUI screen which has a JList and it's defined as: l = new JList(); l.setModel(new AbstractListModel() { String[] v = new String[] {"animal id 1", "2", "3"}; public int getSize() { return v.length; } public Object getElementAt(int index) { return v[index]; } }); What I want to do is to display the AnimalID's in the JList. I need to find a way to call the allAnimal() method and display all its Animal Id's in the JList. How can i do this ?

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  • Smack API - How to display loop jxTaskpane for expand and collapse roster list

    - by MYE
    Hello everybody ! i have problem to display Taskpane for loop. i have a code to get the groups of roster (Groups : Friends - Business - Company, so on) my code is : Roster rost = xmppcon.getRoster(); Collection<RosterGroup> groups = rost.getGroups(); for(RosterGroup group : groups){ DefaultListModel model = new DefaultListModel(); model.addElement(group.getEntries()); String GroupNameCount = group.getName() + "("+group.getEntryCount()+")"; jXTaskPane1.setTitle(GroupNameCount); jXList1.setModel(model); } but jxTaskpane not loop, but when i print group name it print 2 line (because in database user A have two group is Friends and NIIT) sample print System.out.println(group.getName()); result: Friends NIIT

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  • How can I pipe a large amount of data as a runtime argument?

    - by Zombies
    Running an executable JAR on a linux platform here. The program it self works on a somewhat large amount of data, basically a list of URLs... could be up to 2k. Currently I get this from a simple DB call. But I was thinking that instead of creating a new mode and writing SQL to get a new result set and having to redploy everytime, I could just make the program more robust by passing in the result set (the list of URLs) that need to be worked on... so, within a linux environment, is there a pain-free/simple way to get the result set and pass it in dynamically? I know file i/o is one, but it doesn't seem to be effecient because each file has to be named, as well more logic to handle grabbing the correct file, creating a file with a unique name, etc.

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  • Wrap output of struts2 ServletDispatcherResult ?

    - by krosenvold
    I'd like to do much the same thing as the Struts2 sitemesh servlet-filter does, i.e. wrap the output of an action with some chosen content. The "problem" with the sitemesh approach is that it AFIK it does not have any relationship to the ActionInvocation, and I would like to be able to query information from the ActionInvocation when determining which content to add. I have looked through the ServletDispatcherResult, and I'm not entirly sure what's the best way to achieve this. Any suggestions ?

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  • How to make JTabbedPane autoresize to fit page dimensions?

    - by teamon
    I have only JTabbedPane inside JFrame. JTabbedPane sets its dimensions to biggest page width/height. As pages has different size is it possible to force JTabbedPane to change its dimensions when selecting other page? http://grab.by/3hIg Top one is how it behave now and bottom one is how i want it to behave (i resized frame by hand)

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  • Why won't this println command start a new line?

    - by David
    Here's the relevant code: public static void printBoarders (Territory x) { int t = 0 ; int n = 0 ; for (int i = 0; i<x.borders.length; i++) { if (x.borders[i] == -1) t = i ; } for (int j = 0; j<x.borders.length; j++) { if (x.borders[j] == 1) n++ ; } Territory.translate (t) ; System.out.print (" has " + n + " borders: ") ; Territory.translate (x.borders) ; System.out.println (" ") ; } When I run this, I get everything on one line without a line break. Why isn't the System.out.println (" ") ; creating a line break? Here is an example of what the output winds up being: Northwest Territory, Alberta, Kamchatka, hidavid-names-macbook-pro:~ davidname$ EDIT: the problem was that this method was never being invoked. A different one which i was replacing was. All is well.

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  • Can I close and reopen a socket?

    - by Roman
    I learned an example of usage of sockets. In this example a client sends a request to a server to open a socket and then the server (listening to a specific port) opens a socket and everything is fine, socket is "opened" from both sides (client and server). But it is still not clear to me how flexible is this stuff. For example, is it possible for the client to close an opened (from both ends) socket and to reopen it again (under condition that the server keeps the socket opened). Is it possible for the server to "know" that a socket was closed on the client side? Is it possible for the client to know that a socket was closed on the server side?

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  • Pageview implementation

    - by The Elite Gentleman
    Hi everyone I want to add a pageview feature on my current web application. This page view is based on the count of user viewing the page. It must be unique, i.e. I must not view a person's page 10000 times and record it as 10000 views, just record 1 view instead. My question is, should I base my pageview count on IP address? If not, what is/are the best approach in doing this? I know that if the person has logged in to my system, I can simply use the user id stored in the session and check on the record if the user has/hasn't viewed the page and update accordingly. But for "anonymous" viewers, what is the best approach? Thanks. PS How does Youtube does it?

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  • Help in debugging the string concatenation code

    - by mithun1538
    I have a code to concatenate strings. However, for some reason, the final string is not a combination of the required strings. Consider the following code : //cusEmail is of type String[] String toList = ""; for(i=0; i < cusEmail.length - 1; i++) { toList.concat(cusEmail[i]); toList.concat("; "); System.out.println(cusEmail[i]); } toList.concat(cusEmail[i]); System.out.println(toList); The first sout statement displays the strings in cusEmail[i] correctly. However, once concatenated, the second sout displays a blank / empty. Any reason for this? Am i concatenating it correctly?

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  • How to add two label in one gridbox?

    - by Jessy
    Hello everyone, How can I add two label in the same grid box? e.g. in row 1, col 1 the will be 2 labels? The code below will add the label in two different grid. JPanel chckBox = new JPanel(new GridLayout(1,8,3,3)); JLabel label1 = new JLabel("A"); JLabel label2 = new JLabel("B"); ... chckBox.add(label1); chckBox.add(label2); ...

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