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  • Postgres: clear entire database before re-creating / re-populating from bash script

    - by Hoff
    hi folks, I'm writing a shell script (will become a cronjob) that will: 1: dump my production database 2: import the dump into my development database Between step 1 and 2, I need to clear the development database (drop all tables?). How is this best accomplished from a shell script? So far, it looks like this: #!/bin/bash time=`date '+%Y'-'%m'-'%d'` # 1. export(dump) the current production database pg_dump -U production_db_name > /backup/dir/backup-${time}.sql # missing step: drop all tables from development database so it can be re-populated # 2. load the backup into the development database psql -U development_db_name < backup/dir/backup-${time}.sql Many thanks in advance! Martin

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  • Advanced Where Statements in Linq to Entity Framework

    - by JimJams
    Hi, I am wanting to create a Where statement within my Linq statement, but have hit a bit of a stumbling block. I would like to split a string value, and then search using each array item in the Where clause. In my normal Sql statement I would simply loop through the string array, and build up there Where clause then either pass this to a stored procedure, or just execute the sql string. But am not sure how to do this with Linq to Entity? ( From o In db.TableName Where o.Field LIKE Stringvalue Select o ).ToList() Hope you can help. Thanks in advance!

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  • How to insert into two different tables in one statement with Java and MySQL?

    - by MalcomTucker
    I am using Java, Spring (NamedParameterJdbcTemplate) and MySQL. My statement looks like this: INSERT INTO Table1 (Name) VALUES (?); INSERT INTO Table2 (Path, Table1Id) VALUES (?, LAST_INSERT_ID()) But it is throwing the following error: PreparedStatementCallback; bad SQL grammar [INSERT INTO Table1 (Name) VALUES (?); INSERT INTO Table2 (Path, Table1Id) VALUES (?, LAST_INSERT_ID())] ` Nested exception is: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO Table2 (Path, Table1Id' at line 1 The syntax works fine in MySQL but something is up when combining via the Spring template. Thanks!

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  • Accessing Textboxes in Repeater Control

    - by CccTrash
    All the ways I can think to do this seem very hackish. What is the right way to do this, or at least most common? I am retrieving a set of images from a LINQ-to-SQL query and databinding it and some other data to a repeater. I need to add a textbox to each item in the repeater that will let the user change the title of each image, very similar to Flickr. How do I access the textboxes in the repeater control and know which image that textbox belongs to? Here is what the repeater control would look like, with a submit button which would update all the image rows in Linq-to-SQL:

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  • How to drop null values with a native Oracle XML DB Web Service?

    - by gfjr
    I am using native Oracle XML DB Web Services (using a PL/SQL function with a web service). I want to drop null values (put nothing in the output (no XML element)). It's working with Oracle 11.2.0.1.0 but not with Oracle 11.2.0.3.0. Just to clarify... I don't want to consume a webservice with PL/SQL, I want to publish my PL/SQL packages/procedures/functions as a web service! Hope someone can help me. Thank you. In this example is the column "country" null. Oracle 11.2.0.1.0 (this is what I want): <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <GET_PERSONOutput xmlns="http://xmlns.oracle.com/orawsv/TESTSTUFF/GET_PERSON"> <RETURN> <PERSON> <PERSON_ID>3</PERSON_ID> <FIRST_NAME>Harry</FIRST_NAME> <LAST_NAME>Potter</LAST_NAME> </PERSON> </RETURN> </GET_PERSONOutput> </soap:Body> </soap:Envelope> Oracle 11.2.0.3.0: <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <GET_PERSONOutput xmlns="http://xmlns.oracle.com/orawsv/TESTSTUFF/GET_PERSON"> <RETURN> <PERSON> <PERSON_ID>3</PERSON_ID> <FIRST_NAME>Harry</FIRST_NAME> <LAST_NAME>Potter</LAST_NAME> <COUNTRY/> </PERSON> </RETURN> </GET_PERSONOutput> </soap:Body> </soap:Envelope>

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  • MySQL query killing my server

    - by Webnet
    Looking at this query there's got to be something bogging it down that I'm not noticing. I ran it for 7 minutes and it only updated 2 rows. //set product count for makes $tru->query->run(array( 'name' => 'get-make-list', 'sql' => 'SELECT id, name FROM vehicle_make', 'connection' => 'core' )); while($tempMake = $tru->query->getArray('get-make-list')) { $tru->query->run(array( 'name' => 'update-product-count', 'sql' => 'UPDATE vehicle_make SET product_count = ( SELECT COUNT(product_id) FROM taxonomy_master WHERE v_id IN ( SELECT id FROM vehicle_catalog WHERE make_id = '.$tempMake['id'].' ) ) WHERE id = '.$tempMake['id'], 'connection' => 'core' )); } I'm sure this query can be optimized to perform better, but I can't think of how to do it. vehicle_make = 45 rows taxonomy_master = 11,223 rows vehicle_catalog = 5,108 rows All tables have appropriate indexes

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  • My PowerShell functions do not appear to be registered

    - by Frank
    Hi there, I have a script saved in a ps1 file in which I define 2 functions as such: function Invoke-Sql([string]$query) { Invoke-Sqlcmd -ServerInstance $Server -Database $DB -User $User -Password $Password -Query $query } function Get-Queued { Invoke-Sql "Select * From Comment where AwaitsModeration = 1" } In the PowerShell console I then call the ps1 file by typing it in (it's in a folder in the path, and autocompletion works) However, I cannot start using the functions. I am confused, because when I copy / paste the functions into the console, all is fine and they work. I also have a function defined in my profile, and it works. Where am I thinking wrong, why doesn't it work what I'm trying to do?

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  • SecurityException when trying to export a java resource

    - by thecoop
    I'm trying to get the source of a java resource stored in an oracle database using this code (connecting as SYSTEM for testing): DECLARE javalob CLOB; BEGIN DBMS_LOB.CREATETEMPORARY(javalob, false); DBMS_JAVA.EXPORT_RESOURCE('RESOURCENAME', 'SCHEMA', javalob); DBMS_OUTPUT.PUT_LINE(javalob); END; But when I try to run it I get this: Java call terminated by uncaught Java exception: java.lang.SecurityException: cannot read <Resource Handle: RESOURCENAME|SCHEMA|301> because SYSTEM does not have execute privilege on it This thing is, I'm not sure how to grant permissions on <Resource Handle: RESOURCENAME|SCHEMA|301>, as this isn't a SQL or PL/SQL object. And why doesn't SYSTEM have access to it anyway?

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  • JPA Entity Manager resource handling

    - by chiragshahkapadia
    Every time I call JPA method its creating entity and binding query. My persistence properties are: <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/> <property name="hibernate.cache.provider_class" value="net.sf.ehcache.hibernate.SingletonEhCacheProvider"/> <property name="hibernate.cache.use_second_level_cache" value="true"/> <property name="hibernate.cache.use_query_cache" value="true"/> And I am creating entity manager the way shown below: emf = Persistence.createEntityManagerFactory("pu"); em = emf.createEntityManager(); em = Persistence.createEntityManagerFactory("pu").createEntityManager(); Is there any nice way to manage entity manager resource instead create new every time or any property can set in persistence. Remember it's JPA. See below binding log every time : 15:35:15,527 INFO [AnnotationBinder] Binding entity from annotated class: * 15:35:15,527 INFO [QueryBinder] Binding Named query: * = * 15:35:15,527 INFO [QueryBinder] Binding Named query: * = * 15:35:15,527 INFO [QueryBinder] Binding Named query: 15:35:15,527 INFO [QueryBinder] Binding Named query: 15:35:15,527 INFO [QueryBinder] Binding Named query: 15:35:15,527 INFO [QueryBinder] Binding Named query: 15:35:15,527 INFO [QueryBinder] Binding Named query: 15:35:15,527 INFO [QueryBinder] Binding Named query: 15:35:15,527 INFO [QueryBinder] Binding Named query: 15:35:15,527 INFO [EntityBinder] Bind entity com.* on table * 15:35:15,542 INFO [HibernateSearchEventListenerRegister] Unable to find org.hibernate.search.event.FullTextIndexEventListener on the classpath. Hibernate Search is not enabled. 15:35:15,542 INFO [NamingHelper] JNDI InitialContext properties:{} 15:35:15,542 INFO [DatasourceConnectionProvider] Using datasource: 15:35:15,542 INFO [SettingsFactory] RDBMS: and Real Application Testing options 15:35:15,542 INFO [SettingsFactory] JDBC driver: Oracle JDBC driver, version: 9.2.0.1.0 15:35:15,542 INFO [Dialect] Using dialect: org.hibernate.dialect.Oracle10gDialect 15:35:15,542 INFO [TransactionFactoryFactory] Transaction strategy: org.hibernate.transaction.JDBCTransactionFactory 15:35:15,542 INFO [TransactionManagerLookupFactory] No TransactionManagerLookup configured (in JTA environment, use of read-write or transactional second-level cache is not recomm ended) 15:35:15,542 INFO [SettingsFactory] Automatic flush during beforeCompletion(): disabled 15:35:15,542 INFO [SettingsFactory] Automatic session close at end of transaction: disabled 15:35:15,542 INFO [SettingsFactory] JDBC batch size: 15 15:35:15,542 INFO [SettingsFactory] JDBC batch updates for versioned data: disabled 15:35:15,542 INFO [SettingsFactory] Scrollable result sets: enabled 15:35:15,542 INFO [SettingsFactory] JDBC3 getGeneratedKeys(): disabled 15:35:15,542 INFO [SettingsFactory] Connection release mode: auto 15:35:15,542 INFO [SettingsFactory] Default batch fetch size: 1 15:35:15,542 INFO [SettingsFactory] Generate SQL with comments: disabled 15:35:15,542 INFO [SettingsFactory] Order SQL updates by primary key: disabled 15:35:15,542 INFO [SettingsFactory] Order SQL inserts for batching: disabled 15:35:15,542 INFO [SettingsFactory] Query translator: org.hibernate.hql.ast.ASTQueryTranslatorFactory 15:35:15,542 INFO [ASTQueryTranslatorFactory] Using ASTQueryTranslatorFactory 15:35:15,542 INFO [SettingsFactory] Query language substitutions: {} 15:35:15,542 INFO [SettingsFactory] JPA-QL strict compliance: enabled 15:35:15,542 INFO [SettingsFactory] Second-level cache: enabled 15:35:15,542 INFO [SettingsFactory] Query cache: enabled 15:35:15,542 INFO [SettingsFactory] Cache region factory : org.hibernate.cache.impl.bridge.RegionFactoryCacheProviderBridge 15:35:15,542 INFO [RegionFactoryCacheProviderBridge] Cache provider: net.sf.ehcache.hibernate.SingletonEhCacheProvider 15:35:15,542 INFO [SettingsFactory] Optimize cache for minimal puts: disabled 15:35:15,542 INFO [SettingsFactory] Structured second-level cache entries: disabled 15:35:15,542 INFO [SettingsFactory] Query cache factory: org.hibernate.cache.StandardQueryCacheFactory 15:35:15,542 INFO [SettingsFactory] Statistics: disabled 15:35:15,542 INFO [SettingsFactory] Deleted entity synthetic identifier rollback: disabled 15:35:15,542 INFO [SettingsFactory] Default entity-mode: pojo 15:35:15,542 INFO [SettingsFactory] Named query checking : enabled 15:35:15,542 INFO [SessionFactoryImpl] building session factory 15:35:15,542 INFO [SessionFactoryObjectFactory] Not binding factory to JNDI, no JNDI name configured 15:35:15,542 INFO [UpdateTimestampsCache] starting update timestamps cache at region: org.hibernate.cache.UpdateTimestampsCache 15:35:15,542 INFO [StandardQueryCache] starting query cache at region: org.hibernate.cache.StandardQueryCache

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  • ELMAH: Only sending specific exception type via mail

    - by Sir Code-A-Lot
    Hi, I have ELMAH set up for a webapp, logging exceptions to a SQL server. I wish to have ELMAH send me an email too, but only when a specific exception is thrown (ie. MySpecialException). ELMAH must still log all exceptions to SQL server. I know you can do it programmatically in global.asax, but I'd prefer to use web.config. So, how do I restrict ELMAH error mails to filter out everything but a specific exception type, using web.config?

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  • TFS 2012 fresh install on fresh Windows Server 2008 warning that reporting services are not installed

    - by jshin47
    I am attempting to evaluate TFS 2012 for our organization but cannot seem to get past the first step of configuring the server using the "Standard Single Server" configuration wizard. In particular, in the service account selection screen, I am warned that: Reporting services are not installed on this computer. You need to install Reporting Services to complete TFS installation with this wizard. This is disheartening because the way I understand it, this should have been installed with the default TFS installation (in fact, no installation options are even provided) and this is a fresh and up-to-date Windows Server 2008 VM. I know I could install SQL Server 2008 or 2012 from MSDN, but shouldn't this work "out of the box?" I'd really rather use the default, small, integrated version of SQL Server that comes with TFS 2012 rather than rolling my own. If it matters, this server is joined to a domain and I am running TFS installation wizard as a domain administrator.

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  • hibernate not picking sessionFactory

    - by Satya
    My application-context.xml is <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd"> <beans> <bean id="myDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName"><value>com.mysql.jdbc.Driver</value></property> <property name="url"><value>jdbc:mysql://localhost:3306/myDB</value></property> <property name="username"><value>myUser</value></property> <property name="password"><value>myUser</value></property> </bean> <bean id="mySessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="mappingResources"> <property name="dataSource"><ref bean="myDataSource"/></property> <list> <value>com/x/model/config/hibernate/user.hbm.xml</value> </list> </property> <property name="hibernateProperties" > <value> hibernate.dialect=org.hibernate.dialect.MySQLDialect </value> </property> </bean> <bean id="userdao" class="com.x.y.z.UserDao"> <property name="sessionFactory"><ref bean="mySessionFactory"/></property> </bean> </beans> user.hbm.xml is <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="com.cpt.model"> <class name="User" table="user"> <id name="userId" column="id"> <generator class="native"/> </id> <property name="firstname" column="firstName" /> <property name="lastName" column="lastName"/> <property name="login" column="login"/> <property name="pass" column="pass"/> <property name="superemail" column="superEmail"/> </class> </hibernate-mapping> and the UserDao is package com.x.y.z; import java.sql.Connection; import java.sql.DriverManager; import java.sql.SQLException; import java.sql.Statement; import org.hibernate.HibernateException; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.cfg.Configuration; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.orm.hibernate.support.HibernateDaoSupport; import org.springframework.stereotype.Component; import com.x.model.User; @Component public class UserDao { private SessionFactory sessionFactory; public void addUser(User user) { Session session; try { try { session = getSessionFactory().openSession(); // session = sessionFactory.openSession(); session.save(user); } catch (RuntimeException e) { // TODO Auto-generated catch block e.printStackTrace(); } } catch (HibernateException e) { // TODO Auto-generated catch block System.out.println("printing in the catch"); e.printStackTrace(); } } public SessionFactory getSessionFactory() { System.out.println("returning session factory ::: sessionFactory == null :: "+sessionFactory.openSession()); return sessionFactory; } public void setSessionFactory(SessionFactory sessionFactory) { System.out.println("this is setting session factory" + sessionFactory.getClass()); System.out.println("setting session factory ::: sessionFactory == null :: "+sessionFactory==null); this.sessionFactory = sessionFactory; System.out.println("setting session factory ::: sessionFactory == null :: "+this.sessionFactory.openSession().getClass()); System.out.println(getSessionFactory().openSession().isOpen()); } } However, I keep getting 14:45:09,929 INFO [org.hibernate.impl.SessionFactoryImpl] building session fact ory 14:45:09,933 WARN [net.sf.ehcache.config.Configurator] No configuration found. Configuring ehcache from ehcache-failsafe.xml found in the classpath: vfs:/C:/jb /server/default/deploy/C.war/WEB-INF/lib/ehcache-1.1.jar/ehcache-failsafe.xml 14:45:10,007 INFO [org.hibernate.impl.SessionFactoryObjectFactory] Not binding factory to JNDI, no JNDI name configured 14:45:10,008 INFO [org.hibernate.impl.SessionFactoryImpl] Checking 0 named quer ies 14:45:10,017 INFO [STDOUT] this is setting session factoryclass $Proxy178 14:45:10,017 INFO [STDOUT] false 14:45:10,019 INFO [STDOUT] setting session factory ::: sessionFactory == null : : class org.hibernate.impl.SessionImpl 14:45:10,020 INFO [STDOUT] returning session factory ::: sessionFactory == null :: org.hibernate.impl.SessionImpl(PersistentContext[entitiesByKey={}] ActionQue ue[insertions=[] updates=[] deletions=[] collectionCreations=[] collectionRemova ls=[] collectionUpdates=[]]) It is giving sessionFactory null . Any Idea where am I failing ? Thanks

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  • Correct way to make datasources/resources a deploy-time setting

    - by Draemon
    I have a web-app that requires two settings: A JDBC datasource A string token I desperately want to be able to deploy one .war to various different containers (jetty,tomcat,gf3 minimum) and configure these settings at application level within the container. My code does this: InitialContext ctx = new InitialContext(); Context envCtx = (javax.naming.Context) ctx.lookup("java:comp/env"); token = (String)envCtx.lookup("token"); ds = (DataSource)envCtx.lookup("jdbc/datasource") Let's assume I've used the glassfish management interface to create two jdbc resources: jdbc/test-datasource and jdbc/live-datasource which connect to different copies of the same schema, on different servers, different credentials etc. Say I want to deploy this to glassfish with and point it at the test datasource, I might have this in my sun-web.xml: ... <resource-ref> <res-ref-name>jdbc/datasource</res-ref-name> <jndi-name>jdbc/test-datasource</jndi-name> </resource-ref> ... but sun-web.xml goes inside my war, right? surely there must be a way to do this through the management interface Am I even trying to do the right thing? Do other containers make this any easier? I'd be particularly interested in how jetty 7 handles this since I use it for development. EDIT Tomcat has a reasonable way to do this: Create $TOMCAT_HOME/conf/Catalina/localhost/webapp.xml with: <?xml version="1.0" encoding="UTF-8"?> <Context antiResourceLocking="false" privileged="true"> <!-- String resource --> <Environment name="token" value="value of token" type="java.lang.String" override="false" /> <!-- Linking to a global resource --> <ResourceLink name="jdbc/datasource1" global="jdbc/test" type="javax.sql.DataSource" /> <!-- Derby --> <Resource name="jdbc/datasource2" type="javax.sql.DataSource" auth="Container" driverClassName="org.apache.derby.jdbc.EmbeddedDataSource" url="jdbc:derby:test;create=true" /> <!-- H2 --> <Resource name="jdbc/datasource3" type="javax.sql.DataSource" auth="Container" driverClassName="org.h2.jdbcx.JdbcDataSource" url="jdbc:h2:~/test" username="sa" password="" /> </Context> Note that override="false" means the opposite. It means that this setting can't be overriden by web.xml. I like this approach because the file is part of the container configuration not the war, but it's not part of the global configuration; it's webapp specific. I guess I expect a bit more from glassfish since it is supposed to have a full web admin interface, but I would be happy enough with something equivalent to the above.

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  • How to get Joomla users data into a json array

    - by sami
    $sql = "SELECT * FROM `jos_users` LIMIT 0, 30 "; $response = array(); $posts = array(); $result=mysql_query($sql); while($row=mysql_fetch_array($result)) { $id=$row['id']; $id=$row['name']; $posts[] = array('id'=> $title, 'name'=> $name); } $response['jos_users'] = $posts; $fp = fopen('results.json', 'w'); fwrite($fp, json_encode($response)); fclose($fp); I want to fetch the user id and name to the json file.i thought id did wrong code.can anyone correct it ?

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  • Asp.Net MVC best way to update cached table

    - by Eddy Mishiyev
    There are certain tables that get called often but updated rarely. One of these tables is Departments. So to save DB trips, I think it is ok to cache this table taking into consideration that the table has very small size. However, once you cached it an issue of keeping the table data fresh occurs. So what is the best way to determine that the table is dirty and therefore requires a reload and how that code should be invoked. I look for solution that will be scalable. So updating the cache right after inserting will not work. So if one machine inserted the record all other on network should get notified to reload the cache. I was thinking for calling corresponding web service from T-SQL but don't really like the idea of consuming recourses on sql server. So what are the best practices to resolve this type of problems. Thanks in advance Eddy

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  • Access Edit Mode Values of BindingSource Control

    - by Christopher Edwards
    I have a BindingSource control (http://msdn.microsoft.com/en-us/library/system.windows.forms.bindingsource.aspx) with a datasource of a (single) Linq object. If I change any of the properties of the underlying Linq-to-Sql object then all the other changes on the bound controls on the form are lost. Does anyone now why and how I work around it? I don't want to call EndEdit because this will commit the changes to the underlying object. I think this might be because my underlying object linq-to-sql object does not implement IEditableObject so the potental new values for the object fields are sort of stored in the forms controls. Can anyone either clarify what is going on and/or suggest a work around. Thanks!

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  • Perform Grouping of Resultset in Code

    - by NinjaBomb
    Stackoverflowers, I have a resultset from a SQL query in the form of: Category Column2 Column3 A 2 3.50 A 3 2 B 3 2 B 1 5 ... I need to group the resultset based on the Category column and sum the values for Column2 and Column3. I have to do it in code because I cannot perform the grouping in the SQL query that gets the data due to the complexity of the query (long story). This grouped data will then be displayed in a table. I have it working for specific set of values in the Category column, but I would like a solution that would handle any possible values that appear in the Category column. I know there has to be a straightforward, efficient way to do it but I cannot wrap my head around it right now. How would you accomplish it?

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  • How to do a range query

    - by Walter H
    I have a bunch of numbers timestamps that I want to check against a range to see if they match a particular range of dates. Basically like a BETWEEN .. AND .. match in SQL. The obvious data structure would be a B-tree, but while there are a number of B-tree implementations on CPAN, they only seem to implement exact matching. Berkeley DB has the same problem; there are B-tree indices, but no range matching. What would be the simplest way to do this? I don't want to use an SQL database unless I have to. Clarification: I have a lot of these, so I'm looking for an efficient method, not just grep over an array.

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  • How to Loop & rename MySQL table in Perl

    - by Nano HE
    Hi, Could you plesae teach me how to Loop & rename MySQL table in Perl. Thanks. my code snippet attached use strict; use warnings; use DBI; my $dbh = DBI->connect( 'DBI:mysql:database=dbdev;host=localhost', 'dbdev', 'dbdevpw', { RaiseError => 1, AutoCommit => 1 }, ); my $sql = RENAME TABLE old_table TO new_table; my $sth = $dbh->prepare($sql); while (<DATA>){ chomp; // How to implement the Rename all the old tables with the while loop. $sth->execute(); }

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  • Php mysqli and stored-procedure

    - by Mneva skoko
    I have a stored procedure: Create procedure news(in dt datetime,in title varchar(10),in desc varchar(200)) Begin Insert into news values (dt,title,desc); End Now my php: $db = new mysqli("","","",""); $dt = $_POST['date']; $ttl = $_POST['title']; $desc = $_POST['descrip']; $sql = $db-query("CALL news('$dt','$ttl','$desc')"); if($sql) { echo "data sent"; }else{ echo "data not sent"; } I'm new with php please help thank you

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  • How do i keep my DB and lucene in sync?

    - by acidzombie24
    So i can have a transaction in sql. But i am sure its not a good idea to wait in the middle of a transaction for lucene to finish also i am unsure if lucene is permanently saved in the DB until i do something there. Whats the best way to keep my DB and lucene in sync? I am thinking of adding a lucene_queue in my sql db and everytime i make a change i add it into the queue (removing older queue if any) and delete it once it is done. Is this the best way? Also i am unsure how to make lucene permanently keep the changes i made and how frequent i can/should do it.

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  • Passing an array of data as an input parameter to an Oracle procedure

    - by Sathya
    I'm trying to pass an array of (varchar) data into an Oracle procedure. The Oracle procedure would be either called from SQL*Plus or from another PL/SQL procedure like so: BEGIN pr_perform_task('1','2','3','4'); END; pr_perform_task will read each of the input parameters and perform the tasks. I'm not sure as to how I can achieve this. My first thought was to use an input parameter of type varray but I'm getting Error: PLS-00201: identifier 'VARRAY' must be declared error, when the procedure definiton looks like this: CREATE OR REPLACE PROCEDURE PR_DELETE_RECORD_VARRAY(P_ID VARRAY) IS To summarize, how can I pass the data as an array, let the SP loop through each of the parameters and perform the task ? I'm using Oracle 10gR2 as my database.

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  • How to handle all exceptions in a web java project

    - by Nick Donovan
    I am doing an web java project about an hotel reservation. I am using, sql, hibernate, java server pages. I want to know how can I redirect an incoming exception to an error.jsp file . There are a lot of java code , and a lot of jsp file. So I want to rederict every exception that I haven't handle to an error page, is there any way to do it ? An exception can come from everywhere and I can't know and handle them all ( for example an user can write to much data in an textfield, and it will generate me an sql exception for data to long) Thank you, sorry for my english.

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  • php extract data from mysql

    - by florin
    I have this mysql table with the following rows: id_cont suma_lun month year -------------------------------------------- FL28 2133 March 2012 FL28 2144 April 2012 FL28 2155 May 2012 FL28 2166 June 2012 How can i extract suma_lun, month and year foreach id_cont? so that i get an output like this: ID: Month: Monthly Sum: Year: ---------------------------------------------- FL28 March 2133 2012 April 2144 2012 May 2155 2012 June 2166 2012 This is my current code: $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) die ('Could not connect to database: '.mysql_error()); mysql_select_db(DB_DATABASE,$link); $sql="SELECT * FROM test WHERE id_cont = '$cur'"; $result=mysql_query($sql); while ($row=mysql_fetch_array($result)) { $a=$row["id_cont"]; $b=$row["suma_lun"]; $c=$row["month"]; $d=$row["year"]; } I echo the data in a table Thanks!

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