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  • How does the dataset determine the return type of a scalar query?

    - by Tobias Funke
    I am attempting to add a scalar query to a dataset. The query is pretty straight forward, it's just adding up some decimal values in a few columns and returning them. I am 100% confident that only one row and one column is returned, and that it is of decimal type (SQL money type). The problem is that for some reason, the generated method (in the .designer.cs code file) is returning a value of type object, when it should be decimal. What's strange is that there's another scalar query that has the exact same SQL but is returning decimal like it should. How does the dataset designer determine the data type, and how can I tell it to return decimal?

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  • PHP IF statement not taking variable into account!

    - by Jess
    I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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  • Separating MySQL SELECT statement based on data in a column

    - by NightMICU
    Hi everyone, I need to retrieve data (vehicle details, in this case) from a MySQL table tabled and then loop through the results to generate separate lists for each category of vehicle. Is there a simple way to do this without having to have a SELECT statement for each type of vehicle? If I were just doing this for one category, I would use the following: <?php $sql = "SELECT * FROM apparatus WHERE vehicleType = 'Support'; $getSQL = mysql_query($sql); ?> <ul> <?php while ($vehicleData = mysql_fetch_assoc($getSQL)) {?> <li><?php echo $vehicleData['name'];?></li> <?php } ?> </ul> ..etc. Need to do this for four different types of vehicles. Thanks!

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  • How would I add an if statement into MSQLI query?

    - by Josh
    Okay so I'm just learning mysqli and I'm having a little trouble putting this code together. I've posted the mysqli query below and then below that is the code I'm trying to combine with the mysqli query and I can't seem to get it to work. Maybe what I'm doing isn't possible, but the third section below is how I had the query written for mysql and it's working fine. Answers in code are appreciated! Thanks! MYSQLI QUERY: <?php require("../config.php"); if ($stmt = $mysqli->prepare("SELECT firstname,lastname,spousefirst,phonecell,email,date,contacttype,status FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') ORDER BY date DESC")) { $stmt->execute(); $stmt->bind_results($firstname,$lastname,$spousefirst,$phonecell,$email,$date,$contacttype,$status); while ($stmt->fetch()) { echo ''.$firstname.' '." ".' '.$lastname.' '.",".' '.$spousefirst.' '.",".' '.$phonecell.' '.",".' '.$email.' '.",".' '.$date.' '.",".' '.$contacttype.' '.",".' '.$status.'</br>'; } $stmt->close(); } $mysqli->close(); ?> WHAT I'M TRYING TO COMBINE THE ABOVE WITH: if (($_GET['date'] == 'today')) { $sql = "SELECT * FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') AND date = DATE(NOW()) ORDER BY date DESC"; } WHAT I HAD BEFORE WITH MYSQL THAT WORKS: <?php require("../config.php"); $sql = "SELECT * FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') AND status = 'New' ORDER BY date DESC"; if (($_GET['date'] == 'today')) { $sql = "SELECT * FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') AND date = DATE(NOW()) ORDER BY date DESC"; } ?>

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  • How to know record has been updated successfully in php

    - by Lisa Ray
    $sql = "UPDATE...."; if(mysql_query($sql)) { $_SESSION['Trans']="COMMIT"; header("location:result.php"); exit; } else { $_SESSION['Trans']="FAIL"; $_SESSION['errors'] = "Error: Sorry! We are unable to update your Profile, Please contact to PNP HelpDesk."; header("location:result.php"); exit; }//end IF data is getting updated then why compiler is not coming inside IF condition.

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  • sqlite 3 opening issue

    - by anonymous
    I'm getting my data ,with several similar methods, from sqlite3 file like in following code: -(NSMutableArray *) getCountersByID:(NSString *) championID{ NSMutableArray *arrayOfCounters; arrayOfCounters = [[NSMutableArray alloc] init]; @try { NSFileManager *fileManager = [NSFileManager defaultManager]; NSString *databasePath = [[[NSBundle mainBundle] resourcePath ]stringByAppendingPathComponent:@"DatabaseCounters.sqlite"]; BOOL success = [fileManager fileExistsAtPath:databasePath]; if (!success) { NSLog(@"cannot connect to Database! at filepath %@",databasePath); } else{ NSLog (@"SUCCESS getCountersByID!!"); } if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK){ NSString *tempString = [NSString stringWithFormat:@"SELECT COUNTER_ID FROM COUNTERS WHERE CHAMPION_ID = %@",championID]; const char *sql = [tempString cStringUsingEncoding:NSASCIIStringEncoding]; sqlite3_stmt *sqlStatement; int ret = sqlite3_prepare(database, sql, -1, &sqlStatement, NULL); if (ret != SQLITE_OK) { NSLog(@"Error calling sqlite3_prepare: %d", ret); } if(sqlite3_prepare_v2(database, sql, -1, &sqlStatement, NULL) == SQLITE_OK){ while (sqlite3_step(sqlStatement)==SQLITE_ROW) { counterList *CounterList = [[counterList alloc]init]; CounterList.counterID = [NSString stringWithUTF8String:(char *) sqlite3_column_text(sqlStatement,0)]; [arrayOfCounters addObject:CounterList]; } } else{ NSLog(@"problem with database prepare"); } sqlite3_finalize(sqlStatement); } else{ NSLog(@"problem with database openning %s",sqlite3_errmsg(database)); } } @catch (NSException *exception){ NSLog(@"An exception occured: %@", [exception reason]); } @finally{ sqlite3_close(database); return arrayOfCounters; } //end } then i'm getting access to data with this and other similar lines of code: myCounterList *MyCounterList = [[myCounterList alloc] init]; countersTempArray = [MyCounterList getCountersByID:"2"]; [countersArray addObject:[NSString stringWithFormat:@"%@",(((counterList *) [countersTempArray objectAtIndex:i]).counterID)]]; I'm getting a lot of data like image name and showing combination of them that depends on users input with such code: UIImage *tempImage = [UIImage imageNamed:[NSString stringWithFormat:@"%@_0.jpg",[countersArray objectAtIndex:0]]]; [championSelection setBackgroundImage:tempImage forState:UIControlStateNormal]; My problem: When i'm run my app for some time and get a lot of data it throws error: " problem with database openning unable to open database file - error = 24 (Too many open files)" My guess is that i'm opening my database every time when getCountersByID is called but not closing it. My question: Am i using right approach to open and close database that i use? Similar questions that have not helped me to solve this problem: unable to open database Sqlite Opening Error : Unable to open database UPDATE: I made assumption that error is showing up because i use this lines of code too much: NSFileManager *fileManager = [NSFileManager defaultManager]; NSString *databasePath = [[[NSBundle mainBundle] resourcePath ]stringByAppendingPathComponent:@"DatabaseCounters.sqlite"]; BOOL success = [fileManager fileExistsAtPath:databasePath]; and ending up with error 24. So i made them global but sqlite3_errmsg shows same err 24, but app runs much faster now I'll try to debug my app, see what happens

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  • Error when creating database in MySQL using Netbeans 6.8

    - by nix
    I am trying to create a database using MySQL statements in NetBeans 6.8. However, I keep getting Error code 1064. I don't know what the problem is really since the same statements work in NetBeans 6.0. Here is the error: Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '; /*!40000 ALTER TABLE students ENABLE KEYS */; -- -- Definition of table `w' at line 1016 Line 46, column 1

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  • MySQL COUNT help

    - by space
    I'm trying to count all the ids form table3 that are related to the first two tables but I think my SQL code is wrong can some one help me fix it? Here is the code: $dbc = mysqli_query($mysqli,"SELECT table1.*, table2.*, COUNT(id) as num, table3.id FROM table1 INNER JOIN table2 ON table1.id = table2.id INNER JOIN table3 ON table2.id = table3.id WHERE table2.id = '$id'"); Here is the error message. Mixing of GROUP columns (MIN(),MAX(),COUNT(),...) with no GROUP columns is illegal if there is no GROUP BY clause You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 4

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  • PHP mySQL query's and PHP Variables

    - by jon
    I'm trying to make an OO Login system for a project I'm working on, and am having trouble with inserting variables into the query strings. In the code below, if I replace "$TBL_NAME" with the actual table name it works. Why isn't $TBL_NAME translating to the value of $TBL_NAME? class UserDB { private $TBL_NAME = "users"; public static function CheckLogin($username, $password) { Database::Connect(); $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT uid FROM $TBL_NAME WHERE username='$username' AND password='$password' "; $result =mysql_query($sql); $count=mysql_num_rows($result); if ($count==1) return true; else return false; } The Query is returning false.

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  • PHP loop position

    - by Jordan Pagaduan
    Can someone help me on this. I'm made an image uploader and i want the image to make another tr if it reach to 5 pics so it will not overflow. Here is my code: Can someone help me on this. I'm made an image uploader and i want the image to make another tr if it reach to 5 pics so it will not overflow. Here is my code: $dbc = mysql_connect("localhost" , "root" , "") or die (mysql_error()); mysql_select_db('blog_data') or die (mysql_error()); $sql = "SELECT * FROM img_uploaded"; $result = mysql_query($sql); while($rows=mysql_fetch_array($result)) { if ($rows) { echo "<tr><td><img src='user_images/".$rows['img_name'] . "' width='100' height='100'></td></tr>"; } else { echo "<td><img src='user_images/".$rows['img_name'] . "' width='100' height='100'></td>"; } }

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  • Read a large result set in chunks from mysql

    - by ripper234
    I am trying to read a huge result set from mysql. Reading them in a straight-forward manner didn't work, as mysql tries to return all results together, which times out. I found the following piece of code which tells mysql to read the results back one at a time: stmt = conn.createStatement(java.sql.ResultSet.TYPE_FORWARD_ONLY, java.sql.ResultSet.CONCUR_READ_ONLY); stmt.setFetchSize(Integer.MIN_VALUE); Can I read a chunk at a time instead of one by one? I've tried setting fetch size to a different value, but it doesn't work.

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  • Stop Submit With empty and error Input Values Using PHP

    - by user3615781
    I am using the following code for sending data to database, but it sends the data even the values of the fields are incorrect or empty. So can anyone help me solve this by using php? Here is my code: <?php //Connecting to sql db $connect = mysqli_connect("localhost","root","","form"); /* check connection */ if (!$connect) { die('Connect Error: ' . mysqli_connect_error()); } //Sending data to sql db $result = mysqli_query($connect,"INSERT INTO students(name,email,website,comment,gender) VALUES('$name','$email','$website','$comment','$gender')"); if (!$result) { die('Query Error:'. mysqli_error($connect)); } ?>

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  • How to get variable value from inside a stored procedure in DB2?

    - by Sylvia
    This seems like it should be very easy...anyway, it is in MS SQL Server In a DB2 stored procedure, how can I just get the value of a variable? Say I have the following stored procedure: CREATE PROCEDURE etl.TestABC( ) LANGUAGE SQL BEGIN declare Stmt varchar(2048); set Stmt = 'this is a test'; -- print Stmt; -- select Stmt; return 0; END @ I'd like to print out the value of Stmt after I set it. Print doesn't work, select doesn't work. Somebody said I have to insert it to a table first, and then get it after I run the stored procedure. Is this really necessary? Thanks, Sylvia EDIT: I should have made clearer that I want to see the value of Stmt each time after I set it, and I may need to set it multiple times within the same stored procedure.

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  • PDO:sqlite doesnt INSERT data, yet no error

    - by Phonethics
    try { $res = $db-exec($sql); if ($res === FALSE) { print_r($db-errorInfo()); die(); } } catch(PDOException $e) { die($e-getCode().':'.$e-getMessage()); } catch(Exception $e) { die($e-getCode().':'.$e-getMessage()); } No error info, and neither does it get caught as an exception. Yet $res is FALSE and no data gets inserted. Array ( [0] => ) But when I echo $sql and enter that query in SQLiteManager, it works inserting the data.

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  • Possibly simple PHP/MYSQL issue with retrieving and showing data

    - by envoys
    I have been racking my brains over this for a while now. Here is the data i have in the sql data base as an example: ID | TYPE | DATA 1 | TXT | TEST 2 | PHP | php 3 | JS | JAVASCRIPT That is just an example, there are multiple listing for TXT, PHP and JS throughout the table. What I want to do is retrive all the data and display it all into separate drop down/select boxes. Meaning, select box one would list all data with type TXT, select box two would list all data with type PHP and select box 3 would list all data with type JS. The only way I have came about doing this is doing individual sql queries for each different type. I know there is a way to do it all in 1 query and then display it the way I want to but I just can't seem to figure out how and I know its going to drive me nuts when someone helps and I see just how they did it. Thanks for the input.

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  • How can you get the average of the count of records in Reporting Services

    - by Tim Coker
    I have a report where I'm counting the number of records for a day. At the bottom, I have the total records for that time period. I'd like to display the average records for each day. An example: Day Tests 1/1/2010 5 1/2/2010 10 1/3/2010 8 Average 7.7 Total 23 I can accomplish this by aggregating the data by date in SQL then just doing the Average and Sum of the count from SQL, but that would complicate the report considerably as I'm doing other column filters for the types of tests performed. There seems to be a simple way to accomplish this that I'm missing. I can't do Average(Count(field)) in SSRS, unfortunately. Is there something I'm missing, or is there really not a way to accomplish this simply?

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  • how to print not mapped value

    - by IcanMakeIt
    I am using complicated SQL queries, i have to use SqlQuery ... in simple way: MODEL: public class C { public int ID { get; set; } [NotMapped] public float Value { get; set; } } CONTROLLER: IEnumerable<C> results = db.C.SqlQuery(@"SELECT ID, ATAN(-45.01) as Value from C); return View(results.ToList()); VIEW: @model IEnumerable<C> @foreach (var item in Model) { @Html.DisplayFor(modelItem => item.Value) } and the result for item.Value is NULL. So my question is , how can i print the computed value from SQL Query ? Thank you for help.

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  • How does the dataset designer determine the return type of a scalar query?

    - by Tobias Funke
    I am attempting to add a scalar query to a dataset. The query is pretty straight forward, it's just adding up some decimal values in a few columns and returning them. I am 100% confident that only one row and one column is returned, and that it is of decimal type (SQL money type). The problem is that for some reason, the generated method (in the .designer.cs code file) is returning a value of type object, when it should be decimal. What's strange is that there's another scalar query that has the exact same SQL but is returning decimal like it should. How does the dataset designer determine the data type, and how can I tell it to return decimal?

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • Setting an empty default value for a char-column in MySQL?

    - by user281434
    Hi In phpMyAdmin I have a char(32) column that has no default value(ie. Default: None). When I try to insert data through a SQL query, it throws out an error saying that the column "doesn't have a default value". I need it to be empty, so instead I've just set it's default value as "As defined: " and then nothing in the value field. Is this a bad idea? And is it any better than simply throwing in an empty value for the column in the SQL query? Thanks for your time.

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  • Mysql question about UPDATE

    - by Beck
    UPDATE counter_reports SET `counter`=`counter`+1,`date`=? WHERE report_id IN( (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `year`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `month`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `week`=1 ORDER BY report_id DESC LIMIT 1), (SELECT report_id FROM counter_reports WHERE report_name="emails_sent" AND `day`=1 ORDER BY report_id DESC LIMIT 1) ) Is there any alternative for such sql? I need to update(increment by 1) last counter reports for day,week,month and year. If I'm adding manually, sql works fine, but with subqueries it fails to launch. Thanks. :)

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  • PHP 1-liner each() with mysql_fetch_assoc()

    - by MVC You Know Me
    Hey All. Trying to create a 1-liner to loop through a mysql result set. Example: $sql = "SELECT uid, role FROM usr WHERE uid = '$this-uid'"; $r = db::q($sql); if($r-rows()) { $q = mysql_fetch_assoc($r-result); while(list($k, $v) = each($q)) { // would like to omit line above and consolidate here $_SESSION['usr'][$k] = $this->$k = $v; } } problem is that consolidating while loop like so: while(list($k, $v) = each(mysql_fetch_assoc($r-result)) returns an error a la each() not getting object or array, even though of course it is. I think the problem is a casting issue, but it does not seem you can do: each( (array) mysql_fetch_assoc($r-result)) Any ideas? I like to code as tersely as possible, and having "$q = mysql_fetch_assoc($r-result)" everywhere will annoy me, does already. Keep posted... Thanks!

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