How to convert string "0671" or "0x45" into integer form with 0 and 0x in the beginning.
- by Harshit Sharma
I wanted to make my own encryption algorithm and decryption algorithm , encryption algorithm works fine and converts ascii value of the characters into alternate hexadecimal and octal representations. But when I tried decryption, problem occured as it return int('0671') = 671, as 0671 is string type in the following code. Is there a method to convert "ox56" into integer form??????
NOTE: Following string is alternate octal and hexa of ascii value of char.
///////////////DECRYPTION///////
l="01630x7401620x6901560x67"
f=len(l)
k=0
d=0
x=[]
for i in range(0,f,4):
g=l[i:i+4]
print g
k=k+1
if(k%2==0):
p=g
print p
else:
p=int(g)
print p
