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  • Extending Zend_Log for application-specific need

    - by spdaly
    I am building a Zend Framework application that performs jobs submitted by the user. The actions taken need to be logged to a database. I would like to correlate the job with its log entries. Instead of creating my own logging class, I would like to extend Zend_Log since it provides 99% of the functionality that I need. All I need to do is add a foreign key of the job id to the log data model. Is this possible? I'm also looking for a good example of Zend_Log writing to a database. I haven't searched SO yet. I will do that after I post this. Thanks in advance... Steve

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  • aggregate form elements into object ? [Solved]

    - by Mahmoud
    hey all i am trying to aggregate form elements into object and then send it via ajax here is the code that i start using but i cant figure out how to do the rest $('.jcart').live('submit', function() { }); Update 1: html form http://pasite.org/code/572 Update 2: I have successfully submit the form using ajax but it still refreshes the page after submiting this what i did function adding(form){ $( "form.jcart" ).livequery('submit', function() {var b=$(this).find('input[name=<?php echo $jcart['item_id']?>]').val();var c=$(this).find('input[name=<?php echo $jcart['item_price']?>]').val();var d=$(this).find('input[name=<?php echo $jcart['item_name']?>]').val();var e=$(this).find('input[name=<?php echo $jcart['item_qty']?>]').val();var f=$(this).find('input[name=<?php echo $jcart['item_add']?>]').val();$.post('<?php echo $jcart['path'];?>jcart-relay.php',{"<?php echo $jcart['item_id']?>":b,"<?php echo $jcart['item_price']?>":c,"<?php echo $jcart['item_name']?>":d,"<?php echo $jcart['item_qty']?>":e,"<?php echo $jcart['item_add']?>":f} }); return false; }

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  • Separating Variables Inside an Array

    - by Jake Avila Talledo
    Hey i have an array an I need to separate each value so it would be something like this $arry = array(a,b,c,d,e,f) $point1 = (SELECT distance FROM Table WHERE Origin = a AND Destination = b); $point2 = (SELECT distance FROM Table WHERE Origin = b AND Destination = c); $point3 = (SELECT distance FROM Table WHERE Origin = c AND Destination = d); $point4 = (SELECT distance FROM Table WHERE Origin = d AND Destination = e); $point5 = (SELECT distance FROM Table WHERE Origin = e AND Destination = f); $point6 = (SELECT distance FROM Table WHERE Origin = f AND Destination = g); $point7 = (SELECT distance FROM Table WHERE Origin = g AND Destination = f); $total_trav = $point1+$point2+$point3+$point4+$point5+$point6+$point7

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  • Use count or have a field that tallies?

    - by Dan LaManna
    Fairly simple concept, making an extremely basic message board system and I want users to have a post count. Now I was debating on whether or not to have a tally in their row that is added each time a post by them is created, or subtracted by one each time a post of theirs is deleted. However I'm sure that performing a count query when the post count is requested would be more accurate due to unforseen circumstances (say a thread gets deleted and it doesn't lower their tally properly), however this seems like it would be less efficient to run a query EVERY time their post count is loaded, especially in the case of them having 10 posts on the same page and it lists their post count each post. Thoughts/Advice? Thanks

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  • MySQL update query, how to skip empty values?

    - by Pawel
    I've got such query: $sql = "UPDATE test_accs SET acc_owner = '$owner_id', acc_policy_version = '$version', acc_policy_last_update = '$approved', acc_policy_next_update = '$renewed' WHERE acc_id = '1'"; Now, all of these values on the web folmular are optional, one can set one of these values, two, or so. Now, after I submit the form, it goes in the query like that: UPDATE test_accs SET acc_owner = '2', acc_policy_version = '1.2', acc_policy_last_update = '2012-12-19', acc_policy_next_update = '2012-12-18' WHERE acc_id = '1' It works only when I submit all values from the form. Can you please show me how could it work even if not all the values has been sent, just for example one of them? When I set one value (f.ex. policy version), it looks like that: UPDATE test_accs SET acc_owner = '', acc_policy_version = '1.2', acc_policy_last_update = '', acc_policy_next_update = '' WHERE acc_id = '1' and it isn't working. It might be possible cause of the acc_owner table values? #1366 - Incorrect integer value: '' for column 'acc_owner' at row 1 Thanks in advice.

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  • Need some advice on MVC separation..

    - by Zenph
    I should note I am using Zend Framework. Although this shouldn't affect the concrete answer, it does mean there are several places I can implement my following method (action helper, controller etc). The issue is I have buildOptions() and parseOptions() method which takes $_GET/$_POST variables based on a 'tag' and builds rules which are then used in a select query. An example would be ?modelSort=id&modelOrder=asc The 'model' in the above obviously relates to the particular model, and it used as a 'tag' so that I can for example also have model2Sort and model2Order so there is no conflict between parameters. However, the trouble I am having now is where should these methods go? They are generally dealing with request params. I have been reading a lot about fat model, thin controller. Should this be in an abstract model. My thinking was that if it were, I would do something like: (note, I know I wouldn't call directly like this. Method would be used by child classes) $abstractModel-buildOptions($params); Where 'params' could be anything, like the request parameters $_GET or $_POST: $abstractModel-buildOptions($_GET); Now from what I can see the model is not inherintly dealing with request variables but rather parameters passed to the method. Advice? Where does this method belong? Model, Controller? Specifically on Zend, should it be an action helper, plugin, within an abstract model? Appreciate any advice.

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  • The way to send duplicate email to the user?

    - by Josephine
    I made simple email in wordpress but it would only send email to the administrator email. I need to find the way to send duplicate email with Thanks to the user. $emailTo = get_option('tz_email'); if (!isset($emailTo) || ($emailTo == '') ){ $emailTo = get_option('admin_email'); } $subject = 'I Have A Question to Ask from '.$name; $body = "Name: $name \n\nEmail: $email \n\nPhone: $phone \n\nComments: $comments"; $headers = 'From: '.$name.' ' . "\r\n" . 'Reply-To: ' . $email; wp_mail($emailTo, $subject, $body, $headers); $emailSent = true; } Insight is appreciated. Thank you.

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  • advanced search with mysql

    - by Arsenal
    I'm creating a search function for my website where the user can put in anything he likes in a textfield. It get's matched against anything (name, title, job, car brand, ... you name it) I initially wrote the query with an INNER JOIN on every table that needed to be searched. SELECT column1, column2, ... FROM person INNER JOIN person_car ON ... INNER JOIN car ... This ended up in a query with 6 or 8 INNER JOINs, and a whole lot WHERE ... LIKE '%searchvalue%' Now this query seems to cause a time'out in MySql, and I even got a warning from my hosting provider that the queries just taking up too many resources. Now obviously I'm doing this very wrong, but I was wondering how the correct approach to these kind of search functions is. Thanks!

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  • Copying a database into a new database including structure and data

    - by Jason
    In phpMyAdmin under operations I can "Copy database to:" and select Structure and data CREATE DATABASE before copying Add AUTO_INCREMENT value I need to be able to do that without using phpMyAdmin. I know how to create the database and user. I have a source database that's a shell that I can work from so all I really need is the how to copy all the table structure and data part. (I know, the harder part) system() & exec() are not options for me which rules out mysqldump. (I think) How can I loop through each table and recreate it's structure and data? Is it just looping through the results of SHOW TABLES then for each table looping through DESCRIBE tablename Then, is there an easy way for getting the data copied?

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  • How to convert my mysql data into this?

    - by sky
    <script type="text/javascript"> var cityList = new Array(....etc), signImgList = new Array('http:\/\/pic.sitename.com:80\/file\/11\/34\/01\/22\/default\/SIGN11340122_48x48.jpg?t=1257391453468'....etc), titleList = new Array(....etc), userSex = new Array(....etc), userAge = new Array('19','26'....etc), userMid = new Array('lwowl','kylin0621'....etc); </script>

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  • Is it possible to cancel function override in parent class and use function from top level parent

    - by Anatoliy Gusarov
    class TopParent { protected function foo() { $this->bar(); } private function bar() { echo 'Bar'; } } class MidParent extends TopParent { protected function foo() { $this->midMethod(); parent::foo(); } public function midMethod() { echo 'Mid'; } public function generalMethod() { echo 'General'; } } Now the question is if I have a class, that extends MidParent because I need to call class Target extends MidParent { //How to override this method to return TopParent::foo(); ? protected function foo() { } } So I need to do this: $mid = new MidParent(); $mid->foo(); // MidBar $taget = new Target(); $target->generalMethod(); // General $target->foo(); // Bar UPDATE Top parent is ActiveRecord class, mid is my model object. I want to use model in yii ConsoleApplication. I use 'user' module in this model, and console app doesn't support this module. So I need to override method afterFind, where user module is called. So the Target class is the class that overrides some methods from model which uses some modules that console application doesn't support.

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  • localhost + staging + production environments?

    - by Kentor
    Hello, I have a website say www.livesite.com which is currently running. I have been developing a new version of the website on my local machine with http://localhost and then committing my changes with svn to www.testsite.com where I would test the site on the livesite.com server but under another domain (its the same environment as the live site but under a different domain). Now I am ready to release the new version to livesite.com. Doing it the first time is easy, I could just copy & paste everything from testsite.com to livesite.com (not sure its the best way to do it). I want to keep testsite.com as a testing site where I would push updates, test them and once satisfied move to livesite.com but I am not sure how to do that after the new site is launched.. I don't think copy pasting the whole directory is the right way of doing it and it will break the operations of current users on the livesite.com. I also want to keep my svn history on testsite.com. What is the correct way of doing this with SVN ? Thank you so much!

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  • Spreadsheet_Excel_Writer large data output is damaged

    - by dr3w
    I use Spreadsheet_Excel_Writer to generate .xls file and it works fine until I have to deal with a large amount of data. On certain stage it just writes some nonsense chars and quits filling certain columns. However some columns are field up to the end (generally numeric data) I'm not quite sure how the xls document is formed: row by row, or col by col... Also it is obviously not an error in a string, because when i cut out some data, the error appears a little bit further. I think there is no need in all of my code here are some essentials $filename = 'file.xls'; $workbook = & new Spreadsheet_Excel_Writer(); $workbook->setVersion(8); $contents =& $workbook->addWorksheet('Logistics'); $contents->setInputEncoding('UTF-8'); $workbook->send($filename); //here is the part where I write data down $contents->write(0, 0, 'Field A'); $contents->write(0, 1, 'Field B'); $contents->write(0, 2, 'Field C'); $ROW=1; foreach($ordersArr as $key=>$val){ $contents->write($ROW, 0, $val['a']); $contents->write($ROW, 1, $val['b']); $contents->write($ROW, 2, $val['c']); $ROW++; } $workbook->close();

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  • mysql : possible to put IF statment in LEFT JOIN ?

    - by Haroldo
    Ok so i want to get an artists info from the db, but i want to know if they have any forthcoming events. To do this i need to traverse 2 tables, where events_artists is a 2 col link table... (this doesnt work but is what id like to do) SELECT art.*, events.event_id FROM art LEFT JOIN events_artists ON art.art_id = events_artists.art_id LEFT JOIN events ON events_artists.event_id = events.event_id IF ( {criteria} ) what should i be doing here to get this to work?!!

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  • mysql join 3 tables and count

    - by air
    Please look at this image here is 3 tables , and out i want is uid from table1 industry from table 3 of same uid count of fid from table 2 of same uid like in the sample example output will be 2 records Thanks

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  • How to search for a specific word in a row in MYSQL?

    - by user220755
    I have a row that has keywords in this way (keyword1, keyword2, keyword3) separated by commas as shown. When a user signs in, you know that he wants information about (keyword1, keyword3). Now, I have another table that has bunch of information related to different keywords, this table has a row called (keywords) which indicates if this information is suitable for which keyword. How do I render for the user the information he needs depending on the keywords. In other words, if the user wants information about (keyword3, keyword1) how do I go to the (information) table and find all the information that has the word (keyword1) or the word (keyword3) in the row (keyword)? Sorry if this is complicated (my explanation) but I tried my best to explain it. Thank you in advance :)

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  • CodeIgniter static class question

    - by Josh K
    If I would like to have several static methods in my models so I can say User::get_registered_users() and have it do something like public static function get_registered_users() { $sql = "SELECT * FROM `users` WHERE `is_registered` = 0"; $this->db->query($sql); // etc... } Is it possible to access the $this->db object or create a new one for a static method?

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  • dwoo template variables inside JavaScript?

    - by user344711
    Hi everyone! i have this code. {if $loginUrl} {literal} <script type="text/javascript"> var newwindow; var intId; function login() { var screenX = typeof window.screenX != 'undefined' ? window.screenX : window.screenLeft, screenY = typeof window.screenY != 'undefined' ? window.screenY : window.screenTop, outerWidth = typeof window.outerWidth != 'undefined' ? window.outerWidth : document.body.clientWidth, outerHeight = typeof window.outerHeight != 'undefined' ? window.outerHeight : (document.body.clientHeight - 22), width = 500, height = 270, left = parseInt(screenX + ((outerWidth - width) / 2), 10), top = parseInt(screenY + ((outerHeight - height) / 2.5), 10), features = ( 'width=' + width + ',height=' + height + ',left=' + left + ',top=' + top ); newwindow=window.open('{$loginUrl}','Login by facebook',features); if (window.focus) {newwindow.focus()} return false; } </script> {/literal} {/if} It is dwoo templates, i wonder how can i use my dwoo variables inside javascript? im trying to do it just at you can see at the code, but it doesnt work. I need to warp my code between {literal} so it can work.

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  • Manually Building a Tree in CakePHP

    - by mabwi
    I'm currently working on building an application in CakePHP. There's a quite extensive existing data set that's conceptually a tree, but wasn't previously stored as one. What I mean by that, is there's no real relationship defined in the data. The problem I'm having is getting it to work correctly with the CakePHP tree behaviour. Because I have to set all the values on existing data - as opposed to Cake setting up the structure as elements are inserted - I need to understand how the lft/rght values work. So, I guess the question is: How does the structure data work, specifically the lft/rght values? How do I set it up so that the data comes out rationally, without inserting them one at a time? It's a 2 level tree, with Sections and sub-sections. Thanks for the help

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  • Admin panel - what is the best way to display "static" data in the layout?

    - by rkj
    I'm about to write a admin panel for my CMS written in CodeIgniter. There will be some user information visible at all time - both in the layout's header section and the sidebar. I'm used to do it in a way that I personally hope and think could be done a lot easier, since I'm tired of sending the same parametres to the view over and over again, when it's dynamic data that needs to be displayed on every page anyways (such as unread messages, username, name, status, etc). I'll need controllers and models, I know that, but do I have to pass, just for an example, the user's username, unread messages etc. every time I need to load a view? Should I do some kind of library for this? Now my question is: How would I do it when it comes to best practice and for making it easy to maintain in the future? I hope my question is understandable :)

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