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  • PHP Array to CSV

    - by JohnnyFaldo
    I'm trying to convert an array of products into a CSV file, but it doesn't seem to be going to plan. The CSV file is one long line, here is my code: for($i=0;$i<count($prods);$i++) { $sql = "SELECT * FROM products WHERE id = '".$prods[$i]."'"; $result = $mysqli->query($sql); $info = $result->fetch_array(); } $header = ''; for($i=0;$i<count($info);$i++) { $row = $info[$i]; $line = ''; for($b=0;$b<count($row);$b++) { $value = $row[$b]; if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$data"; Also, the header doesn't force a download. I've been copy and pasting the output and saving as .csv

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  • EGODatabase does not retain inserted record

    - by user135775
    Hi Guy! I'm using EGODatabase to process my data. When I tried to insert data into the database which I created with Base and attached to the project, the data that was inserted programmatically will not show up when I restart my app.However the data inserted manually using Base will show up just fine. Following is the code for inserting data into the database: NSString *path = [[NSBundle mainBundle] pathForResource:@"Database" ofType:@"db"]; db = [EGODatabase databaseWithPath:path]; if ([db open]) { NSLog(@"Database is opened successfully!"); } else { NSLog(@"Database is failed to open!"); } NSArray *params = [NSArray arrayWithObjects:[aFeed feedID], [aFeed title], nil]; [db executeUpdate:@"Insert INTO Feed (FeedID, Title) VALUES (?, ?)" parameters:params]; EGODatabaseResult *results = [db executeQuery:@"SELECT * FROM Feed"]; for ( EGODatabaseRow * row in results) { NSLog(@"ID: %@ Title: %@", [row stringForColumn:@"FeedID"], [row stringForColumn:@"Title"]); } I appreciate if anyone can share me a working sample code for EGODatabase. I'm using EGODatabase because I might have multi-threading code that write to the database. Thank in advance.

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  • PHP & MySQL username validation and storage problem.

    - by php
    For some reason when a user enters a brand new username the error message <p>Username unavailable</p> is displayed and the name is not stored. I was wondering if some can help find the flaw in my code so I can fix this error? Thanks Here is the PHP code. if($_POST['username'] && trim($_POST['username'])!=='') { $u = "SELECT * FROM users WHERE username = '$username' AND user_id <> '$user_id'"; $r = mysqli_query ($mysqli, $u) or trigger_error("Query: $u\n<br />MySQL Error: " . mysqli_error($mysqli)); if (mysqli_num_rows($r) == TRUE) { echo '<p>Username unavailable</p>'; $_POST['username'] = NULL; } else if(isset($_POST['username']) && mysqli_num_rows($r) == 0 && strlen($_POST['username']) <= 255) { $username = mysqli_real_escape_string($mysqli, $_POST['username']); } else if($_POST['username'] && strlen($_POST['username']) >= 256) { echo '<p>Username can not exceed 255 characters</p>'; } }

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  • Variable won't store in session

    - by Mittens
    So I'm trying to store the "rank" of a user when they log in to a control panel which displays different options depending on the given rank. I used the same method as I did for storing and displaying the username, which is displayed on the top of each page and works just fine. I can't for the life of me figure out why it won't work for the rank value, but I do know that it is not saving it in the session. Here is the bit that's not working; $username = ($_POST['username']); $password = hash('sha512', $_POST['password']); $dbhost = 'mysql:host=¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦;dbname=¦¦¦¦¦¦¦¦¦¦¦'; $dbuser = '¦¦¦¦¦¦¦¦¦¦¦'; $dbpassword = '¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦'; try { $db = new PDO($dbhost, $dbuser, $dbpassword); $statement = $db->prepare("select password from users where email = :name"); $statement->execute(array(':name' => $username)); $result = $statement->fetch(); $pass = $result[password]; $rank = $result[rank];} catch(PDOException $e) {echo $e->getMessage();} if ($password == $pass) { session_start(); $_SESSION['username'] = $username; $_SESSION['rank'] = $rank; header('Location: http://¦¦¦¦¦¦¦¦¦.ca/manage.php'); } else{ include'../../includes/head.inc'; echo '<h1>Incorrect username or password.</h1>'; include'../../includes/footer.inc'; } I'm also new to the whole PDO thing, hence why my method of authenticating the password is pretty sketchy.

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  • Entity framework 4.0 compiled query with Where() clause issue

    - by Andrey Salnikov
    Hello, I encountered with some strange behavior of System.Data.Objects.CompiledQuery.Compile function - here is my code for compile simple query: private static readonly Func<DataContext, long, Product> productQuery = CompiledQuery.Compile((DataContext ctx, long id) => ctx.Entities.OfType<Data.Product>().Where(p => p.Id == id) .Select(p=>new Product{Id = p.Id}).SingleOrDefault()); where DataContext inherited from ObjectContext and Product is a projection of POCO Data.Product class. My data context in first run contains Data.Product {Id == 1L} and in second Data.Product {Id == 2L}. First using of compilled query productQuery(dataContext, 1L) works perfect - in result I have Product {Id == 1L} but second run productQuery(dataContext, 2L) always returns null, instead of context in second run contains single product with id == 2L. If I remove Where clause I will get correct product (with id == 2L). It seems that first id value caching while first run of productQuery, and therefore all further calls valid only when dataContext contains Data.Product {id==1L}. This issue can't be reproduced if I've used direct query instead of its precompiled version. Also, all tests I've performed on test mdf base using SQL Server 2008 express and Visual studio 2010 final from my ASP.net application.

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  • Why use shorter VARCHAR(n) fields?

    - by chryss
    It is frequently advised to choose database field sizes to be as narrow as possible. I am wondering to what degree this applies to SQL Server 2005 VARCHAR columns: Storing 10-letter English words in a VARCHAR(255) field will not take up more storage than in a VARCHAR(10) field. Are there other reasons to restrict the size of VARCHAR fields to stick as closely as possible to the size of the data? I'm thinking of Performance: Is there an advantage to using a smaller n when selecting, filtering and sorting on the data? Memory, including on the application side (C++)? Style/validation: How important do you consider restricting colunm size to force non-sensical data imports to fail (such as 200-character surnames)? Anything else? Background: I help data integrators with the design of data flows into a database-backed system. They have to use an API that restricts their choice of data types. For character data, only VARCHAR(n) with n <= 255 is available; CHAR, NCHAR, NVARCHAR and TEXT are not. We're trying to lay down some "good practices" rules, and the question has come up if there is a real detriment to using VARCHAR(255) even for data where real maximum sizes will never exceed 30 bytes or so. Typical data volumes for one table are 1-10 Mio records with up to 150 attributes. Query performance (SELECT, with frequently extensive WHERE clauses) and application-side retrieval performance are paramount.

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  • Custom layout in Android: scrollable graphic with selectable elements over top

    - by Martyn
    Hi, I'm fairly new to the Android platform and was wondering if I could get some advice for my current head scratcher: I'm making an app which in one view will need an image, which can be scrolled on one axis, with a load of selectable points over the top of it. Each point needs to be positionable on the x and y (unlikely to change once the app is running, but I'll need to fine tune the positions whilst I'm developing it). I'd like to be able to let the user select each point and have a graphic drawn on the point the user has selected or just draw a graphic on one/more points without user intervention. I though for the selectable points I could extend the checkbox with a custom image for the selected state - does that sounds right, or is there a better way of doing this? Is there any thing I can read up on doing this, I can't seem to find anything on the net about replacing the default images? I was going to use the absolute layout, but see that it's been depreciated and I can't find anything to replace it. Can anyone give me some code or advice on where to read up on what I need to do? Thank you in advance

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  • ASP.NET DropDownList control doesn't postback correctly inside of UserControl

    - by RichardAZ
    I have a situation where a DropDownList control is not posting back correctly. The AutoPost property is set to true, so the postback does happen, but the SelectedValue is not set to the correct value. In addition, the onSelectedIndexChanged event doesn't fire. The exact same code works perfect fine on an ASPX page, but does not work in a ASCX control. I have tried all the obvious things, I hope, trying to figure this one out, but no luck so far. I have even investigated what comes back in Request.Form["__EVENTTARGET"] and __EVENTARGUMENT. __EVENTTARGET does point to the drop down list, but the argument is empty. Can the folks of StackOverflow help lead me in the right direction to debug this issue. Of course, it is further complicated by master pages and the usual overcomplication of ASP.NET. Here is the code: <div> <asp:DropDownList ID="testDrop" runat="server" AutoPostBack="true" EnableViewState="true" onselectedindexchanged="testDrop_SelectedIndexChanged"> <asp:ListItem Value="1" Text="1">1</asp:ListItem> <asp:ListItem Value="2" Text="2">2</asp:ListItem> </asp:DropDownList> </div> And here is the generated html: <select id="ctl00_MainContent_rptAccordion_ctl00_statControl_testDrop" onchange="javascript:setTimeout('__doPostBack(\'ctl00$MainContent$rptAccordion$ctl00$statControl$testDrop\',\'\')', 0)" name="ctl00$MainContent$rptAccordion$ctl00$statControl$testDrop"> <option value="1" selected="selected">1</option> <option value="2">2</option> THANKS!

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  • PHP Session doesn't get read in next page after login validation, Why?

    - by NetStar
    I have a web site and when my users login it takes them to verify.php (where it connects to the DataBase and matches email and password to the user input and if OK puts client data into sessions and take the client to /memberarea/index.php ELSE back to login page with message "Invalid Email or password!") <?php ob_start(); session_start(); $email=$_POST['email']; $pass=md5($_POST['pass']); include("conn.php"); // connects to Database $sql="SELECT * FROM `user` WHERE email='$email' AND pass='$pass'"; $result=mysql_query($sql); $new=mysql_fetch_array($result); $_SESSION['fname']=$new['fname']; $_SESSION['lname']=$new['lname']; $_SESSION['email1']=$new['email1']; $_SESSION['passwrd']=$new['passwrd']; $no=mysql_num_rows($result); if ($no==1){ header('Location:memberarea/index.php'); }else { header("Location:login.php?m=$msg"); //msg="Invalid Login" } ?> then after email id and password is verified it takes them to ` /memberarea/index.php (This is where the problem happens.) where in index.php it checks if a session has been created in-order to block hackers to enter member area and sends them back to the login page. <? session_start(); isset($_SESSION['email'])` && `isset($_SESSION['passwrd'])` The problem is the client gets verified in verify.php (the code is above) In varify.php only after I put ob_start(); ontop of session_start(); It moves on to /memberarea/index.php , If I remove ob_start() It keeps the client on the verify.php page and displays error header is alredy SENT. after I put ob_start() it goes in to /memberarea/index.php but the session is blank, so it goes back to the login page and displays the error ($msg) "Invalid Login" which I programed to display. Can anyone tell me why the session cant pass values from verify.php to /memberarea/index.php

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  • How to reference input elements within a specific scope when there are multiple input elements of same kind?

    - by Will Merydith
    How do I select data for input elements within a specific scope? I have the same form multiple times (class "foo-form), and want to ensure I get the values for the hidden inputs within the scope of the form being submitted. Is the scope "this" implied? If not, what is the syntax for selecting input class "foo-text" within the scope of this? Feel free to point me to examples in the jquery docs - I could not find what I was looking for. $('.foo-form').submit(function() { // Store a reference to this form var $thisForm = $(this); }); <form class="foo-form"> <input type="hidden" class="foo-text"/> <input type="submit" class="button" /> </form> <form class="foo-form"> <input type="hidden" class="foo-text"/> <input type="submit" class="button" /> </form> <form class="foo-form"> <input type="hidden" class="foo-text"/> <input type="submit" class="button" /> // user clicks this submit button </form>

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  • Binding the selected value from a combobox to a member of a class.

    - by CM
    I have a combobox that is bound to a an instance of a class. I need to get the user's selection ID of the combobox and set a class property equal to it. For example, here is the class: public class robot { private string _ID; private string _name; private string _configFile; [XmlElement("hardware")] public hardware[] hardware; public string ID { get { return _ID; } set { _ID = value; } } public string name { get { return _name; } set { _name = value; } } public string configFile { get { return _configFile; } set { _configFile = value; } } } Now here is the code to bind the combobox to an instance of that class. This display's the name of each robot in the array in the combobox. private void SetupDevicesComboBox() { robot[] robot = CommConfig.robot; cmbDevices.DataSource = robot; cmbDevices.DisplayMember = "name"; cmbDevices.ValueMember = "ID"; } But now I can't seem to take what the user selects and use it. How do I use the "ID" of what the user select's from the combobox? Settings.selectedRobotID = cmbDevices.ValueMember; //This just generates "ID" regardless of what is selected. I also tried Settings.selectedRobotID = cmbDevices.SelectedItem.ToString(); //This just generates "CommConfig.robot" Thanks

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  • Attribute value nil

    - by mridula
    Can someone tell me why is this happening? I have created a social networking website using Ruby on Rails. This is my first time programming with RoR. I have a model named "Friendship" which contains an attribute "blocked" to indicate whether the user has blocked another user. When I run the following in IRB - friendship = u.friendships.where(:friend_id => 22).first IRB gives me - Friendship Load (0.6ms) SELECT `friendships`.* FROM `friendships` WHERE `friendships`.`user_id` = 17 AND `friendships`.`friend_id` = 22 LIMIT 1 => #<Friendship id: 33, user_id: 17, friend_id: 22, created_at: "2012-04-07 10:29:49", updated_at: "2012-04-07 10:29:49", blocked: 1> As u can see, the "blocked" attribute has value '1'. But when I run the following 1.9.2-p290 :030 > friendship.blocked => nil - it says, the value of blocked is 'nil' and not '1'. Why is this happening? This could be a very silly mistake but I am new to RoR, so kindly help me! I initially didn't include the accessor method for 'blocked'.. I tried that, and still its giving the same result.. Following is the Friendship model.. class Friendship < ActiveRecord::Base belongs_to :friend, :class_name => "User" validates_uniqueness_of :friend_id , :scope => :user_id attr_accessor :blocked attr_accessible :blocked end Here is the schema of the table: 1.9.2-p290 :009 > friendship.class => Friendship(id: integer, user_id: integer, friend_id: integer, created_at: datetime, updated_at: datetime, blocked: integer)

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  • getting page info from a webpage while sharing facebook style

    - by user556167
    Hi all. I am writing an app to share a page to friends when browsing. To this end, I can get the url of the page to my app and display it on the screen. Could anyone tell me, how to improve this, to show the headline of the page and the picture of a page as it appears when a page is being shared to friends on facebook. Here is the code to get and display the url of the page: Intent intent = getIntent(); String action = intent.getAction(); String type = intent.getType(); String mNewLinkUrl=""; if (action != null && type != null && Intent.ACTION_SEND.equals(action) && "text/plain".equals(type)){ mNewLinkUrl = intent.getStringExtra(Intent.EXTRA_TEXT); } TextView ptext = (TextView) findViewById(R.id.pagetext); ptext.append("\n"+mNewLinkUrl); Any insight will be appreciated. //update 1 found a method: use Jsoup to download the html as a Document. And use Elements and Element to get the data. For eg, the following is the code to get the links in imports in the html page: Elements imports = doc.select("link[href]"); for (Element link : imports) { Log.d(TAG,"link.tagName()"+link.tagName()+"link.attr(abs:href)"+link.attr("abs:href") +"link.attr(rel)"+link.attr("rel")); } But I am not able to figure out what attributes facebook exactly gets. Can anyone help me in this? Thank you.

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  • .net web service annoying issue

    - by JL
    Excuse the title, but it's best I just explain the problem. I have 2 projects in my solution A Class Library A Web Application, which consists of a web service (asmx). the web service has code sitting in the app_code folder, with a file [webservicename].cs Inside the webservice code behind class, I have a web method here is a sample example (its simplified): [WebMethod] public EnumTaskExportState ProcessTask() { var tm = new UploadTaskManager(); return tm.ProcessTask(); } Now at design time, in visual studio (2010 or 2008), when I right click on UploadTaskMananger, and then select "Go to definition". I get taken to AppData\Temp[some folder structure]...etc.... and it displays the public class definition. Instead I would like to have complete integration, so that I get taken directly to the actual class in the class library project. My guess is, this is happening because I am using the app_code route, and not a compiled file for the web service class. But I don't know any other way to do this. How can I fix this? Possibly do away with the need for the app_code directory?

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  • Followed the official android documentations but still could not use SQLite in app

    - by user366539
    My DBHelper class public class DBHelper extends SQLiteOpenHelper { public DBHelper(Context context) { super(context,"SIMPLE_DB",null,1); } @Override public void onCreate(SQLiteDatabase db) { db.execSQL("CREATE TABLE SIMPLE_TABLE ( " + "ID INTEGER PRIMARY KEY " + "DESC TEXT);"); } @Override public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { } } Activity class public class SimpleDatabase extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); DBHelper dbHelper = new DBHelper(this); SQLiteDatabase db = dbHelper.getReadableDatabase(); db.execSQL("INSERT INTO SIMPLE_TABLE VALUES (NULL, 'test');"); Cursor cursor = db.rawQuery("SELECT * FROM SIMPLE_TABLE", null); TextView text = (TextView)findViewById(R.id.textbox); text.setText(cursor.getString(0)); } } I figure it crashed (application has stopped unexpectedly!) at SQLiteDatabase db = ... because if I commented the code out from there to the end then it worked fine. But I have no idea whatsoever why it does that. Any help would be appreciated.

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  • Enabling all buttons in a repeater except for the clicked one

    - by NewAmbition
    I have a Repeater Control with various buttons in it. When the button gets clicked, it needs to disable itself so it cant be clicked again. Working. However, when I click that button, it needs to enable any other button but it. So, When I click on it, it needs to disable. When I click on another one, the previous button must enable, and that one must disable. So for I've tried: Button btnLoad = (Button)e.Item.FindControl("btnLoad"); foreach (Button b in e.Item.Controls.OfType<Button>().Select(c => c).Where(b => b != btnLoad)) { b.Enabled = true; } btnLoad.Text = "Currently Viewing"; btnLoad.Enabled = false; But it isnt working. Depending on where I put it, its either leaving all the buttons enabled (But still changing its text), or not doing anything at all. What do I need to do to make this work?

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  • jQuery UI Calendar displays too large, would like the demo size???

    - by Phill Pafford
    So I downloaded a custom themed UI for jQuery and added the calendar control to my sight (Example: link text). In the example it shows/displays the size I would like but on my webpage it's about twice the size. why??? I do have a ton of other CSS but I don't have control over the look and feel of the page (Can't touch current CSS, MEH!!). Is there a way to get the demo look on my site? I think this is the code that jQuery UI has that might be complicating things /* Component containers ----------------------------------*/ .ui-widget { font-family: Arial, Helvetica, Verdana, sans-serif; font-size: 1.1em; } .ui-widget input, .ui-widget select, .ui-widget textarea, .ui-widget button { font-family: Arial, Helvetica, Verdana, sans-serif; font-size: 1em; } .ui-widget-content { border: 1px solid #B9C4CE; background: #ffffff url(../images/ui-bg_flat_75_ffffff_40x100.png) 50% 50% repeat-x; color: #616161; } .ui-widget-content a { color: #616161; } .ui-widget-header { border: 1px solid #467AA7; background: #467AA7 url(../images/ui-bg_highlight-soft_75_467AA7_1x100.png) 50% 50% repeat-x; color: #fff; font-weight: bold; } .ui-widget-header a { color: #fff; } It's part of the Custom UI CSS

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  • php mysql error beginner

    - by Marcelo
    Hi, I'm trying to print some values on the screen from a table but I having a problem, I don't know much about string, vector and array but I think that my problem is related to them. I'm getting this on the screen Fatal error: Cannot use [] for reading ... My code $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql) or trigger_error(mysql_error().$sql); while($row = mysql_fetch_array($result)){ $DATA = $row[]; } //line with probelm mysql_close(); //html part <table> <? foreach($DATA as $row): ?> <tr> <td><?=$row['id']?></td> //more stuff </tr> <? endforeach ?> </table> What I'm trying to do is print somevalues form a database. But I'm getting this error. I'm sorry for any mistake in English, and thanks in advance for any help.

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  • How do I run an array through an IF statement in rails?

    - by codyvbrown
    I am creating an application that highlights user messages from a stream based on whether or not the user has been 'vouched'. It works fine if it's setup for a single author. For example controller: @vouch = Vouch.last.vouched_user_nickname view: <% Twitter::Search.new(params[:id]).each do |tweet| %> <li> <%= image_tag tweet.profile_image_url %> <% if @vouch.include? tweet.from_user %> <div class="flit_message_containerh"> <u> <a href="http://twitter.com/<%= tweet.from_user %>"> <%= tweet.from_user %></a></u> <%= linkup_mentions(auto_link(h tweet.text)) %> <div class="time_ago"> <%= link_to distance_of_time_in_words_to_now(tweet.created_at) , tweet %> <% else %> <div class="flit_message_container"> <u> <a href="http://twitter.com/<%= tweet.from_user %>"> <%= tweet.from_user %></a></u> <%= linkup_mentions(auto_link(h tweet.text)) %> <div class="time_ago"> <%= link_to distance_of_time_in_words_to_now(tweet.created_at) , tweet %> <% end %> But I'm having trouble doing it for multiple user nicknames. @vouch = Vouch.find(:all, :select => "vouched_user_nickname", :group => 'vouched_user_nickname' ) Any ideas would be greatly appreciated. I'm a rails noob.

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  • Optimize Duplicate Detection

    - by Dave Jarvis
    Background This is an optimization problem. Oracle Forms XML files have elements such as: <Trigger TriggerName="name" TriggerText="SELECT * FROM DUAL" ... /> Where the TriggerText is arbitrary SQL code. Each SQL statement has been extracted into uniquely named files such as: sql/module=DIAL_ACCESS+trigger=KEY-LISTVAL+filename=d_access.fmb.sql sql/module=REP_PAT_SEEN+trigger=KEY-LISTVAL+filename=rep_pat_seen.fmb.sql I wrote a script to generate a list of exact duplicates using a brute force approach. Problem There are 37,497 files to compare against each other; it takes 8 minutes to compare one file against all the others. Logically, if A = B and A = C, then there is no need to check if B = C. So the problem is: how do you eliminate the redundant comparisons? The script will complete in approximately 208 days. Script Source Code The comparison script is as follows: #!/bin/bash echo Loading directory ... for i in $(find sql/ -type f -name \*.sql); do echo Comparing $i ... for j in $(find sql/ -type f -name \*.sql); do if [ "$i" = "$j" ]; then continue; fi # Case insensitive compare, ignore spaces diff -IEbwBaq $i $j > /dev/null # 0 = no difference (i.e., duplicate code) if [ $? = 0 ]; then echo $i :: $j >> clones.txt fi done done Question How would you optimize the script so that checking for cloned code is a few orders of magnitude faster? System Constraints Using a quad-core CPU with an SSD; trying to avoid using cloud services if possible. The system is a Windows-based machine with Cygwin installed -- algorithms or solutions in other languages are welcome. Thank you!

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  • Codeigniter - Active record - sql - complex join

    - by Jack
    I have a function that retrieves all tags from a table: function global_popular_tags() { $this->db->select('tags.*, COUNT(tags.id) AS count'); $this->db->from('tags'); $this->db->join('tags_to_work', 'tags.id = tags_to_work.tag_id'); $this->db->group_by('tags.id'); $this->db->order_by('count', 'desc'); $query = $this->db->get()->result_array(); return $query; } I have another table called 'work'. The 'work' table has a 'draft' column with values of either 1 or 0. I want the COUNT(tags.id) to take into account whether the work with the specific tag is in draft mode (1) or not. Say there are 10 pieces of work tagged with, for example, 'design'. The COUNT will be 10. But 2 of these pieces of work are in draft mode, so the COUNT should really be 8. How do I manage this?

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  • mysql php problem: no error message despite error_reporting(E_ALL) line

    - by herrturtur
    index.php <html> <head> <title>Josh's Online Playground</title> </head> <body> <form method="POST" action="action.php"> <table> <tr> <td>"data for stuff"</td> <td><input type="text" ?></td> </tr> <tr> <td><input type="submit"></td> </tr> </table> </form> </body> </html> action.php <?php error_reporting(E_ALL); ini_sit("display_errors", 1); $mysqli = new mysqli('localhost', 'root', 'password', 'website'); $result = $mysqli->query("insert into stuff (data) values (' .$_POST['data'] ."'); echo $mysqli->error(); if($result = $mysqli->query("select data from stuff")){ echo 'There are '.$result->num_rows.' results.'; } while ($row = $result->fetch_object()){ echo 'stuff' . $row->data; } ?> Despite the first two lines in action.php, I get no error or warning messages. Instead I get a blank page after clicking the submit button. Do I have to do something differently to insert data?

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  • Help Me With This MS-Access Query

    - by yae
    I have 2 tables: "products" and "pieces" PRODUCTS idProd product price PIECES id idProdMain idProdChild quant idProdMain and idProdChild are related with the table: "products". Other considerations is that 1 product can have some pieces and 1 product can be a piece. Price product equal a sum of quantity * price of all their pieces. "Products" table contains all products (p EXAMPLE: TABLE PRODUCTS (idProd - product - price) 1 - Computer - 300€ 2 - Hard Disk - 100€ 3 - Memory - 50€ 4 - Main Board - 100€ 5 - Software - 50€ 6 - CDroms 100 un. - 30€ TABLE PIECES (id - idProdMain - idProdChild - Quant.) 1 - 1 - 2 - 1 2 - 1 - 3 - 2 3 - 1 - 4 - 1 WHAT I NEED? I need update the price of the main product when the price of the product child (piece) is changed. Following the previous example, if I change the price of this product "memory" (is a piece too) to 60€, then product "Computer" will must change his price to 320€ How I can do it using queries? Already I have tried this to obtain the price of the main product, but not runs. This query not returns any value: SELECT Sum(products.price*pieces.quant) AS Expr1 FROM products LEFT JOIN pieces ON (products.idProd = pieces.idProdChild) AND (products.idProd = pieces.idProdChild) AND (products.idProd = pieces.idProdMain) WHERE (((pieces.idProdMain)=5)); MORE INFO The table "products" contains all the products to sell that it is in the shop. The table "pieces" is to take a control of the compound products. To know those who are the products children. For example of compound product: computers. This product is composed by other products (motherboard, hard disk, memory, cpu, etc.)

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  • ASP.NET - Google Chrome caching DropDownList selections

    - by Fake
    I'm experiencing what seems to be a caching issue with Google Chrome and Safari on my cart page. In the cart there are 2 dropdown lists. When you hit the checkout button after changing the values in the dropdown lists, it commits what's selected in the lists to the database. It's a little bit hard to explain the unexpected behavior so I will try to write it out step by step with an illustration of my problem. Lets say the first dropdown list has the values of: VALUE1 VALUE2 VALUE3 And the second dropdown list has the values of: DUMBO1 DUMBO2 DUMBO3 I add an item to my cart. Screen Says: VALUE1, DUMBO1 Database Says: VALUE1, DUMBO1 I hit Checkout. Database says: VALUE1, DUMBO1 (I can't see the dropdown lists after I hit checkout because i'm not at the cart page) I hit the back button. Screen Says: VALUE1, DUMBO1 Database Says: VALUE1, DUMBO1 I drop down the VALUE1 combo and select VALUE2, VALUE2 is selected momentarily and then the site posts back and VALUE1 is re-selected in the drop down list (from being reloaded from the DB) MOMENTARILY Screen Says: VALUE2, DUMBO1 Database Says: VALUE1, DUMBO1 THEN AFTER POSTBACK FROM DROPDOWNLIST_SELECTIONCHANGED EVENT Screen Says: VALUE1, DUMBO1 Database Says: VALUE1, DUMBO1 Hit Checkout. Database Says VALUE1 ,DUMBO1 (I can't see the dropdown lists after I hit checkout because i'm not at the cart page) Go back. Screen Says: VALUE2, DUMBO1 Database Says: VALUE1, DUMBO1 So it appears that it's remembering my selection of VALUE2 even though it jumped back to VALUE1 before I checked out. It seems to be a caching problem, however I've got some no-cache code to prevent caching of that page that works great in firefox and internet explorer but seems to be failing in Chrome and Safari. I'm basically returning in the headers for the cart page: no-cache, no-store, and must-revalidate to attempt to prevent caching, but based on this scenario it seems to be caching the page anyway and not reloading it when I hit the back button. I am open to any solutions or suggestions at this point. Thanks!

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  • Visual Studio 2010 is not allowing me to debug my code

    - by Tejs
    So, this interesting issue has been plaguing me for the past couple of hours. Visual Studio 2010 Ultimate no longer attaches the debugger and lets me debug my code. If I use the built in development server, then everything works fine. If I switch to Use Local IIS Web Server (http://localhost/), then all it does it attach to w3wp.exe, but no DLLs or PDBs are loaded for anything. I can go to Debug Windows Modules, and literally nothing is loaded in this window. Conversely, when using the built in development server, the Modules window displays all the DLLs and shows that the symbols for my DLLs have been loaded. Something is obviously amiss. The VS installation is completely bone stock. In IIS, my website is configured with ASP.NET 2.0 (because no 3.5 exists to select from the drop down), along with read / log visits / index this resource options checked on the "Home Directory" tab. Some of my failed ideas: 1) If I attach to process on the iexplore.exe instance where the website is displayed, it loads Internet Explorer's DLLs, but not mine. 2) I've restarted the computer multiple times 3) I've invoked devenv.exe /resetuserdata once 4) I've confirmed that every project is indeed set to debug and not release. 5) Deleted all \bin contents and rebuilt the solution. 6) Deleted entire solution and repulled from Source Control. Can someone tell me what is wrong with this thing? I'm going to have an aneurism from the headache this is causing me.

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