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  • How to force delete cookies even if one window is still open?

    - by medopal
    Apparently in IE8, there is this option 'Preserve Favorites website data', even if I uncheck it the browser will still keep the cookies until the last window is closed. Problem scenario. say I logged in to somesite.com, then without out logging out, I closed the window, but there was still another IE8 window open. In this case IE8 will keep the cookies of this site. So If I opened the site again (same window or another) the site won't ask for login info. The client wants the web application to be logged off as soon as the user closes the browser. Can I force delete the cookies IE8 is saving? or maybe I can stop the user from closing the window until I simulate a click on logout button?

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  • Setting up new project in Eclipse

    - by kbrin80
    So I set up a new project into Eclipse and created a build.xml that creates a war file. The problem that I am having is that the only files that are included in the war are what's in the WEB-INF. How do you include my web folder into the war? Project src web WEB-INF

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  • Better way to implement custom views in a listview with simpleadapter?

    - by jonaz
    I have a value called tags which is a comma separated list of words. I want to put this into nicely designed "tag-buttons". The below works. However the line ((LinearLayout) view).removeAllViews(); seems like an ugly fix for not adding the tags multiple times every time adapter.notifyDataSetChanged(); is called after i load more rows with a setOnScrollListener() Any suggestion to "best practice" here, or at least a more good looking solution? adapter = new SimpleAdapter(activity,data, R.layout.list_transactions, new String[] {"comment", "amount","date","tags","category"}, new int[] { R.id.comment, R.id.amount,R.id.date,R.id.tags_container,R.id.category } ); SimpleAdapter.ViewBinder binder = new SimpleAdapter.ViewBinder() { @Override public boolean setViewValue(View view, Object object, String value) { //Log.d(TAG,"view.toString()= "+ view.toString()); if (view.getId() == R.id.tags_container) { String[] tags = value.split(","); ((LinearLayout) view).removeAllViews(); for (String tag : tags) { View v = createTagView(activity.getLayoutInflater(),tag); ((LinearLayout) view).addView(v); } return true; } return false; } };

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  • 3D array initialization

    - by xdevel2000
    I need to represent some spatial points: x,y,z when I try to initialize the array like this: int[][][] points { { {100, 120, 10}, {100, 120, 18}, ... } } I got an error: Uncompilable source code - not a statement where is the error?

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  • Better product to develop for, iPad or Android based tablet in a purely business related application

    - by Caylem
    Hey guys Just wondering what you'd suggest as the best platform for developing a business application for a tablet device. The application needs to be multitouch, have access to a maps API, a database on the device. It will not be going on sale in the app store or Androids market, it is purely for specific business task and not for the general consumer. Obviously the options seem to be iPhone OS and the iPad or Android and an Android tablet device. The form factor for the end product requires something in the region of 8 inch+ screen and enough processing power to provide a good experience for the end user. Any help would be much appreciated. Thanks

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  • Choosing design method for ladder-like word game.

    - by owca
    I'm trying to build a simple application, with the finished program looking like this : I will also have to implement two different GUI layouts for this. Now I'm trying to figure out the best method to perform this task. My professor told me to introduce Element class with 4 states : - empty - invisible (used in GridLayout) - first letter - other letter I've thought about following solutions (by List I mean any sort of Collection) : 1. Element is a single letter, and each line is Element[]. Game class will be array of arrays Element[]. I guess that's the dumbest way, and the validation might be troublesome. 2. Like previously but Line is a List of Element. Game is an array of Lines. 3. Like previously but Game is a List of Lines. Which one should I choose ? Or maybe do you have better ideas ? What collection would be best if to use one ?

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  • Unnecessary 'else' statement

    - by Vitalii Fedorenko
    As you know, in Eclipse you can turn on "Unnecessary 'else' statement" check that will trigger on if-then-else with premature return. And, from my experience, there are two most possible situations when use such statement: 1) Pre-check: if (validate(arg1)) { return false; } doLotOfStuff(); 2) Post-check: doLotOfStuff(); if (condition) { return foo; } else { return bar; } In the second case, if the trigger is on, Eclipse will suggest you to change the code to: doLotOfStuff(); if (condition) { return foo; } return bar; However, I think that the return with else statement is more readable as it is like direct mapping of business logic. So I am curios if this "Unnecessary 'else' statement" code convention is widespread or else statement is more preferable?

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  • Default Record Voice in Android

    - by Fevos
    Hi, i notice in the Android Default Voice Recorder that can sense how loud is your voice and show it to you in UI parameter . Can i use this from the intent or how can i program a code that sense the loudness of the voice in Android.

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  • How did this get 8?

    - by David
    Here's the code: class qual { public static int fibonacci(int n) { if (n == 0 || n == 1) { return 1; } else { return fibonacci(n-1) + fibonacci(n-2); } } public static void main(String[] arg) { System.out.println(fibonacci(5)); } } The output was 8. The output should be 8 but when I look at this I think it should be 7 ((5-1) +(5-2)). Why was the output 8? I think the reasoning behind getting 8 will make recursion maybe stop being confusing for me.

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  • JSF, writeAttribute("value", str, null) fails with strings obtained through ValueExpression.getValue

    - by Roma
    Hello, I'm having a somewhat weird problem with custom JSF component. Here's my renderer code: public class Test extends Renderer { public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); System.out.println("Value: " + val); writer.writeAttribute("value", val, null); } writer.endElement("textarea"); writer.flush(); } } The code generates: <textarea name="j_id2:j_id12:j_id19" value=""></textarea> Property binding contains "test" and as it should be, "Value: test" is successfully printed to console. Now, if I change the code to: public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); String str = "new string"; System.out.println("Value1: " + val + ", Value2: " + str); writer.writeAttribute("value", str, null); } writer.endElement("textarea"); writer.flush(); } generated html is: <textarea name="j_id2:j_id12:j_id19" value="new string"></textarea> and console output is "Value1: test, Value2: new string" What's going on here? This doesn't make sense. Why would writeAttribute differentiate between the two strings? Additional info: The component extends UIComponentBase I am using it with facelets

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  • Howto check if a object is connected to another in hibernate

    - by codevourer
    Imagine two domain object classes, A and B. A has a bidirectional one-to-many relationship to B. A is related to thousands of B. The relations must be unique, it's not possible to have a duplicate. To check if an instance of B is already connected to a given instance of A, we could perform an easy INNER JOIN but this will only ensure the already persisted relations. What about the current transient relations? class A { @OneToMany private List<B> listOfB; } If we access the listOfB and perform a check of contains() this will fetch all the connected instances of B lazy from the datasource. I only want to validate them by their primary-key. Is there an easy solution where I can do things like "Does this instance of A is connected with this instance of B?" Without loading all these data into memory and perform a based on collections?

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  • Calling web service from seems to hang

    - by anothershrubery
    I am trying to call an asmx web service from an Android app. Just literally started some Android development today. I've been following various solutions I have found on the net and on here and it seems it is more difficult than anticipated. I have tried various solutions and using KSoap2 seems to be the easiest way to implement this, well it would be if I could get it working. I have the following code which works up until a point: private class CallWebService extends AsyncTask<Void, Void, Void> { private static final String SOAP_ACTION = "http://tempuri.org/GetUser"; private static final String METHOD_NAME = "GetUser"; private static final String NAMESPACE = "http://tempuri.org/"; private static final String URL = "http://160.10.1.79:59315/Service1.asmx"; TextView tv; @Override protected Void doInBackground(Void... params) { tv=(TextView)findViewById(R.id.txtMessage); try { SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet=true; envelope.setOutputSoapObject(request); HttpTransportSE androidHttpTransport = new HttpTransportSE(URL); androidHttpTransport.call(SOAP_ACTION, envelope); Object result = (Object)envelope.getResponse(); tv.setText(result.toString()); } catch (Exception e) { tv.setText(e.getMessage()); } return null; } } It seems to hang at the line androidHttpTransport.call(SOAP_ACTION, envelope); Any ideas why? Is this the correct approach? Should I be looking in another direction?

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  • Collections removeAll method

    - by srinannapa
    I would like to know if something like below is possible , list<**MyObject**>.**removeAll**(list<**String**>) I hope the context is understandable. The list<MyObject : is a ArrayList<MyObject The list<String : is a ArrayList<String I know this can be achieved by overriding equals method in MyObject class. I would like to know if any other choice is prsent. Thanks,Srinivas N

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  • How can I change the arrow style in a JComboBox

    - by Stephane Grenier
    Let's say I want to use a custom image for the arrow in JComboBox, how can I do this? I understand it's possible using the synth xml files, or maybe even UIManager.put(...), but I don't know how. All I want to do at this time is change the arrow image to something else, either programatically or even just overriding the image it uses. How exactly can I do this?

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  • Correct handling of return data

    - by Serhiy
    Hello, I have a question related to correct handling of returns of the DAO library I'm writing for one project. This library probably is going to be used by another people and I want to do it correctly. So I would like to know, how I should deal with return statements of the functions of my DAO. Example 1 I have function to getCustomer which should return String. In case query doesn't return any result should I return null, empty string or throw some kind of Exception? Example 2 I have function getCutomerList which return ArrayList. In case query doesn't return any result should I return null, empty ArrayList or throw some Exception? Example 3 Some sql exception was detected, what should I do: throw exception or do try..catch of the block where it can occur? What is the "good" practice or "best" practice to apply in my case? Thanks on advance, Serhiy.

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  • Playing craps, asking and printing

    - by Angelo Mejia
    How do I ask the amount of games of craps someone wants to play and print the number of wins as a result of n number of games? Also How do I make a table in the main method using the previous methods I have? A table like this but shows the results: Percent Wins Games Experiment Number 1 2 3 4 5 6 7 8 9 10 100 1000 10000 100000 1000000 public class CrapsAnalysis { public static int rollDie( int n) { return (int)(Math.random()*n) + 1 ; } public static int rollDice( ) { int die1 ; int die2 ; die1 = rollDie(6) ; die2 = rollDie(6) ; return die1 + die2 ; } public static boolean playOneGame( ) { int newDice ; //repeated dice rolls int roll ; //first roll of the dice int playerPoint = 0 ; //player point if no win or loss on first roll newDice = rollDice() ; roll = rollDice() ; if (roll == 7 || roll == 11) return true; else if (roll == 2 || roll == 3 || roll == 12) return false; else { playerPoint = roll; newDice = rollDice(); do { newDice = rollDice(); } while (newDice != playerPoint || newDice != 7) ; if (newDice == 7) return false; else return true; } } public static int playGames ( int n ) { int numWon = 0; for (int i = 1; i <= n; i++) if(playOneGame()) numWon++; return numWon; } public static void main(String[] args) { //Don't know how to ask and print out the results of the number of wins depending on the n number of games played } }

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  • How do "modern JVMs" differ from older JVMs?

    - by Lord Torgamus
    Here's a phrase that I heard a lot throughout high school and university computer science classes: "That's not an issue for modern JVMs." Usually this would come up in discussions about overall performance or optimization strategies. It was always treated as a kind of magical final answer, though, as if it makes issues no longer worth thinking about. And that just leads me to wonder: what are the differences between the prototypical "modern JVM" and older JVMs, really?

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  • Is my Joda Time format pattern incorrect to produce a `T` and `Z` inside the parsed DateTime output?

    - by Tree
    Using Joda Time's pattern syntax below, this input string: Sunday, January 09, 2011 6:15:00 PM becomes this datetime: 2011-01-09T06:15:00.000Z Code: String start = "Sunday, January 09, 2011 6:15:00 PM"; DateTimeFormatter parser1 = DateTimeFormat.forPattern("EEEE, MMMM dd, yyyy H:mm:ss aa"); DateTime startTime = parser1.parseDateTime(start); Is this format pattern incorrect? If not, what are the T and Z doing inside the DateTime output? 2011-01-09T06:15:00.000Z

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  • Possible to "next track" e.g. Spotify from my app?

    - by parse
    I'm planning on doing a application for Android 2.1 that changes song every minute (through what I hope exists in Android, "next track") for the application using the audio device atm. So if I have Spotify (http://www.spotify.com) running in background already, playing music, can I through my program change to the next track? Let me know if I was unclear about anything. Thanks in advance!

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