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  • What is a proper MySql replication configuration for frequent db updates and rare selects?

    - by serg555
    We currently have 1 master db on its own server and slave db on app server. App executes very frequent but light updates (like increasing counters), and occasional (once in a few minutes) heavy selects (which is the most important part of the app). When app was connected only to master db there were no performance issues. With slave db introduction CPU load avg on app server increased to about 6-10 during that heavy select period (from 3-4 as before). When server doesn't run those frequent updates it seems like performance for selects stays within the limits. So I have a feeling that those updates is what is causing the performance drop (also these frequent updates are not critical so if slave db doesn't have them in sync with master for some time it would be ok). What would be a good db replication setup for such kind of app? What are the replication parameters we could tweak? Thanks.

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  • No remote access to PostgreSQL db

    - by gattol
    i'm stuck in connecting to a PostresSQL database from remote host. The server is accepting incoming connections on port 5432 and i've configured pg_hba.conf like this: local all all md5 host all all 0.0.0.0/0 md5 and the postgresql.conf like this: listen_addresses = '*' port = 5432 max_connections = 100 I don't have any problem accessing from local but when i try to connect via psql with something like this: psql -U myuser -h hostname db_name I get this error: psql: FATAL: no pg_hba.conf entry for host "87.zz.yy.xxx", user "myuser", database "db_name", SSL off I also tried to put the host 87.zz.yy.xxx in the pg_hba.conf file without success.

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  • Strange Photoshop Problem: Can not select, zoom, paint, option button 'locked'

    - by nikcub
    I have a very strange problem with Photoshop. I can not use any of the tools, since the cursor appears 'locked'. If I select v on my keyboard, it goes to the zoom tool, but the cursor does not change. If I select the paintbrush tool, I can only paint if I hold down the option key. This is what the cursor look like (I had to paint it since I couldn't capture it). It is a rectangle with two lines through it. I am running Photoshop CS4 on a Macbook Pro with Mac OS X 10.6.6. Using both the trackpad and an external Logitech MX5000 mouse I see the same issue. This started when I fired up Photoshop today for the first time in a while. I can't remember changing any options or doing anything that could cause this. Is it possible that the option key is somehow locked in place, or there is some equivalent of num lock on? Very strange problem, I would appreciate any help anybody can offer. Edit: To add, the icon remains the same within all the menu options - it never goes back to being just a normal mouse cursor. Also, right click works fine, and if I hold down option, the cursor goes back to normal and I can paint with it. I can't use Marquee, Lasso, Crop, Type etc. even with option held down. When I go into Bridge, it is the same icon.

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  • 10 Million records = wiped MySQL DB?

    - by Josh K
    So I was trying to load some test data and it appears to have killed my entire database. This is one case where it's great to have backups! They were all plain insert queries, probably about a 900 MB file. What could have gone wrong?

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  • Mirror for Oracle DB 10g or 11g download

    - by kane77
    I was trying to download Oracle Database (10g and 11g). On webpage of oracle there are links, however they give me 404 when I accept OTN license and try to download. I googled around and found forum with users reporting the same issue and the workaround was to change the url of download link from download.oracle.com/... to download download-uk.oracle.com/... however this does not work either, is there any mirror that is working at the moment?

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  • Modify Oracle SOA Suite 11g repository DB config

    - by Alfabravo
    Hello there! Don't know if this question goes here or in superuser. Anyhow, let's try. I have an Oracle SOA Suite installed in a server. The repository database is installed in another server. Both are virtual. Sadly, we don't have snapshots neither UPS and lights went off yesterday... the repo database is now a bunch of unformed bits and we need to recreate it. ¿Is there any way to reconfigure Oracle SOA Suite to use a brand new repository? Or should I paninfully reinstall the whole crap? Thanks in advance.

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  • Allowing wildcard (%) access on MySQL db, getting error "access denied for '<user>'@'localhost'"

    - by Wayne M
    I've created a database and a user, and allowed access via the following: create user 'someuser'@'%' identified by 'password'; grant all privileges on somedb.* to 'someuser' with grant option; however, when I try to connect to MySQL I get the following error: $ mysql -u someuser -p > Enter Password: > ERROR 1045 (28000): Access denied for user 'someuser'@'localhost' (using password: YES) If "%" is the wildcard, then wouldn't it also enable localhost?

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  • IsNumeric() Broken? Only up to a point.

    - by Phil Factor
    In SQL Server, probably the best-known 'broken' function is poor ISNUMERIC() . The documentation says 'ISNUMERIC returns 1 when the input expression evaluates to a valid numeric data type; otherwise it returns 0. ISNUMERIC returns 1 for some characters that are not numbers, such as plus (+), minus (-), and valid currency symbols such as the dollar sign ($).'Although it will take numeric data types (No, I don't understand why either), its main use is supposed to be to test strings to make sure that you can convert them to whatever numeric datatype you are using (int, numeric, bigint, money, smallint, smallmoney, tinyint, float, decimal, or real). It wouldn't actually be of much use anyway, since each datatype has different rules. You actually need a RegEx to do a reasonably safe check. The other snag is that the IsNumeric() function  is a bit broken. SELECT ISNUMERIC(',')This cheerfully returns 1, since it believes that a comma is a currency symbol (not a thousands-separator) and you meant to say 0, in this strange currency.  However, SELECT ISNUMERIC(N'£')isn't recognized as currency.  '+' and  '-' is seen to be numeric, which is stretching it a bit. You'll see that what it allows isn't really broken except that it doesn't recognize Unicode currency symbols: It just tells you that one numeric type is likely to accept the string if you do an explicit conversion to it using the string. Both these work fine, so poor IsNumeric has to follow suit. SELECT  CAST('0E0' AS FLOAT)SELECT  CAST (',' AS MONEY) but it is harder to predict which data type will accept a '+' sign. SELECT  CAST ('+' AS money) --0.00SELECT  CAST ('+' AS INT)   --0SELECT  CAST ('+' AS numeric)/* Msg 8115, Level 16, State 6, Line 4 Arithmetic overflow error converting varchar to data type numeric.*/SELECT  CAST ('+' AS FLOAT)/*Msg 8114, Level 16, State 5, Line 5Error converting data type varchar to float.*/> So we can begin to say that the maybe IsNumeric isn't really broken, but is answering a silly question 'Is there some numeric datatype to which i can convert this string? Almost, but not quite. The bug is that it doesn't understand Unicode currency characters such as the euro or franc which are actually valid when used in the CAST function. (perhaps they're delaying fixing the euro bug just in case it isn't necessary).SELECT ISNUMERIC (N'?23.67') --0SELECT  CAST (N'?23.67' AS money) --23.67SELECT ISNUMERIC (N'£100.20') --1SELECT  CAST (N'£100.20' AS money) --100.20 Also the CAST function itself is quirky in that it cannot convert perfectly reasonable string-representations of integers into integersSELECT ISNUMERIC('200,000')       --1SELECT  CAST ('200,000' AS INT)   --0/*Msg 245, Level 16, State 1, Line 2Conversion failed when converting the varchar value '200,000' to data type int.*/  A more sensible question is 'Is this an integer or decimal number'. This cuts out a lot of the apparent quirkiness. We do this by the '+E0' trick. If we want to include floats in the check, we'll need to make it a bit more complicated. Here is a small test-rig. SELECT  PossibleNumber,         ISNUMERIC(CAST(PossibleNumber AS NVARCHAR(20)) + 'E+00') AS Hack,        ISNUMERIC (PossibleNumber + CASE WHEN PossibleNumber LIKE '%E%'                                          THEN '' ELSE 'E+00' END) AS Hackier,        ISNUMERIC(PossibleNumber) AS RawIsNumericFROM    (SELECT CAST(',' AS NVARCHAR(10)) AS PossibleNumber          UNION SELECT '£' UNION SELECT '.'         UNION SELECT '56' UNION SELECT '456.67890'         UNION SELECT '0E0' UNION SELECT '-'         UNION SELECT '-' UNION SELECT '.'         UNION  SELECT N'?' UNION SELECT N'¢'        UNION  SELECT N'?' UNION SELECT N'?34.56'         UNION SELECT '-345' UNION SELECT '3.332228E+09') AS examples Which gives the result ... PossibleNumber Hack Hackier RawIsNumeric-------------- ----------- ----------- ------------? 0 0 0- 0 0 1, 0 0 1. 0 0 1¢ 0 0 1£ 0 0 1? 0 0 0?34.56 0 0 00E0 0 1 13.332228E+09 0 1 1-345 1 1 1456.67890 1 1 156 1 1 1 I suspect that this is as far as you'll get before you abandon IsNumeric in favour of a regex. You can only get part of the way with the LIKE wildcards, because you cannot specify quantifiers. You'll need full-blown Regex strings like these ..[-+]?\b[0-9]+(\.[0-9]+)?\b #INT or REAL[-+]?\b[0-9]{1,3}\b #TINYINT[-+]?\b[0-9]{1,5}\b #SMALLINT.. but you'll get even these to fail to catch numbers out of range.So is IsNumeric() an out and out rogue function? Not really, I'd say, but then it would need a damned good lawyer.

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  • Using one sqlconnection/sqlcommand through 2 DB-bound methods

    - by dotnetdev
    I have a class with a method which gets data from a database through a SELECT stored proc. This method uses a SqlDbReader by returning ExecuteReader() on a SqlCommand. The connection and everything is made in this method, with fields (such as connection string) set as class level fields. I now need to populate an array based on the results of this query (so the columns of each row will go into the array with its own index). However, this query will not select all of the data from one table which is involved. I can write the queries to get what I need, but how can I use one connection throughout the class? If I instantiate the connection object and call Open() in the constructor, I get an exception @ runtime. I'm hoping for something like this: // At class level: sqlconn.Open(); // sqlcommand set up Method() { // Fire stored proc // Insert results in a collection } Method2() { // Pass same collection in (use same one), // Add new row columns into same collection } How can I do this with strict performance in mind? Thanks

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  • MIgrating to Oracle

    - by Harish
    We are using a JEE application and we are right now using Informix DB.Our code hits the DB with queries like "select first 10 * from test" Now as far as I know Oracle does not support 'first 10 *' kind of statements.We have more than 1000 queries like this.Should we manually change this or can have some manual customization?

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  • Problem with date_select when using :discard option. (Rails)

    - by MikeH
    I'm using a date_select with the option :discard_year => true If a user selects a date in the date select, and then he comes back and returns the select to the prompt values of Month and Day, Rails automatically sets the select values to January 1. I know this is the intended functionality if a month is selected and a day is left blank, but that's not the case here. In my example, the user sets both the month and day back to the prompt. By Rails forcing January 1, I'm getting bad results. I've tried every parameter available in the api. :default = nil, :include_blank = true. None of those change the behavior I'm describing. I've isolated the root of the problem, which is this: Because I'm discarding the :year parameter, when the user tries to return the month and day to the prompt values, Rails doesn't see an empty prompt select. It perhaps sees a year selected with empty month and day, which it then sets to January 1. This is the case because the :discard_year parameter does in fact set a date in the database, it just removes it from the view. How can I code around this problem?

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  • Yahoo Query Language Problem

    - by Damiano
    Hello everybody! Today, I've started with Yahoo Query Language. I would use it to retrive stocks details, so I'm talking about Yahoo Finance. I think there is a bug on this language. This is my query: select * from yahoo.finance.quoteslist where symbol='@^GSPC' I ALWAYS get 51 results! it's impossible, take a look at: http://it.finance.yahoo.com/q/cp?s=^GSPC There are 500 results! I also tried some paging parameters. select * from yahoo.finance.quoteslist(50,30) where symbol='@^GSPC' (to get from 50 to 80) select * from yahoo.finance.quoteslist(100) where symbol='@^GSPC' (to get the first 100 results) select * from yahoo.finance.quoteslist where symbol='@^GSPC' limit 30 offset 50 but ALWAYS the last stock is: <quote symbol="BBY"> <Symbol>BBY</Symbol> <LastTradePriceOnly>41.03</LastTradePriceOnly> <LastTradeDate>5/7/2010</LastTradeDate> <LastTradeTime>4:00pm</LastTradeTime> <Change>-0.48</Change> <Open>41.35</Open> <DaysHigh>42.35</DaysHigh> <DaysLow>39.60</DaysLow> <Volume>14129531</Volume> </quote> Why do I have this kind of problem? Thank you so much for your support! (P.S. I've tested it on Yahoo YQL console)

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  • Funny characters in my db

    - by hdx
    My web app is breaking when I try edit a certain content type and I'm pretty sure it is because of some weird characters in my database. So when I do: SELECT body FROM message WHERE id = 666 it returns: <p>⢠<span></span></p><p><br /></p><p><em><strong>NOTE:</strong> Please remember to use your to participate in the discussion.</em></p> However when I try to count how many documents have those characters postgres complains: foo_450_prod=# SELECT COUNT(*) FROM message WHERE body LIKE'%â¢%'; ERROR: invalid byte sequence for encoding "UTF8": 0xe2a225 HINT: This error can also happen if the byte sequence does not match the encodi Does anybody know what the issue is and how I can query for those funny characters? Thanks in advance!

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  • YAHOO QUERY LANGUAGE BUG!

    - by Damiano
    Hello everybody! Today, I've started with Yahoo Query Language. I would use it to retrive stocks details, so I'm talking about Yahoo Finance. I think there is a bug on this language. This is my query: select * from yahoo.finance.quoteslist where symbol='@^GSPC' I ALWAYS get 51 results! it's impossible, take a look at: http://it.finance.yahoo.com/q/cp?s=^GSPC There are 500 results! I also tried some paging parameters. select * from yahoo.finance.quoteslist(50,30) where symbol='@^GSPC' (to get from 50 to 80) select * from yahoo.finance.quoteslist(100) where symbol='@^GSPC' (to get the first 100 results) select * from yahoo.finance.quoteslist where symbol='@^GSPC' limit 30 offset 50 but ALWAYS the last stock is: <quote symbol="BBY"> <Symbol>BBY</Symbol> <LastTradePriceOnly>41.03</LastTradePriceOnly> <LastTradeDate>5/7/2010</LastTradeDate> <LastTradeTime>4:00pm</LastTradeTime> <Change>-0.48</Change> <Open>41.35</Open> <DaysHigh>42.35</DaysHigh> <DaysLow>39.60</DaysLow> <Volume>14129531</Volume> </quote> Why do I have this kind of problem? Thank you so much for your support! (P.S. I've tested it on Yahoo YQL console)

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  • Jquery .Show() .Hide() not working as expected

    - by fizgig07
    I'm trying to use the show and hide to display a different set of select options when a certain report type is selected. I have a couple problems with this: The .show .hide only execute properly if I pass params, slow fast, in the the first result of my conditional statement. If I take out the params or pass params in both results, only one select shows and it never changes.. here's is the code that currently kind of works. if ($('#ReportType').val() == 'PbuseExport') { $('#PbuseServices').show('fast'); $('#ReportServiceDropdown').hide('fast'); } else { $('#PbuseServices').hide(); $('#ReportServiceDropdown').show(); } After i've used this control I am taken to a differnt page. When I use the control again, it reatins the original search values and repopulates the control. Then again I only want to show one select option if a certain report is chosen.. This works correctly if the report type I originally searched on is not the "PbuseExport". If I searched on the report type "PbuseExport", then both selects show on the screen, and only until I change the report type does it show only one select. I know this probably isn't very clear.. Here is the code that handles the change event on the report type drop down. var serviceValue = $("#ReportType").val(); switch (serviceValue) { case 'PbuseExport': $('#PbuseServices').show('fast'); $('#ReportServiceDropdown').hide('fast'); default: $('#PbuseServices').hide(); $('#ReportServiceDropdown').show(); break; }

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  • Can't get values from Sqlite DB using query

    - by Sana Joseph
    I used sqlite to populate a DB with some Tables in it. I made a function at another javascript page that executes the database & selects some values from the table. Javascript: function GetSubjectsFromDB() { tx.executeSql('SELECT * FROM Subjects', [], queryNSuccess, errorCB); } function queryNSuccess(tx, results) { alert("Query Success"); console.log("Returned rows = " + results.rows.length); if (!results.rowsAffected) { console.log('No rows affected!'); return false; } console.log("Last inserted row ID = " + results.insertId); } function errorCB(err) { alert("Error processing SQL: "+err.code); } Is there some problem with this line ? tx.executeSql('SELECT * FROM Subjects', [], queryNSuccess, errorCB); The queryNSuccess isn't called, neither is the errorCB so I don't know what's wrong.

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  • Customising Flex datagrid headerText

    - by Jad
    Gurus, I have a Adobe AIR application which has a datagrid. My requirement is to allow the user to make the column headers and the number of columns of that grid, customizable. 1. How can I get the column headerText values from DB? 2. If the user can enter the column names, it has to be saved to the DB and then loaded. Pl suggest. Regards ~Jad

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  • sql CE 3.5 pros and cons

    - by Buzz
    Hi, Currently we are using xml files as local data store for our disconnected application, there is proposal to move to SQL CE database. Can some one with experience of SQL CE provide some pros and cons of using sql compact, for example data type support etc. As Central DB server we are using SQL Server2005. One of the requirement is to merge local store with central DB, and we don't want any data loss. Thanks

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  • Help with IF THEN breaking when comparing results from MYSQL query.

    - by roydukkey
    I'm have a problem with an invite system. The if statement seems to break. It shows the message "Fail" but the UPDATE statement still executes. Why do both the THEN and the ELSE excute? $dbConn = new dbConn(); // Check if POST user_username and user_hash are matching and valid; both are hidden for fields $sql = "SELECT user_username " . "FROM table_users " . "WHERE user_id=".mysql_real_escape_string($_POST["user_id"])." " . "AND user_hash='".mysql_real_escape_string($_POST["user_hash"])."' " . "AND user_enabled=0;"; $objUser = $dbConn->query($sql); // If result contains 1 or more rows if( mysql_num_rows($objUser) != NULL ){ $objUser = mysql_fetch_assoc($objUser); $ssnUser->login( $objUser["user_username"] ); $sql = "UPDATE table_users SET " . "user_enabled=1, " . "user_first_name='".mysql_real_escape_string($_POST["user_first_name"])."', " . "user_last_name='".mysql_real_escape_string($_POST["user_last_name"])."', " . "user_password='".mysql_real_escape_string( md5($_POST["user_password"]) )."' " . "WHERE user_id=".mysql_real_escape_string($_POST["user_id"]).";"; $dbConn->query($sql); echo "Success"; header( "Refresh: 5; url=/account/?action=domains" ); } else { echo "Fail"; } This dbConn Class is as follows: class dbConn{ var $username = "xxxx_admin"; var $password = "xxxxxxxx"; var $server = "localhost"; var $database = "xxxx"; var $objConn; function __construct(){ $conn = mysql_connect( $this->server, $this->username, $this->password, true ); if( !$conn ){ die("Could not connect: ".mysql_error() ); } else { $this->objConn = $conn; } unset($conn); } function __destruct(){ mysql_close( $this->objConn ); unset( $this ); } function query( $query, $db = false ){ mysql_select_db( $db != false ? $db : $this->database, $this->objConn ); $result = mysql_query( $query ); unset($query,$db); return $result; } }

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  • Most efficient way to LIMIT results in a JOIN?

    - by johnnietheblack
    I have a fairly simple one-to-many type join in a MySQL query. In this case, I'd like to LIMIT my results by the left table. For example, let's say I have an accounts table and a comments table, and I'd like to pull 100 rows from accounts and all the associated comments rows for each. Thy only way I can think to do this is with a sub-select in in the FROM clause instead of simply selecting FROM accounts. Here is my current idea: SELECT a.*, c.* FROM (SELECT * FROM accounts LIMIT 100) a LEFT JOIN `comments` c on c.account_id = a.id ORDER BY a.id However, whenever I need to do a sub-select of some sort, my intermediate level SQL knowledge feels like it's doing something wrong. Is there a more efficient, or faster, way to do this, or is this pretty good? By the way... This might be the absolute simplest way to do this, which I'm okay with as an answer. I'm simply trying to figure out if there IS another way to do this that could potentially compete with the above statement in terms of speed.

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  • mysqli::query returns true on SELECT statement

    - by Travis Pessetto
    I have an application that reads in one of its classes: public function __construct() { global $config; //Establish a connection to the database and get results set $this->db = new Database("localhost",$config["dbuser"],$config["dbpass"],"student"); $this->records = $this->db->query("SELECT * FROM major") or die("ERROR: ".$this->db->error); echo "<pre>".var_dump($this->records)."</pre>"; } My problem is that var_dump shows that $this->records is a boolean. I've read the documentation and see that the SELECT query should return a result set. This is the only query used by the application. Any ideas where I am going wrong?

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  • sql select with php variable

    - by user1572526
    I'm trying to print out a html-table from db-table 'dimensions'. I only want dimensions from the selected pipetype which I get from a dropdownbox. For now I just put in "Steel" manually. Steel has pipe_id = 2 in db-table 'pipes'. I've run the first query in my db-tool and it returns 2 so there's nothing wrong there. The second query returns nothing. But when I manually set $wq = 2 (which I comment out below) it prints out the html-table perfectly. What am I doing wrong here? $wq="SELECT pipe_id FROM pipes WHERE title_en = 'Steel'"; //$wq = '2'; $sql="SELECT * FROM dimensions WHERE pipe_id = '".$wq."'";

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  • Can't select database table even though the code is right

    - by Lisa
    I am trying to display a list of my vbulliten threads on a non-vbulliten portion of my site. However I can't select the vbulliten database: <?php $host = "localhost"; $user = "my username"; $pass = "my password"; $dbname = "tableprefix_forum"; mysql_connect($host, $user, $pass) or die ("Could not connect to database server."); mysql_select_db($dbname) or die ("Could not select database."); ?> I am substituting some things here in this example but all my credentials are correct including my db server username, password and forum db name. So what is the problem? Is it due to some internal security feature in vbulliten, does this system not allow you to connect to it's db if the page trying to connect to it is a non-vbulliten page?

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