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  • JQuery - .position isn't returning offset relative to parent.

    - by Spines
    I'm using .position to find the offset of where the element is relative to the parent, however it seems to be returning a value that is the offset from some parent up the ancestor tree. I have a button, and its wrapped withing a div and its the only element of that div. The div is floated right. .position is returning a value like {left:780, top:370}, when the true value should be around {left:200, top:0}. I'm using jquery 1.4

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  • MySQL join problem

    - by snaken
    Whats wrong with this SQL? It should return results but returns nothing SELECT `pid` FROM `products` LEFT JOIN `prods_to_features` ON (`ptf_pid` = `pid`) WHERE (`ptf_id` = '66' OR `ptf_id` = '67') AND (`ptf_id` = '76') Is it not possible to have the 2nd where clause for the table that has been used in the left join?

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  • How do I center this CSS?

    - by sarthaksss
    Here is the CSS - #slider ul, #slider li, #slider2 ul, #slider2 li{ margin:0; padding:0; list-style:none; } #slider2{margin-top:1em;} #slider li, #slider2 li{ /* define width and height of list item (slide) entire slider area will adjust according to the parameters provided here */ width:500px; height:250px; overflow:hidden; } #prevBtn, #nextBtn, #slider1next, #slider1prev{ display:block; width:30px; height:77px; position:absolute; left:-30px; top:71px; z-index:1000; } #nextBtn, #slider1next{ left:696px; } #prevBtn a, #nextBtn a, #slider1next a, #slider1prev a{ display:block; position:relative; width:30px; height:77px; background:url(../images/btn_prev.gif) no-repeat 0 0; } #nextBtn a, #slider1next a{ background:url(../images/btn_next.gif) no-repeat 0 0; } /* numeric controls */ #slider img{ width:500px; height:300px; } ol#controls{ margin:1em 0; padding:0; height:28px; } ol#controls li{ margin:0 10px 0 0; padding:0; float:left; list-style:none; height:28px; line-height:28px; } ol#controls li a{ float:left; height:28px; line-height:28px; border:1px solid #ccc; background:#b32d45; color:white; padding:0 10px; text-decoration:none; } ol#controls li.current a{ background:#5DC9E1; color:#fff; } ol#controls li a:focus, #prevBtn a:focus, #nextBtn a:focus{outline:none;} I want to center the #slider HTML <div id="slider"> <ul> <li>IMAGE</li> <li>IMAGE2</li> </ul> </div>

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  • JavaScript and error "end tag for element which is not open"

    - by Andrew Spilak
    I have problem with validation such code function show_help_tip(event, element) { var $e = $(element); var pos = $e.offset(); $('.body-balloon',$help_tip_div).html($(' <p>&nbsp;</p> ').html(element.getAttribute('title'))); $help_tip_div.css({position:'absolute',top:530,left:pos.left+$e.width()-20}).show(); } end tag for element "P" which is not open What's wrong?

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  • Implement two lists in ExtJS

    - by Anandan
    Hi, I am new to ExtJS. I want to implement two tables. First one will have list of possible items to select. Second one can be empty. I will have 4 buttons in between the two tables as "move this item left", "move all to left", "move all to right" and "move this to right". Which component should i use to implement this? Regards, Anandan

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  • Are comonads a good fit for modeling the Wumpus world?

    - by Tim Stewart
    I'm trying to find some practical applications of a comonad and I thought I'd try to see if I could represent the classical Wumpus world as a comonad. I'd like to use this code to allow the Wumpus to move left and right through the world and clean up dirty tiles and avoid pits. It seems that the only comonad function that's useful is extract (to get the current tile) and that moving around and cleaning tiles would not use be able to make use of extend or duplicate. I'm not sure comonads are a good fit but I've seen a talk (Dominic Orchard: A Notation for Comonads) where comonads were used to model a cursor in a two-dimensional matrix. If a comonad is a good way of representing the Wumpus world, could you please show where my code is wrong? If it's wrong, could you please suggest a simple application of comonads? module Wumpus where -- Incomplete model of a world inhabited by a Wumpus who likes a nice -- tidy world but does not like falling in pits. import Control.Comonad -- The Wumpus world is made up of tiles that can be in one of three -- states. data Tile = Clean | Dirty | Pit deriving (Show, Eq) -- The Wumpus world is a one dimensional array partitioned into three -- values: the tiles to the left of the Wumpus, the tile occupied by -- the Wumpus, and the tiles to the right of the Wumpus. data World a = World [a] a [a] deriving (Show, Eq) -- Applies a function to every tile in the world instance Functor World where fmap f (World as b cs) = World (fmap f as) (f b) (fmap f cs) -- The Wumpus world is a Comonad instance Comonad World where -- get the part of the world the Wumpus currently occupies extract (World _ b _) = b -- not sure what this means in the Wumpus world. This type checks -- but does not make sense to me. extend f w@(World as b cs) = World (map world as) (f w) (map world cs) where world v = f (World [] v []) -- returns a world in which the Wumpus has either 1) moved one tile to -- the left or 2) stayed in the same place if the Wumpus could not move -- to the left. moveLeft :: World a -> World a moveLeft w@(World [] _ _) = w moveLeft (World as b cs) = World (init as) (last as) (b:cs) -- returns a world in which the Wumpus has either 1) moved one tile to -- the right or 2) stayed in the same place if the Wumpus could not move -- to the right. moveRight :: World a -> World a moveRight w@(World _ _ []) = w moveRight (World as b cs) = World (as ++ [b]) (head cs) (tail cs) initWorld = World [Dirty, Clean, Dirty] Dirty [Clean, Dirty, Pit] -- cleans the current tile cleanTile :: Tile -> Tile cleanTile Dirty = Clean cleanTile t = t Thanks!

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  • traverse a binary decison tree using python?

    - by kaushik
    how to traverse a binary decision tree using python language. given a tree,i want know how can we travesre from root to required leaf the feature of the required leaf are given in an dictionary form assume and have to traverse from root to leaf answering the questions at each node with the details given in feature list.. the decision tree node has format ((question)(left tree)(right tree)) while traversing it should answer question at each node and an choose left or right and traverse till leaf?

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  • How can I animate multiple elements sequentially using jQuery?

    - by lorenzium
    I thought it would be simple but I still can't get it to work. By clicking one button, I want several animations to happen - one after the other - but now all the animations are happening at once. Here's my code - can someone please tell me where I'm going wrong?: $(".button").click(function(){ $("#header").animate({top: "-50"}, "slow") $("#something").animate({height: "hide"}, "slow") $("ul#menu").animate({top: "20", left: "0"}, "slow") $(".trigger").animate({height: "show", top: "110", left: "0"}, "slow"); });

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  • Adding LambaExpression to an instance of IQueryable

    - by Paul Knopf
    ParameterExpression parameter = Expression.Parameter(typeof(Product), "x"); MemberExpression Left = Expression.MakeMemberAccess(parameter, typeof(Product).GetProperty("Name")); ConstantExpression Right = Expression.Constant(value, typeof(String)); BinaryExpression expression = Expression.Equal(Left, Right); LambdaExpression lambada = Expression.Lambda<Func<Product, bool>>(expression, parameter); Now how do I add this lambada to an instance of an IQuerybale, lets say _query _query.Where(lambada.Compile());?

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  • NHibernate join and projection properties

    - by devgroup
    Hello, I have simple situation (like on the image link text) and simple SQL query SELECT M.Name, A.Name, B.Name FROM Master M LEFT JOIN DetailA A ON M.DescA = A.Id LEFT JOIN DetailB B ON M.DescB = B.Id How to achive the same effect in nHibernate using CriteriaAPI ?

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  • Boxy Submit Form

    - by jornbjorndalen
    I am using the boxy jQuery plugin in my page to display a form on a clickEvent for the fullCalendar plugin. It is working all right , the only problem I have is that the form in boxy brings up the confirmation dialog the first time the dialog is opened and when the user clicks "Ok" it submits the form a second time which generates 2 events on my calendar and 2 entries in my database. My code looks like this inside fullCalendar: dayClick: function(date, allDay, jsEvent, view) { var day=""+date.getDate(); if(day.length==1){ day="0"+day; } var year=date.getFullYear(); var month=date.getMonth()+1; var month=""+month; if(month.length==1){ month="0"+month; } var defaultdate=""+year+"-"+month+"-"+day+" 00:00:00"; var ele = document.getElementById("myform"); new Boxy(ele,{title: "Add Task", modal: true}); document.getElementById("title").value=""; document.getElementById("description").value=""; document.getElementById("startdate").value=""+defaultdate; document.getElementById("enddate").value=""+defaultdate; } I also use validators on the forms fields: $.validator.addMethod( "datetime", function(value, element) { // put your own logic here, this is just a (crappy) example return value.match(/^([0-9]{4})-([0-1][0-9])-([0-3][0-9])\s([0-1][0-9]|[2][0-3]):([0-5][0-9]):([0-5][0-9])$/); }, "Please enter a date in the format YYYY-mm-dd hh:MM:ss" ); var validator=$("#myform").validate({ onsubmit:true, rules: { title: { required: true }, startdate: { required: true, datetime: true }, enddate: { required: true, datetime: true } }, submitHandler: function(form) { //this function renders a new event and makes a call to a php script that inserts it into the db addTask(form); } }); And the form looks like this: <form id ='myform'> <table border='1' width='100%'> <tr><td align='right'>Title:</td><td align='left'><input id='title' name='title' size='30'/></td></tr> <tr><td align='right'>Description:</td><td align='left'><textarea id='description' name='description' rows='4' cols='30'></textarea></td></tr> <tr><td align='right'>Start Date:</td><td align='left'><input id='startdate' name='startdate' size='30'/></td></tr> <tr><td align='right'>End Date:</td><td align='left'><input id='enddate' name='enddate' size='30' /></td></tr> <tr><td colspan='2' align='right'><input type='submit' value='Add' /></td></tr> </table> </form>

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  • Calendar Day View in PHP

    - by JamesArmes
    I'm working on adding a day view option to an existing calendar solution. Like many people implementing their own calendars, I am trying to model Google Calendars. They have an excellent calendar solution and their day view provides a lot of flexibility. For most part, the implementation is going well; however, I'm having issues when it comes to conflicting events. Essentially, I want the events to share the same space, side by side. Events that start at the same time should have the longest event first. In the example data set I'm working with, I have four events: A: 10:30 - 11:30 B: 13:30 - 14:30 C: 10:30 - 11:00 D: 10:45 - 14:00 I can handle A, C, and D just fine, the problem comes with D. A should be left of C which should be left of D; each taking one third of the width (it's fixed width so I can do simple math to figure that out). The problem is that B should be under A and C, to the left of D. Ideally, B would take up the same amount of space as A and C (two thirds width), but I would even settle for it only taking up only one third width. My array of events looks similar to the following: $events = array( '1030' => array( 'uniqueID1' => array( 'start_time' => '1030', 'end_time' => '1130', ), 'uniqueID2' => array( 'start_time' => '1030', 'end_time' => '1100', ), ), '1045' => array( 'uniqueID3' => array( 'start_time' => '1045', 'end_time' => '1400', ), ), '1330' => array( 'uniqueID3' => array( 'start_time' => '1330', 'end_time' => '1430', ), ), ); My plan is to add some indexes to each event that include how many events it conflicts with (so I can calculate the width) and which position in that series it should be (so I can calculate the left value). However, that doesn't help the B. I'm thinking I might need an algorithm that uses some basic geometry and matrices, but I'm not sure where to begin. Any help is greatly appreciated.

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  • Circular shift operations in C++

    - by Elroy
    Left and right shift operators (<< and ) are already available in C++. However, I couldn't find out how I could perform circular shift or rotate operations. How can operations like "Rotate Left" and "Rotate Right" be performed? Rotating right twice here Initial --> 1000 0011 0100 0010 should result in: Final --> 1010 0000 1101 0000 An example would be helpful.

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  • Div not filling width of floated container (css expert needed

    - by Rayden
    I know there are many variations of this question posted, but none I've found quite provide an answer that works for this case. I basically have two left floated divs. Inside those two divs are div headers and tabled content. I want the Div headers (Hour/Minute) to stretch to the width of the tabled content, but they only do this in FF and Chrome, not IE7. IE7 is my works official browser so the one I need it to work with the most. Here is the CSS: #ui-timepicker-div { padding:0.2em; } #ui-timepicker-hours { float:left; } #ui-timepicker-minutes { margin:0 0 0 0.2em; float:left; } .ui-timepicker .ui-timepicker-header { padding:0.2em 0; } .ui-timepicker .ui-timepicker-title { line-height:1.8em; text-align:center; } .ui-timepicker table { margin:0.15em 0 0 0; font-size:.9em; border-collapse:collapse; } .ui-timepicker td { padding:1px; width:2.2em; } .ui-timepicker th, .ui-timepicker td { border:0; } .ui-timepicker td a { display:block; padding:0.2em 0.3em 0.2em 0.5em; text-align:right; text-decoration:none; } Here is the HTML (did not include tabled content): <div style="position: absolute; top: 252.667px; left: 648px; z-index: 1; display: none;" class="ui-timepicker ui-widget ui-widget-content ui-helper-clearfix ui-corner-all" id="ui-timepicker-div"> <div id="ui-timepicker-hours"> <div class="ui-timepicker-header ui-widget-header ui-helper-clearfix ui-corner-all"> <div class="ui-timepicker-title">Hour</div> </div> <table class="ui-timepicker"> </table> </div> <div id="ui-timepicker-minutes"> <div class="ui-timepicker-header ui-widget-header ui-helper-clearfix ui-corner-all"> <div class="ui-timepicker-title">Minutes</div> </div> <table class="ui-timepicker"> </table> </div> </div>

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  • Double variable argument list.

    - by Lukasz Lew
    I need something like this: class Node (left : Node*, right : Node*) I understand the ambiguity of this signature. Is there a way around it better than the following? class Node (left : Array[Node, right : Array[Node]) val n = new Node (Array(n1, n2), Array(n3)) Maybe some kind of separator like this? val n = new Node (n1, n2, Sep, n3)

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  • styling the data loaded from another page

    - by zurna
    Tabs plugin I use loads the data from another page. Data loaded is in xml format so I need to style that data loaded. How can I do it? ny suggestion highly appreciated. Data loaded needs to be used in the following: <img src="[ImageURL]" alt="" class="MultimediaImageURL" style="float:left; margin:0 10px 0 0;" /> <div class="MultimediaInfo" style="float:left; width:200px;"> <span class="MultimediaCategory" style="float:left; color:#CCC; font-size:10px; width:100%;">[CategoryName]</span> <span class="MultimediaTitle" style="float:left; color:#D90306; font-weight:bold; width:100%;">[Title]</span> tabs plugin $("div.row-title").tabs("div.panes", {effect: 'ajax'}, function(i) { // get the pane to be opened var pane = this.getPanes().eq(i); // load it with a page specified in the tab's href attribute pane.html('<img src="http://www.refinethetaste.com/FLPM/cp/images/loading.gif" alt="Loading..." />') .load(this.getTabs().eq(i).attr("href")); }); xml <rows> - <row id="1"> <MultimediaTitle>Hagi Goals</MultimediaTitle> <ImageURL>/FLPM/media/images/5Y2K4T5V_sm.jpg</ImageURL> - <Videos> - <VideoID id="1"> <VideoURL>/FLPM/media/videos/0H7T9C0F.flv</VideoURL> </VideoID> - <VideoID id="2"> <VideoURL>/FLPM/media/videos/9L6X9G9J.flv</VideoURL> </VideoID> </Videos> </row> </rows>

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  • How to align Definition Lists in IE6 ?

    - by ellander
    I'm having a major headache trying to align some and elements in ie6. It looks fine in ie7 and firefox but the dt elements don't appear in ie6. can anyone help? here is the code.. <div id="listMembers"> <h3>Members</h3> <dl class="myDL"> <dt>Name</dt> <dd>John Smith</dd> <dt>Address</dt> <dd>the street</dd> ... </dl> <div id="listOptions"> <div> <table>...</table> </div> </div> <div> and the css:- DL.myDL { BORDER-RIGHT: black 2px outset; PADDING-RIGHT: 2px; BORDER-TOP: black 2px outset; DISPLAY: block; PADDING-LEFT: 2px; BACKGROUND: #ccbe99; PADDING-BOTTOM: 2px; BORDER-LEFT: black 2px outset; WIDTH: auto; PADDING-TOP: 2px; BORDER-BOTTOM: black 2px outset; FONT-FAMILY: "Trebuchet MS", Arial, sans-serif } DL.myDL DT { CLEAR: both; PADDING-RIGHT: 3px; DISPLAY: inline; FLOAT: left; WIDTH: 250px; TEXT-ALIGN: right } I basically want the dt text aligned to the right and the dd on the right hand side with left align text. I reset the margin on all elements to be 0 before anything else in the css and the elements are within a dive with position relative.

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  • Why are my lines getting thicker and thicker?

    - by mystify
    I try to draw some lines with different colors. This code tries to draw two rectangles with 1px thin lines. However, the second rectangle is drawn with 2px width lines, while the first one is drawn with 1px width. - (void)addLineFrom:(CGPoint)p1 to:(CGPoint)p2 context:(CGContextRef)context { // set the current point CGContextMoveToPoint(context, p1.x, p1.y); // add a line from the current point to the wanted point CGContextAddLineToPoint(context, p2.x, p2.y); } - (void)drawRect:(CGRect)rect { CGContextRef context = UIGraphicsGetCurrentContext(); CGPoint from, to; // ----- draw outer black frame (left, bottom, right) ----- CGContextBeginPath(context); // set the color CGFloat lineColor[4] = {26.0f * colorFactor, 26.0f * colorFactor, 26.0f * colorFactor, 1.0f}; CGContextSetStrokeColor(context, lineColor); // left from = CGPointZero; to = CGPointMake(0.0f, rect.size.height); [self addLineFrom:from to:to context:context]; // bottom from = to; to = CGPointMake(rect.size.width, rect.size.height); [self addLineFrom:from to:to context:context]; // right from = to; to = CGPointMake(rect.size.width, 0.0f); [self addLineFrom:from to:to context:context]; CGContextStrokePath(context); CGContextClosePath(context); // ----- draw the middle light gray frame (left, bottom, right) ----- CGContextSetLineWidth(context, 1.0f); CGContextBeginPath(context); // set the color CGFloat lineColor2[4] = {94.0f * colorFactor, 94.0f * colorFactor, 95.0f * colorFactor, 1.0f}; CGContextSetStrokeColor(context, lineColor2); // left from = CGPointMake(200.0f, 1.0f); to = CGPointMake(200.0f, rect.size.height - 2.0f); [self addLineFrom:from to:to context:context]; // bottom from = to; to = CGPointMake(rect.size.width - 2.0f, rect.size.height - 2.0f); [self addLineFrom:from to:to context:context]; // right from = to; to = CGPointMake(rect.size.width - 2.0f, 1.0f); [self addLineFrom:from to:to context:context]; // top from = to; to = CGPointMake(1.0f, 1.0f); [self addLineFrom:from to:to context:context]; CGContextStrokePath(context); }

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  • Need help with 2 MySql Queries. Join vs Subqueries.

    - by BugBusterX
    I have 2 tables: user: id, name message: sender_id, receiver_id, message, read_at, created_at There are 2 results I need to retrieve and I'm trying to find the best solution. I have included queries that I'm using in the very end. I need to retrieve a list of users, and also with each user have information available whether there are any unread messages from each user (them as sender, me as receiver) and whether or not there are any read messages between us ( they send I'm receiver or I send they are receivers) I need Same as above, but only those members where there has been any messaging between us, sorted by unread first, then by last message received. Can you advise please? Should this be done with joins or subqueries? In first case I do not need the count, I just need to know whether or not there is at least one unread message. I'm posting code and my current queries, please have a look when you get a chance: BTW, everything is the way I want in fist query. My concern is: In second query I would like to order by messages.created_at, but I dont think I can do that with grouping? And also I dont know if this approach is the most optimized and fast. CREATE TABLE `user` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) INSERT INTO `user` VALUES (1,'User 1'),(2,'User 2'),(3,'User 3'),(4,'User 4'),(5,'User 5'); CREATE TABLE `message` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `sender_id` bigint(20) DEFAULT NULL, `receiver_id` bigint(20) DEFAULT NULL, `message` text, `read_at` datetime DEFAULT NULL, `created_at` datetime NOT NULL, PRIMARY KEY (`id`) ) INSERT INTO `message` VALUES (1,3,1,'Messge',NULL,'2010-10-10 10:10:10'),(2,1,4,'Hey','2010-10-10 10:10:12','2010-10-10 10:10:11'),(3,4,1,'Hello','2010-10-10 10:10:19','2010-10-10 10:10:15'),(4,1,4,'Again','2010-10-10 10:10:25','2010-10-10 10:10:21'),(5,3,1,'Hiii',NULL,'2010-10-10 10:10:21'); SELECT u.*, m_new.id as have_new, m.id as have_any FROM user u LEFT JOIN message m_new ON (u.id = m_new.sender_id AND m_new.receiver_id = 1 AND m_new.read_at IS NULL) LEFT JOIN message m ON ((u.id = m.sender_id AND m.receiver_id = 1) OR (u.id = m.receiver_id AND m.sender_id = 1)) GROUP BY u.id SELECT u.*, m_new.id as have_new, m.id as have_any FROM user u LEFT JOIN message m_new ON (u.id = m_new.sender_id AND m_new.receiver_id = 1 AND m_new.read_at IS NULL) LEFT JOIN message m ON ((u.id = m.sender_id AND m.receiver_id = 1) OR (u.id = m.receiver_id AND m.sender_id = 1)) where m.id IS NOT NULL GROUP BY u.id

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  • Nesting QDockWidgets

    - by Brent Parker
    Right now I have four customized QDockWidgets on the left side of my application. When you start the application, each one is visible, but very small because of the visibility of each one. I would like for three of the QDockWidgets to nest behind one primary one to give that one priority and the entire left side of the screen. Does anyone know how to tell QDockWidgets to nest when they are created?

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  • wpf how to bind a listbox to a list (two ways) - c#

    - by user429400
    Hi, I want to create a 2 way bind between a listbox and a .NET list. In my GUI, I have a listbox, a textbox and add and remove buttons. The listbox displays cars, and my goal is to create a 2way bind between the .Net car list and the listbox: when the user enters a car into the textbox, it gets updated only in the .Net list, and the listbox is updated automatically. When the user press the GUI "remove" button, a car gets removed from the GUI and the .Net list is updated automatically. I've started to write the xaml code, but figured that I don't actually know how to do the binding on both sides (c# and xaml): <Window x:Class="WpfApplication1.Window1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:c="clr-namespace:WpfApplication1" Title="Window1" Height="300" Width="369" Loaded="Window_Loaded"> <Window.Resources> <ObjectDataProvider x:Key="carsData" ObjectType="{x:Type c:Window1}" /> </Window.Resources> <Grid Width="332"> <ListBox Margin="10,62,0,100" Name="myListBox" HorizontalAlignment="Left" Width="120" ItemsSource="{Binding Source={StaticResource CarsData}}"/> <Button Height="23" Margin="66,0,0,65" Name="addBtn" VerticalAlignment="Bottom" Click="addBtn_Click" HorizontalAlignment="Left" Width="64">add</Button> <TextBox Margin="10,0,0,64.48" Name="myTextBox" Height="23" VerticalAlignment="Bottom" HorizontalAlignment="Left" Width="47" /> <Button Height="23" Margin="66,0,0,33" Name="removeButton" VerticalAlignment="Bottom" HorizontalAlignment="Left" Width="64" Click="removeButton_Click">Remove</Button> </Grid> </Window> There is my c# code: namespace WpfApplication1 { public partial class Window1 : Window { MyModel listMgr; ObservableCollection carList; public Window1() { InitializeComponent(); listMgr = new MyModel(); } private void addBtn_Click(object sender, RoutedEventArgs e) { listMgr.add(new Car(0, myTextBox.Text, 2011)); } private void removeButton_Click(object sender, RoutedEventArgs e) { //myListBox.Items.RemoveAt(0); } private void Window_Loaded(object sender, RoutedEventArgs e) { carList = listMgr.getList(); myListBox.DataContext = carList; //secondListBox.DataContext = carList; } } } Thanks, Li

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  • Complex multiple join query across 3 tables

    - by Keir Simmons
    I have 3 tables: shops, PRIMARY KEY cid,zbid shop_items, PRIMARY KEY id shop_inventory, PRIMARY KEY id shops a is related to shop_items b by the following: a.cid=b.cid AND a.zbid=b.szbid shops is not directly related to shop_inventory shop_items b is related to shop_inventory c by the following: b.cid=c.cid AND b.id=c.iid Now, I would like to run a query which returns a.* (all columns from shops). That would be: SELECT a.* FROM shops a WHERE a.cid=1 AND a.zbid!=0 Note that the WHERE clause is necessary. Next, I want to return the number of items in each shop: SELECT a.*, COUNT(b.id) items FROM shops a LEFT JOIN shop_items b ON b.cid=a.cid AND b.szbid=a.zbid WHERE a.cid=1 GROUP BY b.szbid,b.cid As you can see, I have added a GROUP BY clause for this to work. Next, I want to return the average price of each item in the shop. This isn't too hard: SELECT a.*, COUNT(b.id) items, AVG(COALESCE(b.price,0)) average_price FROM shops a LEFT JOIN shop_items b ON b.cid=a.cid AND b.szbid=a.zbid WHERE a.cid=1 GROUP BY b.szbid,b.cid My next criteria is where it gets complicated. I also want to return the unique buyers for each shop. This can be done by querying shop_inventory c, getting the COUNT(DISTINCT c.zbid). Now remember how these tables are related; this should only be done for the rows in c which relate to an item in b which is owned by the respective shop, a. I tried doing the following: SELECT a.*, COUNT(b.id) items, AVG(COALESCE(b.price,0)) average_price, COUNT(DISTINCT c.zbid) FROM shops a LEFT JOIN shop_items b ON b.cid=a.cid AND b.szbid=a.zbid LEFT JOIN shop_inventory c ON c.cid=b.cid AND c.iid=b.id WHERE a.cid=1 GROUP BY b.szbid,b.cid However, this did not work as it messed up the items value. What is the proper way to achieve this result? I also want to be able to return the total number of purchases made in each shop. This would be done by looking at shop_inventory c and adding up the c.quantity value for each shop. How would I add that in as well?

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