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  • Entity Framework - Store parent reference on child relationship (one -> many)

    - by contactmatt
    I have a setup like this: [Table("tablename...")] public class Branch { public Branch() { Users = new List<User>(); } [Key] public int Id { get; set; } public string Name { get; set; } public List<User> Users { get; set; } } [Table("tablename...")] public class User { [Key] public int Id {get; set; } public string Username { get; set; } public string Password { get; set; } [ForeignKey("ParentBranch")] public int? ParentBranchId { get; set; } // Is this possible? public Branch ParentBranch { get; set; } // ??? } Is it possible for the User to know what parent branch it belongs to? The code above is not working. Entity Framework version 5.0 .NET 4.0 c#

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  • How to copy referenced assembly's dependecies to ASP.NET output bin folder?

    - by LD2008
    Hi all, In Visual Studio 2010, I have project A (asp.net application). Project A references project B (class library). Project B references assembly C (direct reference to a DLL). When building project A, only project A and project B binaries are present in the /bin directory of project A, but not the assembly C. Why is that? If project B depends on assembly C, why is assembly C not copied together to the output folder? "Copy local" is already set to "true" for assembly C. Any information would be appreciated. Thanks!

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  • Missing $ on loop variable

    - by k0re
    Hi, 1 #!/usr/bin/perl 2 use strict; 3 use warnings; 4 5 my @array = qw[a b c]; 6 foreach my($a,$b,$c) (@array) { 7 print "$a , $b , $c\n"; 8 } I receive following error: Missing $ on loop variable What is wrong? I am using: perl v5.10.1 (*) built for x86_64-linux-thread-multi

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  • Excel assign copied sheet name as variable

    - by rach-90
    I'm trying to copy an existing sheet in my workbook and then I want to use the copied sheet to run the rest of my code. (Sheet3 is the existing sheet, S_Temp is the copied sheet) Dim s_Temp as string Sheet3.copy Activesheet.name = S_Temp Sheets("S_Temp").Range("A1").value = "Test" How can I reference to the copied sheet?

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  • Linking a Text Box to a variable?

    - by cam
    I would like to have direct access to the text inside a textbox on another form, so I added a public variable _txt to a form and added an event like so: private void richTextBox1_TextChanged(object sender, EventArgs e) { _txt = richTextBox1.Text; } But the form is loaded like this: public FrmTextChild(string text) { InitializeComponent(); _txt = text; richTextBox1.Text = _txt; Text = "Untitled.txt"; } Is there a better way to directly link the two?

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  • Require_once to variable

    - by swamprunner7
    I want to call require_once("test.php") but not display result and save it into variable like this: //pseudocode $test = require_once('test.php'); //some operations like $test = preg_replace(…); echo $test; Is it possible?

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  • how to get an xml in a variable

    - by sam
    I have a stored procedure that will return xml. I have delared a variable of type xml and trying to execute the following code declare @v xml set @v = execute get_xml @id, 33 whereas id is returned by another query. now it keeps compalinng about the following error Incorrect syntax near the keyword 'execute'.

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  • java app behind proxy to use http_proxy variable in linux

    - by rbbeltran
    hello java guys, im thinking of a simple java app (command line) that connects to the internet to download xml file, the problem is that my ubuntu is using a proxy to connect to internet with username and password (tru http_proxy ="http://:@:" ). So My question is, could it be possible to write a java app to use http_proxy variable? instead of programmatically setting http proxy and host in every app i will write.

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  • find the total values get in a variable in php

    - by Hmwd
    hi, i am doing a shopping cart.i had a variable $total.when i add 1st product of price 200 i get $total=200 , when i add 2nd product of price 100 i get $total=200100 when i add 3rd product of price 400 i get $total=200100400 . i want to get $total=700. how to fix this problem? please help me........ thanks, Hmwd

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  • Bash, Concatenating 2 strings to reference a 3rd variable

    - by Im Fine
    I have a bash script I am having some issues with concatenating 2 variables to call a 3rd. Here is a simplification of the script, but the syntax is eluding me after reading the docs. server_list_all="server1 server2 server3"; var1 = "server"; var2 = "all"; echo $(($var1_list_$var2)); This is about as close as I get to the right answer, it acknowledges the string and tosses an error on tokenization. syntax error in expression (error token is "server1 server2 server3.... Not really seeing anything in the docs for this, but it should be doable. EDIT: Cleaned up a bit

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  • int vs const int&

    - by Valdo
    I've noticed that I usually use constant references as return values or arguments. I think the reason is that it works almost the same as using non-reference in the code. But it definitely takes more space and function declarations become longer. I'm OK with such code but I think some people my find it a bad programming style. What do you think? Is it worth writing const int& over int? I think it's optimized by the compiler anyway, so maybe I'm just wasting my time coding it, a?

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  • jQuery Reference First Column in HTML Table

    - by Vic
    I have a table where all of the cells are INPUT tags. I have a function which looks for the first input cell and replaces it with it's value. So this: <tr id="row_0" class="datarow"> <td><input class="tabcell" value="Injuries"></td> <td><input class="tabcell" value="01"></td> becomes this: <tr id="row_0" class="datarow"> <td>Injuries</td> <td><input class="tabcell" value="01"></td> Here is the first part of the function: function setRowLabels() { var row = []; $('.dataRow').each(function(i) { row.push($('td input:eq(0)', this).val() + ' - '); $('td input:eq(0)', this).replaceWith($('td input:eq(0)', this).val()); $('td input:gt(0)', this).each(function(e) { etcetera But when the page reloads, the first column is not an input type, so it changes the second column to text too! Can I tell it to only change the first column, no matter what the type is? I tried $('td:eq(0)', this).replaceWith($('td:eq(0)', this).val()); but it does not work. Any suggestions appreciated! Thanks

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  • i can't get variable in function.

    - by kaym
    i can't read the variable in the function, i want to use it outside the function, here is my code. var contentLoader:URLLoader = new URLLoader(); contentLoader.load(new URLRequest("http://localhost/data.php")); function onComplete(event:Event):void { var txtu:String = event.target.data; } contentLoader.addEventListener(Event.COMPLETE, onComplete); trace(txtu); thanks.

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  • how can put a javascript variable in img tag

    - by ajithperuva
    I need to put a javascript variable as image source.That is my image tag should be in this format here i am adding my script document.getElementById("pricefilter").innerHTML ='' here variablename carries my image path.How can i put this in double quates.Please help to solve this

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  • how to declare variable in POSTGRE

    - by user307880
    I try to declare a variable in a code like this, but it's doesn't work. Can you tell me what's the problem? ERROR: syntax error at or near "VARCHAR" LINE 2: p_country VARCHAR; DECLARE p_country VARCHAR; p_country : = ''; SELECT p_country;

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  • Reference to fnc.

    - by atch
    Hi guys, Is there a way in java to do something like this: void fnc(void Reference_to_other_func()); What I'm trying is basically I have number of places where I need to display this same text to the user and the only difference is which method is invoked after this text. So for example instead of writing: System.out.println("Hello"); f1(); //in some other place System.out.println("Hello"); f2(); //etc I would like to define one function: public void f(void Reference_to_other_func()) { System.out.println("Hello"); Reference_to_other_func();//HERE I'M INVOKING } and then instead of repeating this whole code I could write something like this: f(f1); //in some other place f(f2) //etc. Thanks for answers

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