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  • ActionLink sending a model of a complex type

    - by Xenph Yan
    I'm trying to paginate the results of a "advanced search", I have a complex model that represents the search options; int ZipCode int MinAge int MaxAge Availability bool Monday bool Tuesday ... bool Friday Requirements bool FirstAid bool DriversLicense I'm using; <%: Html.ActionLink("Next »", "Save", "Notification", Model.options)%> Which correctly sends all the data at the first level, but anything that is a sub-object (Availability or requirements) isn't expanded in the URL, all I get is the class name and so I lose most of the search options when I click the link to change to a different page. Any thoughts?

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  • Drupal. Use AJAX to update view's content

    - by ozke
    Hi, I've created a view in Drupal that retrieves a list of nodes. The display of this view is a page and it works perfectly well. It does even allow me to filter its content by argument. See the current's view configuration (click to enlarge): I want to use AJAX to use the filter (by parameter) functionality without reloading the page. I've enabled the "Use AJAX" option but I am not sure on how to continue. Any ideas on how to do that? By the way, I'm building my own theme (in case that changes anything). Thanks in advance Update: Basically, this view works when I browse through section/parameter1, section/parameter2... but I want to do the same with AJAX, without reloading the page. I hope is clearer now

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  • Passing values from action class to model class in symfony

    - by THOmas
    I have a action class for saving some data to a database.In action class iam getting a id through url.I have to save the id in table. I am getting the id by $request-getParameter('id') I used this code for saving $this-form-bind($request-getParameter('question_answers')); if ($this-form-isValid()) { $this-form-save(); $this-redirect('@homepage'); } in model class i used a override save method to save extra field public function save(Doctrine_Connection $conn = null) { if ($this-isNew()) { $now=date('Y-m-d H:i:s', time()); $this->setPostedAt($now); } return parent::save($conn); so i want to get the id value here . So how can i pass id value from action class to model class is any-other way to save the id in action class itself Thanks in advance

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  • Query for model by key

    - by Jason Hall
    What I'm trying to do is query the datastore for a model where the key is not the key of an object I already have. Here's some code: class User(db.Model): partner = db.SelfReferenceProperty() def text_message(self, msg): user = User.get_or_insert(msg.sender) if not user.partner: # user doesn't have a partner, find them one # BUG: this line returns 'user' himself... :( other = db.Query(User).filter('partner =', None).get() if other: # connect users else: # no one to connect to! The idea is to find another User who doesn't have a partner, that isn't the User we already know. I've tried filter('key !=, user.key()), filter('__key__ !=, user.key()) and a couple others, and nothing returns another User who doesn't have a partner. filter('foo !=, user.key()) also returns nothing, for the record.

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  • ASP.NET MVC Referencing Html Helper from a view

    - by Dan
    I've written an Html Helper called DetailsForm to reduce repetition when displaying fields in a view. Within a view - actually a partial view, ascx file - I can refer to it like this: Storyboard.Helpers.DetailsForm.LabelAndData(Html, m => m.id) But would like to refer to it like this: LabelAndData(Html, m => m.id) A 'using' directive doesn't seem to be allowed in the ascx file. Is there an equivalent?

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  • ASP.NET MVC: View does not get rendered with updated model value

    - by Newton
    I'm experiencing the a challenge in populating the child records. My previous code was like - <%= Html.TextBox("DyeOrder.Summary[" + i + "].Ratio", Model.DyeOrder.Summary[i].Ratio.ToString("#0.00"), ratioProperties) %> This code does not render the updated values after post back. To resolve this issue my work around was like - <%= "<input id='DyeOrder_Summary_" + i + "__Ratio' name='DyeOrder.Summary[" + i + "].Ratio' value='" + Model.DyeOrder.Summary[i].Ratio.ToString("#0.00") + "' " + ratioCss + " type='text' />"%> This is very clumsy to me. Is there any better ideas...

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  • persistent view controller

    - by derrichh
    Im building an iphone radio application and I want to have the controls, play, pause, stop, etc. in a tool bar (a custom view controller) at the bottom of the application. I want to keep this there throughout all the views so you can control the audio while navigating through the other parts of the application (multiple view/table controllers). Is there a way to create a view that stays in place like a tab bar?

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  • Problem autosizing second view

    - by Ruthy
    Hello, Once a view is called from appdelegate, it is properly loaded but not autosized correctly, on the bottom you see last lines from previous view! On xib file, view mode property is set to scale to fill but I tried others and still happening the same... Thanks for any idea to solve it!

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  • ListView is Widget(View) or Layout(Viewgroup)?

    - by Manoj Maurya
    Hi All, I need your help to explore few topics in Android. My understanding is Widget is View and Layout is ViewGroups in Android. I described the problems as below- Please go through the below links- developer.android.com/guide/topics/ui/custom-components.html- (add http:// in the beginning) developer.android.com/resources/tutorials/views/index.html - (add http:// in the beginning) In the first link ListView is included as Widget and in the Second link ListView has been shown as Layout. So, is ListView is Widget(View) or Layout(Viewgroup)? Same is the case for Spinner in Andriod developer.android.com/resources/tutorials/views/hello-spinner.html- (add http:// in the beginning) (Link- says Spinner is Widget(View)) developer.android.com/guide/topics/ui/layout-objects.html- (add http:// in the beginning) says Spinner is Layout(ViewGroup) So, Spinner is View or ViewGroup? Please update me with your views?

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  • How to make softkeyboard candidate view not block application view?

    - by Cedric
    Hi, I am playing with the Demo SoftKeyboard the comes with the Android SDK. In portrait mode when the candidate view is shown, it doesn't move the app up as the default android keyboard does. Hence it covers part of the application view. What should be changed in order to make the candidate view in the demo softkeyboard behave as the default android keyboard does? I've also looked at the source of the android keyboard from git but found nothing related to this behavior.

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  • CCK NodeReference - Pass current user id as argument to selection view

    - by Chaulky
    Hi all, I'm trying to create a view to limit the options available to a user for a CCK NodeReference field. I want to pass the current user's ID as an argument to the view that selects the options for the CCK NodeReference field. Basically when the user creates a new item, I only want them to be able to reference a node which they created (not someone else's node). I've got a view set up that accepts a user ID as an argument, but how do I pass the current user's ID to the view from the CCK NodeReference field? Thanks in advance!!!

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  • [N]Hibernate: view-like fetching properties of associated class

    - by chiccodoro
    (Felt quite helpless in formulating an appropriate title...) In my C# app I display a list of "A" objects, along with some properties of their associated "B" objects and properties of B's associated "C" objects: A.Name B.Name B.SomeValue C.Name Foo Bar 123 HelloWorld Bar Hello 432 World ... To clarify: A has an FK to B, B has an FK to C. (Such as, e.g. BankAccount - Person - Company). I have tried two approaches to load these properties from the database (using NHibernate): A fast approach and a clean approach. My eventual question is how to do a fast & clean approach. Fast approach: Define a view in the database which joins A, B, C and provides all these fields. In the A class, define properties "BName", "BSomeValue", "CName" Define a hibernate mapping between A and the View, whereas the needed B and C properties are mapped with update="false" insert="false" and do actually stem from B and C tables, but Hibernate is not aware of that since it uses the view. This way, the listing only loads one object per "A" record, which is quite fast. If the code tries to access the actual associated property, "A.B", I issue another HQL query to get B, set the property and update the faked BName and BSomeValue properties as well. Clean approach: There is no view. Class A is mapped to table A, B to B, C to C. When loading the list of A, I do a double left-join-fetch to get B and C as well: from A a left join fetch a.B left join fetch a.B.C B.Name, B.SomeValue and C.Name are accessed through the eagerly loaded associations. The disadvantage of this approach is that it gets slower and takes more memory, since it needs to created and map 3 objects per "A" record: An A, B, and C object each. Fast and clean approach: I feel somehow uncomfortable using a database view that hides a join and treat that in NHibernate as if it was a table. So I would like to do something like: Have no views in the database. Declare properties "BName", "BSomeValue", "CName" in class "A". Define the mapping for A such that NHibernate fetches A and these properties together using a join SQL query as a database view would do. The mapping should still allow for defining lazy many-to-one associations for getting A.B.C My questions: Is this possible? Is it [un]artful? Is there a better way?

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  • R: including model specifications in xtable(anova(...))

    - by HamiltonUlmer
    Hello R comrades: I have a bunch of loglinear models, which, for our purposes will just be glm() objects called mx, my, mz. I want to get a nicely-formatted xtable of the analysis of deviance, so naturally I would want to perform xtable(anova(mx, my, mz, test = "Chisq")). The vanilla output of xtable, however, doesn't include the model specifications. I'd like to include those for all the ANOVA tests I'm running, so if there is not a param I'm missing that does this I'll probably just have to hack up my own solution. But looking over the help page, there doesn't seem to be an easy way to include the model specifications. Any thoughts? Alternatives? If it helps this was done in 2.9.1 with xtable 1.5-5.

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  • Xcode: view references for a variable?

    - by David.Chu.ca
    I am new to Xcode. I am not sure if there is a way to view a variable's references just like "Find all references" in Visual Studio by right click on a var? For example, in my .h file, I would like to know or view all the references for property isSet: @interface MyInterface { ... BOOL isSet; // view all references to this var? ... }

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  • explaining $this->load->view()

    - by ajsie
    in a controller you can use this method to load a view. but i want to know behind the scenes here. im new to php and frameworks, but i’ve learned the basics of OOP. when $this-view() is made then the method in the current class or the parent class is used. but what does this mean: $this-load-view(). what is the intermediate load? is it a function or is it a property? where is it located? how could it contain view()? grateful for explanation.

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  • Unpredictable CCK field name in returned View data

    - by AK
    I'm using views_get_view_result to directly access the data in a view. I've stumbled upon this odd behavior where cck fields are prefixed with the first field name as a query optimization. Explained here. What's bizarre though is that fields are named differently depending on whether I retrieve that data as Anonymous or as Admin. I'm pretty sure all my permissions are set up, and the view itself has no restrictions. What is going on here? This is a big problem since I can't know how to retrieve a field. Here's a dump of the two view results. Notice that node_data_field_game_date_field_game_home_score_value != node_data_field_game_official_field_game_home_score_value. // View as Admin stdClass Object ( [nid] => 3191 [node_data_field_game_date_field_game_date_value] => 2010-03-27T00:00:00 [node_type] => game [node_vid] => 5039 [node_data_field_game_date_field_game_official_value] => 0 [node_node_data_field_game_home_team_title] => TeamA [node_node_data_field_game_home_team_nid] => 3396 [node_data_field_game_date_field_game_home_score_value] => 68 [node_node_data_field_game_visitor_team_title] => TeamB [node_node_data_field_game_visitor_team_nid] => 3442 [node_data_field_game_date_field_game_visitor_score_value] => 118 ) // View as Anonymous stdClass Object ( [nid] => 3191 [node_data_field_game_date_field_game_date_value] => 2010-03-27T00:00:00 [node_type] => game [node_vid] => 5039 [node_data_field_game_official_field_game_official_value] => 0 [node_node_data_field_game_home_team_title] => TeamA [node_node_data_field_game_home_team_nid] => 3396 [node_data_field_game_official_field_game_home_score_value] => 68 [node_node_data_field_game_visitor_team_title] => TeamB [node_node_data_field_game_visitor_team_nid] => 3442 [node_data_field_game_official_field_game_visitor_score_value] => 118 )

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  • Trouble setting FIrst view controller which will appear on App Startup

    - by Matte.Car
    I'm setting setting FIrst view controller which will appear on my App Startup. It should appear an UIView first time as a tutorial and, from second time, another standard view. In AppDelegate I wrote this: #import "AppDelegate.h" #import "TabBarController.h" #import "TutorialController.h" @implementation AppDelegate TabBarController * viewControllerStandard; // standard view TutorialController * viewControllerFirst; // tutorial view @synthesize window; - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { if ([@"1" isEqualToString:[[NSUserDefaults standardUserDefaults] objectForKey:@"Startup"]]) { window.rootViewController = viewControllerStandard; } else { window.rootViewController = viewControllerFirst; } [window makeKeyAndVisible]; return YES; } It doesn't return any alert but, launching app, after splashscreen, it appear only a black screen. Without that codes everything works fine. What could be wrong? Thank you!

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  • How Do I Import a 3D Object into Adobe Flex?

    - by Kim
    Hi everyone, I wanted to know if anyone here knows how to import a 3D Object (i.e. Maya 3D Model) into Adobe Flex Application? I needed to create a simple Flex application which will allow me to rotate the 3D Object by dragging but I cannot seem to start doing it because I'm having a hard time trying to figure out how I can import my 3D model into Flex. This is exactly what I wanted to do: 3D Object in Flex I hope someone can help me. Thanks a lot :)

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  • Backbone JS central model where all views can use

    - by chchrist
    I am new to backbone js and require js. I use requirejS to organize my backbone code into modules. I don't know if this has any importance to what I want though. I want to have a central model where all my views will have access to. They should be able to get and set values. I don't want to use it as each view model though. I need to keep in memory search options, user status (logged in/out) etc. Any ideas? EDIT Maybe the answer is here? Share resources across different amd modules

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  • How to handle this type of model validation in Ruby on Rails

    - by randombits
    I have a controller/model hypothetically named Pets. Pets has the following declarations: :belongs_to owner :has_many dogs :has_many cats Not the best example, but again, it demonstrates what I'm trying to solve. Now when a request comes in as an HTTP POST to http://127.0.0.1/pets, I want to create an instance of Pets. The restriction here is, if the user doesn't submit at least one dog or one cat, it should fail validation. It can have both, but it can't be missing both. How does one handle this in Ruby on Rails? Dogs don't care if cats exists and the inverse is also true. Can anyone show some example code of what the Pets model would look like to ensure that one or the other exists, or fail otherwise? errors.add also takes an attribute, in this case, there is no particular attribute that's failing. It's almost a 'virtual' combination that's missing.

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  • Model Django Poll

    - by MacPython
    I followed the django tutorial here: http://docs.djangoproject.com/en/dev/intro/tutorial01/ and now I am at creating a poll. The code below works fine until I want to create choices, where for some reason I always get this error message: line 22, in unicode return self.question AttributeError: 'Choice' object has no attribute 'question' Unfortunatley, I dont understand where I made an error. Any help would be greatly appreciated. Thanks for the time! CODE: import datetime from django.db import models class Poll(models.Model): question = models.CharField(max_length=200) pub_date = models.DateTimeField('date published') def __unicode__(self): return self.question def was_published_today(self): return self.pub_date.date() == datetime.date.today() class Choice(models.Model): poll = models.ForeignKey(Poll) choice = models.CharField(max_length=200) votes = models.IntegerField() def __unicode__(self): return self.question

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