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  • How is starting and ending row number of a Range obtained?

    - by Robert Kerr
    Given a user-selected Range, what is the simplest way to determine the starting row number, and ending row number? Range.Address returns a string containing any number of possible formats. There has to be something simpler. Desired: Dim oRange As Range Dim startRow As Integer Dim endRow As Integer oRange = Range("A1:X50") startRow = oRange.Address.StartRow endRow = oRange.Address.EndRow of course, those properties do not exist. I want to do the same to return column letters.

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  • how to know which display number for the variable DISPLAY to be exported when ssh to server

    - by insidepower
    When i ssh to server using -X, i always confuse about which display number i should export. It seems to me sometimes the display number has been used by something, so what i can do is only export DISPLAY=localhost:0 && xclock export DISPLAY=localhost:1 && xclock export DISPLAY=localhost:2 && xclock export DISPLAY=localhost:... until the clock appear. Then i will use that display number. Each time log in to the server, the display number which is able to tunnel the gui data correct would be different. I know many of such similar questions has been asked and answer. However I couldn't find answer to my question, anyone know about it? Thanks!

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  • How to auto dial 9+Number on Cisco 7941 redial?

    - by NotDan
    Is it possible to set up a Cisco 7941 phone to dial 9 before the redial number? When I view missed calls, and try to redial one of the numbers, it always fails because it doesn't dial 9 first. I have to write the number down and then manually dial the 9 and then the number.

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  • ASM programming, how to use loop?

    - by chris
    Hello. Im first time here.I am a college student. I've created a simple program by using assembly language. And im wondering if i can use loop method to run it almost samething as what it does below the program i posted. and im also eager to find someome who i can talk through MSN messanger so i can ask you questions right away.(if possible) ok thank you .MODEL small .STACK 400h .data prompt db 10,13,'Please enter a 3 digit number, example 100:',10,13,'$' ;10,13 cause to go to next line first_digit db 0d second_digit db 0d third_digit db 0d Not_prime db 10,13,'This number is not prime!',10,13,'$' prime db 10,13,'This number is prime!',10,13,'$' question db 10,13,'Do you want to contine Y/N $' counter dw 0d number dw 0d half dw ? .code Start: mov ax, @data ;establish access to the data segment mov ds, ax mov number, 0d LetsRoll: mov dx, offset prompt ; print the string (please enter a 3 digit...) mov ah, 9h int 21h ;execute ;read FIRST DIGIT mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov first_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros add number, ax ;save ;variable <number> now contains 1st digit * 10 ;---------------------------------------------------------------------- ;read SECOND DIGIT, multiply by 10 and add in mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov second_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros. Ignore them add number, ax ;save -- nearly finished ;variable <number> now contains 1st digit * 100 + second digit * 10 ;---------------------------------------------------------------------- ;read THIRD DIGIT, add it in (no multiplication this time) mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov third_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer add number, ax ;Both my variable number and ax are 16 bits, so equal size mov ax, number ;copy contents of number to ax mov cx, 2h div cx ;Divide by cx mov half, ax ;copy the contents of ax to half mov cx, 2h; mov ax, number; ;copy numbers to ax xor dx, dx ;flush dx jmp prime_check ;jump to prime check print_question: mov dx, offset question ;print string (do you want to continue Y/N?) mov ah, 9h int 21h ;execute mov ah, 1h int 21h ;execute cmp al, 4eh ;compare je Exit ;jump to exit cmp al, 6eh ;compare je Exit ;jump to exit cmp al, 59h ;compare je Start ;jump to start cmp al, 79h ;compare je Start ;jump to start prime_check: div cx; ;Divide by cx cmp dx, 0h ;reset the value of dx je print_not_prime ;jump to not prime xor dx, dx; ;flush dx mov ax, number ;copy the contents of number to ax cmp cx, half ;compare half with cx je print_prime ;jump to print prime section inc cx; ;increment cx by one jmp prime_check ;repeat the prime check print_prime: mov dx, offset prime ;print string (this number is prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat print_not_prime: mov dx, offset Not_prime ;print string (this number is not prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat Exit: mov ah, 4ch int 21h ;execute exit END Start

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  • How to obtain a random sub-datatable from another data table

    - by developerit
    Introduction In this article, I’ll show how to get a random subset of data from a DataTable. This is useful when you already have queries that are filtered correctly but returns all the rows. Analysis I came across this situation when I wanted to display a random tag cloud. I already had the query to get the keywords ordered by number of clicks and I wanted to created a tag cloud. Tags that are the most popular should have more chance to get picked and should be displayed larger than less popular ones. Implementation In this code snippet, there is everything you need. ' Min size, in pixel for the tag Private Const MIN_FONT_SIZE As Integer = 9 ' Max size, in pixel for the tag Private Const MAX_FONT_SIZE As Integer = 14 ' Basic function that retreives Tags from a DataBase Public Shared Function GetTags() As MediasTagsDataTable ' Simple call to the TableAdapter, to get the Tags ordered by number of clicks Dim dt As MediasTagsDataTable = taMediasTags.GetDataValide ' If the query returned no result, return an empty DataTable If dt Is Nothing OrElse dt.Rows.Count < 1 Then Return New MediasTagsDataTable End If ' Set the font-size of the group of data ' We are dividing our results into sub set, according to their number of clicks ' Example: 10 results -> [0,2] will get font size 9, [3,5] will get font size 10, [6,8] wil get 11, ... ' This is the number of elements in one group Dim groupLenth As Integer = CType(Math.Floor(dt.Rows.Count / (MAX_FONT_SIZE - MIN_FONT_SIZE)), Integer) ' Counter of elements in the same group Dim counter As Integer = 0 ' Counter of groups Dim groupCounter As Integer = 0 ' Loop througt the list For Each row As MediasTagsRow In dt ' Set the font-size in a custom column row.c_FontSize = MIN_FONT_SIZE + groupCounter ' Increment the counter counter += 1 ' If the group counter is less than the counter If groupLenth <= counter Then ' Start a new group counter = 0 groupCounter += 1 End If Next ' Return the new DataTable with font-size Return dt End Function ' Function that generate the random sub set Public Shared Function GetRandomSampleTags(ByVal KeyCount As Integer) As MediasTagsDataTable ' Get the data Dim dt As MediasTagsDataTable = GetTags() ' Create a new DataTable that will contains the random set Dim rep As MediasTagsDataTable = New MediasTagsDataTable ' Count the number of row in the new DataTable Dim count As Integer = 0 ' Random number generator Dim rand As New Random() While count < KeyCount Randomize() ' Pick a random row Dim r As Integer = rand.Next(0, dt.Rows.Count - 1) Dim tmpRow As MediasTagsRow = dt(r) ' Import it into the new DataTable rep.ImportRow(tmpRow) ' Remove it from the old one, to be sure not to pick it again dt.Rows.RemoveAt(r) ' Increment the counter count += 1 End While ' Return the new sub set Return rep End Function Pro’s This method is good because it doesn’t require much work to get it work fast. It is a good concept when you are working with small tables, let says less than 100 records. Con’s If you have more than 100 records, out of memory exception may occur since we are coping and duplicating rows. I would consider using a stored procedure instead.

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  • Stage3D Camera problem

    - by Thomas Versteeg
    I am trying to create a 2D Stage3D game where you can move the camera around the level in an RTS style. I thought about using Orthographic Matrix3D functions for this but when I try to scroll the whole "stage" also scrolls. This is the Camera code: public function Camera2D(width:int, height:int, zoom:Number = 1) { resize(width, height); _zoom = zoom; } public function resize(width:Number, height:Number):void { _width = width; _height = height; _projectionMatrix = makeMatrix(0, width, 0, height); _recalculate = true; } protected function makeMatrix(left:Number, right:Number, top:Number, bottom:Number, zNear:Number = 0, zFar:Number = 1):Matrix3D { return new Matrix3D(Vector.<Number>([ 2 / (right - left), 0, 0, 0, 0, 2 / (top - bottom), 0, 0, 0, 0, 1 / (zFar - zNear), 0, 0, 0, zNear / (zNear - zFar), 1 ])); } public function get viewMatrix():Matrix3D { if (_recalculate) { _recalculate = false; _viewMatrix.identity(); _viewMatrix.appendTranslation( -_width / 2 - _x, -_height / 2 - y, 0); _viewMatrix.appendScale(_zoom, _zoom, 1); _renderMatrix.identity(); _renderMatrix.append(_viewMatrix); _renderMatrix.append(_projectionMatrix); } return _renderMatrix; } Here are two screenshots to show what I mean: How do I only let the inside of the stage3D scroll and not the whole stage?

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  • How can a large, Fortran-based number crunching codebase be modernized?

    - by Dave Mateer
    A friend in academia asked me for advice (I'm a C# business application developer). He has a legacy codebase which he wrote in Fortran in the medical imaging field. It does a huge amount of number crunching using vectors. He uses a cluster (30ish cores) and has now gone towards a single workstation with 500ish GPUS in it. However where to go next with the codebase so: Other people can maintain it over next 10 year cycle Get faster at tweaking the software Can run on different infrastructures without recompiles After some research from me (this is a super interesting area) some options are: Use Python and CUDA from Nvidia Rewrite in a functional language. For example, F# or Haskell Go cloud based and use something like Hadoop and Java Learn C What has been your experience with this? What should my friend be looking at to modernize his codebase? UPDATE: Thanks @Mark and everyone who has answered. The reasons my friend is asking this question is that it's a perfect time in the projects lifecycle to do a review. Bringing research assistants up to speed in Fortran takes time (I like C#, and especially the tooling and can't imagine going back to older languages!!) I liked the suggestion of keeping the pure number crunching in Fortran, but wrapping it in something newer. Perhaps Python as that seems to be getting a stronghold in academia as a general-purpose programming language that is fairly easy to pick up. See Medical Imaging and a guy who has written a Fortran wrapper for CUDA, Can I legally publish my Fortran 90 wrappers to Nvidias' CUFFT library (from the CUDA SDK)?.

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  • Stage3D: Camera pans the whole screen

    - by Thomas Versteeg
    I am trying to create a 2D Stage3D game where you can move the camera around the level in an RTS style. I thought about using Orthographic Matrix3D functions for this but when I try to scroll the whole "stage" also scrolls. This is the Camera code: public function Camera2D(width:int, height:int, zoom:Number = 1) { resize(width, height); _zoom = zoom; } public function resize(width:Number, height:Number):void { _width = width; _height = height; _projectionMatrix = makeMatrix(0, width, 0, height); _recalculate = true; } protected function makeMatrix(left:Number, right:Number, top:Number, bottom:Number, zNear:Number = 0, zFar:Number = 1):Matrix3D { return new Matrix3D(Vector.<Number>([ 2 / (right - left), 0, 0, 0, 0, 2 / (top - bottom), 0, 0, 0, 0, 1 / (zFar - zNear), 0, 0, 0, zNear / (zNear - zFar), 1 ])); } public function get viewMatrix():Matrix3D { if (_recalculate) { _recalculate = false; _viewMatrix.identity(); _viewMatrix.appendTranslation( -_width / 2 - _x, -_height / 2 - y, 0); _viewMatrix.appendScale(_zoom, _zoom, 1); _renderMatrix.identity(); _renderMatrix.append(_viewMatrix); _renderMatrix.append(_projectionMatrix); } return _renderMatrix; } And the camera is send directly to the GPU with: c3d.setProgramConstantsFromMatrix(Context3DProgramType.VERTEX, 0, cameraMatrix, true); And these are the shaders: ------Vertex Shader------ m44 op, va0, vc0 mov v0, va1.xy mov v0.z, va0.z ------Fragment Shader------ tex ft0, v0, fs0 <2d,linear,nomip> mov oc, ft1 Here is a example and here are two screenshots to show what I mean: How do I only let the inside of the stage3D scroll and not the whole stage?

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  • Date Tracking in Oracle HRMS

    - by Manoj Madhusoodanan
    Update Date Track Modes To maintain employee data effectively Oracle HCM is using a mechanism called date tracking.The main motive behind the date track mode is to maintain past,present and future data effectively.The various update date track modes are: CORRECTION : Over writes the data. No history will maintain.UPDATE : Keeps the history and new change will effect as of effective dateUPDATE_CHANGE_INSERT : Inserts the record and preserves the futureUPDATE_OVERRIDE : Inserts the record and overrides the future Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Action: Created Employee # 22 on 01-JAN-2012 The record in PER_ALL_PEOPLE_F is as shown below. Effective Start Date Effective End Date Employee Number Marital Status Object Version Number 01-JAN-2012 31-DEC-4712 24 2 Action: Updated record in CORRECTION mode Effective Start Date Effective End Date Employee Number Marital Status Object Version Number 01-JAN-2012 31-DEC-4712 24 Single 3 Action: Updated record in UPDATE mode effective 01-JUN-2012 and Marital Status = Married Effective Start Date Effective End Date Employee Number Marital Status Object Version Number 01-JAN-2012 31-MAY-2012 24 Single 4 01-JUN-2012 31-DEC-4712 24 Married 5 Action: Updated record in UPDATE mode effective 01-SEP-2012 and Marital Status = Divorced Effective Start Date Effective End Date Employee Number Marital Status Object Version Number 01-JAN-2012 31-MAY-2012 24 Single 4 01-JUN-2012 31-AUG-2012 24 Married 6 01-SEP-2012 31-DEC-4712 24 Divorced 7 Action: Updated record in UPDATE_CHANGE_INSERT mode effective 01-MAR-2012 and Marital Status = Living Together Effective Start Date Effective End Date Employee Number Marital Status Object Version Number 01-JAN-2012 29-FEB-2012 24 Single 8 01-MAR-2012 31-MAY-2012 24 Living Together 9 01-JUN-2012 31-AUG-2012 24 Married 6 01-SEP-2012 31-DEC-4712 24 Divorced 7 Action: Updated record in UPDATE_OVERRIDE mode effective 01-AUG-2012 and Marital Status = Divorced Effective Start Date Effective End Date Employee Number Marital Status Object Version Number 01-JAN-2012 29-FEB-2012 24 Single 8 01-MAR-2012 31-MAY-2012 24 Living Together 9 01-JUN-2012 31-JUL-2012 24 Married 10 01-AUG-2012 31-DEC-4712 24 Divorced 11  Delete Date Track Modes The various delete date track modes are ZAP : wipes all recordsDELETE : Deletes  current recordFUTURE_CHANGE : Deletes current and future changes.DELETE_NEXT_CHANGE : Deletes next change Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Element Entry records are shown below. Effective Start Date Effective End Date Element Entry Id Object Version Number 01-JAN-2012 12-OCT-2012 129831 3 13-OCT-2012 19-OCT-2012 129831 5 20-OCT-2012 31-DEC-4712 129831 6 Action: Delete record in ZAP mode effective 14-JAN-2012 No rows Action: Delete record in DELETE mode effective 14-OCT-2012 Effective Start Date Effective End Date Element Entry Id Object Version Number 01-JAN-2012 12-OCT-2012 129831 3 13-OCT-2012 14-OCT-2012 129831 6 Action: Delete record in FUTURE_CHANGE mode effective 14-JAN-2012 Effective Start Date Effective End Date Element Entry Id Object Version Number 01-JAN-2012 31-DEC-4712 129831 4 Action: Delete record in NEXT_CHANGE mode effective 14-JAN-2012 Effective Start Date Effective End Date Element Entry Id Object Version Number 01-JAN-2012 19-OCT-2012 129831 4 20-OCT-2012 31-DEC-4712 129831 6

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  • OpenOffice Calc: How can I count the number of different items with data pilot?

    - by manu
    Hi all, I have a rather long spreadsheet with historical information of issues solved by some user on a colaborative environment. The spreadsheet have the following (relevant) columns date, week no., project, author id, etc... The week no. is calculated from the date, is basically the year concatenated with the week number within that year; for instance, both 2009-02-18 and 2009-02-20 yield the week number 200908 - the 8th week of year 2009; and 2009-02-23 yields 200909 - the 9th week of year 2009. I need to count how many different users (given by author id) contributed to some project, on a weekly basis. I have setup a data pilot with the week as Row Field, the project as the Column Field, and count-author as the Data Field. However, this counts the author id as different instances. This is not what I need. I need to count how many different users contributed to each project on a weekly basis. I expect to get something like: projects week Project1 Project2 Project3 200901 10 2 200902 2 7 Each inner cell containing how many different users contributed. With the count-author configuration, what I get is how many contributions (total) got the project on that week. Is there a way to tell OpenOffice Calc to do what I want?

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  • Do large number of internal broken links affect SEO?

    - by TheBigK
    We've a WordPress blog and had disqus plugin in stalled for several months. Around late August this year, the plugin created a ton of URLs that linked to non-existent location on our website. For example - Correct URL: domain.com/correct-URL/ Disqus created - domain.com/correct-URL/344322/ - Throws 404 domain.com/correct-URL/433466/ - Throws 404 So essentially, Google found a LARGE number of broken links that pointed to unknown locations on our own domain. As the count of those errors (404) rose, our site suffered massive drop in traffic and crawl rate dropped to 10% of what it was earlier. I wish to know - Can large number of (we've over 99k of them) internal broken links cause rankings to drop? I've fixed the issue in one go by creating 301 redirects for each bad URL to correct URL and removing disqus. Google however drops the count by ~1000 daily, as I mark errors as 'fixed' in Google Webmaster Tools. Is there any way to speed this up? Should I setup custom crawl rate to 'Fast' in GWT to make Google crawl our website faster? I'd appreciate your inputs and experience sharing.

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  • Are there any good examples of open source C# projects with a large number of refactorings?

    - by Arjen Kruithof
    I'm doing research into software evolution and C#/.NET, specifically on identifying refactorings from changesets, so I'm looking for a suitable (XP-like) project that may serve as a test subject for extracting refactorings from version control history. Which open source C# projects have undergone large (number of) refactorings? Criteria A suitable project has its change history publicly available, has compilable code at most commits and at least several refactorings applied in the past. It does not have to be well-known, and the code quality or number of bugs is irrelevant. Preferably the code is in a Git or SVN repository. The result of this research will be a tool that automatically creates informative, concise comments for a changeset. This should improve on the common development practice of just not leaving any comments at all. EDIT: As Peter argues, ideally all commit comments would be teleological (goal-oriented). Practically, if a comment is made at all it is often descriptive, merely a summary of the changes. Sadly we're a long way from automatically inferring developer intentions!

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  • Given an integer, determine if it is a Palindrome in less than O(n) [on hold]

    - by user134235
    There is an O(n) solution to the problem of determining if an integer is a palindrome below. Is it possible to solve this problem in O(log n) or better? static void IsPalindrome(int Number) { int OrignalNum = Number; int Reverse = 0; int Remainder = 0; if (Number > 0) { while (Number > 0) { Remainder = Number % 10; Reverse = Reverse * 10 + Remainder; Number = Number / 10; } if (OrignalNum == Reverse) Console.WriteLine("It is a Palindrome"); else Console.WriteLine("It is not a Palindrome"); } else Console.WriteLine("Enter Number Again"); }

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  • Segmentation. strcmp [C]

    - by FILIaS
    Hello, I have a file with format: [name][number][amount] number is taken as a string. and im using it in a strcmp. Problem is that i get a segmentation fault. I know that on most cases when strcmp signs segmentation fault it means that one of the parameters is null or cant find its "end" ('\0'). I checked with gdb and i cant say if this is the problem.Take a look: > (gdb) bt full > #0 0x08048729 in lookup (hashtable=0x804b008, hashval=27, > number=0x804b740 "6900101001") > list = 0xffffffff > #1 0x080487ac in add (hashtable=0x804b008, > number=0x804b740 "9900101001", name=0x804b730 "Smithpolow", > time=6943) > new_elem = 0xffffffff > hashval = 27 > #2 0x08048b25 in main (argc=1, argv=0xbffff4b4) > number = 0x804b740 "9900101001" > name = 0x804b730 "Smithpolow" > time = 6943 > i = 2 Code: clientsList *lookup_on_Clients(clientsHashTable *hashtable,int hashval,char number[10]) { printf("NUMBER:%s\n",number); clientsList *list=hashtable[hashval].head; for(list; list!=NULL; list=list->next){ if (strcmp(number,list->number)==0) //SEGMENTATION! return list; } return NULL; } int add ( HashTable* hashtable,char number[10],char* name,int time) { List *new_elem; int hashval=hash (hashtable,number); new_elem=hashtable[hashval].head; if(hashtable[hashval].length>0) { if ((lookup (hashtable,hashval,number))!=NULL) {return 0;} } //an den uparxei stoixeio sth lista if (!(new_elem=malloc(sizeof(struct clientsList)))){ return -1;} //insert values for the new elem new_elem->number=strdup(number); new_elem->name=strdup(name); new_elem->time=time; hashtable[hashval].head=new_elem; new_elem->next=NULL; hashtable[hashval].length++; /* rehash existing entries if necessary */ if(hashTableSize(hashtable)>= 2*primes[PrimesIndex]) { hashtable = expand(hashtable); if (hashtable ==NULL){ return 0; } PrimesIndex++; } return 1; } and the main: FILE * File2; if ( ( File2=fopen(" File.txt","r")) !=NULL ) { // File.txt format: [name number time] e.g lountemis 6900254565 700651 int li = 0; char *lin = (char *) malloc(MAX_LINE * sizeof(char)); while(fgets(lin, MAX_LINE, clientFile2) != NULL) { token = my_linetok(lin, " "); if(token != NULL) { char* number ; char* name; int time; int i; for(i = 0; token[i] != NULL; i++) { name=strdup(token[0]); number=strdup(token[1]); time=atoi(token[2]); if (i==2) { int insertDone=0; insertDone =add(my_hash_table,number,name,time); } } free(name); free(number); free(token); } else { printf("Error reading line %s\n", lin); exit(1); } } } else { printf("Error opening file \nEXIT!"); exit(0); }

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  • Give a number to return the approximated value of an Enum?

    - by ElektroStudios
    I have this enumeration: Enum Lame_Bitrate kbps_8 = 8 kbps_16 = 16 kbps_24 = 24 kbps_32 = 32 kbps_40 = 40 kbps_48 = 48 kbps_56 = 56 kbps_64 = 64 kbps_80 = 80 kbps_96 = 96 kbps_112 = 112 kbps_128 = 128 kbps_144 = 144 kbps_160 = 160 kbps_192 = 192 kbps_224 = 224 kbps_256 = 256 kbps_320 = 320 End Enum And I would like to return the approximated value of the Enum given a number. For example, if I have the number 190 then I expect to find the more approximated value in the Enum to return the 192 (kbps_192 value of the Enum), if I have the number 196 then again I expect to return the value 192 (not return the next value 224 because is less approximated). Something like this: Private Sub Test() Dim wma_file As String = "C:\windows media audio file.wma" Dim wma_file_Bitrate As Integer = 172 Dim mp3_bitrate_approximated As Integer mp3_bitrate_approximated = Return_Approximated_Value_Of_Enum(wma_file_Bitrate) End Sub private function Return_Approximated_Value_Of_Enum(byval value as integer) as integer return... enum.find(value).approximated... end function Exist any framework method to find the more approximated number given other number in a Enum? I hope you can understand my question, thank you. PS: I prefer a solution using LINQ extensions if can be.

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  • set target.id to div id and a number?

    - by Claes Gustavsson
    The target id below is map_external, but I would like to get map_external(and a number) I have this: $('#jqt').bind('pageAnimationStart', function(e, info){ if (e.target.id == 'map_external') { if (info.direction =='in') { localiser(); } and it works, and my target page looks like this: <div id="map_external"> content.... </div> but I would like to have a random number aswell, like this: <div id="map_external<%=asp random number%>"> content.... </div> so how do i write if (e.target.id == 'map_external') so that it gets map_external and a number(any number)? Thanks!

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  • In SQL, how can I count the number of values in a column and then pivot it so the column becomes the

    - by Josh Yeager
    I have a survey database with one column for each question and one row for each person who responds. Each question is answered with a value from 1 to 3. Id Quality? Speed? -- ------- ----- 1 3 1 2 2 1 3 2 3 4 3 2 Now, I need to display the results as one row per question, with a column for each response number, and the value in each column being the number of responses that used that answer. Finally, I need to calculate the total score, which is the number of 1's plus two times the number of 2's plus three times the number of threes. Question 1 2 3 Total -------- -- -- -- ----- Quality? 0 2 2 10 Speed? 2 1 1 7 Is there a way to do this in set-based SQL? I know how to do it using loops in C# or cursors in SQL, but I'm trying to make it work in a reporting tool that doesn't support cursors.

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  • Grouping parent node based on child elements values and sequence number.

    - by Mahir
    Hi, I need to transform XML using xslt. Logic: Split the parent if the parent having different child address and append the sequence number with parent name. Also need line number for the child. Here we may have number of parent nodes and each parent node may have more number of child nodes. I have tried numerous ways to achieve this and I am stuck with generating sequence number in the foreach. So can any one try and give a solution for this. Source XML as below: P1 CName1 Address1 CName2 Address2 CName3 Address1 P2 CName1 Address1 The target XML should as below: P1_1 CName1 Address1 1 CName2 Address2 2 CName3 Address1 P1_2 1 CName2 Address2 P2_1 1 CName1 Address1

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  • usb wifi dongle on ubuntu server, cannot install realtek driver RTL 8188cus

    - by Sandro Dzneladze
    I got cheap Ebay wifi dongle from HongKong, Im trying to set it up on my ubuntu server. Occasionally need to move server, so it cannot always be connected to router via lan. Anyhow, usb wifi came with a driver cd. I uploaded files to my home directory and tried to run install script (RTL 8188cus): sudo bash install.sh But I get error: Authentication requested [root] for make driver: make ARCH=x86_64 CROSS_COMPILE= -C /lib/modules/2.6.38-8-server/build M=/home/minime/RTL 8188cus/Linux/driver/rtl8192CU_linux_v2.0.1324.20110126 modules make[1]: Entering directory `/usr/src/linux-headers-2.6.38-8-server' make[1]: *** No rule to make target `8188cus/Linux/driver/rtl8192CU_linux_v2.0.1324.20110126'. Stop. make[1]: Leaving directory `/usr/src/linux-headers-2.6.38-8-server' make: *** [modules] Error 2 Compile make driver error: 2, Please check error Mesg Any ideas what Im doing wrong? There is another driver folder for linux called: RTL 81XX, which doesn't have install.sh at all! I tried to use make command, but I get: make: *** No targets specified and no makefile found. Stop. Any help? this is first time I'm installing driver from source. Im on Ubuntu 11.04 server. lsusb Bus 001 Device 002: ID 0bda:8176 Realtek Semiconductor Corp. lspci -nn 00:00.0 Host bridge [0600]: Intel Corporation N10 Family DMI Bridge [8086:a000] (rev 02) 00:02.0 VGA compatible controller [0300]: Intel Corporation N10 Family Integrated Graphics Controller [8086:a001] (rev 02) 00:1b.0 Audio device [0403]: Intel Corporation N10/ICH 7 Family High Definition Audio Controller [8086:27d8] (rev 02) 00:1c.0 PCI bridge [0604]: Intel Corporation N10/ICH 7 Family PCI Express Port 1 [8086:27d0] (rev 02) 00:1d.0 USB Controller [0c03]: Intel Corporation N10/ICH 7 Family USB UHCI Controller #1 [8086:27c8] (rev 02) 00:1d.1 USB Controller [0c03]: Intel Corporation N10/ICH 7 Family USB UHCI Controller #2 [8086:27c9] (rev 02) 00:1d.2 USB Controller [0c03]: Intel Corporation N10/ICH 7 Family USB UHCI Controller #3 [8086:27ca] (rev 02) 00:1d.3 USB Controller [0c03]: Intel Corporation N10/ICH 7 Family USB UHCI Controller #4 [8086:27cb] (rev 02) 00:1d.7 USB Controller [0c03]: Intel Corporation N10/ICH 7 Family USB2 EHCI Controller [8086:27cc] (rev 02) 00:1e.0 PCI bridge [0604]: Intel Corporation 82801 Mobile PCI Bridge [8086:2448] (rev e2) 00:1f.0 ISA bridge [0601]: Intel Corporation NM10 Family LPC Controller [8086:27bc] (rev 02) 00:1f.2 IDE interface [0101]: Intel Corporation N10/ICH7 Family SATA IDE Controller [8086:27c0] (rev 02) 00:1f.3 SMBus [0c05]: Intel Corporation N10/ICH 7 Family SMBus Controller [8086:27da] (rev 02) 01:00.0 Ethernet controller [0200]: Atheros Communications Device [1969:1083] (rev c0) sudo lshw description: Desktop Computer product: To Be Filled By O.E.M. (To Be Filled By O.E.M.) vendor: To Be Filled By O.E.M. version: To Be Filled By O.E.M. serial: To Be Filled By O.E.M. width: 64 bits capabilities: smbios-2.6 dmi-2.6 vsyscall64 vsyscall32 configuration: boot=normal chassis=desktop family=To Be Filled By O.E.M. sku=To Be Filled By O.E.M. uuid=00020003-0004-0005-0006-000700080009 *-core description: Motherboard product: AD525PV3 vendor: ASRock physical id: 0 *-firmware description: BIOS vendor: American Megatrends Inc. physical id: 0 version: P1.20 date: 04/01/2011 size: 64KiB capacity: 448KiB capabilities: pci upgrade shadowing cdboot bootselect socketedrom edd int13floppy1200 int13floppy720 int13floppy2880 int5printscreen int9keyboard int14serial int17printer int10video acpi usb ls120boot zipboot biosbootspecification netboot *-cpu description: CPU product: Intel(R) Atom(TM) CPU D525 @ 1.80GHz vendor: Intel Corp. physical id: 4 bus info: cpu@0 version: Intel(R) Atom(TM) CPU D525 @ 1.80GHz serial: To Be Filled By O.E.M. slot: CPUSocket size: 1800MHz capacity: 1800MHz width: 64 bits clock: 200MHz capabilities: x86-64 fpu fpu_exception wp vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush dts acpi mmx fxsr sse sse2 ss ht tm pbe syscall nx constant_tsc arch_perfmon pebs bts rep_good nopl aperfmperf pni dtes64 monitor ds_cpl tm2 ssse3 cx16 xtpr pdcm movbe lahf_lm configuration: cores=2 enabledcores=2 threads=4 *-cache:0 description: L1 cache physical id: 5 slot: L1-Cache size: 48KiB capacity: 48KiB capabilities: internal write-back data *-cache:1 description: L2 cache physical id: 6 slot: L2-Cache size: 1MiB capacity: 1MiB capabilities: internal write-back unified *-memory description: System Memory physical id: c slot: System board or motherboard size: 2GiB *-bank:0 description: SODIMM DDR2 Synchronous 800 MHz (1.2 ns) product: ModulePartNumber00 vendor: Manufacturer00 physical id: 0 serial: SerNum00 slot: DIMM0 size: 2GiB width: 64 bits clock: 800MHz (1.2ns) *-bank:1 description: DIMM [empty] product: ModulePartNumber01 vendor: Manufacturer01 physical id: 1 serial: SerNum01 slot: DIMM1 *-pci description: Host bridge product: N10 Family DMI Bridge vendor: Intel Corporation physical id: 100 bus info: pci@0000:00:00.0 version: 02 width: 32 bits clock: 33MHz configuration: driver=agpgart-intel resources: irq:0 *-display description: VGA compatible controller product: N10 Family Integrated Graphics Controller vendor: Intel Corporation physical id: 2 bus info: pci@0000:00:02.0 version: 02 width: 32 bits clock: 33MHz capabilities: msi pm vga_controller bus_master cap_list rom configuration: driver=i915 latency=0 resources: irq:41 memory:fea80000-feafffff ioport:dc00(size=8) memory:e0000000-efffffff memory:fe900000-fe9fffff *-multimedia description: Audio device product: N10/ICH 7 Family High Definition Audio Controller vendor: Intel Corporation physical id: 1b bus info: pci@0000:00:1b.0 version: 02 width: 64 bits clock: 33MHz capabilities: pm msi pciexpress bus_master cap_list configuration: driver=HDA Intel latency=0 resources: irq:43 memory:fea78000-fea7bfff *-pci:0 description: PCI bridge product: N10/ICH 7 Family PCI Express Port 1 vendor: Intel Corporation physical id: 1c bus info: pci@0000:00:1c.0 version: 02 width: 32 bits clock: 33MHz capabilities: pci pciexpress msi pm normal_decode bus_master cap_list configuration: driver=pcieport resources: irq:40 ioport:e000(size=4096) memory:feb00000-febfffff ioport:80000000(size=2097152) *-network description: Ethernet interface product: Atheros Communications vendor: Atheros Communications physical id: 0 bus info: pci@0000:01:00.0 logical name: eth0 version: c0 serial: XX size: 100Mbit/s capacity: 1Gbit/s width: 64 bits clock: 33MHz capabilities: pm msi pciexpress vpd bus_master cap_list ethernet physical tp 10bt 10bt-fd 100bt 100bt-fd 1000bt-fd autonegotiation configuration: autonegotiation=on broadcast=yes driver=atl1c driverversion=1.0.1.0-NAPI duplex=full firmware=N/A ip=192.168.1.99 latency=0 link=yes multicast=yes port=twisted pair speed=100Mbit/s resources: irq:42 memory:febc0000-febfffff ioport:ec00(size=128) *-usb:0 description: USB Controller product: N10/ICH 7 Family USB UHCI Controller #1 vendor: Intel Corporation physical id: 1d bus info: pci@0000:00:1d.0 version: 02 width: 32 bits clock: 33MHz capabilities: uhci bus_master configuration: driver=uhci_hcd latency=0 resources: irq:23 ioport:d880(size=32) *-usb:1 description: USB Controller product: N10/ICH 7 Family USB UHCI Controller #2 vendor: Intel Corporation physical id: 1d.1 bus info: pci@0000:00:1d.1 version: 02 width: 32 bits clock: 33MHz capabilities: uhci bus_master configuration: driver=uhci_hcd latency=0 resources: irq:19 ioport:d800(size=32) *-usb:2 description: USB Controller product: N10/ICH 7 Family USB UHCI Controller #3 vendor: Intel Corporation physical id: 1d.2 bus info: pci@0000:00:1d.2 version: 02 width: 32 bits clock: 33MHz capabilities: uhci bus_master configuration: driver=uhci_hcd latency=0 resources: irq:18 ioport:d480(size=32) *-usb:3 description: USB Controller product: N10/ICH 7 Family USB UHCI Controller #4 vendor: Intel Corporation physical id: 1d.3 bus info: pci@0000:00:1d.3 version: 02 width: 32 bits clock: 33MHz capabilities: uhci bus_master configuration: driver=uhci_hcd latency=0 resources: irq:16 ioport:d400(size=32) *-usb:4 description: USB Controller product: N10/ICH 7 Family USB2 EHCI Controller vendor: Intel Corporation physical id: 1d.7 bus info: pci@0000:00:1d.7 version: 02 width: 32 bits clock: 33MHz capabilities: pm debug ehci bus_master cap_list configuration: driver=ehci_hcd latency=0 resources: irq:23 memory:fea77c00-fea77fff *-pci:1 description: PCI bridge product: 82801 Mobile PCI Bridge vendor: Intel Corporation physical id: 1e bus info: pci@0000:00:1e.0 version: e2 width: 32 bits clock: 33MHz capabilities: pci subtractive_decode bus_master cap_list *-isa description: ISA bridge product: NM10 Family LPC Controller vendor: Intel Corporation physical id: 1f bus info: pci@0000:00:1f.0 version: 02 width: 32 bits clock: 33MHz capabilities: isa bus_master cap_list configuration: latency=0 *-ide description: IDE interface product: N10/ICH7 Family SATA IDE Controller vendor: Intel Corporation physical id: 1f.2 bus info: pci@0000:00:1f.2 logical name: scsi0 version: 02 width: 32 bits clock: 66MHz capabilities: ide pm bus_master cap_list emulated configuration: driver=ata_piix latency=0 resources: irq:19 ioport:1f0(size=8) ioport:3f6 ioport:170(size=8) ioport:376 ioport:ff90(size=16) memory:80200000-802003ff *-disk description: ATA Disk product: WDC WD10TPVT-11U vendor: Western Digital physical id: 0.0.0 bus info: scsi@0:0.0.0 logical name: /dev/sda version: 01.0 serial: WD-WXC1A80P0314 size: 931GiB (1TB) capabilities: partitioned partitioned:dos configuration: ansiversion=5 signature=00088c47 *-volume:0 description: EXT4 volume vendor: Linux physical id: 1 bus info: scsi@0:0.0.0,1 logical name: /dev/sda1 logical name: /media/private version: 1.0 serial: 042daf2d-350c-4640-a76a-4554c9d98c59 size: 300GiB capacity: 300GiB capabilities: primary journaled extended_attributes large_files huge_files dir_nlink recover extents ext4 ext2 initialized configuration: created=2011-11-06 11:05:03 filesystem=ext4 label=Private lastmountpoint=/media/private modified=2012-04-13 20:01:16 mount.fstype=ext4 mount.options=rw,relatime,barrier=1,stripe=1,data=ordered mounted=2012-04-13 20:01:16 state=mounted *-volume:1 description: Extended partition physical id: 2 bus info: scsi@0:0.0.0,2 logical name: /dev/sda2 size: 625GiB capacity: 625GiB capabilities: primary extended partitioned partitioned:extended *-logicalvolume:0 description: Linux filesystem partition physical id: 5 logical name: /dev/sda5 logical name: /media/storage capacity: 600GiB configuration: mount.fstype=ext4 mount.options=rw,relatime,barrier=1,stripe=1,data=ordered state=mounted *-logicalvolume:1 description: Linux filesystem partition physical id: 6 logical name: /dev/sda6 logical name: /media/dropbox capacity: 24GiB configuration: mount.fstype=ext4 mount.options=rw,relatime,barrier=1,stripe=1,data=ordered state=mounted *-volume:2 description: EXT4 volume vendor: Linux physical id: 3 bus info: scsi@0:0.0.0,3 logical name: /dev/sda3 logical name: /media/www version: 1.0 serial: 9b0a27b4-05d8-40d5-bfc7-4aeba198db7b size: 2570MiB capacity: 2570MiB capabilities: primary journaled extended_attributes large_files huge_files dir_nlink recover extents ext4 ext2 initialized configuration: created=2011-11-06 11:05:11 filesystem=ext4 label=www lastmountpoint=/media/www modified=2012-04-15 11:31:12 mount.fstype=ext4 mount.options=rw,relatime,barrier=1,stripe=1,data=ordered mounted=2012-04-15 11:31:12 state=mounted *-volume:3 description: Linux swap volume physical id: 4 bus info: scsi@0:0.0.0,4 logical name: /dev/sda4 version: 1 serial: 6ed1130e-3aad-4fa6-890b-77e729121e3b size: 4098MiB capacity: 4098MiB capabilities: primary nofs swap initialized configuration: filesystem=swap pagesize=4096 *-serial UNCLAIMED description: SMBus product: N10/ICH 7 Family SMBus Controller vendor: Intel Corporation physical id: 1f.3 bus info: pci@0000:00:1f.3 version: 02 width: 32 bits clock: 33MHz configuration: latency=0 resources: ioport:400(size=32) *-scsi physical id: 1 bus info: usb@1:4 logical name: scsi2 capabilities: emulated scsi-host configuration: driver=usb-storage *-disk description: SCSI Disk physical id: 0.0.0 bus info: scsi@2:0.0.0 logical name: /dev/sdb size: 3864MiB (4051MB) capabilities: partitioned partitioned:dos configuration: signature=000b4c55 *-volume description: EXT4 volume vendor: Linux physical id: 1 bus info: scsi@2:0.0.0,1 logical name: /dev/sdb1 logical name: / version: 1.0 serial: 33926e39-4685-4f63-b83c-f2a67824b69a size: 3862MiB capacity: 3862MiB capabilities: primary bootable journaled extended_attributes large_files huge_files dir_nlink recover extents ext4 ext2 initialized configuration: created=2011-10-11 14:03:46 filesystem=ext4 lastmountpoint=/ modified=2012-03-19 11:47:29 mount.fstype=ext4 mount.options=rw,noatime,errors=remount-ro,barrier=1,data=ordered mounted=2012-04-15 11:31:11 state=mounted rfkill list all Doesnt show anything! dmesg | grep -i firmware [ 0.715481] pci 0000:00:1f.0: [Firmware Bug]: TigerPoint LPC.BM_STS cleared

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  • How to Get Serial Number or ID of Android Emulator After it Runs?

    - by papalagi
    If I run several emulators with -no-window option in one machine. The command "adb devices" shows: List of devices attached emulator-5554 device emulator-5556 device emulator-5558 device ... However, according to this output, I can't tell the difference between each emulator device at all. I need to know which emulator runs on what AVD, then I can install APKs or send commands to the emulator. How can I recognize each emulator device or get the serial number of emulator after it runs?

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  • With Go, how to append unknown number of byte into a vector and get a slice of bytes?

    - by Stephen Hsu
    I'm trying to encode a large number to a list of bytes(uint8 in Go). The number of bytes is unknown, so I'd like to use vector. But Go doesn't provide vector of byte, what can I do? And is it possible to get a slice of such a byte vector? I intends to implement data compression. Instead of store small and large number with the same number of bytes, I'm implements a variable bytes that uses less bytes with small number and more bytes with large number. My code can not compile, invalid type assertion: 1 package main 2 3 import ( 4 //"fmt" 5 "container/vector" 6 ) 7 8 func vbEncodeNumber(n uint) []byte{ 9 bytes := new(vector.Vector) 10 for { 11 bytes.Push(n % 128) 12 if n < 128 { 13 break 14 } 15 n /= 128 16 } 17 bytes.Set(bytes.Len()-1, bytes.Last().(byte)+byte(128)) 18 return bytes.Data().([]byte) // <- 19 } 20 21 func main() { vbEncodeNumber(10000) } I wish to writes a lot of such code into binary file, so I wish the func can return byte array. I haven't find a code example on vector.

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  • How to generate a number in arbitrary range using random()={0..1} preserving uniformness and density?

    - by psihodelia
    Generate a random number in range [x..y] where x and y are any arbitrary floating point numbers. Use function random(), which returns a random floating point number in range [0..1] from P uniformly distributed numbers (call it "density"). Uniform distribution must be preserved and P must be scaled as well. I think, there is no easy solution for such problem. To simplify it a bit, I ask you how to generate a number in interval [-0.5 .. 0.5], then in [0 .. 2], then in [-2 .. 0], preserving uniformness and density? Thus, for [0 .. 2] it must generate a random number from P*2 uniformly distributed numbers. The obvious simple solution random() * (x - y) + y will generate not all possible numbers because of the lower density for all abs(x-y)>1.0 cases. Many possible values will be missed. Remember, that random() returns only a number from P possible numbers. Then, if you multiply such number by Q, it will give you only one of P possible values, scaled by Q, but you have to scale density P by Q as well.

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  • Using Loops for prompts with If/Else/Esif

    - by Dante
    I started with: puts "Hello there, and what's your favorite number?" favnum = gets.to_i puts "Your favorite number is #{favnum}?" " A better favorite number is #{favnum + 1}!" puts "Now, what's your favorite number greater than 10?" favnumOverTen = gets.to_i if favnumOverTen < 10 puts "Hey! I said GREATER than 10! Try again buddy." else puts "Your favorite number great than 10 is #{favnumOverTen}?" puts "A bigger and better number over 10 is #{favnumOverTen * 10}!" puts "It's literally 10 times better!" end That worked fine, but if the user entered a number less than 10 the program ended. I want the user to be prompted to try again until they enter a number greater than 10. Am I supposed to do that with a loop? Here's what I took a swing at, but clearly it's wrong: puts "Hello there, and what's your favorite number?" favnum = gets.to_i puts "Your favorite number is #{favnum}?" " A better favorite number is #{favnum + 1}!" puts "Now, what's your favorite number greater than 10?" favnumOverTen = gets.to_i if favnumOverTen < 10 loop.do puts "Hey! I said GREATER than 10! Try again buddy." favnumOverTen = gets.to_i until favnumOverTen > 10 else puts "Your favorite number great than 10 is #{favnumOverTen}?" puts "A bigger and better number over 10 is #{favnumOverTen * 10}!" puts "It's literally 10 times better!" end

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