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  • forcing a download using PHP / jQuery

    - by Dirty-flow
    I know there are already many questions about forcing a download with PHP, but I can't find what I'm doing wrong and what should I do. I'm having an list with filenames, and I want to download one of them by clicking a button. My jQuery: $(".MappeDownload").on("click",function(e){ e.stopPropagation(); fileId=$(this).val() $.post("ajax/DownloadFile.php",{ id : fileId}) }) and on the server side I have a table with the file names and the file path. $sql = "SELECT vUploadPfad, vUploadOriginname FROM tabUpload WHERE zUploadId='$_POST[id]'"; $result = mysql_query($sql) or die(""); $file = mysql_fetch_array($result); $localfile = $file["vUploadPfad"]; $name=$file["vUploadOriginname"]; $fp = fopen($localfile, 'rb'); header("Cache-Control: "); header("Pragma: "); header("Content-Type: application/octet-stream"); header("Content-Length: " . filesize($localfile)); header("Content-Disposition: attachment; filename='".$name."';"); header("Content-Transfer-Encoding: binary\n"); fpassthru($fp); exit; The AJAX request is successful, I'm getting the right header(filesize, filename etc...) but the download are not starting.

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  • Choosing local versus public domain name for Active Directory

    - by DSO
    What are the pros and cons of choosing a local domain name such as mycompany.local versus a publicly registered domain name such as mycompany.com (assuming that your org has registered the public name)? When would you choose one over the other? UPDATE Thanks to Zoredache and Jay for pointing me to this question, which had the most useful responses. That also led me to find this Microsoft Technet article, which states: It is best to use DNS names that are registered with an Internet authority in the Active Directory namespace. Only registered names are guaranteed to be globally unique. If another organization later registers the same DNS domain name, or if your organization merges with, acquires, or is acquired by other company that uses the same DNS names, then the two infrastructures cannot interact with one another. Note Using single label names or unregistered suffixes, such as .local, is not recommended. Combining this with mrdenny's advice, I think the right approach is to use either: Registered domain name that will never be used publicly (e.g. mycompany.org, mycompany.info, etc). Subdomain of an existing public domain name which will never be used publicly (e.g. corp.mycompany.com). The "never used publicly" part is a business decision so its probably best to get sign off from those in the company authorized to reserve domain names and subdomains. E.g. you don't want to use a registered name or subdomain that the marketing dept later wants to use for some public marketing campaign.

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  • Data confusion - Selecting data in one DataGridView based on selection in another

    - by Logan Young
    This probably isn't the best way to do what I want, but I can't think of anything else to try... NB: I'm using Visual Basic.NET My form has 2 DataGridView controls. One of these is bound to a DataSet, the other isn't visible - at least not until the user selects a uniqueidentifier cell in the 1st grid. When the user makes this selection, the 2nd grid will become visible and display the row from another with the same id as the one selected in the 1st grid. So, basically, I want to dynamically display data in one grid based on user selection in another grid. My code looks like this so far... Private Sub RulesGrid_CellClick(ByVal sender As System.Object, ByVal e As System.Windows.Forms.DataGridViewCellEventArgs) Handles RulesGrid.CellClick Try FlagsGrid.Visible = True ''// MsgBox(RulesGrid.CurrentCell.Value.ToString()) Dim sql As String = "SELECT * FROM ctblMKA_Status_Flags " + _ "WHERE intStatusID = '" & RulesGrid.CurrentCell.Value & "'" DSFlags = GetDS(sql) DSFlags.DataSetName = "FlagsDataSet" FlagsGrid.DataSource = DSFlags ProgressBar.Visible = False Catch ex As Exception MsgBox(ex.ToString) End Try End Sub I feel like I'm missing something here... Any ideas anyone?

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  • c# creating a database query METHOD

    - by Sinaesthetic
    I'm not sure if im delluded but what I would like to do is create a method that will return the results of a query, so that i can reuse the connection code. As i understand it, a query returns an object but how do i pass that object back? I want to send the query into the method as a string argument, and have it return the results so that I can use them. Here's what i have which was a stab in the dark, it obviously doesn't work. This example is me trying to populate a listbox with the results of a query; the sheet name is Employees and the field/column is name. The error i get is "Complex DataBinding accepts as a data source either an IList or an IListSource.". any ideas? public Form1() { InitializeComponent(); openFileDialog1.ShowDialog(); openedFile = openFileDialog1.FileName; lbxEmployeeNames.DataSource = Query("Select [name] FROM [Employees$]"); } public object Query(string sql) { System.Data.OleDb.OleDbConnection MyConnection; System.Data.OleDb.OleDbCommand myCommand = new System.Data.OleDb.OleDbCommand(); string connectionPath; //build connection string connectionPath = "provider=Microsoft.Jet.OLEDB.4.0;Data Source='" + openedFile + "';Extended Properties=Excel 8.0;"; MyConnection = new System.Data.OleDb.OleDbConnection(connectionPath); MyConnection.Open(); myCommand.Connection = MyConnection; myCommand.CommandText = sql; return myCommand.ExecuteNonQuery(); }

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  • Using placeholders/variables in a sed command

    - by jesse_galley
    I want to store a specific part of a matched result as a variable to be used for replacement later. I would like to keep this in a one liner instead of finding the variable I need before hand. when configuring apache, and use mod_rewrite, you can specificy specific parts of patterns to be used as variables,like this: RewriteRule ^www.example.com/page/(.*)$ http://www.example.com/page.php?page=$1 [R=301,L] the part of the pattern match that's contained inside the parenthesis is stored as $1 for use later. So if the url was www.example.com/page/home, it would be replaced with www.example.com/page.php?page=home. So the "home" part of the match was saved in $1 because it was the part of the pattern inside the parenthesis. I want something like this functionality with a sed command, I need to automatically replace many strings in a SQL dump file, to add drop table if exist commands before each create table, but I need to know the table name to do this, so if the dump file contains something like: ... CREATE TABLE `orders` ... I need to run something like: cat dump.sql | sed "s/CREATE TABLE `(.*)`/DROP TABLE IF EXISTS $1\N CREATE TABLE `$1`/g" to get the result of: ... DROP TABLE IF EXISTS `orders` CREATE TABLE `orders` ... I'm using the mod_rewrite syntax in the sed command as a logical example of what I'm trying to do. Any suggestions?

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  • UIImage Object surprisingly returning null but not NSData

    - by riyaz
    i have created a sqlite db. and i have insert a few datas in my db.. UIImage * imagee=[UIImage imageNamed:@"image.png"]; NSData *mydata=[NSData dataWithData:UIImagePNGRepresentation(imagee)]; const char *dbpath = [databasePath UTF8String]; NSString *insertSQL=[NSString stringWithFormat:@"insert into CONTACTS values(\"%@\",\"%@\")",@"Mathan",mydata]; NSLog(@"mydata %@",mydata); sqlite3_stmt *addStatement; const char *insert_stmt=[insertSQL UTF8String]; if (sqlite3_open(dbpath,&contactDB)==SQLITE_OK) { sqlite3_prepare_v2(contactDB,insert_stmt,-1,&addStatement,NULL); if (sqlite3_step(addStatement)==SQLITE_DONE) { sqlite3_bind_blob(addStatement,1, [mydata bytes], [mydata length], SQLITE_TRANSIENT); NSLog(@"Data saved"); } else{ NSLog(@"Some Error occured"); } sqlite3_close(contactDB); } else{ NSLog(@"Failure"); } have written some codes to retrive the data sqlite3_stmt *statement; if (sqlite3_open([databasePath UTF8String], &contactDB) == SQLITE_OK) { NSString *sql = [NSString stringWithFormat:@"SELECT * FROM contacts"]; if (sqlite3_prepare_v2( contactDB, [sql UTF8String], -1, &statement, nil) == SQLITE_OK) { while (sqlite3_step(statement) == SQLITE_ROW) { char *field1 = (char *) sqlite3_column_text(statement, 0); NSString *field1Str = [[NSString alloc] initWithUTF8String: field1]; NSLog(@"UserName %@",field1Str); NSData *data = [[NSData alloc] initWithBytes:sqlite3_column_blob(statement, 1) length:sqlite3_column_bytes(statement, 1)]; UIImage *newImage = [[UIImage alloc]initWithData:data]; NSLog(@"Image OBJ %@",newImage); NSLog(@"Image Data %@",data); } sqlite3_close(contactDB); } } sqlite3_finalize(statement); the problem is in log, inserted NSData object and retrieved NSData Objects are different (printing in log gives different stream) moreover Image OBJ is printed null in log.. Have seen similar questions in stackoverflow. But nothing seems to help. Please give some suggestions to overcome this issue.

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  • How to pass an array of objects trough a jquery $.post?

    - by majc
    Hi, I want to pass the result of a query trough a $.post. function GetAllTasks() { $sql = "select t.id as task_id, description, createdat, createdby, max_requests, max_duration, j.name as job_name from darkfuture.tasks t, darkfuture.jobs j where t.job_id = j.id"; $sqlresult = mysql_query($sql) or die("The list of works failed: ".mysql_error($this->con)); $result = array(); while($row = mysql_fetch_assoc($sqlresult)) { $task = new TasksResult(); $task->id = $row["task_id"]; $task->description = $row["description"]; $task->createdat = $row["createdat"]; $task->createdby = $row["createdby"]; $task->max_requests = $row["max_requests"]; $task->max_duration = $row["max_duration"]; $task->job_id = $row["job_name"]; array_push($result, $task); } mysql_free_result($sqlresult); return $result; } Here is how i call it: $tasksDB = new TasksDB(); $tasks = $tasksDB->GetAllTasks(); Now i want to pass $tasks through here: $.post("views/insert_tasks.php",{'tasks[]': $tasks}, function(data) { }); I know this {'tasks[]': $tasks} it's wrong but i don't know how to do it right. Some help will be appreciated. Thanks in advance!

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  • newbie hibernate first level cache confusion

    - by Bruce
    Hi all I'm just geting to grips with hibernate. Little bit confused. I just wanted to watch the operation of the first level cache, which I understood to batch up queries until the end of the session. But if I create an object, hibernate saves it immediately, so that when I later update it in the same transaction, it has to do an update too: Session session = factory.getCurrentSession(); session.beginTransaction(); Test1 test1 = new Test1(); test1.setName("Test 1"); test1.setValue(10); // Touch it session.save(test1); System.out.println("At checkpoint 1"); test1.setValue(20); session.getTransaction().commit(); I see the sql for the save, then 'At checkpoint 1', then the sql for the update. Do I have something set up wrong or am I misunderstanding hibernate's first level cache? Is there a good document on the first level cache - I didn't find anything in the hibernate docs, but I could easily have missed it.. Thanks!

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  • Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in

    - by user1493540
    <html> <title>Title</title> <body> <link type="text/css" rel="stylesheet" href="css/bootstrap.css"/> </body> <center> <? mysql_connect ("localhost", "root","") or die (mysql_error()); mysql_select_db ("dbname"); $term = $_POST['term']; $sql = mysql_query("select * from items where name like '%$term%'"); while ($row = mysql_fetch_array($sql)){ echo '<table class="table - striped"> <theader> <tr> <th>ID</th> <th></br> Name</th></tr>'; echo ' <tbody><td>'.$row['id']; echo'</td>'; echo '<td>'; echo '</theader>' .$row['name']; echo '</td>'; echo ''; } ?> </center> <script src="js/bootsrap.js"> </script> </html> I'm, getting this error: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/runedev1/public_html/itemdb/search.php on line 19 When I run the code on localhost using Xampp, it works fine, when I upload it to the web-host, the error appears. Yes, I am changing the database name, user and password when putting it on the webhost.

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  • SQLITE crash when no data present in table

    - by johnblack45
    Hey, Im having a problem with my app that causes it to crash when no data is present in the table when using a table view. I have tested my code and it works fine as long as there is data present but i need it to work when there is no data present. -(void)initialiseTableData { NSMutableArray *array = [[NSMutableArray alloc]init]; sqlite3 *db = [iCaddyAppDelegate getNewDBConnection]; sqlite3_stmt *statement; const char *sql = "select courseId, courseName, totalPar, totalyardage, holePars, holeYardages, holeStrokeIndexs from Course"; if(sqlite3_prepare_v2(db, sql, -1, &statement, NULL)!= SQLITE_OK) { NSAssert1(0,@"Error preparing statement",sqlite3_errmsg(db)); sqlite3_close(db); } else { while (sqlite3_step(statement) == SQLITE_ROW) { Course *temp = [[Course alloc]init]; temp.courseId = sqlite3_column_int(statement,0); temp.courseName = [NSString stringWithFormat:@"%s",(char*)sqlite3_column_text(statement,1)]; temp.totalPar =sqlite3_column_int(statement,2); temp.totalYardage =sqlite3_column_int(statement,3); NSString tempHolePars = [NSString stringWithFormat:@"%s",(char)sqlite3_column_text(statement,4)]; NSString tempHoleYardages = [NSString stringWithFormat:@"%s",(char)sqlite3_column_text(statement,5)]; NSString tempHoleStrokeIndexes = [NSString stringWithFormat:@"%s",(char)sqlite3_column_text(statement,6)]; NSArray *temp1 = [tempHolePars componentsSeparatedByString:@":"]; NSArray *temp2 = [tempHoleYardages componentsSeparatedByString:@":"]; NSArray *temp3 = [tempHoleStrokeIndexes componentsSeparatedByString:@":"]; for(int i = 0; i<=17; i++) { NSString *temp1String = [temp1 objectAtIndex:i]; [temp.holePars insertObject:temp1String atIndex:i]; NSString *temp2String = [temp2 objectAtIndex:i]; [temp.holeYardages insertObject:temp2String atIndex:i]; NSString *temp3String = [temp3 objectAtIndex:i]; [temp.holeStrokeIndexes insertObject:temp3String atIndex:i]; } [array addObject:temp]; } self.list = array; [self.table reloadData]; } }

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  • jQuery and MySQL

    - by Wayne
    I have taken a jQuery script which would remove divs on a click, but I want to implement deleting records of a MySQL database. In the delete.php: <?php $photo_id = $_POST['id']; $sql = "DELETE FROM photos WHERE id = '" . $photo_id . "'"; $result = mysql_query($sql) or die(mysql_error()); ?> The jQuery script: $(document).ready(function() { $('#load').hide(); }); $(function() { $(".delete").click(function() { $('#load').fadeIn(); var commentContainer = $(this).parent(); var id = $(this).attr("id"); var string = 'id='+ id ; $.ajax({ type: "POST", url: "delete.php", data: string, cache: false, success: function(){ commentContainer.slideUp('slow', function() {$("#photo-" + id).remove();}); $('#load').fadeOut(); } }); return false; }); }); The div goes away when I click on it, but then after I refresh the page, it appears again... How do I get it to delete it from the database? Thanks :) EDIT: Woopsie... forgot to add the db.php to it, so it works now .<

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  • Why should I abstract my data layer?

    - by Gazillion
    OOP principles were difficult for me to grasp because for some reason I could never apply them to web development. As I developed more and more projects I started understanding how some parts of my code could use certain design patterns to make them easier to read, reuse, and maintain so I started to use it more and more. The one thing I still can't quite comprehend is why I should abstract my data layer. Basically if I need to print a list of items stored in my DB to the browser I do something along the lines of: $sql = 'SELECT * FROM table WHERE type = "type1"';' $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { echo '<li>'.$row['name'].'</li>'; } I'm reading all these How-Tos or articles preaching about the greatness of PDO but I don't understand why. I don't seem to be saving any LoCs and I don't see how it would be more reusable because all the functions that I call above just seem to be encapsulated in a class but do the exact same thing. The only advantage I'm seeing to PDO are prepared statements. I'm not saying data abstraction is a bad thing, I'm asking these questions because I'm trying to design my current classes correctly and they need to connect to a DB so I figured I'd do this the right way. Maybe I'm just reading bad articles on the subject :) I would really appreciate any advice, links, or concrete real-life examples on the subject!

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  • Web services or shared database for (game) server communication?

    - by jaaronfarr
    We have 2 server clusters: the first is made up of typical web applications backed by SQL databases. The second are highly optimized multiplayer game servers which keep all data in memory. Both clusters communicate with clients via HTTP (Ajax with JSON). There are a few cases in which we need to share data between the two server types, for example, reporting back and storing the results of a game (should ultimately end up in the database). We're considering several approaches for inter-server communication: Just share the MySQL databases between clusters (introduce SQL to the game servers) Sharing data in a distributed key-value store like Memcache, Redis, etc. Use an RPC technology like Google ProtoBufs or Apache Thrift Using RESTful web services (the game server would POST back to the web servers, for example) At the moment, we're leaning towards web services or just sharing the database. Sharing the database seems easy, but we're concerned this adds extra memory and a new dependency into the game servers. Web services provide good separation of concerns and fit with the existing Ajax we use, but add complexity, overhead and many more ways for communication to fail. Are there any other good reasons not to use one or the other approach? Which would be easier to scale?

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  • how to print data in a table from mysql

    - by robertdd
    hello, i want to extract the last eight entries from my database and print them into a 2 columns table!like this: |1|2| |3|4| |5|6| |7|8| is that possible? this is my code: $db = new Database(DB_SERVER, DB_USER, DB_PASS, DB_DATABASE); $db->connect(); $sql = "SELECT ID, movieno FROM movies ORDER BY ID DESC LIMIT 8 "; $rows = $db->query($sql); print '<table width="307" border="0" cellspacing="5" cellpadding="4">'; while ($record = $db->fetch_array($rows)) { $vidaidi = $record['movieno']; print <<<END <tr> <td> <a href="http://www.youtube.com/watch?v=$vidaidi" target="_blank"> <img src="http://img.youtube.com/vi/$vidaidi/1.jpg" width="123" height="80"></a> </td> </tr> END; } print '</table>';

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  • Disabling Text field with Javascript when value in drop down box is from mysql

    - by SteveJ313
    Hi I have a simple script in HTML, using a dropdown menu. When the value 1 is selected, the user can write in the text field, if value 2 is selected, it disables the text field. However, i changed the values of the dropdown menu, so that one value was from a mysql table(using PHP) and the other remained 'option value='1''. Yet now neither text field is disabled. Below is the code. `<script type="text/javascript"> function findselected() { if (document.form.selmenu.value == <?php echo $id; ?>) { document.form.txtField.disabled=true; // return false; // not sure this line is needed } else { document.form.txtField.disabled=false; // return false; // not sure this line is needed } } ` And the PHP section if(mysql_num_rows($SQL) == 1) { echo "<select name='selmenu' onChange='findselected()'>"; echo "<label>TCA_Subject</label>"; while ($row=mysql_fetch_array($SQL)) { echo "<option value='$id'>$thing</option>"; echo "<option value='2'>Choice 2</option>"; } } echo "<option value=$userid>'Choice 1'</option>"; ?> <option value='2'>Choice 2</option>"; </select> I have tried taking the second option value out of the loop, putting it into html, editing the variable in the javascript function. There is not a fault with the PHP as it is retrieving the right results and displaying it, yet the text field doesnt become disabled. Does anyone know of a possible solution? Thanks

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  • Return the exact ID using fetch_assoc

    - by Selom
    Hi, I have a small problem in my code and I need your help. Well Im using fetch_assoc to get data from database and I need to get the ID number of each of returned values. the issue is that my code only return the ID number of the last data. Here's my code: <form method="post" action="action.php"> <select name="album" style="border:1px solid #CCC; font-size:11px; padding:1px"> <?php $sql = "SELECT * FROM table"; $stmt = $dbh -> prepare($sql); $stmt -> execute(); while($row = $stmt -> fetch(PDO::FETCH_ASSOC)) { $album_ID = $row['album_ID']; $value = $row['album_name']; print "<option value ='". $value ."'>". $value. "</option>"; } ?> </select> <input type="hidden" name="album_ID" value="<?php print $album_ID?>"/> </form> I would like the hidden input type holds the selected album id, but it always holds the album id of the last data. Please help.

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  • How do Oracle Forms compare to Microsoft Access as a "front-end"?

    - by webworm
    I recently started a project where I was set to build an ADP based application in Access 2003. The font end GUI was going to be in Access while all the data resided in MS SQL Server. I say "was", because the powers that be have decided that Oracle Forms might be a better choice than Access and SQL Server. The place where I am doing this work is an Oracle shop where they use Oracle 10g. They also use Oracle Forms quite a bit internally. As for me I am always up for learning anything new. I have always been a rather "eclectic" developer (I work with .NET WinForms, ASP.NET, Java, C#, Python, and Access) so I would not mind moving to Oracle Forms as long as it could do the same things as MS Access (hopefully even more as VBA is rather limited). So my question is this. How does Oracle Forms (10g) compare to MS Access for developing a GUI application? Access uses VBA for it's language, what does Oracle Forms use? I know the Forms app is a Java applet. Does that means you can write Oracle Forms using Java?

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  • Incorrect Internal DNS Resolution

    - by user167016
    I'm having a DNS issue. Server 2008 R2. The first clue was that after being off the network for a month, I could no longer Remote Desktop into my workstation by name, it wouldn't find it. Both via VPN and internally. But if I connect using its IP, that works. Now I notice in the server's Share and Storage Management, in Manage Sessions, it's displaying the incorrect computer name for some users. So I try, for one example: Ping -a 192.168.16.81 Pinging BOBS_COMPUTER.ourdomain.local [192.168.16.81] with 32 bytes of data: - replies all successful Then I try Ping RICHARDS_COMPUTER Pinging RICHARDS_COMPUTER.ourdomain.local [192.168.16.81] with 32 bytes of data: -all replies successful In DHCP, .81 belongs to RICHARDS_COMPUTER I did try flushdns. Not sure if this is related, apologies if it's not, but when I try to connect, I also get prompted: "The identity of the remote computer cannot be verified. Do you want to connect anyway? The remote computer could not be authenticated due to problems with its security certificate. It may be unsafe to proceed.." It then lists the correct name as the name in the certificate from the remote computer, but claims that the certificate is not from a trusted authority. Any thoughts are most appreciated!

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  • Print table data mysql php

    - by Marcelo
    Hi people, i'm having a problem trying to print some data of a table. I'm new at this php mysql stuff but i think my code is right. Here it is: <html> <body> <h1>Lista de usuários</h1> <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="sabs"; // Database name $tbl_name="doador"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); while($rows = mysql_fetch_array($result)){ echo $row['id'] . " " .$row['nome'] . " " . $row['sobrenome'] . " " . $row['email'] . " " . $row['login'] . " " . $row['senha'] . " " . $row['idade'] . " ". $row['peso'] . " " . $row['fuma'] . " " . $row['sexo'] . " " . $row['doencas']; echo "<BR/>"; } mysql_close(); ?> </body> </html> All columns of the echo command exist in my table in the database. Don't get why it's not printing those values. Thanks for the attention.

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  • iPhone: Same Rows Repeated in Each Section of Grouped UITableview

    - by Rank Beginner
    I have an app that is a list of tasks, like a to do list. The user configures the tasks and that goes to the SQLite db. The list is displayed in a tableview. The SQL table in question consists of a taskid int, groupname varchar, taskname varchar, lastcompleted datetime, nextdue datetime, weighting integer. I currently have it working by creating an array from each column in the SQL table. In the tableView:cellForRowAtIndexPath: method, I create the controls for each task by binding their values to the array for each column. I want to add configurable task groups that should display as the section titles. I got the task groups to display as the section headers. My problem is that all the task rows are repeated in each group under each header. How do I get the correct rows to show up only under the correct section? I'm really new to development period and took on a hobby of trying to teach myself how to develop iphone apps. So, pretty please, be a little more detailed than you normally would with a professional developer. :)

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  • decoding jquery json data in php

    - by Mac Taylor
    hey guys recenlty i made a script to move objects and save the orders now i have a little to do to finish this script everything works fine , just one question : how can i save not numeric data in my json script this is my script : function updateWidgetData(){ var items=[]; $('.widget-title').each(function(){ var weightId=$(this).attr('id'); $('.column').each(function(){ var columnId=$(this).attr('id'); $('.widget', this).each(function(i){ var collapsed=0; if($(this).find('.widget-inside').css('display')=="none") collapsed=1; //Create Item object for current panel var item={ id: $(this).attr('id'), collapsed: collapsed, order : i, column: columnId, weight: weightId }; //Push item object into items array items.push(item); }); }); }); //Assign items array to sortorder JSON variable var sortorder={ items: items }; //Pass sortorder variable to server using ajax to save state $.post('updatePanels.php', 'data='+$.toJSON(sortorder), function(response){ if(response=="success") $("#console").html('<div class="success">Saved</div>').hide().fadeIn(1000); setTimeout(function(){ $('#console').fadeOut(1000); }, 2000); }); } and this is my php script : $data=json_decode($_POST["data"]); foreach($data->items as $item) { //Extract column number for panel $col_id=preg_replace('/[^\d\s]/', '', $item->column); //Extract id of the panel $widget_id=preg_replace('/[^\d\s]/', '', $item->id); $sql="UPDATE widgets SET column_id='$col_id', sort_no='".$item->order."', collapsed='".$item->collapsed."' WHERE id='".$widget_id."'"; mysql_query($sql) or die('Error updating widget DB'); } echo "success"; everything works fine till i use numeric value for columns' id but i need non numeric values forexample id='columnr' i want to extract r but i cant get it right any help plz !?

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  • Create 2nd tables and add data

    - by Tyler Matema
    I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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  • Problem with mysql query in paging

    - by jasmine
    I have a very simple paging and mysql query. Im not sure that my query is right: $perPage =4; $page= (isset($GET['page']) && is_numeric($GET['page'])) ? $_GET['page'] : 1; $start = ($page * $perPage ) - $perPage ; if (is_numeric($_GET['cID'])){$cid = $_GET['cID'];} $totalCount = sprintf("SELECT COUNT(*) as 'Total' FROM content WHERE catID = %d", $cid ) ; $count = mysql_query($totalCount); $rowCount = mysql_fetch_array($count); $sql = sprintf("SELECT id, title, abstract, content_image FROM content WHERE catID = %d ORDER BY id DESC LIMIT %d, %d", $cid, $start, $perPage ); $query = mysql_query($sql) or die(mysql_error()); while($row = mysql_fetch_array($query)){ echo $row['id'].' : '. $row['title'] .'<br>'; } with /categories.php?cID=1&page=2 and /categories.php?cID=1&page=1 The output is: 95 : titlev 94 : titlex 93 : titlec 92 : titleb and not changed. What is wrong in my query? Thanks in advance

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  • Django: getting the list of related records for a list of objects

    - by Silver Light
    Hello! I have two models related one-to many: class Person(models.Model): name = models.CharField(max_length=255); surname = models.CharField(max_length=255); age = models.IntegerField(); class Dog(models.Model): name = models.CharField(max_length=255); owner = models.ForeignKey('Person'); I want to output a list of persons below each person a list of dogs he has. Here's how I can do it: in view: persons = Person.objects.all()[0:100]; in template: {% for p in persons %} {{ p.name }} has dogs:<br /> {% for d in persons.dog_set.all %} - {{ d.name }}<br /> {% endfor %} {% endfor %} But if I do it like that, Django will execute 101 SQL queries which is very inefficient. I tried to make a custom manager, which will get all the persons, then all the dogs and links them in python, but then I can't use paginator (my another question: http://stackoverflow.com/questions/2532475/django-paginator-raw-sql-query ) and it looks quite ugly. Is there a more graceful way doing this?

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  • inserting facebook app users details to database

    - by fusion
    i'm trying to insert user details, who authorize the app, into the database, but nothing seems to be happening. the data is null and no record is being inserted. is there something wrong with the code? function insertUser($user_id,$sk,$conn) { //$info = $facebook->api_client->users_getInfo($user_id, 'first_name, last_name', 'name', 'sex'); $info = $facebook->api_client->fql_query("SELECT uid, first_name, last_name, name, sex FROM user WHERE uid = $user_id"); for ($i=0; $i < count($info); $i++) { $record = $info[$i]; $first_name=$record['first_name']; $last_name=$record['last_name']; $full_name=$record['name']; $gender=$record['sex']; } $data= mysql_query("select uid from users where uid='{$user_id}'",$conn); if(mysql_num_rows($data)==0) { $sql = "INSERT INTO users (uid,sessionkey, active, fname, lname, full_name, gender) VALUES('{$user_id}','{$sk}','1', '{$first_name}', '{$last_name}', '{$full_name}', '{$gender}')"; mysql_query($sql,$conn); return true; } return false; }

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